Use the given scale factor and the side lengths of the scale drawing to determine the side lengths of the real object.​

Use The Given Scale Factor And The Side Lengths Of The Scale Drawing To Determine The Side Lengths Of

Answers

Answer 1

Answer:

B) 2 in x 5 in

Step-by-step explanation:

6 x 15   (divide each by 3)

2 x 5

Answer 2

Answer: its B

Step-by-step explanation:


Related Questions

jojo makes 100 working eight hours. Trish earned 25 working one hour. How much more money does Trish make than Jojo after 10 hours?

Answers

Answer:

Jojo makes 1000 and Trish makes 250

Step-by-step explanation:

I hope this helped

Answer:

Trish makes $125 more than Jojo after 10 hours

Step-by-step explanation:

$125 jojo

$250 Trish

A giant panda lives in the Washington, DC zoo. What does the point shown tell you about the panda?

Answers

Answer:

he is 36 months old or 3 years old, and he ways 82 kilograms.

Step-by-step explanation:

quick mafs

The point shown in the graph tell about the panda which lives in the Washington, DC zoo that the age of panda is 36 months and the weight of panda is 82 kilograms.

How to read the data from the graph?

In a graph, the line which is horizontal is known as the x-axis of the graph. The vertical line in the graph is called the y-axis of it. These axis helps to read the data from graph in following way-

The value of a point parallel to x axis in graph gives the value x-value. It is the value of parameter which is titled on x-axis.The value of a point parallel to y axis in graph gives the value y-value. It is the value of parameter which is titled on y-axis.

In the given graph, the x-axis is labeled with age in months and y-axis is labeled with weight of panda.

The point with coordinates (36,82) tells that the age of panda is 36 months and the weight of the panda is 82 kilograms.

Hence, the point shown in the graph tell about the panda which lives in the Washington, DC zoo that the age of panda is 36 months and the weight of panda is 82 kilograms.

Learn more about the graph here;

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pls help me math its due today​

Answers

Answer:

For multiplication you added the exponents and for division you minus the exponents

Answer:

kdkdjdduidddsisiodiod

hacmin birimi ...... ve ......dır​

Answers

Answer:

?

Step-by-step explanation:

don't get your question

What is the y-intercept of the equation of the line that is perpendicular to the line and passes through the point (15,-5)?

Answers

Answer:

hi

Step-by-step explanation:

First of all let’s find out the slope of the line y = x +10

As, we know the equation y= mx + c . So comparing the given equation with the general equation we get, m = 1

Now, we know that the product of two perpendicular lines is -1.

Thus, mn = -1 (considering slope of the second line as n)

Putting the value of m we get , n = -1

Now , y+5= -1( x -15) i.e y=-x + 10

if we compare again with the general equation then we find that.

The y intercept of the required equation is 10.

Thank You

Answer:

10

Step-by-step explanation:

First of all let’s find out the slope of the line y = x +10

As, we know the equation y= mx + c . So comparing the given equation with the general equation we get, m = 1

Now, we know that the product of two perpendicular lines is -1.

Thus, mn = -1 (considering slope of the second line as n)

Putting the value of m we get , n = -1

Now , y+5= -1( x -15) i.e y=-x + 10

if we compare again with the general equation then we find that.

The y intercept of the required equation is 10.

Thank You

n
2. (a) If ^nP2= 20, find the value of n.
2​

Answers

Answer:

[tex]n = 5[/tex]

Step-by-step explanation:

Given

[tex]^nP_2 = 20[/tex]

Required

Find n

To do this, we apply permutation formula.

[tex]^nP_r = \frac{n!}{(n-r)!}[/tex]

So, we have:

[tex]\frac{n!}{(n-2)!} = 20[/tex]

Expand the numerator

[tex]\frac{n(n-1)(n-2)!}{(n-2)!} = 20[/tex]

Divide by (n-2)!

[tex]n(n-1)= 20[/tex]

Expand

[tex]n^2 - n = 20[/tex]

[tex]n^2 - n - 20 = 0[/tex]

Expand

[tex]n^2 +4n -5n - 20 = 0[/tex]

Factorize

[tex]n(n+4)-5(n+4)= 0[/tex]

[tex](n-5)(n+4) = 0[/tex]

[tex]n - 5 = 0[/tex] or [tex]n + 4 = 0[/tex]

[tex]n = 5[/tex] or [tex]n = -4[/tex]

Since n cannot be negative, then:

[tex]n = 5[/tex]

Simplify the following monomials 1-12

Answers

Answer:

1. [tex]x^{8}[/tex]

2. [tex]k^{45[/tex]

3. [tex]m^{6}n^{21}[/tex]

4. [tex]64w^{18}[/tex]

5. [tex]81y^{12}[/tex]

6. [tex]16x^{4}[/tex]

7. [tex]-125y^{9}[/tex]

8. [tex]a^{36}b^{4}[/tex]

9. [tex]\frac{1}{128} x^{28}[/tex]

10. [tex]54a^{6}[/tex]

11. [tex]8k^{10}[/tex]

12. [tex]-\frac{16}{9} p^{24}[/tex]

Step-by-step explanation:

please help if you are good at math :( thank you

Answers

Answer:

your answer will be

A)(6,10)

B)(2,12)

C)(4,4)

Step-by-step explanation:

hope this helps

have a nice day/night ^_^

Find the range of the data in the box plot below.
cokies
Number of cookies eaten
by each contestant

Answers

Answer:

20 cookies

Step-by-step explanation:

Range of a data set plotted on a box plot = the maximum value - the minimum value

The maximum value is indicated by the whisker to your extreme right = 25

The minimum value is indicated by the whisker to your extreme left = 5

Range = 25 - 5 = 20

You've decided to give your best friend a
bag of marbles for his birthday.
Since you know that your friend likes
green marbles better than red ones, the
bag has twice as many green marbles as
red.
The label on the bag says it contains a
total of 84 marbles.
How many green marbles are in the bag?

Answers

56 green marbles!

Hope this helps!:)

Number of green marbles in the bag is equals to [tex]56.[/tex]

What is number?

" Number is defined as the count of any given quantity as per condition."

According to the question,

Given,

Total number of marbles [tex]= 84[/tex]

[tex]'x'[/tex] represents the number of red marbles

As per given condition,

[tex]'2x'[/tex] represents the number of green marbles

Required equation we have,

[tex]x + 2x = 84\\\\\implies 3x =84\\\\\implies x = \frac{84}{3} \\\\\implies x = 28[/tex]

Substitute the value of [tex]'x'[/tex] to get number of green marbles ,

Number of green marbles [tex]2x = 2\times 28[/tex]

                                                 [tex]= 56[/tex]

Hence, number of green marbles in the bag is equals to [tex]56.[/tex]

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HELP PLS ASAP!!!

these figures are congruent. What series of transformations moves quadrilateral FGHI onto quadrilateral F’G’H’I’?

Answers

Answer:

D

Step-by-step explanation:

It must first translate 1 unit to the left because quadrilateral F'G'H'I is one unit away from to y axis. It can then translate across the y-axis.

Answer:

ITS B!

Step-by-step explanation:

Ape x!

x
<
>
The probability of drawing a blue ball from Bag A is 1/5 and the
probability of drawing a red ball from Bag B is 2/3.
What is the probability of drawing a blue ball from Bag A AND a red
ball from Bag B?

Answers

Answer:

the probability of drawing a blue ball from bag A is 1/5 and the probability of drawing a red ball from bag B is 2/3.

The probability of drawing a blue ball from Bag A and a red ball from Bag B will be 2/15.

What is the definition of probability?

Probability denotes the likelihood of something happening. It is concerned with the occurrence of an unpredicted event.

Probability can only have a value between 0 and 1. Its simple notion is that something will most likely occur. The favorable event's proportion to the overall number of events is known as the favorable event ratio.

The probability of drawing a blue ball from Bag A is, 1/5

The probability of drawing a red ball from Bag B is, 2/3.

P(A)=1/5

P(B)=2/3

The probability of drawing a blue ball from Bag A and a red ball from Bag B will be;

P(A and B)=P(A). P(B)

P(A and B)=(1/5)×(2/3)

P(A and B)=(2/15)

Hence,the probability of drawing a blue ball from Bag A and a red ball from Bag B will be 2/15.

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ASAP!! Find the length of side x in simplest form with a rational denominator

Answers

Answer:

[tex]x=\sqrt{14}[/tex]

Step-by-step explanation:

This triangle is a 45-45-90 triangle.

By using the image I posted, we can find x easily.

So, we have [tex]\sqrt{7}[/tex] as one of the sides.

They hypotenuse, which is x is just [tex]\sqrt{7} \sqrt{2}[/tex]

Simplify and we get x = [tex]\sqrt{14}[/tex]

write the equation of the image y=x^2 after vertically stretched by a factor of 2 and horizontally shifted 3 units to the left​

Answers

Answer:

2=3^2?????

Step-by-step explanation:

y=x^2

(3,2)

substitute

2=3^2

Which of the following expressions is equivalent to: 4x-12 *
16x
O
-8x
4(x-3)
O
4 + X-12
O
4(x-12)

Answers

Answer:

4(x - 3)

Step-by-step explanation:

4x = 4 * x

12 = 4 * 3

GCF = 4

4x - 12 = 4*x - 4*3

           = 4(x - 3)

                                                                                    the second one.

............................

Does anyone have the link to this or have the pages please help

Answers

Answer:

I personally don't, but if you search up graph helper you could answer all of them. Hope you find the answer.

Step-by-step explanation:

Use the app Socratic, it’ll check the internet for similar/same sheets.

Select the correct answer.
The equation of a line is y = -3x – 2. What are the slope and the y-intercept of the line?
A.
slope = -3 and y-intercept = 2
B.
slope = 3 and y-intercept = -2
C.
slope = 3 and y-intercept = 2
D.
slope = -3 and y-intercept = -2

Answers

Answer:

The answer is D slope = -3 y-intercept = -2

Step-by-step explanation:

Answer

D.

Step-by-step explanation:

The first part of the equation is -3 and the second part is -2. The number attached to the variable is the "slope" and the number coming after the variable is the y intercept.

Help ASAP please!
The question is attached

Answers

Answer:Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?Nora is going to invest $9,600 and leave it in an account for 8 years.Assuming the interest is compounded continuously, what interest rate,to the nearest hundredth of a percent, would be required in order forNora to end up with $14,400?

Let X be a normal random variable with mean 3 and variance 4. (a) Find the probability P(2 < X < 6). (b) Find the value c such that P(X > c) = 0.33. (c) Find E[X2 ]. Hint: You can integrate with the density function, but it is quicker to relate E[X2 ] to the mean and variance.

Answers

Answer:

a) the probability of (2 < X < 6) is 0.6247

b) the value of c is 3.878

c) the value of E[ x² ] is 13

Step-by-step explanation:

Given that;

mean μ = 3

variance = 4

standard deviation s = √variance  = √4 = 2

(a) Find the probability P(2 < X < 6)

P(2 < X < 6) = p( (x - μ / s ) < z <  (x - μ / s ) )

= p( (2 - 3 / 2 ) < z < (6 - 3 / 2 ) )

= p( -0.5  < z <  1.5)

from z-score table, 1.5; z = 0.9332 and -0.5; z = 0.3085

so

P(2 < X < 6)  = 0.9332 - 0.3085 = 0.6247

Therefore, the probability of (2 < X < 6) is 0.6247

b) Find the value c such that P(X > c) = 0.33

with p-value = 0.33, the corresponding z -score to the right is 0.439

we know that;

z = x - μ / s

we substitute

0.439 = x - 3 / 2

x - 3 = 2 × 0.439

x - 3 = 0.878

x = 0.878 + 3

x = 3.878

Therefore, the value of c is 3.878

c) Find E[ x² ].

Variance = E[ x² ] - [ mean ]²

E[ x² ]  = Variance + [ mean ]²

we substitute

E[ x² ]  = 4 + [ 3 ]²

E[ x² ]  = 4 + 9

E[ x² ]  = 13

Therefore, the value of E[ x² ] is 13

The distribution follows a normal distribution.

[tex]\mathbf{P(2 < x < 6) =0.6247}[/tex]The value of c is 3.878The value of [tex]\mathbf{E(x^2) }[/tex] is 13

The given parameters are:

[tex]\mathbf{\mu = 3}[/tex] --- mean

[tex]\mathbf{\sigma^2= 4}[/tex] --- variance

(a) P(2 < x < 6)

Start by calculating the standard deviation

[tex]\mathbf{\sigma = \sqrt{\sigma^2}}[/tex]

This gives

[tex]\mathbf{\sigma = \sqrt{4}}[/tex]

[tex]\mathbf{\sigma =2}[/tex]

Calculate the z-scores for x = 2 and 6

[tex]\mathbf{z = \frac{x - \mu}{\sigma}}[/tex]

So, we have:

[tex]\mathbf{z = \frac{2 - 3}{2} = -0.5}[/tex]

[tex]\mathbf{z = \frac{6 - 3}{2} = 1.5}[/tex]

So, the probability becomes

[tex]\mathbf{P(2 < x < 6) = P(-0.5 < z < 1.5)}[/tex]

Using z table of probabilities, we have:

[tex]\mathbf{P(2 < x < 6) =0.9332 - 0.3085}[/tex]

[tex]\mathbf{P(2 < x < 6) =0.6247}[/tex]

(b) Calculate c if P(X > c) = 0.33

Start by calculating the z-score for p-value = 0.33

From the z table, z = 0.439 when p-value = 0.33

Recall that:

[tex]\mathbf{z = \frac{x - \mu}{\sigma}}[/tex]

So, we have:

[tex]\mathbf{0.439 = \frac{x - 3}{2}}[/tex]

Multiply both sides by 2

[tex]\mathbf{0.878= x - 3}[/tex]

Add 3 to both sides

[tex]\mathbf{3.878= x}[/tex]

Rewrite as:

[tex]\mathbf{x = 3.878}[/tex]

Replace x with c

[tex]\mathbf{c = 3.878}[/tex]

The value of c is 3.878

(c) Calculate E[x²]

The variance of a dataset is:

[tex]\mathbf{\sigma^2 =E(x^2) - \mu^2}[/tex]

Substitute known values

[tex]\mathbf{4 =E(x^2) - 3^2}[/tex]

[tex]\mathbf{4 =E(x^2) - 9}[/tex]

Add 9 to both sides

[tex]\mathbf{13 =E(x^2) }[/tex]

Rewrite as:

[tex]\mathbf{E(x^2) = 13 }[/tex]

Hence, the value of [tex]\mathbf{E(x^2) }[/tex] is 13

Read more about normal random variables at:

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Cab A charges $20 at the start and $5 every mile after . Cab B charges $30 no matter how far you go. What are their initial values and their rates of change? When will their fares be equal?

Answers

Answer:

Car A: Initial Charge = 20

Car B: Initial Charge = 30

Car A: Rate = 5

Car B: Rate = 0

At 2 miles, their charges will be the same

Step-by-step explanation:

Given

Car A

[tex]Base\ Charge = \$20[/tex]

[tex]Rate = \$5[/tex] per mile

Car B

[tex]Base\ Charge = \$30[/tex]

Solving (a): The initial charge

First, we get the  linear equation that represents both car's charges.

Represent number of miles with m.

So, the charges is:

Car A

[tex]A = Base\ Charge + Rate * m[/tex]

[tex]A = 20 + 5 * m[/tex]

[tex]A = 20 + 5m[/tex]

Set m to 0 to get the initial charge:

[tex]A = 20 + 5*0[/tex]

[tex]A=20[/tex]

and

[tex]Rate = 5[/tex]

Car B:

[tex]B = Base\ Charge + 0 * m[/tex] i.e. Rate is 0

[tex]B = 30+ 0 * m[/tex]

[tex]B = 30[/tex]

So:

[tex]Initial = 30[/tex] and [tex]Rate = 0[/tex]

Solving (b): When their charge wil be equal.

To do this, we set:

[tex]A = B[/tex]

[tex]20 + 5m = 30[/tex]

[tex]5m = 30- 20[/tex]

[tex]5m = 10[/tex]

[tex]m = 2[/tex]

At 2 miles, their charges will be equal

HOW DO YOU FIND PERCENT INCREASE

Answers

Answer:

Step-by-step explanation:

First: work out the difference (decrease) between the two numbers you are comparing.

Decrease = Original Number - New Number

Then: divide the decrease by the original number and multiply the answer by 100.

% Decrease = Decrease ÷ Original Number × 100

If your answer is a negative number, then this is a percentage increase

Estimate the product of 3.8 and 11.9 rounding.

Answers

Answer:

48

Step-by-step explanation:

round off 3.8 to 4 and 11.9 to 12 and multiply the values

What is the area of this circle? Use 3.14 for π


Question 7 options:

530.66 cm squared


81.64 cm squared


2122.64 cm squared


849.56 cm squared

Answers

Answer:

530.66 cm squared

Step-by-step Explanation:

Diameter of the circle = 26 cm

Radius of the circle (r) = 26/2 = 13 cm

[tex]A_{circle} = \pi {r}^{2} \\ \\ A_{circle} = 3.14 \times {(13)}^{2} \\ \\ A_{circle} = 3.14 \times 169 \\ \\ A_{circle} =530.66 \: {cm}^{2} [/tex]

Answer:

The area of 530.66 cm squared.

Option (a) 530.66 cm² is the correct answer.

Step-by-step explanation:

Given :

Diameter of circle = 26 cm.

To Find :

Radius of circle Area of circle

Using Formulas :

[tex]\star{\small{\underline{\boxed{\sf{\red{R = \dfrac{D}{2}}}}}}}[/tex]

R = Radius D = Diameter

[tex]\star{\small{\underline{\boxed{\sf{\red{Area_{(Circle)} = \pi{r}^{2}}}}}}}[/tex]

π = 3.14 r = radius

Solution :

Finding the radius of circle by substituting the values in the formula :

[tex]{\longrightarrow{\sf{Radius = \dfrac{D}{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = \dfrac{26}{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = \cancel{\dfrac{26}{2}}}}}[/tex]

[tex]{\longrightarrow{\sf{Radius = 13}}}[/tex]

[tex]\star{\underline{\boxed{\sf{\red{Radius = 13 \: cm}}}}}[/tex]

Hence, the radius of circle is 13 cm.

[tex]\rule{200}2[/tex]

Now, finding the area of circle by substituting the values in the formula :

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \pi{r}^{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = 3.14 \times {(13)}^{2}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314}{100} \times {(13 \times 13)}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314}{100} \times 169}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{314 \times 169}{100}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = \dfrac{53066}{100}}}}[/tex]

[tex]{\longrightarrow{\sf{Area_{(Circle)} = 530.66}}}[/tex]

[tex]\star{\small{\underline{\boxed{\sf{\red{Area_{(Circle)} = 530.66 \: {cm}^{2}}}}}}}[/tex]

Hence, the area of circle is 530.66 cm².

[tex]\rule{300}{1.5}[/tex]

Find the solutions to x2 = 18.
O A.
- +32
B. X = +63
O c. X = +376
O D. X = +2/3

Answers

Answer:

what in the math equations is this???

Step-by-step explanation:

4/5 - 2/3 =
Find equivalent fractions and rewrite the problem and solve

Answers

Answer:

1001/1500

Step-by-step explanation:

The easiest method for doing this is to just average the two numbers.

e.g. to find a number x between the two numbers ab and cd

x=12[ab+cd]

=12[adbd+bcbd]

=ad+bc2bd

In this case…

x=(2×5)+(3×4)2×2×5=10+1230=2230=1115

You can easily see where that came from.

23=1015 and 45=1215

and the ‘common denominator’ means you just have to pick a value between 10 and 12 . i.e. 11

But you can also say…

23=100150 and 45=120150

and choose any of 101150,102150,...,119150

or

23=10001500 and 45=12001500

and choose any of 10011500,10021500,...,11991500

Answer:4/5 and 2/3 each have a common bottom of 15 so 4/5 is

12/15 and 2/3 will be 10/15

Step-by-step explanation:So than 12/15 forget the bottom don't subtract the bottom just look at it like [12-10] then you got 2 then you go back to the bottom and put it together so your answer is [2/15]

3/4(1/6x+16)=3/7(4 3/8x-21) I WILL AWORD BRILLENEST :>

Answers

Answer:

x=12

Step-by-step explanation:

Let's solve your equation step-by-step.

34(16x+16)=37((438)(x)−21)

Step 1: Simplify both sides of the equation.

18x+12=158x−9

Step 2: Subtract 15/8x from both sides.

18x+12−158x=158x−9−158x

−74x+12=−9

Step 3: Subtract 12 from both sides.

−74x+12−12=−9−12

−74x=−21

Step 4: Multiply both sides by 4/(-7).

(4−7)*(−74x)=(4−7)*(−21)

x=12

Answer:

x=12

Answer:

x = 12

Step-by-step explanation:

34(16x + 16) = 37((438)(x) − 21)

18x + 12 = 158x − 9

18x + 12 − 158x = 158x − 9 − 158x

−74x + 12 = −9

−74x + 12 −12 = −9 −12

−74x = −21

(4−7) × (−74x) = (4−7) × (−21)

x = 12

Last week, the Bay City Bus Company tracked how long their school buses took to complete their routes. This box plot shows the results. Length of route (min.) 24 26 28 30 32 34 What percent of the buses completed their routes in 27 to 30 minutes?

Answers

Answer:

See Explanation

Step-by-step explanation:

Given

[tex]Plot: \{24, 26, 28, 30, 32, 34\}[/tex]

Required

Determine the percentage of those who uses the bus for 27 to 30 mins

The box plot is not given. So, I will make assumptions in order to solve this question.

Assume the following readings from the box plot:

[tex]Total\ Buses= 60[/tex]

[tex]27-30\ Minutes = 20\ buses[/tex]

Using these assumptions, the required percentage is:

Total = 6

27 to 30 minutes = 2

[tex]Percent = \frac{27\ to\ 30\ mins}{Total} * 100\%[/tex]

[tex]Percent = \frac{20}{60} * 100\%[/tex]

[tex]Percent = \frac{2000}{60} * \%[/tex]

[tex]Percent = 33.33 * \%[/tex]

Answer:

50%

Step-by-step explanation:

I took the test!

Which polynomial represents the sum below? (-x^3 + 3x^2 + 3) + (3x^2 + x + 4)

Answers

Answer:

Cddd

Step-by-step explanation:

detrmine if 7, 5, 84, 48 are in proportion or not​

Answers

Answer:

No, the numbers are not in proportion

Step-by-step explanation:

The proportion between the first two and the second two numbers are:

7/5 and 84/48

Simplifying the second fraction:

84/48 = 7*12/4*12 = 7/4

Comparing the fractions:

7/5 ≠ 7/4

The answer is no

MY
2B =
Cou
Round your answer to the nearest hundredth.
SA
A
MY
Pro
9
Pro
Tea
B
5

Answers

Answer:

<B = 56.25°

Step-by-step explanation:

Reference angle = B

Hypotenuse = AB = 9

Adjacent = BC = 5

Applying trigonometric ratio:

[tex] cos (B) = \frac{adj}{hyp} [/tex]

[tex] cos (B) = \frac{5}{9} [/tex]

[tex] B = cos^{-1}(\frac{5}{9}) [/tex]

B = 56.25° (nearest hundredth)

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