Answer:
26500 W/m²
Explanation:
Given that:
The diameter of the dish d = 1.2 m
Assuming the Solar power P capture by the dish = 1300 W
The surface area of the pot is calculated by using the formula:
[tex]= \pi r^2[/tex]
[tex]\pi \dfrac{d^2}{4}[/tex]
where; the diameter = 25 cm
Area = [tex]\pi \dfrac{d^2}{4}[/tex]
Area = [tex]\pi \dfrac{0.25^2}{4}[/tex]
Area = 0.049 m²
The intensity is calculated by using the formula
I = power/area
I = 1300/0.049
I = 26530.6 W/m²
I ≅ 26500 W/m²
What is the weight of an object (on earth) that has a mass of 45 kg?
Answer:
441 N
Explanation:
weight = mass x gravity
w = m x g.
We know that gravity = 9.8 m/s^2 and mass = 45 kg.
w = 45 kg x 9.8 m/s^2
w = 441 N
So the weight of the object is 441 N (newtons).
Answer:441 N.
Explanation:
The weight of 45 kg at rest on the surface of the Earth is about 45 * 9.8 N = 441 N.
A 30kg uniform solid cylinder has a radius of 0.18m. if the cylinder accelerates at 0.023 rad/s^2 as it rotates about an axis through its center, how large is the torque acting on the cylinder? With work please
Answer:
0.011 N-m
Explanation:
Given that
The mass of a solid cylinder, m = 30 kg
The radius of the cylinder, r = 0.18 m
The acceleration of the cylinder, [tex]\alpha =0.023\ rad/s^2[/tex]
It rotates about an axis through its center. We need to find the torque acting on the cylinder. The formula for the torque is given by :
[tex]\tau=I\alpha[/tex]
Where
I is the moment of inertia of the cylinder,
For cylinder,
[tex]I=\dfrac{mr^2}{2}[/tex]
So,
[tex]\tau=\dfrac{mr^2\alpha }{2}\\\\\tau=\dfrac{30\times (0.18)^2\times 0.023 }{2}\\\\\tau=0.011\ N-m[/tex]
So, the required torque on the cylinder is 0.011 N-m.
a stone of mass 6 kg is released from a height of 30 metre calculate the potential energy
Answer:
P.E = 1764 Joules
Explanation:
Given the following data;
Mass = 6kg
Height = 30m
We know that acceleration due to gravity is equal to 9.8m/s²
To find the potential energy;
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
[tex] P.E = mgh[/tex]
Where,
P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Substituting into the equation, we have;
P.E = 6 * 9.8 * 30
P.E = 1764 Joules
When the starter motor on a car is engaged, there is a 320 A current in the wires between the battery and the motor. Suppose the wires are made of copper and have a total length of 1.5 m . For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. What minimum diameter can the wires have if the voltage drop along the wires is to be less than 0.50 V?
Answer:
0.5
Explanation:
because it is V uwbsusvegwjosnfvehdbuxbdusndgdghqbwbwbbeuehdbdhdhdhdudhdhdudhdnskowoqllqlqlqnebe
4) Snowman melting in the sun
Answer:
is there more information for the question
An object is experiencing an acceleration of 12 m/s2 while traveling in a circle of radius 5.0 m. What is its velocity?
Answer:
v = 7.74 m/s
Explanation:
Given that,
The acceleration of the object, a = 12 m/s²
The radius of the circle, r = 5 m
We need to find the velocity of the object. The centripetal acceleration act on the object that is given by :
[tex]a=\dfrac{v^2}{r}\\\\v=\sqrt{ar} \\\\v=\sqrt{12\times 5} \\\\v=7.74\ m/s[/tex]
So, the velocity of the car is 7.74 m/s.
A car company is doing crash tests and has installed forcesensors in the chairs and seatbelts to measure the forces thatare exerted on crash test dummies during a crash. In oneparticular test the sensors measure a horizontal net force onthe dummy of 39,400 N when the car comes to a complete stopfrom an initial speed of 35 m/s in 1.4 m. Treating the dummyas a point particle and assuming it comes to rest in the samedistance, what is the mass of the test dummy used during thistest
Answer:
[tex]m=90.1kg[/tex]
Explanation:
From the question we are told that
Force F=39400
Initial speed [tex]V_1=35m/s[/tex]
Distance[tex]d=1.4m[/tex]
Generally the equation for acceleration is mathematically given by
[tex]a=\frac{V^2-U^2}{2d}[/tex]
[tex]a=\frac{0^2-35^2}{21.4}[/tex]
[tex]a=\frac{0^2-35^2}{21.4}[/tex]
[tex]a=-437.5m/sec^2[/tex]
Generally the equation for mass is mathematically given by
[tex]F=ma\\m=F/a[/tex]
[tex]m=\frac{-39400}{-437.5}[/tex]
[tex]m=90.1kg[/tex]
why is the galaxy when me is the no galaxy so not galaxy but is galaxy so why is thee aliens is the yes but is the no but should not be the ok but when the yes 20 lashes
Answer:
they are in imaginary world in this every thing is possible
What is a force that causes an object to slow down when it touches another object
Inertia
Massive force
Frictional force
Balanced force
Frictional force is the force that causes an object to slow down when it touches another object. Thus, the correct option is C.
What is Frictional force?Frictional force of an object is the force which is generated by the two surfaces which generate due to their contact and slide against each other. A few factors which affect the frictional force are that these forces are mainly affected by the surface texture of the object and the amount of force impelling them together.
Frictional force is mainly of four types which include static friction, sliding friction, rolling friction, and the fluid friction. The frictional force can be given by the formula: F = μN, where μ is a constant.
Therefore, the correct option is C.
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A man standing on the Earth can exert the same force with his legs as when he is standing on the moon. We know that the mass of the man is the same on the Earth and the moon. We also know that F=ma is true on both the Earth and the moon. Will the man be able to jump higher on the moon than the Earth? Why or why not?
PLEASE HELPPPP
Answer:
yes
Explanation:
earth has gravity force that is high than the moon gravity force which is 1/6 of earth gravity
Earth has gravity force that is high than the moon gravity force which is 1/6 of earth gravity.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The force on the moon is less than earth as gravity is 1/6 on the moon
When man jump than he will jump high on the moon than the earth.
Earth has gravity force that is high than the moon gravity force which is 1/6 of earth gravity.
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a dump truck travels 70mph for 3 hours, then for 20mph for another 2 hours in the same direction. what is the average speed the car traveled?
Answer:
the average speed of the car is 170 mph.
Explanation:
Given;
initial speed, u = 70 mph
time of motion, t₁ = 3 hours
final speed, v = 20 mph
time of motion, t₂ = 2 hours
The average speed of the car is calculated as;
[tex]v' = \frac{70(3) - 20(2)}{3-2} \\\\v' = 170 \ mph[/tex]
Therefore, the average speed of the car is 170 mph.
Consider a 2 m wide and 5 m long slab resting on flat, fixed, earthen bed. The slab is 20 cm thick with uniform properties. You may assume the slab is much longer and wider than it is thick. Write the reduced form of the governing equation for the slab. Clearly identify your coordinate system on a sketch and state your assumptions identifying which terms you are eliminating and why.
Answer:
Explanation:
The coordinate sketch for the system is shown in the attached file below. Also, in the cartesian coordinate system, since the height is less than the length and width, we did neglect the height. Thus, we eliminate the height and converted it to a two-dimension.
1. Two boxes stacked on top of one another weigh 100 kg total. They apply
a friction force of 250N. You apply a force of 300N in the right direction.
What is the total net force and direction of the box?
Answer:
150
Explanation:
A pressure vessel that has a volume of 10m3 is used to store high-pressure air for operating a supersonic wind tunnel. If the air pressure and temperature inside the vessel are 20 atm and 300K, respectively: What is the mass of air stored in the vessel
Answer:
The mass of air stored in the vessel is 235.34 kilograms.
Explanation:
Let supossed that air inside pressure vessel is an ideal gas, The density of the air ([tex]\rho[/tex]), measured in kilograms per cubic meter, is defined by following equation:
[tex]\rho = \frac{P\cdot M}{R_{u}\cdot T}[/tex] (1)
Where:
[tex]P[/tex] - Pressure, measured in kilopascals.
[tex]M[/tex] - Molar mass, measured in kilomoles per kilogram.
[tex]R_{u}[/tex] - Ideal gas constant, measured in kilopascal-cubic meters per kilomole-Kelvin.
[tex]T[/tex] - Temperature, measured in Kelvin.
If we know that [tex]P = 2026.5\,kPa[/tex], [tex]M = 28.965\,\frac{kg}{kmol}[/tex], [tex]R_{u} = 8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K}[/tex] and [tex]T = 300\,K[/tex], then the density of air is:
[tex]\rho = \frac{(2026.5\,kPa)\cdot \left(28.965\,\frac{kg}{kmol} \right)}{\left(8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K} \right)\cdot (300\,K)}[/tex]
[tex]\rho = 23.534\,\frac{kg}{m^{3}}[/tex]
The mass of air stored in the vessel is derived from definition of density. That is:
[tex]m = \rho \cdot V[/tex] (2)
Where [tex]m[/tex] is the mass, measured in kilograms.
If we know that [tex]\rho = 23.534\,\frac{kg}{m^{3}}[/tex] and [tex]V = 10\,m^{3}[/tex], then the mass of air stored in the vessel is:
[tex]m = \left(23.534\,\frac{kg}{m^{3}} \right)\cdot (10\,m^{3})[/tex]
[tex]m = 235.34\,kg[/tex]
The mass of air stored in the vessel is 235.34 kilograms.
3. An ecosystem is different from all of
the other groups because it contains
things.
O only living
O only nonliving
O both living and nonliving
Answer:
I think it is O only nonliving
Someone please please please help me with this. I’ll give u whatever rating u want
The vertical forces add up to zero.
The net force on the object is 60N to the right.
F = m • a
60N right = (10kg) • (a)
a = (60N right) / (10kg)
a = 6 m/s^2 to the right
Multi-engine Commercial would be nice.
Follow these steps to solve this problem: Two identical loudspeakers, speaker 1 and speaker 2, are 2.0 mm apart and are emitting 1700-HzHz sound waves into a room where the speed of sound is 340 m/sm/s . Consider a point 4.0 mm in front of speaker 1, which lies along a line from speaker 1, that is perpendicular to a line between the two speakers. Is this a point of maximum constructive interference, a point of perfect destructive interference, or something in between
Answer:
The point is neither maximum constructive interference nor perfect destructive interference, the interference is something in between.
Explanation:
Given data in the question;
first we find the wavelength of the sound λ
Then we find the path-length difference to the point from the two speakers, and divide it by the wavelength.
wavelength λ = velocity / frequency = 340 m/s / 1700 Hz = 0.2 m
L1 = 4 m
L2 = √(4² +2² ) m
delta L = L2 - L1 = √(4² +2² ) m - 4 m = 0.472 m
x = deltaL / λ
If the result is nearly an integer, the waves reinforce at the point.
If it is nearly an integer + 0.5, the waves interfere destructively at the point.
If it is neither, the point is "something in between".
so we solve for x
x = 0.472 m / 0.2m
x = 2.36
since its not an integer, it is not point maximum constructive interference
delta L = ( 2x + 1 ).λ/2
x = ((2deltaL/λ) - 1)/2
x = (((2×0.472)/0.2) - 1)/2
x = 3.72 / 2
x = 1.86
Here also, it is not an integer, so it is not a point perfect destructive interference.
Therefore, The point is neither maximum constructive interference nor perfect destructive interference, the interference is something in between.
The speed limit on suburban roads is 50 km/h. You are traveling at the limit when an empty bag blows onto the road from behind a parked car 5.0m in front of you. If you maintain your speed how long will it be before you hit?
If a 6-kg bowling ball is rolled down the bowling lane with a force of 12 N, what is the acceleration of the ball?
Two loudspeakers face each other, vibrate in phase, and produce identical 406 Hz tones. A listener walks from one speaker toward the other at a constant speed and hears the loudness change (loud-soft-loud) at a frequency of 2.86 Hz. The speed of sound is 343 m/s. What is the walking speed
Answer:
1.21 m/s
Explanation:
Given :
2 loudspeakers
F2 - F1 = 2.86 Hz
Speed of sound, V = 343
Fo = frequency when listener is at rest = 406Hz
To obtain the walking speed Vo, speed as observer moves away from speaker ;
Vo = [(F2 - F1) * V] ÷ 2 * Fo
Vo = [2.86 * 343] ÷ (2 * 406)
Vo = 980.98 / 812
Vo = 1.2081034
Vo = 1.21 m/s
What type of wave has crests and troughs?
Answer:
tidal wave
Explanation:
A 0.160 pF parallel-plate capacitor is charged to a potential difference of 10.0 V and then disconnected from the battery. A cosmic ray burst creates 1.00 x 106 electrons and 1.00 x 106 positive charges between the plates. If the charges do not recombine, but reach the oppositely charged plates, by how much is the potential difference between the capacitor plates reduced
Answer:
1.0 volts
Explanation:
Given that:
The potential difference between the plate V = 10 V
C = 0.160 pF = 0.160 × 10⁻¹² F
The charge on the capacitor
Q = CV
Q = 0.160 × 10⁻¹² × 10
Q = 1.6 × 10⁻¹² C
It implies that the positive plate of capacitor has +1.6 × 10⁻¹² C charge while the negative plate has -1.6 × 10⁻¹² C
The number of excess electrons on the negative plate is:
[tex]n = \dfrac{q}{e}[/tex]
[tex]n = \dfrac{-1.6\times 10^{-12}}{-1.6\times 10^{-19}}[/tex]
[tex]n = 1.0 \times 10^7[/tex]
Thus, electron deficiency on the positive plate is [tex]1.0 \times 10^7[/tex]
The net negative charge that moves towards the positive plate is :
q = number of electrons moved × e
[tex]q = 1\times 10^6 \times (-1.6 \times 10^{-19})[/tex]
[tex]q = -1.6 \times 10^{-13} \ C[/tex]
Now, the net charge on the positive plate is:
[tex]q_{net} = q +q' \\ \\ q_{net} = (1.6 \times 10^{-12}) + (-1.6 \times 10^{-13})[/tex]
[tex]q_{net} =1.44 \times 10^{-12} \ C[/tex]
The potential difference between the plate;
[tex]V_{new} = \dfrac{q_{net} }{c}[/tex]
[tex]V_{new} = \dfrac{1.44 \times 10^{-12} }{0.16 \times 10^{-12}}[/tex]
[tex]V_{new} = 9.0 V[/tex]
The reduction in potential difference
[tex]\Delta V = V - V_{new}[/tex]
[tex]\Delta V = 10 - 9.0[/tex]
[tex]\mathbf{\Delta V = 1.0 \ volts}[/tex]
the angular speed of an automobile engine is increased at a constant rate from 1300rev/min to 2000rev/min in 3s (a) what is its angular acceleration in revolutions per minute squared
Answer:
please find attached pdf
Explanation:
If you double the compression of a spring it’s elastic potential energy will do what
Answer:
When you stretch or compress a spring you work against the restoring force of the spring. This work is stored as elastic potential energy in the spring. The more you stretch or compress the spring, the more work is done by you and more energy is stored.
This is also evident from the expression of the potential energy ( U ) -
U=(1/2)kx2
Where x is the displacement from the unstretched position of the spring. Greater is the x. more is the energy stored.
Batteries are usually identified by their voltage.
Which battery would be able to give 18 joules of energy to 12 coulombs of charge?
Question 7 options:
1.5 Volt battery
216 Volt battery
9 Volt battery
12 Volt battery
6 Volt battery
3 Volt battery
Answer:
Explanation:
Given parameters:
Electrical energy = 18J
Quantity of charge Q = 12C
Unknown:
Voltage = ?
Solution:
The expression of electrical potential energy is given as:
Electrical potential energy = [tex]\frac{1}{2}[/tex] c v²
c is the quantity of charge
v is the voltage
18 = [tex]\frac{1}{2}[/tex] x 12 x v²
18 = 6v²
v² = 3
v = 1.7v
Minimum interplanar spacing required for Bragg's diffraction is:
Answer:
Explanation:
\frac{\lambda }{2} is the minimum interplanar spacing which is required for Bragg's diffraction to occur.
Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
This question is incomplete, the complete question is;
A positive charge of magnitude Q1 = 6.5 nC is located at the origin.
A negative charge Q2 = -3.5 nC is located on the positive x-axis at x = 16.5 cm from the origin. The point P is located y = 10.5 cm above charge Q2.
Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
Answer:
the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C
Explanation:
Given the data in the question;
Q1 = 6.5 nC, Q2 = -3.5 nC
from the image below, to get our angle ∅
tan∅ = opp/adj
tan∅ = 10.5 / 16.5
tan∅ = 0.636363
∅ = tan⁻¹( 0.636363 )
∅ = 32.47°
also, r1 = √( 16.5² + 10.5²)
r1 = √( 272.25 + 110.25 )
r1 = √382.5
r1 = 19.55 cm = 0.1955 m
Now, the x-component of the electric field at point P due to charge Q1 will be;
Ex = E2cos32.47°
= (kQ1/r1²)cos32.47°
we know that; k is Coulomb's law constant ( 9 × 10⁹ N.m²/ C²
Q1 = 6.5 nC = 6.5 × 10⁻⁹ C
so we substitute
= ((9 × 10⁹ × 6.5 × 10⁻⁹) / (0.1955)²) cos32.47°
= (58.5 / 0.03822025) × 0.843672
= 1291.33 N/C
Therefore, the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C
Trevor is charting the motion of his pet tortoise across the floor. The diagram below shows its position every 60 seconds.
A.The tortoise is moving at a constant speed
B. The tortoise’s speed is decreasing through time
C. The tortoise’s speed is increasing through time
D. The tortoise’s position is not changing through time
Answer:
A.The tortoise is moving at a constant speed
Explanation:
The chart shows the tortoise covering a distance of 0.5 meters every 60.0 seconds. Since this rate of motion is not changing, the tortoise is moving at a constant speed.
The diagram shows the tortoise moving at a constant speed. Thus the correct option is option A.
What is speed?Speed is defined as how far the object travels. It is also defined as the rate of change of distance per unit of time. Speed is the scalar quantity and the unit of speed is m/s.
Speed is denoted by the letter v. v = s/t, where s is the distance traveled along the path and t is the time taken by the object to move along the path. The SI unit of distance is meter and the unit of time is seconds.
When the object covers an equal distance at equal intervals of time is called uniform speed. When the object covers unequal distance with equal intervals of time or equal distance with unequal intervals of time is called Non-uniform speed.
The graph shows the Tortoise covers 0.5 m in 60 seconds is called uniform speed. Thus, option A is correct.
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What is the kinetic energy of a 30 kg dog that is running at a speed of 8.6 m/s (about 19 mi/h)?
Answer:
Uhm thags hsed
Explanation:
Dkrr
Is altitude abiotic or biotic or neither SCIENCE WORK NEEDED BY 11:59 HELP HELP HLEP
Answer:
abiotic
Explanation:
goggle:)))))))