Answer:
hi I don't know the answer but really sorry I did because I needed some points so that I can ask my questions from another people and thank you for free points
Winston deposited $3,294 in a bank account with an annual interest rate of 2.6%. How much interest was earned in 5
years? Round your answer to two decimal places.
Answer:
FV= $3,725.07
Step-by-step explanation:
Giving the following information:
Initial investment (PV)= $3,294
Number of periods (n)= 5 years
Interest rate (i)= 2.6% = 0.026
To calculate the future value (FV), we need to use the following formula:
FV= PV*(1+i)^n
FV= 3,294*(1.026^5)
FV= $3,725.07
What is the equation in slope-intercept from of the line that passes through the point (3, 1) and is parallel to the line represented by y = 2.4x + 6.5?
9) Use the spinner below to answer the following questions
What is the Expected Value of a single spln?
Answer:
is that paper or did you write on the screen?
What's the largest odd number you can make using all four digits 4, 5, 3, 6
Answer:
6543
Step-by-step explanation:
Not much to explain lol
Here,
Odd numbers are 3 and 5.
5>3The largest odd number =6543
The phone company Splint has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount of money per minute used on the phone. If a customer uses 330 minutes, the monthly cost will be $141.5. If the customer uses 890 minutes, the monthly cost will be $337.5.
Required:
a. Find an equation in the form y= mx +b, where x is the number of monthly minutes used and y is the total monthly of the Splint plan.
b. Use your equation to find the total monthly cost if 624 minutes are used
Answer:
a) $141.5 = 330m + b...... Equation 1
$337.5 = 890m + b..... Equation 2
b) $244.4
Step-by-step explanation:
The phone company Splint has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount of money per minute used on the phone. If a customer uses 330 minutes, the monthly cost will be $141.5. If the customer uses 890 minutes, the monthly cost will be $337.5.
Required:
a. Find an equation in the form y= mx +b, where x is the number of monthly minutes used and y is the total monthly of the Splint plan.
If a customer uses 330 minutes, the monthly cost will be $141.5.
y = mx + b
$141.5 = 330m + b
If the customer uses 890 minutes, the monthly cost will be $337.5.
$337.5 = 890m + b
Combining the equations
$141.5 = 330m + b...... Equation 1
$337.5 = 890m + b..... Equation 2
b. Use your equation to find the total monthly cost if 624 minutes are used
Combining the equations
$141.5 = 330m + b...... Equation 1
$337.5 = 890m + b..... Equation 2
We Subtract Equation 2 from 1
-196 = -560m
m = -196/-560
m = 0.35
$337.5 = 890m + b..... Equation 2
$337.5 = 890 × 0.35 + b
$337.5 - 311.5 = b
b = 26
When x = 624
y = 624× m + b
m = 0.35 , b = 26
y = 624 × 0.35 + 26
y = 218.4 + 26
y = $ 244.4
What is the result of 4 divided by one-half? A number line going from 0 to 4. 2 8 12 16
Answer:
2
4/.5 = 2
Therefore, your answer is 2, or A. Hope this helped!
Answer:
the answer is B) 8
Step-by-step explanation:
hope this helped sorry if it didn't and if it's wrong sorry for that also.
What is the quotient in simplest form?
Three-fourths divided by StartFraction 5 Over 16 EndFraction
StartFraction 15 Over 64 EndFraction
StartFraction 15 Over 16 EndFraction
2 and two-fifths
2 and StartFraction 8 Over 20 EndFraction
Answer:
2 and 2/5
Step-by-step explanation:
Trust me on this, also can I have brainlest please? Hope you do well!
2 and two fifths i took the test 6 years ago
If x = 3 + 2√2, then the value of (x - 1/x) is
a) 4√2
b) 2√4
c) 8
Find the value of x.
X
5x - 9
3x + 15
At Green Island Farms the annual Turkey Trot is being held. This year’s contestants are Tom Turkey, Gary Gobbler and Donny Drumstick. The turkeys chase little RC cars loaded with feed. The buzzer sounds and the turkeys are off. Gary Gobbler chases his RC car trying to eat that sweet turkey feed for 15 feet before he manages to side swipe the RC car and knock it on its side. All the feed spills out and Gary Gobbler gobbles it down. That silly turkey happily eats his food for 1.75 seconds. A mouse comes out of the hay bale and tries to join Gary Gobbler in his feasting. But Gary Gobbler is scared of mice so when he sees the mouse he freaks out and tears down the racetrack.
Write a similar story for Tom Turkey making sure to include the different segments of the graph.
Answer:
The company is expected the company will receive
q(x)=2 −2+? please solve this huhu
Answer:
I mean it would just be q(x) = 0
Step-by-step explanation:
Answer: q=0
Step-by-step explanation: Let's solve for q.
qx=2−2
Step 1: Divide both sides by x.
qx
x
=
0
x
q=0
Answer:
q=0
Multiply. Express your answer in simplest form.
5/9 x 3/10
Answer:
5/9 x 3/10 = 15/90 as simplified as 1/6 in fraction form.
5/9 multiplied by 3/10 is equal to 1/6 in its simplest form.
We have,
To multiply fractions, we multiply the numerators together and the denominators together.
The resulting fraction is then simplified to its simplest form.
Let's multiply 5/9 by 3/10:
(5/9) x (3/10) = (5 x 3) / (9 x 10) = 15/90
To simplify the fraction 15/90, we can divide both the numerator and denominator by their greatest common divisor, which is 15:
15/90 = (15 ÷ 15) / (90 ÷ 15) = 1/6
Therefore,
5/9 multiplied by 3/10 is equal to 1/6 in its simplest form.
Learn more about fractions here:
https://brainly.com/question/24370499
#SPJ6
pls help i have pictures pls explain how you get your answer
Answer:
0.75
Step-by-step explanation:
To find the slope of the graph, you have to find the rise and the run by any two points on the graph. (I'm going to calculate using the two blue dots as shown in the picture)
[tex]\frac{rise}{run}[/tex] = [tex]\frac{(-2)-(-5)}{4-0}[/tex]
= [tex]\frac{-2+5}{4}[/tex]
= [tex]\frac{3}{4}[/tex]
= 0.75
A store has a sale with 10% off every item. When you enter the store, you receive a coupon that states that you receive an additional 40% off. Is this equal to a discount? Explain your answer.
The total percent of reduction is _____% , so this __ * is or is not * __equal to a discount.
Step-by-step explanation:
Step one:
We are told that the store offers off 10% of sales, this means that the store is offsetting the price down by 10% hence a price reduction.
Moreso, a coupon is a voucher entitling the holder to a discount off a particular product. the coupon is 40%, hence this is equal to a discount, that is price reduction by 40%.
Step two:
Say the price of an item is $100, a coupon if 40% will entitle the holder to only pay $60, that is
=40/100*100
=0.4*100
=$40 off
= 100-40
=$60
The total percent of reduction 10+40= 50%
This is equal to a discount on the sales price
Miguel has $25. He spends $6.75 on a movie ticket, $3.70 for snacks, and $2.00 for bus fare each way.
How much money does Miguel have left?
Miguel has $_____
left.
Answer:
$12.55
Step-by-step explanation:
25-6.75=18.25
18.25-3.70=14.55
14.55-2=12.55
Miguel has $12.55 left
16.9 and 1.7 and 0.17 and 2.0 added up
Answer:
20.77
Step-by-step explanation:
Answer:
20.77
Step-by-step explanation:
Simplify 16.9+ 1.7 to 18.6
18.6 +0.17+2.0
Simplify 18.6+0.17 to 18.77
18.77+2.0
Simplify.
ANddddd the answer is
20.77
Write the given trinomial if possible as a square of a binomial or as an expression opposite to a square of a binomial: 15ab-9a^2-6 1/4b^2
Answer:
[tex] - \bigg(3a - \frac{5}{2} b) \bigg)^{2} [/tex]
Step-by-step explanation:
[tex]15ab-9a^2-6 \frac{1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{6 \times 4 + 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{24+ 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{25}{4} b^2 \\ \\ = 15ab- (3a)^2- \bigg(\frac{5}{2} b \bigg)^2 \\ \\ = - \{ - 15ab + (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 \} \\ \\ = - \{ (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 - 15ab \} \\ \\ = - \bigg(3a - \frac{5}{2} b \bigg)^{2} [/tex]
Solve the system of equations.
−2x+5y =−35
7x+2y =25
Answer:
The equations have one solution at (5, -5).
Step-by-step explanation:
We are given a system of equations:
[tex]\displaystyle{\left \{ {{-2x+5y=-35} \atop {7x+2y=25}} \right.}[/tex]
This system of equations can be solved in three different ways:
Graphing the equations (method used)Substituting values into the equationsEliminating variables from the equationsGraphing the Equations
We need to solve each equation and place it in slope-intercept form first. Slope-intercept form is [tex]\text{y = mx + b}[/tex].
Equation 1 is [tex]-2x+5y = -35[/tex]. We need to isolate y.
[tex]\displaystyle{-2x + 5y = -35}\\\\5y = 2x - 35\\\\\frac{5y}{5} = \frac{2x - 35}{5}\\\\y = \frac{2}{5}x - 7[/tex]
Equation 1 is now [tex]y=\frac{2}{5}x-7[/tex].
Equation 2 also needs y to be isolated.
[tex]\displaystyle{7x+2y=25}\\\\2y=-7x+25\\\\\frac{2y}{2}=\frac{-7x+25}{2}\\\\y = -\frac{7}{2}x + \frac{25}{2}[/tex]
Equation 2 is now [tex]y=-\frac{7}{2}x+\frac{25}{2}[/tex].
Now, we can graph both of these using a data table and plotting points on the graph. If the two lines intersect at a point, this is a solution for the system of equations.
The table below has unsolved y-values - we need to insert the value of x and solve for y and input these values in the table.
[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & a \\ \cline{1-2} 1 & b \\ \cline{1-2} 2 & c \\ \cline{1-2} 3 & d \\ \cline{1-2} 4 & e \\ \cline{1-2} 5 & f \\ \cline{1-2} \end{array}[/tex]
[tex]\bullet \ \text{For x = 0,}[/tex]
[tex]\displaystyle{y = \frac{2}{5}(0) - 7}\\\\y = 0 - 7\\\\y = -7[/tex]
[tex]\bullet \ \text{For x = 1,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(1)-7}\\\\y=\frac{2}{5}-7\\\\y = -\frac{33}{5}[/tex]
[tex]\bullet \ \text{For x = 2,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(2)-7}\\\\y = \frac{4}{5}-7\\\\y = -\frac{31}{5}[/tex]
[tex]\bullet \ \text{For x = 3,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(3)-7}\\\\y= \frac{6}{5}-7\\\\y=-\frac{29}{5}[/tex]
[tex]\bullet \ \text{For x = 4,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(4)-7}\\\\y = \frac{8}{5}-7\\\\y=-\frac{27}{5}[/tex]
[tex]\bullet \ \text{For x = 5,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(5)-7}\\\\y=2-7\\\\y=-5[/tex]
Now, we can place these values in our table.
[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]
As we can see in our table, the rate of decrease is [tex]-\frac{2}{5}[/tex]. In case we need to determine more values, we can easily either replace x with a new value in the equation or just subtract [tex]-\frac{2}{5}[/tex] from the previous value.
For Equation 2, we need to use the same process. Equation 2 has been resolved to be [tex]y=-\frac{7}{2}x+\frac{25}{2}[/tex]. Therefore, we just use the same process as before to solve for the values.
[tex]\bullet \ \text{For x = 0,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(0)+\frac{25}{2}}\\\\y = 0 + \frac{25}{2}\\\\y = \frac{25}{2}[/tex]
[tex]\bullet \ \text{For x = 1,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(1)+\frac{25}{2}}\\\\y = -\frac{7}{2} + \frac{25}{2}\\\\y = 9[/tex]
[tex]\bullet \ \text{For x = 2,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(2)+\frac{25}{2}}\\\\y = -7+\frac{25}{2}\\\\y = \frac{11}{2}[/tex]
[tex]\bullet \ \text{For x = 3,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(3)+\frac{25}{2}}\\\\y = -\frac{21}{2}+\frac{25}{2}\\\\y = 2[/tex]
[tex]\bullet \ \text{For x = 4,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(4)+\frac{25}{2}}\\\\y=-14+\frac{25}{2}\\\\y = -\frac{3}{2}[/tex]
[tex]\bullet \ \text{For x = 5,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(5)+\frac{25}{2}}\\\\y = -\frac{35}{2}+\frac{25}{2}\\\\y = -5[/tex]
And now, we place these values into the table.
[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]
When we compare our two tables, we can see that we have one similarity - the points are the same at x = 5.
Equation 1 Equation 2
[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex] [tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]
Therefore, using this data, we have one solution at (5, -5).
3) How many counting numbers less than 50 are multiples of both 3 and 5?
Answer: 3 numbers
Step-by-step explanation:
For this questions to be solved, we need to write the multiples of both 3 abd 5 that are less than 50. This will be:
Multiples of 3 = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48
Multiples of 5 = 5, 10, 15, 20, 25, 30, 35, 40, 45.
Common multiples = 15, 30 and 45
Therefore, the numbers that is less than 50 that are multiples of both 3 and 5 are 3 numbers
This question concerns bit strings of length six. These bit strings can be divided up into four types depending on their initial and terminal bit. Thus the types are: 0XXXX0, 0XXXX1, 1XXXX0, 1XXXX1. How many bit strings of length six must you select before you are sure to have at least 6 that are of the same type?
Answer:
We have to choose 21 strings to be sure we have chosen at least 6 strings of the same type.
Step-by-step explanation:
Since the string type is determined by the initial and terminal bits as understood from the question, then the value of the bits between the initial and terminal bits is of no concern to us.
Now, to be sure you have atleast 6 of the same type, we select each string five times. By doing this, we have already selected 20 strings because we have 4 strings there. Now if you choose any of the string one more time, we are certain that we must have chosen atleast 6 strings that are the same. This means we have to choose 21 strings to be sure we have chosen at least 6 strings of the same type.
50 points please help please see image below
Answer:
395.841Step-by-step explanation:
surface area = 2πrh + 2πr²
where r = 7 m radius
h = 2 m
plugin values into the formula
surface area = 2πrh + 2πr²
= 2π (7) 2 + 2π (7)²
= 87.965 + 307.867
= 395.841 m²
Answer:
395.841 m²
Step-by-step explanation:
surface area = 2πrh + 2πr² and r = 7 m radius
h = 2 m
Plugin
2π (7) 2 + 2π (7)²
multiply into itself than add
87.965 + 307.867
add
395.841 m²
Therefore your answer would be 395.841 m²
write the equation of a line perpendicular to y=7 that passes through (2,13)
Level 3
Solve: |x + 2|– 5 = -1
Answer:
x=−6
x=2
Step-by-step explanation:
Combine like terms and use the properties of equality to get the variable on one side of the equal sign and the numbers on the other side. Remember to follow the order of operations.
∣x+2∣−5=−1
Add 5 to both sides of the equation.
∣x+2∣=4
Use the definition of absolute value.
x+2=4
x+2=−4
Subtract 2 from both sides of the equation.
x=2
x=−6
Ryanne is 14. Her brother’s age is three more than half her age. How old is her brother?
Answer:
Her brother is 10 years old
Step-by-step explanation:
14 ÷ 2 = 7
7 + 3 = 10
The answer is 10
You have fit a regression model with two regressors to a data set that has 20 observations. The total sum of squares is 1000 and the model sum of squares is 750.(a) What is the value of R2 for this model?(b) What is the adjusted R2 for this model?(c) What is the value of the F-statistic for testing the significance of regression? What conclusions would you draw about this model if α = 0.05? What if α = 0.01?(d) Suppose that you add a third regressor to the model and as a result, the model sum of squares is now 785. Does it seem to you that adding this factor has improved the model?
Answer:
0.75
0.7205882
25.5
Result is significant at α = 0.01 and α = 0.05
Model improved
Step-by-step explanation:
Given that:
Number of observations (n) = 20
Total sum of squares (SST) = 1000
Model sum of squares (SSR) = 750
1) R² = SSR / SST = 750 / 1000 = 0.75
2.)
Adjusted R² = [(SST - SSR) /(n-k-1)] / (SST ÷ (n - 1))
k = number of regressors = 2
Adj R² = 1 - ((1000 - 750) / (20-2-1)) / (1000 / (20 - 1))
1 - 0.2794117 = 0.7205882
3.) Fstat = (SSR / k) / ((SST - SSR) / (n - k-1))
= (750 /2) / ((1000 - 750) / (20 - 2 - 1))
= 25.5
4.) At α = 0.05
Fα,k,(n - k-1) = F0.05, 2, (20 - 2 - 1) = F0.05,2, 17 = 3.5915 (f distribution calculator)
Fstat > F0.05, 2, (20 - 2 - 1)
25.5 > 3.5915 (Hence result is significant at α = 0.05
At α = 0.01
Fα,k,(n - k-1) = F0.01, 2, (20 - 2 - 1) = F0.01,2, 17 = 6.112 (f distribution calculator)
Fstat > F0.01, 2, (20 - 2 - 1)
25.5 > 6.112 (Hence result is significant at α = 0.01
Adjusted R² if a 3rd regressors is added : k = 3
Adjusted R² = [(SST - SSR) /(n-k-1)] / (SST ÷ (n - 1))
k = number of regressors = 3
SSR = 785
Adj R² = 1 - ((1000 - 785) / (20-3-1)) / (1000 / (20 - 1))
1 - 0.2553125 = 0.7446875
Adjusted R² value is now 0.7446875 which is greater than with 2 regressors,. Hence, adding a third regressors improved the model.
Emile is a long-distance runner. He runs at a constant speed of six miles/hour. His goal is to run nine miles on each practice run, but he normally runs a distance that varies three miles more or less than that. Select the correct answer from each drop-down menu. The equation that can be used to find the minimum and maximum time (in hours) Emile runs is_____. For each practice run, the minimum number of hours Emile runs is______ and the maximum number of hours he runs is ______.
Answer:
[tex]t=\dfrac{9\pm 3}{6}[/tex]
[tex]1\ \text{hour}[/tex]
[tex]2\ \text{hour}[/tex]
Step-by-step explanation:
s = Speed of Emile = 6 miles/hour
d = Distance traveled by Emile = [tex](9\pm 3)\ \text{miles}[/tex]
Time taken to find the minimum and maximum time Emile ran for is
[tex]t=\dfrac{d}{s}\\\Rightarrow t=\dfrac{9\pm 3}{6}[/tex]
The required equation is [tex]t=\dfrac{9\pm 3}{6}[/tex]
The time taken is
[tex]t=\dfrac{9-3}{6}\\\Rightarrow t=\dfrac{6}{6}\\\Rightarrow t=1\ \text{hour}[/tex]
The minimum number of hours Emile runs is 1 hour.
[tex]t=\dfrac{9+3}{6}\\\Rightarrow t=\dfrac{12}{6}\\\Rightarrow t=2\ \text{hour}[/tex]
The maximum number of hours Emile runs is [tex]2\ \text{hour}[/tex].
Answer:
|6x – 9| = 3
1 Hour
2 Hours
Step-by-step explanation:
The equation that can be used to find the minimum and maximum time (in hours) Emile runs is_|6x – 9|= 3_. For each practice run, the minimum number of hours Emile runs is__1 hour_ and the maximum number of hours he runs is _2 hour.
In what quadrant of the complex plane is -30-40i
BD bisects ABC.
Find mZABD, mZCBD, and m ZABC.
A
(3x + 6°
D
B (7x – 18)°C
The answer is 43 because when you multiply 6x6 you get 36 and if you add 6 more you get 42 which is one less that 43
A 0.8-liter bottle of Mexican wine costs 100 pesos. At that price, how much would a halfgallon jug of the same wine cost in dollars? Mexican peso Dollars per foreign: 0.07855 Foreign per dollar: 12.73
Answer:
$11.83
Step-by-step explanation:
1 gallon = 3.785 litres
0.5(1/2gallon) = x liters
x = 0.5 × 3.785 liters
x = 1.89271 liters
0.8 liter = 100 pesos
1.89271 liters = x pesos
x = 1.89271 × 100/0.8
x = 236.58875 pesos
Converting to dollars
1 mexican peso = $0.050
236.58875 pesos = x
x = 236.58875 × $0.050
x = $11.8294375
Approximately = $11.83
A half gallon jug of the same wine cost in dollars $11.83
I need the missing length help (10 points )
Answer:
5.38516480713
Step-by-step explanation:
a^2+b^2=c^2
5^2+2^2=c^2
25+4=c^2
c^2=square root of 29
c=5.38516480713