What coefficient is needed in front of H2O to balance the equation below?

Answer:

I = 250N*s

Explanation:

I = F*t

I =  impulse or momentum

F = Force

t = time

I = 25N*10s

I = 250N*s

Answer:

41.7 watts

Explanation:

power=work done/time

2500/60seconds

=41.6666

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4       ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28   momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm

Answer:

The capacitance C of a capacitor is defined as the ratio of the maximum charge Q that can be stored in a capacitor to the applied voltage V across its plates. In other words, capacitance is the largest amount of charge per volt that can be stored on the device: C = Q V . 1 F = 1 C 1 V .

Explanation:

A capacitor's capacity to hold an electric charge when a potential difference (voltage) is applied across its plates is measured by the capacitance of the device.

It can be calculated using the formula C = Q/V,

where Q is the electric charge stored on the capacitor in coulombs (C), C is the capacitance in farads (F), and V is the voltage across the capacitor in volts (V). The capacitor's physical properties, such as the area of the plates, the space between them (dielectric separation), and the substance between the plates (dielectric constant), all affect capacitance. A better charge storage capability is indicated by a higher capacitance value.

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The conservation of energy and moment allows to find the results for the velocity of the pendulum and the bullet in the system are:

          m (kg)    v (m / s)

            0.05      41.58

            0.10       21.78

            0.15       15.18

            0.20      11.88

           0.25       9.90

The conservation of mechanical energy is one of the most important principles of physics, it establishes that if there is no friction force, the energy is constant at all points. Mechanical energy is the sum of the kinetic energy plus the potential energies.

In the attachment we can see a diagram of the system, let's start by finding the speed of the pendulum when it leaves, for this we use the  conservation of energy.

Starting point. In the lowest part of the movement.

      Em₀ = K = ½ (m + M) v₀²

Final point. At the top of the movement.

      Em_f = U = (m + M) g y

Energy is conserved because there is no friction.

      Em₀ = Em_f

      ½ (m + M) v₀² = (m + M) g y

      [tex]v_o = \sqrt{2gy}[/tex]  

They indicate a table with several measurements of the masses and the period, let's use the relationship of the simple harmonic motion.

        y = y₀ cos wt

The period and the angular velocity are related.

        w = 2π / T

we substitute

          y = y₀ cos ( [tex]2 \pi \frac{t}{T}[/tex] )

Let's analyze how long it takes to reach the point of maximum height, the period is the time of a complete oscillation, therefore from the lowest point to the highest point we have ¼ of oscillation, consequently the time to the highest point.

        t = T / 4

        y = y₀ cos ( [tex]2 \pi 4[/tex])  

        y = y₀

Therefore the point of maximum amplitude coincides with the maximum height and must be average by the student, suppose that the height is

          y₀ = 20 cm = 0.20 m

Let's calculate the initial velocity.

     v₀ = [tex]\sqrt{2 \ 9.8 \ 0.20 }[/tex]  

     v₀ = 1.98 m / s

They ask for the speed of the bullet before striking the basket of mass

       M = 1 Kg.

The conservation of the momentum that for an isolated system the momentum is constant in all the instants. Let's form the system by the bullet and the basket.

Initial instant. Before the crash

       p₀ = m v

Final moment. Right after the crash.

      P_f = (m + M) v₀

The momentum is conserved because the system is isolated.

      p₀ = p_f

      m v = (m + M) v₀

      v = m + M / m v₀

they have tabulated various mass for the bullet, we calculate the speed of each bullet.

m = 0.05 kg

    v = [tex]\frac{0.05+1}{0.05} \ 1.98[/tex]  

    v = 41.58 m / s

m = 0.10 kg

     v = [tex]\frac{0.10+1}{0.10} \ 1.98[/tex]  

     v = 21.78 m / s

m = 0.15 kg

     v = [tex]\frac{0.15+1}{0.15y}[/tex]  

     v = 15.18 m / s

m = 0.20 kg

     v = 11.88 m / s

m = 0.25 kg

     v = 9.9 m / s

In conclusion with the conservation of energy and the momentum we can find the results for the speed of the pendulum and the bullet in the system are:

          m (kg)    v (m / s)

            0.05      41.58

            0.10       21.78

            0.15       15.18

            0.20      11.88

           0.25       9.90

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Answer:

Answer:

Speed of the wave in the string will be 3.2 m/sec

Explanation:

We have given frequency in the string fixed at both ends is 80 Hz

Distance between adjacent antipodes is 20 cm

We know that distance between two adjacent anti nodes is equal to half of the wavelength

So \frac{\lambda }{2}=20cm

2

λ

=20cm

\lambda =40cmλ=40cm

We have to find the speed of the wave in the string

Speed is equal to v=\lambda f=0.04\times 80=3.2m/secv=λf=0.04×80=3.2m/sec

So speed of the wave in the string will be 3.2 m/sec

Answer:

w

Explanation:

renal artery...the blood flow into the kidney via this blood vassles

and the filtration take place is called ultrafiltration

Answer:2 reactants 2 products.

this is a balanced chemical equation. That means the number of chlorine before the arrow will be the same after the arrow

Explanation: i think this answer will help you very much

The major reason why a wet saw that is used in cutting optical crystals is constantly lubricated with oil is largely due to friction, lubrication decreases friction and minimises the increase of internal energy.

Friction is basically the coming together of two parts that rubs against each other, it causes heat and lead to  deterioration of surfaces, it can also lead to wear and tear.

Although, despite it down side, friction is desire-able in most applications

e.g the brake system of vehicles, and if not for friction, we humans cannot walk without falling

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By using Lami's theorem, Mass m = 1.75 kg approximately

Given that a strong weightless rope has a mass, m, hanging from the middle of it. If the tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees to the horizontal.

By using Lami's theorem, we can get how much mass is hanging from the rope.

Let the angle between the rope = α = 180 - 40

α = 140 degrees

The angle between one of the rope and mass = β = 20 + 90

β = 110 degrees

The angle between the mass and the other rope = γ = 360 - (140 + 110)

γ = 360 - 250

γ = 110 degrees

W/ sinα = T/ sinβ = T/sinγ

W/ sinα = T/ sinβ

Substitute all the necessary parameters

W/sin140 = 25/sin 110

W / 0.643 = 25 / 0.939

W = 17.1 N

Weight W = mg

17.1 = 9.8m

mass m = 17.1/9.8

Mass m = 1.7455 kg

Mass m = 1.75 kg approximately

Therefore, 1.75 kg mass is hanging from the rope.

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The viscous force ​refers to the resistance of a fluid to flow.  It is measured in Newton-second per square meter.

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Answer:

Doppler Theory

Explanation:

it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.

=============================================

Explanation:

To compute the speed, we divide the distance traveled over the time duration.

For instance, if a car goes 100 km in 5 hours, then its speed is 100/5 = 20 km per hour.

-----------------

For section A, the car travels 30 km over the course of 2 hours (since 11:00-9:00 = 2:00)

speed = distance/time = (30 km)/(2 hrs) = 15 km/hr

-----------------

We don't need to do any computations for section B. It's a flat horizontal line, so the speed is zero. There's no change in distance, so the car is stationary for this 1 hour period.

You could say speed = distance/time = 0/1 = 0 km/hr if you wanted.

-----------------

For section C, its change in distance is 60-30 = 30 km and the change in time is 0.5 hour (because it spans from 12:00 to 12:30)

So, speed = distance/time = (30 km)/(0.5 hr) = 60 km/hr

The steeper slope of section C, compared to section A, means the car is going faster.

-----------------

Section D spans from 12:30 to 14:00. This is a time period of 14:00-12:30 = 1:30 = 1.5 hours. The change in distance is 60 km

(60 km)/(1.5 hrs) = 40 km/hr

The speed of the car during section D is 40 km per hour.

Side note: if you were talking about velocities instead of speeds, then section D would have a negative velocity of -40 km/hr to indicate the car is going the opposite direction (compared to sections A and C). However, speed is always nonnegative.

Answer:

Velocity of the vehicle (v) = 6.5 m/s

Explanation:

Mass of automobile (m) = 1200 kg

Momentum of vehicle (p) = 7800 kg m/s

By using formula of momentum:

[tex] \rm p = mv \\ \rm 7800 = 1200 \times v \\ \rm v = \frac{7800}{1200} \\ \rm v = 6.5 \: m {s}^{ - 1} [/tex]

Answer:

Exercising is not only good for their physical and mental health, but also helps them to socialise with other dogs and puppies, which is crucial to their ...

Explanation:

Answer: Saving is important to the economic progress of a country because of its relation to investment. If there is to be an increase in productive wealth, some individuals must be willing to abstain from consuming their entire income.

Explanation:

Savings is important to the economy because it enables growth and development of a nation.

The importance of savings to the economy in general can not be over emphasized.

The following are some importance of savings to the economy;

Thus, savings is important to the economy because it enables growth and development of a nation.

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Simplicity of conducting the study is to archival research as ability to test large numbers of participants is to surveys.

Archival research is a type of research which involves seeking out and extracting the evidence from archival records. These archival records may be held together either in the collection of institutions, such as libraries and museums, or in the custody of the organization that originally generated or accumulated them, or in that of a successor object.

Archival research can be contrasted with the secondary research, which involves identification and consulting the secondary sources related to the topic of enquiry; and with the other types of primary research and empirical investigation such as fieldwork and experiment.

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Answer:

Sample answer: part 1:

What was your hypothesis?

This is what you wanted to prove or study with the experiment. Reading the question I can see that the experiment seems to study the relation between the viscosity of honey and the temperature, so the hypothesis may be something like:

"The viscosity of honey decreases as temperature increases".

According to your data, do you think your hypothesis was correct?

Here you need to see your experimental data, probably, you found that yes, as you increase the temperature the viscosity decreases.

The last thing we need to do here is to summarize difficulties and problems that you had in the experiment, and propose how you could solve them in order to have a better experiment.

Obviously, this depends on how you performed the experiment, but for example, if you saw that the temperature of the honey increased too fast, you could say:

"one problem was that the temperature of the honey increased too fast"

And one way to solve that would be submerging the honey in a water bath so the temperature increases a bit slower.

part 2:

Viscosity depends strongly on temperature, but this relation depends also on the given material.

Generally, we would see that the viscosity decays exponentially as the temperature increases.

So for the first question:

What effect did the temperature have on the viscosity of the honey?

You should have seen that, as the temperature increased, the viscosity decreased.

Now, we need to give some practical examples where knowledge of viscosity is important.

The first one is for cleaning: We know that if we increase the temperature, the viscosity decreases. Thus if we have some object with some viscous thing on it, increasing the temperature will cause it to be easier to clean.

Another example is to store/transport viscous things, for example, honey, it is actually a lot easier to pour honey in bottles if you first heat it a little, so it becomes less viscous.

So there you have two examples where knowing about viscosity (and how it relates to temperature) may be important.

Explanation:

Answer: decrease

Explanation: it does

Their combined momentum after they meet is 0.

According to the law of conservation of momentum, absent an external force, the combined momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.

Let the mass of each billiard balls = m.

If the initial velocity of first ball is u; according to the question, the initial velocity of the second ball be -u.

Hence, initial momentum of the first ball is: P₁ = mu

initial momentum of the second ball is: P₂ = -mu

Hence, total initial momentum of the two balls = P₁ + P₂ = mu + ( -mu) = 0.

So, according to law of conservation of momentum:

Their combined momentum after they meet is = 0.

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The combined momentum of the two billiard balls after they meet is zero.

When two pool balls of the same size and speed roll directly at each other and collide, their momentum will increase.

Let us denote the speed of the first ball as [tex]\rm p_1[/tex] and the speed of the second ball as [tex]\rm p_2[/tex]. The momentum of the balls are equal in magnitude but opposite in direction because they have the same mass and velocity.

[tex]\rm p_1= -p_2[/tex]

When the balls collide, their momentum increases:

Total momentum after the collision= [tex]\rm p_1+ p_2[/tex]

Substituting the relationship

[tex]\rm p_1= -p_2[/tex]

Total momentum after the collision

[tex]\rm p_1- p_1= 0[/tex]

Therefore, the combined momentum of the two billiard balls after they meet is zero.

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Answer:

The car that is hald as massive

Explanation:

We can use the eqation for kinetic energy to solve this problem

KE = 1/2mv^2 (where m is mass and v is velocity/speed)

Lets give the original car a mass of 100kg and use the equation

KE = 1/2(100kg)(16m/s)^2 = 12800J

and now lets find kinetic energy of the half as massive car

KE2 = 1/2(50kg)(32m/s)^2 = 25600J

From this, we find that the hald as massive car will experience a greater kinetic energy while travling at double the velocity

Option C with uniform displacement at each time interval represents the photograph of light as the cart moves with constant velocity.

At constant velocity, the change in displacement with time is uniform. The displacement of the given object in motion increases at equal rate.

At constant velocity, the initial velocity is equal to the final velocity.

v₁ = v₂

The acceleration of the object at constant velocity is zero, because the change in velocity with time will be zero.

[tex]a = \frac{\Delta v}{\Delta t} \\\\a = \frac{v_2- v_1}{t} \\\\v_2 = v_1\\\\a = \frac{v_1 - v_1}{t} \\\\a = 0[/tex]

Thus, from the given options we can conclude that option C with uniform displacement at each time interval represents the photograph of light as the cart moves with constant velocity.

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Answer:

Acceleration  is measured in meters per second squared (m/s²) change in velocity is measured in meters per second (m/s) time taken

Answer:

Blue

Explanation:

Did the question already

The acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].

We know that acceleration is the change in velocity divided by the change in time. In this case, the bicycle is accelerating from rest to a velocity of 6 m/s. The change in time is the time it takes the bicycle to travel 50 m.

We can use the following equation to find the acceleration:

a = (v2 - v1) / t

where:

a is the acceleration

v2 is the final velocity (6 m/s)

v1 is the initial velocity (0 m/s)

t is the time

Plugging in the values from the problem, we get:

a = (6 m/s - 0 m/s) / 50 s

= 0.12 m/[tex]s^{2}[/tex].

Therefore, the acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].

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The distance indicator can be used to measure the most distant objects among all indicators stated above is Type Ia supernovae

In the field of Astronomy, there are different kind of distance indicators that can be used to measure the distance objects.

Few among them are :

Cepheid variables can be measured up to 18 million light years.

The expansion rate of the universe can also be measured by trying to measure the apparent brightness of the Type Ia supernovae

Parallax means illusory state of an object when viewed from different points

Main sequence fitting makes use of a H-R diagram of the cluster to determine the distance to a stellar cluster.

The distance indicator can be used to measure the most distant objects among all indicators stated above is Type Ia supernovae

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Answer:

The length of time between each transit is the planet's "orbital period", or the length of a year on that particular planet. Not all planets have years as long as a year on the Earth! Some planets discovered by Kepler orbit around their stars so quickly that their years only last about four hours!

I hope it helps.

Answer:

Explanation:

Hi there!

Recall that:

Change in momentum = mass × change in velocity

Or:

Δp = mΔv = m(vf - vi)

Plug in the given values. We can assign east to be positive and west to be negative in this instance (Velocity is a vector with direction).

Thus:

Δp = (1)(-21 - 10) = -31 kgm/s OR 31 kgm/s WEST.

The correct answer is B.

Change in momentum is EQUIVALENT to the quantity of IMPULSE.

The correct answer is H.

Answer:

23: Acceleration 24:1m/s^2

Explanation:

[tex]a = (v_f - v_i) /delta(t)\\a=(16-10)/6\\a=6/6\\a=1m/s^2[/tex]