using the equation y=-6x+1: if you choose -2 as the input ,what will be the output

Answer:

2+10x-x^2, the last answer

Step-by-step explanation:

Answer:

A. 36.6

B. -94.18

C. -3.25

D. -75.01

E. -54.03

Answer:

a. 36.6

b. - 94.18

c. - 3.25

d. - 75.01

e. -54.03

Step-by-step explanation:

Hope this helps, have a great day

Answer:

According to the calculation, Wayra mage a mistahe in step 2 where she added 13 and 6 together instead of multiplying to get 78.

She also make a mistake in step 2 where he subtracted 5z from 4z to get z instead of -z

Step-by-step explanation:

Given the equation solved by Wayra expressed as;

Step 1: 13(z+6) = 4(z-3)-5z

She is find the value of z from the equation;

Step 2: Open the parenthesis using the distributive property;

13(z+6) = 4(z-3)-5z

13z + 13(6) = 4z - 4(3) - 5z

13z + 78 = 4z - 12 - 5z

Step 3: Simplify

13z + 78 = 4z - 5z - 12

13z + 78 = -z -12

Step 4: Collect the like terms;

13z + z = -12 - 78

Step 5: Simplify the result

14z = -90

Step 6: Divide both sides by 14

14z/14 = -90/14

z = 6.428

According to the calculation, Wayra mage a mistahe in step 2 where she added 13 and 6 together instead of multiplying to get 78.

She also make a mistake in step 2 where he subtracted 5z from 4z to get z instead of -z

Answer:

10 i believe

Step-by-step explanation:

Answer:

C.) 1 5/b boxes

Number of boxes left over

= 3 - 1/2 - 2/3

Convert each  fraction to one in terms of the LCM:

= 18/6 - 3/6 - 4/6

= 11/6

= 1 5/6 boxes.

The solution is Option B.

The number of boxes of crackers left with Eloise is 1 5/6 boxes of crackers

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the number of boxes of crackers left with Eloise be = A

Now , the total number of boxes of crackers be = 3 boxes

The number of boxes of crackers ate on Saturday = 1/2

The number of boxes of crackers ate on Sunday = 2/3

So , the equation will be

Number of boxes of crackers left with Eloise A =  total number of boxes of crackers - number of boxes of crackers ate on Saturday - number of boxes of crackers ate on Sunday

Substituting the values in the equation , we get

Number of boxes of crackers left with Eloise A = 3 - 1/2 - 1/3

On simplifying the equation , we get

Number of boxes of crackers left with Eloise A = 5/2 - 2/3

Number of boxes of crackers left with Eloise A = ( 15 - 4 ) / 6

Number of boxes of crackers left with Eloise A = 11/6

Number of boxes of crackers left with Eloise A = 1 5/6 boxes

Therefore , the value of A is 1 5/6 boxes

Hence , the number of boxes left is 1 5/6 boxes of crackers

To learn more about equations click :

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Answer:

D is the correct answer

Step-by-step explanation:

The coordinates of the x axis is always listed first.

On the x axis the line was less than one and more than zero leaving the fraction as the only option.

hope it helps

have a great day

:)

Answer:

The solutions are:

-28.25, -14.5, -2.25

Step-by-step explanation:

Given compound inequality is:

[tex]-17.5\leq \frac{2x+4}{3} <17.5[/tex]

The compound inequalities are broken down into two inequalities to find the solution

The two inequalities will be:

[tex]\frac{2x+4}{3} \geq -17.5[/tex]   AND   [tex]\frac{2x+4}{3}<{17.5}[/tex]

Solving both inequalities one by one

[tex]\frac{2x+4}{3} \geq -17.5\\2x+4 \geq -52.5\\2x \geq -52.5-4\\2x \geq -56.5\\\frac{2x}{2} \geq \frac{-56.5}{2}\\x \geq -28.25\\\frac{2x+4}{3} < 17.5\\2x+4 < 52.5\\2x < 52.5-4\\2x \geq 48.5\\\frac{2x}{2} \geq \frac{48.5}{2}\\x < 24.25[/tex]

The solution is:

-28.25 ≤ x < 24.25

We have to see which options lie in the solution range.

The solutions are:

-28.25, -14.5, -2.25

Answer:

[tex]C(w) = 5w + 12[/tex]

[tex]C(w) = 12+5w[/tex]

Step-by-step explanation:

Given information:

- Monthly fee of $12

- $5 fee per workout class

- [tex]w[/tex] represents the workout classes taken for a month

- - - -

With the given information, we can conclude that [tex]C(w)=[/tex] workout fee + monthly fee.

Workout fee = [tex]$5w[/tex]

Monthly fee = [tex]$12[/tex]

∴ [tex]C(w) = 5w + 12[/tex] or [tex]C(w) = 12+5w[/tex] (they are the same)

Hope this helps :)

Answer:

42.3

Step-by-step explanation:

3.6(3)+4.5(7)

10.8+31.5

42.3

Answer:

GH=45

HJ=81.6

GJ=53.4

Step-by-step explanation:

hope i helped <3

Answer:

PAIN

Step-by-step explanation:

Answer:

points waisted

Step-by-step explanation:

Answer:

Yeah its parallel

Step-by-step explanation:

I would waste your points, but nah. Anyways, its parallel

Answer: D.

Step-by-step explanation:

the ratio of 12/4 is the same as 3

Answer:

2.82842712 + 2 i

Step-by-step explanation:

Answer:

the first one and last one are true

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

5x4=20

20/2=10

17-10=7

Answer:

your answer is 7

Step-by-step explanation:

17-5×4÷2

P- parenthesis

E- Exponents

M- Multiplication

D- Divide

A- Add

S- Subtract

Answer:

They will both have paid the same amount after 4 months

Step-by-step explanation:

Assume that they will pay the same amount after x months

∵ Billy pays $30 for his new phone

∵ He only pays $12.50 each month

→ Find how much he will pay in x month

∴ He will pay → 30 + 12.50x

∵ Annie got her new phone for free

∵ She only pays $20 a month

→ Find how much she will pay in x month

∴ She will pay → 20x

∵ They will pay the same amount

→ Equate their expressions above

∴ 20x = 30 + 12.50x

→ Subtract 12.50x from both sides

∵ 20x - 12.50x = 30 + 12.50x - 12.50x

∴ 7.50x = 30

→ Divide both sides by 7.50

∴ x = 4

∴ They will both have paid the same amount after 4 months

Answer:

57°

Step-by-step explanation:

LHS angle=RHS angle=57° (vert. opp angles)

Answer:

23

Step-by-step explanation:

y=f(n)=( -4× -7)-5

f(n)=28-5 =23

9514 1404 393

Answer:

  44 inches

Step-by-step explanation:

The sides of a rhombus are all the same length, so we have ...

  AB = BC

  3x -4 = 2x +1

  x = 5 . . . . . . . . . add 4-2x

Then the side lengths are ...

  3x -4 = 3·5 -4 = 11

Four of them total 4·11 = 44 inches.

Answer:

40 square cm

Step-by-step explanation:

Answer:40 square cm

Step-by-step explanation:

Answer:

1 in on the map = [tex]\frac{16}{7}\ miles[/tex] on the street

Step-by-step explanation:

Represent the actual distance as y and the map distance as x

So:

x = 3.5in when y = 8 miles

Required

Determine the proportion

The proportion of map measurement to actual measurement is:

[tex]x : y[/tex]

This gives:

[tex]3.5\ in : 8\ miles[/tex]

Divide by 3.5

[tex]\frac{3.5\ in}{3.5} : \frac{8\ miles}{3.5}[/tex]

[tex]1\ in: \frac{8\ miles}{3.5}[/tex]

Simplify the fraction

[tex]1\ in: \frac{8 * 2\ miles}{3.5*2}[/tex]

[tex]1\ in: \frac{16\ miles}{7}[/tex]

[tex]1\ in: \frac{16}{7}\ miles[/tex]

This means that:

1 in on the map = [tex]\frac{16}{7}\ miles[/tex] on the street

Answer:4 1/2  Teaspoons  of vanilla will be left in the bottle

Step-by-step explanation:

Step 1

Recipe for 1 cheesecake = 1 1/2 teaspoons of vanilla

Since she s making 5 cheesecakes, she will requite = 5 x 1 1/2 teaspoons

= 5 x 3/2= 15/2 = 7 1/2 teaspoons of vanilla.

Step 2

If a bottle of vanilla contains = 12 teaspoons of vanilla

After baking 5 cheesecakes which consumed = 7 1/2 teaspoons of vanilla

Teaspoons left of vanilla = Total teaspoons of vanilla-teaspoons of vanilla used for 5 cheesecakes= 12 - 7 1/2 =4 1/2

Therefore 4 1/2  Teaspoons  of vanilla will be left in the bottle

Answer: 4

Step-by-step explanation: 4 was the biggest denominator in that equation. so if we multiply by 4 on all the terms, all the denominators will go away. we will not have any more fractions!

Answer:

c = 29km

Step-by-step explanation:

[tex]A^{2}[/tex] + [tex]B^{2}[/tex] = [tex]C^{2}[/tex]

[tex]20^{2}[/tex] + [tex]21^{2}[/tex] = 841

[tex]\sqrt{841}[/tex] = 29