Answer:
For empiricists like van Fraassen, the phenomena of physics are the appearances observed or perceived by sensory experience. Constructivists, however, regard the phenomena of physics as artificial structures generated by experimental and mathematical methods.
Explanation:
I hope it's help u Have a great dayWe have that the the phenomena that physics in applied in are much but these are phenomena's where Physics as a discipline is applied
Physics is applied in LightingElectricityMovementHeatGravityWe first define physics Before we go into it variant applications
Physics
Physics is a part(branch,denomination) of science a that focuses heavily on the facts of Matter and Energy that is seen on earth and the world around us.
Different Application of Physics
Physics is applied in Lighting
one of the Greatest phenomena of the application of Physics is the light bulb
this follows its distinct principle follow laws and principle to achieve its invention
Electricity
Physics studies atoms and its particle electron which is the bases of electricity
Movement
Movement or motion is a core part of physics with newtons three laws of motion playing a big role to the understanding of motion
Heat
Physics studies the heat and all its principle and sources e.g the sun, and Quantities used to define heat at different stages
Gravity
Gravity is a constant force that that acts on all matter that exist.
It is the bases of weight as weight is a function of Gravity and Mass of matter
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An object’s mass 300 kg is observed to accelerate at the rate of 4 m/s^2. Calculate the force required to produce this acceleration. *
1. 1000 N
2 .75 N
3. 1200 N
4. 1250 N
You kick 5.6 kg ball with a force of 39 N. Find the acceleration of the ball in m/s2. Round your answer to 1 decmial place.
Answer:
7.0 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
We have
[tex]a = \frac{39}{5.6} \\ = 6.964285...[/tex]
We have the final answer as
7.0 m/s²Hope this helps you
HELP PLZ
Calculate the resistivity of a metal of length 2m at 20°C having the resistance
of 20 ohm and diameter 0.3mm?
Answer:
40*C
Explanation:
How does rainwater contribute to aquatic succession
Answer:
Rain water carries sediment and then these accumulate on the bottom of ponds, lakes and wetlands. This accumulation build up over time and eventually, the water disappears (because they sink into the ground) and the area once covered with water becomes land.
The design of a 60.0 cm industrial turntable requires that it has a kinetic energy of 0.250 j when turning at 45.0 rpm. What must be the moment of inertia of the turntable about the rotation axis
Answer:
The moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²
Explanation:
Given;
radius of the turnable, r = 60 cm = 0.6 m
rotational kinetic energy, E = 0.25 J
angular speed of the turnable, ω = 45 rpm
The rotational kinetic energy is given as;
[tex]E_{rot} = \frac{1}{2} I \omega ^2[/tex]
where;
I is the moment of inertia about the axis of rotation
ω is the angular speed in rad/s
[tex]\omega = 45 \frac{rev}{\min} \times \frac{2 \pi \ rad}{1 \ rev} \times \frac{1 \ \min}{60 \ s} \\\\\omega = 4.712 \ rad/s[/tex]
[tex]E = \frac{1}{2} I \omega ^2\\\\I = \frac{2E}{\omega ^2} \\\\I = \frac{2 \ \times \ 0.25}{(4.712)^2} \\\\I = 0.0225 \ kg.m^2[/tex]
Therefore, the moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²
on what factors, current sensitivity voltage sensitivity of
a galvanometer depend?
Explanation:
The voltage sensitivity of a galvanometer is given by :
[tex]\dfrac{NBA}{RK}[/tex]
Where
N=Number of turns
A=Area of coil
B=Magnetic field produced in coil
K=Torsion constant of galvanometer
R=Resistance of galvanometer
The current sensitivity of a galvanometer is given by :
[tex]\dfrac{NBA}{K}[/tex]
Hence, this is the required solution.
An object is placed 50cm in front of a concave mirror of radius 60cm. How far from the mirror is the image?
Answer:To explian the exact calculation of this pruduct we must not try!
Light travels at 300,000,000 m/s. This is an example
Answer:
ook soooooo
Explanation:
An individual's belief that they can master a situation and produce positive outcomes is
Answer:
optimism
Explanation:
just an idea
....
PHYSICS HELP !! 30 points please answer correctly !! questions attached below
Two waves that have
(10 Points)
will add together to produce beats *
the same frequency
slightly different frequencies
different speeds
the same wavelength
Answer:
slightly different frequencies
Explanation:
The alternate increase or decrease of sound produced by the interference of two sound waves of slightly different frequencies is called ‘Beat’. The maximum beat frequency that a human ear can detect is 7 beats/sec.
This definition of the beats is clearly pointing out that the two waves whose frequencies are slightly different will add together to produce the beats.
Therefore, the correct answer will be:
slightly different frequencies
Blue whales apparently communicate with each other using sound of frequency 17.0 Hz, which can be heard nearly 1000 away in the ocean. What is the wavelength of such a sound in seawater, where the speed of sound is 1531 m/s
Answer:
the wavelength of the sound in seawater is 90.1 m.
Explanation:
Given;
frequency of the sound, f = 17 Hz
speed of the sound in seawater, v = 1531 m/s
The wavelength of the wave is calculated as follows;
v = fλ
λ = v / f
where;
λ is the wavelength of the sound
λ = 1531 / 17
λ = 90.1 m
Therefore, the wavelength of the sound in seawater is 90.1 m.
Two identical circular, wire loops 35.0 cm in diameter each carry a current of 2.80 A in the same direction. These loops are parallel to each other and are 24.0 cm apart. Line ab is normal to the plane of the loops and passes through their centers. A proton is fired at 2600 m/s perpendicular to line ab from a point midway between the centers of the loops.
Find the magnitude of the magnetic force these loops exert on the proton just after it is fired.
Answer:
The answer is "[tex]4659.2 \times 10^{-24} \ N[/tex]"
Explanation:
The magnetic field at ehe mid point of the coils is,
[tex]\to B=\frac{\mu_0 i R^2}{(R^2+x^2)^{\frac{3}{2}}}\\\\[/tex]
Here, i is the current through the loop, R is the radius of the loop and x is the distance of the midpoint from the loop.
[tex]\to B=\frac{(4\pi\times 10^{-7})(2.80\ A) (\frac{0.35}{2})^2}{( (\frac{0.35}{2})^2+ (\frac{0.24}{2})^2)^{\frac{3}{2}}}\\\\[/tex]
[tex]=\frac{(12.56 \times 10^{-7})(2.80\ A) \times 0.030625}{( 0.030625+ 0.0144)^{\frac{3}{2}}}\\\\=\frac{ 1.07702 \times 10^{-7} }{0.0095538976}\\\\=112.730955 \times 10^{-7}\\\\=1.12\times 10^{-5}\ \ T\\[/tex]
Calculating the force experienced through the protons:
[tex]F=qvB=(1.6 \times 10^{-19}) (2600)(1.12 \times 10^{-5})= 4659.2 \times 10^{-24}\ N[/tex]
A spherical conducting shell has an inner radius of 0.2 m and an outer radius of 0.4 m. There is no charge on the outer surface but the shell does have a nonzero net charge. All charges remain at rest. The potential at the outer surface is -2 V. The potential at the center of the cavity is g
Answer:
[tex]P_c=-4v[/tex]
Explanation:
From the question we are told that:
Inner radius [tex]r_1=0.2[/tex]
Outer radius[tex]r_2=0.4[/tex]
Potential at the outer surface is [tex]P_o= -2 V[/tex]
Generally the equation for Potential at the outer surface P_o is mathematically given by
[tex]P_o=\frac{KQ}{r_2}[/tex]
[tex]-2=\frac{KQ}{0.4}[/tex]
Therefore
[tex]KQ=-0.8v[/tex]
Generally the equation for Potential at Center of outer cavity [tex]P_c[/tex] is mathematically given by
[tex]P_c=\frac{KQ}{r_1}[/tex]
[tex]P_c=\frac{-0.8}{0.2}[/tex]
[tex]P_c=-4v[/tex]
Therefore the potential at the center of cavity
[tex]P_c=-4v[/tex]
The potential at the center of the cavity of the spherical conducting shell is -0.4 V.
What is electric potential of spherical shell?Electric potential of spherical shell is the total amount of work required to move a charge in s spherical shell from one point to other.
Electric potential of spherical shell at outer surface can be given as,
[tex]P_{outer}=k\dfrac{Q}{r_o}[/tex]
Electric potential of spherical shell at center of outer gravity can be given as,
[tex]P_{cavity}=k\dfrac{Q}{r_i}[/tex]
Here, (Q) is the charge, (k) is the constant and [tex](r_o, r_i)[/tex] is the outer and inner radius.
A spherical conducting shell has an outer radius of 0.4 m and the potential at the outer surface is -2 V. Thus, the potential at the outer surface can be find out using the above formula as,
[tex]-2=k\dfrac{Q}{0.4}\\kQ=-0.8\rm V[/tex]
The spherical conducting shell has an inner radius of 0.2 m. Thus, the potential at the outer surface can be find out using the above formula as,
[tex]P_{cavity}=k\dfrac{Q}{0.2}\\P_{cavity}=\dfrac{-0.8}{0.2}\\P_{cavity}=-0.4\rm V[/tex]
Thus, the potential at the center of the cavity of the spherical conducting shell is -0.4 V.
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You purchased 1.9 kg of apples from Wollaston. You noticed that they used a spring scale with the smallest division of 2.1 g to weigh them. What is the relative error in this weight measurement as a percentage
The relative error in this weight measurement as percentage is
[tex]0.1105\%[/tex]What is relative error?is the ratio of the absolute error of a measurement to the measurement being taken. In other words, this type of error is relative to the size of the item being measured.
Therefore,
[tex]\% relative error = \frac{smallest division}{mass of apples}*100\\\\\% relative error = \frac{2.1g}{1900}*100\\\\\% relative error = 0.1105\%[/tex]
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Answer:
The relative error in this weight measurement is approximately 0.1105 %.
Explanation:
We know that,
Relative Error is the ratio of the absolute error of a measurement to the actual measurement . It can be mathematically represented as,
Relative Error = (Measured Value - Actual Value) / Actual Value * 100
In this case, the actual weight is 1.9 kg, and the smallest division of the spring scale is 2.1 g.
Actual Weight = 1.9 * 1000 = 1900 (As 1 kg = 1000g)
We know that the absolute error will be equal to the smallest division hence,
Measured Value - Actual Value = 2.1 g
By replacing this in the general formula we get,
Relative Error = (Measured Value - Actual Value) / Actual Value * 100
= [tex]\frac{2.1}{1900} *100[/tex] %
= [tex]\frac{2.1}{19}[/tex] %
≈ 0.1105 %
Therefore, the relative error in this weight measurement is approximately 0.1105 %.
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Radon has a half-life of 56s. After what time will it's activity be reduced to (a) 90% (b) 50% (c) 10% of it's initial value
Answer:
A) 11.2 s
B) is 56 s
C) 170.8 s
A French submarine and a U.S. submarine move toward each other during maneuvers in motionless water in the North Atlantic. The French sub moves at 43.00 km/hkm/h , and the U.S. sub at 64.00 km/hkm/h . The French sub sends out a sonar signal (sound wave in water) at 1000 Hz. Sonar waves travel at 5470 km/hkm/h . What is the signal's frequency as detected by the U.S. sub
Answer:
[tex]f_{U}= 1019.72hz[/tex]
Explanation:
From the equation we are told that:
Velocity of French sub [tex]V_{U}= 43.00km/h[/tex]
Velocity of U.S. sub at [tex]V_{F}|=64.00 km//h[/tex]
French Wave Frequency [tex]F_{F}=1000Hz[/tex]
Velocity of wave [tex]V_{s}=5470 km/h[/tex]
Generally the equation for Signal's frequency as detected by the U.S. is mathematically given by
Doppler effect
[tex]f_{U} = \frac{ f_F (vs + v_{U})}{(v_s - v_F) }[/tex]
[tex]f_{U}= \frac{ 1000 x ( 5470+64)}{(5470-43)}[/tex]
[tex]f_{U}= 1019.72hz[/tex]
I need help. 2x+2x=6
Answer:
in decimal form x = 1.5
in exact form x = 3/2
and as a mixed number x = 1 1/2
Explanation:
How could an astronomical event affect the biodiversity of life on Earth?
Explanation:
Impacts of large meteorites have never been observed by humans. Much of our knowledge about what happens next must come from scaled experiments. As the solid object plows into the Earth, it will compress the rocks to form a depression and cause a jet of fragmented rock and dust to be expelled into the atmosphere.
Two containers have a substantial amount of the air evacuated out of them so that the pressure inside is half the pressure at sea level. One container is in Denver at an altitude of about 6,000 ft and the other is in New Orleans (at sea level). The surface area of the container lid is A
Answer:
[tex](a)\ F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]
[tex](b)\ F_{No} = 771.125N[/tex]
Explanation:
Given
[tex]d_D = 6000ft[/tex] ---- Altitude of container in Denver
[tex]A = 0.0155m^2[/tex] -- Surface Area of the container lid
[tex]P_D = 79000Pa[/tex] --- Air pressure in Denver
[tex]P_{No} = 100250Pa[/tex] --- Air pressure in New Orleans
See comment for complete question
Solving (a): The expression for [tex]F_{No[/tex]
Force is calculated as:
[tex]F = \triangle P * A[/tex]
The force in New Orleans is:
[tex]F_{No} = \triangle P * A[/tex]
Since the inside pressure is half the pressure at sea level, then:
[tex]\triangle P = P_{No} - \frac{P_{area}}{2}[/tex]
Where
[tex]P_{area} = 101000Pa[/tex] --- Standard Pressure
Recall that:
[tex]F_{No} = \triangle P * A[/tex]
This gives:
[tex]F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]
Solving (b): The value of [tex]F_{No[/tex]
In (a), we have:
[tex]F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]
Where
[tex]A = 0.0155m^2[/tex]
[tex]P_{No} = 100250Pa[/tex]
[tex]P_{area} = 101000Pa[/tex]
So, we have:
[tex]F_{No} = [100250 - \frac{101000}{2}] * 0.0155[/tex]
[tex]F_{No} = [100250 - 50500] * 0.0155[/tex]
[tex]F_{No} = 49750* 0.0155[/tex]
[tex]F_{No} = 771.125N[/tex]
A cannonball is shot from the top of a
47.8 m high hill at a speed of 53.7 m/s.
How fast is it going when it reaches
the plain below?
Answer:
61.8
Explanation:
It must be going at a speed of 61.81 m/s when it reaches the plain below
What are kinematic equations?
The kinematic equations are a set of equations that describe the motion of an object with constant acceleration. Kinematics equations require knowledge of derivatives, rate of change, and integrals.
using Kinematics equations
[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2gs ( a = g)
= [tex](53.7)^{2}[/tex] + 2 * 9.8 * 47.8 m
v = 61.81 m/s
It must be going at a speed of 61.81 m/s when it reaches the plain below
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How long does it take for a 3.5 kW electric water heater to heat 40 kg of water? from 20 ° C to 75 ° C? The specific heat capacity of water is 4190 J/kgK PLEASE HURRY ITS A TEST
Answer:
2633.7 s
Explanation:
From the question,
Heat lost by the water heater = Heat gained by the water
Applying,
P = cm(t₂-t₁)/t.................. Equation 1
Where P = power of the heat, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature, t = time
make t the subject of the equation
t = cm(t₂-t₁)/P.............. Equation 2
From the question,
Given: c = 4190 J/kgK, P = 3.5 kW = 3500 W, m = 40 kg, t₁ = 20°C, t₂ = 75°C
Substitute these values into equation 2
t = 4190×40(75-20)/3500
t = 9218000/3500
t = 2633.7 s
Help me with this please
HELP ME PLEASEEEEEEEEEEEEEEEE
A bowling ball of mass 2.2kg is rolling along a track at 3.2m/s when it reaches a
ramp angled at 55 degrees. The ball rolls up the ramp to the top where the track levels
out again, and the ball rolls at 0.3m/s. How long is the ramp?
Answer:
10m
Explanation:
Which of the following means that an
image is real?
A. +do
B. +di
c. -di
D.-do
Answer:
B
Explanation:
Use the drop-down menus to complete each sentence.
The number of half-lives changes. This is the _______ variable.
The number of radioactive atoms changes due to the number of half-lives. The number of radioactive atoms is
therefore the _______
variable.
Answer:
Independent, then dependent
Explanation:
Just took this on Edge 2021
What happens to the force of gravity between two masses if the mass of one of the objects decreases?
The force of gravity also increases
The force of gravity stays the same
The force of gravity decreases
none of these apply
It increases
Explanation:
The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between object
Answer:
C: Gravity decreases
Explanation:
im paying on my phone but dont have full access when i log into computer
Answer:
um let me know what i can do to try get you full access
Explatnation:
Write the differential equation that governs the motion of the damped mass-spring system, and find the solution that satisfies the initial conditions specified. Units are mks;
????
is the damping coefficient, with units of kg/sec.
m
This question is incomplete, the complete question is;
Write the differential equation that governs the motion of the damped mass-spring system, and find the solution that satisfies the initial conditions specified. Units are mks; γ is the damping coefficient, with units of kg/sec
m = 0.2, γ = 1.6 and k = 4
Initial displacement is 1 and initial velocity is -2
x" + _____ x' ____x = 0
x(t) =
Answer:
the solution that satisfies the initial conditions specified is;
x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]
Explanation:
Given the data in the question ;
m = 0.2, γ = 1.6, k = 4
x(0) = 1, x'(0) = -2
Now, the differential equation that governs the motions of spring mass system is;
mx" + γx' + kx = 0
so we substitute
0.2x" + 1.6x' + 4x = 0
divide through by 0.2
x" + 8x' + 20x = 0
hence, characteristics equation will be;
m² + 8m + 20 = 0
we find m using; x = [ -b±√(b² - 4ac) ] / 2a
m = [ -8 ± √((8)² - 4(1 × 20 )) ] / 2(1)
m = [ -8 ± √( 64 - 80 ) ] / 2
m = [ -8 ± √-16 ) ] / 2
m = ( -8 ± 4i ) / 2
m = -4 ± 2i
Hence, the general solution of the differential equation is;
x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]
From the initial conditions;
c₁ = 1, c₂ = 1
the solution that satisfies the initial conditions specified is;
x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]