What average net force is required to stop a 1950 kg car in 10.5 s if it’s initially traveling at 28m/s

Answers

Answer 1

Answer:

An average net force of 5200 N is needed to stop the car

Explanation:

Cinematics and Dynamics

Cinematics describes the variables involved in the movement without dealing with its causes. There are four main concepts in cinematics: Velocity (or its scalar equivalent, the speed), acceleration, time, and displacement (or the scalar equivalent, distance).

The acceleration can be calculated by:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

The initial speed is vo=28 m/s, it stops (vf=0) in t=10.5 seconds, thus the acceleration is:

[tex]\displaystyle a=\frac{0-28}{10.5}[/tex]

[tex]a = -2.67~m/s^2[/tex]

The acceleration is negative because the car loses speed.

Knowing the mass of the car m=1950 Kg, we can calculate the net force required to stop the car by using the formula:

F = m.a =1950*2.67

F = 5200 N

An average net force of 5200 N is needed to stop the car


Related Questions

Where are alkaline earth metals found on the periodic table?

Group 1
Group 2
Groups 3–12
Group 17

Answers

Answer:

B

Explanation:

Answer:

B

Explanation:

I had a feeling

What wavelength would a ripple in water have if the frequency is 1.8 Hz and a
wave speed of 825 m/s?

Answers

Explanation:

825m/s / 1.8Hz = 458.33m

λ=v/f

λ-wavelength

v-speed

f-frequency

λ=825/1.8=458.33m

when it comes to graphs I am no genius lol​

Answers

Answer:

Option B

Explanation:

Displacement  = Area under the velocity-time graph

So to find the displacement of a particle from 7 to 8 seconds we take the triangle and calculate its area.

[tex]Area\ of\ a\ right\ angled\ triangle = \frac{1}{2}*(base)*(height) \\\\Area\ of\ a\ right\ angled\ triangle = \frac{1}{2}*(1)*(3) \\\\Area\ of\ a\ right\ angled\ triangle = 1.5[/tex]

So the displacement is 1.5 meters

I have an uploaded image so you can understand it better hope it helps

Integrated science please help ASAP!...

Answers

1: sewage
2: agriculture pollution
3: oil pollution
4: radioactive substances
5: river dumping
6: marine dumping
This is all I can find I hope this helps.

Answer:

SewageAgricultural pollutionOilRadioactive substanceRiver dumpingMarine dumpingLittering trash Industrial wasteMining activitiesChemical fertilizers

Explanation:

I hope this helps

5. Describe the relationship between the buoyant force and the weight of an object if the object:
a) is floating
b) is sinking
c) is rising up through the water.​

Answers

A) the state of deep mental and physical therapy or relaxation

B) falling or moving to a lower level

C) up to owns kness

What is the work energy transfer equation?

Answers

Answer:

The equation used to calculate the work done is: work done = force × distance. W = F × d. This is when: work done (W) is measured in joules (J)

Answer:

The equation used to calculate the work done is: work done = force × distance. W = F × d. This is when: work done (W) is measured in joules (J)

Explanation:

The net work done on a particle equals the change in the particle's kinetic energy:

A car of mass 1000 kg travelling at a velocity of 25 m/s collides with another car of mass 1500kg which is at rest. The two cars stick and move off together. What is the velocity of the two cars after the collision?​

Answers

Answer:

The velocity of the two cars is 10 m/s after the collision.

Explanation:

Law Of Conservation Of Linear Momentum

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=m.v

If we have a system of bodies, then the total momentum is the sum of them all

[tex]P=m_1v_1+m_2v_2+...+m_nv_n[/tex]

If some collision occurs, the velocities change to v' and the final momentum is:

[tex]P'=m_1v'_1+m_2v'_2+...+m_nv'_n[/tex]

In a system of two masses, the law of conservation of linear momentum  takes the form:

[tex]m_1v_1+m_2v_2=m_1v'_1+m_2v'_2[/tex]

If both masses stick together after the collision at a common speed v', then:

[tex]m_1v_1+m_2v_2=(m_1+m_2)v'[/tex]

The car of mass m1=1000 Kg travels at v1=25 m/s and collides with another car of m2=1500 Kg which is at rest (v2=0).

Knowing both cars stick and move together after the collision, their velocity is found solving for v':

[tex]\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}[/tex]

[tex]\displaystyle v'=\frac{1000*25+1500*0}{1000+1500}[/tex]

[tex]\displaystyle v'=\frac{25000}{2500}[/tex]

v' = 10 m/s

The velocity of the two cars is 10 m/s after the collision.

Please find attached photograph for your answer.

HELP ASAP Which statement is true about magnetic field lines?
A. There is no consistent pattern in the lines, B. The lines form a loop from the north pole back to the north pole and from the south pole to the south pole. C. The lines point away from the south pole of a magnet and toward the north pole. D. The lines point away from the north pole of a magnet and toward the south pole.​

Answers

Answer:

i think it's c

Explanation:

but I'm not sure

Answer:

The answer is D

Explanation:

Engine 1 produces twice the power of engine 2.
If it takes engine 1 the time T to do the work W, how long does it take engine 2 to do the same work?
Express your answer in terms of some of all of the variables T and W.
T2=________________

Answers

Answer:

[tex]T_2=\frac{T}{2}[/tex]

Explanation:

Given that engine 1 produces twice the power of engine 2.

Let [tex]P_1[/tex] and [tex]P_2[/tex] be the power of engine 1 and engine2.

So, the power of the engine 2,

[tex]P_2 = 2P_1\cdots(i)[/tex]

As, Work = Power x time,

So, the work, W, done by an engine 1:

[tex]W=P_1\timesT\cdots(ii)[/tex]

The work, W, done by an engine 2:

[tex]W_2=P_2\times T_2\cdots(iii)[/tex]

If the work done by both the engines are the same, then

[tex]W_2=W[/tex]

[tex]\Rightarrow P_2\times T_2=P_1\timesT[/tex] [from (ii) nd (iii)]

[tex]\Rightarrow 2P_1\times T_2=P_1\timesT[/tex] [by using (i)]

[tex]\Rightarrow 2 T_2=T \\\\\Rightarrow T_2=\frac{T}{2}[/tex]

Hence, [tex]T_2=\frac{T}{2}.[/tex]

The time taken for engine 2 to do the same amount of work is given by:

T₂ = 2T

Let the power of the 1st engine be P₁

Let the power of the 2nd engine be P₂

Power = Work / time

From the question given above,

Engine 1 produces twice the power of engine 2.

Thus,

P₁ = 2P₂

P₂ = ½P₁

Next, we shall determine the power used by engine 1 to do the work in time T.

Work = W

Time (T₁) = T

Power (P₁) =?

Power = Work / time

[tex]P_{1} = \frac{W}{T}\\\\[/tex]

Finally, we shall determine the time taken for engine 2 to do the same work.

Work = W

Power of engine 1 (P₁) = [tex]\frac{W}{T}\\\\[/tex]

Power of engine 2 (P₂) = ½P₁

Power of engine 2 (P₂) = [tex]\frac{1}{2} (\frac{W}{T}) = \frac{W}{2T}[/tex]

Time (T₂) =?

[tex]Power = \frac{Work}{time} \\\\ P_{2} = \frac{W}{T_{2}} \\\\\frac{W}{2T} = \frac{W}{T_{2}} \\\\\frac{1}{2T} = \frac{1}{T_{2}}\\\\[/tex]

Invert

T₂ = 2T

Therefore, the time taken for engine 2 to do the same amount of work is: T₂ = 2T

Learn more: https://brainly.com/question/21822614

An object in motion will remain in motion and an object at rest will remain at rest until a greater force interrupts it. Explain this concept.

Answers

Answer:

A object, lets say a cup. This cup will never, ever move unless something or someone disturbs it. If something touches or hits this cup the cup will move. But, until the cup gets touched, nothing will EVER make it move.

Explanation:

I hope this helps!!

A girl pushes a wagon at constant velocity. If the
momentum of the wagon is 50 kg*m/s at a
velocity of 2 m/s, the mass of the wagon is what

Answers

Answer; 100 m/s
Explanation;
F= ma
50 kg x 2 m/s

which one?? please someone quick!​

Answers

Answer:

i think its second law of motion.

Explanation:

Answer:

it’s the second law

Explanation:

I need a little help with this

Answers

Answer:

truck 1 has the most velocity

Explanation:

Because it weights less which means it faster and yea

If a lever has a mechanical advantage of 5 and 50 N of force is used to lift a rock, what is the weight of the rock?

Answers

Green green tea hot green tea green orange

deducing the acceleration = deduce the gradient of velocity-time graphs
true or false?

Answers

Answer:

True

Explanation:

Understanding the relationship between change in velocity with time will explain to you how the object is accelerating or decelerating. This means acceleration is a ratio calculated from the change in velocity of an object and change in time. In a velocity time graph, the y-axis represents the velocity and the x-axis represents the time.

The slope of the graph m = Δ y-axis values/Δ x-axis values

m= Δvelocity / Δ time

m= Δ v / Δ t ------this the definition of acceleration so;

a= Δ v / Δ t

Conclusion : The slope/gradient of a velocity -time graph is acceleration.

A substance will take on the shape of an open container if it is a

liquid.
plasma.
gas.
solid.

Answers

The answer would be liquid if it is just requiring one answer

Answer:

liquid

Explanation:

Bob can run the 100 meter dash in 25 seconds. What is his speed?

Answers

Answer:

4 meters a second

Explanation:

100/25

plzz mark brainiest

4m/s.

Speed = distance/time
=100/25
=4
Speed = 4m/s

A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s in a direction 5° north of east for an hour.

Answers

Answer:

first one 31

second one 23

Explanation:

on edge ;))

Nore ordered an ice cream cone.

Answers

Answer:

okay

Explanation:

okay

Answer:

Cool

Explanation:

a motorbike can travel 1000 meters in 10 minutes calculate how car it can travel in 1 sec. ​

Answers

Answer:

1.67meter

Explanation:

if it can travel 1000 meters in 10 minutes, 10 minutes are 600 secs (10×60), 1000÷600 is 1.67

Answer:

HI

Explanation:

A stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potential energy with respect to the ground is equal to its kinetic energy

Answers

Answer:

A

Explanation:

Given that a stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potential energy with respect to the ground is equal to its kinetic energy. (use 9 - 10 m/s)

O at the moment of impact

2 seconds after the stone is released after the stone has fallen 40 m

when the stone is moving at 20 m/s

At the top of the hill, the P.E = mgh

P.E = 10 × 80 × m

P.E = 800m

At the moment of impact, K.E = 1/2mv^2

K.E = 1/2 × 40^2 × m

K.E = 1/2 × 1600 × m

K.E = 800m

Since both P.E and K.E are the same, we can therefore conclude that the stone's potential energy with respect to the ground is equal to its kinetic energy at the moment of impact.

The correct answer is option A.

the velocity of a body of mass 60kg reaches 15m/s from 0m/s in 12 second. calculate the kinetic energy and power of the body.​

Answers

Answer:

KE=1/2m v^2

1/2*60*15*15

30*15*15

6750 joules

power=work/time

A rose plant inherited two alleles for white flower petals.

Which conclusion is best supported by the given information?

Answers

Answer:

a

Explanation:

Answer:

A or each parent had at least one allele for white pedals

Explanation:

What distance does a biker travel if he rides at a constant speed or 22 m/s for 45 seconds?

Answers

Answer:

it would be 990 m.

Explanation:

22 m/s x 45 seconds.

What connects the colon to the anus?AColon B Anus C Rectum D Biceps​

Answers

The answer is C. Rectum.

Answer:

You have a severe case.

Explanation:

My anus smells foul, like poop or diarrhea. Why? Like your anus might be tired of making the same old sensational brown. No fear needed! Anus Maker is here! With this app, you can post poop photos for help if you need! No more foul sensational browns! Start your free Anus Maker trial today!

Consider an elevator carrying Kermit the frog weighing 4000.0 N is held 5.00 m above a spring with a force constant of 8000.0 N/m. The elevator falls onto the spring while subject to a frictional force (brake) of 1000.0 N. Determine the maximum compression distance, x, of the spring.

Answers

Answer:

Maximum compression distance (x) = 2.236 m (Approx)

Explanation:

Given:

Weight of frog = 4,000 N

Height = 5 m

Constant force = 8,000 N/m

Frictional force = 1,000 N

Find:

Maximum compression distance (x)

Computation:

Using Law of conservation;

mgh = 1/2(k)(x)²

4,000(5) = 1/2(8,000)(x)²

Maximum compression distance (x) = 2.236 m (Approx)

Charles, the 75 kg trampoline artist, lands on a trampoline with a speed of 9.0 m/s.
If the trampoline behaves like a spring with a spring constant of 52,000 N/m, what maximum distance will Charles push down the trampoline before bouncing back up? (Hint: at maximum compression, Charles is not moving.)

Answers

Answer:

The maximum distance Charles will push down the trampoline ≈ 0.342 m

Explanation:

The given parameters are;

The mass of the trampoline artist, m = 75 kg

The speed with which the trampoline artist lands, v = 9.0 m/s

The value of the spring constant of the trampoline, k = 52,000 N/m

Let x represents the maximum distance Charles will push down the trampoline

Therefore, we have;

Kinetic energy = 1/2·m·v²

The kinetic energy with which the trampoline artist lands  = 1/2 × 75 × 9.0² = 3037.5

The kinetic energy with which the trampoline artist lands  =  3037.5 J

The potential energy stored in a spring = 1/2·k·x² = The kinetic energy with which the trampoline artist lands

∴ 1/2 × 52,000 × x² = 3037.5

∴ x = √(3037.5/(1/2 × 52,000)) ≈ 0.342

The maximum distance Charles will push down the trampoline = x ≈ 0.342 m

why is thouching the live wire of an appliane when it is connecfed to the mains dangerous

Answers

Answer: The live wire is the most dangerous one, since it is at 230 V. it should never touch the earth wire (unless the insulation is between them, of course!), because this would make a complete circuit from your mains supply to the ground (earth). A shock or fire would be highly likely.

Explanation:

A red 120 kg bumper car moving at 4 m/s collides with a green 100 kg bumper car moving at 3 m/s. The red bumper car bounces off at 2 m/s. What is the green car's final velocity?​

Answers

we can utilize the equation pi=pf (p=momentum). because p=mv, we can sub in the initial masses and velocities as well as the finals in order to form an equation. this results in 120(4)+100(3)=120(2)+100x. this can be simplified to 540=100x, or x=5.4 m/s.

A 2450 kg stunt airplane accelerates from 120 m/s to 162 m/s in 2.10s. If the airplane is putting out an average force of 5.8810x10^4 N during this time, what is the average friction force exerted on the airplane by the air?

Answers

Given :

A 2450 kg stunt airplane accelerates from 120 m/s to 162 m/s in 2.10 s.

If the airplane is putting out an average force of [tex]5.8810\times 10^4 \ N[/tex].

To Find :

The average friction force exerted on the airplane by the air.

Solution :

Acceleration is given by :

[tex]a = \dfrac{162-120}{2.10}\ m/s^2\\\\a = 20 \ m/s^2[/tex]

Now, force equation is given by :

[tex]F - F_{friction} = ma\\\\F_{friction} = F-ma\\\\F_{friction} = 58810 - (2450\times 20 )\\\\F_{friction} = 9810\ N[/tex]

Therefore, frictional force exerted in the airplane by the air is 9810 N.

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