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Chapter

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CH5.3

Problem

Problem List

10SMB

Printed circuit boards are used in the electronics industry to both connect and hold components in place. In production, 0.03 in. of copper foil is laminated to an insulating plastic board. A circuit pattern made of a chemically resistant polymer is then printed on the board. Next, the unwanted copper is chemically etched away by using selected reagents. If copper is treated with Cu(NH3 ) 4Cl2 (cupric ammonium chloride) and NH4OH (ammonium hydroxide), the products are water and Cu(NH3) 4Cl (cuprous ammonium chloride). Once the copper is dissolved, the polymer is removed by solvents, leaving the printed circuit ready for further processing. If a single-sided board 4 in. by 8 in. is to have 75% of the copper layer removed using these reagents, how many grams of each reagent will be consumed? Data: The density of copper is 8.96 g/cm3.​

Answers

Answer 1

ladoooooooooioooooioiiioooo


Related Questions

If the molecule has n-C2 axes perpendicular to its Cn axis, choose True. Otherwise, choose False. Be sure to build a model or draw the structure before selecting your answer. If needed, search for the molecular structure online or in a textbook.XeF4[PdCl4]2−naphthalenefuran, C4H4O

Answers

Answer:

XeF4                  True

[PdCl4]2−           True

naphthalene      True

Furan                  False

C4H4O               False  

Explanation:

From the given information:

Only XeF4;  [PdCl4]2−;  naphthalene are true. This is because their molecules contain -nC₂ axis which is perpendicular to the Cn axis. The image attached below shows the structural formula of each compound, there below, we can see that Furan only possesses one C₂ axis but not -nC₂ ⊥ C₂.

(1.21 x 10^-3 + 1.3 x 10^-3) x 6.453 x 10^2 =

Answers

Answer:

1.61

Explanation:

calculate the molecular mass of sodium trioxocarbonate (iv) decahydrate. hints (H= 1, C=12, O=16, Na=23​

Answers

Given :

A compound sodium trioxocarbonate (iv) decahydrate.

To Find :

The molecular mass of sodium trioxocarbonate (iv) decahydrate.

Solution :

We know, molecular formula of sodium trioxocarbonate (iv) decahydrate is :

Na₂CO₃.10H₂O

Now, we can calculate its molecular mass :

M = ( 2 × 23 ) + 12 + ( 3 × 16 ) + 10 × ( 1 × 2 + 16)

M = 46 + 12 + 48 + ( 10 × 18 )

M = 286 gram/mol

Hence, this is the required solution.

Which of the following describes a spectrum?
A. A measurement of the energy associated with an electron
transition
B. A piece of glass that causes light to be divided into different
colors
C. A range of wavelengths or frequencies of electromagnetic
radiation
D. A list of the quantum numbers assigned to a particular electron

Answers

Answer: The Answer would be C

Explanation: A spectrum is a Range of Wavelengths and Frequencies of Electromagnetic Radition.

The statement that describe spectrum is a range of wavelengths or frequencies of electromagnetic radiation.

What is Spectrum?

Spectrum arrangement or electromagnetic radiations base on their wavelength and frequency which can be visible light, ultraviolet, and infrared light. An instrument that is use for visual observation of spectra is called a spectroscope.

Therefore, The statement that describe spectrum is a range of wavelengths or frequencies of electromagnetic

radiation.

Learn more about spectrum from the link below.

https://brainly.com/question/4901067

According to one acid-base theory, water can act as a base because a water molecule can

1) donate an H+ ion
2) accept an H+ ion
3) donate an H- ion
4) accept an H- ion

Answers

Answer:

1) donate an H+ ion

Explanation:

option 1 is correct

3 A soil has 70% sand, 20% silt
and 10% clay. What kind of soil is it? How do its proportions need
to be changed to make it
into a loam?

Answers

Today, as part of the series of posts on soils, we are going to look at ‘soil texture’. Soil forms the basis for all life but it’s important to know about its mineral constitution as well as its biological profile.

Texture refers to the ‘feel’ of the soil. This is affected by the constituent materials found within it, specifically sand, silt and clay particles. A coarse sand will feel gritty but a wet clay will feel heavy and sticky. The texture of a soil has a direct impact on the way the soil reacts to certain environmental conditions – for example, towards drought or heavy rain (with sandy soils more freely draining).

There is a big difference in the size of the different particles.

Coarse sand = diameter 2-0.2mm

Fine sand = diameter 0.2-0.02mm

Silt = diameter 0.02-0.002mm

Clay = diameter less than 0.002mm

Note how the clay particles are much smaller than the sand particles – this is important as it means the total surface area of a clay soil is much greater and so the capacity to hold water is also much greater.

Between the sand, silt and clay particles there are lots of pores. In fact a soil as a whole is generally 45% mineral, 5% organic matter (depending on the soil) and 50% pore space through which air and water can pass.

Sand –

Made up of weathered primary rock minerals.

The particles are irregular in outline.

They are large and so do not pack together easily.

Large pore spaces in between.

Air gets in very easily and water flows rapidly through it.

Silt –

Is HNO3 an acid or a base



I NEED HELP ASAP​

Answers

Answer:

HNO3 is a potent acid, a base, a nitrating agent and a heavy oxidising agent at times. In the presence of a stronger acid, it serves as a base.

Explanation:

Answer:

It is a strong acid

Explanation:

Science- I need help with a question really quick I’m ending school soon

Answers

Bar graph, and charge your phone
the answers bar graph

I have added 15 L of air to a balloon at sea level (1.0 atm). If I take the balloon with me
to Denver, where the air pressure is 0.85 atm, what will the new volume of the balloon
be?

Answers

Answer:17.65 or 18 L

Explanation:

What is the molarity and normality of solution containing 80 g of NaOH dissolved in 2.0 liter of the solution?

Answers

AAnswer:

Explanation:

Chemical properties of an element are primarily dependent upon Group of answer choices the electron configuration of the element atomic weight of the element the number of main energy levels (electron shells) of the element the number of electrons in the innermost shell of the atom

Answers

Answer:

The answer is "the electron configuration of the element".

Explanation:

Electronics are distributed in atomic and molecular orbit via electrons from an atom or a molecule.

It reflects a most frequent dependence on valence electrons in the outer.

Through analyzing the context of the regular periodic table, the individual atoms are helpful. That's also important to understand chemical connections, which hold electrons together. This similar approach helps to explain the specific characteristics of lasers or semiconductors for bulk materials.

what's autonization of water​

Answers

Explanation:

The self-ionization of water (also autoionization of water, and autodissociation of water) is an ionization reaction in pure water or in an aqueous solution, in which a water molecule, H2O, deprotonates (loses the nucleus of one of its hydrogen atoms) to become a hydroxide ion, OH−. The hydrogen nucleus, H+, immediately protonates another water molecule to form hydronium, H3O+. It is an example of autoprotolysis, and exemplifies the amphoteric nature of water

Animation of the self-ionization of water

Chemically pure water has an electrical conductivity of 0.055 μS/cm. According to the theories of Svante Arrhenius, this must be due to the presence of ions. The ions are produced by the water self-ionization reaction, which applies to pure water and any aqueous solution:

H2O + H2O ⇌ H3O+ + OH−

Expressed with chemical activities a, instead of concentrations, the thermodynamic equilibrium constant for the water ionization reaction is:

{\displaystyle K_{\rm {eq}}={\frac {a_{\rm {H_{3}O^{+}}}\cdot a_{\rm {OH^{-}}}}{a_{\rm {H_{2}O}}^{2}}}}

which is numerically equal to the more traditional thermodynamic equilibrium constant written as:

{\displaystyle K_{\rm {eq}}={\frac {a_{\rm {H^{+}}}\cdot a_{\rm {OH^{-}}}}{a_{\rm {H_{2}O}}}}}

under the assumption that the sum of the chemical potentials of H+ and H3O+ is formally equal to twice the chemical potential of H2O at the same temperature and pressure.[1]

Because most acid–base solutions are typically very dilute, the activity of water is generally approximated as being equal to unity, which allows the ionic product of water to be expressed as:[2]

{\displaystyle K_{\rm {eq}}\approx a_{\rm {H_{3}O^{+}}}\cdot a_{\rm {OH^{-}}}}

In dilute aqueous solutions, the activities of solutes (dissolved species such as ions) are approximately equal to their concentrations. Thus, the ionization constant, dissociation constant, self-ionization constant, water ion-product constant or ionic product of water, symbolized by Kw, may be given by:

{\displaystyle K_{\rm {w}}=[{\rm {H_{3}O^{+}}}][{\rm {OH^{-}}}]}

where [H3O+] is the molarity (≈ molar concentration)[3] of hydrogen or hydronium ion, and [OH−] is the concentration of hydroxide ion. When the equilibrium constant is written as a product of concentrations (as opposed to activities) it is necessary to make corrections to the value of {\displaystyle K_{\rm {w}}} depending on ionic strength and other factors (see below).[4]

At 25 °C and zero ionic strength, Kw is equal to 1.0×10−14. Note that as with all equilibrium constants, the result is dimensionless because the concentration is in fact a concentration relative to the standard state, which for H+ and OH− are both defined to be 1 molal (or nearly 1 molar). For many practical purposes, the molal (mol solute/kg water) and molar (mol solute/L solution) concentrations can be considered as nearly equal at ambient temperature and pressure if the solution density remains close to one (i.e., sufficiently diluted solutions and negligible effect of temperature changes). The main advantage of the molal concentration unit (mol/kg water) is to result in stable and robust concentration values which are independent of the solution density and volume changes (density depending on the water salinity (ionic strength), temperature and pressure); therefore, molality is the preferred unit used in thermodynamic calculations or in precise or less-usual conditions, e.g., for seawater with a density significantly different from that of pure water,[3] or at elevated temperatures, like those prevailing in thermal power plants.

We can also define pKw {\displaystyle \equiv } −log10 Kw (which is approximately 14 at 25 °C). This is analogous to the notations pH and pKa for an acid dissociation constant, where the symbol p denotes a cologarithm. The logarithmic form of the equilibrium constant equation is pKw = pH + pOH.

Question 2
4 pts
Inside a car that was at STP, a 0.95 L bottle warms up to 144 C. If the volume of the bottle
remains constant, what is the pressure, in atm, inside the hot water bottle?

Answers

Answer:

1.53 atm

Explanation:

From the question given above, the following data were obtained:

Volume = constant

Initial pressure (P₁) = stp = 1 atm

Initial temperature (T₁) = 273 K

Final temperature (T₂) = 144 °C = 144 °C + 273 = 417 K

Final pressure (P₂) =?

Since the volume is constant, the final pressure can be obtained as follow:

P₁ / T₁ = P₂ / T₂

1 / 273 = P₂ / 417

Cross multiply

273 × P₂ = 417

Divide both side by 273

P₂ = 417 / 273

P₂ = 1.53 atm

Therefore, the final pressure (i.e the pressure inside the hot water bottle) is 1.53 atm.

What is the [OH-] in a solution if the [H*] = 1.2 x 10-3 M?

Answers

We know that [OH⁻] * [H⁺] = 10⁻¹⁴

plugging the value of [H⁺]

[OH⁻] * 1.2 * 10⁻³ = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ * (10³/1.2)

[OH⁻] = 833.3 * 10⁻¹⁴

[OH⁻] = 8.33 * 10⁻¹²

Acids and bases are chemical molecules with very different characteristics.

a. True
b. Fasle

Answers

Answer:

TRUE ,hope it helped you

Explanation:

A sample of a gas has a volume of 852 mL at 298 K. If the gas is cooled to 200K, what would the new volume be?

Answers

Answer:

571.81 mL

Explanation:

Assuming constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:

V₁T₂=V₂T₁

Where in this case:

V₁ = 852 mLT₂ = 200 KV₂ = ?T₁ = 298 K

We input the data:

852 mL * 200 K = V₂ * 298 K

And solve for V₂:

V₂ = 571.81 mL

The new volume would be 571.81 mL.

What volume of chlorine gas at 27 °C, 812 mmHg, is required to react with an excess of carbon disulfide so that 5.00kJ of heat is evolved?

Answers

Answer:

The correct answer is 1.21 L.

Explanation:

Based on the given information, the reaction will be,

CS2 (l) + 3Cl2 (g) ⇒ CCl4 (l) + S2Cl2 (l)

By using the standard values of the substances, the standard enthalpy of the reaction is,

ΔH° = [(-139.5) + (-58.5) – 0 – (87.3)] kJ/mol

= -285.3 kJ/mol

The amount of heat evolved for 3 moles of chlorine reacted us 285.3 kJ.

Now the number of moles of chlorine needed to react to produce 5.00 kJ is,

= 5.00 kJ × 3 mol Cl2/285.3 kJ

= 0.0526 mol Cl2

Now the volume of chlorine gas at 27degree C and 812 mmHg will be,

Volume = 0.0526 mol Cl2 × 0.0821 Latm/mol K × 300 K/ 1.07 atm

= 1.21 L

Which of these half-reactions represents reduction?
I. Fe2+ → Fe3+
II. Cr2O72- → Cr3+
III. MnO4- → Mn2+

Answers

Answer: The half-reactions represents reduction are as follows.

[tex]Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}[/tex][tex]MnO^{-}_{4} \rightarrow Mn^{2+}[/tex]

Explanation:

A half-reaction where addition of electrons take place or a reaction where decrease in oxidation state of an element  takes place is called reduction-half reaction.

For example, the oxidation state of Cr in [tex]Cr_{2}O^{2-}_{7}[/tex] is +6 which is getting converted into +3, that is, decrease in oxidation state is taking place as follows.

[tex]Cr_{2}O^{2-}_{7} + 3 e^{-} \rightarrow Cr^{3+}[/tex]

Similarly, oxidation state of Mn in [tex]MnO^{-}_{4}[/tex] is +7 which is getting converted into +2, that is, decrease in oxidation state is taking place as follows.

[tex]MnO^{2-}_{4} + 5 e^{-} \rightarrow Mn^{2+}[/tex]

Thus, we can conclude that half-reactions represents reduction are as follows.

[tex]Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}[/tex][tex]MnO^{-}_{4} \rightarrow Mn^{2+}[/tex]

A mixture of 0.224 g of H2, 1.06 g of N2, and 0.834 g of Ar is stored in a closed container at STP. Find the volume (in L) of the container, assuming that the gases exhibit ideal behavior.

Answers

Answer: The volume of given container is 3.83 L.

Explanation:

Given: Mass of [tex]H_{2}[/tex] = 0.224 g

Mass of [tex]N_{2}[/tex] = 1.06 g

Mass of Ar = 0.834 g

Since, moles is the mass of a substance divided by its molar mass. Therefore, moles of given substances present in the mixture are as follows.

Moles of  [tex]H_{2}[/tex] are:

[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.224 g}{2 g/mol}\\= 0.112 mol[/tex]

Moles of [tex]N_{2}[/tex] are:

[tex]Moles = \frac{mass}{molar mass}\\= \frac{1.06 g}{28 g/mol}\\= 0.038 mol[/tex]

Moles of Ar are:

[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.834 g}{40 g/mol}\\= 0.021 mol[/tex]

Total moles = (0.112 + 0.038 + 0.021) mol = 0.171 mol

Now, using ideal gas equation the volume is calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

[tex]V = \frac{nRT}{P}\\= \frac{0.171 mol \times 0.0821 L atm/mol K \times 273 K}{1 atm}\\= 3.83 L[/tex]

Thus, we can conclude that the volume of given container is 3.83 L.

To which family of organic compounds does CH3COCH2CH2CH3 belong?

Answers

Answer:

I think:

CH3COCH2CH2CH3 belongs to ketone because it has a carbonyl group C=O in its structure.

Interpreting Velocity vs. Time Graphs
Velocity vs Time
Use the information presented in the graph to answer
the questions,
Which segments show acceleration?
Which segment indicates that the object is slowing
down?
What is the velocity of segment B?
What is the acceleration of segment B?|
50
B
40
30
Velocity (m/s)
20
А
10
0
8 9 10
1 2 3 4 5 6 7
Time (s)

Answers

Answer:first part is A and C, second part is C, third part is 40 m/s and the fourth part is zero

Explanation: I guessed and got them right lol

Measure the initial temperature of the water to the nearest 0.1°C. Record in the data table.
Initial Temp. of Metal
Initial Temp. of water
Initial Temp. of Both

Subtract to find the temperature changes for the water and the metal

Water
Metal ​

Answers

The heat capacity of the metal is calculated using the formula:

Heat capacity = quantity of heat/(mass * temperature difference)

What is temperature?

The temperature of a substance is the degree of hotness or coldness of that substance.

Temperature difference between substances enables heat flow.

Heat flows from hot to cold bodies.

In the given experiment, to determine the heat capacity of a metal, the temperature difference is obtained by substracting the initial and final temperatures.

The heat capacity of the metal is then calculated using the formula:

Heat capacity = quantity of heat/mass * temperature difference

Learn more about heat capacity at: https://brainly.com/question/21406849

#SPJ1

200 grams of iron (III) chloride reacts with ammonium carbonate [(NH4)2CO3] in the following equation.

FeCl3 + (NH4)2CO3 ---------> NH4Cl + Fe2(CO3)3



_ mole(s) of iron (III) carbonate [Fe2CO3)3] is/are produced in the balanced equation.


a
4
b
1
c
3
d
2

Answers

Answer:

0.616 moles of Fe₂(CO₃)₃ are produced when 200 g of FeCl₃ react

b. 1.

Explanation:

The balanced reaction is:

2FeCl₃ + 3(NH₄)₂CO₃ → 6NH₄Cl + Fe₂(CO₃)₃

First we convert 200 grams of FeCl₃ into moles, using its molar mass:

200 g ÷ 162.2 g/mol = 1.23 mol FeCl₃

Then we convert 1.23 moles of FeCl₃ into moles of Fe₂(CO₃)₃, using the stoichiometric coefficients of the balanced reaction:

1.23 mol FeCl₃ * [tex]\frac{1molFe_2(CO_3)_3}{2molFeCl_3}[/tex] = 0.616 mol Fe₂(CO₃)₃

The closest answer would be option b. 1.

Explanation:

[tex]FeCl₃ + (NH₄)₂CO₃ → NH₄Cl + Fe₂(CO₃)₃[/tex]

first balance the chemical equation

[tex]2FeCl₃ + 3(NH₄)₂CO₃ → 6NH₄Cl + Fe₂(CO₃)₃[/tex]

2 mole. 3 mole. 6mole. 1mole

2*162g of FeCl₃ produce 236 g of Fe₂(CO₃)₃

200g of of FeCl₃

produce 236/(2*162)*20=145.68 g of Fe₂(CO₃)₃

1 mole of Fe₂(CO₃)₃=236g

145.68g of Fe₂(CO₃)=1/236*145.68=}0.61mole

closest answer is b 1

b.1mole(s) of iron (III) carbonate [Fe2CO3)3] is/are produced in the balanced equation

Find the mass of 0oC ice that 10 gof 100oC steam will completely melt. Latent heat of fusion of ice is 80cal/g oCand heat of vaporization of water 540 cal/g oC ?

Answers

Answer:

The right approach is "80 g".

Explanation:

Given:

[tex]L_f=80 \ Cal/g[/tex]

[tex]L_v=540 \ Cal/g[/tex]

[tex]S=1 \ Cal/g[/tex]

Now,

The amount of heat cooling will be:

= [tex]mL_v+mS \Delta T[/tex]

= [tex](10\times 540)+10\times 1\times (100-0)[/tex]

= [tex]5400+1000[/tex]

= [tex]6400 \ Cal[/tex]

then,

⇒ [tex]m_{ice} L_f=6400[/tex]

[tex]m_{ice}\times 80=6400[/tex]

        [tex]m_{ice}=\frac{6400}{80}[/tex]

                [tex]=80 \ g[/tex]            

How many moles of Aluminum are in 54.0 grams of Aluminum (Al)

Answers

Answer:

2 moles!

Explanation:

Hi i hope this helped! I researched it and 2 moles was what came up first.

Predict the effect of an eightfold pressure increase on the equilibriunm composition of the reaction 3 Nalg) + H21g) =2 NaHlg)​

Answers

According to Le cha telier's principle when we increase the pressure of a equilibrium reaction the reaction shift to the side where few moles of gas present.

Your reaction (Notice - I guess the reaction you written is wrong, but still I'm solving with your given prediction)

3NaI (g) + H2 (g) = 2NaHI (g)

Where access of sodium iodide is reacting with Hydrogen gas to form NaHI molecule.

Number of moles of gas on reaction side - 3+2 = 5 moles

Number of moles of gas on product side - 2 moles

Conclusion- the reaction will shift to the right of the reaction

According to Le cha telier's principle when we increase the pressure of a equilibrium reaction the reaction shift to the side where few moles of gas present.

Your reaction (Notice - I guess the reaction you written is wrong, but still I'm solving with your given prediction)

3NaI (g) + H2 (g) = 2NaHI (g)

Where access of sodium iodide is reacting with Hydrogen gas to form NaHI molecule.

Number of moles of gas on reaction side - 3+2 = 5 moles

Number of moles of gas on product side - 2 moles

Conclusion- the reaction will shift to the right of the reaction

If carbon can count the shared hydrogen
atoms for itself, how many electrons are
now in carbon's outer orbital?

Answers

Answer:

Mars and Orbital code saber and the alien

An unknown compound (152 mg) was dissolved in water to make 75.0 mL of solution. The solution did not conduct electricity and had an osmotic pressure of 0.328 atm at 27°C. Elemental analysis revealed the substance to be 78.90% C, 10.59% H, and 10.51% O. Determine the molecular formula of this compound.

Answers

Answer:

The molecular formula of the compound is C10H16O.

Explanation:

Based on the given information, the mass of an unknown compound is 152 mg or 0.152 g, which was dissolved to produce 75 ml of solution.

The osmotic pressure of the solution is 0.328 atm at 27 degrees C or 300 K.

The formula of osmotic pressure is,

P = CRT

Now putting the values in the formula we get,

0.328 = C*0.0821*300

C = 0.013317

C = (mass/molecular mass) * (1000/volume of solution in ml)

0.013317 = (0.152/Molecular mass) * (1000/75)

Molecular mass = 152.186

C mass = 152.186 * 0.789 = 120.07 grams

C mole = 120.07/12 = 10

H mass = 152.186 * 0.1059 = 16.11 grams

H mole = 16.11/1 = 16

O mass = 152.186 - 120.07 - 16.116 = 16 grams

O mole = 16/16 = 1

Thus, the molecular formula of the compound will be,

C10H16O

Write a conclusion statement that addresses the following questions: • Explain what the color change indicated about the changes in the concentrations of Co(H2O)62+ and CoCl42– in each trial. • Do your data support or fail to support your hypothesis (include examples)? • How do you think the investigation can be explored further?

Answers

When the concentration of the HCl is varied, the color of the solution is changed as the equilibrium position moves to the left or right.

What is equilibrium?

The term equilibrium in a chemical reaction connotes that the forward and the revers reactions proceed at the same rate. Let us note that Co(H2O)6^2+ is pink in color while  CoCl4^2– is blue in color.

As such, when the concentration of the HCl is varied, the color of the solution is changed as the equilibrium position moves to the left or right.

Learn more anout equilibrium: https://brainly.com/question/365923

In a different titration, a 0.7529 g sample of a mixture of solid C6H5COOH and solid NaCl is dissolved in water and titrated with 0.150 M NaOH. The equivalence point is reached when 24.78 mL of the base solution is added. Calculate each of the following.

a. The mass, in grams, of benzoic acid in the solid sample
b. The mass percentage of benzoic acid in the solid sample

Answers

Answer:

a. 0.4539g benozic acid

b. 60.29% of benzoic acid in the solid sample

Explanation:

The benzoic acid reacts with NaOH as follows:

C6H5COOH + NaOH → C6H5COONa + H2O

Where 1 mole of the acid reacts per mole of NaOH

The NaCl doesn't react with NaOH

To solve this question we must find the moles of NaOH added = Moles of benzoic acid. With the moles of the acid and its molar mass (C6H5COOH = 122.12g/mol) we can find the mass of the acid and its mass percentage:

a. Moles NaOH = Moles Benzoic acid:

24.78mL = 0.02478L * (0.150mol / L) = 0.003717 moles Benozic acid

Mass benzoic acid:

0.003717 moles Benozic acid * (122.12g / mol) = 0.4539g benozic acid

b. Mass percentage is:

0.4539g / 0.7529g * 100 = 60.29% of benzoic acid in the solid sample

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