Answer:
2. A) LNM-ONP
3. B) HI
4. A) GH AND HI
Step-by-step explanation:
2. corresponding sides of similar triangle are proportional and corresponding angles are congruent
3. it seems that triangles are 45-45-90 so GH correspondents with HI
4. JH is geometric mean of line segment making hypotenuse
so JH = [tex]\sqrt{GH*HI}[/tex]
What is the area of the triangle below?
18
Answer:
D. 32 sq. unit s
Step-by-step explanation:
4×18/2=32
if 3x+2y=72 and y=3x, then x whoever solve I give them all my points
Answer:
[tex]x=8[/tex]
[tex]y=24[/tex]
Step-by-step explanation:
3x+2y=72
If y=3x, we plug it into our equation and get:
3x+2×3x=72
3x+6x=72
9x=72
Divide both sides by 9
x=8
Answer:
x = 8
Step-by-step explanation:
3x + 2y = 72
Put y as (3x), and solve for x.
3x + 2(3x) = 72
Multiply 2(3x).
3x + 6x = 72
Add like terms 3x and 6x.
9x = 72
Divide 9 into both sides and isolate x.
x = 72/9
x = 8
The value of x is 8.
Un importante grupo de inversionistas, asociado a una línea de buses interurbanos, está considerando instalar un centro logístico de mantención, a usted le ha encargado la evaluación de este proyecto, considerando un horizonte de 5 años. el estudio técnico del proyecto indica que se requiere disponer de un galpón 1000 m2 dentro de las instalaciones que la empresa ya cuenta, además de un acceso pavimentado con cimientos especiales de 6000 m2. el costo de construcción del galpón es de $ 42 por m2, y el costo de construcción del acceso pavimentado es de $ 32 por cada m2. adicionalmente, se requiere adquirir servidores de punta para realizar el check de los buses antes de comenzar sus recorridos, su costo se estima en $ 630.000, además se necesitan equipos especiales para la revisión de los neumáticos, con un costo de $ 400.000. finalmente, se deberá conseguir un terreno al interior del terminal de buses, con una superficie de 1 m2, con un costo de $50 por m2.
Answer:
Monto total de inicio requerido, de acuerdo con los detalles proporcionados en la pregunta = $ 1,264,000
Total start-up amount required, according to the details provided in the question = $1,264,000
Step-by-step explanation:
- Hay 1000 m² de espacio de almacén para construir a $ 42 por m². Dinero total requerido = 1000 × 42 = $ 42,000.
- Hay 6000 m² de espacio de acceso pavimentado para construir a $ 32 por m². Dinero total requerido = 6000 × 32 = $ 192,000.
- Compra de servidores de última generación para revisar los autobuses antes de comenzar sus recorridos. Costo total = $ 630,000.
- Se necesita comprar equipo especial para revisar los neumáticos. Costo = $ 400,000.
Monto total de inicio requerido, de acuerdo con los detalles proporcionados en la pregunta = 42000 + 192000 + 630000 + 400000 = $ 1,264,000
¡¡¡Espero que esto ayude!!!
English Translation
- There is 1000 m² of warehouse space to construct at $42 per m². Total required money = 1000 × 42 = $42,000
- There is 6000 m² of paved access space to construct at $32 per m². Total money required = 6000 × 32 = $192,000
- Purchase of state-of-the-art servers to check the buses before starting their tours. Total Cost = $630,000
- Purchase of special equipment is needed to check the tires. Cost = $400,000
Total start-up amount required, according to the details provided in the question = 42000 + 192000 + 630000 + 400000 = $1,264,000
Hope this Helps!!!
Help needed ASAP please !!!!
Answer:I believe that it is A but i am not fully sure
Step-by-step explanation:
The exchange rate at a post office is £1 = 1.77 euros How many euros will you get with £280
Answer:
495.6 Euros
Step-by-step explanation:
If 1 pound equals 1.77 euros we can set up a proportion that;
[tex] \frac{1 pound}{1.77 euros} [/tex]
This proportion would be equal to the new amount;
[tex] \frac{280 pounds}{x euros} [/tex]
This means that
[tex] \frac{1 pound}{1.77 euros} = \frac{280 pounds}{ x euros} [/tex]
So;
[tex]280 pounds*1.77 euros / 1 pound[/tex]
Pounds cancel out; and so you have
[tex]280 * 1.77 euros[/tex]
giving you as performed on a calculator;
495.6 euros.
Hope this helps
Answer:
495.6 euros.
Step-by-step explanation:
For each pound we get 1.77 euros so:
it is 280 * 1.77
= 495.6 euros.
g Consider a 1 × n floor to be covered by 1 × 1 tiles that come in three different colors(Blue, Red, Green) and 1 × 2 tiles that come in 2 different colors (orange, white). Find a recurrence relation for the number of the ways the floor can be tiled. (Just find the recurrence relation together with an appropriate number of initial terms. Do not solve the recurrence)
Answer:
[tex]f(n) = 3f(n - 1) + 2f(n - 2)[/tex], if [tex]n \geq 2[/tex].
[tex]f(0) := 1[/tex], [tex]f(1) := 3[/tex]
Step-by-step explanation:
Let [tex]f(n)[/tex] be the number of different tiling of [tex]1 \times n[/tex] floor. We can divide all possible tiling of floor [tex]1 \times n[/tex] into five not overlapping groups by color of last cell in the row (Blue, Red, Green, Orange, White).
The number of tiling [tex]1\times n[/tex] floor such that last cell in row is Blue is exactly f(n - 1) because we can throw away last [tex]1\times 1[/tex] tile and cover the rest [tex]1\times (n - 1)[/tex] cells in f(n - 1) ways. Similarly for Red and Green.
The number of tiling [tex]1\times n[/tex] floor such that last cell in row is Orange is exactly f(n - 2) because we can throw away last [tex]1\times 2[/tex] tile and cover the rest [tex]1\times (n - 2)[/tex] cells in f(n - 2) ways. Similarly for White.
So we get recurrent relation:
[tex]f(n) = 3f(n - 1) + 2f(n - 2)[/tex], if [tex]n \geq 2[/tex].
Now we should define the initial conditions.
[tex]f(0) := 1[/tex] because there is only one empty tiling.
[tex]f(1) := 3[/tex] because we can place Blue, Red or Green tile.
This completely define our recurent sequence because the depth of reccurence is 2.
Brian invests £8300 into his bank account. He receives 1.4% per year compound interest. How much will Brian have after 7 years? Give your answer to the nearest penny where appropriate.
Answer:
The nearest penny will be £9146.6
Step-by-step explanation:
A = P[1 + (r/n)]^(nt)
A = final amount
P = initial principal balance
r = interest rate
n = number of times interest applied per time period
t = number of time periods elapsed
A = 8300 [ 1 + {1.4 / (7*100)}]^(7*7)
A = 8300 [ 1 + {0.002}]^(49)
A= 8300 [ 1.002 ]^(49)
A = 8300 [ 1.102 ]
A = £9146.6
What is Compound Interest (CI) ?
Compound Interest is all about adding interest to principal amount of loan , deposit .
Data on the number of work days missed and the annual salary increase for a company’s employees show that, in general, employees who missed more days of work during the year received smaller raises than those who missed fewer days. A detailed analysis shows that the number of days missed explains 60% of the variation in salary increases. What is the correlation between the number of days missed and salary increase?
Answer:
Step-by-step explanation:
Correlation describes how strongly pairs of given variablé are related. In this case, a detailed analysis that was carried out shows that the number of days missed by employees explains 60% of the variation in salary increases and also impressed upon this fact that employees who missed more days of work during the year received smaller raises than those who missed fewer days.
From the analysis, we can draw a conclusion that there is a correction between days missed and variation in salary increase and that this type of correction is a negative correlation where an increase in the number of days missed will lead to a decrease in the raises awarded to each employee.
Please answer this correctly
Answer:
The range would decrease by 2
Step-by-step explanation:
The range is the difference between the highest number and the lowest number.
8 is the highest number and 1 is the lowest number here, so to find the range we would subtract 1 from 8. 8-1=7
But since 8 is being replaced by 6, we would subtract 1 from that instead.
6-1=5
The range decreased from 7 to 5, so it decreased by 2.
Hope that helps :)
Suppose that, in an experimental setting, 100 students are asked to choose between Gamble A and Gamble B, where: Gamble A: The student will receive $5,100 with a 70 percent probability and $200 with a 30 percent probability. Gamble B: The student will receive $5,100 with a 50 percent probability, $200 with a 25 percent probability, and $0 (nothing) with a 25 percent probability. What is the expected value (EV) of Gamble B
Focus on Gamble B only. Multiply each winnings with their corresponding probabilities.
5100*0.50 = 2550
200*0.25 = 50
0*0.25 = 0
Add up those results: 2550+50+0 = 2600
The expected value of gamble B is $2600
Determine the value(s) of h such that the matrix is the augmented matrix of a consistent linear system. [Start 2 By 3 Matrix 1st Row 1st Column negative 15 2nd Column 21 3rd Column h 2nd Row 1st Column 5 2nd Column negative 7 3rd Column negative 3 EndMatrix ]
Answer: h = 9
Step-by-step explanation: A system of linear equations is consistent when it has at least one solution.
The matrix given is:
[tex]\left[\begin{array}{ccc}-15&21&h\\5&-7&-3\end{array}\right][/tex]
Transform this matrix in a row-echelon form:
[tex]\left[\begin{array}{ccc}-15&21&h\\5&-7&-3\end{array}\right][/tex] [tex]R_{2} = 3R_{2}+R_{1}[/tex] [tex]\left[\begin{array}{ccc}-15&21&h\\0&0&-9+h\end{array}\right][/tex]
For this row-echelon form to have solutions:
-9 + h = 0
h = 9
For this system to be consistent: h = 9.
A group of campers is going to occupy 4 campsites at a campground. There are 14 campsites from which to choose. In how many ways can the campsites be chosen?
There are
possible ways to choose the campsites.
Check
Enter your answer in the answer box and then click Check Answer.
Clear All
All parts showing
Answer:
24024 are the total number of ways of choosing 4 campsites out of 14.
Step-by-step explanation:
We are given that there are a total of 14 campsite out of which 4 campsites are to be chosen.
It is a simple example of selection problem.
Number of ways to choose the first campsite = 14
Now, one campsite is chosen, 13 campsites are left.
Therefore,
Number of ways to choose the second campsite = 13
Now, one more campsite is chosen, 12 campsites are left.
Therefore,
Number of ways to choose the third campsite = 12
Now, one more campsite is chosen, 11 campsites are left.
Therefore,
Number of ways to choose the fourth campsite = 11
So, total number of ways for choosing 4 campsites out of 14:
14 [tex]\times[/tex] 13 [tex]\times[/tex] 12 [tex]\times[/tex] 11 = 24024
Hence, answer is 24024.
A product is introduced to the market. The weekly profit (in dollars) of that product decays exponentially as function of the price that is charged (in dollars) and is given by P ( x ) = 95000 ⋅ e − 0.05 ⋅ x Suppose the price in dollars of that product, x ( t ) , changes over time t (in weeks) as given by x ( t ) = 53 + 0.95 ⋅ t 2 Find the rate that profit changes as a function of time, P ' ( t ) dollars/week How fast is profit changing with respect to time 7 weeks after the introduction. dollars/week
Answer:
1). [tex]P'(t) = (-9025t).e^{-0.05(53+0.95t^2)}[/tex]
2). (-435.36) dollars per week
Step-by-step explanation:
Weekly price decay of the product is represented by the function,
P(x) = [tex]95000.e^{-0.05x}[/tex]
And the price of the product changes over the period of 't' weeks is represented by,
x(t) = [tex]53+0.95t^2[/tex]
Function representing the rate of change in the profit with respect to the time will be represented by,
1). P'(t) = [tex]\frac{dP}{dx}.\frac{dx}{dt}[/tex]
Since, P(x) = [tex]95000.e^{-0.05x}[/tex]
P'(x) = [tex]95000\times (-0.05).e^{-0.05x}[/tex]
= [tex](-4750).e^{-0.05x}[/tex]
Since, x(t) = 53 + 0.95t²
x'(t) = 1.9t
[tex]\frac{dP}{dx}.\frac{dx}{dt}=(-4750).e^{-0.05x}\times (1.9t)[/tex]
By substituting x = 53 + 0.95t²
[tex]\frac{dP}{dx}.\frac{dx}{dt}=(-4750).e^{-0.05(53+0.95t^2)}\times (1.9t)[/tex]
P'(t) = [tex](-9025t).e^{-0.05(53+0.95t^2)}[/tex]
2). For t = 7 weeks,
P'(7) = [tex](-9025\times 7).e^{-0.05(53+0.95(7)^2)}[/tex]
= [tex](-63175).e^{-4.9775}[/tex]
= (-63175)(0.006891)
= (-435.356) dollars per week
≈ (-435.36) dollars per week
For every 1% increase in
unemployment, there is a 2%
decrease in potential GDP. This
creates a GDP gap. What is the GDP
gap when there is 4.5%
unemployment?
Answer:
The GDP gap is 9 % when there is 4.5 % unemployment.
Step-by-step explanation:
The statement shows a reverse relationship, where an increase in unemployment is following by decrease in potential GDP and can be translated into the following rate:
[tex]r = \frac{2\,\% \,GDP}{1\,\% unemp.}[/tex]
The GDP gap at a given increase in unemployment can be estimated by the following expression:
[tex]\frac{g}{u} = r[/tex]
[tex]g = r\cdot u[/tex]
Where:
[tex]r[/tex] - GDP gap-unemployment increase rate, dimensionless.
[tex]u[/tex] - Increase in unemployment rate, measured in percentage.
[tex]g[/tex] - GDP gap, measured in percentage.
If [tex]r = \frac{2\,\% \,GDP}{1\,\% unemp.}[/tex] and [tex]u = 4.5\,\%\,unemp.[/tex], the GDP gap is:
[tex]g = \left(\frac{2\,\%\,GDP}{1\,\%\,unemp.} \right)\cdot (4.5\,\%\,unemp.)[/tex]
[tex]g = 9\,\%\,GDP[/tex]
The GDP gap is 9 % when there is 4.5 % unemployment.
Please answer this correctly. I want genius,expert or ace people to answer this correctly
Answer:
6 times.
Step-by-step explanation:
There is a 1/9 chance you pick the orange one. If you pick 54 times, you can expect to pick the orange marble 6 times.
Solve the linear equality 4x-7 <5
Answer:
X<3
Step-by-step explanation:
4x-7 <5
4x < 5+7
4x < 12
X < 12/4
X < 3
Hope this helps..
Good Luck!
what is the remainder for the synthetic division problem below 3/2-11 7
Answer:
-115.5
Step-by-step explanation:
here's ur answer I hope I was able to help you
The height of seaweed of all plants in a body of water are normally distributed with a mean of 10 cm and a standard deviation of 2 cm. Which length separates the lowest 30% of the means of the plant heights in a sampling distribution of sample size 15 from the highest 70%? Round your answer to the nearest hundredth. Use the z-table below:
0.00 0.01 0.02 0.030.04 0.05 0.06 0.08 0.09 0.07 -0.8 0.212 0.209 0.206 0.203 0.201 0.198 0.195 0.192 0.189 0.187 -0.7 0.242 0.239 0.236 0.233 0.230 0.227 0.224 0.221 0.218 0.215 -0.6 0.274 0.271 0.268 0.264 0.261 0.258 0.255 0.251 0.248 0.245 -0.5 0.309 0.305 0.302 0.298 0.295 0.291 0.288 0.284 0.281 0.278 -0.4 0.345 0.341 0.337 0.334 0.330 0.326 0.323 0.319 0.316 0.312 -0.3 0.382 0.378 0.374 0.3710.367 0.363 0.359 0.356 0.352 0.348
Round the z-score and i to two decimal places. Provide your answer below: Z-Score =
Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: height of seaweed.
X~N(μ;σ²)
μ= 10 cm
σ= 2 cm
You have to find the value of the variable X that separates the bottom 0.30 of the distribution from the top 0.70
P(X≤x)= 0.30
P(X≥x)= 0.70
Using the standard normal distribution you have to find the value of Z that separates the bottom 0.30 from the top 0.70 and then using the formula Z= (X-μ)/σ translate the Z value to the corresponding X value.
P(Z≤z)= 0.30
In the body of the table look for the probability of 0.30 and reach the margins to form the Z value. The mean of the distribution is "0" so below 50% of the distribution you'll find negative values.
z= -0.52
Now you have to clear the value of X:
Z= (X-μ)/σ
Z*σ= X-μ
X= (Z*σ)+μ
X= (-0.52*2)+10= 8.96
The value of seaweed height that divides the bottom 30% from the top 70% is 8.96 cm
I hope this helps!
Answer:-0.53 and 9.72
Step-by-step explanation:
Deanna's Quiz Scores
Use the dot plots to answer the question
has quiz scores that are less variable and
typically higher
80 82 84 86 88 90 92 94 96 98 100
Amy's Quiz Scores
.
.
.
..
80 82 84 86 88 90 92 94 96 98 100
Answer:
1.90.93
2.90.27
Step-by-step explanation:
Answer:
one above correct
Step-by-step explanation:
1st - 90.93
2nd-90.27
Suppose we take repeated random samples of 50 college students from the same population and determine a 95% confidence interval for the mean GPA from each sample. Which of the following statements is true regarding the confidence intervals?
A. The intervals are centered around the population mean GPA.
B. The intervals are centered around the sample mean GPA.
C. 95% of the intervals will contain the sample mean in the long run.
D. 95% of the intervals will contain the population mean in the long run.
Answer:
B. The intervals are centered around the sample mean GPA.
D. 95% of the intervals will contain the population mean in the long run.
Step-by-step explanation:
Confidence interval:
Depends on two things: The sample mean and the margin of error.
Lower end: Sample mean - margin of error
Upper end: Sample mean + margin of error
This means that the intervals are centered around the sample mean.
x% level:
x% of the intervals will contain the population mean in the long run.
So the true statements are:
B. The intervals are centered around the sample mean GPA.
D. 95% of the intervals will contain the population mean in the long run.
Any help would be appreciated
Which statements are true? Check all that apply. All rectangles are squares. All rhombi are parallelograms. All squares are rhombi. All trapezoids are parallelograms. No trapezoid is a rectangle.
Answer:
All rhombi are parallelograms.
All squares are rhombi.
No trapezoid is a rectangle.
A test consists of 580 true or false questions. If the student guesses on each question, what is the standard deviation of the number of correct answers? Round the answer to the nearest hundredth.
Answer:
12.04
Step-by-step explanation:
Because the questions are true and false, that is, there are only two answer options, therefore, you have a success probability = 1/2 = 0.5
The standard deviation can be calculated as follows:
Standard Deviation = (n*p* (1-p)] ^ (1/2)
replacing we have:
SD = (290 * (1-0.5)] ^ (1/2) = 12.04
That is, the standard deviation is 12.04
A bank is reviewing its risk management policies with regards to mortgages. To minimize the risk of lending, the bank wants to compare the typical mortgage owed by their clients against other homebuyers. The average mortgage owed by Americans is $306,500, with a standard deviation of $24,500. Suppose a random sample of 150 Americans is selected. Identify each of the following, rounding your answers to the nearest cent when appropriate:
1. $mu=?
2. $sigma=?
3. $=n=$
4. $mu_{overlinex}=$x=?
5. $sigma_{overlinex}=$x=?
Answer:
1. [tex]$ \mu = \$306,500 $[/tex]
2. [tex]\sigma = \$24,500[/tex]
3. [tex]n = 150[/tex]
4. [tex]$ \mu_{x}= \mu = \$306,500 $[/tex]
5. [tex]\sigma_x = \$ 2,000 \\\\[/tex]
Step-by-step explanation:
The average mortgage owed by Americans is $306,500, with a standard deviation of $24,500.
From the above information, we know that,
The population mean is
[tex]$ \mu = \$306,500 $[/tex]
The population standard deviation is
[tex]\sigma = \$24,500[/tex]
Suppose a random sample of 150 Americans is selected
[tex]n = 150[/tex]
Since the sample size is quite large then according to the central limit theorem, the sample mean is approximately normally distributed.
The sample mean would be the same as the population mean that is
[tex]$ \mu_{x}= \mu = \$306,500 $[/tex]
The sample standard deviation is given by
[tex]\sigma_x = \frac{\sigma}{\sqrt{n} }[/tex]
Where [tex]\sigma[/tex] is the population standard deviation and n is the sample size.
[tex]\sigma_x = \frac{24,500}{\sqrt{150} } \\\\\sigma_x = \$ 2,000 \\\\[/tex]
Therefore, the required parameters are:
1. [tex]$ \mu = \$306,500 $[/tex]
2. [tex]\sigma = \$24,500[/tex]
3. [tex]n = 150[/tex]
4. [tex]$ \mu_{x}= \mu = \$306,500 $[/tex]
5. [tex]\sigma_x = \$ 2,000 \\\\[/tex]
A tree that is 40 feet tall casts a 30 foot shadow. At the same time another tree casts a 20 foot shadow. How tall is the second tree?
Answer:26 2/3 feet
Step-by-step explanation:40/30 = 4/3
(26 2/3) / 20= 4/3
The perimeter of a triangle is 39 feet one side of the triangle is 1 foot longer than the second side the third is 2 feet longer than the second side find the length of each side
Answer:
second side = s first side = s +1 third side = s +2
39 feet = s + (s+1) + (s +2)
39 feet = 3s +3
36 feet = 3s
s = second side = 12 feet
first side = 13 feet
third side = 14 feet
Step-by-step explanation:
Engineers want to design passenger seats in commercial aircraft so that they are wide enough to fit 95 percent of adult men. Assume that adult men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1.1 inches. Find the 95th percentile of the hip breadth of adult men. Round your answer to one decimal place; add a trailing zero as needed. The 95th percentile of the hip breadth of adult men is [HipBreadth] inches.
Answer:
[tex]z=1.64<\frac{a-14.4}{1.1}[/tex]
And if we solve for a we got
[tex]a=14.4 +1.64*1.1=16.204[/tex]
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(14.4,1.1)[/tex]
Where [tex]\mu=14.4[/tex] and [tex]\sigma=1.1[/tex]
For this part we want to find a value a, such that we satisfy this condition:
[tex]P(X>a)=0.05[/tex] (a)
[tex]P(X<a)=0.95[/tex] (b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
[tex]P(X<a)=P(\frac{X-\mu}{\sigma}<\frac{a-\mu}{\sigma})=0.95[/tex]
[tex]P(z<\frac{a-\mu}{\sigma})=0.95[/tex]
And we have:
[tex]z=1.64<\frac{a-14.4}{1.1}[/tex]
And if we solve for a we got
[tex]a=14.4 +1.64*1.1=16.204[/tex]
The 95th percentile of the hip breadth of adult men is 16.2 inches.
At which root does the graph of f(x) = (x – 5)3(x + 2)2 touch the x-axis?
-5
-2
2
5
Answer:
-2
Step-by-step explanation:
the power is 2 for (x+2) so it will touch the axis
thepower of (x-5) is 3 so it will cross the axis
the correct answer is then -2
hope this helps
Answer:
B. -2
Step-by-step explanation:
What is the slope of the line below
Answer:
C. [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
You can use the formula to find the slope: [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
(-1.5, 1.5) & (1.5, 0)
[tex]\frac{0-(-1.5)}{1.5-(-1.5)} =\\\\\frac{0+1.5}{1.5+1.5} =\\\\\frac{1.5}{3} =\\\\\frac{1}{2}[/tex]
The slope is [tex]\frac{1}{2}[/tex]
An aircraft seam requires 30 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with the same probability. (Round your answers to four decimal places.)
(a) If 21% of all seams need reworking, what is the probability that a rivet is defective?
(b) How small should the probability of a defective rivet be to ensure that only 11% of all seams need reworking?
Answer:
a. 0.00783
b. 0.003876
Step-by-step explanation:
The computation is shown below;
a. The probability for the rivet to be defective is
Let us assume A is the event for seam failure and B would be event for rivets failure
Now
a) [tex]P[A] = 1 - P[B']^{30}[/tex]
[tex]0.21 = 1 - P[B']^{30}[/tex]
[tex]0.79 = P[B']^{30}[/tex]
[tex]P[B'] = 0.79^{\frac{1}{30}}[/tex]
P[B'] = 0.99217
P[B] = 1 - P[B']
= 0.00783
b) Now the Next one is
[tex]0.08 = 1 - P[B']^{25}[/tex]
[tex]0.89 =P[B']^{30}[/tex]
[tex]P[B'] = 0.89^{(\frac{1}{30})}[/tex]
= 0.99612
So,
P[B] is
= 1 - P[B']
= 0.003876
We simply applied the above formula so that each one part could be calculated i.e the probabilities of the given question