Answer:
4.2 mL
Explanation:
To make the problem more interesting, let's assume that you don't know the formula for dilution calculations.
The idea with diluting a solution is that the number of moles of solute will remain constant after the initial solution is diluted. The only thing that changes in such cases is the volume of the solution.
in which of the following compounds is the mass ratio of chromium to oxygen closest to 1.62 to 1.00? responses cro3 cro 3 cro2 cro 2 cro cro cr2o cr 2 o cr2o3
The compounds is the mass ratio of the chromium to the oxygen closest to 1.62 to 1.00 is CrO₃.
The Atomic mass of Cr = 52 g /mol
The Atomic mass of O = 16 g/mol
The mass ratio of the chromium to the oxygen is given below as :
1) CrO₃ = 52 / 16 × 3 = 1.08
2) CrO₂ = 52 / 16 ×2 = 1.63
3) CrO = 52 / 16 = 3.25
4) Cr₂O = 52 × 2 / 16 = 6.5
5) Cr₂O₃ = 52 × 2 / 16 × 3 = 2.1
Thus the compound correct mass ratio of chromium to oxygen closest to 1.62 to 1.00 is CrO₃.
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Please match each word with the correct description. (Lesson 1.01)
First layer of the
atmosphere
Layer that contains the
Ozone Layer
The layer of the atmosphere that has the least molecules
atmosphere that has the
least molecules
1. Troposphere
2. Stratosphere
3. Exosphere
Answer:
First layer of the atmosphere = Troposphere
Layer that contains the Ozone Layer = Stratosphere
The layer of the atmosphere that has the least molecules atmosphere that has the least molecules = Exosphere
Explanation:
From the formula for calcium acetate,Ca(C2H3O2)2, calculatethe mass of carbon that can be obtained from 65.3 g of thecompound.
The mass of carbon that can be obtained from 65.3 g of the compound is 19.83 grams of carbon,
First, you should calculate the % of carbon in calcium acetate
% of carbon - (12.01 x 4)/(40.08+12.01 x 4+ 1.008 x 6+16x 4)
% of carbon-48.04/158.168 x 100%
% of carbon 30.37% In 65.3 g of compound,
there are 65.3 x 30.37% -19.83 grams of carbon.
What do you mean by compound?
A object created by joining several different elements or parts. Particularly: a separate substance created by the chemical fusion of two or more substances in a certain weight-to-volume ratio. a fresh antibiotic substance.
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In which of the following intermolecular interactions will polar molecules, such as water, commonly participate? (Mark all that apply A. Hydrogen bonding with non-polar molecules B. Hydrogen bonding with polar molecules C. Van der Waal interaction with polar molecules D. Electrostatic interaction with lonic compounds
B. Hydrogen bonding with polar molecules is the inter molecular interactions will water participate commonly with polar molecules.
Why does water pull polar molecules toward it?Polarity causes the water molecules to attract each other. Water is polar despite possessing a zero net charge because of the structure of its molecules. The molecule's hydrogen ends are positive, and its oxygen ends are negative. Water molecules are attracted to other polar molecules and to one another as a result.
What polar molecules are drawn to water?The polarity of water enables hydrogen bonds to form whenever adjacent water molecules are drawn to each other by their opposing charges. Other polar molecules and ions, such as many biomolecules including sugars, nucleic acids, and certain amino acids, are also attracted to or attracted by water.
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T/F rf values should be kept in the range of 0.2 to 0.8 for the most effective separation when more than one compound is present in the sample.
The statement is true that rf values should be kept in the range of 0.2 to 0.8
Polar compoundsPolar will have higher Rf values than nonpolar compounds under the same developing conditions. Rf values should be kept in the range of 0.2 to 0.8 for the most effective separation when more than one compound is present in the sample. The less polar the solvent, the higher the Rf value.The fastest moving spot has the highest Rf value. polar (fastest moving), and the spot with the lowest polargo through the given link below to know more about rf values:-
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The hottest temperature yet recorded in Phoenix, Arizona, was 122 O F on June 26, 1990. IVhat is that temperature in 0 C? In K?
The temperature in Celsius and kelvin is 50°C and 323.15 K.
The three most used temperature scales for usage in business, science, and daily life are Kelvin, Celsius, and Fahrenheit.
A scale in Kelvin is absolute. There are no degree symbols after its values, which begin at absolute zero.
Both Celsius and Fahrenheit are relative scales. The degree symbol is used to indicate Fahrenheit and Celsius temperatures.
Given the temperature is 122°F
Temperature in Celsius is -
⇒ C = (F - 32)/1.80
⇒ C = (122 - 32) / 1.80
⇒ C = 90 / 1.80
⇒ C = 50°C
Temperature in Kelvin is -
K = 5/9(F - 32) + 273.15
⇒ K = 5/9 (122 - 32) + 273.15
⇒ K = 323.15 K
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would you expect the following compound to have a dipole moment? if the molecule has a dipole moment, specify its direction. select the single best answer.
The compound to have a dipole moment, the correct statement about the dipole moment is 4) The molecule has no dipole moment.
The molecule is CF₄, carbon tetrafluoride. The bond between the C - F is the polar covalent bond because of the greater electronegativity difference between the C and the F atoms. Even though it has no dipole moment because of the geometry that is tetrahedral geometry. The all the C - F bonds are arrange in such a manner that the dipole moment will cancel out each other.
Thus, the CF₄ molecule has no dipole moment. The molecule is the non - polar molecule.
This question is in complete , the complete question is :
Would you expect the following compound to have a dipole moment? if the molecule has a dipole moment, specify its direction. select the single best answer. CF₄
1) The dipole moment is oriented from the fluorine atom towards the carbon atom.
2) The dipole moment is oriented from the carbon atom towards the fluorine atom.
3) The orientation cannot be determined.
4) The molecule has no dipole moment.
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Caroline knows the amount of a compound in moles.To find the number of molecules in the given sample of her compound, which of these values must also be used in her calculation? a. mass of the sample in grams b. Avogadro's numberc. Omolecular mass of the compound d. atomic mass of each element in the compound
Caroline knows the amount of a compound in moles.To find the number of molecules in the given sample of her compound, b. Avogadro's number also must be used in her calculation.
About Avogadro's numberAvogadro's constant or “Avogadro's number” (symbol: L, NA) is the number of constituent particles (usually atoms or molecules) found in the amount of substance in one mole. Therefore, Avogadro's number is a proportional factor relating the molar mass of a substance to the mass of the sample. This value is equal to 6.022 140 857 (62) × 1023 mol−1.
Previous definitions of chemical quantities involved Avogadro's number, a historical term closely related to Avogadro's constant but defined differently: it was originally defined by Jean Baptiste Perrin as the number of atoms in one mole of hydrogen. It was later redefined as the number of atoms in 12 grams of the carbon-12 isotope and then generalized to relate the number of substances to their molecular weight.
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a gas is compressed from a volume of 5.42 l to a volume of 2.75 l by an external pressure of 748 torr. which of the following correctly reflect the calculations required to determine the work done on/by the system (the gas)? select all that apply.
The one which correctly reflect the calculation required to find the work done is a) W = - P ΔV = 266 J
The initial volume = 5.42 L
The final volume = 2.75 L
The change in volume , ΔV = final volume - initial volume
= 2.75 - 5.42
The change in volume , ΔV = - 2.67 L
The work done is expressed as :
Work done, W = - P ΔV
where,
ΔV = - 2.67 L
P = 748 torr = 0.984 atm
W = - P ΔV
W = - ( 0.98 × - 2.67 ) × 101.3 J ( 1 atm ⋅L = 101.3 J )
W = 266 J
The work done is 266 J.
A gas is compressed from a volume of 5.42 l to a volume of 2.75 l by an external pressure of 748 torr. which of the following correctly reflect the calculations required to determine the work done on/by the system (the gas)? select all that apply.
a) W = - P ΔV = 266 J
b) W = + P ΔV = - 266 J
c) none of the above
d) both a and b
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Which of the following are correct procedures for
handling microorganisms? Check all of the boxes
that apply.
Touch the microorganisms with your bare
hands.
Use aseptic techniques.
Wash your hands frequently.
Use disinfectants to clean lab surfaces.
The correct procedure for handling microorganisms is to wash your hands frequently to make preventive doings. For the safest reason, using Personal Protective Equipment is recommended.
What is Personal Protective Equipment?
Personal Protective Equipment (PPE) is equipment that must be used when working, according to the potential hazards and work risks on the job. This is used to maintain the safety of the workers themselves and those around them. Personal Protective Equipment must be in accordance with the type of work so that the safety and health of workers can be guaranteed.
Activities in the microbiology laboratory will always be closely related to the following things
Biological substanceChemical substancePhysics substanceThe tool used in assisting the examination or identification of microorganisms can be in the form of a Bunsen which uses spirit, which has flammable properties. If the test tube is not used carefully, it can break and can injure the limbs.
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Answer:
Use aseptic techniques, Wash your hands frequently, and use disinfectants to clean lab surfaces.
Explanation:
The density of air at ordinary atmospheric pressure and 25 ∘C is 1.19 g/L. What is the mass of the air in a room that measures 14.5×16.5×6.0 ft?
Answer:
40,827.34 g
Explanation:
First find the volume of the room and then multiply it by the density of air at ordinary atmospheric pressure and 25 ∘C.
In this case, the room has a length of 14.5 ft, a width of 16.5 ft, and a height of 6.0 ft.
volume = 14.5 ft x 16.5 ft x 6.0 ft = 1209.25 ft^3
To convert ft^3 to L, we can use the conversion factor 1ft^3 = 28.316846592 L
1209.25 ft^3 = 1209.25 * 28.316846592 = 34,416.99 L
Calculate the mass of the air in the room by multiplying the volume of the room by the density of air:
mass = 34,416.99 L x 1.19 g/L = 40,827.34 g
So, the mass of the air in the room is 40,827.34 g
The following carbocation is capable of rearranging to a more stable carbocation. Limiting yourself to a single 1,2-shift, suggest a structure for the rearranged carbocation.
Each carbocation is capable of rearranging to a more stable carbocation. Limiting yourself to a single 1,2-shift, suggest a structure for the rearranged
What is carbocation?
A carbocation is a molecule in which a carbon atom has a positive charge and three bonds. We can basically say that they are carbon cations. Formerly, it was known as carbonium ion. Carbocation today is defined as any even-electron cation that possesses a significant positive charge on the carbon atom.The ion which contains the positive charge on Carbon atom is called Carbocation. The ion which contains the negative charge on the Carbon atom is called Carbanion.A carbocation's prime job is to stop being a carbocation and there are two approaches to it. It can either get rid of the positive charge or it can gain a negative charge. Both method involves providing the missing electrons to the carbon lacking electrons.To learn more about structure refers to:
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the enthalpy of the overall reaction represented above can be determined by adding the enthalpies of reactions 1 and 2. which of the following could be reaction 2 ?
Most probably the reaction 2 could be A: "( 2NO(g)+O2(g)→2NO2(g) )".
Reaction 2 is the second step of the overall reaction, which is the formation of NO2 from NO and O2. The overall reaction is (2O3(g)+2NO(g)→2NO2(g) + 2O2(g) ).
From the given options, the best match for reaction 2 is (NO(g) + O2(g) → 2NO2(g) ) because it is a balanced equation that forms 2 moles of NO2 from 1 mole of O2 and 1 m0le of NO. This is consistent with the balanced equation of the overall reaction, which forms 2 moles of NO2.
Option A: 2NO(g) + O2(g) → 2NO2(g) forms 2 moles of NO2 but it consumes 2 moles of NO which is not consistent with the overall reaction.
Option B: 5NO(g) + O2(g) → 3NO2(g) forms 3 moles of NO2 but it consumes 5 moles of NO, again this is not consistent with the overall reaction.
Option C: NO(g)+O2(g)→2NO2(g), it is a balanced equation that forms 2 moles of NO2 from 1 mole of O2 and 1 m0le of NO.
Therefore, based on the information provided, the correct option for reaction 2 is C: NO(g) + O2(g) → 2NO2(g)
"
Complete question
Reachtion 1 = (2O2(g)→3O2(g) ).
Reachtion 2 = ?
Overall recation = (2O3(g)+2NO(g)→2NO2(g) + 2O2(g) ).
the enthalpy of the overall reaction represented above can be determined by adding the enthalpies of reactions 1 and 2. which of the following could be reaction 2 ?
A: 2NO(g)+O2(g)→2NO2(g)
B: 5NO(g)+O2(g)→3NO2(g)
C: NO(g)+O2(g)→2NO2(g)
D: None
"
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x consists of a flexible container with eight particles of a gas as shown. what happens to the pressure of the system when x is converted to the representations in (a), (b), and (c)?
When a gas is heated in a flexible container with constant pressure, the statement "The gas particles travel quicker" is accurate.
option (C)
The container's walls are struck more forcefully by the gas particles inside the container.
(a) Gas molecules lack a fixed form and a fixed volume. They grow till they fill their container. Gas molecules move readily both inside and outside of the container because they are fluid. Unless compressed, gas molecules are not very dense.
(b) Gas molecules mix and disperse as they diffuse and effuse (travel through small holes).
(c) The container's walls are struck more forcefully by the gas particles inside the container. The gas container's capacity expands as a result of the impact.
The gas container's capacity expands as a result of the impact. Gas molecule characteristics
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The complete question follows
x consists of a flexible container with eight particles of a gas as shown. what happens to the pressure of the system when x is converted to the representations in (a), (b), and (c)?
(a) pressure increased
(b) pressure decreased
(c) pressure is constant
what is the formula of manganese which contains 50.48% oxygen? Ar (Mn) = 64.94
(Hint: Oxide is the result of combining Mn and O.) Mn (Mass of the element, in g) (assuming 100 g of compound) elements in moles The smallest moles or moles of an element Multiplier mathematical model O 1. 49.5 2. _50,5 3.
What is the empirical equation for a manganese oxide with a 49.5 manganese content?(Hint: Oxide is the result of combining Mn and O.) Mn (Mass of the element, in g) (assuming 100 g of compound) elements in moles The smallest moles or moles of an element Multiplier mathematical model O 1. 49.5 2. _50,5 3.The chemical having the formula MnO2 is known as manganese dioxide.By elemental manganese oxidation, When oxygen in the environment interacts with elemental manganese, MnO2 is the result. In nature, manganese is typically found as manganese dioxide since elemental manganese cannot exist due to this reaction.(Hint: Oxide is the result of combining Mn and O.) Mn (Mass of the element, in g) (assuming 100 g of compound) elements in moles The smallest moles or moles of an element Multiplier mathematical model O 1. 49.5 2. _50,5 3.To learn more about manganese dioxide refer to:
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The Northville School Board has proposed this budget for the upcoming school year:
20% for school staff’s salaries
50% for school maintenance and upkeep
10% to refurbish the gymnasium
5% to upgrade the computer lab hardware
10% for new instruments for the music department
5% for new sports equipment
After a brief discussion, the school board revised the budget as follows:
20% for school staff’s salaries
50% for school maintenance and upkeep
10% to refurbish the gymnasium
10% to upgrade the computer lab hardware
5% for new instruments for the music department
5% for new sports equipment
In this case, the opportunity cost for
was
.
The opportunity cost for the new instruments for the music department is the 10% to upgrade the computer lab hardware
What is the opportunity cost here?The revision of the budget is that the school board had to redistribute the budget allocation for upgrading the computer lab hardware from 5% to 10%. This means that the school board had to make a trade-off in terms of allocating more budget for upgrading the computer lab hardware and less for other areas such as new instruments for the music department or new sports equipment.
This trade-off is known as the opportunity cost, as the school board had to give up the potential benefits of allocating more budget to those areas in order to allocate more budget to upgrading the computer lab hardware.
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Deduce the structure of a compound of molecular formula C4H9Br which exhibits the following 1H NMR spectrum.
The structure C₄H₉Br that is 2-bromo-2-methylpropane , exhibits the ¹H NMR is as follows :
CH₃
|
CH₃ - CH - CH₃
|
Br
In the 2-bromo-2-methylpropnae molecule, all the 9 protons has the same chemical environment and there no splitting of the ¹H NMR resonance. All the protons are chemically equivalent, and they will have the same resonance frequency in the NMR.
In the molecule , 9 protons of the 2-bromo-2-methylpropane, as all the hydrogen atoms are having the same chemical environment. In the the Chemical shift (a) of the 1.80 ppm on the ¹H NMR spectrum for the 2-bromo-2-methylpropane is present.
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A. The atomic number (Z) of an element is the number of protons in the nucleus of atoms of that element. Because the net charge on an atom is zero, the number of protons is equal to the number of electrons. Thus, the atomic number also gives the number of electrons in a neutral atom. The mass number (A) of an atom is the total number of nucleons (protons plus neutrons). Therefore, the number of neutrons in an atom can be found by subtraction:
Mass number – atomic number = number of neutrons
Atomic Number Mass Number Number of protons Number of neutrons Number of electrons Element Symbol
6 6
39 19
77 Xe
64 29
35 45
The Atomic Number, Mass Number, Number of protons, Number of neutrons, Number of electrons, Element, and Symbol is shown below:
Atomic Number = 6; Mass Number = 12; Number of protons = 6; Number of neutrons = 6; Number of electrons = 6; Element = Carbon, Symbol = CAtomic Number = 19; Mass Number = 39; Number of protons = 19; Number of neutrons = 20; Number of electrons = 19; Element = Potassium, Symbol = KAtomic Number = 54; Mass Number = 131; Number of protons = 54; Number of neutrons = 77; Number of electrons = 54; Element = Xenon, Symbol = XeAtomic Number = 29; Mass Number = 64; Number of protons = 29; Number of neutrons = 35; Number of electrons = 29; Element = Copper, Symbol = CuAtomic Number = 35; Mass Number = 80; Number of protons = 35; Number of neutrons = 45; Number of electrons = 35; Element = Bromine, Symbol = Br.What is the atomic number of an element?The atomic number of an element is the number of protons present in the nucleus of the atom of the element.
The mass number is the sum of the protons and neutrons in the nucleus of the atom of the element.
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consider the following two substances and their vapor pressures at 298 k . substance vapor pressure ( mmhg ) a 275 b 459 based on this information, compare the characteristics of the two substances. d
The characteristics of the two substances :
Substance A:
It has a higher boiling point.
It has higher heat of vaporization
Substance B:
It has the weaker intermolecular forces.
It is a gas at 300 mmHg
1) The substance A has the vapor pressure of 275 mmHg . It has low vapor when compared to the substance B . It has the higher boiling point and has the higher heat of vaporization.
2) The substance B has the vapor pressure of the 459 mmHg and it has the weaker intermolecular forces when compared to the substance A and also it is a gas at 300 mmHg.
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Enter your answer in the provided box. Ammonium hydrogen sulfide decomposes according to the following reaction, for which Kp = 0.11 at 250°C: NH4HS(s) ⇌ H2S(g) + NH3(g) If 59.4 g of NH4HS(s) is placed in a sealed 5.0−L container, what is the partial pressure of NH3(g) at equilibrium? PNH3 = __________atm
The partial pressure of NH3(g) at equilibrium is 0.122 atm.
To calculate the partial pressure of NH3(g) at equilibrium, we can use the equilibrium constant expression (Kp = [H2S][NH3]/[NH4HS]). We know that Kp = 0.11 at 250°C and that the initial amount of NH4HS is 59.4 g. Since we also know the volume of the container is 5.0 L, we can use the ideal gas law (PV = nRT) to convert the number of moles of NH4HS to pressure.
First, we need to convert the mass of NH4HS to moles:
n = m/M = (59.4 g) / (51.11 g/mol) = 1.162 moles
Next, we can use the ideal gas law to find the pressure of NH4HS at the start of the reaction:
P = (nRT) / V = (1.162 mol)(0.0821 atm·L/mol·K)(523 K) / (5.0 L) = 9.98 atm
At equilibrium, the sum of the partial pressures of H2S and NH3 must equal 9.98 atm. Therefore, we can use the equilibrium constant expression to find the partial pressure of NH3:
Kp = [H2S][NH3]/[NH4HS] = 0.11
[NH4HS] = [H2S][NH3] / Kp = (P_H2S)(P_NH3) / 0.11
We know that P_NH4HS = 9.98 atm, so we can solve for P_NH3:
P_NH3 = [NH4HS] * Kp / [H2S] = 9.98 atm * 0.11 / P_H2S
Since we know that the sum of the partial pressures of H2S and NH3 must equal 9.98 atm, we can substitute that in for P_H2S:
P_NH3 = 9.98 atm * 0.11 / (9.98 atm - P_NH3)
Solving for P_NH3, we get P_NH3 = 0.122 atm
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What is the correct reading of the volume in the pictured buret? Make sure to report your reading with the appropriate significant figures. Select one: a. 39.9 mL b. 39.5 mL c. 40.0 mL d. 39.950 mL e. 39.95 mL f. 40.05 mL
The correct reading of the volume in the pictured burette is e) 39.95 mL. The picture is attached below.
The purpose of the burette reading is to show that how much the solution has been dispensed, not the how much the burette contains. As compared to the volumetric glassware, the zero scale on the burette is written on the top. The Measurement scale on the burette is at the 1.0 intervals.
The intervals can be calculated as :
Intervals = (larger value - small value) / 2
Intervals = 1
The reading will be 39.95 mL.
Thus, according to the picture of the burette, the reading of the burette is the 39.95 mL.
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An energy _____ is the change of energy from one form to another. An energy _____ is the movement of energy from one object to another.
Urgent, will mark Brainliest.
An energy conversion is the change of energy from one form to another. An energy transfer is the movement of energy from one object to another.
What is energy conversion?Energy is a property of matter that gives us the ability to move or do work. The process of converting energy from one form to another is called energy transformation or energy conversion.
Energy is transformed in someplace every minute of every day. Thermal, electrical, nuclear, electromagnetic, mechanical, chemical, and sound energy are just a few of the many distinct sources of energy.
Energy transfer is the act of moving energy from one location to another.
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a student combines a solution of nacl(aq)nacl(aq) with a solution of agno3(aq)agno3(aq), and a precipitate forms. question which of the following is the balanced net ionic equation for the formation of the precipitate?
When a solution of NaCl (aq) and a solution of AgNO₃ (aq) are mixed, the net ionic equation is Na⁺ (aq) + Cl⁻ (aq) AgCl(s), and an AgCl precipitate is formed.
The net ionic equation is a chemical equation for a reaction that only lists the species involved.
In other words, an ionic equation is a chemical equation in which dissociated ions represent electrolytes in aqueous solution. Typically, this is a salt dissolved in water, with the ionic species indicated in the equation by (aq) to indicate that they are in aqueous solution.
The balanced equation will be as follows:
NaCl (aq) + AgNO₃ (aq) + AgNO₃ (aq) + AgCl(s)
Where (aq) stands for aqueous and (s) stands for solid.
In a separated aqueous solution, the total ionic equation will be:
Na⁺ (aq) + Cl⁻(aq) + Ag⁺ (aq) + NO3(aq) Ag⁺ + NO₃⁻(aq) + AgCl(s)
The spectator ions in this case are Ag⁺ and NO3 because they appear unchanged in both the product and the reagent. By writing the net ionic equation for these ions:
AgCl + Na⁺ (aq) + Cl(aq) (s)
AgCl will precipitate because it is an insoluble salt.
Finally, the net ionic equation is Na⁺(aq) + Cl⁻(aq) AgCl(s), and an AgCl precipitate is formed when a solution of NaCl(aq) is mixed with a solution of AgNO₃(aq).
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You need a KOAc solution at pH 5, which is 3 M in K+. Such a solution is used in bacterial plasmid DNA isolation. How many moles of KOAc and acetic acid (HOAc) do you need to make 500 mL of this solution?
1.73/2 approximately 0.86 moles of acetic acid must be added. KOAc should be used at a ratio of 3/2, or 1.5 moles.
Is acetic acid poisonous to people?Effects on People Acetic acid is a potent irritant to the skin, upper respiratory tract, eyes, and mucous membranes when inhaled as vapor. Sodium acetate mixtures of 80% or over can be corrosive when in contact with skin or eyes, severely burning any exposed tissue.
Using the Henderson-Hasselbalch equation, determine the quantity of acetic acid (x) required to produce a pH-5.0 solution that contains
3MK+(3 M KOAc). The pK of acetic acid is 4.76 (Table 2-4).
[tex]$$\begin{aligned}\mathrm{pH} & =\mathrm{p} K+\log \frac{[\mathrm{KOAc}]}{[\mathrm{HOAc}]} \\5 & =4.76+\log \frac{3}{x} \\0.24 & =\log 3-\log x \\0.24-0.48 & =-\log x \\0.24 & =\log x \\x & =1.73 \mathrm{M}\end{aligned}$$[/tex]
Therefore, for a 500 mL solution, the amount of acetic acid added should be 1.73/2 or 0.86 moles. The amount of KOAc should be 3/2 or 1.5 moles.
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Given the following balanced equation, determine the rate of reaction with respect to [O2]: 2O3 (g).....yields.....3O2 (g)
a. Rate = -2deltaO2 over delta t
b. Rate = -2/3delta O2 over delta t
c. Rate = +1/3delta O2 over delta t
d. Rate = +3delta O2 over delta t
e. it is not possible to determine without more information
The balanced equation is :
2O₃(g) -----> 3O₂(g)
The rate of the reaction with [O₂] :The correct option c) Rate = + (1/3) Δ[O₂] /Δt
The balanced chemical equation is as follows :
2O₃(g) -----> 3O₂(g)
The rate of the reaction is the speed of the reaction at which the product is formed from the reaction in the chemical reactions. The rate for the chemical reaction is expressed by the decrease in the concentration of the reactants or the increase in the concentration of the products:
The rate of reaction with respect to the [O₂] is expressed as :
The rate = + (1/3) Δ[O₂] /Δt
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A gas sample at a certain temperature has an initial volume of 5.345 L. What is the initial temperature of the sample if the volume and the temperature are changed to 4.345 L and 898.0 K, respectively? Assume that the pressure and the amount of the gas remain constant.
Answer:
1104 K
Explanation:
We can use Charles' Law: [tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]
Plugging in the numbers gives us the initial temperature to be 1104 K
If a person practicing yoga for one hour burns 285 kilocalories (kcal),
how many joules (J) of energy have they burned?
Using unit conversion, One hour of yoga can result in 285 kilocalories burned (kcal) 1192440 j of energy were burned.
Unit conversion is what?It involves changing a value stated in one unit of measurement into an equivalent value expressed in a different unit of measurement that is of the same kind.
The same attribute is expressed using a unit conversion, but in a different unit of measurement. For instance, time can be expressed in minutes rather than hours, and distance can be expressed in kilometers, feet, or any other measurement unit instead of miles.
We must convert the units using the provided data in order to solve this challenge.
information regarding the issue:
energy is equal to 285 kcal (kcal)
Energy measured in joules (j) equals.
A calorie (kcal) is equal to 4184 joules (j)
Kilocalories (kcal) are converted to joules (j), which gives us:
1 kcal = 285 kcal * 4184 j of energy.
1192440 j = energy
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Calculate the number of grams of sulfuric acid in 1 gallon of battery acid if the solution has a density of 1.31 g/ml and is 38.7 % sulfuric acid by mass.
Answer:
4.956 g/gallon * 0.387 = 1.91 g of sulfuric acid in 1 gallon of battery acid.
Explanation:
To calculate the number of grams of sulfuric acid in 1 gallon of battery acid, we can use the density of the solution and the percentage of sulfuric acid by mass.
First, we need to convert the density from g/ml to g/gallon. Since 1 gallon is equal to 3.785 L, we can multiply the density of 1.31 g/ml by 3.785 to get 4.956 g/gallon.
Next, we can use the percentage of sulfuric acid by mass to find the mass of sulfuric acid in the solution. To do this, we can multiply the mass of the solution by the percentage of sulfuric acid by mass, which is 0.387.
Consider the composition. information from the SDS. What is a possible name of this compound?
A. Glycine
B. Glycogen
C. Glycerol
This substance may also be known as glycol. Each chemical's characteristics, potential physical, mental, and environmental health risks, as well as safety precautions, are all covered in the SDS.
What do a compound and an element mean?Atoms of various elements are chemically mixed in compounds in a predetermined ratio. A pure chemical compound made of the same type of atom is referred to as an element. Composition. Different elements are found in compounds in a predetermined ratio, organized by chemical bonds in a predetermined way.
Which best explains a compound?A substance that has been chemically linked by the joining of two or more distinct components. Saltwater (NaCl), which is derived from the components sodium and chloride, and water (H2O), which is created from the elements and oxygen, are two examples of compounds.
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Covalent bond formation depends on the ability of atoms to...
a) share electrons with other atoms
b) donate electrons to other atoms
c) receive electrons from other atoms
d) share electrons with ions
e) capture electrons from gases
The correct answer is a) share electrons with other atoms.
Covalent bond formation occurs when atoms share electrons in order to achieve a stable electron configuration, also known as a full outermost electron shell. This is known as a covalent bond. In this type of bond, atoms share electrons in order to achieve a stable electron configuration. This is different from ionic bond formation, where atoms transfer electrons to each other in order to achieve a full outermost electron shell. Atoms collaborate with other atoms to form stable electron configurations in covalent bonds. In covalent bond, atoms share electrons with other atoms in order to achieve a stable electron configuration.
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