What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? quadratic formula: x = startfraction negative b plus or minus startroot b squared minus 4 a c endroot over 2 a endfraction.

Answer:

8

Step-by-step explanation:

Josh is 6 years older than 5 times Kim's age. The sum of their ages is less than 54. What is the oldest Kim could be?

J + k < 54 when  J = 5k + 6 so:

5k + 6  + k < 54

6k + 6 < 54

subtract 6 from both sides:

6k + 6 - 6 < 54 - 6

6k < 48

divide both sides by 6:

6k/6 < 48/6

k < 8

Kim could be 8 at maximum.

When a linear transformation is done to a nonzero vector in linear algebra, the vector is said to have an eigenvector, or characteristic vector, which only changes by a scalar amount. The scaling factor for the eigenvector is the appropriate eigenvalue, frequently represented as lambda.

When a linear transformation is done to a nonzero vector in linear algebra, the vector is said to have an eigenvector, or characteristic vector, which only changes by a scalar amount. The factor by which the eigenvector is scaled is known as the associated eigenvalue, frequently denoted by.

Hence, characteristic polynomial of A and A^T are the same, therefore their eigenvalues are also same.

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The maximum area to enclose a rectangular pasture with one side of the pasture up against a river is equal to 500,000 square feet.

As given in the question,

Let 'x' represents the length of the rectangular pasture

And 'y' represents the width of the rectangular pasture

Condition:

One side of the pasture is up against a river

Perimeter of the rectangular pasture with one side up against river

= x + 2y

⇒ 2000 = x + 2y

⇒x= 2000 - 2y

Area of the rectangular pasture

=( 2000 - 2y )( y )

= - 2 ( y² - 1000y)

= -2( y² - 1000y + 250000 - 250000 )

= -2 (y - 500 )² + 500, 000

Maximum area is at y = 500

Maximum area is 500,000

Therefore, the maximum area of the given rectangular pasture is 500,000 square pasture.

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Answer:

6.48 <= x <= 7.5

Step-by-step explanation:

(5/12)×18=7.5

(10.80/30)×18=6.48

6.48 <= x <= 7.5

The required volume of the triangular prism will be 126 cubic meters.

The triangular prism is the amount of space occupied by an object. It is determined by the number of unit cubes required to completely fill the solid.

V = 1/2 x H x W x L

The volume of the triangular prism will be

Volume of triangular prism = 1/2 x 9 x 6 x 13

Volume of triangular prism = 9 x 3 x 13

Volume of triangular prism = 27 x 13

Volume of triangular prism = 351 cubic yards

Thus, the volume of the triangular prism will be 126 cubic meters.

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The measure of an angle ∠TQU is 26.6° if  PQ=3 and QR=4

In Euclidean geometry, an angle is the figure formed by two rays, known as the sides of the angle, that have a common termination, known as the vertex of the angle. These are referred to as dihedral angles. An angle can also be defined by two intersecting curves, which is the angle of the rays lying tangent to the respective curves at their point of intersection.

Angle can also refer to a rotation or the measurement of an angle. This measurement is the ratio of the length of a circular arc to its radius.

Given,

Rectangle PQRS has PQ=3 and QR=4

The points T and U are on side PS such that PT=US=1

As PQRS is rectangle so opposite sides of rectangle should be equal.

PS=QR and PQ=RS

QR=4, PS=4

But, PS=PT+TU+US

4=1+TU+1

TU=4-2

TU=2

And PU=PT+TU

1+2=3

PU=3

Consider, ΔQPU, Right angled at P.

We know that,

tan Q=PU/PQ

tan Q=3/3

tan Q=1

Q=tan⁻¹

Q=45°

∠PQU=45°

Now, let us consider ΔQPT is right angled at P

tan Q=PT/PQ

tan Q=1/3

Q= tan⁻¹(1/3)

Q=18.43°

∠PQT=18.43°

∠PQU=∠PQT+∠TQU

45°=18.43°+∠TQU

∠TQU=45°-18.43°

∠TQU=26.57°

∠TQU≈26.6°

Therefore, the measure of ∠TQU is 26.6°.

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[tex]\fbox{7x-12}[/tex]

Distributive property:

[tex]x+(3)(2x)+(3)(-4)[/tex]

[tex]x+6x+-12[/tex]

Combine like terms:

[tex](x+6x)+(-12)[/tex]

[tex]7x-12[/tex]

(A.)test statistic for this test using Ha: p8くPN is Z = -2.164 (B.) p-value (3 decimal places) is 0.015. (C.) Based on this p-value, which of the following would you expect for a 95% is negative. (D.) the correct conclusion is The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.

A.)

According to given data find the test statistic for this test using Ha:

p1 = 0.581

p2 = 0.832

standard error = SE = 0.116

Z = [tex]\frac{p1 - p2}{SE}[/tex]

Z = [tex]\frac{0.581 - 0.832}{0.116}[/tex] = -2.164

Z = -2.164

B.)

According to given Determine the p-value (3 decimal places).

it is left tailed test.

p - value for left tailed test is,

p - value = P(Z < test statistics )

p - value = P(Z < -2.164)

P - value = 0.015

C.)

Based on this p-value, which of the following would you expect for a 95%

confidence level = 95% = 0.95

significance level = α = 0.05

P -value is less than 0.05

so, reject null hypothesis at α = 0.05

That is [tex]P_{B}[/tex] < [tex]P_{NY}[/tex]

so, based on P - value , All values in the 95% confidence interval

PB - PNY  is negative.

D.)

According to given data What is the correct conclusion?

Reject null hypothesis at α = 0.05

so, [tex]P_{B}[/tex] < [tex]P_{NY}[/tex]

Hence, The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.

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Answer:

Step-by-step explanation:

Cosine is adjacent over hypotenuse.

So for Angle Z, the adjacent leg is 12 and the hypotenuse leg is 20.

The Cosine ratio is 12/20.

16 is not used and would be the opposite leg to Angle Z

The dunking booth is the shape of a cube represented below (x+3). Therefore, the polynomial of volume of the dunking booth is

                                            (x +3) (x+3)².

Lets talk about the cube prism

- It has cube faces each two opposite faces are congruent

- It has three dimensions.

- Its volume = a³

In our problem the dunking booth is a cube prism with dimensions:  x + 3

Side = x +3

therefore,

V = a³ = ( x +3)³

          = (x)³ + 3× (x)²× 3 + 3× x × (3)² + (3)³

          = x³ + 9x² + 27x + 27

Regrouping ,

          = x³+ 27+ 9x² + 27x

Rewrite 27as 33.

x³+ 3³+9x²+ 27x

Since both terms are perfect cubes, factor using the sum of cubes formula,

a³+b³ = (a + b)(a²- ab+ b²) where a=x and b=3.

(x+3)(x− x⋅3 + 32)+ 9x²+ 27x

Simplify.

     (x+3)(x²− 3x + 9)+ 9x²+ 27x

⇒  (x+3)(x²− 3x + 9)+ 9x(x+3)

Now,

x+3 out of  (x+3)(x²− 3x + 9)+ 9x(x+3) .

⇒ (x+3)(x²− 3x + 9 + 9x)

Add −3x and 9x.

(x+3) (x²+ 6x+ 9)

Rewrite the polynomial.

   (x+3)(x²+ 2⋅x⋅3+ 3²)

Factor using the perfect square trinomial rule a²+2ab+b² = (a + b)² , where a = x and b = 3.

                  (x+3)(x+3)².

Therefore, the polynomial is   (x+3)(x+3)².

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Answer:

Option 3 (Parentheses, division, multiplication, subtraction)

Step-by-step explanation:

Using PEMDAS, we can know that we need to solve the parentheses first. Next, we need to solve the multiplication and division, so we can eliminate the first option and last option. However, we need to solve the operations left to right, meaning we'd solve the division first. Therefore, the answer is option 3.

Answer:

The answer is Parentheses multiplication division subtraction

Step-by-step explanation:

Always remember

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

The number of gallons that can be filled is 18 gallons.

Rate demonstrates how many times one number can fit into another number. It contrast two numbers by ordinarily dividing them. A/B will be the formula if one is comparing one data point (A) to another data point (B).

In this case, the number of hours in 3 days will be:

= 24 × 3

= 72 hours.

Since the leaky faucet is losing water and is filling a 5-gallon bucket every 20 hours. The gallon filled in 72 hours will be represented by x.

5/20 = x/72

Cross multiply

20x = 72 × 5

20x = 360

x = 360/20

x = 18

There'll be 18 gallons

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Answer:

1st blank = 6x

2nd blank = 12

3rd blank = 2

4th blank = 2

5th blank = 8

6th blank = 5

Elastic demand for a good is defined as when the price of a good rises by 10% while the quantity required falls by 20%.

When a product's price changes, consumer demand is said to be elastic. Consumers will purchase significantly more if the price drops just a little. They won't buy as much if prices increase somewhat instead opting to wait for them to level out.

If all other variables remain constant, the ratio of a product's percent change in demand to its percent change in price determines whether a product's demand is elastic or inelastic.

It is neither elastic nor inelastic for an item's price to alter in proportion to its change in demand. In other words, a product has elastic demand if demand fluctuates more than price does.

Hence, Elastic demand for a good is defined as when the price of a good rises by 10% while the quantity required falls by 20%.

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The variables of the test statistic can be concluded as [tex]s_{1} ^{2}[/tex], [tex]s_{2} ^{2}[/tex] as the variance of two samples, [tex]n_{1}[/tex], [tex]n_{2}[/tex] as the respective size of the two samples, [tex]t[/tex] as the t-distribution test statistic, and [tex]x_{1}[/tex], [tex]x_{2}[/tex] as the mean of the two samples.

It is given to us that the test statistic is used for a two sample test of means where the population variances are unknown and unequal.

Pooled standard deviation estimates cannot be used when the two groups have unequal variances. Instead, we have to find out the standard error for each group separately.

The formula for this type of test statistic is given by -

[tex]t=\frac{x_{1} -x_{2} }{\sqrt{\frac{s_{1} ^{2} }{n_{1} } +\frac{s_{2} ^{2} }{n_{2} } } }[/tex] ------- (1)

Here, the variables can be defined as below -

[tex]s_{1} ^{2}[/tex], [tex]s_{2} ^{2}[/tex] = The variance of two samples

[tex]n_{1}[/tex], [tex]n_{2}[/tex] = The respective sizes of the two samples

[tex]t[/tex] = t-distribution test statistic

[tex]x_{1}[/tex], [tex]x_{2}[/tex] = Mean of the two samples

Thus, the variables of the test statistic can be concluded as [tex]s_{1} ^{2}[/tex], [tex]s_{2} ^{2}[/tex] as the variance of two samples, [tex]n_{1}[/tex], [tex]n_{2}[/tex] as the respective size of the two samples, [tex]t[/tex] as the t-distribution test statistic, and [tex]x_{1}[/tex], [tex]x_{2}[/tex] as the mean of the two samples.

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As we can see, the equality is equal for only one value of xx, which was the same as the one we found in part (a).
(a) [tex]x = \frac{L\pi }{4+\pi }[/tex]
(b) True
(c) Yes

What is maximum and minimum?

The smallest value in the data set is the minimum. The largest value in the data set is the maximum.

(a) The circumference of the circle is xx, which means that

[tex]P_ 1= 2\pi r\\x = 2\pi r\\r = \frac{x}{2\pi }[/tex]

The area of the circle is,

[tex]A_c = \pi r^2\\A_c = \frac{x^2}{4\pi }[/tex]

The circumference of the square is L - x, which means

[tex]P_2 = 4a \\L-x=4a\\a = \frac{L-x}{4}[/tex]

The area of the square is,

[tex]A_s = a^2\\A_s=\frac{(L-x)^2}{16}[/tex]

The sum of the areas of the circle and the square is

[tex]A = A_c + A_s\\A = \frac{x^2}{4\pi } +\frac{(L-x)^2}{16} \\A = \frac{4x^2+(L-x)^2\pi \pi }{16\pi } \\A = \frac{4x^2+(L^2 -2Lx+x^2)\pi }{16\pi } \\A = \frac{(4+\pi )x^2-2Lx\pi +L^2\pi }{16\pi }[/tex]

The derivative of the function of the total area is

[tex]A = \frac{4+\pi }{8\pi }x-\frac{L}{8}[/tex]

We solve the equation A'(x) = 0

[tex]\frac{4+\pi }{8\pi }x-\frac{L}{8}=0\\ \frac{4+\pi }{\pi }x=L\\ x = \frac{L\pi }{4+\pi }[/tex]

So, [tex]x = \frac{L\pi }{4+\pi }[/tex] is a critical point A, and it is a global minimum of A since

[tex]A"(x) = \frac{4+\pi }{8\pi } > 0[/tex] for all x.

(b) The area of the circle for [tex]x = \frac{L\pi }{4+\pi }[/tex] is

[tex]A_c = \frac{(\frac{L\pi }{4+\pi } )^2}{4\pi } \\A_c = \frac{(\frac{L^2\pi ^2}{(4+\pi )^2} )}{4\pi } \\A_c= \frac{L^2\pi }{4(4+\pi )^2}[/tex]

The area of the square for [tex]x = \frac{L\pi }{4+\pi }[/tex]  is

[tex]A_s = \frac{(L-\frac{L\pi }{4+\pi } )^2}{16}[/tex]

The ratio of the area is,

[tex]\frac{A_s}{A_c} = \frac{(\frac{(L-\frac{L\pi }{4+\pi })^2 }{16} )}{(\frac{L^2\pi }{4(4+\pi )^2} )}[/tex]

[tex]= \frac{(L - \frac{L\pi }{4+\pi })^2 }{16}*\frac{4(4+\pi )^2}{L^2\pi } \\ = \frac{L^2-\frac{2L^2\pi }{4+\pi }+(\frac{L\pi }{4+\pi } )^2 }{4} *\frac{(4+\pi )^2}{L^2\pi } \\= \frac{(4+\pi)^2 }{4\pi }-\frac{4+\pi }{2}+\frac{\pi }{4}\\ = \frac{4}{\pi }[/tex]

The ratio of the length of wire in the square to the length of wire in the circle for [tex]x = \frac{L\pi }{4+\pi }[/tex]  is

[tex]\frac{L-x}{x} =\frac{L-\frac{L\pi }{4+\pi } }{\frac{L\pi }{4+\pi } } \\= \frac{\frac{4L}{4+\pi } }{\frac{L\pi }{4+\pi } } \\= \frac{4}{\pi }[/tex]

As we can see (1) = (2)

(c) To prove this, we solve the equation

[tex]\frac{A_s}{A_c} = \frac{L-x}{x} \\ \frac{\frac{(L-x)^2}{16} }{\frac{x^2}{4\pi } } = \frac{L-x}{x}\\ \frac{(L-x)^2}{4}*\frac{\pi }{x^2} = \frac{L-x}{x} \\ \frac{L-x}{4} *\frac{\pi }{x} =1\\L\pi -\pi x=4x\\L\pi = (4 + \pi )x\\x = \frac{L\pi }{4+x}[/tex]

As we can see, the equality is equal for only one value of xx, which was the same as the one we found in part (a).

Hence,

(a) [tex]x = \frac{L\pi }{4+\pi }[/tex]

(b) True

(c) Yes

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f(x) = x + 1 is the monic quadratic polynomial used here

Given,

The monic quadratic polynomial f(x)

The remainder when f(x) divided by x - 1 is 2

The remainder when f(x) divided by  x - 3 is 4

We have to find f(x).

Monic Quadratic Polynomial;-

A monic polynomial in algebra is a univariate polynomial with a single variable and a leading coefficient of 1. Its leading coefficient is the highest degree nonzero coefficient.

Here,

The remainder when f(x) divided by x - 1 is 2

Assume f(x) / x - 1 = 1

Then,

f(x) = (x - 1) × 1 + 2

f(x) = x - 1 + 2

f(x) = x + 1

Next,

The remainder when f(x) divided by  x - 3 is 4

Assume f(x) / x - 3 = 1

Then,

f(x) = (x - 3) × 1 + 4

f(x) = x - 3 + 4

f(x) = x + 1

That is,

The monic quadratic polynomial used here is, f(x) = x + 1

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Answer:

2x + 6

Step-by-step explanation:

If the number of months Hassan takes voice lessons is x, and he learns two pieces every month, you would multiply the number of months, x, together with the number of pieces he will learn each month, 2, making 2x.

Hassan already knows how to sing 6 vocal pieces, which you would add to 2x.

That makes 2x + 6.

The Python program prints the value of the integer n from the input string shown. (Refer to the coding below)

An arrangement of Python statements that have been specifically designed to accomplish a task is the simplest definition of a program.

A program is even our straightforward hello.py script.

Although it is only one line long and of limited use, it is a Python program by the strictest definition.

Functions assist in segmenting our program into manageable, modular portions.

Our program becomes more organized and controlled as it gets bigger and bigger.

It also makes the code reusable and prevents repetition.

So, we know that the program is for the given integer n:

Defining the integer variable "N" that accepts a user-supplied integer value.

The user-end string value is input using another variable "W" that is declared in the next step.

A for loop using the range method and an integer variable is declared after all input values have been entered.

This loop prints the string value.

The Python program prints the value of the supplied string.

N= int(input("Enter a value of integer N (0 <= N <= 100): "))#defining an integer variable N that inputs integer value from the user-end

W = input("Enter the word W (length of 1 <= L <= 50): ")#defining a string variable W that inputs the value fom the user-end

for n in range(N):#defining a for loop that uses the range method with integer variable and prints the string value

  print(W)#printing the string value

Therefore, the Python program prints the value of the integer n from the input string shown.

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Complete question:
You are given an integer N where 0 <= N <= 100, followed by another line of input which has a word W with length L where 1 <= L <= 50. Your task is to print N lines with the word W. The lines of your output should not have any trailing or leading spaces.

Your output lines should not have any trailing or leading whitespaces

Input

3

Hello

Output

Hello

Hello

Hello

The amount of ham Ms.D  has left is [tex]6\frac{3}{4}[/tex] pounds.

Ms.D bought [tex]8\frac{1}{2}[/tex] pounds of ham from Excellente Hambaked Shop.  She gave [tex]1\frac{3}{4}[/tex] pounds of ham to Mr.Chavir. The number of pounds of ham she has left can be calculated as follows:

Hence, the amount of hams in pounds she has left is the difference between what she had and the amount of pounds of hams she gave to Mr Chavir.

Therefore,

Amount bought by Ms.D  = [tex]8\frac{1}{2}[/tex] pounds

Amount given to Mr.Chavir.  = [tex]1\frac{3}{4}[/tex] pounds

Therefore,

Amount of she has left = [tex]8\frac{1}{2}[/tex] - [tex]1\frac{3}{4}[/tex]

Amount of she has left = [tex]\frac{17}{2} - \frac{7}{4}[/tex]

Amount of she has left = [tex]\frac{34-7}{4}[/tex]

Amount of she has left = [tex]\frac{27}{4}[/tex]

Amount of she has left = [tex]6\frac{3}{4}[/tex] pounds

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Answer: 8

Step-by-step explanation: 16/2 is simply 16 ÷ 2 in fraction form,

16 ÷ 2 = 8

8c to the power of 18

The number 2.9 × 10^3 is 126 times smaller than 3.654 × 10^5. Because its ratio is 126. It can be calculed by the concept of ratio.

What is ratio?

It is the way of representation of a quantity relative to the other quantity. Its symbol is :. For example size of 2 relative to 5 is represented by 2:5 or 2/5.

To find how many times 2.9 × 10^3 is smaller than 3.654 × 10^5, take ratio of 3.654 × 10^5 and 2.9 × 10^3 as follows:

[tex]=\frac{3.654\times 10^5}{2.9 \times10^3}\\[/tex]

Now, subtract the indices as follows:

[tex]=\frac{3.654\times 10^2}{2.9}\\[/tex]

Now, divide the number as follows:

[tex]=1.26\times 10^{2}\\[/tex]

Now, write in simplest form as follows:

[tex]=126[/tex]

Hence, 2.9 × 10^3 is 126 times smaller than 3.654 × 10^5. It can be calculed by the concept of ratio.

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Answer:

126 times smaller

Step-by-step explanation:

Yes, if Trapezoid abcd has vertices a(2, 4), b(5, 4), c(7, 1), and d(0, 1) , ABCD is an isosceles trapezoid.

Since, If in a trapezoid two opposite nonparallel sides are equal then it is called isosceles trapezoid.

In trapezoid ABCD sides are AB, BC, CD and DA.

According to the question,  A≡(2,4) B≡(5,4) C≡(7,1) and D≡(0,1)

After making the diagram of ABCD, we found that DA and BC are nonparallel sides.

And, by the distance formula BC = √((7 - 5)² + (1 - 4)²) =

⇒ BC =√(4 + 9)

⇒BC = √13 unit.

Similarly, DA = √((0 - 2)² + (1 - 4)²)

DA  = √(4 + 9)

⇒ DA  = √13 unit.

Thus, In trapezoid ABCD, two non parallel sides BC and DA are equal.

Therefore, trapezoid ABCD is a isosceles trapezoid.

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The second number used by Ameekah to represent the consecutive integers is (x + 1).

Let 'x' be the first number written by Ameekah.

Then, the second number will be obtained by adding one to first number.

= x + 1

Thus, the second number used by Ameekah to represent the consecutive integers is (x + 1).

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Answer:

"B" is correct, "x + 1"

Step-by-step explanation:

Have a Jocular Day

The rule with describes the expression 8,4,10,6,12,8,14 is the alternating numbers gets increased by 2

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the expression be represented as A

Now , the expression A is

A = 8,4,10,6,12,8,14

Taking out the alternate numbers from the expression A , we get

A₁ = 8 , 10 , 12 , 14

So ,the values of A₁ increases by 2

And ,Taking out the alternate numbers from the expression A , we get

A₂ = 4 , 6 , 8 , 10

So , the values of A₂ also increases by 2

Hence , the alternating numbers in the expression increases by 2

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Answer:

17

Step-by-step explanation:

I hope this helps!!!

3/4 3/4 3/4 3/4= 3 hours

3 hours equals 4 shifts

you do this 4 times and it equals 12 hours, and 16 . Then you have 3/4 left which equals a shift. So 16+1=17

The required confidence interval for the difference of means is (-18.52, -13.48).

Statisticians use  confidence intervals to gauge vulnerability in an example variable. For instance, a scientist chooses various examples haphazardly from a similar populace and registers a certainty span so that each example might be able to perceive how it might address the genuine worth of the populace variable. The subsequent datasets are different where a few stretches incorporate the genuine populace boundary and others don't.

[tex]n_{a}[/tex] = 18 represent the sample of A

[tex]n_{b}[/tex] = 18 represent the sample of B

μₐ = 39 represent the mean sample  for A

μᵇ =  represent the mean sample for B  

σ = 9 represent the sample deviation for A

σ = 6 represent the sample deviation for B

α = 0.01 represent the significance level

Confidence =99% or 0.99

confidence interval for the difference of means is given by the following formula,

μₐ - μᵇ± [tex]t_{\frac{α}{2}}[/tex][tex]\sqrt{\frac{S_{a}}{n_{a}} +\frac{S_{b}}{n_{b}} }[/tex]

39 - 55 ± 2.756[tex]\sqrt{\frac{9}{18} +\frac{6}{18} }[/tex]

-16 - 2.756(0.912) =  -18.52

-16 + 2.756(0.912) = -13.48

Thus, required confidence interval is (-18.52, -13.48).

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Answer:

43.1%

Step-by-step explanation: