Explain when acceleration remains constant.
Explanation:
acceleration remains constant when velocity does not increase or decrease
A child is stationary on a swing.(a)The child is given a push by his brother to start him swinging.His brother applies a steady force of 84 N over a distance of 0.25 m.(i) Calculate the work done by this force.(2)..............................................................................................................................................(ii) State how much energy is transferred by this force.(1)..............................................................................................................................................(iii) After several more pushes, the child has a kinetic energy of 71 J.The mass of the child is 27 kg.Show that the velocity of the child at this point is about 2.3 m/s.(2)(iv) Which one of these quantities changes in both size and direction while he is swinging?Put a cross ( ) in the box next to your answer.(1)Ahis gravitational potential energyBhis momentumCthe force of gravity acting on himDhis kinetic energy
Answer:
Work done = Fs
Explanation:
(i) W = Fxs
= 84N x0.25m
= 21 Joules
(ii) Ek = 1/2mv^2
71 = 1/2×27×v^2
71×2/27 = v^2
v = 23m/s
The work done by this force is 21 Joule.
Energy transferred by the force is 21 Joule.
The boy's momentum changes periodically, that is, in both size and direction.
What is force?An external force is an agent that has the ability to change the resting or moving condition of a body. It has a direction and a magnitude. So, it is a vector quantity. Newton is the SI unit of force (N).
(i) Given parameter:
Steady force applied by his brother, F = 84 N.
Displacement, d = 0.25 m.
The work done by this force, W = F.d = 84×0.25 = 21 Joule.
(ii) Amount of work done is transferred by this force as an energy. So, amount of energy transferred by the force is 21 Joule.
(iii) Given parameter:
Mass of the child, m= 27 kg.
Kinetic energy, E = 71 J.
Let, velocity of the child = v, then kinetic energy is,
E = 1/2 × mv²
⇒ v = √(2E/m)
= √(2×71/27)
= 2.3 m/s.
Hence, the velocity of the boy is 2.3 m/s. (proved).
(iv) During swing, his velocity changes periodically. That's why, his momentum changes periodically, that is, in both size and direction.
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what is the average speed of the toy car during the two trials to the nearest tenth of m/s
wait nvm the answer is D
Answer:
what is the average speed of the toy car during the two trials to the nearest tenth of m/s
wait nvm the answer is B
Explanation:
CARRY ON LEARNING
A particle has 37.5 joules of kinetic energy and 12.5 joules of gravitational potential
energy at one point during its fall from a tree to the ground. An instant before striking
the ground, how much mechanical energy.
Hi there!
[tex]\large\boxed{ME = 50 J}}[/tex]
Mechanical Energy = Potential Energy + Kinetic Energy, or:
E = U + K
Plug in the given potential and kinetic energies:
E = 12.5 + 37.5 = 50 J
The gravitational field strength on Mars is 3. 7 N/kg. Kai has a mass of 55 kg. What would Kai weigh on Mars? Give your answer to 1 decimal place.
Hi there!
Weight = mass × acceleration due to gravity (or gravitational field strength)
We can write this as:
W = mg
Plug in the given values:
W = 55 × 3.7
W = 203.5 N
Plzzzz help meeeeee plzzz
hun I wish I can help you but I have the same problem here!! sorry
Find the gravitational potential energy of a body of mass 25kg,kept at a height of 4m
Answer:
Massm=2.5kg
Massm=2.5kgGravitational potential energy is the work done against force of gravity is stored in the body at a height h .
Massm=2.5kgGravitational potential energy is the work done against force of gravity is stored in the body at a height h .P.E.=U=mgh
Massm=2.5kgGravitational potential energy is the work done against force of gravity is stored in the body at a height h .P.E.=U=mghU=2.5×10×15
Massm=2.5kgGravitational potential energy is the work done against force of gravity is stored in the body at a height h .P.E.=U=mghU=2.5×10×15U=25/10×10×=375j
A ball is launched from a slingshot. As the ball travels along its trajectory, what force(s) are acting on it? Select all that apply.
Group of answer choices
Force of air and gravitational force are acting on the ball when launched from the slingshot.
When a ball is launched from a slingshot, during its travel force of air as well as gravitational force are acting on the ball because there is air which moves opposite to the motion of a ball whereas the force of gravity attracts the ball downward.
The force of air slows down the motion of the ball while on the other hand, the force of gravity brings the ball to the ground due to attraction. If these two forces are not present then the ball continues its motion forever so we can conclude that force of air and force of gravity are acting on the ball when launched from the slingshot.
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A circular coil consisting of 500 turns with an area of 6.0x10-4 m 2 is rotating in a uniform magnetic field. At the start, the normal to the coil is perpendicular to the magnetic field. After 15s, the normal to the coil is 60⸰ with the magnetic field. The average induced emf is -0.058V. What is the magnitude of the magnetic field?
The magnitude of the magnetic field in the coil is 21.65 T.
The given parameters;
number of turns, N = 500 turnsarea of the coil, A = [tex]6\times 10^{-4} \ m^2[/tex]change in time, t = 15 sThe induced emf in the coil is determined by applying Faradays law;
[tex]emf =N \frac{d\phi }{dt} \\\\emf = N ( \frac{\phi _2 - \phi_1}{t} )\\\\emf= N(\frac{BAsin\ 60 - BAsin\ 90}{t} )\\\\emf = NBA(\frac{sin60 - sn90}{t} )\\\\-0.058 = 500(6\times 10^{-4})\times B\times (\frac{0.866 - 1}{15} )\\\\-0.058 = -0.00268B\\\\B = \frac{0.058}{0.00268} \\\\B = 21.65 \ T[/tex]
Thus, the magnitude of the magnetic field in the coil is 21.65 T.
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What is the weight, on Earth, of a book with a mass of 1. 5 kg? 1. 5 N 6. 5 N 11. 3 N 14. 7 N.
Answer:
The weight, on Earth, of a book with a mass of 1.5kg is 14.7N.
Explanation:
Hi there!
Weight of an object = mass (kg) × acceleration due to gravity (N/kg)
Plug in the given values using the g constant g = 9.8 N/kg:
W = 1.5 × 9.8 = 14.7 N
Mjchddjnfndndnddnndnddn
Answer:b
Explanation:
Thirty Joules of energy are transferred out of a system. The energy is lost through heat, mechanical, and electrical energy. If mechanical energy took up 10 J and electrical energy took up 5 J, how many Joules were lost through heat energy?
OPTIONS
5 J
15 J
30 J
45 J
Answer:
its 15 J i belive
Explanation:
if there is a gravitational force between all objects, why do we not feel or observe it?
Answer:
We do. It's just way too small compared to the force between the objects we're observing and the earth. It's like looking inside a room with an elephant and a grain of rice. The rice is there, it's just too small compared to the room and the elephant inside for you to notice it. Or, if you ever traveled on a plane, you can easily see the towns, or the roads, but not the single people walking the street.
To minimize signal distortion, at each end of the J-1939 CAN-bus there is a(n)_____________resistor.
22.13 .. Two very long uniform lines of charge are parallel and are separated by 0.300 m. Each line of charge has charge per unit length 5.20 mC>m. What magnitude of force does one line of charge exert o
Answer:
Two very long uniform lines of charge are parallel and are separated by 0.300 m. Each line of charge has charge per unit length.
Explanation:
Asap
A cyclist needs to spin 100 meters with a velocity of 5 m/s. How long will the cyclist take?
Answer:
[tex]v = \frac{d}{t} \rightarrow t= \frac{v}{d} \\ = 100m \div 5m. {s}^{ - 1} = \frac{100}{5} \\ \color{green} \boxed{ t = 20s}[/tex]
Which statements represent properties of intermolecular forces? Select all that apply.
1. As the temperature decreases, the kinetic energy of the particles increases, and the molecules will move more. This causes the
Intermolecular forces to decrease.
2. As the kinetic energy of the particles increase, the Intermolecular forces decrease. 3.As the distance between the particles decreases, the intermolecular forces Increase.
4. As the kinetic energy of the particles increase, the Intermolecular forces Increase.
Answer:
Two numbers
Explanation:
see it first
....................................
Answer:
yeah
Explanation:
Jefferson refers to
_____ rights in the Declaration of Independence.
Explain what these rights are:
Answer: natural
Explanation:
Answer:
natural i just copy tha answer in there i just explain it(づ￣ 3￣)づ
Explanation:
The meaning of the term “Pursuit of Happiness.” In the Declaration of Independence, Thomas Jefferson announced that every human being has “certain unalienable rights,” among which are those to “life, liberty, and the pursuit of happiness.” What did he mean by “the pursuit of happiness”?
Please help...
Will give the brainliest !!!
Please answer correctly
5) a) An alpha particle consists of 4 nucleons. Two of these are protons and two are neutrons. An alpha particle carries a charge of +2 (due to the particles having 2 protons).
b) A beta minus particle is a fast moving electron that's emitted from the nucleus. It's created when neutrons in the nucleus decays to form a proton & the beta particle.
c) A 3rd type of ionising radiation has no mass. It's called gamma radiation (gamma rays / X - rays). This type of radiation is a type of wave with a very short / low wavelength. (shortest wavelength among others)
d) Gamma radiation is a part of the electromagnetic spectrum.
_______
Hope it helps ⚜
a dragster accelerate to a speed of 112m/s over a distance of 398m/s. determine the acceleration (assume uniform) of the dragster
A 22 kg body is moving through space in the positive direction of an x axis with a speed of 190 m/s when, due to an internal explosion, it breaks into three parts. One part, with a mass of 13 kg, moves away from the point of explosion with a speed of 130 m/s in the positive y direction. A second part, with a mass of 2.2 kg, moves in the negative x direction with a speed of 460 m/s. What are the (a) x-component and (b) y-component of the velocity of the third part
Answer: Our notation is as follows : the mass of the original body is M=20.0kg ; its initial velocity is
ν
0
=(200m/s)
i
^
; the mass of one fragment is m
1
=10.0kg ; its velocity is
ν
1
=(100m/s)
j
^
; the mass of the second fragment is m
2
=4.0kg ; its velocity is
ν
2
=(−500m/s)
i
^
; and , the mass of the third fragment is m
3
=6.00kg . Conservation of linear momentum requires
M
ν
0
=m
1
ν
1
m
2
ν
2
+m
3
ν
3
.
The energy released in the explosion is equal to ΔK , the change in kinetic energy .
(a) Using the above momentum -conservation equation leads to
ν
3
=
m
3
M
ν
0
−m
1
ν
1
−m
2
ν
2
=
6.00kg
(20.0kg)(200m/s)
i
^
−(10.0kg)(100m/s)
j
^
−(4.0kg)(−500m/s)
i
^
=(1.00×10
3
m/s)
i
^
−(0.167×10
3
m/s)
j
^
.
The magnitude of
ν
3
is
ν
3
=
(1000m/s)
2
+(−167m/s)
2
=1.01×10
3
m/s
It points at θ=tan
−1
(−167/1000)=−9.48
∘
(that is at 9.5
∘
measured clockwise from the +x axis) .
(b) The energy released is ΔK :
ΔK=K
f
−K
i
=(
2
1
m
1
ν
1
2
+
2
1
m
2
ν
2
2
+
2
1
m
3
ν
3
2
)−
2
1
Mν
0
2
=3.23×10
6
J
Explanation:
please help me guys please
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Solution is in attachment ~
I hope that you got what you were looking for, and if there's different data then go through the same procedure, using same formula with different values and you will get your answer ~
[tex]\mathrm{✌TeeNForeveR✌}[/tex]
Answer:1.9 × 10³⁰
Explanation:
How to find resistance
Answer:
R = V/I
Explanation:
Example:
V = IR
R = V/I
If we were to use V = 120 and I = 0.25
R = 120/0.25
R = 480 Ohms
Your resistence would equal Ohms
The Maximum and Minimum resultant of two forces are 35N and 51N. What is the possible Value of the two forces ?
hplhevsdvakxjb1zonsvaka shdv
100N force is applied to a ball with a mass of 0.25kg. Calculate the ball acceleration.
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
Rory uses a force of 25 N to lift her grocery bag while doing 50 J of work. How far did she lift the
grocery bag?
Answer:
[tex]W=Fd \\ 50 = 25d \\ d = \frac{50}{25} \\ \color{yellow} \boxed{d = 2m}[/tex]
where would you look for the youngest stars in the milky way galaxy?
Answer:
at the center of the galaxy
Explanation:
as there r more new born stars found
Describe what introspection is.
Answer:
Introspection is a process that involves looking inward to examine one's own thoughts and emotions. ... The experimental use of introspection is similar to what you might do when you analyze your own thoughts and feelings but in a much more structured and rigorous way.
Explanation:
Example of it: The definition of introspection is self-examination, analyzing yourself, looking at your own personality and actions, and considering your own motivations. An example of introspection is when you meditate to try to understand your feelings. noun.
Answer: Introspection is when you examine your own thoughts, feelings, and emotions. A spiritual idea of introspection is like examining your soul while a pyschological way would be examining your mental state.
Explanation: tried my best
The brightest light detected from the star Antares has a frequency of about 3 x 10^(14) Hz. What is the wavelength of this light?
Taking into account the definition of wavelength, frecuency and propagation speed, the wavelength of a light with a frequency of 3×10¹⁴ Hz is 1×10⁻⁶ m.
First of all, wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.
The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f * λ
All electromagnetic waves propagate in a vacuum at a constant speed of 3x 10⁸ m/s, the speed of light.
In this case, you know:
v=3x 10⁸ m/s f= 3×10¹⁴ Hz λ= ?Replacing:
3x 10⁸ m/s= 3×10¹⁴Hz× λ
Solving:
λ= 3x 10⁸ m/s ÷ 3×10¹⁴Hz
λ=1×10⁻⁶ m
In summary, the wavelength of a light with a frequency of 3×10¹⁴ Hz is 1×10⁻⁶ m.
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