Answer:
A) 10 moles of CO and 5 moles O2
3.Which of these is NOT part of the cell theory? * "
all living things are made of cells
Ocells come only from other cells
cells are the smallest living unit of an organism
O all living things have blood cells
Answer:
Cells are the smallest living unit of an organism
Answer:
all living things living things have blood cells
Explanation:
this is because robert hooke did not make this apart of the theory
A rock-climbing group reached the top of Mount Everest in the Himalayan mountains. Mount Everest is about 29,000 feet above sea level and formed by the interaction of two tectonic plates. The group leader was surprised to find fossilized marine organisms on top of the mountain. Which of the following describes the geologic history of Mount Everest?
Answer:
Two tectonic plates had the same density and a collision of the plates pushed the advancing plate that contained fossilized marine organisms upward forming the Himalayan mountains and Mount Everest.
Explanation:
:)
Which of these statements is false?
A. All matter is made up of atoms.
B. Atoms are made up of protons,
neutrons, and electrons.
C. Atoms contain chemical bonds.
D. Atoms are the smallest particles of
elements.
Answer:
C is the false one atoms contain chemical bonds
Answer:
C. Atoms contain chemical bonds.
Reason:
Atoms don't have any chemical bonds. Molecules are the particles have chemical bonds.
(b) Why must acidic gases be treated before they are released into the atmosphere?
Answer:
because they react with other gases of atmosphere and pollute the environment
According to this video, how do scientists use data to study/monitor earthquakes and tsunamis?
Answer:
ewan ko po
Explanation:
sana makatulong
The process utilized to save an organism's DNA for use in the future is:
A tissue biopsy
B DNA
C clone
D genetic preservation
Answer:
I believe it's D!
Explanation:
B is what is being saved, C is a potential creation of, A is a method.
write a chemical equation that represents baking soda (NaHCO3) reacts with hydrochloric acid (HCI) to produce sodium chloride, water and carbon dioxide
Answer:
NaHCO3 + HCl = NaCl + H2O + CO2
Explanation:
The total number of atoms of each element on either side of the equation must be equal.
2. What is the percent composition of Mg(IO3)2?
Answer:
Mass percentage 6.4967
Explanation:
I had some study notes
PLEASE HELP!! DIMENSIONAL ANALYSIS USING METRIC CONVERSIONS!!!
I am so confused and am so lost despite all the videos i’ve tried watching, please help!!
Answer: Simpe its 1
Explanation:I took that quiz before hope this helps :)
Which of the following particles has the smallest
mass?
A) electron
C) neutron
B) hydrogen atom
D) proton
Answer:
AN ELECTRON HAS THE SMALLEST MASS!
Answer:
A) electron
good luck, i hope this helps :)
How many moles are in 1.51x10^26 atoms of xenon (Xe)? Please and thank you :)!!
251 mol Xe
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 1.51 × 10²⁶ atoms Xe
[Solve] moles Xe
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
[DA] Set up: [tex]\displaystyle 1.51 \cdot 10^{26} \ atoms \ Xe(\frac{1 \ mol \ Xe}{6.022 \cdot 10^{23} \ atoms \ Xe})[/tex][DA] Multiply/Divide [Cancel out units]: [tex]\displaystyle 250.747 \ mol \ Xe[/tex]Step 4: Check
Follow sig fig rule and round. We are given 3 sig figs.
250.747 mol Xe ≈ 251 mol Xe
3. What molecule or ion acts as the nucleophile in the base-catalyzed reaction between acetic anhydride and vanillin? A. Vanillin as a neutral phenol B. Vanillin as a phenoxide ion (conjugate base) C. Acetic anhydride D. Sodium hydroxide 4. According to the class notes, the first step in the acid-catalyzed reaction between acetic anhydride and vanillin is: A. Loss of a proton from the alcohol group in vanillin B. Protonation of acetic anhydride C. Protonation of the alcohol group in vanillin D. Departure of water as a leaving group in vanillin FOR QUESTIONS 5 AND 6 USE THE FOLLOWING INFORMATION: • Vanillin (solid) MW = 152.15 g/mol • Acetic anhydride (liquid) MW = 102.04 g/mol • Acetic anhydride density = 1.082 g/mL 5. How many mmoles of vanillin and how many mmoles of acetic anhydride are being reacted in the BASE CATALYZED reaction as described in the textbook? A. 1.97 mmol of vanillin and 8.45 mmol acetic anhydride B. 45.6 mmol of vanillin and 82 mmol acetic anhydride C. 8.45 mmol of vanillin and 2 mmol acetic anhydride D. 2 mmol of vanillin and 2 mmol acetic anhydride 6. How many mmoles of vanillin and how many mmoles of acetic anhydride are being reacted in the ACID CATALYZED reaction as described in the textbook? A. 23 mmol of vanillin and 102 mmol acetic anhydride B. 11 mmol of vanillin and 1 mmol acetic anhydride C. 1 mmol of vanillin and 10.6 mmol acetic anhydride D. 1 mmol of vanillin and 9 mmol acetic anhydride
Answer:
B
B
A
C
Explanation:
3
B. Vanillin as a phenoxide ion (conjugate base)
4
B. Protonation of acetic anhydride
5
A. 1.97 mmol of vanillin and 8.45 mmol acetic anhydride
6
C. 1 mmol of vanillin and 10.6 mmol acetic anhydride
Help me plsss
What is the mass in grams of H₂ that can be formed from 47.2 grams of NH₃ in the following reaction?
2 NH₃(g) → 3 H₂(g) + N₂(g)
Answer:
8.34
Explanation:
1) how much moles of NH₃ are in the reaction;
2) how much moles of H₂ are in the reaction;
3) the required mass of the H₂.
all the details are in the attachment; the answer is marked with red colour.
Note1: M(NH₃) - molar mass of the NH₃, constant; M(H₂) - the molar mass of the H₂, constant; ν(NH₃) - quantity of NH₃; ν(H₂) - quantity of H₂.
Note2: the suggested solution is not the shortest one.
Your uncle complained about feeling weak and dizzy and having experienced
palpitations. The doctor’s diagnosis is that he has hyperthyroidism, which may lead to
goiter. Which of the following ions is related to this disorder?
A. Calcium ion
B. Potassium ion
C. Iodine ion
D. Sodium ion
Answer:
C.Iodine ion
Explanation:
BECAUSE HIS LACK OF IODINE THAT'S WHY HE HAS GOITER
help asap pls,
find the percent composition
Explanation:
1. Pb(CO3)2
Element Number Mass Percet Composition
Oxygen 6 16.00 29.34%
Carbon 2 12.01 7.34%
Lead 1 207.21 63.32%
2. Ga(OH)3
Element Number Mass Percet Composition
Hydrogen 3 1.0079 2.50%
Oxygen. 3 16.00 39.75%
Gallium 1 69.72 57.74%
3. P4O10
Element Number Mass Percet Composition
Oxygen. 10 16.00. 56.36%
Phosphorus. 4 30.97 43.64%
4. Ca3P2
Element Number Mass Percet Composition
Phosphorus 2 30.97 34.00%
Calcium. 3 40.08 66.00%
5. Ti(NO3)3
Element Number Mass Percet Composition
Oxygen. 9 16.00 61.56%
Titanium. 1 47.87 20.47%
Nitrogen. 3 14.01 17.97%
A certain substance has a heat of vaporization of 64.08 kJ/mol. At what Kelvin temperature will the vapor pressure be 6.50 times higher than it was at 355 K?
Answer:
[tex]T_2 =388.50K[/tex]
Explanation:
Given
[tex]p_1 = ??[/tex] -- Initial vapour pressure
[tex]p_2 = 6.50p_1[/tex] --- Final vapour pressure
[tex]T_1 = 355K[/tex] ---- Initial temperature
[tex]T_2 = ??[/tex] --- Final temperature
[tex]\triangle _{vap}H = 64.08kJmol[/tex] --- Enthalpy of vaporization
Required
Calculate T2
To do this, we make use of Clausius-Clapeyron equation.
Which states that:
[tex]ln(\frac{p_2}{p_1}) = \frac{\triangle _{vap}H}{R}(\frac{1}{T_1} - \frac{1}{T_2})[/tex]
Where:
[tex]R = 8.314 J.K^{-1}mol^{-1}[/tex] --- Universal Gas constant
[tex]\triangle _{vap}H = 64.08kJmol[/tex]
[tex]\triangle _{vap}H = 64080\ kJmol[/tex]
[tex]ln(\frac{p_2}{p_1}) = \frac{\triangle _{vap}H}{R}(\frac{1}{T_1} - \frac{1}{T_2})[/tex] becomes
[tex]ln(\frac{6.50p_1}{p_1}) = \frac{64080}{8.314}(\frac{1}{355} - \frac{1}{T_2})[/tex]
[tex]ln(\frac{6.50p_1}{p_1}) = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]
[tex]ln(6.50) = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]
[tex]1.872 = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]
Take LCM
[tex]1.872 = 7707.48(\frac{T_2 - 355}{355T_2})[/tex]
[tex]1.872 = 7707.48*\frac{T_2 - 355}{355T_2}[/tex]
[tex]1.872 = \frac{7707.48*(T_2 - 355)}{355T_2}[/tex]
Cross Multiply
[tex]355T_2*1.872 = 7707.48*(T_2 - 355)[/tex]
[tex]664.56T_2 = 7707.48T_2 - 2736155.4[/tex]
Collect Like Terms
[tex]664.56T_2 - 7707.48T_2 =- 2736155.4[/tex]
[tex]-7042.92T_2 =- 2736155.4[/tex]
Make T2 the subject
[tex]T_2 =\frac{- 2736155.4}{-7042.92}[/tex]
[tex]T_2 =388.497299416[/tex]
[tex]T_2 =388.50K[/tex]
The final temperature is 388.50K
The temperature at which the vapor pressure will be 6.50 times higher than it was at 355K is 389 K
The Clausius-Clapeyron Equation is widely used for the determination of the vapor pressure of another temperature, provided we know the vapor pressure at a certain temperature as well as the heat of vaporization.
Given that:
the heat of vaporization [tex]\mathbf{\Delta H_{vap} = 64.08 \ kJ/mol = 64.08 \times 10^3 J/mol}[/tex] the initial temperature T₁ = 355 Kthe final temperature T₂ = ???if the pressure at T₁ = P₁then, the pressure at T₂ = 6.5P₁the universal gas constant = 8.314 J/K/molBy using the Clausius-Clayperon Equation:
[tex]\mathbf{In \Big( \dfrac{P_2}{P_1} \Big) = \dfrac{\Delta H_{vap}}{R} \Big (\dfrac{1}{T_1} - \dfrac{1}{T_2} \Big) }[/tex]
[tex]\mathbf{In \Big( \dfrac{6.5P_1}{P_1} \Big) = \dfrac{64.08 \times 10^3 }{8.314} \Big (\dfrac{1}{355} - \dfrac{1}{T_2} \Big) }[/tex]
[tex]\mathbf{In(6.5)=7707.48 \Big (\dfrac{1}{355} - \dfrac{1}{T_2} \Big) }[/tex]
[tex]\mathbf{1.872 =21.71 - \dfrac{7707.48}{T_2} }[/tex]
[tex]\mathbf{\dfrac{7707.48}{T_2} = 21.71- 1.872 }[/tex]
[tex]\mathbf{\dfrac{7707.48}{T_2} = 19.838 }[/tex]
[tex]\mathbf{T_2= \dfrac{7707.48}{19.838} }[/tex]
[tex]\mathbf{{T_2}=388.521 \ K }[/tex]
T₂ ≅ 389 K
Learn more about Clausius-Clayperon equation here:
https://brainly.com/question/1077674?referrer=searchResults
An airplane has a mass of 12,000kg. If it is accelerating at 16m/sec2, what is its force?(round to the nearest whole number) NEED THIS ASAP
Answer:
[tex]F=1.92x10^5N[/tex]
Explanation:
Hello!
In this case, since the force exerted by an object with a certain mass an acceleration is:
[tex]F=m*a[/tex]
We can plug in the given mass of 12,000 kg and acceleration of 16 m/s^2 to obtain:
[tex]F=12,000kg*16m/s^2\\\\F=192,000kg*m/s^2\\\\F=1.92x10^5N[/tex]
Best regards!
1. Mixing Water at Two Temperatures
a. One flask contains 150.0 g water at 20.0 °C. A second flask contains 350.0 g water at 95.0 °C. If the two water samples are mixed, what will the final temperature of the water be?
-Assume that the density of water it 1.000 g/cm^3
-The specific heat capacity for water is 4.184 J/g °C
Answer:
[tex]T_f=72.5\°C[/tex]
Explanation:
Hello!
In this case, since this a problem in which the cold water is heated by the hot water, we can write:
[tex]Q_{hot}+Q_{cold}=0[/tex]
Thus, by plugging in the mass, specific heat and temperatures, we obtain:
[tex]m_{hot}C_{hot}(T_f-T_{hot})+m_{cold}C_{cold}(T_f-T_{cold})=0[/tex]
Now, we can also write:
[tex]m_{hot}(T_f-T_{hot})+m_{cold}(T_f-T_{cold})=0[/tex]
Then, after applying some algebra, it is possible to obtain:
[tex]T_f=\frac{m_{hot}T_{hot}+m_{cold}T_{cold}}{m_{hot}+m_{cold}}[/tex]
If we plug in, we obtain:
[tex]T_f=\frac{350.0g*95.0\°C+150.0g*20.0\°C}{350.0g+150.0g}[/tex]
[tex]T_f=72.5\°C[/tex]
Best regards!
What is a word that means carbon and water
Answer:
When Carbohydrates are burned (decomposed ) they break down into carbon and water.
Explanation:
The formula for glucose sugar is C6H12O6 If the compound is broken down it results in
6C+6H2O six carbon atoms and six water molecules.
An experiment that illustrates this well is to pour concentrated sulfuric acid about 1/3 deep into the volume of graduated sucrose sugar in a beaker about 1/4 full
The sulfuric acid is hydrophilic it will break the sucrose sugar molecule apart. The water will rise as steam above the beaker.
The sugar will turn brown and the a black carbon cone will rise out of the sugar sulfuric acid solution. The carbon cone will rise about the top of the beaker.
This experiment shows that the carbohydrate sugar is made of only Carbon and Water.
How much would the temperature of a 34.2 g sample of argon gas decrease when 2.8 kJ of heat is removed?
Your answer should be in °C.
Answer:
8.90
Explanation:
because I calculated it
why is seawater a better conductor of electricity than freshwater?
Answer:
please refer to the attachment above;)
Answer:
Because it contains Na+ and Cl- ions, Which are conductors of electricity
Explanation:
if you were one of the immigrants, would you willingly submit to have yourself undergone x-ray to prove yourself being a minor? why or why not?
Answer:
I'm pretty sure this is a question about your opinion so there is no wrong answer! Just think about the question and if you were in those shoes. There is no right or wrong answer! :)
Explanation:
Please help :) hope you have a good day
Have a wonderful day :) thanks for the points
A weather balloon contains 394 L of hydrogen gas at STP. How many moles of hydrogen are present?
Answer:
PV=nRT
STP is 100kPa and 273.15K
PV/RT=n
n=17.3moles
Explanation:
b. If you have 50 grams of Molybdenum-99, how many grams will remain
after 11 days?
Answer:
6.25gm
half life is 66hrs 11 days is 24*11 then take that and divide by 66 to find out how many time it will have halved and half 50 by that many times
Explanation:
If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.
Molybdenum-99 follows first-order decay.
What is first-order decay?First-order decay means that for a population of atoms (e.g. radioactive), molecules, or anything else, a constant fraction/unit time is converted to something else.
The half-life (th) of Mo-99 is 66 h.
We will find its rate constant (k) using the following expression.
k = ln2 / th = ln2 / 66 h = 0.011 h⁻¹
Next, we will convert 11 days to hours, knowing that 1 day = 24 h.
11 d × 24 h/1 d = 264 h
If we start with 50 g of Mo-99, we can calculate the remaining mass after 264 h using the following expression.
[tex][Mo] = [Mo]_0 \times e ^{-k \times t} }\\\\[Mo] = 50g \times e ^{-0.011 h^{-1} \times 264 h} } = 2.7 g[/tex]
where,
[Mo] is the final amount of Mo-99.[Mo]₀ is the initial amount of Mo-99.t is the elapsed time.If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.
Learn more about first-order decay here: https://brainly.com/question/14478152
Hello, this is a science task and it is due today I would really appreciate it if you guys can help me answer and explain what is the difference between expansion and contraction:) I will mark brainliest!
Answer:
Expansion: increase in size Contraction: decrease in size
Explanation:
The increase in size of an object on heating is called expansion where as the decrease in size of an object on cooling is called contraction.
Determine the molecular formula for a compound that has a molecular mass of 52.0 g/mole
and and is composed of 92.31% carbon and 7.69% hydrogen.
Answer:
C4H4
Explanation:
92.31% of 52.0 g/mol is 48.0012 g/mol
7.69% of 52.0 g/mol is is 3.9988 g/mol
Carbon has a gram-formula mass of about 12, which goes into 48.0012 about 4 times, so there should be 4 atoms of Carbon
Hydrogen has a gram-formula mass of about 1, which goes into 3.9988 about 4 times, so there should also be 4 atoms of hydrogen
What is delta Gº for the following reaction at 25 °C?
CO(g) + 2 H2(g) = CH OH(9)
Ky = 2.1 x 10-4
Answer:
21 kJ/mol
Explanation:
Step 1: Given and required data
Temperature (T): 25 °C (298 K)Equilibrium constant (Kc): 2.1 × 10⁻⁴Ideal gas constant (R): 8.314 J/K.molStep 2: Write the balanced equation at equilibrium
CO(g) + 2 H₂(g) ⇄ CH₃OH(g)
Step 3: Calculate the standard Gibbs free energy of the reaction (ΔG°)
We will use the following expression.
ΔG° = - R × T × ln Kc
ΔG° = - (8.314 J/K.mol) × 298 K × ln 2.1 × 10⁻⁴ = 2.1 × 10⁴ J/mol = 21 kJ/mol
1. How many liters of water can be produced with 45 moles of sodium hydroxide?
Zn(s) + 2 HCl(aq) —> ZnCl2(aq)
+ H2(g)
If a scientist wanted to create 10L of hydrogen gas at RTP, what mass of HCl would they need to start with?
Answer:
First write the balanced equation for the reaction of HCl with Zn (NOTE: the previous answer did NOT do this and thus obtained an incorrect answer)
Zn + 2HCl ==> ZnCl2 + H2(g)
moles of H2 desired: PV = nRT
n = PV/RT = (1 atm)(10L)/(0.0821 Latm/Kmol)(298K)
n = 0.409 mole H2 desired
moles Zn needed:
0.409 moles H2 x 1 mole Zn/2 moles HCl = 0.204 moles Zn needed
mass Zn needed = 0.204 moles Zn x 65.4 g/mol = 13.4 g Zn needed (to 3 sig. figs.)
Explanation:people always get this wrong but i got you