Answer:
They would land at the same time
Explanation:
They would land at the same exact time.
As weird, impossible and unbelievable as it appears. When in a vacuum, every weight, body and material when released from the same height would land on the ground at the same time. This also means that like in the question, a feather and a ball would land at the same time. And just for illustrations as well, a feather and a car would land at the same time as well.
Compare and contrast O2 and F2.
Answer:
1) Similarity:
1. diatomic molecules.
2. nonpolar covalent bond.
3. gaseus state at room temperature.
4. very reactive, with high electronegativity.
How would the force of gravity between two objects change if the mass of
each object were doubled?
A. The force between them would be 2 times larger than with the
initial masses.
B. The force between them would be 1/4 the force with the initial
separation.
C. The force between them would be 4 times larger than with the
initial masses.
D. The force between them would be 1/2 the force with the initial
separation
Answer:
Option C. The force between them would be 4 times larger than with the
initial masses.
Explanation:
To know which option is correct, we shall determine the force of attraction between the two masses when their masses are doubled. This can be obtained as follow:
From:
F = GMₐM₆/ r²
Keeping G/r² constant, we have
F₁ = MₐM₆
Let the initial mass of both objects to be m
F₁ = MₐM₆
F₁ = m × m
F₁ = m²
Next, let the masses of both objects doubles i.e 2m
F₂ = MₐM₆
F₂ = 2m × 2m
F₂ = 4m²
Compare the initial and final force
Initial force (F₁) = m²
Final (F₂) = 4m²
F₂ / F₁ = 4m² / m²
F₂ / F₁ = 4
F₂ = 4F₁ = 4m²
From the above illustrations, we can see that when the mass of both objects doubles, the force between them would be 4 times larger than with the
initial masses.
Thus, option C gives the correct answer to the question.
What has gravity led scientists to understand?
Answer:
Gravity is a non-contact force that was observed famously by Sir Isaac Newton, who watched an apple falling from a tree to the ground. ... Newton was the first to realise that gravity existed in space and it was the force which holds the Moon in orbit around the Earth and planets in orbit around the Sun.
Answer:
Newton's theory had prove that all objects, as small as an apple and as large as a planet, are subjected to gravity. Gravity helped to keep the planets rotating around the sun and creates the ebbs and flows of rivers and tides.Which of these materials is permeable?
PLEASE if you see these people (they all seem to have the same profile picture) NOTIFY THE PERSON ASKING THE QUESTION THAT THIS IS MALWARE AND REPORT IT!!
Stay safe, everyone!
(posting this in all subjects)
Answer:
ʕ •ᴥ•ʔ
Explanation:
What is the gravitational energy of a 2.63kg
book when it is lifted 14.29m off the floor?
Give your answer rounded to one place after the
decimal, no units.
Question 3
Answer:
G.P.E = 368.3
Explanation:
Given the following data;
Mass = 2.63kg
Height, h = 14.29m
We know that acceleration due to gravity is equal to 9.8m/s²
To find the gravitational potential energy;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;
[tex] G.P.E = mgh[/tex]
Where;
G.P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
[tex] G.P.E = 2.63*9.8*14.29 [/tex]
G.P.E = 368.3
Note: the unit of gravitational potential energy is Joules.
Pls someone help me!!!!!
Answer:
Seeing as how the balloon is mainly negatively charged and the paper being positively charged, the answer would be B: The tissue paper will stick to the balloon because the tissue paper is positively charged!
Pedro picked up and held a cube of ice in his hand and noticed that he no longer felt a difference in temperature after the ice cube melted in his hand. Which of the following statement best explains what happened?
1.Heat was transferred from Pedro’s hand to the ice increasing the temperature of the ice.
2.Heat was released from the ice cube into the air increasing the temperature of the ice.
3.Cold was transferred to Pedro’s hand from the ice increasing the temperature of the ice.
4.Heat was released from Pedro’s hand into the air melting the ice increasing the temperature of the ice.
Answer:
the answers is 1.
Explanation:
this is because heat always travel's from the warmest object to the coldest. His hands thermal energy is transferred to the ice making the ice round to the same temperature of his hand. This can also be an example of equalibrum.
1.
X, Y and Z are the weights of three objects
suspended by pulleys as shown.
Assuming the pulleys in this system are frictionless
and weightless and that Z= 12 N, what are the
values of X and Y?
24°
50°
Х
Y
Z
Answer:
The weight of the object X is approximately 3.262 N (Acting downwards)
The weight of the object Y is approximately 8.733 N (Acting downwards)
Explanation:
The question can be answered based on the principle of equilibrium of forces
The given parameters are;
The weight of Z = 12 N (Acting downwards)
The weight of the pulleys = Negligible
From the diagram;
The tension in the in the string attached to object Z = The weight of object Z = 12 N
The tension in the in the string attached to object X = The weight of the object X
The tension in the in the string attached to object Y = The weight of the object Y
Given that the forces are in equilibrium, we have;
The sum of vertical forces acting at a point, [tex]\Sigma F_y[/tex] = 0
Therefore;
[tex]T_{1y} + T_{2y} + T_{3y} = 0[/tex]
[tex]T_{1y} = -( T_{2y} + T_{3y} )[/tex]
Where;
[tex]T_{1y}[/tex] = The weight of object Z = 12 N
[tex]T_{1y}[/tex] = 12 N
[tex]T_{2y}[/tex] = The vertical component of tension, T₂ = T₂ × sin(24°)
∴ [tex]T_{2y}[/tex] = T₂ × sin(156°)
Similarly;
[tex]T_{3y}[/tex] = T₃ × sin(50°)
From [tex]T_{1y} = -( T_{2y} + T_{3y} )[/tex], and [tex]T_{1y}[/tex] = 12 N, we have;
12 N = -(T₂ × sin(156°) + T₃ × sin(50°))...(1)
Given that the forces are in equilibrium, we also have that the sum of vertical forces acting at a point, ∑Fₓ = 0
Therefore at point B, we have;
T₁ₓ + T₂ₓ + T₃ₓ = 0
The tension force, T₁, only has a vertical component, therefore;
∴ T₁ₓ = 0
∴ T₂ₓ + T₃ₓ = 0
T₂ₓ = -T₃ₓ
T₂ₓ = T₂ × cos(156°)
T₃ₓ = T₃ × cos(50°)
From T₂ₓ = -T₃ₓ, we have;
T₂ × cos(156°) = - T₃ × cos(50°)...(2)
Making T₃ the subject of equation (1) and (2) gives;
Making T₃ the subject of equation in equation (1), we get;
12 = -(T₂ × sin(156°) + T₃ × sin(50°))
∴ T₃ = (-12 - T₂ × sin(156°))/(sin(50°))
Making T₃ the subject of equation in equation (2), we get;
T₂ × cos(156°) = - T₃ × cos(50°)
∴ T₃ = T₂ × cos(156°)/(-cos(50°))
Equating both values of T₃ gives;
(-12 - T₂ × sin(156°))/(sin(50°)) = T₂ × cos(156°)/(-cos(50°))
-12/(sin(50°)) = T₂ × cos(156°)/(-cos(50°)) + T₂ × sin(156°)/(sin(50°))
∴ T₂ = -12/(sin(50°))/((cos(156°)/(-cos(50°)) + sin(156°)/(sin(50°))) ≈ -8.02429905283
∴ T₂ ≈ -8.02 N
From T₃ = T₂ × cos(156°)/(-cos(50°)), we have;
T₃ = -8.02× cos(156°)/(-cos(50°)) = -11.3982199717
∴ T₃ ≈ -11.4 N
The weight of the object X = -T₂ × sin(156°)
∴ The weight of the object X ≈ -(-8.02 × sin(156°)) = 3.262 N
The weight of the object X ≈ 3.262 N (Acting downwards)
The weight of the object Y = -(T₃ × sin(50°))
∴ The weight of the object Y = -(-11.4 × sin(50°)) ≈ 8.733 N
The weight of the object Y ≈ 8.733 N (Acting downwards)
4. Without the sun, there would be no way to replace energy released into the environment. True or False
Answer:
true
Explanation:
If you walk at an average speed of 5 km/h for 30 minutes,
how far will you walk?
Answer:
150
Explanation:
30 times 5 = 150 i think
6. Explain how you could increase the potential energy of an object. *
Answer:
a doubling of the height will result in a doubling of the gravitational potential energy.
Explanation:
why do colliding objects of unequal mass experience different effects
If the charge 16 C flows through the lightening during time 0.002 s then the AVERAGE current is equal to
80 A
8000 A
80000 A
0 A
Other:
Answer:
the average current is 8000 A
Explanation:
I got it answered by an expert
Assume that a vaulter is able to carry a vaulting pole while running as fast
as Carl Lewis in his world record 100-m dash (around 12 m/s). Also assume
that all of the vaulter's kinetic energy is transformed into gravitational
potential energy. What vaulting height could that person attain?
(Hint: Use the equation 5 mu? = mgh.)
Answer:
5mu = carry a vaulting pole ( 12 m/s) Also
fast
All the vaulter's kinetic energy is transformed into gravitational potential energy. 7.35m is the that person's height.
What is kinetic energy ?Kinetic energy is the energy that an object has as a result of its movement. If we want to accelerate an object, we must apply force to it. Using force requires us to put in effort. After work is completed, energy is transferred to the object, and the object moves at a new constant speed.
The two most important factors influencing kinetic energy are mass and speed. Because an object's motion is determined by its velocity as well as its mass, though velocity is th
Given:
v = 12m/s
g = 9.8 m/s²
Kinetic energy = potential energy
K.E = P.E
1/2 mv² = mgH
H = v² /2g
H = 7.35m
Thus, 7.35m is the that person's height.
To learn more about the kinetic energy, follow the link;
https://brainly.com/question/15764612
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Newton’s 3rd law is for every action, there is an equal and opposite reaction
True of false
Answer:
true
Explanation:
newton's third law of motion states that if body A exerts a force on the body B, then body B will exert an equal and opposite force on body A,
this is called action reaction pair
hope this helps
how can we realize that light travel in straight line ?
Answer:
It can be seen from the operation of pin-hole camera, formation of shadows and eclipse.
Explanation:
The phenomenon of light traveling in a straight line is known as rectilinear propagation of light.
One this evidence can be seen from the operation of pin-hole camera, which depends on rectilinear propagation of light
Also two natural effects that result from the rectilinear propagation of light are the formation of Shadows and Eclipse.
What is a parallel universe, and could there potentially be ones that contain doppelgängers of everyone on Earth?
Answer:
what i commented.
Explanation:
8. A partial food web is shown. The mourning dove is a bird that is often part of this food web. Which of these describes the mourning dove when it is part of the food web shown? A Parasite-host relationship with the robin because it uses the robin's nest. B Predator-prey relationship with tent caterpillars because they both use the same resources from the sugar-maple tree. C Producer-consumer relationship with sugar-maple trees because it gets food from the trees. D Producer-consumer relationship with its young because it feeds its young regurgitated food
Answer:
It has producer-consumer relationship with sugar-maple trees because it gets food from the trees.
Explanation:
The mourning bird is primarily a seed eater and not an insect eater. Since it is a seed eater, it will directly from the sugar-maple tree which is the producer.
In an ecosystem, the producers are plants which can trap energy directly from the sun during photosynthesis. This energy is passed on to the consumers.
Hence, the mourning bird has producer-consumer relationship with sugar-maple trees because it gets food from the trees.
help plz ??????????what’s the answer
Answer:
Gtvybhnhufv
Vvghccg. cguvtj. ohcswtil
Explanation:
Windowing. Undisturbed. Undisputed. JDownloader infidel into JDownloader krypton JDownloader kcfu kcfu
Pls help me find the electrons of these 4 questions asap.
The frequency will be 6 × 1014 H z of a typical green photon of 500nm emitted by the Sun. a. TRUE
b. FALSE
what is wavelength ??? sound is heard louder in newly furnished room why?
Answer:
Wavelength is the distance fromone crest to another or from one troughtto another of a wave is called wavelength.
When do sunspots disappear?
A) Sunspots are always present and NEVER disappear.
B) Once the magnetic field weakens in the area and cold plasma enters the area of the sunspot
C) Once the magnetic field weakens in the area and hotter plasma enters the area of the sunspot
D) Once the magnetic field strengthens in the area and hotter plasma enters the area of the sunspot
Answer:
In 5 years or so, the sun will be awash in sunspots and more prone to violent bursts of magnetic activity.
Explanation
once the magnetic field weakens the area and cold plasma enters the area of the sunspot
Answer
The answer is C I took the test an got an A.
Explanation:
K12 ASTRONOMY 7.07.04
Under the Big Top elephant, Ella (2500 kg), is attracted to Phant, the 3,000 kg
elephant. They are separated by 8 m. What is the gravitational attraction between
them?
Under the Big Top elephant, Ella (2500 kg), is attracted to Phant, the 3,000 kg elephant. They are separated by 8
A series of four different cylinders were each subjected to a force by placing four different masses on top of them. The mass placed on each cylinder
and dimensions of each cylinder are shown below. Rank the stress on these cylinders from least to greatest.
Mass (kg) Diameter (cm) Height (cm)
Case
A
B
С
D
5.2
3.6
4.7
2.9
2.6
2.3
2.7
32.2
32.5
27.3
16.9
Answer:
C, B, D, A
Explanation:
Stress is F/A, where F = 9.8*mass and A = pi(d/2)^2
Do the math for each and the stress from least to greatest is C, B, D, A.
The height column is unnecessary information.
When four different cylinders(A,B,C,D) were each subjected to a force by placing four different masses on top of them. the Rank of stress on these cylinders from least to greatest is D, C, B, A.
What is Stress ?Stress is defined as applied force(F) per unit cross sectional area(A) on which force is applied. it I.e. Stress = F/A. its SI unit is N/m². More force on small area leads to higher stress.
Given,
For A
Mass m = 5.2 kg
Diameter = 2.6 cm
Radius r = 1.3 cm = 0.013 m
Height = 32.5
Stress on A = Force ÷ A = mg ÷ πr²
Stress = (5.2×9.8) ÷ (3.14×0.013²)
Stress = 96031 N/m²
For B
Mass m = 3.6 kg
Diameter = 2.3 cm
Radius r = 1.15 cm = 0.011 m
Height = 27.3
Stress on B = Force ÷ A = mg ÷ πr²
Stress = (3.6 ×9.8) ÷ (3.14×0.011 ²)
Stress = 92856 N/m²
C
Mass m = 4.7 kg
Diameter = 2.7 cm
Radius r = 1.35 cm = 0.0135 m
Height = 16.9
Stress on C= Force ÷ A = mg ÷ πr²
Stress = (4.7 ×9.8) ÷ (3.14×0.0135²)
Stress = 80487 N/m²
D
Mass m = 2.9 kg
Diameter = 32.2 cm
Radius r = 16.1 cm = 0.16 m
Stress on D = Force ÷ A = mg ÷ πr²
Stress = (2.9×9.8) ÷ (3.14×0.16²)
Stress = 353 N/m²
Hence Rank of stresses on the 4 cylinders are D, C, B, A
To know more about Stress, click :
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A car has a mass of 1500 kg. It is traveling at a speed of 0.52 m/s. What is the kinetic energy of the car?
a.202.8 J
b.202.8
c.390 J
d.390
Answer:
c
Explanation:
A rock is thrown straight up with an initial speed of 15.5 m/s . It is caught at the same distance above the ground . How high does the ball rise? How long does the ball remain in the air?
Answer:
The height risen by the rock is 12.26 mThe time spent in air by the rock is 3.16 sExplanation:
Given;
initial velocity of the rock, u = 15.5 m/s
at maximum height the final velocity of the rock, v = 0
The height risen by the rock is calculated as follows;
v² = u² - 2gh
0 = u² - 2gh
2gh = u²
h = u² / 2g
h = (15.5²) / (2 x 9.8)
h = 12.26 m
The time spent in air by the rock is known as time of flight, which is calculated as follows;
v = u - gt
0 = u - gt
gt = u
t = u/g
where;
t is the time to reach maximum height
t = 15.5 / 9.8
t = 1.58 s
Time of flight (time spent in air) is calculated as;
T = 2t
T = 2 x 1.58 s
T = 3.16 s.
10 turns of wire are closely wound around a pencil as shown in the figure. when measured using a scale as shown, the length of total turns is obtained 25mm. then a) What is the thickness of the wire? b) Express the thickness of the wire in centimetre.
Answer:
1. 2.5 mm
2. 0.25 cm
Explanation:
Since the length of the 10 turns of the wire around the pencil is 25 mm, then;
1. the thickness of the wire = [tex]\frac{length of total turns}{number of turns}[/tex]
= [tex]\frac{25}{10}[/tex]
= 2.5 mm
The thickness of the wire is 2.5 mm.
2. Since 10 mm = 1 cm, then;
25 mm = 2.5 cm
So that,
the thickness of the wire in centimetre = [tex]\frac{length of total turns}{number of turns}[/tex]
= [tex]\frac{2.5}{10}[/tex]
= 0.25 cm
The thickness of the wire is 0.25 cm.
What is the ideal mechanical advantage of a ramp with a height of 3.5 and a length of 14.0 meters
Answer:
ghj
Explanation: