What are the zeros of the quadratic function f(x) = 6x² + 12x – 7?
x = -1
ve
13
6
and x = -1 +
13
V6
X = -1
2
V3
2
and x = -1 +
V3
X = -1
and x = -1 +
+
7
V 6
6
1
x = -1
1
16
and x = -1 +
V6

median=order them and find the middle=6

mean=add them all up and divide by the amount of numbers=(3+6+9+7+4+6+7+0 +7)/9=5.4

range= the difference between the smallest and largest number=9-3=6

mode= the one that appears the most= 7

The median, mean, range and mode will be 6, 5.4, 9 and 7.

The median is the number in the middle when arranged in an ascending order. The numbers will be:

0, 3, 4, 6, 6, 7, 7, 7, 9.

The median is 6.

The range is the difference between the highest and lowest number which is: = 9 - 0 = 9

The mode is the number that appears most which is 7.

The mean will be the average which will be:

= (0 + 3 + 4 + 6 + 6 + 7 + 7 + 7 + 9) / 9.

= 49/9

= 5.4

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Step-by-step explanation:

define define equation we need the value of the radius and

Answer:

  D. The distance from the mean to an inflection point

Step-by-step explanation:

We rarely encounter the actual formula for the normal PDF. It is ...

  [tex]p(x)=\dfrac{1}{\sqrt{2\pi}}e^{-\dfrac{x^2}{2}}[/tex]

In fact, the inflection points are at x = ±1, where the curve changes from being concave downward to concave upward.

So, one standard deviation is the distance from the mean to an inflection point.

Answer:

100%

Step-by-step explanation:

Start with x.

x = x/1

Increase the numerator by 60% to 1.6x.

Decrease the numerator by 20% to 0.8.

The new fraction is

1.6x/0.8

Do the division.

1.6x/0.8 = 2x

The fraction increased from x to 2x. It became double of what it was. From x to 2x, the increase is x. Since x was the original number x is 100%.

The increase is 100%.

Answer:

33%

Step-by-step explanation:

let fraction be x/y

numerator increased by 60%

=x+60%ofx

=8x

denominator increased by 20%

=y+20%of y

so the increased fraction is 4x/3y

let the fraction is increased by a%

then

x/y +a%of (x/y)=4x/3y

or, a%of(x/y)=x/3y

[tex]a\% = \frac{x}{3y} \times \frac{y}{x} [/tex]

therefore a=33

anda%=33%

Answer:

perimeter = 12 miles

area = 6 square miles

Step-by-step explanation:

Since it makes a right triangle, use the Pythagorean Formula.

3^2+4^2=c^2

9+16=c^2

25=c^2

5=c, so the hypotenuse of the right triangle is 5.

Perimeter = 3+4+5 = 12 miles

area = 1/2bh (1/2 base times height)

=1/2x3x4

=6

Area = 6 square miles

Answer:

7/3 or 13/15

Step-by-step explanation:

So you told me that it will be

8/(20/9) -2 11/15 I put parenthesis to make it easier to understand for me

so you must know that a/(b/c)=ac/b si

72/20 -2 11/15 so we work with -2 11/15 which is equal to -30/15 + 11/15 and that will be -19/15 so we have

72/20 - 19/15 we simplify

18/5 - 19/15 so we multiply and divide by 3 in 18/5

54/15 - 19/15 and we add up

35/15 which is equal to

7/3

If this is wrong so we work with -2 11/15 which is equal to -30/15 + 11/15 well it should be so we work with -2 11/15 which is equal to -30/15 - 11/15 and  that equals -41/15 and we get

54/15-41/15

13/15

Answer:

[tex]z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23[/tex]    

The p value would be given by:

[tex]p_v =2*P(z<-2.23)=0.0257[/tex]  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

Step-by-step explanation:

Information given

[tex]\bar X=46.5[/tex] represent the mean

[tex]\sigma=1.1[/tex] represent the population standard deviation

[tex]n=150[/tex] sample size  

[tex]\mu_o =46.7[/tex] represent the value to verify

[tex]\alpha=0.05[/tex] represent the significance level for the hypothesis test.  

z would represent the statistic

[tex]p_v[/tex] represent the p value

Hypothesis to test

We want to test if the true mean for this case is 46.7, the system of hypothesis would be:  

Null hypothesis:[tex]\mu = 46.7[/tex]  

Alternative hypothesis:[tex]\mu \neq 46.7[/tex]  

Since we know the population deviation the statistic is given by:

[tex]z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}[/tex]  (1)  

Replacing we got:

[tex]z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23[/tex]    

The p value would be given by:

[tex]p_v =2*P(z<-2.23)=0.0257[/tex]  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

Answer:

The statistic would be given by:

[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)  

And replacing we got:

[tex]z=\frac{0.65 -0.5}{\sqrt{\frac{0.5(1-0.5)}{421}}}=6.16[/tex]  

Step-by-step explanation:

Information given

n=421 represent the random sample taken

[tex]\hat p=0.65[/tex] estimated proportion of adults  that would erase all of their personal information online if they could

[tex]p_o=0.5[/tex] is the value that we want to test

z would represent the statistic  

Hypothesis to test

We want to check if Most adults would erase all of their personal information online if they could, then the system of hypothesis are :  

Null hypothesis:[tex]p\leq 0.5[/tex]  

Alternative hypothesis:[tex]p > 0.5[/tex]  

The statistic would be given by:

[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)  

And replacing we got:

[tex]z=\frac{0.65 -0.5}{\sqrt{\frac{0.5(1-0.5)}{421}}}=6.16[/tex]  

From the information given, it is found that the value of the test statistic is z = 6.16.

At the null hypothesis, we test if it is not most adults that would erase all of their personal information online if they could, that is, the proportion is of at most 50%, hence:

[tex]H_0: p = 0.5[/tex]

At the alternative hypothesis, we test if most adults would, that is, if the proportion is greater than 50%.

[tex]H_1: p > 0.5[/tex]

The test statistic is given by:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

In which:

In this problem, the parameters are: [tex]p = 0.5, n = 421, \overline{p} = 0.65[/tex].

Hence, the value of the test statistic is:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

[tex]z = \frac{0.65 - 0.5}{\sqrt{\frac{0.5(0.5)}{421}}}[/tex]

[tex]z = 6.16[/tex]

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Answer:

true

Step-by-step explanation:

A prism is a solid with parallelogram sides (usually rectangles) and a polygon for the 2 bases. Any polygon can be the base.

Answer:

Hello!

__________________

Your answer would be (A) True.

Step-by-step explanation: Hope this helped you!

Any polygon can be the base of a prism so the answer is true.

Answer:

x=12.5

Step-by-step explanation:

0.7x times (-1.4)=-3.5

-0.28x=-3.5 (divide both sides)

Ans:12.5

Answer:

19, 16, 20

Step-by-step explanation:

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side.

Aka the highest number - the next highest number = lowest possible number.

3+4 is not greater than 8.

8 + 11 is not greater than 19.

5 + 5 is not greater than 11.

16+19 is greater than 20.

19+20 is greater than 16.

16+ 20 is greater than 19.

the set of numbers that could represent the lengths of the sides of a triangle is D. {19, 16, 20}.

To determine if a set of numbers can represent the lengths of the sides of a triangle, we need to apply the triangle inequality theorem. According to the theorem, for a triangle with side lengths a, b, and c:

a + b > c

a + c > b

b + c > a

Let's evaluate each set of numbers:

A. {3, 4, 8}

3 + 4 > 8 (7 > 8) - Not true

4 + 8 > 3 (12 > 3) - True

3 + 8 > 4 (11 > 4) - True

Since the first inequality is not true, set A cannot represent the lengths of the sides of a triangle.

B. {8, 11, 19}

8 + 11 > 19 (19 > 19) - Not true

8 + 19 > 11 (27 > 11) - True

11 + 19 > 8 (30 > 8) - True

Since the first inequality is not true, set B cannot represent the lengths of the sides of a triangle.

C. {11, 5, 5}

11 + 5 > 5 (16 > 5) - True

11 + 5 > 5 (16 > 5) - True

5 + 5 > 11 (10 > 11) - Not true

Since the third inequality is not true, set C cannot represent the lengths of the sides of a triangle.

D. {19, 16, 20}

19 + 16 > 20 (35 > 20) - True

19 + 20 > 16 (39 > 16) - True

16 + 20 > 19 (36 > 19) - True

All three inequalities are true for set D, so it can represent the lengths of the sides of a triangle.

Therefore, the set of numbers that could represent the lengths of the sides of a triangle is D. {19, 16, 20}.

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Answer:

14000

Step-by-step explanation:

Of means multiply

10% * 140000

Change to decimal form

.10 * 140000

14000

Answer:

[tex]14000[/tex]

Step-by-step explanation:

[tex]10\% \times 140000[/tex]

[tex]\mathrm{Apply} \: a\% = \frac{a}{100}[/tex]

[tex]\frac{10}{100} \times 140000[/tex]

[tex]\mathrm{Apply} \: \frac{a}{100} \times b = \frac{ab}{100}[/tex]

[tex]\frac{1400000}{100}[/tex]

[tex]\mathrm{Simplify.}[/tex]

[tex]\frac{14000}{1} =14000[/tex]

Answer:

20

Step-by-step explanation:

fist you convert 6l to ml=6×1000

then,300/300:6000/300

gives you 1:20

Answer:

Increasing: [tex](0, 750)[/tex]

Decreasing: [tex](750, \infty)[/tex]

Step-by-step explanation:

Critical points:

The critical points of a function f(x) are the values of x for which:

[tex]f'(x) = 0[/tex]

For any value of x, if f'(x) > 0, the function is increasing. Otherwise, if f'(x) < 0, the function is decreasing.

The critical points help us find these intervals.

In this question:

[tex]P(x) = -0.004x^{2} + 6x - 5000[/tex]

So

[tex]P'(x) = -0.008x + 6[/tex]

Critical point:

[tex]P'(x) = 0[/tex]

[tex]-0.008x + 6 = 0[/tex]

[tex]0.008x = 6[/tex]

[tex]x = \frac{6}{0.008}[/tex]

[tex]x = 750[/tex]

We have two intervals:

(0, 750) and [tex](750, \infty)[/tex]

(0, 750)

Will find P'(x) when x = 1

[tex]P'(x) = -0.008x + 6 = -0.008*1 + 6 = 5.992[/tex]

Positive, so increasing.

Interval [tex](750, \infty)[/tex]

Will find P'(x) when x = 800

[tex]P'(x) = -0.008x + 6 = -0.008*800 + 6 = -0.4[/tex]

Negative, then decreasing.

Answer:

Increasing: [tex](0, 750)[/tex]

Decreasing: [tex](750, \infty)[/tex]

Answer:

  all are "yes"

Step-by-step explanation:

A polynomial is defined for all values of x. None are excluded. Every value listed is in the domain of f(x) = (x +1)².

Answer:

Step-by-step explanation:

Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t  ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

[tex]\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}[/tex]

e. Maximum of the function

The maximum of the function is at t= 0.

Max = 73 %

The graph below shows your knowledge decay curve. Knowledge decays rapidly at first but slows as time goes on.

Answer:

D

Step-by-step explanation:

Solution:-

The standard sinusoidal waveform defined over the domain [ 0 , 2π ] is given as:

                                   f ( x ) = sin ( w*x ± k ) ± b

Where,

                 w: The frequency of the cycle

                 k: The phase difference

                 b: The vertical shift of center line from origin

We are given that the function completes 2 cycles over the domain of [ 0 , 2π ]. The number of cycles of a sinusoidal wave is given by the frequency parameter ( w ).

We will plug in w = 2. No information is given regarding the phase difference ( k ) and the position of waveform from the origin. So we can set these parameters to zero. k = b = 0.

The resulting sinusoidal waveform can be expressed as:

                           f ( x ) = sin ( 2x )  ... Answer

Answer:

KU = 8

Step-by-step explanation:

From the diagram

KU + UN = KN , that is

KU + 40 = 48 ( subtract 40 from both sides )

KU = 8

Answer:

KU = 8

Step-by-step explanation:

UN = 40

        KN = 48

KU + UN = 48

 KU + 40 = 48  {Subtract 40 from both sides}

         KU = 48 -40

         KU = 8

Answer:

-2n

Step-by-step explanation:

f(x)=7-2x {1,2}

f(1)=7-2(1)=5

f(2)=7-2(2)=3

Slope (m)=3/5

{7-2(1)}-{7-2(2)}=3-5=-2

In terms of n=-2n

The upper and lower sums for the region bounded by the graph of the function and the x-axis on the given interval is [5, 3]

Given the function of the graph bounded by the inteval [1, 2] expressed as

f(x) = 7 - 2x

The upper limit of the function is the point where the domain of the function x is 2. Substitute x = 2 into the function, we will have:

f(2) = 7 - 2(2)

f(2) = 7 - 4

f(2) = 3

For the lower limit, the domain of the function is at x = 2:

f(1) = 7 - 2(1)

f(1) = 7 - 2

f(1) = 5

Hence the upper and lower sums for the region bounded by the graph of the function and the x-axis on the given interval is [5, 3].

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Explanation:

The graph shows that f(x) has the y intercept at -5. This is where the red line crosses the vertical y axis. More specifically, the y intercept is located at the point (0,-5)

We're told that g(x) has a y intercept at -1. So we must move f(x) 4 units up to go from y = -5 to y = -1. This is because -5+4 = -1.

Do this for every point on f(x) and you'll end up with g(x) = f(x)+4. Recall that y = f(x). So saying f(x)+4 is the same as y+4 to indicate "shift up 4 units".

f(x) and g(x) have the same slope, but different y intercepts. So they are parallel lines that never cross.

Answer:L=30 S=50

Step-by-step explanation:

3.25 x 50 = 162.5

245 - 162.5 = 82.5

82.5 divided by 30 equals 2.75.

Answer:

14

Step-by-step explanation:

3 1/2 × 4

Convert 3 1/2 to an improper fraction.

7/2 × 4

7/2 × 4/1

Multiply.

(7× 4) / (2 × 1)

28 / 2

= 14

Answer: 14

Step-by-step explanation: To multiply a mixed number times a whole number, first write each of them as an improper fraction.

So we can rewrite 3 and 1/2 as the improper fraction 7/2

and we can write 4 as the improper fraction 4/1.

If you've forgotten how to write a mixed number as an improper fraction, feel free to ask me below and I will review this with you.

So now we have 7/2 × 4/1.

When we're multiplying fractions, we want to

cross-cancel first whenever possible.

So here, notice that we can cross-cancel 2 and 4 to 1 and 2.

So we have 7/1 × 2/1.

Now we just multiply across the numerators and multiply across the denominators and we have our answer, 14/1 or just 14.

Answer:

50.24 yd²

Step-by-step explanation:

pi r² = (3.14)(4)² = 50.24

Answer:

7850 feet.sq

Step-by-step explanation:

the area of a cercle is:

A = r²*π     where r is the radius

A= 50²*3.14 = 7850 ft²

Answer:

After reflection, the coordinates would be A(-6,-8)  B(-2,-6)  C(-4,-2) and  D(-8,-4). After translation, the coordinates would be A(0,-8) B(4,-6)  C(2,-2)  and D(-2,-4).  

Step-by-step explanation:

If the figure ABCD consists of 4 points and we want to reflect this across the x-axis, then the y coordinate values of A, B, C and D will be negated. So,

(-6,8) becomes (-6,-8)

(-2,6) becomes (-2,-6)

(-4,2) becomes (-4,-2)

and (-8,4) becomes (-8,-4).

Now that we know what the reflection is, we translate it 6 units to the right. Therefore, the x value of each coordinate is increased by 6.

(-6,-8) becomes (0,-8)

(-2,-6) becomes (4,-6)

(-4,-2) becomes (2,-2)

and (-8,-4) becomes (-2,-4)

Hope this helped!

Rewrite the equations of the given boundary lines:

y = -x + 1  ==>  x + y = 1

y = -x + 4  ==>  x + y = 4

y = 2x + 2  ==>  -2x + y = 2

y = 2x + 5  ==>  -2x + y = 5

This tells us the parallelogram in the x-y plane corresponds to the rectangle in the u-v plane with 1 ≤ u ≤ 4 and 2 ≤ v ≤ 5.

Compute the Jacobian determinant for this change of coordinates:

[tex]J=\begin{bmatrix}\frac{\partial u}{\partial x}&\frac{\partial u}{\partial y}\\\frac{\partial v}{\partial x}&\frac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}1&1\\-2&1\end{bmatrix}\implies|\det J|=3[/tex]

Rewrite the integrand:

[tex]-3x+4y=-3\cdot\dfrac{u-v}3+4\cdot\dfrac{2u+v}3=\dfrac{5u+7v}3[/tex]

The integral is then

[tex]\displaystyle\iint_R(-3x+4y)\,\mathrm dx\,\mathrm dy=3\iint_{R'}\frac{5u+7v}3\,\mathrm du\,\mathrm dv=\int_2^5\int_1^45u+7v\,\mathrm du\,\mathrm dv=\boxed{333}[/tex]

Answer:

21=2w+2w+3    18=4w     w=4.5

Answer:

C and D

Step-by-step explanation:

khan acedemy

An equation is formed when two equal expressions. The solutions to the given equation are A, B, and C.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The solution of the given equation v²=25/81 can be found as shown below.

v²=25/81

Taking the square root of both sides of the equation,

√(v²) = √(25/81)

v = √(25/81)

v = √(5² / 9²)

v = ± 5/9

Hence, the solutions of the given equation are A, B, and C.

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Answer:

a. 0.34885

b. 0.04651

c. 0.02404

d. 36

e. 14.7, say 15 trials

Step-by-step explanation:

Q17070205

Note:  

1. In order to be applicable to established probability distributions, each roll is considered a Bernouilli trial, i.e. has only two outcomes, success or failure, and are all independent of each other.

2. use R to find the probability values from the respective distributions.

a) the chance that the first 6 appears before the tenth roll

This means that a six appears exactly once between the first and the nineth roll.

Using binomial distribution, p=1/6, n=9, x=1

dbinom(1,9,1/6) = 0.34885

b) the chance that the third 6 appears on the tenth roll

This means exactly two six's appear between the first and 9th rolls, and the tenth roll is a six.

Again, we have a binomial distribution of p=1/6, n=9, x=2

p1 = dbinom(2,9,1/6) = 0.27908

The probability of the tenth roll being a 6 is, evidently, p2 = 1/6.

Thus the probability of both happening, by the multiplication rule, assuming independence  

P(third on the tenth roll) = p1*p2 = 0.04651

c) the chance of seeing three 6's among the first ten rolls given that there were six 6's among the first twenty roles.

Again, using binomial distribution, probability of 3-6's in the first 10 rolls,

p1 = dbinom(3,10,1/6) = 0.15504

Probability of 3-6's in the NEXT 10 rolls

p1 = dbinom(3,10,1/6) = 0.15504

Probability of both happening  (multiplication rule, assuming both events are independent)

= p1 *  p1 = 0.02404

d) the expected number of rolls until six 6's appear

Using the negative binomial distribution, the expected number of failures before n=6 successes, with probability p = 1/6

=  n(1-p)/p

Total number of rolls by adding n  

= n(1-p)/p + n = n(1-p+p)/p = n/p = 6/(1/6) = 36

e) the expected number of rolls until all six faces appear

P1 = 6/6 because the firs trial (roll) can be any face with probability 1

P2 = 6/5 because the second trial for a different face has probability 5/6, so requires 6/5 trials

P3 = 6/4 ...

P4 = 6/3

P5 = 6/2

P6 = 6/1

So the total mean (expected) number of trials is 6/6+6/5+6/4+6/3+6/2+6/1 = 14.7, say 15 trials

Answer:

12

Step-by-step explanation:

Let's call the width x and the length x + 3. Using the Pythagorean Theorem we can write:

(x + 3)² + x² = 15²

x² + 6x + 9 + x² = 225

2x² + 6x - 216 = 0

2(x² + 3x - 108) = 0

2(x + 12)(x - 9) = 0

x + 12 = 0 or x - 9 = 0

x = -12 or x = 9

x cannot be -12 because length/width can't be negative so x = 9 which means that the length is 9 + 3 = 12.