Answer:
A volcanic "hotspot" is an area in the mantle from which heat rises as a thermal plume from deep in the Earth. High heat and lower pressure at the base of the lithosphere (tectonic plate) facilitates melting of the rock. This melt, called magma, rises through cracks and erupts to form volcanoes.
A 5 kg ball is thrown at 4 m/s. What is the ball’s momentum
Answer:
20kgm/s
Explanation:
p=mv
p=5*4
p=20kgm/s
A solid cylinder has a mass of 5 kg and radius of 2 m and is fixed so that it is able to rotate freely around its center without friction. A 0.02 kg bullet is moving from right to left with an angular momentum of 9 kgm2s just before it strikes the cylinder near its bottom and gets stuck at the outer radius. What is the angular velocity (magnitude and direction) of the cylinder bullet system after the impact
Answer:
0.893 rad/s in the clockwise direction
Explanation:
From the law of conservation of angular momentum,
angular momentum before impact = angular momentum after impact
L₁ = L₂
L₁ = angular momentum of bullet = + 9 kgm²/s (it is positive since the bullet tends to rotate in a clockwise direction from left to right)
L₂ = angular momentum of cylinder and angular momentum of bullet after collision.
L₂ = (I₁ + I₂)ω where I₁ = rotational inertia of cylinder = 1/2MR² where M = mass of cylinder = 5 kg and R = radius of cylinder = 2 m, I₂ = rotational inertia of bullet about axis of cylinder after collision = mR² where m = mass of bullet = 0.02 kg and R = radius of cylinder = 2m and ω = angular velocity of system after collision
So,
L₁ = L₂
L₁ = (I₁ + I₂)ω
ω = L₁/(I₁ + I₂)
ω = L₁/(1/2MR² + mR²)
ω = L₁/(1/2M + m)R²
substituting the values of the variables into the equation, we have
ω = L₁/(1/2M + m)R²
ω = + 9 kgm²/s/(1/2 × 5 kg + 0.02 kg)(2 m)²
ω = + 9 kgm²/s/(2.5 kg + 0.02 kg)(4 m²)
ω = + 9 kgm²/s/(2.52 kg)(4 m²)
ω = +9 kgm²/s/10.08 kgm²
ω = + 0.893 rad/s
The angular velocity of the cylinder bullet system is 0.893 rad/s in the clockwise direction-since it is positive.
What is the strength of an electric field 0.2 m from a 1.56 x 10-6 C charge?
Answer:
Solution given:
strength of electric field [E]:?
distance[d]:0.2m
charge[Q]=[tex]1.56×10^{-6} C[/tex]
we have
E =K [tex] \frac{Q}{r²}[/tex]
E=[tex]9×10^{9} C[/tex][tex] \frac{1.56×10^-6 C}{0.2²} [/tex]
E=[tex] 3.51×10^{5}[/tex]V/m
strength of electric field : [tex] 3.51×10^{5}[/tex]V/m
which clock do scientists use to measure time why
Scientists use Atomic clock to measure time
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Solutions, Solubility, Acids/Bases 20-2121 of 35
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Question 32 of 35
The models above show particle arrangement. Read each statement below.
image
1. The substances must undergo a chemical change to transform into a different model
2. The substance in diagram A has the highest energy
3. The substances in diagrams B and C would flow.
4. The substance in diagram C has the lowest temperature.
Which statement above is true?
A.
1
B.
3
C.
4
D.
2
Answer:
hard2
Explanation:
A rookie quarter back throws a football with an initial upward velocity component of 12.0 m/s and a horizontal velocity component of 20.0 m/s. Ignore resistance. How much time is required for the football to reach the highest point of the trajectory
Answer:
t = 1.22 s
Explanation:
Given that,
The initial upward velocity component of a football = 12 m/s
The horizontal velocity component is 20 m/s
We need to find the time required for the football to reach the highest point of the trajectory. Let the time is t.
Using first equation of motion to solve it such that,
[tex]v=u+at[/tex]
u is initial velocity
v is final velocity
a = -g
so,
[tex]t=\dfrac{u}{g}\\\\t=\dfrac{12}{9.8}\\\\t=1.22\ s[/tex]
So, the required time taken by the football to reach the highest point is 1.22 seconds.
(GIVE ME THE ANSWER OR YOU'LL GET REPORTED) Can someone answer this for me with the steps tysm
Answer:
Direction: north-west (45 degrees)
Magnitude: 500 N
Explanation:
The wind exerts a force upwards, a.k.a. north.
The water exerts a force to the left, or west.
The directions are 90 degrees apart from each other, so the angle of the je force is 45 degrees (north-west).
We can use the Pythagorean theorem to calculate the magnitude.
[tex]a^2+b^2=c^2\\400^2+300^2=250000^2\\\sqrt{250000} = 500N[/tex]
La distancia por carretera de Chitré a Parita es de 12 km; exprese en pies ésta distanciaLa distancia por carretera de Chitré a Parita es de 12 km; exprese en pies ésta distancia
Answer:
La distancia por carretera de Chitré a Parita es de 12 km o 39370.08 pies.
Explanation:
La regla de tres es una forma de resolver problemas de proporcionalidad entre tres valores conocidos y un valor desconocido, estableciendo una relación de proporcionalidad entre todos ellos.
Si la relación entre las magnitudes es directa, es decir, cuando una magnitud aumenta, también lo hace la otra (o cuando una magnitud disminuye, también lo hace la otra), se debe aplicar la regla directa de tres. Para resolver una regla directa de tres, se debe seguir la siguiente fórmula, siendo a, b y c los valores conocidos y x el valor a determinar:
a ⇒ b
c ⇒ x
Entonces [tex]x=\frac{c*b}{a}[/tex]
La regla directa de tres es la regla que se aplica en este caso donde hay un cambio de unidades. Para realizar esta conversión de unidades, primero debes saber que 1 km = 3280,84 pies. Entonces, si 1 km son 3280,84 pies, ¿cuántos pies son 12 km?
1 km ⇒ 3280.84 pies
12 km ⇒ x
[tex]x=\frac{12 km*3280.84 pies}{1 km}[/tex]
x= 39370.08 pies
La distancia por carretera de Chitré a Parita es de 12 km o 39370.08 pies.
Fish are hung on a spring scale to determine their mass (most fishermen feel no obligation to truthfully report the mass). What is the force constant of the spring in such a scale if it the spring stretches 8.50 cm for a 8.1 kg load
Answer:
k = 933.88 N/m
Explanation:
Given that,
The mass of a load, m = 8.1 kg
The displacement in the spring, x = 8.5 cm
We need to find the force constant of the spring. We know that Hooke's law is given by :
F = -kx
Also,
F = mg (Force due to its weight)
So,
[tex]k=\dfrac{mg}{x}\\\\k=\dfrac{8.1\times 9.8}{0.085}\\\\k=933.88\ N/m[/tex]
So, the force constant of the spring is equal to 933.88 N/m.
Two charges, each q, are separated by a distance r, and exert mutual attractive forces of F on each other. If both charges become 2q and the distance becomes 3r, what are the new mutual forces
Answer:
F = ⅔ F₀
Explanation:
For this exercise we use Coulomb's law
F = k q₁q₂ / r²
let's use the subscript "o" for the initial conditions
F₀ = k q² / r²
now the charge changes q₁ = q₂ = 2q and the new distance is r = 3 r
we substitute
F = k 4q² / 9 r²
F = k q² r² 4/9
F = ⅔ F₀
Parallel Circuits:
A) are rarely used in the wiring in homes
B) always need more voltage than series circuits
C) will have positive charges flowing in one branch, negative charges in the other
D) provide more than one path fo current flow
Answer:
D.)
Explanation:
the current separates on each branch according to the resistance it experience.
Answer:D
Explanation:
How do you find a wavelength?
A student said,Today, giraffes have long necks that allow them to eat leaves high in trees. They got longer necks by stretching up for even higher leaves. After many generations, the giraffe’s neck was really long.Do you think the student’s explanation for how the giraffe’s neck became long is correct? Explain.
Answer:
yes because there is also a theory about this I studied in biology
theory name -Lamarck's theory
Two astronauts push off each other in space. The 90 kg astronaut ends up with a speed of 5 ms. What is the mass of the other astronaut it he ended up with
a speed of 7 m/s?
Answer:
jsjshs
Explanation:
nsnajsajsnzbzbzbaba
Steph uses 18 Newtons of force to push a piano up a ramp. She uses a total of 900 Joules getting this piano into the moving truck. Calculate the
distance of the ramp.
[tex]\huge{ \mathcal{ \underline{ Answer }: }}[/tex]
[tex] \boxed{ \mathrm{Work done = Force × displacement}}[/tex]
[tex]900 = 18 \times d[/tex][tex]d = \dfrac{900}{18} [/tex][tex]d = 50[/tex]Therefore the distance covered :
[tex] \large \boxed{50 \: m}[/tex]
_____________________________
[tex]\mathrm{ ☠ \: TeeNForeveR \:☠ }[/tex]
Transformar las siguientes unidades al Sistema Internacional: 30 km/h ; 37 Dm ; 750 g ; 4x10-6 km2 ; 7500 cm ; 600000 cm2 ; 520700000 mm3 ; 3,4 años.
Answer:
a) 3.0 10⁴ m / s, b) 3.7 10¹ m, c) 0.750 kg, d) 4 10¹² m², e) 75 m, f) 60 m²
g) 5.207 10³ m², e) 4.847 10⁷ s
Explanation:
The international system (SI) of measurements has as fundamental units the meter for length, the second for time and kilogram for mass.
Let's reduce the different magnitudes to the SI system
a) 30 km / h (1000m / 1 km) (1 h / 3600 s) = 3.0 10⁴ m / s
b) 37 Dm (10 m / 1 Dm) = 3.7 10¹ m
c) 750 g (1 kg / 10,000 g) = 0.750 kg
d) 4 10⁶ km² (1000 m / 1km) ² = 4 10¹² m²
e) 7500 cm (1 m / 100 cm) = 75 m
f) 600000 cm² (1m / 10² cm) ² = 60 m²
g) 520700000 mm³ (1 m / 10³ mm) ³ = 5.20700000 109/10 ^ 6
= 5.207 10³ m²
e) 3.4 years (l65 days / 1 yr) (24 h / 1 day) (3600 s / 1h) = 4.847 10⁷ s
The equation provided (from the textbook) first defines the elastic potential energy of a spring as ΔUsp = −(WB + WW), where WB is work the spring does on an attached block and WW is work the spring does on the wall to which it is attached. But WW is ignored in the next step. Why?
Answer:
The given potential energy of the spring is expressed as follows;
ΔUsp = -(WB + WW)
Where;
WB = Th work done by the spring on the block to which it is attached
WW = The work done by the spring on the wall
We recall that work done, W = Force applied × Distance moved in the direction of the force
The work done by the spring on the block, WB = The spring force × The distance the block moves
The work done by the spring on the wall, WW = The spring force × The distance the wall moves
However, given that the wall does not move, we have;
The distance the wall moves = 0
∴ The work done by the spring on the wall, WW = The spring force × 0 = 0 J
Therefore, WW = 0 J, and the spring does not do work on the wall, and WW can be ignored in the next subsequent) steps
Explanation:
Jenna flips a 10p coin four times. Here are her results:
Trial
Result
1. heads
2. tails
3. heads
4. heads
How can Jenna best improve the reliability of her results?
A
flip the 10p coin one more time
B
flip the 10p coin six more times
C
use a 50p coin instead of a 10p coin
D
use a different 10p coin for each of the four trials
Answer:
Option B
Explanation:
The reliability of an experiment can be increased by conducting experiment sufficient number of times keeping other things constant. Hence, the 10 p coin needs to be flipped again to measure reliability for more than one times.
Hence, option B is correct
Define emf of a battery?
Answer:
Electromotive force or EMF is equal to the terminal potential difference when no current flows. EMF (ϵ) is the amount of energy (E) provided by the battery to each coulomb of charge (Q) passing through.
Give your answer to 2 dp
When taking off a plane accelerates at 2.7m/s2 down the runway. It accelerates from a stationary position for 25 seconds before leaving the ground. What
is the planes speed when it leaves the ground?
Answer:
67.5
Explanation:
The plane accelerates at 2.7m/s,^2
Time is 25 seconds
The velocity can be calculated as follows
= 25×2.7
= 67.5
Hence the speed f the plane is 67.5
A ball is dropped from rest out of a high window in a tall building for 5 seconds. Assuming the we ignore air resistance and assume upwards to be positive. A) What will be the final velocity of the ball B) What is the height of the building if it hits the ground after those 5 seconds. *
Answer:
I am not sure if this is the answer
(B) what is the height of the building if it hits the ground after those 5 seconds.
The energy principle states that:
Energy can be destroyed.
Energy can be created.
Energy cannot be created or destroyed.
Energy cannot be created, but it can be destroyed.
brainleist to correct answer
The energy principle states that:
[tex]\sf\purple{Energy \:cannot \:be \:created \:or\: destroyed.✅}[/tex]
Law of conservation of energy or the first law of thermodynamics states that energy can neither be created nor destroyed; it can only be transferred or changed from one form to another.[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}[/tex]
Help fast please physics
Answer:
10
Explanation:
a rocket with an initial velocity of 20 m/s fires another engine that gives it an acceleration of 4 m/s2 over 10 seconds. How far did the rocket travel during this time?
Answer: 400 m
Explanation:
Vf= 20 + (4*10)
Vf= 60 [m/s]
x= (60^2 - 20^2) / (2*4)
x= 400 m
Determine the applied force required to accelerate a 2.25 kg object rightward with a
constant acceleration of 1.50 m/s2 if the force of friction opposing the motion is 18.2 N.
(Neglect air resistance.)
Answer:
Explanation:
Im going to be using the rules for significant digits properly so I hope you're quite familiar with them. The equation we need for this is
F - f = ma where F is the applied force (our unknown), f is the frictional force, m is the mass, and a is the acceleration. Filling in:
F - 18.2 = 2.25(1.50) and
F = 2.25(1.50) + 18.2 Do the multiplication first and round to get
F = 3.38 + 18.2 The addition rules tell us that we will be rounding to the tenths place after we add to get
F = 21.6 N
How would you calculate the number of moles of oxygen you had?
Answer:
Explanation:
1 mole of gas contains 6.02x10^23 molecules. That is the Avogadro's number. To find the number of moles, you divide the number of molecules by the Avogadro's number.
The correct answer is C.
Answer:
Explanation:
ans is C. divided by Avogadro no.
The distance between two successive crests of a certain transverse wave is 1.40 m. Eight crests (7 waves) pass a given point along the direction of travel every 15.0 s. How fast are the waves traveling
Answer:
the speed of the wave is 0.65 m/s
Explanation:
Given;
distance between two successive crests, λ = 1.4 m
number of crests, n = 8
number of waves formed = 7
The total distance covered by the wave, d= 7λ = 7 x 1.4 = 9.8 m
time of motion of the wave, t = 15 s
The speed of the wave is calculated as;
V = d/t
V = 9.8 / 15
V = 0.65 m/s
Therefore, the speed of the wave is 0.65 m/s
A circuit has a current of 3 amps and is using a 9 volt battery. The circuit has a resistance of ____
ohms.
Answer:
so 9/3=3 current is 3 amperes
Explanation:
The fomula to calculate resistance is:
voltage/cutrent
9 V/3 A= 3 ohms
A vector points -43.0 units
along the x-axis, and 11.1 units
along the y-axis.
Find the direction of the vector.
Answer:
Explanation:
To find the direction of this vector we need o find the angle that has a tangent of the y-component over the x-component:
[tex]tan^{-1}(\frac{11.1}{-43.0})=-14.5[/tex] but since we are in Q2 we have to add 180 degrees to that angle giving us 165.5 degrees
A train accelerates from 30 km/h to 45 km/h in 15.0 second. Find its acceleration and the distance it travels during this time
Answer:
a. Acceleration, a = 0.28 m/s²
b. Distance, S = 156 meters
Explanation:
Given the following data;
Initial velocity = 30 km/h
Final velocity = 45 km/h
Time = 15 seconds
a. To find the acceleration;
Conversion:
30 km/h to m/s = 30*1000/3600 = 8.33 m/s
45 km/h to m/s = 45*1000/3600 = 12.5 m/s
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]
Substituting into the equation;
[tex]a = \frac{12.5 - 8.3}{15}[/tex]
[tex]a = \frac{4.2}{15}[/tex]
Acceleration, a = 0.28 m/s²
b. To find the distance travelled, we would use the second equation of motion given by the formula;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Where;
S represents the displacement or height measured in meters.
u represents the initial velocity measured in meters per seconds.
t represents the time measured in seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
[tex] S = 8.3*15 + \frac {1}{2}*(0.28)*15^{2}[/tex]
[tex] S = 124.5 + 0.14*225[/tex]
[tex] S = 124.5 + 31.5 [/tex]
S = 156 meters