Un niño de 9 años se encuentra balanceándose en un columpio, si el columpio se encuentra en equilibrio y la cadena que soporta la canastilla donde se sienta el niño tiene un peso de 15Kg y este se encuentra a 42°con respecto a la perpendicular. Determine la tensión de la cadena y la fuerza con la que es empujado si el niño pesa 35Kg.

Answers

Answer 1

Answer:

Part A

La tensión en la cadena es de aproximadamente 364,14 Newtons

Part B

La fuerza con la que se empuja el columpio es de aproximadamente 327,874 Newtons

Explanation:

Parte A

Los parámetros dados son;

La masa del asiento en el que se sienta el niño = 15 kg

La inclinación de la cadena de la vertical, θ = 42 °

La masa del niño = 35 kg

La aceleración debida a la gravedad, g = 9,8 m / s²

La tensión en la cuerda, 'T', se da de la siguiente manera;

T = m · g · cos (θ)

Dónde;

m = m₁ + m₂ = 15 kg + 35 kg = 50 kg

g = La aceleración debida a la gravedad = 9,8 m / s²

θ = 42 °

Por lo tanto;

T = 50 kg × 9,8 m / s² × cos (42 °) ≈ 364,14 N

La tensión en la cadena, T ≈ 364.14 N

Parte B

La fuerza con la que se empuja el columpio, 'F', se da de la siguiente manera;

F = m · g · sin (θ)

Por lo tanto;

F ≈ 50 kg × 9,8 m / s² × sen (42 °) ≈ 327,874 N

La fuerza con la que se empuja el columpio, F ≈ 327,874 N.


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