Answer:
4 Quarts = 1 Gallon
Step-by-step explanation:
1 is an integer and not a fraction. However, it can be expressed as a fraction in rational form as 1/1. So a possible answer is 1/1 gallon. I don't know for sure though its my best guess.
Choose the correct transformation.
what is the solution to this equation 4x -6 + 2x =18
Answer:
x=12
Step-by-step explanation:
4x-6+2x=18
2x-6=18
2x=24
x=12
Solve:
A.152
B.176
C.5
D.27
Answer:
Option B
176
Step-by-step explanation:
take 11 to the next side of the equation making the division multiplication getting us 16×11=176
Troy has 5/6 ounces of sprinkles to make cupcakes. The recipe uses 1/4 ounce per dozen of cupcakes. Write an expression which can be used to determine how many dozens of cupcakes Troy can make.
Help please? :)
Answer:
[tex]\frac{\frac{1}{4}}{1}=\frac{\frac{5}{6}}{x}[/tex]
Step-by-step explanation:
Per = 1
[tex]\frac{1}{4}[/tex]
So, if we were to solve:
[tex]\frac{1}{4}=\frac{5}{6x}[/tex]
[tex]\frac{1}{4}\cdot \:6x=1\cdot \:5[/tex]
[tex]\frac{3}{2}x=5[/tex]
[tex]\frac{3}{2}x\cdot \:2=5\cdot \:2[/tex]
[tex]3x=10[/tex]
[tex]\frac{3x}{3}=\frac{10}{3}[/tex]
[tex]x=\frac{10}{3}[/tex]
Troy can make [tex]\frac{10}{3}[/tex] dozen of cupcakes.
6 pounds of candy cost 22.44. What is the cost of one pound
Answer:
$3.74
Step-by-step explanation:
Proportions:
6 pounds ⇔ $22.44
1 pound ⇔ $ C
C = 22.44*1/6
C = $3.74
I don't know the answer to y=48,000(1-13.2)6
What are coordinate of (2,-3) when it is reflected over X axis.
Answer:
the asnwer is (2,3)
Step-by-step explanation:
what is the equation of this graph?
Answer:
y = x³ +2x² +x -1
Step-by-step explanation:
The attachment shows the four points we can read from the graph and the cubic regression function that fits them.
y = x³ +2x² +x -1
_____
Additional comment
It is useful to become familiar with the regression function capability of your graphing calculator or spreadsheet. Free or inexpensive apps are available for tablet or phone, and on the web.
if m * n = √(m²-n²) then 5 * 3 =
[tex]m \cdot n = \sqrt{m^2 -n^2}\\\\\text{When m =5 and n =3,}\\\\\\5\cdot 3 = \sqrt{5^2 -3^2} =\sqrt{25 -9} = \sqrt{16} = 4[/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{Assuming:}[/tex]
[tex]\mathbf{m\times n = \sqrt{(m^2 - n^2)}}[/tex]
[tex]\huge\textbf{Solving:}[/tex]
[tex]\mathbf{\rightarrow 5\times 3 = \sqrt{(5^2 - 3^2)}}[/tex]
[tex]\mathbf{\rightarrow 15 = \sqrt{(5\times5 - 3\times3)}}[/tex]
[tex]\mathbf{\rightarrow 15 = \sqrt{(25 - 9)}}[/tex]
[tex]\mathbf{\rightarrow 15 = \sqrt{16}}[/tex]
[tex]\mathbf{15\neq4}[/tex]
[tex]\huge\textbf{Thus, this answer should be:}[/tex]
[tex]\huge\boxed{\boxed{\textsf{This statement is most likely: \boxed{\textsf{FALSE}}}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
[tex]\frak{Amphitrite1040:)}[/tex]
Someone help pleaseeeee
Answer:
[tex]1. \: \: \: a = \frac{5}{7} \\ 2. \: \: \: 4 \\ 3. \: \: \: 15 {x}^{2} + 60x + 135 \\ 4. \: \: \: m = {75}^{o} \\ [/tex]
Step-by-step explanation:
[tex]1. \: \: 7a - 8 = 13 \\ 7a - 8 + 8 = 13 + 8 \\ 7a = 5 \\ \frac{7a}{7} = \frac{5}{7} \\ a = \frac{5}{7} \\ [/tex]
[tex]2. \: \: \: 4 = 2 \times 2 \\ 8 = 2 \times 2 \times 2 \\ 4 \\ [/tex]
[tex]3. \: \: \: 15 {(x + 3)}^{2} \\ 15(x + 3)(x + 3) \\15 (x + 3)(x + 3) \\ 15 |x(x + 3) + 3(x + 3)| \\ 15 ({x}^{2} + 3x + 3x + 9 )\\ 15( {x}^{2} + 6x + 9) \\ {15x}^{2} + 60x + 135 \\ [/tex]
[tex]4. \: \: \: m = {75}^{o} (opposite \: angles)[/tex]
A river flows at the rate of 12 feet per minute. What is the rate in second per foot?
Six grapefruit cost as much as a dozen oranges. The cost of a dozen grapefruit and two dozen oranges
is $12. If Susan purchased one orange and one grapefruit, how much did she spend? Show your
thinking.
a.Write System of equations for the above problem.
b. Solve the system of equations
c.Explain the meaning of the solution in the context of the problem.
Answer:
$0.73
Step-by-step explanation:
Let's say an orange costs O dollars and a grapefuit costs G dollars.
We add G dollars for each grapefuit and O dollars for each orange, so, for example, 12 grapefuit = G added 12 times = 12 *G = 12G
a.
6G = 10O
12G + 24O = 12
6 grapefuit = 6G = 10 oranges = 10O
b.
6G = 10O
12G + 24O = 12
We can solve this using substitution. First, we can solve the first equation for G. After that, we can plug that into the second to find O and go from there.
6G = 10O
divide both sides by 6 to remove the coefficient for G
G = (10/6)O
plug that into the second equation
12*(10/6)O + 24O = 12
20O + 24O = 12
44O = 12
divide both sides by 44 to solve for O
O=12/44 = 6/22
6G = 10O
6G = 60/22
divide both sides by 6 to solve for G
10/22 = G
c.
These solutions mean that an orange (O) costs 6/22 dollars and a grapefuit (G) costs 10/22, so 1O + 1G = 16/22 dollars ≈ $0.73. Note that O and G are kept as fractions because they are not exact dollar amounts, e.g. 0.27 repreating
Use <, >, or = to make the
statement true.
20[?]-1
Answer:
20 > -1
Step-by-step explanation:
Well 20 is a positive integer that is 20 units from 0 whereas -1 is a negative integer that is 1 unit behind zero.
help me pls..........
Answer:
1000x or 1000 thousand times greater
Step-by-step explanation:
every decimal to the left is 10x greater than the one right of it.
ABC and XYZ are similar triangles with right angles at B and Y. AC=13 cm,
BC=5 cm. Find AB and XZ. (No links pls...)
Answer:
See belowStep-by-step explanation:
Since B is the right angle, AC is the opposite side - hypotenuse.
Use Pythagorean and find the missing side, AB:
[tex]AB = \sqrt{AC^2-BC^2} = \sqrt{13^2-5^2} =\sqrt{144} =12cm[/tex]There is no info given to link the triangles ABC and XYZ and hence can't provide solution to any dimension of XYZ.
If the scale factor was given as k, then XZ would be:
XZ = k*BC = 5kFind the area of the triangle
[tex] =( \frac{1}{2} \times 10.4 \times 16.9) {ft}^{2} \\ = (5.2 \times 16.9) {ft}^{2} \\ = 87.88 {ft}^{2} [/tex]
Answer:
The area of the triangle is 87.88 square feet.
Hope you could get an idea from here.
Doubt clarification - use comment section.
A college is currently accepting students that are both in-state and out-of-state. They plan to accept two times as many in-state students as out-of-state, and they only have space to accept 200 out-of-state students. Let x = the number of out-of-state students and y = the number in-state students. Write the constraints to represent the incoming students at the college. X > 0 and y > 0 0 < x ≤ 200 and y > 400 0 < x and y < 200 0 < x ≤ 200 and 0 < y ≤ 400.
The constraints to represent the incoming students at the college are [tex]0<x \leq 200[/tex] and [tex]0<y \leq 400[/tex] and this can be determined by using the given data.
Given :
College plans to accept two times as many in-state students as out-of-state, and they only have space to accept 200 out-of-state students.x is the number of out-of-state students and y is the number of in-state students.The following steps can be used in order to determine the constraints to represent the incoming students at the college:
Step 1 - The inequalities are formed in order to determine the constraints to represent the incoming students at the college.
Step 2 - The linear equation that represents the situation "two times as many in-state students as out-of-state" is:
[tex]y = 2x[/tex]
Step 3 - The inequality that represents the situation "college only have space to accept 200 out-of-state students" is:
[tex]0<x \leq 200[/tex]
Step 4 - So, the inequality that represents the maximum number of in-state students that college can take is:
[tex]0<y \leq 400[/tex]
Therefore, the correct option is D).
For more information, refer to the link given below:
https://brainly.com/question/19491153
Solve for W
4w^2+9w= -2
Answer:
[tex]w_1=-\frac{1}{4},w_2=-2}[/tex]
Step-by-step explanation:
[tex]4w^2+9w=-2[/tex]
[tex]4w^2+9w+2=0[/tex]
[tex]w^2+9w+8=0[/tex]
[tex](w+1)(w+8)=0[/tex]
[tex](4w+1)(w+2)=0[/tex]
[tex]w_1=-\frac{1}{4},w_2=-2}[/tex]
If you can help, I’ll give brainliest
Answer:
sum of interior angles =180×3= 540°
m<F= 540-105-113-107-87
=128°
m<F= 128°
A= 3x3x3x3x3x5x7x7x7
B= 2x2x2x3x7x7x7x7
Find the Lowest Common Multiple (LCM) of A and B.
Please help
Answer:
LCM(57624, 416745) = 23,337,720 or LCM = 23337720
Step-by-step explanation:
List all prime factors for each number.
Prime Factorization of 57624 is:
2 x 2 x 2 x 3 x 7 x 7 x 7 x 7 => 23 x 31 x 74
Prime Factorization of 416745 is:
3 x 3 x 3 x 3 x 3 x 5 x 7 x 7 x 7 => 35 x 51 x 73
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 2, 3, 3, 3, 3, 3, 5, 7, 7, 7, 7
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 5 x 7 x 7 x 7 x 7 = 23337720
In exponential form:
LCM = 23 x 35 x 51 x 74 = 23337720
LCM = 23337720
Therefore,
LCM(57624, 416745) = 23,337,720
Under his cell phone plan, Jonathan pays a flat cost of $57 per month and $3 per gigabyte. He wants to keep his bill at $71.10 per month. Write and solve an equation which can be used to determine xx, the number of gigabytes of data Jonathan can use while staying within his budget.
Answer:
(71.10-57)/3=amount of gigabytes, 14.10/3=4 gigabytes allowed
Step-by-step explanation:
$71.10-$57=$14.10, the amount of money that Jonathan can spend on gigabytes. Then, determine how many times 3 can go into 14.10: 4 times. Jonathan can use four gigabytes and keep his bill under $71.10 a month.
What is the following sum? 2 (RootIndex 3 StartRoot 16 x cubed y EndRoot) 4 (RootIndex 3 StartRoot 54 x Superscript 6 Baseline y Superscript 5 Baseline) 4 x (RootIndex 3 StartRoot 2 y EndRoot) 12 x squared y (RootIndex 3 StartRoot 2 y squared EndRoot) 8 x (RootIndex 3 StartRoot x y EndRoot) 12 x cubed y squared (RootIndex 3 StartRoot 6 y EndRoot) 16 x cubed y (RootIndex 3 StartRoot 2 y squared EndRoot) 48 x cubed y (RootIndex 3 StartRoot 2 y EndRoot).
Equivalent expressions are expressions that have the same value, and can be used interchangeably.
The result of the sum [tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})[/tex] is [tex]4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})[/tex]
The expression is given as:
[tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})[/tex]
Rewrite the expression as:
[tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (\sqrt[3]{2^4x^3y}) + 4 (\sqrt[3]{3^3 \times 2x^6y^5})[/tex]
Evaluate the roots
[tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (2x\sqrt[3]{2y}) + 4 (3x^2y\sqrt[3]{2y^2})[/tex]
Open the brackets
[tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 4x\sqrt[3]{2y} + 12x^2y\sqrt[3]{2y^2})[/tex]
The above expression cannot be further simplified.
Hence, the result of the sum [tex]2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})[/tex] is [tex]4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})[/tex]
Read more about equivalent expressions at:
https://brainly.com/question/2972832
The sum of the expression is [tex]4 (\sqrt[3]{x^3y} +12x^2y(\sqrt[3]{ 2 y^2})\\[/tex].
We have to determine, the sum of the given expression.
According to the question,
Expression; [tex]2(\sqrt[3]{16x^3y} +4(\sqrt[3]{56x^6y^5})[/tex]
To determine the sum of the given expression following all the steps given below.
Rewrite the expression term in the form of their cubes,
[tex]\rm = 2(\sqrt[3]{16x^3y} +4(\sqrt[3]{56x^6y^5})\\\\ = 2(\sqrt[3]{2^4x^3y} +4(\sqrt[3]{3^3 \times 2 \times x^6y^5})\\\\= 2\times 2(\sqrt[3]{x^3y} +4\times 3(\sqrt[3]{ 2 \times x^6y^5})\\\\= 4 (\sqrt[3]{x^3y} +12x^2y(\sqrt[3]{ 2 y^2})\\\\=4 (\sqrt[3]{x^3y} +12x^2y(\sqrt[3]{ 2 y^2})\\[/tex]
Hence, The sum of the expression is [tex]4 (\sqrt[3]{x^3y} +12x^2y(\sqrt[3]{ 2 y^2})\\[/tex].
For more details refer to the link given below.
https://brainly.com/question/21798224
3 friends share a cake in the ratio of 5:7:4. the cake costs Rs.96 how much does each share cost?
Answer:
Cost of each share is [tex]6Rs[/tex]
Step-by-step explanation:
Let the cost be [tex]5x,7x,4x[/tex]
We have
[tex]5x+7x+4x=96\\\\16x=96\\\\x=6[/tex]
Cost of each share is [tex]6Rs[/tex]
Anna and Sam each want to run for president of their school's student body council. In order
to do so, they must collect a certain number of signatures and get a nomination. So far, Anna
has 20 signatures, and Sam has 25. Anna is collecting signatures at an average rate of 6 per
day, whereas Sam is averaging 5 signatures every day. Assuming that their rate of collection
stays the same, eventually the two will have collected the same number of signatures. How
long will that take?
Time
elapsed
Write a system of equations, graph them, and type the solution.
Answer:
6x+20=5x+25
5 days
Step-by-step explanation:
Let x = the days that they have the same amount of signatures
We know Anna has 20 currently and gets 6 per day, so we can use y=mx+b to describe her linear relationship.
We also know that Sam has 25 and gets 5 per day, so we can again use y=mx+b to describe his linear relationship.
Since both equations equal the variable y, we can say they equal each other and set up 6x+20=5x+25.
Then you subtract 20 from both sides and subtract 5x, so you are left with x =5, or 5 days until they have the same amount of signatures
Hope this made sense :D
ok i rly need help w this PLZ HELPPP
1. 2(x−4 1/2)=−6.
2. 3(p+2.55)=9 3/4
Answer:
1)x=1.5
2) p=0.7
Step-by-step explanation:
Find 48.9% of 264.Round to the nearest hundredth
Step-by-step explanation:
Simply divide the percent by 100 and multiply by the number. For example, 48.9 /100 x 264 = 129.096 or 0.489 x 264 = 129.096
Rounded to nearest hundredth
= 129.10
Answer:129.10
Step-by-step explanation:
Simply, the equation for the percentage value of a number is:
x*(z%/100%)=y
where x is your initial value, z is your percentage value, and y is the resultant value
for this question, the equations gives us as follows
264*(48.9%/100%)=129.096=129.10
Hi! Please help me!
Lightbulbs act as resistors. Janine is building a circuit that contains two lightbulbs in parallel. One of the lightbulbs has a
resistance of 120 ohms, but the resistance of the second lightbulb is unknown. She models the total
resistance in the
circuit, t, with this equation, in which r represents the resistance of the second lightbulb.
t =
1207
+ 120
Find the inverse of Janine's equation.
Look at photo below
Thank you have a nice day:)
Answer:
The answer is t^-1 (r)=120r/120-r
i hope this is right sry if im wrong have a good day :)
The inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .
What is resistance?Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω).
According to the question
Janine is building a circuit that contains two lightbulbs in parallel.
One of the lightbulbs has a resistance of 120 ohms.
R = 120ohms
r = resistance of the second lightbulb
t = total resistance in the circuit
[tex]t = \frac{120r}{r+120}[/tex]
Now,
The inverse of Janine's equation in which we will make r independent
[tex]t = \frac{120r}{r+120}[/tex]
[tex]t(r+120) = 120r[/tex]
[tex]tr + 120t = 120r[/tex]
[tex]120t = 120r - tr[/tex]
[tex]120t = r(120-t)[/tex]
[tex]r = \frac{120t}{120-t}[/tex]
Hence, the inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .
To know more about resistance here:
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i dont know someone help pls
Answer:
The answer is $242
Step-by-step explanation:
We can set up two equations for this one:
286 = 13 * (rate per hour)
divide both sides by 13:
22 = rate per hour
Then knowing her rate per hour is 22 dollars
22 * 11 hours of work = $242
At the same rate she will make $242 in 11 hours.
Kala made $286 for 13 hours of work . Therefore, let's find the rate.
What is rate:Rate is simply the ratio between two values with different units. In our case, its the amount made in dollars versus the time taken to make that amount.
Therefore,
rate = amount made(dollars)/ time taken(hours)
rate = 286 / 13
rate = 22 dollars per hour
At the same rate the amount she will make in 11 hours can be calculated as follows:
rate = amount / 11
22 = amount(dollars) / 11
cross multiply
amount(dollars) = 22 × 11
amount(dollars) = $242
learn more on rate here: https://brainly.com/question/8062121?referrer=searchResults
The price of an item has been reduced by 45%. The original price was $60. What is the price of the item now?
Answer:
the answer to the question is 15$
Can you help me explain
Answer:
6, 60, 0.6, 600 are the answers
the questions all use the same digits but that the powers of 10 are different between the dividends and divisors for some
Step-by-step explanation: