We define the following terms:
Lexicographical Order, also known as alphabetic or dictionary order, orders characters as follows:
For example, ball < cat, dog < dorm, Happy < happy, Zoo < ball.
A substring of a string is a contiguous block of characters in the string. For example, the substrings of abc are a, b, c, ab, bc, and abc.
Given a string, , and an integer, , complete the function so that it finds the lexicographically smallest and largest substrings of length .
Input Format
The first line contains a string denoting .
The second line contains an integer denoting .
Constraints
consists of English alphabetic letters only (i.e., [a-zA-Z]).
Output Format
Return the respective lexicographically smallest and largest substrings as a single newline-separated string.
Sample Input 0
welcometojava
3
Sample Output 0
ava
wel
Explanation 0
String has the following lexicographically-ordered substrings of length :
We then return the first (lexicographically smallest) substring and the last (lexicographically largest) substring as two newline-separated values (i.e., ava\nwel).
The stub code in the editor then prints ava as our first line of output and wel as our second line of output.
Solution:-
import java.util.Scanner;
public class Solution {
public static String getSmallestAndLargest(String s, int k) {
String smallest = "";
String largest = "";
smallest = largest = s.substring(0, k);
for (int i=1; i String substr = s.substring(i, i+k);
if (smallest.compareTo(substr) > 0)
smallest = substr;
if (largest.compareTo(substr) < 0)
largest = substr;
}
return smallest + "\n" + largest;
}
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
String s = scan.next();
int k = scan.nextInt();
scan.close();
System.out.println(getSmallestAndLargest(s, k));
}
}

import java.util.Scanner;

public class JoggerPro {

   public static void main(String[] args) {

       String days[] = {"Monday?", "Tuesday?", "Wednesday?", "Thursday?","Friday?","Saturday?","Sunday?"};

       System.out.println("Welcome to JoggerPro!");

       Scanner myObj = new Scanner(System.in);

       System.out.println("Do you want to continue?");

       String answer = myObj.nextLine();

       if (answer.toLowerCase().equals("y")){

           double totalMiles = 0;

           for (int i =0; i < 7; i++){

               System.out.println(" ");

               System.out.println("How many miles did you jog on " + days[i]);

               double miles = myObj.nextDouble();

               totalMiles += miles;

           }

           double average = totalMiles / 7;

           System.out.println(" ");

           System.out.println("You ran a total of " + totalMiles+ " for the week.");

           System.out.println(" ");

           System.out.println("The average mileage is " + average);

       }

   }

}

I'm pretty sure this is what you're looking for. I hope this helps!

Answer:

Written in Python

numVal = int(input("Input: "))

for i in range(numVal,0,-1):

    print(i)

print("Ready!")

Explanation:

This line prompts user for numVal

numVal = int(input("Input: "))

This line iterates from numVal to 1

for i in range(numVal,0,-1):

This line prints digits in descending order

    print(i)

This line prints the string "Ready!"

print("Ready!")

Answer:

import random

decisions = int(input("How many decisions: "))

for i in range(decisions):

   number = random.randint(0, 1)

   if number == 0:

       print("heads")

   else:

       print("tails")

Explanation:

*The code is in Python.

import the random to be able to generate random numbers

Ask the user to enter the number of decisions

Create a for loop that iterates number of decisions times. For each round; generate a number between 0 and 1 using the randint() method. Check the number. If it is equal to 0, print "heads". Otherwise, print "tails"

The ways that technology helps business professionals to be more efficient is that  Business professionals may stay more organized, communicate more effectively, and keep firms secure with the use of technology.

Technology makes it simpler to connect with employees by utilizing e-mail and memos, and it helps keep employee information and corporate paperwork a lot more organized using computers and software.

By streamlining time-consuming procedures, technology also increases office productivity. For instance, using document management software eliminates the need for manual data entry, filing, as well as in file retrieval.

Therefore, one can say that Technology can be used to safeguard private executive decisions, financial data, and other forms of proprietary information that gives a company a competitive edge. Simply simply, technology aids firms in protecting their ideas from rivals.

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Answer:

C and G

Explanation:

In C language, the asterisks, ' * ', and the ampersand, ' & ', are used to create pointers and references to pointers respectively. The asterisks are used with unique identifiers to declare a pointer to a variable location in memory, while the ampersand is always placed before a variable name as an r_value to the pointer declared.

Answer:

def __str__(self):

       return ('Year: %d, VIN: %s' %(self.year_made, self.car_vin))

Explanation:

Here you go! This should do it.

The program gives an implementation of the car record class which displays the model year and registration number of a car. The program written in python 3 goes thus :

class CarRecord :

#initialize a class named carRecord

def __init__(self):

#define the init method of the class

self.year_made = 0

#year car was made is initialized to 0 (integer)

self.car_vin = ' '

#vehicle registration is an empty string

def __str__(self):

#define an str method

return f"Year:{self.year_made}, VIN:{self.car_vin}"

#returns formatted display of the year and VIN number

my_car = CarRecord()

#creates an instance of the carRecord class

my_car.year_made = int(input())

#prompts user for the model year of the car

my_car.car_vin = input()

#prompts user for the model Vin number

print(my_car)

# display the details

A sample run of the program is given

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In python:

print(steps_walked / 2000)

Answer:

4

Explanation:

Input/output, datapath, control, and memory

There wrong its C bold it.

:)))))

Answer:

Press and hold the power button for up to 10 seconds, until your Mac turns off. If that doesn't work, try using a cellular device to contact Apple Support.

Explanation:

If that also doesn't work try click the following keys altogether:

(press Command-Control-Eject on your keyboard)

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

This makes the laptop (macOS) instruct to restart immediately.

Hopefully this helps! If you need any additional help, feel free and don't hesitate to comment here or private message me!. Have a nice day/night! :))))

Another Tip:

(Press the shift, control, and option keys at the same time. While you are pressing those keys, also hold the power button along with that.)

(For at least 10 seconds)

Answer:

Sentence: Jack or Peggy Zale must fix quickly the fax.

Correct: Either Jack or Peggy Zale must quickly fix the fax.

There are 2 errors in these sentence construction. In stating two persons as an option we must use the word "either" to indicate that you only have two choose from the two of them. The word "

Explanation:

The correct sentence would be "either Jake or Peggy Zale must quickly fix the fax".

In the question construction, there is a conjunction and misarrangement error.

In conclusion, the word " "either Jake or Peggy Zale must quickly fix the fax" is correct

Read more about conjunction

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Answer:

the clock rate of the first machine need to be 1.7 GHz

Explanation:

Given:

CPI of A = 1.9

CPI of B = 1.1

machine, B executes the same program with 20% less instructions and with a CPI of 1.1 at 800MHz

To find:

In order for the two machines to have the same performance, what does the clock rate of the first machine need to be

Solution:

CPU execution time = Instruction Count * Cycles per Instruction/ clock rate

CPU execution time = (IC * CPI) / clock rate

(IC * CPI) (A) / clock rate(A) =  (IC * CPI)B / clock rate(B)

(IC * 1.9) (A) / clock rate(A) = (IC * (1.1 * (1.0 - 0.20)))(B) / 800 * 10⁶ (B)

Notice that 0.20 is basically from 20% less instructions

(IC * 1.9)  / clock rate = (IC * (1.1 * (1.0 - 0.20))) / 800 * 10⁶

(IC * 1.9)  / clock rate =  (IC*(1.1 * ( 0.8))/800 * 10⁶

(IC * 1.9)  / clock rate =  (IC * 0.88) / 800 * 10⁶

clock rate (A) =  (IC * 1.9) / (IC * 0.88) / 800 * 10⁶

clock rate (A) =  (IC * 1.9) (800 * 10⁶) /  (IC * 0.88)

clock rate (A) = 1.9(800)(1000000)  / 0.88

clock rate (A) =  (1.9)(800000000)  / 0.88

clock rate (A) = 1520000000  / 0.88

clock rate (A) = 1727272727.272727

clock rate (A) = 1.7 GHz

Answer:

online toutoring.

helpful games give mind relaxation.

Answer:

Written in C

#include <stdio.h>

int main() {

   float salary;

   printf("Salary: ");

   scanf("%f", &salary);

   float HRA, DA;

   if(salary <= 10000){

       HRA = 0.20; DA = 0.80;

   }

   else if(salary >= 10000 && salary <= 20000){

       HRA = 0.25; DA = 0.90;

   }

   else{

       HRA = 0.30; DA = 0.95;

   }

   salary = salary + salary * HRA + salary * DA;

     printf("Gross Salary: %.2f\n", salary);

   return 0;

}

Explanation:

I've added the full program as an attachment where I used comments as explanation

Answer:

it's business

Explanation:

business you started with small and work for it grow up.

The code will print out 3 4 5

Answer choice D is correct.

The output that would be produced for the given values of n is 3 4 5. The correct option is D.

Codes Program is a free developer platform where programmers can learn and share their knowledge. It is regarded as the simplest application development method, and it is frequently used as the standard (method).

Fixing code well into the software program because they discovered an error while composing the program, then he will modify the program, and then they will fix it again.

Less formally, code refers to text written for markup or styling languages such as HTML and CSS (Cascading Style Sheets). Good code is written in such a way that it is readable, understandable, covered by automated tests, not overly complicated, and does the job well."

Therefore, the correct option is D. 3 4 5.

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i = 3

while i  <= 21:

   if i % 3 == 0:

       print(i)

   i += 1

The required program written in python 3 is as follows :

num = 3

#initialize a variable called num to 3

multiples_of_3 = []

#empty list to store all multiples of 3

while num <=21 :

#while loop checks that the range is not exceeded.

if num%3 == 0:

#multiples of 3 have a remainder of 0, when divided by 3.

multiples_of_3.append(num)

#if the number has a remainder of 0, then add the number of the list of multiples

num+=1

#add 1 to proceed to check the next number

print(multiples_of_3)

#print the list

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Answer:

Written in Python

import random

tryagain = 1

while tryagain == 1:

guess = int(input("Enter your guess number between 1 and 6: "))

num = random.randint(1,7)

if guess == num:

print("Your guess is correct")

else:

print("Wow, the dice number is "+str(num))

tryagain = int(input("Do you want to dice it up again:Enter 1 and if not enter 0: "))

Explanation:

I've added the full source code as an image attachment where I used comments to explain difficult lines

Answer:

The corrected program is:

import java.util.Scanner;

public class LabProgram{

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int qtr, dime, nickel, penny;

double dollars;

System.out.print("Quarters: ");

qtr =scnr.nextInt();

System.out.print("Dimes: ");

dime = scnr.nextInt();

System.out.print("Nickel: ");

nickel = scnr.nextInt();

System.out.print("Penny: ");

penny = scnr.nextInt();

dollars = qtr * 0.25 + dime * 0.1 + nickel * 0.05 + penny * 0.01;

System.out.printf("Amount: $%.2f\n", dollars);

System.out.print((dollars * 100)+" cents");

}

}

Explanation:

I've added the full program as an attachment where I used comments as explanation

Answer:

b. tags

Explanation:

When you write HTML code, you use tags to describe the structure of information on a webpage. These tags are represented by the following symbols <>. All of HTML is written using different types of tags such as <body>, <main>, <div>, <nav>, etc. Each of these serves a different purpose but are all used for structuring the specific information on a website so that the information is well organized and is not all on top of each other. This also allows for specific sections to be easily targeted and styles separately from the other sections.

Answer:

The equivalent if statements is:

ranforce = randi([0, 12]);

if (ranforce == 0)

     disp('There is no wind')

else  if(ranforce>0 && ranforce <7)

     disp('There is a breeze')

else  if(ranforce>6 && ranforce <10)

     disp('This is a gale')

else  if(ranforce>9 && ranforce <12)

     disp('It is a storm')

else  if(ranforce==12)

     disp('Hello, Hurricane!')

end

Explanation:

The solution is straight forward.

All you need to do is to replace the case statements with corresponding if or else if statements as shown in the answer section

Answer:

Follows are the code to this question:

def weeklypay(hour_rate,hour ):#defining a method weeklypay that accepts two parameters

   pay=hour_rate* hour#defining variable pay that calculate payable amount

   return pay#return pay value

hour_rate=float(input("Enter your hour rate $: "))#defining variable hour_rate that accepts rate vlue

hour=int(input("Enter total hours: "))#defining hour variable that accepts hour value

print('The total amount you will get $: ',weeklypay(hour_rate,hour))#call method and print return value

Output:

Enter your hour rate $: 300

Enter total hours: 3

The total amount you will get $:  900.0

Explanation:

In the above-given code, a method "weeklypay" is declared, which holds two value "hour_rate and hour" in its parameter, inside a method a "pay" variable is declared, that calculate the total payable amount of the given inputs and return its value.

In the next step, the above variable is used to input the value from the user-end and uses the print method to call the "weeklypay" method and print its return value.

Answer:

DNS

Explanation:

Hope this helps

Answer:

The answer is interpret Proof is down below

Explanation:

Here is the proooooooffffffff i made a 90 but this one was right

Secondary sources interpret information gathered from primary sources.

A secondary source is known to be made up of discussion that is often based on a primary information source.

Hence, the feature of secondary sources are known to give some kind of interpretation to all the information that has been gathered from other primary sources.

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Answer:

Nmap development list

Explanation:

The list being mentioned in this question is known as the Nmap development list. This list basically acts as an information gathering and analytical tool. It allows the user to easily roll out and integrate Nmap tools on a network in order to easily detect all of the IP addresses that are connected as well as analyze all of the details regarding each connected individual system. All of this information is highly valuable to a developer and facilitates the development process.

Answer:

Search

Explanation:

Because you are searching up a specific recording using keywords.

I hope this helps

Answer:

Filter

Explanation:

I got it correct for a quiz.

Answer and Explanation:

A. The study by the research team may not reflect the purpose of the research which is to know how much inbound tourism is contributing to the economy. They are sampling the population on their favorite spots to visit( which may be too narrow here) and what their leisure activities are (which are not the only things tourists spend on). Also 10000 residents may be too small as a sample to reflect more accurate study outcome representative of the population.

2. A flawed sample which is a sampling error would not represent the population as the results from sample would contradict population results

Answer:Click the Microsoft Office button.

Select New. The New Document dialog box appears.

Select Blank document under the Blank and recent section. It will be highlighted by default.

Click Create. A new blank document appears in the Word window.

Explanation:

Answer:

270 nsec

Explanation:

Ripple-carry adder is a combination of multiple full-adders. It is relatively slow as each full-adder waits for the output of a previous full-adder for its input.

Formula to calculate the delay of a ripple-carry adder is;

  = 2( n + 1 ) x D

delay in a full-adder = 150 nsec.

number of full-adders = number of ripple-carry bits = 8

 = 2 ( 8 + 1 ) x 150

 = 18 x 150

 = 270 nsec

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

              //print the header

              System.out.println("**************************************");

              System.out.println("*                                    *");

              System.out.println("*                                    *");

              System.out.println("*   Gas-N-Clean Service Station      *");

              System.out.println("*                                    *");

              System.out.println("*   March 2, 2004                    *");

              System.out.println("*                                    *");

              System.out.println("**************************************");

               //set the constant values for gasoline

               final double REGULAR_GASOLINE = 2.89;

               final double PLUS_GASOLINE = 3.09;

               final double SUPER_GASOLINE = 3.39;

              // initialize the variables as 0

              double gasolinePrice = 0, gasolineCost = 0, carWashCost = 0, totalCost = 0;

               Scanner input = new Scanner(System.in);

               //ask the user to enter the gallons, gas type and car wash choice

               System.out.print("Enter number of gallons ");

               double gasolinePurchase = input.nextDouble();

               System.out.print("Enter gas type (R, P, S, or N) ");

               char gasType = input.next().charAt(0);

               System.out.print("Enter Y or N for car wash ");

               char carWashChoice = input.next().charAt(0);

               //check the gas type. Depending on the choice set the gasolinePrice from the corresponding constant value

              if(gasType == 'R')

                  gasolinePrice = REGULAR_GASOLINE;

              else if(gasType == 'P')

                  gasolinePrice = PLUS_GASOLINE;

              else if(gasType == 'S')

                  gasolinePrice = SUPER_GASOLINE;

                //calculate the gasolineCost

                gasolineCost = gasolinePurchase * gasolinePrice;

               //check the carWashChoice. If it is yes and gasolineCost is greater than 10, set the carWashCost as 1.25. Otherwise, set the carWashCost as 3.00

               if(carWashChoice == 'Y'){    

                   if(gasolineCost >= 10)

                       carWashCost = 1.25;

                   else

                       carWashCost = 3.00;

               }

              //calculate the total cost, add gasolineCost and carWashCost

              totalCost = gasolineCost + carWashCost;

               //print the values in required format

              System.out.println("Amount Gasoline purchases " + gasolinePurchase);

              System.out.println("Gallons Price per gallons $ " + gasolinePrice);

              System.out.printf("Total gasoline cost $ %.2f\n", gasolineCost);

              System.out.println("Car wash cost $ " + carWashCost);

              System.out.printf("Total due $ %.2f\n", totalCost);

               System.out.println("Thank you for stopping\nPlease come again \nRemember to buckle up and drive safely");

}  

}

Explanation:

*The code is in Java.

Please see the comments in the code for explanation