If you are more than 3,000 AGL, you must be flying at an odd-thousand MSL altitude +500 feet on a magnetic course of 0-179, in accordance with FAR 91.159. Additionally, if you are flying a magnetic course of 180-359, you should fly at an altitude of 1,000 feet plus 500 feet.
Altitude :
A distance measurement between a reference datum and a point or object, typically in the vertical or "up" direction, is known as altitude, height, or depth. Depending on the context, different definitions and reference points are used. Although the term "altitude" is frequently used to refer to a location's height above sea level, the term "elevation" is frequently preferred in the context of geography.
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while a-2 is dribbling, player a–1 sets a rear screen closer than one normal step, on stationary b-2. as b-2 turns and, prior to placing a foot to the floor, contacts a–1. official rules this is a team-control foul on a-1. is the official correct?
Yes, the official is correct. The rules state that when a player sets a rear screen he or she must give the defender enough time to avoid contact by making a move to the side of the screener.
What is contact?
Contact is the act of making physical contact or exchanging words with another person or object. More and more, the question is how on earth we would ever make contact with extraterrestrial life, not whether there's some other life in the universe. To establish communication, whether it be verbal, physical, or another type, is to "make contact" (the noun). It means to establish a certain communication to contact (the verb). Good luck if you're trying to get in touch with Madonna. She employs individuals whose sole responsibility it is to keep people like you from contacting her. Positive and negative contacts are present on batteries. They are the points of contact between the battery and the object receiving power.
Since B-2 had not yet placed a foot on the floor, A-1 did not give them enough time to avoid contact, therefore it was a team-control foul.
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if the earth were of uniform density, what would be the value of g inside the earth at half its radius? (the value of g at the surface of earth is 9.8 m/s2 .)
The value of g inside the earth at half its radius would be 4.9 m/s2. This is calculated by halving the surface gravitational acceleration (9.8 m/s2) due to the inverse square law of gravity.
What is gravity?
Gravity is indeed a fundamental interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force, the weak interaction, and the strong interaction are all significantly stronger than gravity, which is by far the weakest of a four fundamental interactions. As a result, it doesn't have any appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between objects and governs the motion of planets, celestial objects, galaxies, and even light.
The Moon's gravity causes sublunar tides inside the oceans, just as it does on Earth where gravity gives more weight to physical objects.
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what is the angular momentum if the force is 66 n, the moment arm is 7.7 m, and the time is 1.2 seconds?
The angular momentum is 609.84 kgm²/s². if the period is 1.2 seconds, then power is 66 n, and the attached please find is 7.7 m.
What in science is a force?The phrase "force" has a specific meaning in science. At this level, calling a force a push or perhaps a pull is entirely appropriate. A energy is not something an object "has in it" or that it "contains." One thing experiences a force from another. There are both living organisms and non-living objects in the concept of a force.
Briefing:x = m1x1 + m2x2 + m3x3 & y = m1y1 + m2y2 + m3y3/m1 + m2 + m3
x = 6*6 + 5*5 + 4(-4)/15
= 36 + 25 - 16/15
= 3
y = 6*0 + 5*5 + 4(-3)/15
25-12/15 = 13/15
(x,y) = (3, 13/15)
Let L = mvr - (i)
Also F = mu = mdv/dt
∫Fdt = m∫dv = Ft = mv + c -(ii)
When t = 0, v = 0, ⇒ c= 0
u becomes Ft = mv - (iii)
1/tu = L/Ft = r
L= Ftr
L = 66*1.2*7.7
L= 609.84 kgm²/s²
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what theoretical device would generate the maximum possible amount of work from a given amount of heat?
Answer:
An ideal "Carnot" engine
E = (Q2 - Q1) / Q2 or 1 - Q1 / Q2
Q1 (heat wasted) would have to be zero for 100% efficiency
consider that 224.0 j of work is done on a system and 313.9 j of heat is extracted from the system. in the sense of the first law of thermodynamics, what is the value (including algebraic sign) of w, the work done by the system?
The work done by the system including the algebraic sign is -89.9 J.
Work done on the system = W = 224.0 J
Heat extracted from the system = Q = - 313.9 J
Using the first law of thermodynamics,
The work done by the system is = U =
= U = Q + W
= U = -313.9 + 224.0
= U = -89.9 J
The First Law of Thermodynamics states that heat is a form of energy, and thermodynamic processes are therefore subject to the principle of conservation of energy. This means that heat energy cannot be created or destroyed.
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how much force in newtons is required to accelerate a 5 kg bowling ball at 2 m/s2?(1 point) responses 2.5 n 2.5 n 7 n 7 n 10 n 10 n 3 n
To accelerate a 5 kilogram bowling ball at 2 m/s2, 10N of force is needed.
How do you determine force?Newton's second principle of motion provides the definition of the force formula: An object's force is equal to its mass times its acceleration. F = m ⨉ a. To use this method, you must use SI units for force (newtons), mass (kilograms), and acceleration (meters per second squared).
What two categories of forces exist?Contact forces and function at a distance forces are the two different types of forces. Your daily use of force is evident. Basically, push and pull are forces. You exert force on an item when you push against it or pull against it.
Briefing:
To calculate F = ma,
multiply 5 kg by 2 m/s2.
which gives you 10N.
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a type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair. what spring constant is needed to produce a period of 0.5 s for a 0.015 kg mass?
According to the information available in the question, the force constant is 2.37N/m.
Using the relation;
T = 2π√m/k
T = period = 0.500 s
m = mass in kilograms = 0.0150-kg
k = spring constant = ?
Making k the subject of the formula;
k = 4π^2m/T^2
k = 4 × (3.142)^2 × 0.0150/(0.500 )^2
k = 2.37N/m
What is force?
A mass object's velocity changes when it is pushed or pulled. Its SI unit is Newton and its base SI unit is [tex]kgm/s^{2}[/tex]. A device, spring balance is used to measure force.
There are two effects of force, it changes the speed and the direction.
How much force is 1 newton?
1 newton is the amount of force, is the force required to accelerate a mass of 1 kg at 1 m per second with respect to time.
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a 140 nf capacitor is used in a standard 120 volt ac circuit with a frequency of 60 hz, what is the capacitive resistance?
A one hundred forty nf capacitor is utilized in a preferred one hundred twenty volt ac circuit with a frequency of 60 hz, the capacitive resistance = 18956 ohms.
What is a capacitor?
A capacitor is a device that stores electrical energy in an electric field by virtue of accumulating electric charges on two close surfaces insulated from each other. It is a passive electronic component with two terminals. The effect of a capacitor is known as capacitance.
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what can the radial velocity method determine about an exoplanet that the transit detection method cannot?
A transiting exoplanet in relation to the star that it is orbiting. The photometric approach can figure out a planet's radius whereas the radial velocity technique can tell you how much mass a planet has.
How can you find extrasolar planets using the radial velocity method?Utilizing the Doppler changes in the wavelength of the planet's star, the radial velocity approach finds extrasolar planets. A star would show a bluish change as it approached the earth. The radial velocity technique detects the redshift of the spectrum of a star that is travelling away from Earth.
Why is it that low mass stars benefit from the radial velocity method?Because of the fact that planets' gravitational pull on low mass stars is stronger and also because these stars often spin slower rate.
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The radial velocity method can determine the mass of an exoplanet, while the transit detection method cannot.
The radial velocity method, also known as the Doppler spectroscopy method, measures the slight shifts in the wavelength of light emitted by a star due to the gravitational tug of an orbiting exoplanet. This method allows scientists to determine the mass of the exoplanet. When an exoplanet orbits its host star, it induces a small wobble in the star's motion. By measuring these periodic changes in the star's radial velocity (motion along the line of sight), scientists can infer the mass of the exoplanet.
On the other hand, the transit detection method involves observing the periodic dimming of a star's brightness as an exoplanet passes in front of it, blocking a fraction of the star's light. This method provides information about the exoplanet's size, orbital period, and distance from its host star. However, it cannot directly determine the exoplanet's mass.
By combining the radial velocity method with the transit detection method, scientists can gather more comprehensive information about exoplanets. The combination of these two techniques enables the determination of an exoplanet's density, which provides insights into its composition and potential characteristics such as whether it is rocky or gaseous.
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Fill in the blanks. Convert c (speed of light) from m/s to ft/min using convvel in MATLAB.c is speed of light in m/s. cfpm is speed of light in ft/min. No space for this canvas code.c=physconst(_____);cfpm=convvel( _____,
Using MATLAB's convvel function, the formula c=physconst(lightspeed); cfpm = convvel(c, "m/s," "ft/min") converts the lightspeed from m/s to ft/min. In milliseconds per second.
C represents the lightspeed. In feet per minute, the definition of cfpm is the speed of light. A fundamental physical constant, typically abbreviated as c, the speed of light in a vacuum is significant in many branches of physics. 299,792,458 metres per second (about 300,000 kph; 186,000 mph) is the exact value for the speed of light.
The MathWorks company created the proprietary multi-paradigm programming language and computer environment known as MATLAB (short for "MATrix LABoratory"). With MATLAB, you may manipulate matrices, plot functions and data, employ algorithms, build user interfaces, and interact with other programming languages.
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As a result of the experiment scientists did with mexican tetras, it seems likely that their first hypothesis about blindness in the tetras is right. Explain how the result of the experiment supports their first hypothesis.
The first hypothesis put out by the researchers holds that the fish's blindness indirectly confers some form of evolutionary advantage.
Why can't the Mexican tetra see?
The loss of eyes is largely caused by cellular deterioration in the eye lens, according to experiments . Theoretically, the emergence of these eyeless fish was caused by this process in combination with natural selection over many generations.
Regressive evolution can be shown in cave fishes. This kind of evolution involves the loss of a property within a species. That characteristic is vision in cave fishes.
In conclusion, a finding supporting the theory that "blindness affords the fish some evolutionary advantage, although not directly" may be a greater fitness in fish relatives.
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A block with a mass M compresses a spring a distance A and is then released. The block travels along a horizontal surface and encounters a rough region with friction. The block comes to a stop after traveling a distance L along the rough region. How far along the rough region would the block travel if it had a mass of 2M? 4L L/2 OL OL L/4 O 2LPrevious question
The rough region would the block travel if it had a mass of 2M is L/2. Option B.
Solution:
[tex]\frac{1}{2}[/tex] KA² = MGL 2
Similarly, for the second case, we can write (let the distance traveled is x)
[tex]\frac{1}{2}[/tex]kA²= 2u Mgx
Dividing the above equations we can write,
[tex]2x = L \Rightarrow x = \frac{L}{2}[/tex]
A property of a body that is a measure of inertia is usually viewed as a measure of the amount of matter contained in the body that causes it to have weight in a gravitational field. Mass is a dimensionless quantity that describes the amount of matter in a particle or object.
The mass of an object is a measure of its inertial properties or the amount of matter it contains. The weight of an object is a measure of the force exerted on it by gravity, or the force required to support it. Mass can best be understood as the amount of matter present in an object or body. Everything around us has mass.
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a 600-kg satellite is in a circular orbit about earth at a height above earth equal to earth’s mean radius. find (a) the satellite’s orbital speed,
The satellite has an orbital speed of 5.59*103m/s, a revolution lasts 3.98 hours, and a gravitational force of 1.47*103N pulls on it.
What does orbital speed mean?The rate at which an object orbits central habitable zone of a system, which is often a large body, is known as its orbital speed. The earth orbits the sun at a speed of 108,000 km/h.
Briefing:(a). V² = Gm/R+h
Therefore
V² = 6.667*10⁻¹¹*5.98*10²⁴/2*6.38*10⁶
V = 5.59*10³m/s
(b). V = 2π (R + h)/T
Hence
T = 2π (R + h)/V
T = 2π (R + h)/2*3.14*6.38*10⁶/5.59*10³
T = 3.98 hours
(c). F = GMm/R+h²
Therefore
F = 6.67*10⁻¹¹*5.98*10²⁴*650/2*6.38*10⁶
F = 1.47*10³N
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The complete question is-
A 650-kg satellite is in a circular orbit about Earth at a height above Earth equal to earth’s mean radius. Find (a) the satellite’s orbital speed, (b) the period of its revolution, and (c) the gravitational force acting on it.
A rock with density 2300 kg/m3 is suspended from the lower end of a light string. When the rock is in air, the tension in the string is 38.0 N. What is the tension in the string when the rock is totally immersed in a liquid with density 750 kg/m3?
The tension in the string when the rock is totally immersed in a liquid with density 750 kg/m3 is 25.6 N
How to solve for the tensionThe upward buoyant force of a given object can be said to be the same as the weight that it has.
The formula that would be used to get the tension is given as
[tex]mg [1 - \frac{P_{u} }{P_{object} } ][/tex]
Where we have Pu = 750 this is the liquid density
mg = 38.0 N. This is the tension in the string
P object is the rock density = 2300
[tex]38[1-\frac{750}{2300} ][/tex]
38 * 1 - 0.3260
38 * 0.674
= 25 . 6N
The tension is 25.6N
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adisk of mass 2 kg and radius o.26 m hangs in the xy plane froma horizontal low-friction axle. the axle is o.07 m from the center of the disk. what is the frequency f of small-angle oscillations of the disk?
The frequency f of small-angle oscillations of the disk is:
f= 0.955Hz.
T = 2(π)²([tex]I_{s}[/tex] / mgh)
Given:
m = 2kg
r = 0.26m
h = 0.07m
[tex]I_{s}[/tex] = [tex]I_{c}[/tex] + md²
[tex]I_{c}[/tex] = [tex]\frac{mr^{2} }{2}[/tex] ( disk moment of Inertia)
d = h = 0.07
T = 2(π)²( [tex]\frac{mr^{2} }{2}[/tex] + [tex]\frac{m\frac{h^{2} }{2} }{mgh}[/tex] )
T = 2(π)² ( [tex]\frac{( r^{2} + 2h^{2} )}{2g}[/tex] )
T = 1.047s
f = [tex]\frac{1}{T}[/tex]
f = 0.955Hz
period
T = 1.047s
What is the definition of a frequency simple?
Frequency is the number of waves that pass a specific area in a defined amount of time. As a result, the frequency is 2 per second if a wave travels through in half a second.
What other names does frequency go by?
Cycles per second or temporal frequency are other terms for frequency. Frequency is often represented by the Greek letter ν or the Latin letter f. (nu).
Which five types of frequency are there?
Frequency Distribution Types
frequency distribution for groups.
Frequency distribution without grouping.
frequency distribution that is cumulative.
Frequency distribution relative.
distribution of the relative cumulative frequency.
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was newton a realist or anti-realist?
Answer: Newton was a realist
Explanation: Newton held a realist reading of scientific theory as based upon inference from facts and observation, and his gravitational theory (or NGT) as deduced from observed phenomena and Kepler's laws.
a line in the spectrum of atomic mercury has a wavelength of 254 nm. when mercury emits a photon of light at this wavelength, the frequency of this light is
The frequency of the light emitted by the mercury is 1.18×10¹⁵ Hz.
What is frequency?Frequency is the number of complete cycle covered by a wave in one seconds.
To calculate the frequency of the light, we use the formula below.
Formula:
f = v/λ.................. Equation 1Where:
f = Frequency of the light v = Speed of light wave λ = Wavelength of the lightFrom the question,
Given:
λ = 254 nm = 2.54×10⁻⁷ mv = 3×10⁸ m/sSusbtitute these values into equation 1
f = 3×10⁸/2.54×10⁻⁷ f = 1.18×10¹⁵ HzHence, the frequency of the light is 1.18×10¹⁵ Hz.
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After glycolysis, the potential energy of glucose is now in the potential energy of.
After glycolysis, the potential energy of glucose is now in the potential energy of two pyruvate molecules.
How does glycolysis works?The eleven steps of glycolysis are used to obtain energy from glucose molecules.The process of glucose metabolism begins here.Both aerobic and anaerobic circumstances can cause it.Pyruvic acid joins the citric acid cycle in aerobic conditions. It passes through an oxidative phosphorylation process, which produces ATP.Pyruvic acid changes into lactic acid in anaerobic conditions, producing a net of two ATP molecules.Two ATP molecules are used by one glucose molecule, while four ATP, two NADH, and two pyruvates are also produced. The citric acid cycle or other reactions use this pyruvate molecule as a precursor.What is glycolysis?When glucose (a 6-carbon molecule) is broken down into two molecules of pyruvate (a 3-carbon molecule) under aerobic conditions or into lactate under anaerobic conditions, a tiny quantity of energy is also produced.
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A proton and an electron are placed in an electric field. Which undergoes the lesser acceleration?.
Among proton and an electron which are placed in an electric field a proton will undergo lesser acceleration.
Why proton undergoes lesser acceleration?According to Newton's 2nd law ;
F[tex]net[/tex] = ma
m is the object's mass
a is its acceleration
F[tex]net[/tex] is the net force acting on it.
∴The electric force on a charged object is given by
F[tex]e[/tex] = Eq
Where,
F[tex]e[/tex] is the electric force
E is the electric field at the point where the object is
q is the object's charge.
Here, we assume that if the only force acting on the proton and electron is the electric force due to the electric field, that for both particles,
F[tex]net[/tex] = F[tex]e[/tex]
F[tex]e[/tex] = Eq
Eq = ma
a = Eq/m
We'll also suppose that the proton and electron are both subject to the same electric field. The charge of the proton and electron is the same (1.6 10⁻¹⁹ C). Their masses determine how differently they accelerate.
∴mass of proton = 1.67×10⁻²⁷kg
∴mass of electron = 9.11×10⁻³¹kg
Since an object's acceleration is inversely proportional to its mass, the electron will accelerate more slowly than the electron.
What is acceleration?The rate at which velocity varies with respect to time is referred to as acceleration. Since acceleration has both a magnitude and a direction, it is a vector quantity. Additionally, it is the first derivative of velocity with respect to time or the second derivative of position with respect to time.Can learn more about acceleration from https://brainly.com/question/12240608
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Two blocks, each of mass m=3.50kg, are hung from the ceiling of an elevator as in above figure. (a) If the elevator moves with an upward acceleration aof magnitude 1.60m/s 2, find the tensions T 1and T 2in the upper and lower strings. (b) If the strings can withstand a maximum tension of 85.0N, what maximum acceleration can the elevator have before a string breaks.
The tension in the upper and lower string is 79.8 N and 39.9 N respectively and the maximum acceleration of the elevator at tension of 85 N is 2.34 m/s².
(a) Mass of blocks = m = 3.5 Kg
Acceleration of the elevator = a = 1.6 m/s²
Gravitational force experienced by both strings = G
= m X g
= 3.5 X 9.8
= 34.3 N
For the lower block, apply Newton's Second Law of Motion,
Net force on the lower block =
= F = T₂ - (m X g)
= (m X a) = T₂ - (m X g)
= T₂ = (m X a) + (m X g)
= T₂ = m X (a + g)
= T₂ = 3.5 X (1.6 + 9.8)
= T₂ = 39.9 N
For the upper block, apply Newton's Second Law of Motion,
Net force on the Upper block =
= F = T₁ - T₂ - (m X g)
= (m X a) = T₁ - T₂ - (m X g)
= T₁ = T₂ + (m X g) + (m X a)
= T₁ = 39.9 + 3.50 X (9.8 + 1.6)
= T₁ = 79.8 N
(b) Now we know that T₁ > T₂, thus the upper string will break before the lower string. So, acceleration will increase when the upper string breaks.
Tension given = T₁ = 85 N
Acceleration = a =
= T₁ = T₂ + (m X g) + (m X a)
But, T₂ = m X (a + g)
Thus,
= T₁ = m X (a + g) + (m X g) + (m X a)
= T₁ = 2 X (m X a) + 2 X (m X g)
= a = (T₁ - ( 2 X (m X g))) / (2 X m)
= a = (85 - [ 2 X ( 3.5 X 9.8)] ) / (2 X 3.5)
= a = 2.34 m/s²
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a nuclear reactor has a rated capacity of 1 gw and produces 7.9 billion kwh/year. it is fueled using fuel rods that contain 2.5% 235u by mass. the accompanying electric generator is 98% efficient, the thermal cycle of the plant is 33% efficient and 90% of the thermal energy released during fissioning is transferred to the working fluid. a) what is the capacity factor of the power plant? b) what is the rate of u-235 consumption in g/s in order to deliver the average output? c) what is the total mass of fuel rods consumed each year? d) based on the amount of energy released in fission reactions, what is the reduction in mass of fuel each year?
The reduction in mass of fuel each year $0.0075/kW-hr 0.75 cents/kW-hr.
What is electrical energy?
1 GW plant operating at full load produces 1,000,000 kW and an annual electrical energy generation of
1,000,000 . 365 . 24 = 8.76 × 109 kW-hr
With a heat rate of 7.9 Billion Btu/kW-hr, this requires a heat addition rate of
1000000 . 7900000000 = 7.9 X 1014
fueled using fuel rods that contain 2.5% U-235 by mass means
2.5% = 250 ( Fuel carried about 100 tons )
the plant needs = 2.5 X 24 / 100 = 0.6 unit trains per day
If fuel costs $30 per ton, the annual cost of fuel will be
30 X 250 X 24 X 365 = $65,700,000
The cost of fuel alone per kW-hr, based on 100% annual plant capacity, will be
65,700,000/(1000,000 X 365 X 24) = $0.0075/kW-hr 0.75 cents/kW-hr
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A student set up a test tube containing sodium bicarbonate and topped it with a volumeter, but forgot to add the Elodea plant! Which of the statements below gives the result that the student would be likely to observe?
A. The level of liquid in the volumeter would rise due to diffusion.
B. The level of liquid in the volumeter would remain constant since gas is being produced and used at the same rate.
C. The level of the liquid in the volumeter would remain constant since gas is neither being produced nor being used.
D. The level of liquid in the volumeter would fall since there is less mass in the test tube.
E. The level of liquid in the volumeter would fall since atmospheric pressure is greater than the pressure within the test tube.
The result that the student would be likely to observe when A student set up a test tube containing sodium bicarbonate and topped it with a volumeter, but forgot to add the Elodea plant is he level of the liquid in the volumeter would remain constant since gas is neither being produced nor being used. the correct answer is c.
A volumetric meter can be described as any instrument used to measure the volume of solids, liquids, or gases.
Sodium bicarbonate dissolves in water to form carbonic acid and sodium hydroxide. This carbonic acid is further broken down into water and carbon dioxide.
The carbon dioxide produced can be used by Elodea plants for photosynthesis, a process that uses carbon dioxide to produce oxygen and energy.
However, in this case he did not add the Elodea plant, so no sodium bicarbonate was consumed or produced, and the volumetric level remained constant.
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suppose that a flat loop of wire with an area of 0.050 m2 lies in a magnetic field normal to the loop. if the magnetic field changes at a uniform rate from 0.30 t to 1.5 t it induces an emf of 1.2 volts in the loop. find the time interval for the change.
The total time interval of magnetization is 6.28sec.
Given - Area is 0.050 m²
Magnetic field is perpendicular to loop.
M1=0.30 T and M2= 1.5T
electromotive force V=1.2 volt
To find the time interval for the change following concept used-
The Biot-Savart law can be used to determine the magnetic field caused by a current. To demonstrate in a qualitative way that the net magnetic field direction is along the central axis from the loop, we first take into consideration arbitrary segments on the opposite sides of the loop.For a strong uniform field to exist in the middle of the loops, Helmholtz coils typically have equal-radius loops with current flowing in the same direction. A magnetic bottle that can momentarily hold charged particles in place uses a similar application of the magnetic field distribution produced by Helmholtz coils.[tex]T=2\pi \frac{M2-M1}{V}[/tex]
T= 2 x 3.14 x 1.20/1.2
=6.28sec
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45 hard student solutions manual starting with an initial speed of 5.00 m/s at a height of 0.300 m, a 1.50-kg ball swings downward and strikes a 4.60-kg ball that is at rest, as the drawing shows. image described by surrounding text. problem 45 (a) using the principle of conservation of mechanical energy, find the speed of the 1.50-kg ball just before impact. (b) assuming that the collision is elastic, find the velocities (magnitude and direction) of both balls just after the collision. (c) how high does each ball swing after the collision, ignoring air resistance
The speed of the 1.50-kg ball just before impact is 5.557 m/s . After assuming that the collision is elastic, the velocities of both balls just after collision is -2.873 m/s and 2.684 m/s. After ignoring the air resistance, the ball swings up to the height of 0.420 m and 0.367 m.
(a) Initial speed = u = 5 m/s
Height = h = 0.3 m
Using the principle of conservation of mechanical energy, find the speed of the 1.50-kg ball just before impact,
= V = √ (2gh + u²)
= V = √ (2 X 9,81 X 0.3 + 5²)
= V = 5.557 m/s
(b) Initial speed = u = 5 m/s
Height = h = 0.3 m
Weight of the ball = 4.6 Kg
Velocity of 1.50 Kg ball = u'
Velocity of 4.60 Kg ball = v
Now, assuming that the collision is elastic, find the velocities (magnitude and direction) of both balls just after the collision,
= 1.50(5.557 - u) = 4.60v
= 5.557 - u = 3.14v [let this be equation 1]
and,
= 1.50(5.55² - u²) = 4.60v²
= 5.557² - u² = 3.14v² [let this be equation 2]
By dividing 1 and 2,
= 5.557 + u = v [let this be equation 3]
Now, adding 1 and 3,
= 11.114 = 4.14v
Substituting this in equation 3,
= u = -2.873m/s
Thus, for 1.50 kg ball, velocity is -2.873 m/s and that of 4.60 Kg ball is 2.684 m/s.
(c) To find the height,
For a 1.50 Kg ball, h =
= h = u² / 2g
= h = -2.873² / 2 X 9.8
= h = 0.420 m
For a 4.60 Kg ball, h =
= h = u² / 2g
= h = 2.684² / 2 X 9.8
= h = 0.367 m
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a 2 ω resistor is connected to a battery with an emf of 6.30 v. what is the total power dissipated by the resistor?
The total power dissipated by the resistor is 6.30 V x 3.15 A = 19.845 W.
What is power?
The quantity of energy transferred as well as converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power inside the International System of Units. Power is sometimes referred to as activity in older works. A scalar quantity is power.
Power has been related to other factors; for instance, the power required to move a ground vehicle is equal to the product of the vehicle's velocity, traction force on its wheels, and aerodynamic drag. A motor's output power is calculated by multiplying its torque output by the angular velocity of its driveshaft.
The total power dissipated by the resistor is equal to the voltage of the battery multiplied by the current through the resistor.
Since the voltage of the battery is 6.30 volts, and the resistance of the resistor is 2ω, then the current through the resistor is equal to 6.30 V/2ω = 3.15 A.
Therefore, the total power dissipated by the resistor is 6.30 V x 3.15 A = 19.845 W.
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suppose astronomers built a 140-meter telescope. how much greater would its light-collecting area be than that of the 10-meter keck telescope? express your answer using two significant figures. nothing request answer
The light collecting area of 140 m telescope is 196 times greater than 10 m telescopes.
The light collecting area is directly proportional to square of aperture:
A ∝ l²
Aperture of Keck Telescope = l₁ = 10 m
Aperture of 11 m telescope, l₂ = 140 m
Light collecting area of Keck telescope = A₁
Light collecting area of 110 m telescope = A₂
A₁ ∝ l₁²
A₂ ∝ I₂²
A₂/A₁ = I₂²/ l₁² = (140 m)²/(10 m)² = 196
Therefore, the light collecting area of 140 m telescope is 196 times greater than 10 m telescope.
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When you view a distant rainbow, you view from each single water drop that contributes to the bow.
Answer:
Yes the light travelling gets refracted through the tiny water droplets suspended in the air.
Explanation:
There are 2 types of rainbow which includes - Primary and secondary rainbow.
A primary rainbow is a coloured bow or arc that appears on a “screen” of water drops when light from a bright light source (the Sun or Moon) falls upon them. A thick “screen” of raindrops will produce more vivid colours than a thin curtain of fewer drops.
A secondary rainbow is appears outside of a primary rainbow and develops when light entering a raindrop undergoes two internal reflections instead of just one.
Therefore whatever we see comes from each single water drop due to refraction.
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a thin hubcap is modeled by the part of the sphere that lies above the plane , and is made of a material of constant density . what is the moment of inertia of when it is rotated around the -axis?
The moment of inertia of when it is rotated around the -axis [tex]\frac{10\pi }{3}[/tex].
Solution:
= [tex](\sqrt{2\pi _{d6} } ) (\sqrt{3} \frac{r^{3} dr}{4-r^{2} }[/tex]
= [tex]2\pi *\frac{5}{3}[/tex]
= [tex]\frac{10\pi }{3}[/tex]
Consider a line that passes through the center of the ring and is perpendicular to the plane of the ring. Let R be the radius of the ring and M be its mass. All elements are at the same distance from the axis of rotation. The moment of inertia formula is the sum of the mass products of each particle multiplied by the square of the distance from the axis of rotation.
Moments of inertia oppose the rotational motion, so they are called moments of inertia rather than moments of force. A moment of inertia is defined with respect to a particular axis of rotation. The moment of inertia of a mass with respect to an axis is defined as the square of the mass times the distance from the axis.
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you drive a car forwrd with a constant speed. which of the following is true about the direction of the angular velocity of the wheels, w, relative to the direction the car is moving
The correct answer from the problem above about direction of the angular velocity of the wheels, ω, relative to the direction the moving car is:
The angular velocity of the wheels, ω is used to derive how quickly the wheel can rotate in a given period.
The correct answer choice is option b.
What is meant by angular velocity?An angular velocity can simply be defined as a vector quantity which determines how fast or the time rate a particular object revolve in relation to another point. From the context of the problem given above, the wheels of this moving object moves forward in a linear velocity below:
v = rω
Where:
v = linear velocity
r = radius
ω = angular velocity.
In conclusion, it can be therefore deduced from the explanation given above that angular velocity is the velocity along a circular path with respect to time rate.
Complete question:
You are driving a car forwrd with a constant speed. Which of the following is true about the direction of the angular velocity of the wheels, ω, relative to the direction the car is moving.
a. The greater the angular velocity of the wheels, ω, the lower the velocity of the car.
b. The angular velocity of the wheels, ω is used to derive how quickly the wheel can rotate in a given period.
c. a and b
d none of the above
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a particular light photon carries an energy of 3.4x10^-19 j. what are the frequency, wavelength, and color of this light
51.3 x 10^14 is the frequency and the wavelength is 0.58 x 10^-7 m .
What are frequency and wavelength?The distance between two wave crests, which also applies to troughs, is known as the wavelength. The frequency is measured in microseconds (Hz), which is the quantity of vibrations that cross a specific area in a second (Hertz).
Briefing :
Well use the Planck’s equation to find the frequency of the laser;
E = hν where;
E = energy
h = Planck's constant = 6.626 x 10-34 J·s
ν = frequency
3.4x10^-19 j = 6.626 x 10-34v
v = 3.4x10^-19 j −19/6.626 x 10-34
v = 51.3 x 10^14
To find wavelength;
v =c / λ where;
c = speed of light = 3 x 10^8 m/sec
51.3 x 10^14 = 3 x 10^8 / λ
λ = 3 x 10^8/51.3 x 10^14
=0.58 x 10^-7 m
Based on the wavelength of the laser which is 0.58 x 10^-7 m, the color of the laser is RED.
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