A truck is driving over a scale at a weight station. When the front wheels drive over the scale, the scale reads 5800 N. When the rear wheels drive over the scale, it reads 6500 N. The distance between the front and rear wheels is 3.20 m Determine the distance between the front wheels and the truck's center of gravity.
Answer:
[tex]x_2=1.60m[/tex]
Explanation:
From the Question We are told that
Initial Force [tex]F_1=5800N[/tex]
Final Force [tex]F_2=6500N[/tex]
Distance between the front and rear wheels \triangle x=3.20 m
Since
[tex]\triangle x=3.20 m[/tex]
Therefore
[tex]x_1+x_2=3.20[/tex]
[tex]x_1=3.20-x_2[/tex]
Generally the equation for The center of mass is at x_2 is mathematically
given by
[tex]x_2 =\frac{(F_1x_1+F_2x_2)}{(F_1+F_2)}[/tex]
[tex]x_2=3.20F_1-\frac{x_2F_1+F_2x_2}{(F_1+F_2)}[/tex]
[tex]2*F_1*x_2 =3.20F_1[/tex]
[tex]x_2=1.60m[/tex]
Center of gravity of a body is the sum of its moments divided by the overall weight of the object. The distance between the front wheels and the truck's center of gravity is 1.6 meters.
Given-
Scale reading value when the front wheels drive over the scale [tex]m_{1}[/tex] is 5800 N.
Scale reading value when the rear wheels drive over the scale [tex]m_{2}[/tex] is 6500 N
Distance between the front and rear wheel [tex]\bigtriangleup x[/tex] is 3.20 meters.
Let, the distance between the front wheels and the truck's center of gravity is [tex]x_{2}[/tex].
Since sum of the distance between front wheel to truck's center of gravity [tex]x_{1}[/tex], and rear wheel to truck's center of gravity [tex]x_{2}[/tex], is equal to the distance between the front and rear wheel [tex]\bigtriangleup x[/tex]. Therefore,
[tex]\bigtriangleup x=x_{1} +x_{2}[/tex]
[tex]3.20=x_{1} +x_{2}[/tex]
[tex]x_{1} =3.20-x_{2}[/tex]
For the distance between the front wheels and the truck's center of gravity is the formula of center of gravity can be written as,
[tex]x_{2} =\dfrac{m_{1}x_{1}+m_{2} x_{2} }{m_{1} +m_{2} }[/tex]
[tex]x_{2} =\dfrac{5800\times (3.20- x_{2})+6500\times x_{2} }{5800 +6500 }[/tex]
[tex]1230 x_{2} ={18560-5800 x_{2}+6500 x_{2} }[/tex]
[tex]x_{2}= 1.6[/tex]
Hence, the distance between the front wheels and the truck's center of gravity is 1.6 meters.
For more about the center of gravity, follow the link below-
https://brainly.com/question/20662119
If you left a glass fiber-optic cable unshielded by any plastic covering, should the light still be able to travel through the cable?
1. Yes
2. No
Answer:
Yes
Explanation:
a 2kg block of wood starts at rest and slides down a ramp. Its initail height is 12m. if the final velocity of the block is 13m/s, determine the energy of this system that has been turned into heat
Answer:
E = 66.44 J
Explanation:
From the law of conservation of energy:
Total Mechanical Energy at Start = Total Mechanical Energy at the End
Potential Energy at Start = Kinetic Energy at End + Energy Lost
[tex]mgh = \frac{1}{2} mv^2 + E\\\\E = mgh - \frac{1}{2} mv^2\\\\[/tex]
where,
E = Energy turned into heat = ?
m = mass of block = 2 kg
g = acceleration due to gravity = 9.81 m/s²
h = height = 12 m
v = final speed = 13 m/s
Therefore,
[tex]E = (2\ kg)(9.81\ m/s^2)(12\ m)-\frac{1}{2} (2\ kg)(13\ m/s)^2\\\\E = 235.44\ J - 169\ J\\[/tex]
E = 66.44 J
in a Mercury thermometer the level of Mercury Rises when its bulb comes in contact with a hot object what is the reason for this rise in the level of Mercury
Answer:
because thermometric liquid readily expands on heating or contracts on cooling even for a small difference in the temperature of the body.
Rest and motion are relative terms. write in brief
Answer:
Rest and motion are the relative terms because they depend on the observer's frame of reference. So if two different observers are not at rest with respect to each other, then they too get different results when they observe the motion or rest of a body.
Explanation With Example:
Imagine you are sitting inside a moving bus. When you look outside you will observe that you are moving. ... With respect to the roof of bus, you are at rest. Hence it is concluded that rest and motion are relative terms.
The temperature of 10 kg of a substance rises by 55oC when heated. Calculate the
temperature rise when 22 kg of the substance is heated with the same quantity of heat.
Given :
The temperature of 10 kg of a substance rises by 55oC when heated.
To Find :
The temperature rise when 22 kg of the substance is heated with the same quantity of heat.
Solution :
We know, change in temperature when heat is given to object is given by :
[tex]\Delta H = m S\Delta T[/tex]
It is given that same amount of heat is given in both the cases also the substance is same.
So,
[tex]M_1 S \Delta T_1 = M_2 S \Delta T_2\\\\10\times 55 = 22 \times \Delta T_2\\\\\Delta T_2 = 25^o\ C[/tex]
Hence, this is the required solution.
A compound consisting of Cr3+ ions and OH ions would be named chromium (III) hydroxide
True or false
Q11:A police car in hot pursuit goes speeding past you. While the siren is approaching, the frequency of the sound you hear is 5500 Hz. When the siren is receding away from you, the frequency of the sound is 4500 Hz. Use the Doppler formula to determine the velocity of the police car. Use vsound
Answer:
v_s = 34.269 m / s
Explanation:
This is a Doppler effect exercise, in this case the observer is fixed and the sound source is moving.
f ’= f [tex]\frac{v}{v \mp v_s }[/tex]
where the negative sign is used for when the source approaches the observer and the positive sign for when the source moves away from the observer
In this case when f ’= 5500 Hz approaches and when f’ = 4500 Hz moves away, let's write the two expressions together
5500 = f ([tex]\frac{v}{v - v_s }[/tex])
4500 = f ( [tex]\frac{v}{v + vs}[/tex])
let's solve these two equations
[tex]\frac{5500}{4500} = \frac{v+v_s}{v-v_s}[/tex]
1.222 (v-v_s) = v + v_s
v_s (1+ 1.22) = v (1.222 -1)
v_s = v [tex]\frac{0.222}{2.223}[/tex]
the speed of sound in air is v = 343 m / s
v_s = 343 0.09990
v_s = 34.269 m / s
(A)
(B)
(C)
(D)
Which graph is a quadratic graph?
OA graph A
OB. graph B
OC graph
OD. graph D
A superconductor performs best at ______.
Extremely high temperatures
Room temperature
Very cold temperatures
Any temperature
Answer:
c
Explanation:
Superconductors perform best at very cold temperatures because resistivity of this kind of materials decays drastically with temperature. Chromium is most likely to be the best conductor of electricity because it belongs to the Transition Metal group of the periodic table
If v = 4.00 meters/second and makes an angle of 60° with the positive direction of the y–axis, what is the magnitude of vx?
Darcy suffers from farsightedness equally severely in both eyes. The focal length of either of Darcy's eyes is 19.8 mm in its most accommodated state (i.e, when the eye is focusing on the closest object that it can clearly see) What lens strength (a.k.a., lens power) of contact lenses should be prescribed to correct the farsightedness in Darcy's eyes? (Assume the lens-to retina distance of Darcy's eyes is 2.00 cm, and the contact lenses are placed a negligibly small distance from the front of Darcy's eyes)
i. 1.64D
ii. 2.98 D
iii. 2.19 D
iv. 3.49 D
v. 1.37 D
Answer:
Explanation:
Power of defective eye = (1 / near point )+ (1 / lens-retina distance )
1 / .0198 m = (1 / near point )+ (1 / .02 m )
= 50.50 = (1 / near point )+ 50
0.50 = 1 / near point
near point = 1 / .5 = 2m
= 200 cm .
for near point at 25 cm , convex lens will be required.
u = - 25 cm , v = - 200 cm ,
1 / v - 1 / u = 1 /f for lens
- 1 / 200 + 1 / 25 = 1 / f
= .04 - .005 = 1 /f
.035 = 1 / f
f = 28.57 cm = 0.2857 m
power = 1 /f
= 1 / 0.2857
= 3.5 D .
i v ) option is correct .
A 0.390 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 75.0 pC charge on its surface. What is the potential (in V) near its surface
Answer:
V = 346.15 Volts
Explanation:
Given that,
Diameter of the sphere, d = 0.390 cm
Radius, r = 0.195 cm
Charge, [tex]q=75\ pC =75\times 10^{12}\ C[/tex]
The electric potential near its surface is given by :
[tex]V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 75\times 10^{-12}}{0.195\times 10^{-2}}\\\\V=346.15\ V[/tex]
So, the potential near its surface is equal to 346.15 V.
You move to Mars and as a momento from Earth take your Ma-maw's mercury barometer. You place it outside in the Martian atmosphere and read a very low pressure. Does the pressure reading accurately reflect the atmospheric on the surface of Mars
Answer:
Explanation:
No, the reading is not expected to be accurate. This is because Relative to Earth, the air on Mars is extremely thin. The Martian atmosphere is primarily carbon dioxide with a much lower surface pressure, and Mars does not have oceans and an Earthlike hydrological cycle so latent heat release is not as important as it is for Earth.
15) If a magnet produces a force on a current-carrying wire, the wire
A) produces a force on the magnet.
B) may or may not produce a force on the magnet.
C) neither of these
Answer:
The answer is option no. A
Light energy from the Sun reaches an ocean beach, where people are
walking. Which transfer of thermal energy involved in this scenario is an
example of radiation?
Answer:
the correct answers is D
Explanation:
Thermal energy can be transferred by three methods: conduction, convention, and radiation.
Radiation transfer occurs when there is no movement of matter for the exchange of energy.
In this case, checking the correct answers is D
since in this case the transfer is between light and sand without matter exchange
option are
cerebrum, cortex, cerebellum, brain stem, medulla, pons, midbrain , thalamus, hypothalamus, reticular formation
1.________regulates and maintains brain's awareness level.
2. _______controls the activity of the pituitary gland.
3._______relays impulses from one part of the brain to another.
4._______regulates body temperature, hunger, and other internal body conditions.
5______connects nerve impulses from body to cortex.
Answer:
1. Reticular formation.
2. Hypothalamus.
3. Thalamus.
4. Hypothalamus.
5. Thalamus.
Explanation:
The human brain consists of various sections and these includes;
I. Anterior Cingulate Cortex (ACC) which resembles a bow or collar surrounding the frontal part of the corpus callosum. This is the frontal part of the cingulate cortex which helps to make complex cognitive functions such as impulse control, decision-making, emotions and empathy.
II. Ventral prefrontal cortex in humans are interconnected with the brain and are responsible for the processing of risk, empathy, fear and social decision-making
III. The Cerebral Cortex: this part of the brain primarily comprises of grey matter, foldable sheets of neurons and forms its outermost layer. Therefore, cerebral cortex is known as the outermost layer of the brain (cerebrum) and thus, makes up half of its weight. It is about 2.5 millimeters in thickness and as such it's able to fold.
1. Reticular formation: regulates and maintains brain's awareness level.
2. Hypothalamus: controls the activity of the pituitary gland.
3. Thalamus: relays impulses from one part of the brain to another.
4. Hypothalamus: regulates body temperature, hunger, and other internal body conditions.
5. Thalamus: connects nerve impulses from body to cortex.
As part of an exercise program, a woman walks south at a speed of 2.8 m/s for 46 minutes. She then turns around and walks north a distance 3,132 m in 54 minutes . What is the woman's average speed in m/s during her entire motion
Answer:
[tex]A_[avg}=1.81m/s[/tex]
Explanation:
From the question we are told that:
North Movement
Velocity[tex]V=2.8[/tex]
Time [tex]t=46 minuites[/tex]
South movement
Distance [tex]d=3,132[/tex]
Time [tex]t'= 54 minutes[/tex]
Generally the equation for Average Velocity is mathematically given by
[tex]A_[avg}\]frac{Total distance}{Total time}[/tex]
Where
Total distance d_t
[tex]d_t=Souther\ distance\ traveled\ +Northern\ distance\ traveled[/tex]
[tex]d_t=(2.8*46*60)+(3132)[/tex]
[tex]d_t=10860[/tex]
An
Total Time
[tex]T=(46+54)60[/tex]
[tex]T=6000[/tex]
Therefore
[tex]A_[avg}=\frac{d_t}{T}[/tex]
[tex]A_[avg}=\frac{10860}{6000}[/tex]
[tex]A_[avg}=1.81m/s[/tex]
name 3 properties of solids
-A solid has a definite shape and volume.
-Solids in general have higher density.
-In solids, intermolecular forces are strong.
What do we call air in the motion
Answer:
carbon d
Explanation:
A copper (Cu) atom has 29 protons, 34 neutrons, and 29 electrons. What is
copper's atomic number?
O
A. 63
B. 29
C. 58
W
.
D. 34
The Earth is a small, rocky planet. It is known as one of the terrestrial planets.
A planet that is similar to the Earth is
A. Uranus
B. Saturn
C. Jupiter
D. Venus
Answer:
D Venus
Explanation:
in terms of size, average, density, mass and surface gravity venus is similar to earth
4. A 268 kg boulder rolls down a hill. If it had 50,000 J of energy to start with, how high was the hill? (Can anyone explain or give the equation for it? Thank you!)
Answer:
h = 18.65 m
Explanation:
Given that,
The mass of a boulder, m = 268 kg
The potential energy at the hill, E = 50,000 J
We need to find the height of the hill.
We know that, the potential energy of an object is given by :
E = mgh
Where
h is the height of the hill
So,
[tex]h=\dfrac{E}{mg}\\\\h=\dfrac{50000}{268\times 10}\\\\h=18.65\ m[/tex]
So, the height of the hill is 18.65 m.
[tex]\\ \sf\longmapsto PE=mgh[/tex]
[tex]\\ \sf\longmapsto 50000=268(10)h[/tex]
[tex]\\ \sf\longmapsto 50000=2680h[/tex]
[tex]\\ \sf\longmapsto h=\dfrac{50000}{2680}[/tex]
[tex]\\ \sf\longmapsto h=18.65m[/tex]
Người ta đúc một khối nhóm (A) và một khối sắt ( (Fe) hình khối với cũng khói lượng 5 kg Khối lượng riêng (2) của Al và Fe là 2 rho ki =2.7*10^ 3 kg/m^ 3 ; mu 4 =7,8*10^ 3; kg/m^ 3 Hỏi, khối vật liệu nào có kích thước lớn hơn? (a) khối nhằm (b) khối sắt (c) hai khối có cùng kích cỡ
Angles t and v are complementary.angles T has a mesure of (2X+10). Angle v has a measure of 48 what is the value of x
16 because complementary angles equal up to 90. 2x+58 = 90 x= 16
An object accelerates 3 m/s2 , when a force of 6 N acts on it. What is the object’s mass
Answer:
2 kgExplanation:
The mass of the object can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{6}{3} \\ = 2[/tex]
We have the final answer as
2 kgHope this helps you
As a 2.0-kg object moves from (4.4 i + 5j) m to ( 11.6 i - 2j) m, the constant resultant force
acting on it is equal to (41 - 9j) N. If the speed of the object at the initial position is 4.0 m/s,
what is its kinetic energy at its final position?
Answer:
Answer:
v_f = 10.38 m / s
Explanation:
For this exercise we can use the relationship between work and kinetic energy
W = ΔK
note that the two quantities are scalars
Work is defined by the relation
W = F. Δx
the bold are vectors. The displacement is
Δx = r_f -r₀
Δx = (11.6 i - 2j) - (4.4 i + 5j)
Δx = (7.2 i - 7 j) m
W = (4 i - 9j). (7.2 i - 7 j)
remember that the dot product
i.i = j.j = 1
i.j = 0
W = 4 7.2 + 9 7
W = 91.8 J
the initial kinetic energy is
Ko = ½ m vo²
Ko = ½ 2.0 4.0²
Ko = 16 J
we substitute in the initial equation
W = K_f - K₀
K_f = W + K₀
½ m v_f² = W + K₀
v_f² = 2 / m (W + K₀)
v_f² = 2/2 (91.8 + 16)
v_f = √107.8
v_f = 10.38 m / s
Suppose that the electric field in the Earth's atmosphere is E = 131 N/C, pointing downward. Determine the electric charge (in C) in the Earth. (Assume the electric field is measured at the surface of the Earth. Include the sign of the value in your answer.) Hint
Answer:
the electric charge in the Earth is -5.91 × 10⁵ C
Explanation:
Given the data in the question;
Electric field E = 131 N/C
we know that; radius of the earth r = 6,371 km = 6371000 m
and Coulomb's constant k = 8.99 × 10⁹ Nm²/c²
Now, using the following formula to calculate the charge;
E = k × Q/r²
we make Q the subject of the formula
Q = Er² / k
so we substitute
Q = [ 131 N/C × ( 6371000 m )² ] / 8.99 × 10⁹ Nm²/c²
Q = [ 5.317242971 × 10¹⁵ ] / [ 8.99 × 10⁹ ]
Q = 5.91 × 10⁵ C
Since the electric field pointing downward
Q = -5.91 × 10⁵ C
Therefore, the electric charge in the Earth is -5.91 × 10⁵ C
Long Shore Drift is the ...
A. landforms along the shoreline of an ocean or sea
B. submerged or partly exposed ridge of sand along an ocean front
C. accumulation of sand grains along a beach front
D. movement of material along a coast by waves that approach at an angle to the shore.
Answer: D. movement of material along a coast by waves that approach at an angle to the shore.
Explanation:
Longshore drift is also referred to as the littoral druft and it means the sediment that is moved by the longshore current.
Longshore drift is the movement of material along a coast by waves which approach at an angle to the shore but then recede down the beach.
Therefore, the correct option is D.
1. What did you observe about the magnitudes of the forces on the two charges? Were they the same or different? Does your answer depend on whether the charges were of the same magnitude or different? How does this relate to Newton’s 3rd law?
Answer:
Following are the solution to the given question:
Explanation:
Its strength from both charges is equivalent or identical. The power is equal. And it is passed down
[tex]F=\frac{kq_1q_2}{r^2}[/tex]
Therefore, the extent doesn't rely on the fact that charges are the same or different. Newton's third law complies with Electrostatic Charges due to a couple of charges. They are similar in magnitude, and they're in the other way.
[tex]|F_{12}| = |F_{21}|[/tex]