Answers
Answer:
The answer will have to be A
Related Questions
The physical properties of a substance containing the bonded atoms y and z ?
Answers
What is the general trend in electro negativity as you move from left to right across the periodic table
Answers
Answer:
On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you go down a group. As a result, the most electronegative elements are found on the top right of the periodic table, while the least electronegative elements are found on the bottom left.
Explanation:
Answer:
The Electronegativity increases
Explanation:
;)
Rank these transition metal ions in order of decreasing number of unpaired electrons.
a. Fe^3
b. Mn^4+
c. V3+
d. Ni^2+
e. Cu^+
Answers
Answer: The given transition metal ions in order of decreasing number of unpaired electrons are as follows.
[tex]Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}[/tex]
Explanation:
In atomic orbitals, the distribution of electrons of an atom is called electronic configuration.
The electronic configuration in terms of noble gases for the given elements are as follows.
Atomic number of Fe is 26.[tex]Fe^{3+} - [Ar] 3d^{5}[/tex]
So, there is only 1 unpaired electron present in [tex]Fe^{3+}[/tex].
Atomic number of Mn is 25.[tex]Mn^{4+} - [Ar]3d^{3}[/tex]
So, there are only 3 unpaired electrons present in [tex]Mn^{4+}[/tex].
Atomic number of V is 23.[tex]V^{3+} - [Ar] 3d^{2}[/tex]
So, there are only 2 unpaired electrons present in [tex]V^{3+}[/tex].
Atomic number of Ni is 28.[tex]Ni^{2+} - [Ar] 3d^{8}[/tex]
So, there will be 2 unpaired electrons present in [tex]Ni^{2+}[/tex].
Atomic number of Cu is 29.[tex]Cu^{+} - [Ar] 3d^{10}[/tex]
So, there is no unpaired electron present in [tex]Cu^{+}[/tex].
Therefore, given transition metal ions in order of decreasing number of unpaired electrons are as follows.
[tex]Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}[/tex]
Thus, we can conclude that given transition metal ions in order of decreasing number of unpaired electrons are as follows.
[tex]Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}[/tex]
The acid-dissociation constants for three acids are shown in the table.
Which is the strongest acid?
Answers
The strongest acid as per dissociation constant is hydrochloric acid.
What are acids?Acids are defined as substances which on dissociation yield H+ ions , and these substances are sour in taste. Compounds such as HCl, H₂SO₄ and HNO₃ are acids as they yield H+ ions on dissociation.
According to the number of H+ ions which are generated on dissociation acids are classified as mono-protic , di-protic ,tri-protic and polyprotic acids depending on the number of protons which are liberated on dissociation.
Acids are widely used in industries for production of fertilizers, detergents batteries and dyes.They are used in chemical industries for production of chemical compounds like salts which are produced by neutralization reactions.Acids are also used in titrations.
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Complete and balance equation KI(aq)+BaS(aq)→
Answers
The balanced reaction equation is; 2KI(aq)+BaS(aq)→ K2S(aq) + BaI2(aq)
What is equation?A chemical equation shows the conversion of reactants into products. Recall that in a chemical reactions, reactans interact with each other to yield products.
For the reaction we have in the question,the complete reaction equation is; 2KI(aq)+BaS(aq)→ K2S(aq) + BaI2(aq)
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For the following reaction: 4C2H3Cl + 702 → 8CO + 6H20 + 2Cl2 If the reaction of 57.8 grams of O2 produces 36.5 grams of CO, what is the percent yield?
Answers
Answer:
[tex]Y=63.1\%[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction:
[tex]4C_2H_3Cl + 7O_2 \rightarrow 8CO + 6H_2O + 2Cl_2[/tex]
It turns out possible for us to realize about the 7:8 mole ratio of O2 to CO, and therefore, the theoretical yield of the latter is calculated via stoichiometry:
[tex]m_{CO}=57.8gO_2*\frac{1molO_2}{32.0gO_2}*\frac{8molCO}{7molO_2} *\frac{28.01gCO}{1molCO} =57.82gCO[/tex]
Finally, the percent yield is calculated by dividing the actual yield, 36.5 g by the just computed theoretical one:
[tex]Y=\frac{36.5g}{57.8g} *100\%\\\\Y=63.1\%[/tex]
Regards!
What is the chemical equation for F2 + At- -->
Answers
Answer:
F₂ + 2At --> 2AtF
Explanation:
Astatine is a halogen but is not diatomic. It's possible oxidation states are 1⁺, 1⁻, or 5⁺. Fluorine only has the possible oxidation states of 1⁺ or 1⁻.
A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving some glycine () in of . This solution boils at . Calculate the mass of that was dissolved. Round your answer to significant digit.
Answers
The question is incomplete, the complete question is:
A certain substance X has a normal freezing point of [tex]-6.4^oC[/tex] and a molal freezing point depression constant [tex]K_f=3.96^oC.kg/mol[/tex]. A solution is prepared by dissolving some glycine in 950. g of X. This solution freezes at [tex]-13.6^oC[/tex] . Calculate the mass of urea that was dissolved. Round your answer to 2 significant digits.
Answer: The mass of glycine that can be dissolved is [tex]1.3\times 10^2g[/tex]
Explanation:
Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.
The expression for the calculation of depression in freezing point is:
[tex]\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m[/tex]
OR
[tex]\text{Freezing point of pure solvent}=\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}[/tex] ......(1)
where,
Freezing point of pure solvent = [tex]-6.4^oC[/tex]
Freezing point of solution = [tex]-13.6^oC[/tex]
i = Vant Hoff factor = 1 (for non-electrolytes)
[tex]K_f[/tex] = freezing point depression constant = [tex]3.96^oC/m[/tex]
[tex]m_{solute}[/tex] = Given mass of solute (glycine) = ?
[tex]M_{solute}[/tex] = Molar mass of solute (glycine) = 75.07 g/mol
[tex]w_{solvent}[/tex] = Mass of solvent = 950. g
Putting values in equation 1, we get:
[tex]-6.4-(-13.6)=1\times 3.96\times \frac{m_{solute}\times 1000}{75.07\times 950}\\\\m_{solute}=\frac{7.2\times 75.07\times 950}{1\times 3.96\times 1000}\\\\m_{solute}=129.66g=1.3\times 10^2g[/tex]
Hence, the mass of glycine that can be dissolved is [tex]1.3\times 10^2g[/tex]
Glycerol. C3HgO3, is a substance used extensively in the manufacture of cosmetics, foodstuffs, antifreeze, and plastics. Glycerol is a water-soluble liquid
with a density of 1.2656 g/mL at 15 °C. Calculate the molarity of a solution of glycerol made by dissolving 50.000 mL glycerol at 15 °C in enough water to
make 250.00 mL of solution. The molecular weight of C3HgO3 is 92.094 amu.
O A 0.6871
O B. 3.600
O C. 63.28
O 0.92.10
O E. 2.749
Answers
Answer: The correct option is E.) 2.749 M.
Explanation:
Density is defined as the ratio of mass and volume of a substance.
[tex]\text{Density}=\frac{\text{Mass}}{\text{Volume}} [/tex] ......(1)
Given values:
Volume of glycerol = 50.0 mL
Density of glycerol = 1.2656 g/mL
Putting values in equation 1, we get:
[tex]\text{Mass of glycerol }=(1.2656g/mL\times 50.0mL)=63.28g[/tex]
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
[tex]\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}[/tex] .....(2)
Given values:
Given mass of glycerol = 63.28 g
Molar mass of glycerol = 92.094 g/mol
Volume of the solution = 250.00 mL
Putting values in equation 2, we get:
[tex]\text{Molarity of solution}=\frac{63.28\times 1000}{92.094\times 250.00}\\\\\text{Molarity of solution}=2.749M[/tex]
Hence, the correct option is E.) 2.749 M.
Which element has a higher first ionization energy than chlorine (Cl)?
A. Argon (Ar)
B. Phosphorus (P)
C. Lithium (Li)
D. Iodine (I)
Answers
Answer:
Argon
Explanation:
It has more electron than chlorine
m
Un cocodrilo se arrastró 25 m hacia la derecha con una velocidad promedio de –1.2 -.
¿Cuántos segundos se arrastró el cocodrilo?
Answers
Answer:
El cocodrilo se arrastró durante 20.833 segundos.
Explanation:
El enunciado presenta omisiones y errores conceptuales. La forma correcta es la siguiente: "Un cocodrilo se arrastró 25 metros hacia la derecha con una rapidez promedio de 1.2 metros por segundo. ¿Cuántos segundos se arrastró el cocodrilo?"
Consideremos que el cocodrilo tiene un movimiento rectilíneo uniforme, el tiempo requerido para el recorrido se calcula con la siguiente ecuación cinemática:
[tex]t = \frac{x}{v}[/tex] (1)
Donde:
[tex]x[/tex] - Distancia recorrida, en metros.
[tex]v[/tex] - Rapidez del cocodrilo, en metros por segundo.
[tex]t[/tex] - Tiempo, en segundos.
Si [tex]x = 25\,m[/tex] y [tex]v = 1.2\,\frac{m}{s}[/tex], entonces el tiempo empleado por el cocodrilo es:
[tex]t = \frac{25\,m}{1.2\,\frac{m}{s} }[/tex]
[tex]t = 20.833\,s[/tex]
El cocodrilo se arrastró durante 20.833 segundos.
Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:
Answers
The question is incomplete, the complete question is:
Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:
(a): Calculate the grams of [tex]N_2[/tex] in 10.58 L of nitrogen gas
(b): Calculate the grams of [tex]N_2[/tex] in [tex]5.03\times 10^{20}[/tex] moles of nitrogen gas
(c): Calculate the moles of [tex]N_2[/tex] molecules in 3.94 grams of nitrogen gas
(d): Calculate the moles of [tex]N_2[/tex] molecules in 4.73 L of nitrogen gas
Answer: The correct options are (b) and (c).
Explanation:
We are given:
Molar mass of [tex]N_2[/tex] = 28.02 g/mol
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
At STP conditions:
1 mole of gas occupies 22.4 L of volume
For the given options:
(a): Volume is given and to calculate the mass of [tex]N_2[/tex], we need to use both the conversion factors above.
The equation formed will be:
Mass of [tex]N_2[/tex] = [tex]\frac{1mol}{22.4L}\times 10.58L\times 28.02 g/mol[/tex]
(b): Moles are given and to calculate the mass of [tex]N_2[/tex], we need only the first conversion factor.
The equation formed will be:
Mass of [tex]N_2[/tex] = [tex](5.03\times 10^{20}mol)\times 28.02g/mol[/tex]
(c): Mass is given and to calculate the moles of [tex]N_2[/tex] molecules, we need only the first conversion factor.
The equation formed will be:
Moles of [tex]N_2[/tex] molecules = [tex]\frac{3.94 g}{28.02g/mol}[/tex]
(d): Volume is given and to calculate the moles of [tex]N_2[/tex] molecules, we need only the second conversion factor.
The equation formed will be:
Moles of [tex]N_2[/tex] molecules = [tex]\frac{1mol}{22.4L}\times 4.73L[/tex]
Hence, the correct option is (b) and (c)
Using only 28.02 g/mol as a conversion factor, we can:
(b): Calculate the grams of N₂ in 5.03 × 10²⁰ moles of nitrogen gas. (c): Calculate the moles of N₂ molecules in 3.94 grams of nitrogen gas.We want to identify the conversion factors required in a series of calculations.
What is a conversion factor?A conversion factor is an arithmetical multiplier for converting a quantity expressed in one set of units into an equivalent expressed in another.
28.02 g/mol, which is the molar mass of nitrogen, is a conversion factor to convert moles to mass and vice versa.
(a): Calculate the grams of N₂ in 10.58 L of nitrogen gas.We want to convert 10.58 L (volume) to grams (mass). We need to conversion factors:
22.4 L/mol is the conversion factor to convert volume to moles.28.02 g/mol is the conversion factor to convert moles to mass.(b): Calculate the grams of N₂ in 5.03 × 10²⁰ moles of nitrogen gas.We want to convert 5.03 × 10²⁰ moles (moles) to grams (mass). We can do so by just using 28.02 g/mol as the conversion factor.
(c): Calculate the moles of N₂ molecules in 3.94 grams of nitrogen gas.We want to convert 3.94 grams (mass) to moles. We can do so by just using 28.02 g/mol as the conversion factor.
(d): Calculate the moles of N₂ molecules in 4.73 L of nitrogen gas.We want to convert 4.73 L (volume) to moles. The required conversion factor is 22.4 L/mol.
Using only 28.02 g/mol as a conversion factor, we can:
(b): Calculate the grams of N₂ in 5.03 × 10²⁰ moles of nitrogen gas. (c): Calculate the moles of N₂ molecules in 3.94 grams of nitrogen gas.The question is incomplete, the complete question is:
Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:
(a): Calculate the grams of N₂ in 10.58 L of nitrogen gas.
(b): Calculate the grams of N₂ in 5.03 × 10²⁰ moles of nitrogen gas.
(c): Calculate the moles of N₂ molecules in 3.94 grams of nitrogen gas.
(d): Calculate the moles of N₂ molecules in 4.73 L of nitrogen gas.
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HURRY! Carbon and oxygen combine to form carbon dioxide. What are the products, or what is the product, in this chemical reaction?
-carbon and oxygen
-carbon dioxide
-carbon only
-oxygen only
Answers
Answer:
Carbon dioxide.
Explanation:
Hope this will help
The diagram shows a food chain.
Which term best describes the green plant in the food chain?
antiter
A. Competitor
B. Producer
C. Consumer
D. Predator
Answers
Which of the following reactions would result in decreased entropy?
O A. H20(g) → H20(1)
O B. CO2(s) → CO2(9)
O C. 203(9) ► 302(9)
O D. N2204(9) ► 2NO39)
Answers
Answer:
A
Explanation:
A P E X
An imaginary line dividing the earth's surface into two hemisphere the northern and southern hemisphere, it is locatedat 0⁰, which of the following imaginary lines is being described? a.equator b.latitude c.longitude d.prime meridian
Answers
Answer:
A. Equator
Explanation:
The equator is located in the centre of the Earth, dividing the northern and southern hemispheres.
Answer:
Equator because equator divides the earth into Northern and Southern hemisphere.
A student performs an experiment three times. The results are 4.52 g/mL, 4.54 g/mL, and 4.39 g/mL. Which of the following best describes these results with only the information given in this question?
a. high accuracy
b. high accuracy and high precision
c. high accuracy and low precision
d. high precision
Answers
3 valance electrons on the 4th shell
Answers
Scandium..??
Acetylene gas, C2H2, is produced as a result of the following reaction: CaC2 + 2H2O ----> C2H2 + Ca(OH)2.
(a) If 32 grams of CaC2 are consumed in this reaction, how many moles of water are needed ?
(b) How Many moles of each product would form ?
Answers
Given the data from the question,
A. The number of mole of water needed for the reaction is 1 mole
Bi. The number of mole of C₂H₂ formed is 0.5 mole
Bii. The number of mole of Ca(OH)₂ formed is 0.5 mole
How to determine the mole of CaC₂Mass of CaC₂ = 32 gMolar mass of CaC₂ = 40 + (12×2) = 64 g/mol Mole of CaC₂ =?Mole = mass / molar mass
Mole of CaC₂ = 32 / 64
Mole of CaC₂ = 0.5 mole
A. How to determine the mole of water needeBalanced equation
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaC₂ required 2 moles of H₂O
Therefore,
0.5 mole of CaC₂ will require = 0.5 × 2 = 1 mole of H₂O
Thus, 1 mole of H₂O is needed for the reaction.
Bi. How to determine the mole of C₂H₂ produced
Balanced equation
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaC₂ reacted to produce 1 mole of C₂H₂
Therefore,
0.5 mole of CaC₂ will also react to produce 0.5 mole of C₂H₂
Thus, 0.5 mole of C₂H₂ was obtained from the reaction
Bii. How to determine the mole of Ca(OH)₂ producedBalanced equation
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
1 mole of CaC₂ reacted to produce 1 mole of Ca(OH)₂
Therefore,
0.5 mole of CaC₂ will also react to produce 0.5 mole of Ca(OH)₂
Thus, 0.5 mole of Ca(OH)₂ was obtained from the reaction
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The Fischer esterification mechanism is examined in this question. The overall reaction is: Benzoic acid, C H 3 O H and H C l react to form a methyl ester, H 2 O and H C l. Benzoic acid is a carboxylic acid bonded to a benzene ring. Identify the results or mechanism of each step.
Answers
Answer:
See explanation and image attached
Explanation:
Fischer esterification is a type of reaction used to convert carboxylic acids to ester in the presence of excess alcohol and a strong acid which acts as a catalyst. Another final product formed in the reaction is water.
The mechanism for the fischer esterification of Benzoic acid and C H 3 O H in the presence of HCl as the catalyst is shown in the image attached to this answer.
The final products of the reaction are methyl benzoate, water and H^+ as shown in the image attached.
The methyl ester, water, and the acid catalyst (HCl) are byproducts of the Fischer esterification process, which involves protonation, nucleophilic attack, elimination, and deprotonation processes.
Carbonyl oxygen protonation: The carbonyl oxygen of the carboxylic acid (benzoic acid) is protonated by the acid catalyst (HCl) in the first step. The protonation of the carbonyl carbon increases its electrophilicity and promotes the alcohol's nucleophilic assault. Attack by the alcohol's nucleophilic oxygen (methanol, CH3OH) on the protonated carboxylic acid's carbonyl carbon results in the formation of a tetrahedral intermediate. The acid catalyst also helps with this phase. Elimination of water: In the following step, the water molecule must be removed from the tetrahedral intermediate. The hydroxyl group (-OH) from the carboxylic acid and a hydrogen from the hydroxyl group of the alcohol are removed to create this water molecule. Deprotonation: A deprotonation occurs after the removal of water.
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Which of the following is considered a nucleon?
proton
neutron
All of the above
None of the above
Answers
A 100.00 mL volumetric flask weighs 35.9325 g. When an unknown solid is added to it, the flask and sample weigh 48.8565 g. Deionized water is added to the calibration mark. The flask, sample, and water together weigh 140.8321 g. Calculate the density of the unknown, assuming the density of water is 0.998203 g/mL.
Answers
Answer:
1.64 g/mL
Explanation:
Step 1: Calculate the mass of the solid
m(solid+flask) = m(solid) + m(flask)
m(solid) = m(solid+flask) - m(flask)
m(solid) = 48.8565 g - 35.9325 g = 12.9240 g
Step 2: Calculate the mass of water
m(solid+flask+water) = m(solid+flask) + m(water)
m(water) = m(solid+flask+water) - m(solid+flask)
m(water) = 140.8321 g - 48.8565 g = 91.9756 g
Step 3: Calculate the volume occupied by 91.9756 g of water
The density of water is 0.998203 g/mL.
91.9756 g × 1 mL/0.998203 g = 92.1412 mL
Step 4: Calculate the volume occupied by the solid
The 100.00 mL are occupied by the solid and the water.
100.00 mL = V(solid) + V(water
V(solid) = 100.00 mL - V(water)
V(solid) = 100.00 mL - 92.1412 mL = 7.86 mL
Step 5: Calculate the density of the solid
12.9240 g of the solid occupy 7.86 mL.
ρ = 12.9240 g/7.86 mL = 1.64 g/mL
Indica, con base en la siguiente ecuación:
HNO3 + H2S
NO + S + H30
a) Los números de oxidación de todos los átomos que forman cada compuesto
o elemento.
b) los átomos cuyo número de oxidación varía.
c) El elemento que se reduce y el que se oxida.
d) El agente oxidante y el agente reductor.
e) El átomo que gana electrones y el átomo que los pierde.
f) Los coeficientes apropiados para balancear la ecuación química.
Answers
7. Iron combines with 4.00 g of Copper (11) nitrate to form 6.01 g of Iron (I) nitrate and 0.400 g copper
metal.
How much iron did it take to convert the Cu(NO3)2?
Answers
The mass of iron required by one mole or 187.5 g of copper nitrate is 234 g. Then the mass of Fe required by 4 g of copper nitrate is 5 g.
What is copper nitrate?Copper nitrate is an ionic compound formed by donating electrons from metallic copper to the nitrate group. Copper nitrate easily undergoes displacement reactions.
The reaction of copper nitrate with iron is written below:
[tex]\rm Cu(NO_{3})_{2} + 4 Fe \rightarrow 2Fe_{2}(NO_{3})_{2} + Cu[/tex]
As per this reaction, one mole of copper nitrate requires 4 moles of Fe.
molar mass of Fe = 58.5
mass of 4 moles = 234 g
molar mass of copper nitrate = 187.5 g.
187.5 g of copper nitrate need 234 g of Fe. Hence, 4 g of Cu needs:
234 × 4 /187.5 = 5 g
Therefore, the mass of Fe requires is 5 g.
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Would an electron in the 1s orbital of lithium require the same energy to move to a higher energy level as an electron in the
1s orbital of silver?
Answers
Answer:
See explanation
Explanation:
We must remember that the energy required to move an electron from the 1s orbital to a higher energy level depends on the size of the nuclear charge.
The higher the nuclear charge, the more closely held the 1s electron of the atom is to the nucleus and the more difficult it is to excite this electron.
Hence, it requires more energy to excite the 1s electron of silver having a larger size of nuclear charge than it is to excite a 1s electron in lithium.
Need some help with this Chem Question :)
Answers
Answer:
Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂
Explanation:
The activity series helps us to easily define whether or not a reaction will occur.
Elements at the top of the activity series are highly reactive and will always displace those at the bottom of the series in any reaction.
With the above information in mind, let us answer the questions given above.
Ag + NaNO₃ —> Na + AgNO₃
The above reaction will not occur because Na is higher than Ag in the activity series. Thus, Ag cannot displace Na from solution.
Pb + Mg(NO₃)₂ —> Pb(NO₃)₂ + Mg
The above reaction will not occur because Mg is higher than Pb in the activity series. Thus, Pb cannot displace Mg from solution.
Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂
The above reaction will occur because Mg is higher than Fe in the activity series. Thus, Mg will displace Fe from solution.
Cu + Mg(NO₃)₂ —> Cu(NO₃)₂ + Mg
The above reaction will not occur because Mg is higher than Cu in the activity series. Thus, Cu cannot displace Mg from solution.
From the above illustration, only
Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂
Will occur.
Will the contribution of entropy to the free energy be positive or negative
Answers
Answer:
It must be negative, for the reaction to be feasible.
explanation:
Is Dioxin chemical ionic or covalent and acidic or basic? Explain
Answers
Answer:
Learning Objective Identify element pairs which are likely to form ionic or covalent bonds Key Points Ionic compounds are formed from strong electrostatic interactions between ions, which result in higher melting points and electrical conductivity compared to covalent compounds.Dioxins are a group of highly toxic chemical compounds that are harmful to health. They can cause problems with reproduction, development, and the immune system. They can also disrupt hormones and lead to cancer. Known as persistent environmental pollutants (POPs), dioxins can remain in the environment for many years. Covalent compounds have bonds where electrons are shared between atoms. Due to the sharing of electrons, they exhibit characteristic physical properties that include lower melting points and electrical conductivity compared to ionic compounds. Terms electronegativity: The tendency of an atom or molecule to attract electrons and form bonds. octet rule: Atoms lose, gain, or share electrons in order to have a full valence level of eight electrons. Hydrogen and helium are exceptions because they can hold a maximum of two valence electrons. valence electrons: Electrons in the outermost principal energy (valence) level of an atom that can participate in the formation of chemical bonds with other atoms. Two Classes of Compounds Compounds are defined as substances containing two or more different chemical elements. They have distinct chemical structures characterized by a fixed ratio of atoms held together by chemical bonds. Here, we discuss two classes of compounds based on the bond type that holds the atoms together: ionic and covalent. Covalent Compounds Covalent bonds are characterized by the sharing of electrons between two or more atoms. These bonds mostly occur between nonmetals or between two of the same (or similar) elements.Two atoms with similar electronegativity will not exchange an electron from their outermost shell; the atoms instead share electrons so that their valence electron shell is filled. Examples of compounds that contain only covalent bonds are methane (CH4), carbon monoxide (CO), and iodine monobromide (IBr). Ionic Compounds Ionic bonding occurs when there is a large difference in electronegativity between two atoms. This large difference leads to the loss of an electron from the less electronegative atom and the gain of that electron by the more electronegative atom, resulting in two ions. These oppositely charged ions feel an attraction to each other, and this electrostatic attraction constitutes an ionic bond. Ionic bonding occurs between a nonmetal, which acts as an electron acceptor, and a metal, which acts as an electron donor. Metals have few valence electrons, whereas nonmetals have closer to eight valence electrons; to easily satisfy the octet rule, the nonmetal will accept an electron donated by the metal. More than one electron can be donated and received in an ionic bond. Some examples of compounds with ionic bonding include NaCl, KI, MgCl2.Explanation:
#hopeithelpsstaysafe and keep wellcan you mark me as your brainliest pls?g Acetic acid is diluted with water to make a solution of vinegar. You have a sample of vinegar that contains 16.7 g of acetic acid. Determine the number of moles of acetic acid in the vinegar sample.
Answers
Answer:
0.278 mol
Explanation:
Step 1: Given and required data
Mass of acetic acid (m): 16.7 g
Chemical formula of acetic acid: CH₃COOH (C₂H₄O₂)
Step 2: Calculate the molar mass (M) of acetic acid
We will use the following expression.
M(C₂H₄O₂) = 2 × M(C) + 4 × M(H) + 2 × M(O)
M(C₂H₄O₂) = 2 × 12.01 g/mol + 4 × 1.01 g/mol + 2 × 16.00 g/mol = 60.06 g/mol
Step 3: Calculate the number of moles (n) of acetic acid
We will use the following expression.
n = m/M
n = 16.7 g/(60.06 g/mol) = 0.278 mol
For reactions occurring at STP, the conversion between moles and liters is 22.4 L = 1 mol for all gases. How many moles of sodium are in a 7.25-liter container at STP?
0.213 mol
0.126 mol
3.23 mol
0.324 mol
Answers
Answer:
0.324 mole of sodium
Explanation:
From the question given above, the following data were obtained:
Volume of sodium = 7.25 L
Number of mole of sodium =..?
The number of mole of sodium that occupies 7.25 L can be obtained as follow:
22.4 L = 1 mole
Therefore,
7.25 L = 7.25 L × 1 mole / 22.4 L
7.25 L = 0.324 mole
Therefore, 0.324 mole of sodium is present in the container.