Answer:
a) La velocidad del bloque cuando llega al resorte es de aproximadamente 9,9 m / s
b) La distancia a la que se comprime el resorte es de aproximadamente 0,86 m
c) La velocidad con la que el resorte expulsa el bloque es de aproximadamente 9,9 m / s
d) La altura que alcanza el bloque es de 5 metros.
e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción
Explanation:
a) Los parámetros dados del bloque son;
La masa del bloque, m = 3 kg
La altura a la que se coloca el bloque, h = 5 m
La constante de resorte, k = 400 N / m
La aceleración debida a la gravedad, g = 9,8 m / s²
La energía potencial de un cuerpo, P.E. = m · g · h
Por tanto, la energía potencial inicial del bloque, P.E. se da como sigue;
P.E. = 3 kg × 9,8 m / s² × 5 m = 147 julios
P.E. = 147 julios
La energía cinética del bloque al pie de la rampa, K.E. = 1/2 · m · v²
Dónde;
v = La velocidad del bloque cuando llega al resorte
Por lo tanto, para el bloque dado tenemos;
K.E. = 1/2 · m · v² = 1/2 × 3 kg × v²
Por el principio de conservación de la energía, tenemos;
El PE. del bloque en reposo a una altura de 5 m = La energía cinética al pie de la rampa. K.E.
∴ P.E. = K.E.
147 J = 1/2 × 3 kg × v²
v² = 147 J / (1/2 × 3 kg) = 98 m² / s²
v = √ (98 m² / s²) = 7 · √2 m / s
v = 7 · √2 m / s ≈ 9,9 m / s
b) La energía recibida por el resorte comprimido, E = 1/2 · k · x²
Dónde;
k = La constante del resorte = 400 N / m
x = La distancia a la que se comprime el resorte
Por el principio de conservación de la energía, tenemos;
La energía recibida por el resorte comprimido, E = La energía potencial inicial del resorte, P.E.
∴ E = 1/2 · k · x² = P.E.
De lo que tenemos;
E = 1/2 × 400 N / m × x² = 147 julios
x² = 147 Julios / (1/2 × 400 N / m) = 0,735 m²
x = √ (0,735 m²) = 0,7 · √ (3/2) m ≈ 0,86 m
La distancia a la que se comprime el resorte = x ≈ 0.86 m
c) La velocidad con la que el resorte expulsa el bloque se indica a continuación;
La energía en el resorte = 1/2 · k · x² = La energía cinética dada al bloque, 1/2 · m · v²
∴ 1/2 · k · x² = 1/2 · m · v²
∴ La velocidad con la que el bloque es expulsado por el resorte, v = La velocidad con la que el bloque llega al resorte = 7 · √2 m / s
La velocidad con la que el resorte expulsa el bloque, v = 7 · √2 m / s ≈ 9,9 m / s
d) La altura que alcanza el bloque también viene dada por la siguiente relación anterior;
P.E. = K.E.
∴ m · g · h = 1/2 · m · v²
v = 7 · √2 m / s
De donde tenemos h = La altura inicial del bloque en la rampa = 5 metros
e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción porque se utilizará energía para superar la fuerza de fricción
a) La velocidad final del bloque es aproximadamente 9.903 metros por segundo.
b) El resorte se deforma 0.858 metros.
c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.
d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).
a) Conforme a la situación de este problema, la energía cinética traslacional final ([tex]K[/tex]), en joules, es igual a la energía potencial gravitacional inicial ([tex]U[/tex]), en joules.
[tex]U = K[/tex] (1)
Por las definiciones de las energías cinética traslacional y potencial gravitacional expandimos la ecuación anterior:
[tex]m\cdot g\cdot h = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (1)
Ahora despejamos la velocidad de esa ecuación:
[tex]v = \sqrt{2\cdot g\cdot h}[/tex]
Donde:
[tex]m[/tex] - Masa del bloque, en kilogramos.[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.[tex]h[/tex] - Altura inicial del bloque, en metros.[tex]v[/tex] - Velocidad final del bloque, en metros por segundo.Si sabemos que [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] y [tex]h = 5\,m[/tex], entonces la velocidad final del bloque es:
[tex]v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}[/tex]
[tex]v\approx 9.903\,\frac{m}{s}[/tex]
La velocidad final del bloque es aproximadamente 9.903 metros por segundo.
b) Por el principio de conservación de la energía, la energía cinética traslacional inicial es igual a la energía potencial elástica final, cuyas fórmula es la siguiente:
[tex]\frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (2)
Where:
[tex]k[/tex] - Constante de resorte, en newtons por metro.[tex]x[/tex] - Deformación del resorte, en metros.Ahora despejamos la deformación del resorte:
[tex]x = \sqrt{\frac{m}{k} }\cdot v[/tex] (3)
Si sabemos con [tex]k = 400\,\frac{N}{m}[/tex], [tex]m = 3\,kg[/tex] y [tex]v \approx 9.903\,\frac{m}{s}[/tex], entonces la deformación del resorte es:
[tex]x = \sqrt{\frac{3\,kg }{400\,\frac{N}{m} } }\cdot \left(9.903\,\frac{m}{s} \right)[/tex]
[tex]x \approx 0.858\,m[/tex]
El resorte se deforma 0.858 metros.
c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.
d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).
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PHYSICS physics help me pls!
the question is not clear for me the mass of the word and the pivot the artist as the counterweight of the end we calculate the mass of the counterweight sorry
Answer:
calculate mass of the counterweight?
Explanation:
Was Michael Jean Cazabon a local or regional artist?
Answer:
artist
Explanation:
100%
Look carefully at the diagram below, which shows two cells connected in series. What will the reading on the ammeter be?
Enter your answer as a number
Submit
1.5v
1.5v
Answer:
The reading on the ammeter is 0 ampere
Explanation:
When two or more voltage sources are arranged in series as shown in the diagram, the resultant voltage is given by the sum of the voltages by taking into consideration the direction of the polarities of the voltage sources which can be either series aiding voltage source configuration or series opposing voltage source configuration
In the series aiding voltage source configuration, the positive terminal of one voltage source is connected to the negative terminal of the next voltage source such that the current flows in the same direction in both sources of the voltage in the circuit and the resultant voltage source is given by adding the individual voltage sources together
However, in the series opposing voltage source configuration, the positive terminal of one voltage source is connected to the positive terminal of the next voltage source such that the current flows in opposite direction in both voltage sources and the voltage across the entire voltage sources is given by finding the sum of the differences of the opposing voltage sources
The arrangement of the voltage sources in the question is one of a series opposing voltage configuration and the voltage across both voltage sources is given by subtracting one (usually the smaller voltage source) from the other as follows;
[tex]V_{(series \ opposing)}[/tex] = V₁ - V₂
Where;
V₁ = The voltage of one (usually the larger) of the voltage source = 1.5 V
V₂ = The voltage of the other voltage source = 1.5 V
Therefore;
[tex]V_{(series \ opposing)}[/tex] = 1.5 V - 1.5 V = 0 V
The reading on the ammeter = The current in the circuit, 'I', which is given as follows;
V = I·R
∴ I = V/R = 0/R = 0
I = 0 A (ampere)
The reading on the ammeter = I = 0 A (Current cannot flow without the presence of a voltage).
b) The man has a mass of 85 kg. Gravitational field strength = 9.8 N/kg.
Calculate the weight of the man. Use the equation: weight = mass x
gravitational field strength
Answer:
mass× weight
85×9.5=807.5 kg
2. A bullet was shot by a gun with an initial speed of 260 m/s and is fired at an angle of 30 to the ground. a. How much is the value Vy at the top of the bullet's trajectory? b. Calculate the time taken by the bullet to reach its maximum altitude. c. Deduce the total time taken by the bullet in the air. d. Calculate the range of the bullet.
Answer:
Explanation:
a )
the value Vy at the top of the bullet's trajectory will be zero . At the top , only the horizontal component Vx will exist .
b )
At the top Vy = 0
initial velocity will have vertical component = 260 sin30 = 130 m /s
acceleration = - g = - 9.8
v = u - gt
o = 130 - 9.8 t
t = 13.26 s .
c )
Total time = Time of ascent + time of descent
= 13.26 + 13.26 = 26.52 s
d )
Range R = u² sin2Ф / g , where u is initial velocity , Ф is angle of throw , g is acceleration due to gravity .
R = 260² sin 2 x 30 / 9.8
= 5973.8 m .
5 points
What did Alfred Wegener think happens during Continental Drift?
A. Continents move
B. The mantle warms
C. Convection Stops
D. Continents freeze
Answer:
Continents move
Explanation:
The cadmium in the control rods slows down a nuclear fission reaction by absorbing neutrons.
Please select the best answer from the choices provided
T
F
answer:
true
explanation:
cadmium is used during controlled reaction to produce energycredits: https://brainly.in/question/6969690Answer:
True!
Explanation:
cadmium is being used during controlled reaction which creates the energy!
I took this test! :3
Is potential energy higher at the equilibrium position?
Which correctly describes have any giveaway on the electromagnetic spectrum depends on the wavelength and frequency
Answer:
c = λ f
Explanation:
In the electromagnetic spectrum, the wavelength and frequency of a specific radiation are related to the speed of the wave, which in this case the speed of light
c = λ f
where c is the speed of light, λ the wavelength and f the frequency of radiation
If you walk up a set of steps empty handed and walk up the same set of steps holding a flower pot in thesame amount of time. Which requires more work?
a.) empty handed b.) holding flower pot c.) same
Explanation:
I think holding a flower pot. more energy will be needed
please help me answer this
Answer:
W>R...............
Explanation:
.........................
Yes
An old lorry is 20% efficient at converting the
chemical energy in the diesel into useful
mechanical energy. How many joules of
mechanical energy are produced when 600
joules of chemical energy have been used by
the engine?
Answer:
The amount of mechanical energy produced by the old lorry when 600 Joules of chemical energy have been used by the engine, M.E. is 120 Joules
Explanation:
The question is a word problem on the relationship between energy efficiency and energy consumption
The given parameters of the old lorry are;
The chemical energy to mechanical energy conversion efficiency of the old lorry = 20%
The amount of chemical energy used by the engine = 600 joules
Let 'M.E.' represent the amount of mechanical energy produced by the old lorry, we have;
[tex]Energy \ Efficiency = \dfrac{Energy \ produced }{Total \ Energy \ Taken \ In \ or \ Used} \times 100[/tex]
Therefore, the for the old lorry, we have;
[tex]20\% = \dfrac{M.E. \ Produced}{600 \ Joules} \times 100[/tex]
∴ M.E. Produced = 20/100 × 600 J = 120 J
The amount of mechanical energy produced by the old lorry when 600 Joules of chemical energy have been used by the engine, M.E. = 120 Joules
5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
low-friction wheels and as the bullet struck the target, the target with
bullet embedded bullet sped off with a velocity of 6.0 ms.
Calculate the velocity of the bullet just before it hit the stationary
target.
Answer:
306 m/s
Explanation:
Law of conservation of momentum
m1v1 + m2v2 = (m1+m2)vf
m1 is the bullet's mass so it is 0.1 kg
v1 is what we're trying to solve
m2 is the target's mass so it is 5.0 kg
v2 is the targets velocity, and since it was stationary, its velocity is zero
vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s
plugging in, we get
(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)
(0.1)(v1) + 0 = 30.6
(0.1)(v1) = 30.6
v1 = 306 m/s
The initial velocity of the bullet can be determined from the total momentum of the system. The velocity of the bullet was 306 m/s.
What is momentum ?Momentum of a body is the product of its mass and velocity. For a collision, the momentum before and after collision will be the same for the colliding system.
Let m1 and m2 be the masses and u be the initial velocity and v is the final velocity.
then, m1 u1 + m2 u2 = m1 v1 + m2 v2.
Given m1 = 5 kg
m2 = 0.1 kg
The velocity of the combined mass v = 6 m/s.
The momentum of the target is zero since it was stationary.
(0.1 × u1) = (0.1 + 5)6 m/s
(0.1 × u1) = 30.6 m/s
then u1 = 30.6/0.1 = 306 m/s
Therefore, the velocity of the bullet before hitting was 306 m/s.
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Why do sex cells contain only half the number of chromosomes needed for offspring? Explain
Answer:
None, egg cells don't have chromosomes. No, sex cells do have chromosomes. Meiosis reduces chromosome number so that sex cells (eggs and sperm) have a half set of chromosomes–one homolog of each pair. This is the haploid number.
a clay ball with a mass of 0.35 kg hits another 0.35 kg ball at rest and the two stick together. The first balls intial speed us 4.2m/s.
What are the balls final speed?
Answer:
4.2 m/s
the balls final speed is V (m/s)
because the clay ball hits another and the two stick together
=> 0,35.4,2 + 0,35.4,2 = (0,35 + 0,35).V
<=> 2,94 = 0,7V
<=> V = 2,94/0,7 = 4,2
For a clay ball with a mass of 0.35 kg, the ball's final speed is mathematically given as
V2= 4.2
What is the balls final speed?Question Parameter(s):
A clay ball with a mass of 0.35 kg
Hits another 0.35 kg ball at rest and the two stick together.
The first ball's initial speed is 4.2m/s.
Generally, the equation for the conservation of momentum is mathematically given as
M1v1=m2v2
Therefore
0.35*4.2 + 0.3*5.4.2 = (0.35 + 0.35)*V
2,94 = 0,.7V
V2 = 2.94/0.7
V2 = 4.2
In conclusion
V2= 4.2
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PLS ANSWER FAST WILL GIVE BRAINLY!! BUT ONLY IF YOU KNOW!!
Fill in the blanks
Cobalt has 27 protons, 32 neutrons and 27 electrons. What is it's atomic mass?
Answer:
58.933195 u or 59 u
Explanation:
Atomic mass of cobalt is 58.933195 u
Which two statements are true about the wave shown?
A. The wave could be transmitting light. B. The wave is a transverse wave.
C. The wave is a mechanical wave.
D. The wave could be transmitting sound.
Answer:
c and d
Explanation:
The wave shown in the figure is Sound waves. The sound wave is a mechanical wave. Hence, options C and D are correct.
What are sound waves?Sound is traveled by means of vibrations of particles in the medium. Sound waves require a medium to propagate. The energy propagation by means of adiabatic loading and unloading is called sound or acoustic waves.
The sound waves produce compression and rarefaction in the air. The sound waves are called Longitudinal waves because the direction of propagation is parallel to the vibration of particles.
Sound waves are considered only as waves because they exhibit a wave nature. Light has both properties of wave and particle. Light is an electromagnetic wave and it is transverse in nature.
The sound waves require a medium like air, water, solids, etc for propagation. Hence it is called Mechanical waves. Light waves do not require a medium to propagate. From the given wave pattern, it exhibits the property of sound waves.
Hence, the correct option is C) the wave is a mechanical wave, and D) the wave could be transmitting sound.
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Why is it important that a finger be wet
before it is touched to a hot clothes iron?
Why is it important that your finger be wet if you intend to touch it briefly to a hot clothes iron to test its temperature. If your finger is wet, some of the heat transmitted to your finger will be given to the water which has a high specific heat capacity and also a larger latent heat of vaporization.
#carryonlearning
Una fuente luminosa de 75 W consume 75W de potencia electrica. Suponga que toda la energía se transforma en luz emitida de 600 nm de longitud de onda. a) Calcule la frecuencia de luz emitida b) ¿Cuántos fotones por segundo emite la fuente? C) ¿Son iguales las respuestas de de los incisos a) y b)?
Answer:
a) La frecuencia de la luz emitida es 5,0 × 10¹⁴ Hz
b) El número de fotones por segundo que emite la fuente es 2.26380924 × 10²⁰ fotones
c) Las respuestas del inciso a) yb) son diferentes
Explanation:
Los parámetros dados son;
La potencia de la fuente de luz, P = 75 W
La energía consumida cada segundo por la fuente de luz, E = 75 J
La longitud de onda de la luz emitida, λ = 600 nm
a) La relación entre la energía y la frecuencia de la luz se da a continuación;
υ = c/λ
E = n·h·υ
[tex]E = \dfrac{h \times c}{\lambda}[/tex]
Dónde;
E = La energía consumida por segundo = 75 J
h = constante de Planck ≈ 6.626 × 10⁻³⁴ J · s
υ = La frecuencia de la luz
λ = La longitud de onda de la luz = 600 nm
c = La velocidad de la luz, c = 3.0 × 10⁸ m / s
Por lo tanto, tenemos;
υ = c / λ = 3,0 × 10⁸ m / s / (600 nm) = 5,0 × 10¹⁴ Hz
∴ La frecuencia de la luz emitida, υ = 5.0 × 10¹⁴ Hz
b) El número de fotones por segundo que emite la fuente, 'n', se da como sigue;
n = E / (h · υ) = 75 J / (6.626 × 10⁻³⁴ J · s × 5.0 × 10¹⁴ Hz) = 2.26380924 × 10²⁰
El número de fotones por segundo que emite la fuente = n = 2.26380924 × 10²⁰ fotones
c) Las respuestas del inciso a) yb) son diferentes
5.0 × 10¹⁴ Hz ≠ 2.26380924 × 10²⁰ fotones.
what is rickrolling
...
Answer:
"a prank and an Internet meme involving an unexpected appearance of the music video for the 1987 Rick Astley song "Never Gonna Give You Up". The meme is a type of bait and switch using a disguised hyperlink that leads to the music video."
Explanation: G O O G L E
Answer:
here:Rick Astley - Never Gonna Give You Up (Official Music Video)
Explanation:
Can someone pls help me with these questions I’ll give brainliest
Answer:
1= ionic bond
2 =covalent bonding
Explanation:
can answer the others sorry
A solar eclipse may occur when:
A. when the moon is 3rd quarter phase
B. when the moon is full
C. when the moon is at 1st quarter phase
D. when the moon is new
A car of mass 150 kg is riding down at constant velocity What is the friction force?
Answer:
I think it's b
Explanation:
friction is the opposite direction of the object do it's definitely left something
Using a box covered with graph paper allows you to simulate which aspect of a car crash?
Answer:
a computer modeling
Explanation:
Which type of information about rattlesnakes does the bar graph above show?
Answer:
Variation
Explanation:
The planet Mercury travels around the Sun with a mean orbital radius of 5.8x100 m. The mass of the Sun is 1.99x1030 kg. Use Newton's version of Kepler's third law to determine how long it takes Mercury to orbit the Sun. Give your answer in seconds.
The time taken for Planet Mercury to orbit around the sun is determined as 1.21 x 10⁶ s.
Period of the planet mercury
The time of motion of the planet around the sun is calculated as follows;
[tex]T = 2\pi \sqrt{\frac{a^3}{Gm} } \\\\[/tex]
where;
a is the mean radius of the planet MercuryG is universal gravitation constantM is mass of the sun[tex]T = 2\pi \sqrt{\frac{(5.8 \times 10^{10})^3}{(6.67 \times 10^{-11})(1.99\times 10^{30})} } \\\\T = 1.21 \times 10^6 \ s[/tex]
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how could you use Newton's Second Law to study forces?
Answer:
F = ma or force is equal to mass times acceleration.
Explanation:
What is the difference between revolution and rotation, in terms of Earth's movement?
In revolution, the earth revolves around the sun. In rotation, the earth rotates about its own axis.
1 HELP
----
A box is connected to a spring is extended to 200mm, and it stored 3578J of energy. Find the
force.
Answer:
The force applied to the spring is 35,780 N
Explanation:
Given;
extension of the spring, x = 200 mm = 0.2 m
energy stored in the spring, E = 3578 J
The force applied to the spring is calculated as;
E = ¹/₂Fx
where;
F is the applied force
F = 2E/x
F = ( 2 x 3578) / 0.2
F = 35,780 N
Therefore, the force applied to the spring is 35,780 N
(c) What would the angle of reflection be if the incident ray
was 40° from the reflecting mirror surface?
Answer:
So, if a wave hits a mirror at an angle of 36°, it will be reflected at the same angle (36°). ... An incident ray of light hits a plane mirror at an angle and is reflected back off it. The angle of reflection is equal to the angle of incidence. Both angles are measured from the normal.
Explanation: