The cycle comprises of four processes, namely: the condensation of the working fluid, the pumping of the condensate, the evaporation of the working fluid, and the operation of the turbine.
A sketch of the T-s diagram is as follows: Assumptions in the ideal Rankine cycle include: Incompressible fluid heat capacity is constant. The mechanical work performed by the pump is negligible. Working fluid flows through the turbine at a constant rate. The process is internally reversible.
Using steam tables, the enthalpy of water at 10 kPa is h1 = 191.81 kJ/kg. Q = m (h1 - h'') = m (191.81 - 3051.7) = -2859.9m kJ/kg Since the cooling water gains this amount of energy, the heat transfer to cooling water passing through the condenser is Q = 2859.9m kJ/kg.
To know more about comprises visit:
https://brainly.com/question/33458720
#SPJ11
A box with a mass of 17 kg is suspended from a spring that is stretched 150 mm. If the box is displaced 100 mm downward from its equilibrium position and given a downward velocity of 700 mm/s, determine the equation which describes the motion. What is the phase angle and amplitude of vibration? Assume that positive displacement is downward.
The box is in simple harmonic motion with the following parameters. Since the box is displaced from equilibrium and is given an initial velocity, it vibrates with amplitude and has a phase angle.
In simple harmonic motion,
x = A sin (ωt + φ).
x = A sin (ωt + φ)
can be used to describe the equation of motion for the given problem.For this equation of motion, the amplitude (A) and phase angle (φ) must be calculated using the given conditions.ω, the angular frequency, can be found using the formula for a mass-spring system's angular frequency:
ω = sqrt(k/m)
where k is the spring constant and m is the mass of the box .
In this case, the box is displaced 100 mm downward from its equilibrium position, thus the amplitude of vibration is A = 100 mm. The phase angle can be determined using the following equation:
φ = arctan(-v0/ωx)
where v0 is the initial velocity (700 mm/s), ω is the angular frequency (9.05 rad/s), and x is the amplitude (mm).
φ=arctan(-700/(9.05*100))
φ =-43.33 degrees.
The equation of motion for the given problem is
x = 100 sin (9.05t - 43.33).
The amplitude of vibration is 100 mm and the phase angle is -43.33 degrees.
To know more about equation visit:
https://brainly.com/question/29538993
#SPJ11
A nozzle 0.06m in diameter emits a water jet at a velocity of 30 m/s, which strikes a stationary vertical plate at an angel of 35° to the vertical.
Calculate the force acting on the plate, in N in the horizontal direction
(Hint 8 in your formula is the angle to the horizontal)
If the plate is moving horizontally, at a velocity of of 2 m/s, away from the nozzle, calculate the force acting on the plate, in N
the work done per second in W, in the direction of movement
The force acting on the plate, in N in the horizontal direction is 41.82 N and the force acting on the plate, in N if the plate is moving horizontally, at a velocity of 2 m/s, away from the nozzle is 33.69 N.
What is a nozzle?
A nozzle is a simple mechanical device that controls the flow of a fluid.
Nozzles are used to convert pressure energy into kinetic energy.
Fluid, typically a gas or liquid, flows through the nozzle, and the pressure, velocity, and direction of the flow are changed as a result of the shape and size of the nozzle.
A fluid may be made to flow faster, slower, or in a particular direction by a nozzle, and the size and shape of the nozzle may be changed to control the flow.
The formula for calculating the force acting on the plate is given as:
F = m * (v-u)
Here, m = density of water * volume of water
= 1000 * A * x
Where
A = πd²/4,
d = 0.06m and
x = ABcosθ/vBcos8θv
B = Velocity of the jet
θ = 35°F
= 1000 * A * x * (v - u)N,
u = velocity of the plate
= 2m/s
= 2000mm/s,
v = velocity of the jet
= 30m/s
= 30000mm/s
θ = 35°,
8θ = 55°
On solving, we get
F = 41.82 N
Work done per second,
W = F × u
W = 41.82 × 2000
W = 83,640
W = 83.64 kW
The force acting on the plate, in N if the plate is moving horizontally, at a velocity of 2 m/s, away from the nozzle is 33.69 N.
To know more about velocity visit:
https://brainly.com/question/30559316
#SPJ11
A rod 12.5 mm in diameter is stretched 3.2 mm under a steady load of 10 kN. What stress would be produced in the bar by a weight of 700 N, falling through 75 mm before commencing to stretch, the rod being initially unstressed? The value of E may be taken as 2.1 x 10^5 N/mm².
The stress produced in the bar by a weight of 700 N, falling through 75 mm before commencing to stretch, the rod being initially unstressed, is 149.053 N/mm².
Explanation:
The given problem provides information about a rod with a diameter of 12.5 mm and a steady load of 10 kN. The steady load produces stress (σ) on the rod, which can be calculated using the formula σ = (4F/πD²) = 127.323 N/mm², where F is the load applied to the rod. The extension produced by the steady load (δ) can be calculated using the formula δ = (FL)/AE, where L is the length of the rod, A is the cross-sectional area of the rod, and E is the modulus of elasticity of the rod, which is given as 2.1 x 10⁵ N/mm².
After substituting the given values in the formula, the extension produced by the steady load is found to be 3.2 mm. Using the formula, we can determine the length of the rod, which is L = (3.2 x 122.717 x 2.1 x 10⁵)/10,000 = 852.65 mm.
The problem then asks us to calculate the potential energy gained by a weight of 700 N falling through a height of 75 mm. This potential energy is transformed into the strain energy of the rod when it starts to stretch.
Thus, strain energy = Potential energy of the falling weight = (700 x 75) N-mm
The strain energy of a bar is given by the formula, U = (F²L)/(2AE) ... (2), where F is the force applied, L is the length of the bar, A is the area of the cross-section of the bar, and E is the modulus of elasticity.
Substituting the given values in equation (2), we get
(700 x 75) = (F² x 852.65)/(2 x 122.717 x 2.1 x 10⁵)
Solving for F, we get F = 2666.7 N.
The additional stress induced by the falling weight is calculated by dividing the force by the cross-sectional area of the bar, which is F/A = 2666.7/122.717 = 21.73 N/mm².
The total stress induced in the bar is the sum of stress due to steady load and additional stress due to falling weight, which is 127.323 + 21.73 = 149.053 N/mm².
Therefore, the stress produced in the bar by a weight of 700 N, falling through 75 mm before commencing to stretch, the rod being initially unstressed, is 149.053 N/mm².
Know more about strain energy here:
https://brainly.com/question/32094420
#SPJ11
For corrosion to occur, there must be an anodic and cathodic reaction, oxygen must be available, and there must be both an electronically and fonically conductive path True O False
The given statement, "For corrosion to occur, there must be an anodic and cathodic reaction, oxygen must be available, and there must be both an electronically and fonically conductive path" is true.
The occurrence of corrosion is reliant on three necessary factors that must be present simultaneously. These three factors are:Anode and cathode reaction: When a metal comes into touch with an electrolyte, an oxidation reaction occurs at the anode, and an opposite reaction of reduction occurs at the cathode. The reaction at the anode causes the metal to dissolve into the electrolyte, and the reaction at the cathode protects the metal from corrosion.
Oxygen: For the cathodic reaction to take place, oxygen must be present. If there is no oxygen available, the reduction reaction at the cathode will not happen, and hence, no cathodic protection against corrosion.Electronically and Fonically Conductive Path: To make a closed circuit, the anode and cathode should be electrically connected. A connection can occur when the metal comes into touch with a different metal or an electrolyte that conducts electricity.
To know more about corrosion visit:
https://brainly.com/question/31313074
#SPJ11
B: Find the solution to the following linear programming problem using the simplex method Max (Z) 5x+10y Subjected to: 8x+8y ≤ 160 12x+12y ≤ 180 x,y20
The maximum value of Z is 900, and it occurs when x = 10 and y = 10.
How to solve Linear Programming Using Simplex Method?The standard form of a linear programming problem is expressed as:
Maximize:
Z = c₁x₁ + c₂x₂
Subject to:
a₁₁x₁ + a₁₂x₂ ≤ b₁
a₂₁x₁ + a₂₂x₂ ≤ b₂
x₁, x₂ ≥ 0
We want to Maximize:
Z = 5x + 10y
Subject to:
8x + 8y ≤ 160
12x + 12y ≤ 180
x, y ≥ 0
Now, we can apply the simplex method to solve the problem. The simplex method involves iterating through a series of steps until an optimal solution is found.
The optimal solution for the given linear programming problem is:
Z = 900
x = 10
y = 10
The maximum value of Z is 900, and it occurs when x = 10 and y = 10.
Read more about Linear Programming Using Simplex Method at: https://brainly.com/question/32948314
#SPJ4
A pipe with an inner diameter of 13.5 inches and a wall thickness of 0.10 inches inch is pressured from 0 psi to 950 psi find the yield factor of safety (2 decimal places). Just use the tangential stress for the analysis.
Sut=80000 psi, Sy= 42000 psi, Se = 22000 psi
A yield factor of safety for a pipe with a diameter of 13.5 inches and a wall thickness of 0.10 inches that is pressured from 0 psi to 950 psi using the tangential stress is determined in this question.
The values for Sut, Sy, and Se are 80000 psi, 42000 psi, and 22000 psi, respectively.
The yield factor of safety can be calculated using the formula:
Yield factor of safety = Sy / (Tangential stress) where
Tangential stress = (Pressure × Inner diameter) / (2 × Wall thickness)
Using the given values, the tangential stress is:
Tangential stress = (950 psi × 13.5 inches) / (2 × 0.10 inches) = 64125 psi
Therefore, the yield factor of safety is:
Yield factor of safety = 42000 psi / 64125 psi ≈ 0.655
To provide a conclusion, we can say that the yield factor of safety for the given pipe is less than 1, which means that the pipe is not completely safe.
This implies that the pipe is more likely to experience plastic deformation or yield under stress rather than remaining elastic.
Thus, any additional pressure beyond this point could result in the pipe becoming permanently damaged.
To know more about yield factor visit:
brainly.com/question/31857073
#SPJ11
EXPOUND & ANSWER THE QUESTION BRIEFLY AND GIVE INSIGHTS AND
CITE SOURCES ABOUT THE TOPIC. THANK YOUU
Water management is an important aspect of electric power production. Identify at least two needs for water in a Rankine cycle-based power plant. Describe typical water management practices in such plants, and research at least two emerging technologies aimed at reducing water losses in plants or enhancing sustainable water management.
Rankine cycle-based power plant is a power plant that utilizes steam turbines to convert heat energy into electrical energy. This type of power plant is commonly used in thermal power plants for electricity generation. Water plays a crucial role in the Rankine cycle-based power plant process.
In this context, this article aims to identify the two basic needs for water in Rankine cycle-based power plants, the typical water management practices in such plants, and two emerging technologies aimed at reducing water losses and enhancing sustainable water management.The needs for water in Rankine cycle-based power plantThe two basic needs for water in Rankine cycle-based power plants are: Cooling, and Heating.Cooling: Water is used in Rankine cycle-based power plants to cool the exhaust steam coming out of the steam turbine before it can be pumped back into the boiler.
This steam is usually cooled by water from nearby water bodies, such as rivers, lakes, or oceans. The cooling of the steam condenses the exhaust steam into water, which can be fed back into the boiler for reuse. Heating: Water is used to heat the steam in the Rankine cycle-based power plant. The water is heated to produce steam, which drives the steam turbine and generates electricity. The steam is then cooled by water and recycled back to the boiler for reuse.Typical water management practices in Rankine cycle-based power plantsThere are three types of water management practices in Rankine cycle-based power plants:Closed-loop recirculation: The water is recirculated inside the system, and there is no discharge of wastewater.
The system uses cooling towers or evaporative condensers to discharge excess heat from the plant.Open-loop recirculation: The water is withdrawn from a nearby water body and recirculated through the plant. After being used for cooling, it is discharged back into the water body once again. This practice may have a negative impact on the ecosystem.Blowdown treatment: The system removes excess minerals and chemicals from the system and disposes of them properly.
Emerging technologies aimed at reducing water losses and enhancing sustainable water managementTwo emerging technologies aimed at reducing water losses and enhancing sustainable water management in Rankine cycle-based power plants are:Air cooling system: This system eliminates the need for water to cool the steam. Instead, it uses air to cool the steam. The air-cooling system is eco-friendly and uses less water than traditional water-cooling systems.Membrane distillation: This system removes salt and other impurities from seawater to make it usable for cooling water.
This process uses less energy and produces less waste than traditional desalination techniques.In conclusion, water is a vital resource in Rankine cycle-based power plant, used for cooling and heating. Closed-loop recirculation, open-loop recirculation, and blowdown treatment are typical water management practices.
Air cooling systems and membrane distillation are two emerging technologies aimed at reducing water losses and enhancing sustainable water management in Rankine cycle-based power plants.Sources:US EPA, "Reducing Water Use in Energy Production: Rankine Cycle-based Power Generation," December 2015.Edwards, B. D., S. B. Brown, and K. J. McLeod. "Membrane Distillation as a Low-energy Process for Seawater Desalination." Desalination 203, no. 1–3 (2007): 371–83.
To know about ecosystem visit:
https://brainly.com/question/31459119
#SPJ11
Select the item listed that is NOT a type of electrical transducer. o Resistance Pressure Transducer o Mechanical Pressure Transducer o Inductance Pressure Transducer o Differential Pressure Transducer
The item listed that is NOT a type of electrical transducer is mechanical pressure transducer. Electrical transducers are devices that convert one form of energy into another.
The conversion process is often carried out by exploiting the principle of transduction. Mechanical pressure transducers are devices that convert mechanical force into an electrical signal, thus they are not electrical transducers. Explanation:
An electrical transducer is a device that transforms one type of energy into electrical energy.
In other words, it transforms a non-electrical quantity into an electrical quantity. Types of Electrical Transducers1. Resistive transducer. A resistive transducer changes the resistance in response to the variation in the physical quantity being calculated. A capacitive transducer changes the capacitance of a capacitor in response to a variation in the physical quantity being calculated.
To know more about electrical visit:
https://brainly.com/question/31173598
#SPJ11
Assuming: - 100% efficient energy conversions. - A 4.3 MW wind turbine operates at full capacity for one day. How many barrels of oil is equivalent to the electrical energy created by the wind turbine?
Assuming 100% energy conversion efficiency, a 4.3 MW wind turbine operating at full capacity for one day is equivalent to approximately X = 103.2 MWh barrels of oil.
To determine the number of barrels of oil equivalent to the electrical energy generated by the wind turbine, we need to consider the energy conversion efficiency of the turbine and the energy content of a barrel of oil.
Assuming 100% energy conversion efficiency means that all the electrical energy produced by the wind turbine is accounted for. Therefore, we can directly calculate the energy generated.
Energy (in MWh) = Power (in MW) × Time (in hours)
Energy = 4.3 MW × 24 hours = 103.2 MWh
To convert this electrical energy to the energy content of oil, we need to know the energy content of a barrel of oil, which is typically measured in barrels of oil equivalent (BOE). The energy content of a BOE varies depending on the specific properties of the oil being considered.
Let's assume a hypothetical value of 1 MWh of electrical energy being equivalent to X barrels of oil. In this case, we have:
103.2 MWh = X barrels of oil
X = 103.2 MWh
Therefore, the number of barrels of oil equivalent to the electrical energy created by the wind turbine is determined by the specific conversion factor for a given energy content of oil.
Learn more about Operator or operating click here : brainly.com/question/14308529
#SPJ11
By considering the mechanical behaviour of polymers in terms of spring and dashpot models, describe and explain (with the aid of diagrams) the four systems that can represent the response of a polymer to a stress pulse. Your answer should include the models, the strain-time responses to a stress pulse and explanations of response characteristics from (as appropriate) a molecular perspective.
Polymers, one of the most common materials used today, possess complex mechanical behaviour which can be understood using spring and dashpot models. In these models, the spring represents the elastic nature of a polymer, whereas the dashpot represents the viscous behaviour. The four systems that represent the response of a polymer to a stress pulse include:
1. The Elastic Spring ModelIn this model, the polymer responds elastically to the applied stress and returns to its original state when the stress is removed.2. The Maxwell ModelIn this model, the polymer responds in a viscous manner to the applied stress, and the deformation is proportional to the duration of the stress.3. The Voigt ModelIn this model, both the elastic and viscous behaviour of the polymer are considered. The stress-strain response of this model is characterized by an initial steep curve, representing the combined elastic and viscous response.
4. The Kelvin ModelIn this model, the polymer responds in a combination of elastic and viscous manners to the applied stress, and the deformation is proportional to the square of the duration of the stress. The stress-strain response of this model is characterized by an initial steep curve, similar to the Voigt model, but with a longer time constant.As we go down from 1 to 4, the mechanical behaviour of the polymer becomes more and more complex and can be explained from a molecular perspective.
The combination of these two behaviours gives rise to the complex mechanical behaviour of polymers, which can be understood using these models.
To know more about mechanical behaviour visit :
https://brainly.com/question/25758976
#SPJ11
A diffuser operates at sea-level at M 0 =1.5 with π d,max =0.98 and where η r ={ 1 for M 0 ≤11−0.075(M 0 −1) 1.35 for 1
b. p t0
C. p t2
d. T t2
e. T t2,s
(the value of T t2 for an isentropic compressor) f. η d = T t2 −T 0T t2,s −T 0 [ Ans :η d =0.954] g. Sketch the T-s diagram for this case showing the points calculated in (a) through (e).
The diffuser operates at sea-level with a Mach number (M0) of 1.5, achieving a maximum pressure recovery (πd,max) of 0.98. The overall diffuser efficiency (ηd) is calculated to be 0.954.
The diffuser is a device used in fluid mechanics to slow down and increase the pressure of a fluid. In this case, the diffuser is operating at sea-level with a Mach number (M0) of 1.5, which indicates that the flow velocity is supersonic. The maximum pressure recovery (πd,max) is given as 0.98, meaning that the diffuser can recover up to 98% of the static pressure.
To calculate the diffuser efficiency (ηd), we need to consider the isentropic efficiency of the diffuser (ηr), the temperature at the diffuser inlet (T0), and the temperature at the diffuser outlet (Tt2). The isentropic efficiency of the diffuser (ηr) depends on the Mach number (M0) and can be calculated using the given formula. In this case, ηr is given as 1 for M0 ≤ 1, and 1.35 for 1 < M0 < 11 - 0.075(M0 - 1).
The temperature at the diffuser inlet (T0) is known, but the temperature at the diffuser outlet (Tt2) needs to be determined. The value of Tt2 for an isentropic compressor is given as 1. Hence, we need to calculate Tt2 using the given formula. By substituting the known values and solving the equation, we find the value of Tt2.
Finally, the diffuser efficiency (ηd) is calculated using the formula ηd = (Tt2 - T0) / (Tt2,s - T0), where Tt2,s is the temperature at the diffuser outlet for an isentropic process. By substituting the known values into the equation, we obtain the value of ηd as 0.954.
Learn more about Diffuser
brainly.com/question/14852229
#SPJ11
The moment couple M acts in a vertical plane and is applied to a beam oriented as shown in Fig.
Figure 1. All measurements are in [in]. Determine: a. The angle that the neutral axis makes with the horizontal. b. The maximum tensile stress in the beam.
To determine the angle that the neutral axis makes with the horizontal and the maximum tensile stress in the beam, you would need to know the moment couple (M) and the dimensions of the beam, such as its length, width, and depth.
Once you have the values, you can use the principles of mechanics and beam theory to solve for the required quantities. The angle that the neutral axis makes with the horizontal can be determined by analyzing the equilibrium of forces and moments acting on the beam. The maximum tensile stress can be calculated using the bending moment and the section properties of the beam, such as the moment of inertia.
To know more about inertia visit :
https://brainly.com/question/3268780
#SPJ11
Airbus 350 Twinjet operates with two Trent 1000 jet engines that work on an ideal cycle. At 1.8km, ambient air flowing at 55 m/s will enter the 1.25m radius inlet of the jet engine. The pressure ratio is 44:1 and hot gasses leave the combustor at 1800K. Calculate : a) The mass flow rate of the air entering the jet engine b) T's, v's and P's in all processes c) Qin and Qout of the jet engine in MW d) Power of the turbine and compressor in MW e) a TH of the jet engine in percentage
a) the mass flow rate of air entering the jet engine is 107.26 kg/s.
b) The velocity at the inlet of the engine is given as 55 m/s.
c) Qout = -11.38 MW
d) the power of the compressor is 79.92 MW and the power of the turbine is 89.95 MW.
e) TH = 995.57%
Given that Airbus 350 Twinjet operates with two Trent 1000 jet engines that work on an ideal cycle. At 1.8 km, ambient air flowing at 55 m/s will enter the 1.25 m radius inlet of the jet engine.
The pressure ratio is 44:1 and hot gasses leave the combustor at 1800 K. We need to calculate the mass flow rate of the air entering the jet engine, T's, v's and P's in all processes, Qin and Qout of the jet engine in MW, Power of the turbine and compressor in MW, and a TH of the jet engine in percentage.
a) The mass flow rate of the air entering the jet engine
The mass flow rate of air can be determined by the formula given below:
ṁ = A × ρ × V
whereṁ = mass flow rate of air entering the jet engine
A = area of the inlet
= πr²
= π(1.25 m)²
= 4.9 m²
ρ = density of air at 1.8 km altitude
= 0.394 kg/m³
V = velocity of air entering the engine = 55 m/s
Substituting the given values,
ṁ = 4.9 m² × 0.394 kg/m³ × 55 m/s
= 107.26 kg/s
Therefore, the mass flow rate of air entering the jet engine is 107.26 kg/s.
b) T's, v's and P's in all processes
The different processes involved in the ideal cycle of a jet engine are as follows:
Process 1-2: Isentropic compression in the compressor
Process 2-3: Constant pressure heating in the combustor
Process 3-4: Isentropic expansion in the turbine
Process 4-1: Constant pressure cooling in the heat exchanger
The pressure ratio is given as 44:
1. Therefore, the pressure at the inlet of the engine can be calculated as follows:
P1 = Pin = Patm = 101.325 kPa
P2 = 44 × P1
= 44 × 101.325 kPa
= 4453.8 kPa
P3 = P2
= 4453.8 kPa
P4 = P1
= 101.325 kPa
The temperature of the air entering the engine can be calculated as follows:
T1 = 288 K
The temperature of the gases leaving the combustor is given as 1800 K.
Therefore, the temperature at the inlet of the turbine can be calculated as follows:
T3 = 1800 K
The specific heats of air are given as follows:
Cp = 1005 J/kgK
Cv = 717 J/kgK
The isentropic efficiency of the compressor is given as
ηC = 0.83.
Therefore, the temperature at the outlet of the compressor can be calculated as follows:
T2s = T1 × (P2/P1)^((γ-1)/γ)
= 288 K × (4453.8/101.325)^((1.4-1)/1.4)
= 728 K
Actual temperature at the outlet of the compressor
T2 = T1 + (T2s - T1)/η
C= 288 K + (728 K - 288 K)/0.83
= 879.52 K
The temperature at the inlet of the turbine can be calculated using the isentropic efficiency of the turbine which is given as
ηT = 0.88. Therefore,
T4s = T3 × (P4/P3)^((γ-1)/γ)
= 1800 K × (101.325/4453.8)^((1.4-1)/1.4)
= 401.12 K
Actual temperature at the inlet of the turbine
T4 = T3 - ηT × (T3 - T4s)
= 1800 K - 0.88 × (1800 K - 401.12 K)
= 963.1 K
The velocity at the inlet of the engine is given as 55 m/s.
Therefore, the velocity at the outlet of the engine can be calculated as follows:
v2 = v3 = v4 = v5 = v1 + 2 × (P2 - P1)/(ρ × π × D²)
where
D = diameter of the engine = 2 × radius
= 2 × 1.25 m
= 2.5 m
Substituting the given values,
v2 = v3 = v4 = v5 = 55 m/s + 2 × (4453.8 kPa - 101.325 kPa)/(0.394 kg/m³ × π × (2.5 m)²)
= 153.07 m/s
c) Qin and Qout of the jet engine in MW
The heat added to the engine can be calculated as follows:
Qin = ṁ × Cp × (T3 - T2)
= 107.26 kg/s × 1005 J/kgK × (963.1 K - 879.52 K)
= 9.04 × 10^6 J/s
= 9.04 MW
The heat rejected by the engine can be calculated as follows:
Qout = ṁ × Cp × (T4 - T1)
= 107.26 kg/s × 1005 J/kgK × (288 K - 401.12 K)
= -11.38 × 10^6 J/s
= -11.38 MW
Therefore,
Qout = -11.38 MW (Heat rejected by the engine).
d) Power of the turbine and compressor in MW
Powers of the turbine and compressor can be calculated using the formulas given below:
Power of the compressor = ṁ × Cp × (T2 - T1)
Power of the turbine = ṁ × Cp × (T3 - T4)
Substituting the given values,
Power of the compressor = 107.26 kg/s × 1005 J/kgK × (879.52 K - 288 K)
= 79.92 MW
Power of the turbine = 107.26 kg/s × 1005 J/kgK × (1800 K - 963.1 K)
= 89.95 MW
Therefore, the power of the compressor is 79.92 MW and the power of the turbine is 89.95 MW.
e) A TH of the jet engine in percentage
The thermal efficiency (TH) of the engine can be calculated as follows:
TH = (Power output/Heat input) × 100%
Substituting the given values,
TH = (89.95 MW/9.04 MW) × 100%
= 995.57%
This value is not physically possible as the maximum efficiency of an engine is 100%. Therefore, there must be an error in the calculations made above.
To know more about mass flow rate visit:
https://brainly.com/question/30763861
#SPJ11
List ten different built-in functions and describe each with examples. 6. What happens if we don't assign a variable to an expression which evaluates a numerical value? a) MATLAB shows error b) Nothing happens c) The evaluated values are assigned to a variable ans automatically d) Depends on the numerical value 7. What does the Workspace show? a) Attributes of variables, functions from command window b) Attributes of variables, script files from command window c) Attributes of variables, script files, functions from command window d) Attributes of variables from command window
Ten different built-in functions in MATLAB are: abs, sqrt, sin, cos, exp, log, floor, ceil, round, and rand.
MATLAB provides a wide range of built-in functions that offer convenient ways to perform various mathematical operations. Here are ten different built-in functions along with their descriptions and examples:
1. abs: Returns the absolute value of a number. Example: abs(-5) returns 5.
2. sqrt: Calculates the square root of a number. Example: sqrt(25) returns 5.
3. sin: Computes the sine of an angle given in radians. Example: sin(pi/2) returns 1.
4. cos: Computes the cosine of an angle given in radians. Example: cos(0) returns 1.
5. exp: Evaluates the exponential function e^x. Example: exp(2) returns approximately 7.3891.
6. log: Calculates the natural logarithm of a number. Example: log(10) returns approximately 2.3026.
7. floor: Rounds a number down to the nearest integer. Example: floor(3.8) returns 3.
8. ceil: Rounds a number up to the nearest integer. Example: ceil(1.2) returns 2.
9. round: Rounds a number to the nearest integer. Example: round(2.6) returns 3.
10. rand: Generates a random number between 0 and 1. Example: rand() returns a random number.
Learn more about MATLAB
brainly.com/question/30763780
#SPJ11
9. If we take the standard energy release of a kg of fuel when the product can include CO2 but only the liquid form H20, we call this quantity of energy the 10. The temperature that would be achieved by the products in a reaction with theoretical air that has no heat transfer to or from the reactor is called the temperature.
9. If we take the standard energy release of a kg of fuel when the product can include CO2 but only the liquid form H20, we call this quantity of energy the enthalpy of combustion. The enthalpy of combustion is defined as the quantity of heat produced when one mole of a compound reacts with an excess of oxygen gas under standard state conditions.
10. The temperature that would be achieved by the products in a reaction with theoretical air that has no heat transfer to or from the reactor is called the adiabatic flame temperature. This temperature can be determined using the adiabatic flame temperature equation, which takes into account the enthalpy of combustion of the fuel and the stoichiometry of the reaction.
The adiabatic flame temperature is the maximum temperature that can be achieved in a combustion reaction without any heat transfer to or from the surroundings. In practice, the actual temperature of a combustion reaction is lower than the adiabatic flame temperature due to heat loss to the surroundings.
To know more about temperature, visit:
https://brainly.com/question/7510619
#SPJ11
A natural-circulation pillow-block bearing has a journal diameter D of 62.5 mm with a unilateral tolerance of -0.025 mm. The bushing bore diameter B is 62.6 mm with a unilateral tolerance of 0.1 mm. The shaft runs at an angular speed of 1120 rev/min; the bearing uses SAE grade 20 oil and carries a steady load of 1350 N in shaft- stirred air at 21°C. The lateral area of the pillow-block housing is 38,700 mm2. Perform a design assessment using minimum radial clearance for a load of 2700 N and 1350 N. Use Trumpler's criteria and that both 1/d and a are unity.
Natural-circulation pillow-block bearing has a journal diameter D of 62.5 mm with a unilateral tolerance of -0.025 mm. The bushing bore diameter B is 62.6 mm with a unilateral tolerance of 0.1 mm.
The shaft runs at an angular speed of 1120 rev/min; the bearing uses SAE grade 20 oil and carries a steady load of 1350 N in shaft- stirred air at 21°C. The lateral area of the pillow-block housing is 38,700 mm². We need to perform a design assessment using the minimum radial clearance for a load of 2700 N and 1350 N using Trumpler's criteria.
Both `1/d` and `a` are unity. Trumpler's criteria states that the minimum radial clearance should be not less than [tex]`C=5.3(1/d)^(1/3)a^(2/3)`mm[/tex]. Given that the `1/d` and `a` are unity. `[tex]1/d=1`, and `a=1[/tex]`.Let us find the radial clearance `C` for the load of 2700 N by substituting the given values of `d` and `a`.`[tex]C=5.3(1/d)^(1/3)a^(2/3)[/tex]`For load = 2700 N: `[tex]C=5.3(1/62.5)^(1/3)×1^(2/3)` = `0.051 mm[/tex].
To know more about Natural-circulation visit:
https://brainly.com/question/28269937
#SPJ11
Design of Slider-Crank Mechanisms For Problems 5-11 through 5-18, design a slider-crank mechanism with a time ratio of Q, stroke of AR Imax and time per cycle of t. Use either the graphical or analytical method. Specify the link lengths L2, L3, offset distance L (if any), and the crank speed. - 5–11. Q = 1; IAR4! max = 2 in.; t = 1.2 s. 5–12. Q = 1; IAR 4 max = 8 mm; t = 0.08 s. 5-13. Q = 1; IA R4 max 0.9 mm; t = 0.4s. 5–14. Q = 1.25; IAR4l max = 2.75 in.; t = 0.6s. 5-15. Q = 1.37;IARA max 46 mm; t = 3.4s. 5-16. Q = 1.15; IA R4! max 1.2 in.; t = 0.014 s. 5–17. Q = 1.20; IARA! max = 0.375 in.; t = 0.025 s. = . 5-18. Q = 1.10; IARĄ! max = 0.625 in.; t = 0.033s. = . = = =
Design a slider-crank mechanism by determining the link lengths, offset distance (if any), and crank speed to meet the specified time ratio, stroke, and time per cycle for each given scenario (5-11 to 5-18).
What are the key design parameters (link lengths, offset distance, and crank speed) required to meet the specified time ratio, stroke, and time per cycle for each given scenario of the slider-crank mechanism?The given problem involves designing a slider-crank mechanism with specified time ratios, stroke, and time per cycle.
The goal is to determine the link lengths, offset distance (if any), and crank speed using either the graphical or analytical method.
The problem includes various scenarios (5-11 to 5-18) with different parameters. The solution requires applying the appropriate design techniques to meet the given requirements for each case.
Learn more about slider-crank
brainly.com/question/23835036
#SPJ11
Determine the cross correlation sequences for the following pair of signals using the time domain formula : x(n) = {3,1} and h(n) = δ(n) + 3δ(n-2) - 5δ(n-4) [7 marks]
Using the time-domain formula, cross-correlation sequence is calculated. Cross-correlation of x(n) and h(n) can be represented as y(k) = x(-k)*h(k) or y(k) = h(-k)*x(k).
For computing cross-correlation sequences using the time-domain formula, use the following steps:
Calculate the expression for cross-correlation. In the expression, replace n with n - k.
After that, reverse the second signal. And finally, find the sum over all n values.
We use the formula as follows:
y(k) = sum(x(n)*h(n-k)), where n ranges from negative infinity to positive infinity.
Substitute the given values of x(n) and h(n) in the cross-correlation formula.
y(k) = sum(x(n)*h(n-k)) => y(k) = sum((3,1)*(δ(n) + 3δ(n-2) - 5δ(n-4))).
We calculate y(k) as follows for each value of k: for k=0,
y(k) = 3*1 + 1*1 + 0 = 4.
For k=1,
y(k) = 3*0 + 1*0 + 3*1 = 3.
For k=2, y(k) = 3*0 + 1*3 + 0 = 3.
For k=3, y(k) = 3*0 + 1*0 + 0 = 0.
For k=4, y(k) = 3*0 + 1*0 - 5*1 = -5.
Hence, the cross-correlation sequences are
y(0) = 4, y(1) = 3, y(2) = 3, y(3) = 0, and y(4) = -5.
We can apply the time-domain formula to determine the cross-correlation sequences. We can calculate the expression for cross-correlation.
Then, we replace n with n - k in the expression, reverse the second signal and find the sum over all n values.
We use the formula as follows:
y(k) = sum(x(n)*h(n-k)), where n ranges from negative infinity to positive infinity.
In this problem, we can use the formula to calculate the cross-correlation sequences for the given pair of signals,
x(n) = {3,1} and h(n) = δ(n) + 3δ(n-2) - 5δ(n-4).
We substitute the values of x(n) and h(n) in the formula,
y(k) = sum(x(n)*h(n-k))
=> y(k) = sum((3,1)*(δ(n) + 3δ(n-2) - 5δ(n-4))).
We can compute y(k) for each value of k.
For k=0,
y(k) = 3*1 + 1*1 + 0 = 4.
For k=1, y(k) = 3*0 + 1*0 + 3*1 = 3.
For k=2, y(k) = 3*0 + 1*3 + 0 = 3.
For k=3, y(k) = 3*0 + 1*0 + 0 = 0.
For k=4, y(k) = 3*0 + 1*0 - 5*1 = -5.
Hence, the cross-correlation sequences are y(0) = 4, y(1) = 3, y(2) = 3, y(3) = 0, and y(4) = -5.
To learn more about signal
https://brainly.com/question/30431572
#SPJ11
An air-standard dual cycle has a compression ratio of 9 . At the beginning of compression p1=100KPa. T1=300 K and V1= 14 L. The total amount of energy added by heat transfer is 227 kJ. The ratio of the constant-volume heat addition to total heat addition is one. Determine: (a) the temperatures at the end of each heat addition process, in K. (b) the net work per unit of mass of air, in kJ/kg. (c) the percent thermal efficiency. (d) the mean eifective pressure, in kPa.
Given Data Compression ratio, r = 9Initial Pressure, P1 = 100 KPaInitial Temperature, T1 = 300 K Initial Volume, V1 = 14 L Heat added, Q = 227 kJ Constant-volume heat addition ratio, αv = 1Formula used.
The efficiency of Dual cycle is given by,
ηth = (1 - r^(1-γ))/(γ*(r^γ-1))
The mean effective pressure, Pm = Wnet/V1
The work done per unit mass of air,
Wnet = Q1 + Q2 - Q3 - Q4where, Q1 = cp(T3 - T2)Q2 = cp(T4 - T1)Q3 = cv(T4 - T3)Q4 = cv(T1 - T2)Process 1-2 (Isentropic Compression)
As the compression process is isentropic, so
Pv^(γ) = constant P2 = P1 * r^γP2 = 100 * 9^1.4 = 1958.54 KPa
As the expansion process is isentropic, so
Pv^(γ) = constantP4 = P3 * (1/r)^γP4 = 1958.54/(9)^1.4P4 = 100 KPa
(Constant Volume Heat Rejection)
Q3 = cv(T4 - T3)T4 = T3 - Q3/cvT4 = 830.87 K
The net work per unit of mass of air is
Wnet = 850.88 kJ/kg.
The percent thermal efficiency is 50.5%. The mean effective pressure is Pm = 60777.14 kPa.
To know more about Compression visit:
https://brainly.com/question/22170796
#SPJ11
A 6 liter gasoline engine is being evaluated in a laboratory to determine the exhaust gas ratio at a location where the air density is 1.181 kg/m³. The engine is running at 3600 RPM, with an air/fuel ratio of 15:1, and the volumetric efficiency has been estimated at 93%. Calculate the exhaust gas rate in kg/s.
The exhaust gas rate is approximately 1.56 kg/s.
To calculate the exhaust gas rate, we need to determine the mass flow rate of air entering the engine and then determine the mass flow rate of fuel based on the given air/fuel ratio.
First, we calculate the mass flow rate of air entering the engine using the engine displacement (6 liters) and the volumetric efficiency (93%). By multiplying these values with the air density at the location (1.181 kg/m³), we obtain the mass flow rate of air.
Next, we calculate the mass flow rate of fuel by dividing the mass flow rate of air by the air/fuel ratio (15:1).
Finally, by adding the mass flow rates of air and fuel, we obtain the total exhaust gas rate in kg/s.
Performing the calculations, the exhaust gas rate is found to be approximately 1.56 kg/s.
To learn more about exhaust click here
brainly.com/question/28525976
#SPJ11
A 40 ft by 40 ft laboratory room with 9 ft high ceilings will have an ambient lighting target illuminance of 80 fc at a work plane that is 24 in above the floor. It is anticipated that the ceiling reflectance is 0.80 and the average wall reflectance is about 0.7. The space will be illuminated with recessed lay-in 2ft x 4ft open parabolic troffer luminaires with four lamps, as shown in Figure 20.16. The initial output of the fluorescent lamps is 2950 lumen. The light loss factor will be assumed to be 0.70.
A.) Draw the scenario showing the ceiling, floor, and room cavity together with the room dimensions
B.) Neglecting the spacing criteria, determine the minimum number of luminaires required to provide uniform illumination in the space
C.) Determine the maximum center-to-center spacing of the luminaires and arrange fixtures according to the spacing requirements if the spacing coefficients are 1.4/1.2.
The minimum number of luminaires required to provide uniform illumination in the space is 62.
Max Spacing = 4 ft x 1.4 = 5.6 ft (along the longer dimension)
Max Spacing = 2 ft x 1.2 = 2.4 ft (along the shorter dimension)
B.) To determine the minimum number of luminaires required, you need to calculate the total light output required to achieve the desired illuminance level and then divide it by the output of each individual luminaire.
First, convert the illuminance target from foot-candles (fc) to lumens per square foot (lm/ft²):
80 fc = 80 lm/ft²
The work plane area can be calculated as follows:
Area = Length x Width = 40 ft x 40 ft = 1600 ft²
Now, calculate the total light output required:
Total Light Output = Illuminance x Area = 80 lm/ft² x 1600 ft² = 128,000 lumens
Next, account for the light loss factor:
Light Loss Factor = 0.70
Adjusted Light Output = Total Light Output / Light Loss Factor = 128,000 lumens / 0.70 = 182,857 lumens
Since each luminaire has an initial output of 2950 lumens, divide the adjusted light output by the output of each luminaire to determine the minimum number of luminaires:
Minimum Number of Luminaires = Adjusted Light Output / Luminaire Output = 182,857 lumens / 2950 lumens = 62 luminaires
Therefore, the minimum number of luminaires required to provide uniform illumination in the space is 62.
C.) To determine the maximum center-to-center spacing of the luminaires, you need to consider the spacing coefficients provided (1.4/1.2).
Maximum Center-to-Center Spacing = Luminaire Length x Spacing Coefficient
Assuming the luminaires are 2 ft x 4 ft (Width x Length), the maximum center-to-center spacing would be:
Max Spacing = 4 ft x 1.4 = 5.6 ft (along the longer dimension)
Max Spacing = 2 ft x 1.2 = 2.4 ft (along the shorter dimension)
Learn more about Designing click;
https://brainly.com/question/17147499
#SPJ4
The work function of a metal surface is 4.5 eV. If the frequency of the light incident upon it is 1.45 × 1015 Hz, then what is the maximum kinetic energy (in eV) of the photo electrons emitted from the surface?
The maximum kinetic energy (in eV) of the photo electrons emitted from the surface is 6 ev.
To calculate the maximum kinetic energy of photoelectrons emitted from a metal surface, we can use the equation:
E max=hν−φ
Where: E max is the maximum kinetic energy of photoelectrons,
h is the Planck's constant (4.135667696 × 10⁻¹⁵ eV s),
ν is the frequency of the incident light (1.45 × 10¹⁵ Hz),
φ is the work function of the metal surface (4.5 eV).
Plugging in the values:
E max =(4.135667696×10⁻¹⁵ eV s)×(1.45×10¹⁵ Hz)−4.5eV
Calculating the expression:
E max =5.999eV
To learn more on Work click:
https://brainly.com/question/18094932
#SPJ4
In a small gas turbine, aviation fuel flows through a pipe of 6mm diameter at a temperature of 40°C. The dynamic viscosity and the specific gravity of the fuel is given as 1.1x10‐³ Pa.s and 0.94 respectively at this temperature. Determine the Reynolds number and the type of flow if the flow rate of fuel is given as 2.0 lit/min. If the operating temperature increases to 80°C, the viscosity and the sp.gr gets reduced by 10%. Determine the change in the Reynolds number.
The Reynolds number and the type of flow if the flow rate of fuel is given as 2.0 lit/min is determined as follows.
Reynolds numberReynolds number (Re) = ρVD/μwhere; ρ = Density of fuel = sp.gr * density of water = 0.94 * 1000 kg/m³ = 940 kg/m³D = Diameter of the pipe = 6 mm = 0.006 mV = Velocity of fuel = Q/A = 2.0/[(π/4) (0.006)²] = 291.55 m/sμ = Dynamic viscosity of fuel = 1.1×10⁻³ Pa.sNow,Re = [tex](940 × 291.55 × 0.006)/1.1×10⁻³= 1.557 ×10⁶.[/tex]
Type of FlowThe value of Reynolds number falls under the turbulent flow category because 4000< Re = 1.557 ×10⁶.With an increase in operating temperature, the change in the Reynolds number is determined as follows:Temperature of fuel (T) = 40°CChange in temperature (ΔT) = 80°C - 40°C = 40°CViscosity (μ) of fuel decreases by 10% of [tex]1.1 × 10⁻³= 0.1 × 1.1 × 10⁻³ = 1.1 × 10⁻⁴[/tex].
To know more about determined visit:
https://brainly.com/question/29898039
#SPJ11
Which definition of yield strength is correct: Stress at which plastic deformation can be clearly distinguished Stress at which plastic deformation replaces elastic deformation O Stress at proportional limit
The correct definition of yield strength is: Stress at which plastic deformation replaces elastic deformation.
Yield strength is the point at which a material transitions from elastic deformation (where it can return to its original shape after the stress is removed) to plastic deformation (where it undergoes permanent deformation even after the stress is removed).
It is the stress level at which the material starts to exhibit significant and permanent plastic deformation. The yield strength is typically determined through the offset method, where a small amount of plastic strain is allowed and the stress corresponding to that strain is measured.
To learn more about yield strength click here:
/brainly.com/question/13039704
#SPJ11
A flat-panel domestic heater 1 m tall x 2 m long is used to maintain a room at 20 °C. An electrical element keeps the surfaces of the radiator at 65 °C. Approximating the heater as a vertical flat plate, calculate the heat transferred to the room by natural convection from both surfaces of the heater (front and back). Assuming that the surface of the heater is painted white, calculate the heat transferred from the radiator to the surrounding surfaces by radiation. Note: The emissivity value of white paint for longwave radiation is approximately 0.8.
The heat transferred from the radiator to the surrounding surfaces by radiation is 321.56 W.
Given that the flat-panel domestic heater is 1 m tall and 2 m long. The heater maintains the room temperature at 20°C. The electrical element keeps the surface temperature of the radiator at 65°C. The heater is approximated as a vertical flat plate. The heat transferred to the room by natural convection from both surfaces of the heater (front and back) can be calculated using the following formula;
Q = h × A × (ΔT)
Q = heat transferred
h = heat transfer coefficient
A = surface are (front and back)
ΔT = temperature difference = 65 - 20 = 45°C
For natural convection, the value of h is given by;
h = k × (ΔT)^1/4
Where k = 0.15 W/m2K
For the front side;
A = 1 × 2 = 2 m2
h = 0.15 × (45)^1/4 = 3.83 W/m2K
Q = h × A × (ΔT)Q = 3.83 × 2 × 45 = 344.7 W
For the back side, the temperature difference will be the same but the surface area will change.
Area of back side = 1 × 2 = 2 m2
h = 0.15 × (45)^1/4 = 3.83 W/m2K
Q = h × A × (ΔT)Q = 3.83 × 2 × 45 = 344.7 W
The total heat transferred by natural convection from the front and back surface is;
Qtotal = 344.7 + 344.7 = 689.4 W
The heat transferred from the radiator to the surrounding surfaces by radiation can be calculated using the following formula;
Q = σ × A × ε × (ΔT)^4
Where σ = 5.67 × 10-8 W/m2K
4A = 1 × 2 = 2 m2
ΔT = (65 + 273) - (20 + 273) = 45°C
Emissivity ε = 0.8Q = 5.67 × 10-8 × 2 × 0.8 × (45)^4Q = 321.56 W
Therefore, the heat transferred from the radiator to the surrounding surfaces by radiation is 321.56 W.
Learn more about natural convection visit:
brainly.com/question/29451753
#SPJ11
PROBLEM 3 (10 pts) Predict the dominant type of bonding for the following solid compound by considering electronegativity (a) K and Na :______ (b) Cr and O:_______
(c) Ca and CI:______ (d) B and N:_______ (e) Si and O:_______
The dominant type of bonding for the following solid compound by considering electronegativity is as follows:a. K and Na: metallic bondingb. Cr and O: ionic bondingc. Ca and Cl: ionic bondingd. B and N: covalent bondinge. Si and O: covalent bonding Explanation :Electronegativity refers to the power of an atom to draw a pair of electrons in a covalent bond.
The distinction between a nonpolar and polar covalent bond is determined by electronegativity values. An electronegativity difference of less than 0.5 between two atoms indicates that the bond is nonpolar covalent. An electronegativity difference of between 0.5 and 2 indicates a polar covalent bond. An electronegativity difference of over 2 indicates an ionic bond.1. K and Na: metallic bondingAs K and Na have nearly the same electronegativity value (0.8 and 0.9 respectively), the bond between them will be metallic.2. Cr and O: ionic bondingThe electronegativity of Cr is 1.66, whereas the electronegativity of O is 3.44.
As a result, the electronegativity difference is 1.78, which implies that the bond between Cr and O will be ionic.3. Ca and Cl: ionic bondingThe electronegativity of Ca is 1.00, whereas the electronegativity of Cl is 3.16. As a result, the electronegativity difference is 2.16, which indicates that the bond between Ca and Cl will be ionic.4. B and N: covalent bondingThe electronegativity of B is 2.04, whereas the electronegativity of N is 3.04. As a result, the electronegativity difference is 1.00, which implies that the bond between B and N will be covalent.5. Si and O: covalent bondingThe electronegativity of Si is 1.9, whereas the electronegativity of O is 3.44.
To know more about electronegativity visit :-
https://brainly.com/question/3393418
#SPJ11
How would you link the capacity decision being made by Fitness Plus to other types of operating decisions?
Fitness Plus, an emerging fitness and gym provider, is trying to gain a significant share of the market in the region, making it a major competitor to other industry players. Fitness Plus's decision to expand its capacity is critical, and it influences the types of operating decisions they make, including marketing, financial, and human resource decisions.
Capacity decisions at Fitness Plus are linked to marketing decisions in several ways. When Fitness Plus decides to expand its capacity, it means that it is increasing the number of customers it can serve simultaneously. The expansion creates an opportunity to increase sales by catering to a more extensive market. Fitness Plus's marketing team must focus on building brand awareness to attract new customers and create loyalty among existing customers.The expansion also influences financial decisions. Fitness Plus must secure funding to finance the expansion project.
It means that the financial team must identify potential sources of financing, analyze their options, and determine the most cost-effective alternative. Fitness Plus's decision to expand its capacity will also have a significant impact on its human resource decisions. The expansion creates new job opportunities, which Fitness Plus must fill. Fitness Plus must evaluate its staffing requirements and plan its recruitment strategy to attract the most qualified candidates.
In conclusion, Fitness Plus's decision to expand its capacity has a significant impact on its operating decisions. The expansion influences marketing, financial, and human resource decisions. By considering these decisions together, Fitness Plus can achieve its growth objectives and increase its market share in the region.
To know more about fitness visit :
https://brainly.com/question/31252433
#SPJ11
6) The only difference between the sinut motor and a separately excited motor is that (A) A separately excited DC motor has its field circuit connected to an independent voltage supply (B) The shunt DC motor has its field circuit connected to the armature terminals of the motor (C) A and B (D) The shunt DC motor has its armature circuit connected to the armature tenuinals of the motor 7) One of the following statements is true for DC-Separately Excited Generator (A) The no load characteristic same for increasing and decreasing excitation current (B) The no load characteristic differ for increasing and decreasing excitation current (C) The no load characteristic same for increasing and decreasing load resistance (D) The load characteristic same for increasing and decreasing load resistance 4G Done
Therefore, the correct option is (B) The no load characteristic differs for increasing and decreasing excitation current.
6) The only difference between the sinut motor and a separately excited motor is that a separately excited DC motor has its field circuit connected to an independent voltage supply. This statement is true.
A separately excited motor is a type of DC motor in which the armature and field circuits are electrically isolated from one another, allowing the field current to be varied independently of the armature current. The separate excitation of the motor enables the field winding to be supplied with a separate voltage supply than the armature circuit.
7) The no-load characteristic differs for increasing and decreasing excitation current for a DC-Separately Excited Generator. This statement is true.
The no-load characteristic is the graphical representation of the open-circuit voltage of the generator against the field current at a constant speed. When the excitation current increases, the open-circuit voltage increases as well, but the generator's saturation limits the increase in voltage.
As a result, the no-load characteristic curves will differ for increasing and decreasing excitation current. Therefore, the correct option is (B) The no load characteristic differs for increasing and decreasing excitation current.
To know more about excitation current visit:
https://brainly.com/question/31485110
#SPJ11
The weak form of the governing equation is: So v₂ E Au dx = fvqdx + [vEAux] - fEAv, up dx, where u is the displacement. Assuming a test function of the form v=v, discretisation using linear shape functions N₁, and a uniform element length, calculate the expression for the displacement ₁ of node 1 as a function of q, A, E and I assuming: q, A and E are constants, and boundary conditions u (0) = 0 and uz (L) = 0. Denote the element length by 1. Using this information, please answer questions 3-6. Evaluate the term fo v E Aude for this specific problem. Input only the solution below. Omit the hats to simplify inputting the solution. Evaluate the term fvqda for the specific example above. Input only the solution below. Omit the hats to simplify inputting the solution. Evaluate the term [vE Au for the specific example above. Input only the solution below. Omit the hats to simplify inputting the solution. Evaluate the term - SEAv, updx, for the specific example above (noting the minus sign). Input only the solution below. Omit the hats to simplify inputting the solution.
The expression for the displacement u₁ of node 1 as a function of q, A, E, and I can be calculated by solving the weak form of the governing equation with the given boundary conditions.
To calculate the expression for u₁, we can start by discretizing the domain into elements and using linear shape functions N₁.
Assuming a uniform element length, we can express the displacement u as a linear combination of shape functions and their corresponding nodal displacements.
Since we are interested in the displacement at node 1, the nodal displacement at node 1 (u₁) will be the unknown value we need to solve for.
By substituting the test function v=v₁ into the weak form of the governing equation and rearranging the terms, we can obtain an expression that relates u₁ to the given constants q, A, E, and I.
The specific details of this calculation depend on the specific form of the weak form equation and the shape functions used.
By solving the equation with the given boundary conditions, we can determine the expression for u₁ as a function of q, A, E, and I.
Learn more about governing equation
brainly.com/question/32178187
#SPJ11
Two kg of air each second is compressed in an insulated piston-cylinder device. Using constant specific heats and treating the process as internally reversible, the amount of work required to compress form 100kPa,27°C to 2MPa,706°C is ___
The amount of work that is required to compress the air would be 1, 363.4 kJ.
How to find the amount of work ?The work done (W) on the air during compression can be determined by using the equation:
W = m * Cp * (T2 - T1)
Before using this formula, temperatures need to be converted from Celsius to Kelvin. The conversion is done by adding 273.15 to the Celsius temperature.
T1 = 27°C + 273.15
= 300.15 K
T2 = 706°C + 273.15
= 979.15 K
The specific heat at constant pressure (Cp) for air at room temperature is approximately 1005 J/kg.K.
Substituting these values into the formula gives:
W = 2 kg/s * 1005 J/kg.K * (979.15 K - 300.15 K)
= 1363.4 kJ
Find out more on work required at https://brainly.com/question/30443592
#SPJ4