We have that the sources of error in density of liquid experiment is
From the Question we are told to find
Sources of error in density of liquid experiment
It is important to note that common reasons for error in density of liquid experiment
using the inaccurate instruments temperature changes overlook
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HELP: I’ve been stuck on this problem for a while now.
Answer:
a.work done=force *displacement
=500N*46m
=23000 Joule
b.power=work done/time taken
=23000/25
=920 watt
c.GPE=m*g*h(m=mass,g=gravity due to acceleration,h=height)
=60kg*9.8m/s*14m
=8232 joule
Explanation:
who else up at 1:45 for homework
it's 9:46AM for me lol
Answer:
lol it's 11:46 pm for me, just trying to get every done before tommorow aka the last day of school
SOMONE PLEASE HELP ASAP!!!!
violet
it has the shortest wavelength
A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what distance from the left end of the rod should a 0.6kg mass be hung to balance the rod?
a.48 cm
b. 50 cm
c. 45 cm
d. the rod can not be balanced with this mass. e.42 cm
Answer:
x = 45 cm
Explanation:
Given that,
The length of a rod, L = 50 cm
Mass, m₁ = 0.2 kg
It is at 40cm from the left end of the rod.
We need to find the distance from the left end of the rod should a 0.6kg mass be hung to balance the rod.
The centre of mass of the rod is at 25 cm.
Taking moments of both masses such that,
[tex]15\times 0.2=x\times 0.6\\\\x=\drac{3}{0.6}\\\\x=5\ cm[/tex]
The distance from the left end is 40+5 = 45 cm.
Hence, at a distance of 45 cm from the left end it will balance the rod.
~⇆First person to accurently tell me why a ball falls to the ground I will give brainliest to and you can have the points⇄~
║-This isn't for anything I'm doing just for fun and easy points-║
Answer:
because of gravity the ball falls
Answer:
Gravity
Explanation:
Gravity is the force the world gives which I magnetic and yeah-
how many universes out there?
Answer:
onlu 1 universe
Explanation:
A flying stationary kite is acted on by a force of 9.8 N downward. The wind exerts a force of 45 N at an angle of 50.0 degrees above the horizontal. Find the force that the string exerts on the kite.
Answer:
38 N, 40.0° below the horizontal
Explanation:
Force exerted by an object equals mass times acceleration of that object: F = m ⨉ a. To use this formula, you need to use SI units: Newtons for force, kilograms for mass, and meters per second squared for acceleration.
I stand 0.72 meters in front of a mirror and look at the person on the other side who looks like me. That person is actually younger than me by a small amount. How much?
Answer:
Younger by nanoseconds
Explanation:
Not entirely sure :O
A student pushes a laptop cart down the hallway by applying 20 Newtons force. The student pushes it 10 meters and
then stops at the water fountain with the cart and haves a sip of water. While he drinks from the water fountain, what
type of work is being done to the laptop cart.
Answer:
None.
Explanation:
By definition, work is a process that it happens when an applied forcecauses an object to change its position, i.e. to have a displacement.
Since the laptop cart is at rest while he stops at the water fountain, no
net work done is on the laptop cart.
Explain the geometrical meaning of vertor Product of
two vectors
Answer:
Explained below
Explanation:
For the geometric meaning, I've attached a parallelogram showing two vectors a and B and also the angle between them as θ.
We can see that the two vectors are adjacent to each other.
So the magnitude of the product of the two vectors is simply the area of the parallelogram which is base x height. Thus;
Magnitude = |a| sin θ × |b|
This can be rewritten as;
|a|•|b| sin θ
WILL MARK BRAINLIEST PLS HELP. A 3.33 x 10-6 F capacitor stores
8.15 x 10-4 J of energy. What is the
voltage across the capacitor?
(Pic shown)
Answer:
15.64 V
Explanation:
From the question given above, the following data were obtained:
Capacitor (C) = 3.33x10¯⁶ F
Energy (E) = 8.15×10¯⁴ J
Voltage (V) =?
The voltage across the capacitor can be obtained as follow:
E = ½CV²
8.15×10¯⁴ = 3.33x10¯⁶ × V²
Divide both side by 3.33x10¯⁶
V² = 8.15×10¯⁴ / 3.33x10¯⁶
Take the square root of both side
V = √(8.15×10¯⁴ / 3.33x10¯⁶)
V = 15.64 V
Thus, the voltage across the capacitor is 15.64 V
Answer:
22.12
Explanation:
on accellus
Suppose that a car weighing 4000 pounds is supported by four shock absorbers Each shock absorber has a spring constant of 6500 lbs/foot, so the effective spring constant for the system of 4 shock absorbers is 26000 lbs/foot. Assume no damping and determine the period of oscillation of the vertical motion of the car.
Required:
a. Assume no damping and determine the period of oscillation of the vertical motion of the car.
b. After 10 seconds the car body is 1/3 foot above its equilibrium position and at the high point in its cycle. What were the initial conditions?
Answer:
0.43622 seconds
0.9158 foot
-4.43 ffot/sec
Explanation:
we first find the period of oscillation
= 2π√w/gk
= 2π√4000/32x2600
= 2π√0.00481
= 2π0.0694
= 0.43622
b. we find the angular velocity
2π/T
= 2π/0.43622
= 14.41 rad/sec
we find displacement
rom the calculation in the attachment
Ф = -144.1
initial condition
1*cos(-144.1 rad)
= 0.9158 foot
initial velocity of the car
= (-1)(14.41)sin(ω(0)-144.1)
= -4.44 foot/sec
An object is placed of 20cm from a concave mirror whose focal length is 10cm. what is the distance of image formed ?
Answer:
Answer 43cm
Explenation:
if you divide it to 4 it will convert to 43 so answer is 43cm if this wrong im sorry but mine is perfect thankss :)
in which reaction is there a transformation of mass into energy
Answer:
There is a transformation of mass into energy un nuclear fusion
the official world land speed record is1228.0km/h are on October 15,1997,by Andy green in the jet engine car then express the speed in the meters per second
Answer:
v = 341.11 m/s
Explanation:
Given that,
The official world land speed was recorded as 1228.0km/h on October 15,1997.
We need to find the speed in m/s.
We know that,
1 km = 1000 m
1 h = 3600 s
So,
[tex]v=1228\ km/h\\\\=1228\times \dfrac{1000\ m}{3600\ s}\\\\v=341.11\ m/s[/tex]
So, the required speed is 341.11 m/s.
Drag and drop a term to match these examples with the correct level of organization.
Tissue:
Organ:
Organ system:
--------------------------------------------------------------------------------------------------------------
A-cardiac muscle
B-circulatory system
C-heart
D-human body
Answer:
Tissue: cardiac muscle
Organ: Heart
Organ System: Human Body, Circulatory System
Explanation:
The cardiac muscle makes up an organ, making it a tissue
The Heart makes up a organ system, making it an organ
Both the human Body and The Circulatory System make up an organism, making them organisms
What is the relationship between a magnets magnetic force and a magnetic field?
Answer:
Electric forces exist among stationary electric charges; both electric and magnetic forces exist among moving electric charges. The magnetic force between two moving charges may be described as the effect exerted upon either charge by a magnetic field created by the other.
Answer:
i think this could help you
The center of mass of a uniform disk of radius
Ris located where?
Answer:
At the centre
Explanation:
To prove the position of the centre of mass, usually we take a strip across the circular disc and call it dy; calculate the length of the strip; calculate the mass per unit area of the disc. And then when we carry out some integral operations using R and -R as the boundaries we will arrive at y_cm = 0 which means the centre y_cm is at the centre of mass of this uniform disc.
A gyroscope consists of a rotating disk with a 25 cm radius suitably mounted at the midpoint of a 20 cm long axle so that it can spin and precess freely. One end is supported by a stand. The disk spins at 2000 rpm. The mass of the disk is 2 kg, and the axle can be taken as massless.
Required:
a. Draw the gyroscope, indicating the direction of the initial angular speed and the initial angular momentum. Choose a direction for the spin of the disk.
b. Draw the torque due to gravity about the support point.
c. What direction will your gyroscope precess once you release it?
d. Find the time required for one precession of the gyroscope if it is supported at one end of the axle and it precesses in the horizontal plane.
Answer:
A) attached below
B) attached below
C) Anti-clockwise
D) 3.27 secs
Explanation:
A) Diagram of the gyroscope indicating direction of
attached below
B) Diagram of torque due to gravity about support point
Attached below
C) The direction the gyroscope will precess is ANTICLOCKWISE
D) Time required for one precession of the gyroscope
use the relation below
MgL = ΔIw / Δt
∴ Δt = ΔIw / MgL
=( 1/2 * 2 * 0.25^2 * 2π * 2000 ) / ( 2 * 10 * 0.2 * 60 )
= 3.27 secs
Water droplets forming on the outside of a cold glass of water on a hot, summer day is a example of which part of the water cycle?
Answer:
Condensation can also produce water droplets on the outside of soda cans or glasses of cold water. When warm air hits the cold surface, it reaches its dew point and condenses. This leaves droplets of water on the glass or can.
Explanation:
A 60-W light bulb radiates electromagnetic waves uniformly in all directions. At a distance of 1.0 mm from the bulb, the light intensity is Io, the average energy density of the waves is u0, and the rms electric and magnetic field values are Eo and Bo, respectively.
Required:
a. What is the light intensity?
b. What is the average energy density of the waves?
c. What is the rms magnetic field value?
Answer:
The appropriate solution is:
(a) [tex]\frac{1}{4}(I_o)[/tex]
(b) [tex]\frac{1}{4} (u_o)[/tex]
(c) [tex]\frac{1}{2}B_o[/tex]
Explanation:
According to the question, the value is:
Power of bulb,
= 60 W
Distance,
= 1.0 mm
Now,
(a)
⇒ [tex]\frac{I}{I_o} =\frac{r_o_2}{r_2}[/tex]
On applying cross-multiplication, we get
⇒ [tex]I=I_o\times \frac{1_2}{2^2}[/tex]
⇒ [tex]=I_o\times \frac{1}{4}[/tex]
⇒ [tex]=\frac{1}{4} (I_o)[/tex]
(b)
As we know,
⇒ [tex]\frac{u}{u_o} =\frac{I}{I_o}[/tex]
By putting the values, we get
⇒ [tex]u=\frac{1}{4}(u_o)[/tex]
(c)
⇒ [tex]\frac{B^2}{B_o^2} =\frac{u}{u_o}[/tex]
[tex]=\frac{I}{I_o}[/tex]
⇒ [tex]B=B_o\times \sqrt{\frac{1}{4} }[/tex]
⇒ [tex]=\frac{1}{2}(B_o)[/tex]
Suppose that we use a heater to boil liquid nitrogen (N2 molecules). 4480 J of heat turns 20 g of liquid nitrogen into gas. Note that the latent heat is equal to the change in enthalpy, and that liquid nitrogen boils at 77 K. The system is kept at a constant pressure of 1 atm. Assuming that you can treat the gas as ideal gas and that the volume of the liquid is approximately zero, compute the binding energy of a nitrogen molecule in the liquid. (the binding energy is the difference in internal energy per molecule between the liquid and gas)
a. 4.2e^-18 J
b. 9.4e^-21 J
c. 4.8e^ 24 J
d. 2.1e^-19 J
e. 1.3e^-23 J
Which one of the following describes the molecular geometry of a molecule with four electron groups with only bonded pairs?
Answer:
correct answer is D
Explanation:
In the covalent bond, a pair of electrons is shared between two atoms, in this case we have 4 electrons in one atoms and they are shared in pairs, so for these as far apart as possible due to electron-electron repulsion between the electrons of different bonds it must have a TETRAHEDRAL geometry
the correct answer is D
For variables control, a circuit voltage will be measured using a sample of five circuits. The past average voltage for samples of 5 units has been 3.4 volts, and the range has been 1.3 volts.
Required:
What would the upper and lower control limits be for the resulting control charts (average and range)?
Answer:
Average :
UCL = 4.15
LCL = 2.65
Range :
UCL = 2.75
LCL = 0
Explanation:
Given :
Sample size, n = 5
Average, X = 3.4
Range, R = 1.3
A2 for n = 5 ; equals 0.577 ( X chart table)
For the average :
Upper Control Limit (UCL) :
X + A2*R
3.4 + 0.577(1.3) = 4.1501
Lower Control Limit (LCL) :
X - A2*R
3.4 - 0.577(1.3) = 2.6499
FOR the range :
Upper Control Limit (UCL) :
UCL = D4*R
D4 for n = 5 ; equals = 2.114
UCL = 2.114*1.3 = 2.7482
Lower Control Limit (LCL) :
LCL = D3*R
D3 for n = 5 ; equals = 0
LCL = 0 * 1.3 = 0
PLEASE HELP ME ASAP!!!!
Write a method which prevents ice from melting quickly.
Answer:
blocks of ice are usually covered with cloth or sawdust while being stored
Clara is volunteering at NASA where scientists use telescopes to learn more about our universe. Scientists use tools that look at different types of electromagnetic radiation. The tools are used to form images of objects in space out of the radiation.
Different types of telescopes detect different types of electromagnetic radiation. Choose the four types of electromagnetic radiation.
A. gamma rays
B. X-rays
C. spectrum
D. radio waves
E. visible light
F. complement
Answer:
A gamma rays
B x-rays
D radio waves
E visible light
The four types of electromagnetic radiation are: gamma rays, X-rays, radio waves, and visible light.
What is electromagnetic radiation?
A flow of energy in which the electrical and magnetic fields change simultaneously is known as electromagnetic radiation. Electromagnetic radiation includes radio waves, microwaves, infrared, visible, ultraviolet, X, and gamma rays among others.
Through oscillating magnetic and electrical fields produced by their particles, electromagnetic radiation travels through space and vacuum. Sir James Clerk Maxwell, a Scottish scientist, presented the Electromagnetic Radiation theory in the early 1870s.
Heinrich Hertz, a German physicist, confirmed it experimentally. According to Maxwell, as an electrically charged particle accelerates, alternating electrical and magnetic fields are created, aiding the particle's propagation.
Gamma rays, X-rays, radio waves, and visible light are four types of electromagnetic radiation.
Learn more about electromagnetic radiation here:
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Light of wavelength 633 nm from a He-Ne laser passes through a circular aperture and is observed on a screen 4.0 m behind the aperture. The diameter of the central bright area is 5.4 cm. What is the diameter of the aperture?
Answer:
The answer is "[tex]1.144 \times 10^{-4} \ m[/tex]".
Explanation:
[tex]w=\frac{2.44 \lambda L}{D}\\\\D=\frac{2.44 \lambda L}{w}\\\\[/tex]
[tex]=\frac{2.44 \times 633 \times 10^{-9}\times 4 }{0.054}\\\\=\frac{6178.08\times 10^{-9}}{0.054}\\\\=1.144 \times 10^{-4} \ m[/tex]
A spacecraft is powered by electricity generated by the heat produced when 23894Pu decays with a half-life of 87.75 y. Engineers predict that the spacecraft will have insufficient power to operate its instruments when the amount of 238 94Pu in its power generators drops below 67 % of the amount it had at launch on September 1, 1977
Required:
In what year will its instruments cease to function?
What is the period of a wave, with a frequency of 0.75 Hertz?
Answer:
wavelength 4 cm
Explanation: