Answer:
18 O, 17 O, and 16 O
Explanation:
three naturally stable isotopes
The stable forms of oxygen are molecular oxygen ([tex]O_{2}[/tex]) and ozone ([tex]O_{3}[/tex]). Molecular oxygen is the most common form in the Earth's atmosphere, while ozone is found in the ozone layer of the atmosphere and has a different molecular structure than [tex]O_{2}[/tex].
The most stable type of oxygen in the Earth's atmosphere is [tex]O_{2}[/tex], sometimes referred to as molecular oxygen or dioxygen. It is made up of two oxygen atoms joined by a link.
Another stable form of oxygen is [tex]O_{3}[/tex], also referred to as ozone. It is a molecule made up of three linked oxygen atoms. The ozone layer in the stratosphere of the Earth contains ozone, which is essential for protecting life on the planet by absorbing damaging ultraviolet (UV) radiation from the Sun.
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Look at the potential energy diagram below. What amount of energy does the products have ?
100
80
PE
50
AB
40
C D
20
Progress of the reaction
40 KJ
60 KJ
O 20 KJ
80 KJ
Answer:
20 kJ
Explanation:
The products are C + D which is on the right side of the diagram. And it says it has 20 kJ of energy.
Consider the proposed structure of carbon dioxide. Determine whether the structure is correct and justify your decision. Select one: This structure is correct due to the total number of bonds and electrons. This structure is correct due to allowed exceptions to the octet rule for the involved atoms. This structure is incorrect due to the total number of electrons for the involved atoms. This structure is incorrect because the octet rule is not fulfilled for all the atoms.
The question is incomplete, the complete question is found in the image attached to this answer
Answer:
This structure is correct due to the total number of bonds and electrons.
Explanation:
We know that all atoms in a compound are expected to obey the octet rule and we use this rule to ascertain the correctness of any chemical structure.
The structure of carbon IV oxide drawn perfectly satisfies the octet rule for each atom. Each atom in the molecule has eight electrons around its valence shell.
Therefore,since CO2 has sixteen valence electrons, we can conclude that; this structure is correct due to the total number of bonds and electrons.
Name each of the following species for the following acid-base reactions. (The equilibrium lies to the right in each case, i.e., the product side is favored. If the species is an ion, include the word "ion" in the name. Use systematic names such as "methanol" instead of archaic names like "methyl alcohol" or "wood alcohol".)
(a) H3O+ (hydronium ion) + CH3O- (methoxide ion) <--> *reverse reaction arrow*
acid:?
base:?
conjugate acid:?
conjugate base:?
(b) CH3CH2O- (ethoxide ion) + HCl (hydrogen chloride) <--> *reverse reaction arrow*
acid:?
base:?
conjugate acid:?
conjugate base:?
(c) NH2- (amide ion) + CH3OH (methanol) <--> *reverse reaction arrow*
acid:?
base:?
conjugate acid:?
conjugate base:?
Answer: a) [tex]H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O[/tex]
acid : hydronium ion
base : methoxide ion
conjugate acid : methanol
conjugate base: water
b) [tex]CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-[/tex]
acid : hydrogen chloride
base : ethoxide ion
conjugate acid : ethanol
conjugate base: chloride ion
c) [tex]NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-[/tex]
acid : methanol
base : amide ion
conjugate acid : ammonia
conjugate base: methoxide ion
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
The species accepting a proton is considered as a base and after accepting a proton, it forms a conjugate acid.
The species losing a proton is considered as an acid and after loosing a proton, it forms a conjugate base
For the given chemical equation:
a) [tex]H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O[/tex]
acid : hydronium ion
base : methoxide ion
conjugate acid : methanol
conjugate base: water
b) [tex]CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-[/tex]
acid : hydrogen chloride
base : ethoxide ion
conjugate acid : ethanol
conjugate base: chloride ion
c) [tex]NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-[/tex]
acid : methanol
base : amide ion
conjugate acid : ammonia
conjugate base: methoxide ion
.
help! help! plz............
1)What is most important of periodicity lest 4
2)why are energies of
various energy levels in hydrogen atomic are negative?
54.1miles/gallons how many liters of gas will be consumed traveling 132 km
Answer:
5.75 L.
Explanation:
From the question given above, the following data were obtained:
Rate = 54.1 miles/gallons
Distance = 132 km
Volume (in L) consumed =?
Next, we shall convert 132 km to mile. This can be obtained as follow:
1 km = 0.621 mile
Therefore,
132 km = 132 km × 0.621 mile / 1 km
132 km = 81.972 mile
Next, we shall determine the volume (in gallons) of the gas needed. This can be obtained as follow:
Rate = 54.1 miles/gallons
Distance = 81.972 mile
Volume (in gallon) =?
Rate = Distance / volume
54.1 = 81.972 / volume
Cross multiply
54.1 × volume = 81.972
Divide both side by 54.1
Volume = 81.972 / 54.1
Volume = 1.52 gallon.
Finally, we shall convert 1.52 gallon to litre (L). This can be obtained as follow:
1 gallon = 3.785 L
Therefore,
1.52 gallon = 1.52 gallon × 3.785 L / 1 gallon
1.52 gallon = 5.75 L
Therefore, 5.75 L of the gas will be consumed.
After mixing the solutions in a separatory funnel, the stopper should be ________and the liquid should be ________and the layers allowed to separate. When you get close to the interface between the layers, ________the funnel and________until the first layer______ is collected. _______to collect the second layer.
Answer:
The answer is below
Explanation:
The separation technique is used for separating immiscible liquids.
When separating, the stopper has to be removed when draining the lower layer so as to prevent a vacuum. If vacuum is allowed, the draining rate will reduce and stop.
The liquid should be mixed by shaking the funnel and then opening the stopcock so as the vent out gases.
When near interface between the layers, you should set your eye level so that you do not drain up to the second layer.
After completely draining the first layer, the second layer should be collected in a new flask.
After mixing the solutions in a separatory funnel, the stopper should be removed and the liquid should be mixed thoroughly and the layers allowed to separate. When you get close to the interface between the layers, get eye level with the funnel and slow the draining until the first layer is collected. Switch to a new flask to collect the second layer.
After mixing the solutions in a separatory funnel, the stopper should be removed and the liquid should be mixed thoroughly and the layers allowed to separate. When you get close to the interface between the layers, get eye level with the funnel and slow the draining until the first layer is collected. Switch to a new flask to collect the second layer.
Separatory funnel:It is used in liquid-liquid extractions to separate (partition) the components of a mixture into two immiscible solvent phases of different densities.The lab apparatus majorly used for the separation of the two immiscible solutes in the given mixture. For example, oil and alcohol. It is applicable to separate the solvent which are immiscible and which cannot be separated by steam distillation. This method is useful for liquids only.Learn more:
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Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . Suppose 14. g of hydrochloric acid is mixed with 6.55 g of sodium hydroxide. Calculate the minimum mass of hydrochloric acid that could be left over by the chemical reaction. Round your answer to significant digits.
Answer:
8.02 g of HCl could be left over by the chemical reaction
Explanation:
We propose the reaction:
HCl(aq) + NaOH (s) → NaCl (aq) + H₂O (l)
Ratio is 1:1. First of all, we determine the moles of reactants:
14 g . 1mol / 36.45g = 0.384 mol of acid
6.55 g. 1mol / 40g = 0.164 mol of base
If a determined mass of HCl, could be left; this means that the acid is the excess reagent.
For 0.164 moles of NaOH, we need 0.164 moles of HCl.
As we have 0.384 moles, (0.384 - 0.164) = 0.220 moles of acid are left over in the reaction. We convert the moles to mass:
0.220 mol . 36.45 g /1mol = 8.02 g
Given that a 0.130 M HCl(aq) solution costs $39.95 for 500 mL, and that KCl costs $10/ton, which analysis procedure is more cost-effective
Answer:
KCl is cost effective
Explanation:
In order to know this, we need to see how much it cost 1 g of each reactant. Let's begin with HCl
HCl:
In this case, let's calculate the moles of HCl in a 0.130 M solution and then, the mass of HCl using the molecular weight of 36.5 g/mol, to get the cost the HCl at the end using the given price:
nHCl = 0.130 moles/L * 0.5 L = 0.065 moles
mHCl = 0.065 moles * 36.5 g/mol = 2.3725 g
Cost HCl = 39.95 $ / 2.3725 g = 16.84 $/g
Conclusion, 1 g of HCl costs 16.84 $
KCl:
In this case, it's pretty obvious that 1 ton of KCl cost 10$, so, there is no need to do further calculations because 1 ton (or more than 1000 kg of the salt) it's just 10$. This is less expensive than the 16.84$ for just 1 g of HCl, so, final conclusion, KCl is more cost-effective.
Hope this helps
Determine the energy change in the following reaction. This reaction is considered ...
C6H12 + O2
CO2 + H2O + heat
energy absorbed is equal to the energy released
endothermic
O isothermic
O exothermic
Answer:isothermic
Explanation:
Answer:
Energy abosorbed = Energy released.
Thus ISOTHERMIC
Which mission is not going to explore outside of the solar system?
A. SAFIR
B. Europa Clipper
C. MIRI
D. Kepler
An irreversible change would be?
A.chipping ice to flakes
B.getting a hair cut
C.condensing steam
D.boiling water
Answer:
A. Chipping ice to flakes
Explanation:
You can't reverse the ice becoming flakes. They will stay like that until they melt
Nitric acid decomposes in light to form nitrogen dioxide, water, and oxygen, according to the following chemical equation.
4HNO3 (l â 4NO2(g) + 2H2O (l) + O2(g)
If 2.5 g nitric acid decomposes, what is the total volume of gas produced?
a. 0.050L
b. 0.22
c.0.89
d. 1.1L
Answer:
b. 0.22 L
Explanation:
Step 1: Write the balanced equation
4 HNO₃(l) ⇒ 4 NO₂(g) + 2 H₂O(l) + O₂(g)
Step 2: Calculate the moles corresponding to 2.5 g of HNO₃
The molar mass of HNO₃ is 63.01 g/mol.
2.5 g × 1 mol/63.01 g = 0.040 mol
Step 3: Calculate the moles of O₂ produced from 0.040 moles of HNO₃
The molar ratio of HNO₃ to O₂ is 4:1. The moles of O₂ produced are 1/4 × 0.040 mol = 0.010 mol.
Step 4: Calculate the volume corresponding to 0.010 moles of O₂
Assuming the reaction takes place at standard temperature and pressure, the volume of 1 mole of O₂ is 22.4 L.
0.010 mol × 22.4L/1 mol = 0.22 L
The octane rating of gasoline is a relationship of the burning efficiency of the given gasoline mixture to the burning efficiency of octane (C8H18). Like most hydrocarbons, octane reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reaction is
Answer:
C₈H₁₈(l) + O₂(g) ⇒ CO₂(g) + H₂O(l)
Explanation:
Let's consider the unbalanced equation for the combustion reaction of octane.
C₈H₁₈(l) + O₂(g) ⇒ CO₂(g) + H₂O(l)
We can begin balancing H atoms by multiplying H₂O by 9, and C atoms by multiplying CO₂ by 8.
C₈H₁₈(l) + O₂(g) ⇒ 8 CO₂(g) + 9 H₂O(l)
Finally, we get the balanced equation by multiplying O₂ by 12.5.
C₈H₁₈(l) + 12.5 O₂(g) ⇒ 8 CO₂(g) + 9 H₂O(l)
Answer:
The coefficents will be 2, 25 --> 16, 18
Explanation:
A student burned her magnesium sample according to the procedure and obtained a light gray product. Since the crucible looked dirty anyway, she skipped the steps to convert the Mg3N2 contamination to MgO, weighed the gray sample, and calculated the mass of her product. Was her resulting mass likely to be higher or lower the expected
Answer:
The resulting mass will be higher than expected
Explanation:
We have to keep this in mind; When magnesium is being burnt in air, two reactions are taking place. The first one is;
2Mg(s) + O2(g) ------> MgO(s) -------1
And
3Mg(s) + N2(g) -------> Mg3N2(s) ---------2
Now, if the steps that should be taken to convert Mg3N2 to MgO are not taken, the reaction is much quicker but a higher mass of solid is obtained than what was expected.
This higher mass of solid obtained owes to the fact that Mg3N2 from reaction 2 was not converted to MgO leading to contamination of the product.
Convert 65.4 m to mm.
Helppp please
Answer:65.4 meters= 65400 millimeters
Can someone help me with this? And provide an explanation on how they found their answer? Using conversion factors. I'm confused :(
You have used 3.0×102 L of distilled water for a dialysis patient. How many gallons of water is that?
Answer:
This would be 63 gallons :)
Explanation:
The Volume of water = 2.4 × 10² L
The Volume of water in gal = ?
The solution: We know that one gal is equal to 3.785 litter.
So in conclusion, 2.4 × 10²L × 1 gal / 3.785 L
2.4 × 10²L × 0.264 gal. L⁻¹
0.634 × 10² gal
Hopefully this helps :3
63 gal
what causes deep ocean currents to flow
Answer:Deep ocean currents (also known as Thermohaline Circulation) are caused by: ... The sinking and transport of large masses of cool water gives rise to the thermohaline circulation, which is driven by density gradients due to variations in temperature and salinity. The earth's rotation also influences deep ocean currents.
Explanation:
assume that the density of all solutions are 1.000g/ml 1. Calculate the molarity of calcium in 1.9g of calcium chloride diluted in 100 ml of Di water. 2 Calculate the concentration of both calcium and chloride lons in problem 1 in units of mg/mL, ug/L, mg/L and ug/mL. 3. Calculate the concentration of both calcium and chloride ion in problem 1 in units of ppm and ppb. You may assume that the density of the solution is 1.0 g/ml 4. You have been provided 100 ml of a 1000 ug/ml barium standard. What volume of this standard must be diluted to a final volume of 50 ml using DI water to produce a 30 ug/mL standard
Answer:
1. 0.1712M
2. 6.86mg/mL Ca, 12.14mg/mL Cl, 6860000ug/L Ca, 12140000ug/L Cl, 6860mg/L Ca, 12140mg/L Cl, 6860ug/mL Ca, 12140ug/mL Cl.
3. 6860ppm Ca and 12140ppm of Cl.
4. 1.5mL of the 1000ug/mL barium standatd must be taken.
Explanation:
1. Molarity is defined as the amount of moles of solute (Calcium chloride) present in 1L of solution.
The moles of CaCl₂ are:
1.9g CaCl₂ * (1mol / 110.98g) = 0.01712 moles
In 100mL = 0.10L:
0.01712mol / 0.10L = 0.1712M
2. The masses of Calcium and Chloride ions are:
1.9g * (40.078g Ca / 110.98g) = 0.686g Ca
And:
1.9g - 0.686g Ca = 1.214g Cl
mg/mL:
686mg Ca / 100mL = 6.86mg/mL Ca
1214mg Cl / 100mL = 12.14mg/mL Cl
ug/L:
686000ug / 0.1L = 6860000ug/L Ca
1214000ug/ 0.1L = 12140000ug/L Cl
mg/L:
686mg Ca / 0.1L = 6860mg/L Ca
1214mg Cl / 0.1L = 12140mg/L Cl
ug/mL:
686000ug Ca / 100mL = 6860ug/mL Ca
1214000ug Cl / 100mL = 12140ug/mL Cl
3. ppm are defined as mg/L, the ppm of Ca are 6860ppm Ca and 12140ppm of Cl
4. The solution must be diluted from 1000ug/mL to 30ug/mL, that is a dilution of:
1000ug/mL / 30ug/mL:
33.33 times must be diluted the solution.
As final volume of the diluted solution must be 50mL, the volume of the standard needed is:
50mL / 33.33 times = 1.5mL of the 1000ug/mL barium standatd must be taken
What is the percent enantiomeric excess (ee) of a mixture that has 86% of one enantiomer and 14% of the other
Answer:
86% - 14% = 72%
Explanation:
Some hypothetical alloy is composed of 25 wt% of metal A and 75 wt% of metal B. If the densities of metals A and B are 6.17 and 8.00 g/cm3 , respectively, and their respective atomic weights are 171.3 and 162.0 g/mol, determine whether the crystal structure for this alloy is simple cubic, facecentered cubic, or body-centered cubic. Assume a unit cell edge length of 0.332 nm
Answer:
Simple cubic
Explanation:
The density of metal A (ρa) = 6.17 g/cm³, The density of metal B (ρb) = 8 g/cm³, The atomic weight of metal A (Aa) = 171.3 g/mol, The atomic weight of metal B (Ab) = 162 g/mol, the unit cell edge length (a) = 0.332 nm, concentration of metal A (Ca) = 25%, concentration of metal B (Cb) = 75%
The average density is given by:
[tex]\rho_{ave}=\frac{100}{\frac{C_a}{\rho_a} +\frac{C_b}{\rho_b} } \\\\\rho_{ave}=\frac{100}{\frac{25}{6.17} +\frac{75}{8} } =7.45\ g/cm^3\\\\The\ average\ atomic\ weight\ is:\\\\A_{ave}=\frac{100}{\frac{C_a}{A_a} +\frac{C_b}{A_b} } \\\\A_{ave}=\frac{100}{\frac{25}{171.3} +\frac{75}{162} } =164.23\ g/mol\\\\The\ number\ of\ atoms\ per\ unit(n)\ is:\\\\n=\frac{\rho_{ave}*a^3*N_A}{A_{ave}} \\\\N_A=Avogadro\ constant=6.02*10^{22} \ mol^{-1},a=0.332\ nm=3.32*10^{-8}cm\\\\Substituting:\\\\[/tex]
[tex]n=\frac{\rho_{ave}*a^3*N_A}{A_{ave}} =\frac{7.45*(3.32*10^{-8})^3*6.02*10^{23}}{164.23} \\\\n=0.999\\[/tex]
n≅1
Since n≅1, the crystal structure for this alloy is simple cubic
Which would be another way to make the ice melt faster
Answer:
d because ur heating the ice and causing friction
Phosphorus is commercially prepared by heating a mixture of calcium phosphate, sand, and coke in an electric furnace. The process involves two reactions. 2 Ca3(PO4)2(s) 6 SiO2(s) 6 CaSiO3(l) P4O10(g) P4O10(g) 10 C(s) P4(g) 10 CO(g) The P4O10 produced in the first reaction reacts with an excess of coke (C) in the second reaction. Determine the theoretical yield of P4 if 293.5 g Ca3(PO4)2 and 378.5 g SiO2 are heated. (No Response) g If the actual yield of P4 is 44.9 g, determine the percent yield of P4.
Answer:
76.6% is percent yield of P₄
Explanation:
Percent yield is defined as 100 times the ratio of actual yield and theoretical yield. To solve this quesiton we need to find the theoretical yield of the reaction. Using:
2Ca₃(PO₄)₂(s) + 6SiO₂(s) → 6CaSiO₃(l) + P₄O₁₀(g)
P₄O₁₀(g) + 10C(s) → P₄(g) + 10CO(g)
We need to find the moles of Ca₃(PO₄)₂ and SiO₂ to find limiting reactant. With limiting reactant we can find moles of P₄O₁₀ = Moles of P₄. We must convert the moles of P₄ to mass using Molar mass (P₄ = 123.895g/mol):
Moles Ca₃(PO₄)₂ -Molar mass: 310.1767g/mol-
293.5g * (1mol / 310.1767g) = 0.9462moles
Moles SiO₂ -Molar mass: 60.08g/mol-:
378.5g * (1mol / 60.08g) = 6.30 moles
For a complete reaction of 6.30 moles of SiO₂ there are required:
6.30 moles SiO₂ * (2 moles Ca₃(PO₄)₂ / 6 moles SiO₂) =
2.10 moles Ca₃(PO₄)₂. As there are just 0.9462 moles, Ca₃(PO₄)₂ is limiting reactant
Moles P₄O₁₀ = Moles P₄:
0.9462moles Ca₃(PO₄)₂ * (1mol P₄O₁₀ / 2 mol Ca₃(PO₄)₂) = 0.4731 moles P₄O₁₀ = Moles P₄.
The mass is:
0.4731 moles P₄ * (123.895g / 1mol) = 58.6g = Theoretical yield.
Percent yield is:
44.9g / 58.6g * 100 =
76.6% is percent yield of P₄In the desert, wind picks up and carries fine particles of sand and dirt. As 5 points
the wind blows against the rocks, the particles rub against the rocks and
wear them down in a process called: *
Weathering
Erosion
Deposition
Compaction/Cementation
What are the four Earth systems that contribute to the rock cycle?
C
It’s wrong I need points
The rock cycle includes the geosphere, hydrosphere, biosphere, and atmosphere. The wearing of the rock particles is called weathering. Thus, option a is correct.
What is weathering?Weathering is the process of sediment formation where the parent rocks and substances get disintegrated through natural biochemical and physical factors.
The parent rocks get deteriorated into smaller fine particles and sediments by the action of the strong wind and water. The movement causes the particles to dissolve the minerals on the surface.
The method of weathering, erosion, deposition, and compaction/ cementation is the part of the rock cycle that comprises the four major spheres including geosphere, hydrosphere, biosphere, and atmosphere.
Therefore, option a. in weathering the particles get disintegrated due to air and water.
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WHAT IS A PLACE WHERE BOOKS ARE CLASSIFIED! I NEED HELP!
Answer:
From the Online Catalog to the Shelf
Libraries in the United States generally use either the Library of Congress Classification System (LC) or the Dewey Decimal Classification System to organize their books. Most academic libraries use LC, and most public libraries and K-12 school libraries use Dewey.
Explanation:
Answer:
From the Online Catalog to the Shelf
Libraries in the United States generally use either the Library of Congress Classification System (LC) or the Dewey Decimal Classification System to organize their books. Most academic libraries use LC, and most public libraries and K-12 school libraries use Dewey.
Based on your understanding of color's relationship to wavelength, identify the approximate wavelength of light (nm) emitted by strontium when it was burned in Part C. (No quantitative data was collected for this; you are giving an approximate value only, based on what you observed.) Explain your reasoning in full, making sure to cite specific data and observations to support your answer.
Answer:
The flame colour of strontium is red. Red has a wavelength of around 620 to 750 nm.
Explanation:
Visible light is part of the electromagnetic spectrum. The electromagnetic waves are composed of electric and magnetic fields.
The visible spectrum is composed of seven different wavelengths that corresponds to different colours. When a metallic element is exposed flame, one of these colours is observed. This is commonly called the flame test.
The flame colour of strontium is red. Red has a wavelength of around 620 to 750 nm.
The approximate wavelength of light (nm) emitted by strontium when it was burned is red, where red has a wavelength of round 620-750 nm.
Wavelength of light emitted by strontiumGenerally, Visible mild is phase of the electromagnetic spectrum. the electromagnetic waves are composed of electric powered and magnetic fields. When a metal factor is uncovered flame, one of they seven colors of visible spectrum is seen.
The flame shade of strontium is red, where red has a wavelength of round 620-750 nm.
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How much energy is required to remove a neutron from the nucleus of an atom of carbon-13?
Answer:
uh i think 12?
Explanation:
Practice Problem Website: https://www3.nd.edu/~smithgrp/structure/workbook.html
1. Click on Do the problems
2. Click on the number for the practice problem to be completed
3. Click on IR
Example of problem 1 from the website:
Formula: C3H5BrO2
IR Peaks:
1717 nm—Strong peak indicates a carbonyl group C=O
2571-2670 nm- medium peak indicates sp3 hybrid C-H.
3067 nm --- Broad medium peak indicates OH group, specifically in a carboxylic acid (Would not be a carboxylic acid without the carbonyl peak as well)
Complete the following problems: 3, 5, 7, 8, 12, 13, 27, 32, 38, and 40.
Be as accurate as possible. I am looking for the frequency and molecular formula to make sense with the functional group you think is represented.
A sample of a mixture of salt and sugar has a total mass of 0.8920 g. If the sample contains 0.0982 g of salt, what percent of the sample is sugar?
Answer:
89%
Explanation:
The computation of the sample percentage is sugar is shown below:
As we know that
The mass of the total sample mixture is
= Mass of salt + mass of sugar
= 0.8920
And, the mass of salt is 0.0982 g
So, the mass of sugar is
= 0.8920 - 0.0982
= 0.7938 g
Now the percentage of the sample is sugar is
= 0.7938 ÷ 0.8920
= 89%
How many significant figures
are in this number?
3 x 10^6
Rotation about C-C single bonds allows a compound to adopt a variety of _____________. conformations configurations formations isomers projections are often used to draw the various conformations of a compound. conformations are lower in energy, while conformations are higher in energy. The difference in energy between staggered and eclipsed conformations of ethane is referred to as strain. strain occurs in cycloalkanes when bond angles deviate from the preferred °. The conformation of cyclohexane has no torsional strain and very little angle strain. The term "ring flip" is used to describe the conversion of one conformation into the other. When a ring has one substituent the equilibrium will favor the chair conformation with the substituent in the position.
Answer:
Conformation
Explanation:
Conformation refers to "any of the spatial arrangements which the atoms in a molecule may adopt and freely convert between, especially by rotation about individual single bonds"(Oxford dictionary).
Carbon-Carbon single bonds are known to undergo rotations about its axis. These rotations leads to various conformations. The energy difference between conformations may be low or high depending on the structure of the molecule. The difference in energy between conformations determines a molecules's preferred conformation.