Use the diagram to determine total resistance. (Round the FINAL answer to one decimal place.) Note: Use the rated voltage and wattage to determine resistance. Note: Ra and Rb represent the resistance of the wire. The 120 volts of the motor and lamps is their rated voltage and not the actual voltage. I know the answer is 22.7 Ohms. I get very close, but I am not 100%.. I need to be 100%. If you can also: with the same diagram I need the total current as well! Thank you very much.

the answer to that would be a) true

PLEASE GIVE BRAINLIST

A parallel circuit has two or more paths for current to flow through. Voltage is the same across each component of the parallel circuit. The sum of the currents through each path is equal to the total current that flows from the source.

HOPE THIS HELPED

Answer:

Period = 0.2857 nanoseconds

Explanation:

We are told that frequency = 3.5 GHz

This is simply 3.5 × 10^(9) Hz

Now, from wave equations, Period is given by the formula;

Period = 1/frequency

Thus;

Period = 1/(3.5 × 10^(9))

Period = 0.2857 × 10^(-9) seconds

From conversions, we can simplify the answer.

1 second = 10^(-9) nanoseconds

Thus, 0.2857 × 10^(-9) seconds = 0.2857 × 10^(-9) × 10^(-9) nanoseconds = 0.2857 nanoseconds

Answer:

In order to take a portrait, the distance of the mascot from the camera should be approximately 7.33 feet

Explanation:

The size of the film paper = 3 in. × 5 in.

The focal length of the camera = 5.5 in.

The height and width of the guinea pig = 4 ft.

The height of the aperture above the ground = 2 ft.

Therefore, we have;

Magnification = Height of image/(Height of object)

Withe the 3 in. wide film, we have;

Magnification = 3 in./(4 ft.) = 3 in./(48 in.) = 0.0625

Magnification = Length of camera/(Distance of object from pin hole)  

∴ Length of camera/(Distance of object from pin hole) = 0.0625

Length of camera = Focal length of the camera = 5.5 in.

Therefore;

5.5 in./(Distance of object from pin hole) = 0.0625

Distance of object from pin hole = 5.5/0.0625 = 88 inches = 7.33 ft

Therefore, the camera should be approximately 7.33 ft. from the mascot to take a portrait.

In this exercise we have to use the magnification knowledge to calculate the distance that the photograph should be taken, thus we have to:

Distance of the mascot from the camera should be approximately 7.33 feet

To calculate the best distance to take the photo, we have that some information must be taken into account such as:

Therefore, we have that the formula of magnification is:

[tex]Magnification = Height \ of \ image/(Height \ of \ object)[/tex]

With the 3 in wide film, we have;

[tex]Magnification = 3 in/(4 ft) \\= 3 in/(48 in) = 0.0625 in[/tex]

Rewriting the magnification formula as:

[tex]Magnification = Length \ of \ camera/(Distance \ of \ object \ from \ pin \ hole)[/tex]  

Substituting the values ​​already known we have the equation will be matched as:

[tex]Length\ of \ camera/(Distance\ of\ object \ from \ pin \ hole) = 0.0625\\Length \ of \ camera = Focal \ length \ of \ the \ camera = 5.5 in.[/tex]

Therefore;

[tex]5.5 /(Distance \ of \ object\ from \ pin\ hole) = 0.0625 in\\Distance \ of \ object\ from \ pin \ hole = 5.5/0.0625\\ = 88 inches = 7.33 ft[/tex]

See more about distance at brainly.com/question/989117

Answer:

None of the above cause thats what i put

Answer:

Place the jack under the part of the vehicle that it should contact when raised. If you're using jack stands, place them near the jack. If you place your jack incorrectly, you can injure your car. To find the proper place to position the jack for your particular vehicle, check your owner's manual.

Answer:

1) The power developed by the engine is 14705.7739 kW

2) The thermal efficiency is approximately 61.5%

Explanation:

The given parameters are;

P₁ = 95 kPa

T₁ = 22°C

V₁ = 3.17 liters

The cutoff ratio = 2.5

Displacement volume = 3 liters

The number of times the cycle is executed per minute = 1000 times per minute

We have;

The displacement volume = V₁ - V₂ = 3 l

V₁ = 3.17 l

V₂ = 3 - 3.17 = 0.17 l

Compression ratio = V₁/V₂ = 3.17/0.17 ≈ 18.65

P₂/P₁ = P₂/(95 kPa) =  (V₁/V₂)^(k) = 18.65^1.4

P₂ = (95×18.65^(1.4)) ≈ 5710.5 kPa

T₂/T₁ = (V₁/V₂)^(k - 1)

T₂/(295 K)= (18.65)^(1.4 - 1)

T₂ = 295 * (18.65)^(1.4 - 1) = 950.81 K

The cutoff ratio = V₃/V₂ = 2.5

T₃ = T₂ × V₃/V₂  = 2.5 * 950.81 K = 2377.025 K

[tex]Q_{in}[/tex] = [tex]C_p[/tex]×(T₃ - T₂) = 1.006 × (2377.025 - 950.81) = 1,434.77 kJ/kg

T₄ = T₃ × (V₃/V₄)^(k-1) =

Therefore,

[tex]T_4 = T_3 \times \left (\dfrac{r_c}{r} \right )^{k - 1} = 2377.025 \times \left( \dfrac{2.5}{18.65} \right )^{1.4 - 1} \approx 1064 \ K[/tex]

T₄ ≈ 1064 K

[tex]Q_{out}[/tex] = [tex]-C_v \times (T_4 - T_1)[/tex]

[tex]C_v = C_p/k = 1.006/1.4 \approx 0.7186 \ kJ/kg[/tex]

∴ [tex]Q_{out}[/tex] = 0.7186×(1064 - 295) = 552.6034 kJ/kg

1) The net work = [tex]Q_{in}[/tex] - [tex]Q_{out}[/tex] = 1,434.77 kJ/kg - 552.6034 kJ/kg ≈ 882.17 kJ/kg

The number of cycle per minute = 1000 rpm

The number of cycle per minute = 1000 rpm/60 = 16.67 cycles per second

The power developed by the engine = The number of cycles per second × The net work of the engine

Therefore;

The power developed by the engine = 16.67 cycles/second  × 882.17 kJ/kg

The power developed by the engine = 14705.7739 kW

2) Efficiency, [tex]\eta _{th}[/tex], is given as follows;

[tex]\eta _{th} = \dfrac{Q_{in}-Q_{out}}{Q_{in}} \times 100 = 1 - \dfrac{Q_{out}}{Q_{in}} \times 100= 1 - \dfrac{552.6034}{1434.77}\times 100 \approx 61.5\%[/tex]

Therefore, the thermal efficiency ≈ 61.5%.

Answer:

There are actually multiple types of processes a manufacturer uses, and those can be grouped into four main categories: casting and molding, machining, joining, and shearing and forming.

Explanation:

Answer:

The molecular weight of the gas mixture is 35.38 g/mol.

Explanation:

The molecular weight of the gas can be found using the following equation:

[tex] M = \frac{m}{n} [/tex]

Where:

m: is the mass = 230 g

n: is the number of moles

First, we need to find the number of moles using Ideal Gas Law:

[tex] PV = nRT [/tex]

Where:

P: is the pressure = 135 psi

V: is the volume = 15 L

R: is the gas constant = 0.082 L*atm/(K*mol)

T: is the temperature = 465 °R (K = R*5/9)

[tex]n = \frac{PV}{RT} = \frac{135 psi*\frac{1 atm}{14.6959 psi}*15 L}{0.082 L*atm/(K*mol)*465*(5/9) K} = 6.50 moles[/tex]                

Finally, the molecular weight of the gas is:

[tex] M = \frac{m}{n} = \frac{230 g}{6.50 moles} = 35.38 g/mol [/tex]

Therefore, the molecular weight of the gas mixture is 35.38 g/mol.

I hope it helps you!

That is an example of a want because you don't need the ball.

Answer:

a). α =  26.57  

b). Maximum load is 50 .kN

Explanation:

a).

The normal force is given by

N = σ A cosec β

where, σ is the normal stress

            A is the cross sectional area

Similarly, shear force is given by

S= τ A cosec β

where, τ is the shearing stress

Now from the figure,

tan β = S/N

        = τ/σ

Therefore, [tex]$\beta = \tan^{-1}(2)$[/tex]  = 63.43

α = 90 - β = 26.57

b).

The normal force is given by

[tex]$N=(100\times 10^6)(400\times 10^{-6}) \text{ cosec}\ 63.43$[/tex]

[tex]$N=44.78\times 10^3$[/tex] N

We have

[tex]$\Sigma F_y=0$[/tex]

∴ N - F sin β = 0

⇒ F = N / sin β

      = [tex]$\frac{44.72\times 10^3}{\sin(63.43)} = 50\times 10^3 N$[/tex]

Similarly,

The shear force is given by

S = τ A cosec β

  = [tex]$(50\times 10^6)(400\times 10^{-6}) \text{ cosec}\ 63.43 = 22.36\times 10^3 N$[/tex]

[tex]$\Sigma F_x=0$[/tex]

∴ S - F cos β = 0

⇒ F = S / cos β

[tex]$\frac{22.36\times 10^3}{\cos(63.43)} = 49.99\times 10^3 N$[/tex]

Therefore, force is 50 kN.

Answer:

Option C..Farmers saught new technology to help with the workload

hope this helped you

please mark as the brainliest (ㆁωㆁ)

Answer:

  C.  3325 Ω - 3675 Ω

Explanation:

5% of 3500 Ω is ...

  0.05 × 3500 = 175

The lower limit is this amount less than the nominal value:

  3500 -175 = 3325

The upper limit is the nominal value plus the tolerance:

  3500 +175 = 3675

The lower and upper limits are 3325 Ω and 3675 Ω, respectively.

Answer:

The engineer will conduct a variety of tests, including chemical, mechanical, electrical, and physical examinations, to determine the potential of the new material.

Explanation:

They will need to test the material, this will also help to determine its malleability.

Hope this helps!

Answer:

A. voltage

Explanation:

The rate of heat transfer per unit area in a thermal circuit is equivalent to the voltage in an electrical circuit.

This is because, within an electrical circuit the voltage is supplied by a generator, which can be batteries, batteries, or others. The moment the electrical voltage acts within a circuit, it will consist of the gradient of electrical potential between two points, which will cause the electrons to move from the point with the highest concentration to the point with the lowest concentration (similar to the transfer of heat from the thermal circuit) generating the electric current.

Answer:

2k20

Explanation:

4k ✈

Answer:

B) write down all activities and commitments.

Explanation:

also i found the answer on quizlet hope this works:))

Answer:

write down all activities and commitments.

Explanation:

i had got the same question on my unit test and it was the answer it was right

Answer:

While scientists study how nature works, engineers create new things, such as products, websites, environments, and experiences. Because engineers and scientists have different objectives, they follow different processes in their work.

Explanation:

Answer:

A

Explanation:

general information sign

safety is orange

caution is yellow

danger is red

Answer: true

Explanation:

A key is a machine element that us used to connect the element of a rotating machine to a shaft. It should be noted that the key hinders the relative rotation that may take place between the two parts.

Key length is designed to provide desired factor of safety. It should also be noted that the factor of safety shouldn't be much and the key length is typically limited to the hub length.

Answer:

wheel guard

Explanation:

to protect our hands and reduce spark

Incomplete question. However, I provided information that could assist you in identifying the main problem or issue addressed in any case study.

Explanation:

First, note that a case study is simply a learning aid that allows one to learn from a real-life scenario.

To determine the main problems of a case study one needs to:

Thus, by taking these few steps you may be able to determine the main problem in that case study.

Answer:skull and crossbones

Explanation:

Answer: True is correct

A third-degree burn may look charred and black or dry and white.

Explanation:

Answer:

Negative feedback control of the amplifier is achieved by applying a small part of the output voltage signal at Vout back to the inverting ( – ) input terminal via the feedback resistor

Answer:

The system has parts that sense the amount of output

Explanation:

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