Use the definition of the derviative to compute the derivative of f(x)= 1- 7x^2 at the specific point x=2.

Answer: a= w - 4b/ 7

Step-by-step explanation:

Answer:

(3,-1)

Step-by-step explanation:

f(x)=(x2 - 6x)+8

f(x) = (x2 - 6x +9) + 8 - 9

f(x) = (x2 - 6x + 9) - 1

f(x) = (x - 3)^2 - 1

Since the completing square formula = a(x - h) + k

The vertex = (h,k)

= (3,-1)

Area of cylinder = curved area + 2 x base circle

Circles = 2 x π(8)² = 128π cm²

Curved area = circumference of circle x height of cylinder

Circumference of circle = 2πr = 2π(8) = 16π cm

Curved area = 16π x 4 = 64π cm²

Total surface area = 128π + 64π = 192π cm² = 603.19cm² (5sf)

I use to have reddit sorry

Answer:

Yes

Step-by-step explanation:

Mines is u/Brown_Bear17

Answer:

m=4

2y/2=y

8x/2=4x

4/2=2

so

y=4x+4

Answer:

x^2-3y

5^2-3*8

25-24

1

Step-by-step explanation:

Answer:

28.35

Step-by-step explanation:

you can use mathswatch or hegarty maths to help u

Answer:

see explanation

Step-by-step explanation:

∠ 4 and ∠ 6 are same- side interior angles and supplementary, sum to 180°

Step-by-step explanation:

[tex]angle \: 4 \: makes \: a \: c \: shape \: when \: refering \: it \: to \: angle \: 6 \: which \: is \: terefore \: a \: correspndin \: angle \: \\ \\ [/tex]

Answer:

missing angle=36 degree

Answer: See the diagram below

=================================================

Explanation:

The base is always perpendicular to the height, meaning the two form a 90 degree angle (aka right angle).

In column 1, refer to the figures as 1, 2 and 3 (working top to bottom).

In column 2, refer to the figures as A, B, C

Figure 1 matches with figure B

Figure 2 matches with figure C

Figure 3 matches with figure A.

These matches are of course the base with the proper height.

Answer:

3. x=50, y=80, 4. x=6.5, y=5

Step-by-step explanation:

I think, not entirely sure.

Answer:

I would love to help you but what am I helping with there is no question there other that "Help me plssssss"

Step-by-step explanation:

Answer:

The area of the canvas must be 30 feet.

Step-by-step explanation:

Answer:

m<W = 103°

Step-by-step explanation:

First, find the value of x

m<W + m<Y = 180° (opposite angles in a cyclic quadrilateral are supplementary)

11x - 29 + 6x + 5 = 180 (substitution)

Add like terms

17x - 24 = 180

Add 24 to both sides

17x = 180 + 24

17x = 204

Divide both sides by 17

17x/17 = 204/17

x = 12

Find m<W:

m<W = 11x - 29

Plug in the value of x

m<W = 11(12) - 29 = 132 - 29

m<W = 103°

Answer:

Step-by-step explanation:

As you can see from the value in the middle of the questions, the domain refers to all the possible x-values (input values) while the range refers to all the possible f(x) values (output values :: y-values). Therefore, for the domain, since the endpoints of the graph are closed circles it means that they are included so the domain would be ...

Domain: -9 ≤ x ≤ 7

The range would be the lowest and highest included y-value on the graph which in this case would be ...

Range: -6 ≤ f(x) ≤ 4

Answer:

Yes they are all right

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

75ft

Step-by-step explanation:

if the shadow of a 6ft = 2.4ft

then the shadow of x=(30/2.4)×6=75

Answer:

5.25

Step-by-step explanation:

Convert the fraction to a decimal by dividing the numerator by the denominator.

Answer:

17.6369809748oz

Step-by-step explanation:

hope this helps

Answer:

17.637

Step-by-step explanation:

Answer:

[tex]BD = 4[/tex]

[tex]BC =4\sqrt 3[/tex]

Step-by-step explanation:

Given

The attached triangle

Required

Find BD and BC

Solving BD

Considering angle at D, we have:

[tex]\cos(D) = \frac{Adjacent}{Hypotenuse}[/tex]

[tex]\cos(60) = \frac{BD}{8}[/tex]

Solve for BD

[tex]BD = 8 * \cos(60)[/tex]

[tex]\cos(60) = 0.5[/tex] So:

[tex]BD = 8 * 0.5[/tex]

[tex]BD = 4[/tex]

To solve for BC, we make use of Pythagoras theorem

[tex]CD^2 = BC^2 + BD^2[/tex]

This gives

[tex]8^2 = BC^2 + 4^2[/tex]

[tex]64 = BC^2 + 16[/tex]

Collect like terms

[tex]BC^2 =64-16[/tex]

[tex]BC^2 =48[/tex]

Take square roots

[tex]BC =\sqrt{48[/tex]

Expand

[tex]BC =\sqrt{16*3[/tex]

Split

[tex]BC =\sqrt{16}*\sqrt 3[/tex]

[tex]BC =4\sqrt 3[/tex]

[tex]7 \times \frac{1}{3} \\ \\ = \frac{7 }{3} [/tex]

Answer:

a

Step-by-step explanation:

you are correct it is a (decreases) when objects move farther away the strength of the force becomes less.

Answer:

x = 0.5

Step-by-step explanation:

[tex]\frac{5}{2x} +3=\frac{4}{x}[/tex]

[tex]2x(\frac{5}{2x} +3)=2x(\frac{4}{x})[/tex]

5 + 6x = 8

5 - 5 + 6x = 8 - 5

6x = 3

[tex]\frac{6x}{6} =\frac{3}{6}[/tex]

x = 0.5

Answer:

A = 1/2 × b × h

A = 1/2 × 60 × 30

A = 1/2 x 900

A = 450

--------

A = 1/2 x 6 x 18

A= 1/2 x 54

A = 27

----------

27 + 450 = 477

=477

Step-by-step explanation:

Answer:

see first of all it is a quadratic polynomial so it will have 2 zero alpha and beta

now , we will find value of a , b, c

so,

a= 3

b= 5

c= -2

now, sum of the zeros ( alpha + beta) =-b/a

so,-5/3

now product of zeros (alpha *beta) = c/a

so, it will we -2/3

hope you get it !

Answer:

a) This is the p-value of Z when X = A subtracted by the p-value of Z when X = B.

b) P-value of Z when X = 76 subtracted by the p-value of X = 68.

c) Because the underlying distribution(pulse rates of females) is normal.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean [tex]\mu[/tex], standard deviation [tex]\sigma[/tex].

standard deviation of beats per minute.

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is between A beats per minute and B beats per minute.

This is the p-value of Z when X = A subtracted by the p-value of Z when X = B.

b. If 4 adult females are selected, find the probability that they have pulse rates with a mean between 68 beats per minute and 76 beats per minute.

Sample of 4 means that we have [tex]n = 4, s = \frac{\sigma}{\sqrt{4}} = 0.5\sigma[/tex]

The formula for the z-score is:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{X - \mu}{0.5\sigma}[/tex]

[tex]Z = 2\frac{X - \mu}{\sigma}[/tex]

This probability is the p-value of Z when X = 76 subtracted by the p-value of X = 68.

c. Why can the normal distribution be used in heartbeat even the sample side does not exceed 30?

Because the underlying distribution(pulse rates of females) is normal.