Using 2 shapes, how many 5-place patterns can be made

Answer: 0.375

Step-by-step explanation:

Given the following :

Both teams have an equal probability of winning = 0.5

Find the probability that both teams are tied after 4 games, that is 2-2 ( this means each team has exactly 2 successes and 2 losses).

This problem can be modeled using a binomial probability :

P(x) = nCx * p^x * (1-p)^(n-x)

x = number of successes = 2

P = probability of success = 0.5

(1-p) = probability of failure = 0.5

n = number of trials = 4

P(x = 2 ) = 4C2 * 0.5² * 0.5^(4-2)

P(x = 2) = 6 * 0.5² * 0.5²

P(x = 2) = 6 * 0.25 * 0.25

P(x = 2) = 0.375

Looks like the integral should be

[tex]\displaystyle\int\frac{x+2}{\sqrt{x+(2x+3)^2}}\,\mathrm dx[/tex]

Expand the denominator:

[tex]\displaystyle\int\frac{x+2}{\sqrt{4x^2+13x+9}}\,\mathrm dx[/tex]

Notice that

[tex]u=4x^2+13x+9\implies \mathrm du=(8x+13)\,\mathrm dx[/tex]

In order to use this substitution, expand the integral as

[tex]\displaystyle\frac18\int\frac{8x+13}{\sqrt{4x^2+13x+9}}\,\mathrm dx+\frac38\int\frac{\mathrm dx}{\sqrt{4x^2+13x+9}}[/tex]

In the first integral, use the previously mentioned substitution:

[tex]\displaystyle\frac18\int\frac{8x+13}{\sqrt{4x^2+13x+9}}\,\mathrm dx=\frac18\int\frac{\mathrm du}{\sqrt u}=\frac14\sqrt u[/tex]

[tex]=\dfrac14\sqrt{4x^2+13x+9}[/tex]

In the second integral, complete the square in the denominator:

[tex]4x^2+13x+9=4\left(x+\dfrac{13}8\right)^2-\dfrac{25}{16}[/tex]

Now substitute

[tex]x=\dfrac58\sec t-\dfrac{13}8\implies\mathrm dx=\dfrac58\sec t\tan t\,\mathrm dt[/tex]

so that

[tex]\sec t=\dfrac{8x+13}5[/tex]

Then

[tex]4x^2+13x+9=\dfrac{25}{16}(\sec^2t-1)=\dfrac{25}{16}\tan^2t[/tex]

and the integral becomes

[tex]\displaystyle\frac{\frac{15}{64}}{\frac54}\int\frac{\sec t\tan t}{\sqrt{\tan^2t}}\,\mathrm dt=\frac3{16}\int\sec t\,\mathrm dt[/tex]

[tex]=\dfrac3{16}\ln|\sec t+\tan t|[/tex]

[tex]=\dfrac3{16}\ln\left|\dfrac{8x+13}5+\dfrac{\sqrt{(8x+13)^2-25}}5\right|[/tex]

So, the integral is

[tex]\dfrac14\sqrt{4x^2+13x+9}+\dfrac3{16}\ln\left|\dfrac{8x+13}5+\dfrac{\sqrt{(8x+13)^2-25}}5\right|+C[/tex]

Answer:

c.  3 to 9

Step-by-step explanation:

It was right on edg 2020

37.8541

roll another one

Answer:

3:1

Step-by-step explanation:

If John makes 3, Then Kaleel makes 9,  If John makes 1, Then Kaleel makes 3.

Answer: The answer is 25%

Step-by-step explanation:

Answer:

  0.6066066606666066666...(increasing numbers of 6)

Step-by-step explanation:

One way to make a decimal non-repeating is to extend a pattern by one digit each time you write the pattern. That is the structure of the number Sophia and Nora are looking at. It is also the structure of the number in your question ...

  https://brainly.com/question/17546271

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Any irrational number will have a non-repeating decimal: √2, for example.

Answer:

106.08

Step-by-step explanation:

Answer:

106.08 percent

Answer:

7.28

Step-by-step explanation:

Answer: 7.28

Step-by-step explanation:

Answer:

The answer is the last one - t-40

Answer:

F(-6, 3) --> F'(-6,3)

G(-4,3) --> G'(-8,3)

H(-2,4) --> H'(-10,4)

Answer:

F(-6,3)

G(-8,3)

H(-10,4)

Step-by-step explanation:

If your reflecting over the red line then all I do is first try to recreate the shape on the other side of the red line. (Like a reflection) And then look at the points it landed on. And that's your answer

Answer:

Step-by-step explanation:

You observe that each term is 30 less than the previous one. This is the recursive rule. It also means the sequence is arithmetic with a common difference of -30.

Recursive equation

  f[1] = 60; f[n+1] = f[n] -30

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Explicit equation

The general form of the explicit equation is ...

  f(n) = f(1) +d(n -1)

Here, we have f(1) = 60 and d = -30, so your equation is ...

  f(n) = 60 -30(n -1)

Answer:

1/3 in decimal format is .333333333333... so none of these are correct

Answer:

See below

Step-by-step explanation:

Given:

Combination of domain for the function is the following union:

Group of answer choices:

The domain is the depth interval (−26, 1).

The domain is the depth interval (−9, 1].

The domain is the set of times −9 < x < −2, −2 < x < 1, and 1 < x < 7.

The domain is the time interval (−9, 7).

Answer:

2

Step-by-step explanation:

Answer:(-infinity,-29/6)

Step-by-step explanation:

Interval notation of this problem.

Answer:

#5 is b) -250, -200, 0, 300

Step-by-step explanation:

The answer is -9

-4 - 5 = -9

the answer is -4-(5)= -9

Answer:

= - 2.43%

Step-by-step explanation:

From the information given:

Since the variable (daily returns) is normally distributed, Then, using empirical rule at 95% confidence interval level, we have:

[tex]( \mu - 1.96 \sigma \ , \ \mu + 1.96 \sigma)[/tex]

where;

The expected mean daily return [tex]\mu = 0.05 \%[/tex]

The standard deviation [tex]\sigma = 1.5\%[/tex]

Given that the 95% confidence interval is expected to be a maximum loss, then the probability is left-tailed which is 1.65[tex]\sigma[/tex] away from the average.

Thus the distribution of the lower boundary can be computed as:

= [tex](0.05 - 1.65 \times 1.5)\%[/tex]

= [tex](0.05 - 2.475)\%[/tex]

= [tex]( - 2.425)\%[/tex]

= - 2.43%

Answer:

Step-by-step explanation:

[tex]\mathrm{Line\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Find\:the\:line\:}\\\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Compute\:the\:slope\:}\left(-1,\:-3\right),\:\left(2,\:1\right):\quad \\m=\frac{4}{3}\\\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-1,\:-3\right),\:\left(x_2,\:y_2\right)\\\left\\[/tex]

[tex]\\m=\frac{1-\left(-3\right)}{2-\left(-1\right)}\\\\Refine\\\\m=\frac{4}{3}\\\\\mathrm{Compute\:the\:}y\mathrm{\:intercept}:\quad b=-\frac{5}{3}\\\\y=\frac{4}{3}x-\frac{5}{3}\\[/tex]

Convert equation to standard form

[tex]y - \frac{4}{3} x + \frac{5}{3} = 0\\\\Multiply \:through\: by\: 3;\\\\3\times (y - \frac{4}{3} x + \frac{5}{3} )=0\\\\3y -4x+5 = 0\\Arrange\:n\:form\:of \:;\\Ax +By = C\\\\-4x +3y =-5[/tex]

Step-by-step explanation:

3. 7 = -2y + 4

2y = 4 - 7

2y = -3

y = -1.5

5. -3x - 2 = -17

17 - 2 = 3x

15 = 3x

3x = 15

x = 15/3

x = 5

Answer:

The answer is "Nominal"

Step-by-step explanation:

Some of the data is missing which is defined in the attached file. please find it.

The standard measuring degree is nominal for the favorite type of music because the type of music it can be listening for depends on a variety of factors, like age, social or local environment, etc, and the wrong choice can be defined as follows:

Answer:

x=-2

Step-by-step explanation:

3[x+4]+4x=-2

The 3 multiplies x and 4

3x+12+4x=-2

Group like terms

3x+4x=-2-12

7x=-14

Divide through by 7

7x/7=-14/7

x=-2

Answer:

Rational.

Step-by-step explanation:

Irrational are these.

[tex]\sqrt{2} , \sqrt{5}[/tex] ,π

Yes, the given number is a rational number.

Rational numbers are numbers that can be written in the form p/q, where p and q are integers and q≠0.

Given that, a number 2.4444...

Repeating decimals are considered rational numbers because they can be represented as a ratio of two integers.

Hence, 2.4444 is a rational number.

For more references on rational numbers, click;

https://brainly.com/question/24398433

#SPJ2

Answer:

2+x^2=18 = 2+4^2=18

Step-by-step explanation:

Because when you have the ( ^2) then that means your going to multiply a number by the same number and then 4 times 4 equals 16 and you still have the +2 therefore you add that on the 16 and 16+2 equals 18.

Now the aim of the above discussion is to internalize the mathematical relationships for open-end air columns in order to perform calculations predicting the length of air column required to produce a given natural frequency. And conversely, calculations can be performed to predict the natural frequencies produced by a known length of air column. Each of these calculations requires knowledge of the speed of a wave in air (which is approximately 340 m/s at room temperatures). The graphic below depicts the relationships between the key variables in such calculations. These relationships will be used to assist in the solution to problems involving standing waves in musical instruments.