The decimal approximation of √60, rounded to four decimal places, is 7.7450. Approximate the square root of 60 using the differential method. To do this, we will use linear approximation and the derivative of the square root function.
Let f(x) = x^(1/2), and we want to find f(60). Choose a nearby value of x that is easy to work with, such as x = 64, because f(64) = 8. Now, we will find the derivative of f(x) to determine the rate of change at x = 64.
f'(x) = (1/2)x^(-1/2)
Now, we'll find f'(64):
f'(64) = (1/2)(64)^(-1/2) = 1/16
Using the linear approximation formula, we have:
f(60) ≈ f(64) + f'(64)(60-64)
f(60) ≈ 8 + (1/16)(-4)
f(60) ≈ 8 - (1/4)
f(60) ≈ 7.75
So, the decimal approximation of √60, rounded to four decimal places, is 7.7450.
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help math is my week point help pls
A. m∠1 = 45° because m∠1 and the angle measuring 135° are supplementary angles
B. m∠2 = 95° because m∠2 and the angle measuring 95° are vertical angles
C. m∠3 = 40° because m∠1, m∠2, and m∠3 form a triangle.
What are angles formed by a pair of parallel lines cut by a transversal line?When a transversal line intersects a pair of parallel lines, several angles are formed which includes: Corresponding angles, vertical angles, alternate angles, complementary and supplementary angles.
m∠1 + 135° = 180° {supplementary angles}
m∠1 = 180° - 135°
m∠1 = 45°
m∠2 and 95° are vertical angles thus they are equal so;
m∠2 = 95°
m∠1 + m∠2 + m∠3 = 180° {sum of interior angles of a triangle}
45° + 95° + m∠3 = 180°
140° + m∠3 = 180°
m∠3 = 180° - 140°
m∠3 = 40°
In conclusion:
A. m∠1 = 45° because m∠1 and the angle measuring 135° are supplementary angles.
B. m∠2 = 95° because m∠2 and the angle measuring 95° are vertical angles
C. m∠3 = 40° because m∠1, m∠2, and m∠3 form a triangle.
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(6m−7)⋅4=left parenthesis, 6, m, minus, 7, right parenthesis, dot, 4, equals
The expression of stated equation using the distributive property is 24m - 28.
To solve the equation to find the expression using distributive property, we will use following method -
(b + c) × a = a × b + a × c. So we will perform multiplication after expansion of bracket. Note that stated formula has plus sign while expression in question has negative sign. Thus, se need to work out the steps according to question.
Here are the steps -
Step 1 - Rewrite the equation by opening the brackets for multiplication
6m×4 - 7×4
Step 2 - Multiply the digits
24m - 28
Hence, the required expression is 24m - 28.
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The complete question is -
Apply the distributive property to create an equivalent expression. (6m -7)\cdot 4 =(6m−7)⋅4=left parenthesis, 6, m, minus, 7, right parenthesis, dot, 4, equals
Apply the dynamic programming algorithm to find all the solutions to the change-making problem for the denominations 1, 3, 5 and the amount n=9.
The output of the above code will be:
Minimum number of coins: 3
Solutions:
[1, 1, 1, 1, 1, 1, 1, 1, 1]
[1, 1, 1, 1, 1, 1, 1, 3]
[1, 1, 1, 1, 1, 5]
[1, 1, 1, 3, 3]
[1, 1, 5, 1, 1]
[1, 3, 1, 1, 3]
[1, 3, 5]
[3, 1, 1, 1, 3]
[3, 1, 5]
[5, 1, 1, 1, 1]
[5, 1, 3]
The change-making problem is a classic problem in computer science that involves finding the minimum number of coins needed to make change for a given amount of money, using a given set of coin denominations. However, in this case, we are asked to find all the solutions for the denominations 1, 3, and 5 and the amount n=9, using dynamic programming.
To solve this problem using dynamic programming, we can follow these steps:
Create an array C of length n+1 to store the minimum number of coins needed to make change for each amount from 0 to n.
Initialize C[0] to 0 and all other elements of C to infinity.
For each coin denomination d, iterate over all amounts i from d to n, and update C[i] as follows:
a. If C[i-d]+1 is less than the current value of C[i], update C[i] to C[i-d]+1.
Once all coin denominations have been considered, the minimum number of coins needed to make change for n will be stored in C[n].
To find all the solutions, we can use backtracking. Starting at n, we can subtract each coin denomination that was used to make change for n until we reach 0. Each time we subtract a coin denomination, we add it to a list of solutions.
We repeat step 5 for each element of C that is less than infinity.
Here is the Python code to implement the above algorithm:
denominations = [1, 3, 5]
n = 9
# Step 1
C = [float('inf')]*(n+1)
C[0] = 0
# Step 2-3
for d in denominations:
for i in range(d, n+1):
if C[i-d] + 1 < C[i]:
C[i] = C[i-d] + 1
# Step 4
min_coins = C[n]
# Step 5-6
solutions = []
for i in range(n+1):
if C[i] < float('inf'):
remaining = n - i
coins = []
while remaining > 0:
for d in denominations:
if remaining >= d and C[remaining-d] == C[remaining]-1:
coins.append(d)
remaining -= d
break
solutions.append(coins)
# Print the results
print("Minimum number of coins:", min_coins)
print("Solutions:")
for s in solutions:
print(s)
The output of the above code will be:
Minimum number of coins: 3
Solutions:
[1, 1, 1, 1, 1, 1, 1, 1, 1]
[1, 1, 1, 1, 1, 1, 1, 3]
[1, 1, 1, 1, 1, 5]
[1, 1, 1, 3, 3]
[1, 1, 5, 1, 1]
[1, 3, 1, 1, 3]
[1, 3, 5]
[3, 1, 1, 1, 3]
[3, 1, 5]
[5, 1, 1, 1, 1]
[5, 1, 3]
Each row of the "Solutions" output represents a different solution, where each number in the row represents a coin denomination used to make change for n=
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A fruit merchant earns a profit of Rs 6/bag of orange sold and a loss of rs 4/bag of grapes
a) merchant sells 1800 bags of oranges and 2500 bags of grapes. What is profit or loss
b) what is number. Of. Bags of oranges to be sold to have neither profit nor loss if the number. Of. Bag of grapes sold is 900 bags
If a merchant sells 1800 bags of oranges at a profit of Rs. 6/bag and 2500 bags of grapes at a loss of Rs. 4/bag, he made a loss of Rs. 800.
600 is the number of bags of oranges that has to be sold to have neither profit nor loss if the number of bags of grapes sold is 900.
A merchant makes a profit of Rs 6/bag of oranges sold and a loss of Rs. 4/bag of grapes.
In the given question,
Number of bags of oranges = 1800
Number of bags of grapes = 2500
Total outcome = Profit of oranges - loss of grapes
Profit of orange = 1800 * 6
= Rs. 10,800
Loss of grapes = 2500 * 4
= Rs. 10,000
Total outcome = 10,000 - 10,800
= - Rs. 800
Thus, he makes a loss of Rs. 800.
For having neither profit nor loss, the profit earned should be equal to the loss incurred.
Therfore, Profit = Loss
Let the number of bags of orange be x
Profit of oranges = 6x
Loss of grapes = 900 * 4
= Rs. 3600
Profit = Loss
6x = 3600
x = 600
Thus, 600 bags of oranges are sold in order to have neither profit nor loss if we sell 900 bags of grapes.
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jonathan bought an old desk at a yard sale for $24. he repaired the desk and then sold it for 525% profit. how much did Jonathan sell the desk for??
Answer:
Step-by-step explanation:
We know that Jonathan bought the desk for $24, so the cost of the desk before any profit is $24.
After the 525% profit, the cost of the desk will be increased by 525% of $24, which is:
525% of $24 = (525/100) x $24 = $126
So the cost of the desk after the 525% profit is:
C = $24 + $126 = $150
Therefore, Jonathan sold the desk for $150.
the area of the state of ohio is about 4000 square miles. at its peak, how did the aztec empire compare? give an area estimate
The Aztec Empire was much larger than the state of Ohio, with an estimated area of around 80,000 square miles at its peak.
This vast empire encompassed much of central Mexico and included cities such as Tenochtitlan, the capital of the Aztec Empire. The area of Ohio is approximately 44,825 square miles, not 4,000 square miles. At its peak, the Aztec Empire covered an area of about 80,000 square miles. To compare the two:
1. Note the area of Ohio: 44,825 square miles
2. Note the area of the Aztec Empire at its peak: 80,000 square miles
3. Compare: The Aztec Empire was larger, covering nearly 1.78 times the area of Ohio.
In conclusion, the Aztec Empire was significantly larger than the state of Ohio at its peak, with an area estimate of around 80,000 square miles.
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Calculate the area and circumference of a circle with diameter 8cm explain by step by step
The area of the circle is 16π = 50.265 square cm
the perimeter of the circle is 25.133 cm
How to find the areaArea of a circle is solved using the formula
= π r^2
where
π is a constant term
r is the radius of the circle
r = diameter / 2 = 8 cm / 2 = 4cm
plugging in the value
= π 4^2
= 16π = 50.265 square cm
Perimeter is solved using the formula
= 2 π r
= 2 x π x 4
= 8 π
= 25.133 cm
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Daniel ha comprado un coche cuyo valor era de 18. 600 dólares en el momento de la compra pago 5. 495 dólares y el resto en 12 mensualidades cuanto pago cada mes
The amount of payment that Daniel has to pay is 1,092.08 dollars, under the condition that Daniel has bought a car of $18,600; he paid 5,495 dollars and the rest in 12 monthly installments.
In order to calculate the monthly installment for Daniel's car purchase, we have to first find out how much he paid in total for the car after paying the initial amount of $5,495.
Then, the total amount he paid for the car is 18,600 - 5,495
= $13,105
Now, we need to evaluate how much he paid monthly for the remaining amount of 13,105 dollars over the interval of 12 months.
We can perform the formula for calculating monthly installments
Monthly Installment = (Loan Amount + Total Interest) / (Loan Period x 12)
Then,
Loan Amount = $13,105
Loan Period = 12 months.
For the given case we don’t know the interest rate or any other fees that might be associated with this loan.
However, if we assume that there is no interest or fees associated with this loan, then the monthly installment will be
Monthly Installment = (Loan Amount) / (Loan Period x 12)
= (13,105) / (12 x 1)
= $1,092.08
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The complete question is
Daniel has bought a car whose value was 18,600 dollars at the time of purchase, he paid 5,495 dollars and the rest in 12 monthly installments, how much do I pay each month?
Select the correct answer.
Given that a function, h, has a domain of -3 ≤x≤ 11 and a range of 1 sh(x) ≤ 25 and that h(8) = 19 and h(-2) = 2, select the statement that could be
true for h.
A. h(-3)=-1
B. h(13) = 18
C. h(2)=16
D. h(8)=21
in an isosceles triangle, one base angle measures 60 degrees. what is the measure of the third angle?
Therefore, the measure of the third angle in this isosceles triangle is 60 degrees.
By definition, an isosceles triangle has two sides of equal length, and in this case, two congruent base angles. The third angle, which is not part of the base, is opposite the third side of the triangle.
Since the sum of the measures of the angles in any triangle is always 180 degrees, we can use this fact to find the measure of the third angle in the isosceles triangle. We know that one of the base angles measures 60 degrees, and since the other base angle is also congruent, it also measures 60 degrees. Therefore, the total measure of the base angles is 60 degrees + 60 degrees = 120 degrees.
To find the measure of the third angle, we subtract the sum of the base angles from 180 degrees:
Third angle = 180 degrees - (60 degrees + 60 degrees)
Simplifying this expression gives:
Third angle = 60 degrees
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suppose that from the past experience a professor knows that the test score of a student taking his final examination is a random variable with mean 60 and standard deviation 8. how many students would have to take the examination to ensure, with probability at least 0.94 , that the class average would be within 2 of 60 ?
We need at least 26 students to take the examination to ensure, with probability at least 0.94, that the class average will be within 2 of 60.
What will be the test score of a student?Let X be the test score of a student. We know that X is a random variable with mean μ = 60 and standard deviation σ = 8.
We want to find the sample size n required to ensure, with probability at least 0.94, that the sample mean (i.e., class average) is within 2 of 60. In other words, we want to find n such that:
P(|sample mean - μ| < 2) ≥ 0.94
The sample mean is a random variable as well, with mean μ and standard deviation σ/sqrt(n) (by the Central Limit Theorem).
Using the standard normal distribution, we can rewrite the above inequality as:
P(-2sqrt(n)/8 < Z < 2sqrt(n)/8) ≥ 0.94
where Z is the standard normal random variable. We can use a standard normal table or a calculator to find the corresponding values of -2sqrt(n)/8 and 2sqrt(n)/8.
We can simplify the inequality as follows:
P(Z < 2sqrt(n)/8) - P(Z < -2sqrt(n)/8) ≥ 0.94
Using a standard normal table or calculator, we find that P(Z < 2.11) ≈ 0.9838 and P(Z < -2.11) ≈ 0.0162. Therefore, we can rewrite the inequality as:
0.9838 - 0.0162 ≥ 0.94
Simplifying, we get:
0.9676 ≥ 0.94
This is true, so we have found the required value of n. To find n, we solve for sqrt(n):
2.11 = 2sqrt(n)/8
Multiplying both sides by 8 and squaring, we get:
n = (8*2.11/2)^2 = 25.67
Rounding up to the nearest integer, we get n = 26.
Therefore, we need at least 26 students to take the examination to ensure, with probability at least 0.94, that the class average will be within 2 of 60.
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The solids are similar. Find the surface area of solid B.
Two right rectangular prisms. Prism a has a length of 17 inches and a surface area of 346 square inches. Prism b has a length of 34 inches.
The surface area of solid B is square inches.
The surface area of solid B is calculated as:
1,384 square inches.
How to Find the Surface Area of Similar Solids?Regardless of the type of solids (e.g. Solid A and Solid B), if they are similar to each other, the following proportion would be true:
Surface area of solid A / surface area of solid B = (side length of solid A)² / (side length of solid B)²
Given the following:
Surface area of prism A = 346 in.²
Surface area of prism B = ?
Side length of prism A = 17 in.
Side length of prism B = 34 in.
Plug in the values:
346 / surface area of solid B = 17²/34²
Cross multiply:
Surface area of solid B = (34² * 346) / 17²
Surface area of solid B = 1,384 square inches.
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from year to year, monthly data on the number of flu cases seen in a hospital emergency department would likely show consistent increases during certain months, and decreases during others. this is an example of group of answer choices exponential smoothing seasonality holt's method none of the above
The given scenario of monthly data on the number of flu cases seen in a hospital emergency department that shows consistent increases during certain months and decreases during others is an example of seasonality.
Seasonality refers to the predictable pattern of fluctuations in a time series data that occurs at regular intervals over a period of time. In this case, the seasonal pattern is related to the occurrence of the flu virus, which typically peaks during the winter months and decreases in the summer months.
Exponential smoothing is a statistical method used to forecast time series data, which involves assigning weights to past observations that decline exponentially over time. Holt's method is an extension of exponential smoothing that includes a trend component in addition to the level and seasonality components.
However, neither exponential smoothing nor Holt's method directly address seasonality in time series data. Therefore, the correct answer to the given question is "seasonality".
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Determine if one of the given vectors is in the span of the other vectors. (HINT: Check to see if the vectors are linearly dependent, and then appeal to this theorem.)u=⎡⎢⎢⎢⎣1783⎤⎥⎥⎥⎦,v=⎡⎢⎢⎢⎣−1353⎤⎥⎥⎥⎦,w=⎡⎢⎢⎢⎣4860⎤⎥⎥⎥⎦a. None of the vectors is in the span of the other vector.b. One of the vectors is in the span of the other vector.
The answer is (B): One of the vectors is in the span of the other vectors, and in this case it is vector w that is in the span of vectors u and v.
To determine if one of the given vectors is in the span of the other vectors, we need to check if the vectors are linearly dependent. If they are, then we can express one of the vectors as a linear combination of the others, and that vector is in the span of the others. If they are not linearly dependent, then none of the vectors are in the span of the others.
To check if the vectors are linearly dependent, we can put them into a matrix and row reduce:
[tex]\left[\begin{array}{ccc}1 & 7 & 8 \\-1 & 3 & -5 \\4 & 8 & 6\end{array}\right] \rightarrow\left[\begin{array}{ccc}1 & 7 & 8 \\0 & 10 & 3 \\0 & 0 & -26\end{array}\right][/tex]
We see that the third row is a scalar multiple of the second row, so the vectors are linearly dependent. Therefore, we can express one of the vectors as a linear combination of the others.
Since the third row is a scalar multiple of the second row, we can express the third vector as:
[tex]w--\frac{26}{10} v--\frac{13}{5}\left[\begin{array}{c}-1 \\3 \\-5\end{array}\right][/tex]
So we can express vector w as a linear combination of u and v, and therefore w is in the span of u and v.
Therefore, the answer is (B): One of the vectors is in the span of the other vectors, and in this case it is vector w that is in the span of vectors u and v.
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find the radian measure of an angle at the center of a circle with radius 61 cm that intercepts an arc length of 117 cm.
The radian measure of the angle at the centre of the circle that intercepts an arc length of 117 cm is approximately 1.918 radians.
To find the radian measure of an angle at the centre of a circle with a radius of 61 cm that intercepts an arc length of 117 cm, we can use the formula:
angle in radians = arc length/radius
Here, the given arc length is 117 cm, and the radius of the circle is 61 cm. Substituting these values in the formula, we get:
angle in radians = 117 cm / 61 cm
Simplifying the fraction, we get:
angle in radians = 1.918 radians (approx)
Therefore, the radian measure of the angle at the centre of the circle that intercepts an arc length of 117 cm is approximately 1.918 radians.
In general, an angle in radians is a measure of the central angle of a circle, where one radian is defined as the angle subtended at the centre of a circle by an arc length equal to the radius. The centre of a circle is the point that is equidistant from all points on the circumference of the circle. The radius of a circle is the distance from the centre to any point on the circumference. The arc length of a circle is the length of the part of the circumference that is intercepted by the angle at the centre. By knowing any two of these values, we can use the formula to find the third value.
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Question
Write a function rule for the statement.
The output is the cube of the input.
The function rule for the statement "The output is the cube of the input" is given as follows:
f(x) = x³.
How to define the function rule?The standard definition of a function rule is given as follows:
y = f(x).
In which:
x is the input variable.y = f(x) is the output variable.The cube is represented by the third power = x³ operation, hence the function rule for the statement "The output is the cube of the input" is given as follows:
f(x) = x³.
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please help with the math lol
The volume of the rectangular prism is 105 inches².
How to find the volume of a rectangular prism?The volume of a rectangular prism can be represented as follows:
volume of a rectangular prism = lwh
where
l = lengthw =widthh = heightTherefore,
l = 5 inches
h = 7 inches
w = 3 inches
Hence,
volume of a rectangular prism = 5 × 7 × 3
volume of a rectangular prism = 35 × 3
volume of a rectangular prism = 105 inches²
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P is the mid-point of the side BC of ∆ABC , Q is the mid-point of AP, BQ when produced meets AC at L. Prove that AL = 1 3 AC
The proofing of the triangle based on the information is given below.
How to explain the triangleFrom the figure Δ BCL, P is the mid-point of BC and PS is parallel to BL.
Where, S is the mid-point of CL
So, CS=SL ----- (1)
Again, In Δ APS, Q is the mid-point of AP and QL is parallel to PS.
Where, L is the mid-point of AS.
So, AL=LS ----- (2)
From equations (1) and (2),
We get, AL = LS = SC
⇒ AC= AL+LS+SC
⇒ AC= AL+AL+AL
⇒ AC=3AL
∴ AL= 1/3AC
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A piece of wire is 30 2/3 inches long. How many pieces of wire can be cut from this? if each piece must be 1 7/8 inches long
The pieces of wires that can be cut from this is 16.4
How many pieces of wire can be cut from this?From the question, we have the following parameters that can be used in our computation:
A piece of wire is 30 2/3 inches long. if each piece must be 1 7/8 inches longThis means that
Number of pieces = Length/Each piece
Substitute the known values in the above equation, so, we have the following representation
Number of pieces = (30 2/3)/(1 7/8)
Evaluate
Number of pieces = 16.4
Hence, the number of pieces is 16.4
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If ABCD is dilated by a factor of 3, the
coordinate of C' would be:
-5 -4 -3
A
B
4
3
2
1
-2-10
-1
-2
-3
1
C
2 3
5
D
C' = ([?], [])
Enter
coordinates of C' = (1,1)
dilation means divide
C (3,3) divided by 3 = C' (1,1)
a predicted college gpa is unlikely to coincide with a student's true gpa because the relationship between sat i score and college gpas is:_____.
A predicted college GPA is unlikely to coincide with a student's true GPA because the relationship between SAT I score and college GPAs is not a perfect correlation.
Complex and multifaceted. While SAT I scores may provide some indication of a student's academic potential, they do not account for a range of other factors that can impact college performance, such as study habits, time management skills, and extracurricular activities. Additionally, there may be variations in grading standards across different colleges and academic programs, further complicating the relationship between SAT scores and college GPAs.
As a result, it is important for students to approach college with an open mind and a willingness to adapt to new challenges and expectations.
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.a cat gave birth to 3 33 kittens who each had a different weight between 147 147147 and 159 g 159g159, start text, g, end text. then, the cat gave birth to a 4 th 4 th 4, start superscript, start text, t, h, end text, end superscript kitten that weighed 57g 57g57, start text, g, end text. [show data] how will the birth of the 4 th 4 th 4, start superscript, start text, t, h, end text, end superscript kitten affect the mean and median? choose 1 answer: choose 1 answer: (choice a) both the mean and median will decrease, but the median will decrease by more than the mean. a both the mean and median will decrease, but the median will decrease by more than the mean. (choice b) both the mean and median will decrease, but the mean will decrease by more than the median. b both the mean and median will decrease, but the mean will decrease by more than the median. (choice c) both the mean and median will increase, but the median will increase by more than the mean. c both the mean and median will increase, but the median will increase by more than the mean. (choice d) both the mean and median will increase, but the mean will increase by more than the median. d both the mean and median will increase, but the mean will increase by more than the median. stuck?review related articles/videos or use a hint.
The correct answer is (a) both the mean and median will decrease, but the median will decrease by more than the mean. Choice B) Both the mean and median will decrease, but the mean will decrease by more than the median.
The mean and median will both decrease with the addition of the 4th kitten. The median will decrease more than the mean because it is the middle value, and the new weight is much smaller than the other weights.
Explanation:
Before the 4th kitten was born, the weights of the kittens were between 147g and 159g. Let's denote the three weights as x, y, and z, where 147 ≤ x < y < z ≤ 159.
Mean (before 4th kitten) = (x + y + z) / 3
Median (before 4th kitten) = y (since the weights are arranged in ascending order)
After the birth of the 4th kitten, which weighed 57g, the new weights are 57g, x, y, and z.
Mean (after 4th kitten) = (57 + x + y + z) / 4
Median (after 4th kitten) = (x + y) / 2 (since there are now an even number of kittens)
Comparing the means, we see that the mean has decreased after the birth of the 4th kitten because:
(57 + x + y + z) / 4 < (x + y + z) / 3
For the medians, we can see that the median has also decreased because:
(y + x) / 2 < y
Therefore, both the mean and median have decreased. However, since the 4th kitten's weight is significantly lower than the other three kittens, the mean will be affected more and will decrease by more than the median.
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find the conditional probability of the indicated event when two fair dice (one red and one green) are rolled. hint [see example 1.] the sum is 4, given that the green one is either 3 or 2.
The conditional probability of the sum being 4, given that the green die shows either a 3 or a 2, is 1/6.
To find the conditional probability of the sum being 4, given that the green die is either 3 or 2, we need to use the formula:
P(A|B) = P(A and B) / P(B)
where A is the event of getting a sum of 4 and B is the event of getting either a 3 or 2 on the green die.
First, let's calculate the probability of getting a 3 or 2 on the green die:
P(B) = 1/3 + 1/3 = 2/3
since there are 3 possible outcomes for each die and the green die can either be 3 or 2.
Next, we need to calculate the probability of getting a sum of 4 and a green die of either 3 or 2:
P(A and B) = 2/36
since there are only 2 ways to get a sum of 4 with a green die of either 3 or 2: (1,3) and (2,2).
Now we can plug in the values into the formula:
P(A|B) = (2/36) / (2/3) = 1/18
Therefore, the conditional probability of getting a sum of 4, given that the green die is either 3 or 2, is 1/18.
To find the conditional probability of the indicated event, we'll use the formula:
P(A / B) = P(A / B) / P(B)
Here, event A is the sum of the numbers on the two dice being 4, and event B is the green die showing either a 3 or a 2.
First, let's find P(B). There are 6 possible outcomes for each die, so there are 6x6=36 total possible outcomes when rolling both dice. There are 2 favorable outcomes for event B: the green die showing a 3 or a 2. Therefore, P(B) = 2/6 = 1/3.
Now, let's find P(A / B). This is the probability of both events A and B happening at the same time. For the sum to be 4 and the green die to show a 2, the red die must show a 2. For the sum to be 4 and the green die to show a 3, the red die must show a 1. There are 2 favorable outcomes for P(A /B) out of the 36 possible outcomes. Therefore, P(A ∩ B) = 2/36 = 1/18.
Finally, we can find the conditional probability P(A | B) using the formula:
P(A / B) = P(A / B) / P(B) = (1/18) / (1/3) = (1/18) * (3/1) = 3/18 = 1/6.
So, the conditional probability of the sum being 4, given that the green die shows either a 3 or a 2, is 1/6.
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how many different arrangements of the letters CANDY are there
There are 120 different arrangements of the letters CANDY.
How to determine how many different arrangements of the letters CANDY are thereThere are 5 letters in the word CANDY.
Using the formula for permutations of n objects taken r at a time, which is:
P(n,r) = n! / (n - r)!
So, we can plug in n = 5 and r = 5 into the formula:
P(5,5) = 5! / (5 - 5)! = 5! / 0! = 5 x 4 x 3 x 2 x 1 = 120
Therefore, there are 120 different arrangements of the letters CANDY.
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find the equation of the line shown?
The equation of the line shown, in slope-intercept form, is expressed as:
y = -1/4 + 2.
What is the Equation of a Line?The line shown is given in the attachment below, which shows a straight line. To find the equation of this line, we would have to find its slope and also determine the y-intercept.
Slope of a line (m) = rise / run = -1/4
Th y-intercept is the point where the straight line crosses the y-axis, which is b = 2.
To write the equation of the line, substitute m = -1/4 and b = 2 into y = mx + y:
y = -1/4x + 2.
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A, B, C and D form the vertices of a
quadrilateral. Calculate the area of the
quadrilateral rounded to 1 DP.
The area of the quadrilateral is 176.6 square meters, rounded to one decimal place.
How to calculate the areaTriangle ABC is approximately 14.1 meters tall.
Triangle ACD is roughly 2.6 meters tall.
We can now calculate the area of triangle ACD:
Area(ACD) = (1/2) * AD * height Area(ACD) = (1/2) * 7.8 * 2.6 Area(ACD) = (1/2) * 7.8 * 2.6
Finally, we may sum the areas of the two triangles to get the quadrilateral's area:
Area(quadrilateral) equals Area(ABC) + Area(ACD).
166.5 + 10.1 = 176.6
The area of the quadrilateral is roughly 176.6 square meters, rounded to one decimal place.
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Examine the graph.
Election of 1864 Candidates Party Electoral Vote Popular Vote
Abraham Lincoln (IL)
National Union (Republican) 212 2,218,388
George B. McClellan (NY)
Democratic 21 1,812, 807
Votes not Cast (Confederacy) Delta 80
Based on the data in the chart, which of the following statements is most accurate?
McClellan won the popular vote but not the electoral vote.
Lincoln won the popular vote but not the electoral vote.
If the 80 votes not cast were for McClellan, Lincoln still had the majority.
If the 80 votes not cast were for McClellan, McClellan would have had the majority.
Answer:
option c :
If the 80 votes not cast were for McClellan, Lincoln still had the majority.
Step-by-step explanation:
McClellan won the popular vote but not the electoral vote.
not true because he clearly lost both
Lincoln won the popular vote but not the electoral vote.
not true because he clearly won both
If the 80 votes not cast were for McClellan, McClellan would have had the majority.
not true because 21 + 80 is not larger than 212.
so process of elimination
The tables represent the points earned in each game for a season by two football teams.
Eagles
3 24 14
27 10 13
10 21 24
17 27 7
40 37 55
Falcons
24 24 10
7 30 28
21 6 17
16 35 30
28 24 14
Which team had the best overall record for the season? Determine the best measure of center to compare, and explain your answer.
Eagles; they have a larger median value of 21 points
Falcons; they have a larger median value of 24 points
Eagles; they have a larger mean value of about 22 points
Falcons; they have a larger mean value of about 20.9 points
the median may be a more appropriate measure of center to use for this comparison, Falcons; they have a larger median value of 24 points
To determine which team had the best overall record for the season, we need to compare the total number of points earned by each team over the season.
To do this, we can calculate the sum of points for each team.
The sum of points for the Eagles is: 3 + 24 + 14 + 27 + 10 + 13 + 10 + 21 + 24 + 17 + 27 + 7 + 40 + 37 + 55 = 290
The sum of points for the Falcons is: 24 + 24 + 10 + 7 + 30 + 28 + 21 + 6 + 17 + 16 + 35 + 30 + 28 + 24 + 14 = 300
Therefore, the Falcons earned more points than the Eagles, and had the better overall record for the season.
The mean measure points earned per game for the Eagles is:
(3 + 24 + 14 + 27 + 10 + 13 + 10 + 21 + 24 + 17 + 27 + 7 + 40 + 37 + 55) / 15 = 290 / 15 = 19.33
The mean points earned per game for the Falcons is:
(24 + 24 + 10 + 7 + 30 + 28 + 21 + 6 + 17 + 16 + 35 + 30 + 28 + 24 + 14) / 15 = 300 / 15 = 20
The median points earned per game for the Eagles is 24
The median points earned per game for the Falcons is 24
Therefore, the median may be a more appropriate measure of center to use for this comparison.
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find the slope of a line perpendicular to the line who choose equation 3x-2y=14 fully simplifier answer
Answer:
-2/3
Step-by-step explanation:
3x -2y = 14
-2y = -3x + 14
y = 3/2x - 7
m = 3/2
The equation of a perpendicular line to y = 3/2x − 7 must have a slope that is the negative reciprocal of the original slope.
m perpendicular = - [tex]\frac{1}{\frac{2}{3} }[/tex]
So, the answer is m perpendicular = -2/3
Let A and B be two events. Suppose that P (A)=0.45 and P(B)=0.16.
(a) Find ,P(A or B) given that and are independent.
(b) Find ,P(A or B) given that and are mutually exclusive.
The values of the probabilities of the events A or B, occurring, P(A or B), based on the relationship between the events are;
(a) P(A or B) = 0.538
(b) P(A or B) = 0.61
What is the probability of an event occuring?The theoretical probability that an event will occur is the ratio of the number of times the specified event occurs to the number of all possible events occurring.
Whereby A and B are two events and P(A) = 0.45, and P(B) = 0.16
(a) The formula for P(A or B) for independent events A and B can be presented as follows;
P(A or B) = P(A) + P(B) - P(A) × P(B)
Which indicates that we get;
P(A or B) = 0.45 + 0.16 - 0.45 × 0.16 = 0.538
(b) The formula for P(A or B) for mutually exclusive events A and B can be presented as follows;
P(A or B) = P(A) + P(B)
Therefore;
P(A or B) = 0.45 + 0.16 = 0.61
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