Answer:
see answer below
Explanation:
Before we do any kind of calculation, we need to convert the proper units of the exercise. All the units of distance must be in meters, so, let's change distance of the wire, and the magnetic field to meters:
Separation between the wires are 2.5 mm:
2.5 mm * (1 m / 1000 mm) = 0.0025 m
The distance of P from the bottom of the wires is 37 cm:
37 cm * (1 m/100 cm) = 0.37 m
The distance of P from the top of the wires is just the sum of the two distances:
R = 0.37 + 0.0025 = 0.3725 m
Now that we have the distance, we can determine the magnetic field, using the following expression:
B = B(bottom) - B(top) or just B₂ - B₁
And B = μ₀ I / 2πR
Replacing in the above expression we have:
B = μ₀ I / 2π ( 1/R₂ - 1/R₁)
Now we can determine the magnetic field:
B = (4πx10⁻⁷ * 10 / 2π) (1/0.37 - 1/0.3725)
B = 3.63x10⁻⁸ TWhich means that the magnetic field is out of the page.
Hope this helps
A straight wire in a magnetic field experiences a force of 0.026 N when the current in the wire is 1.5 A. The current in the wire is changed, and the wire experiences a force of 0.063 N as a result. What is the new current
Answer:
the new current on the wire is 3.64 A.
Explanation:
Given;
first force on the wire, F₁ = 0.026 N
second force on the wire, F₂ = 0.063 N
first current on the wire, I₁ = 1.5 A
second current on the wire, I₂ = ?
The force on a current carrying conductor placed in a magnetic field is given as;
[tex]F = BIL(sin \theta)\\\\[/tex]
F ∝ I
[tex]\frac{F_1}{I_1} = \frac{F_2}{I_2} \\\\I_2 = \frac{F_2I_1}{F_1} \\\\I_2 = \frac{0.063\ \times\ 1.5 }{0.026} \\\\I_2 = 3.64 \ A[/tex]
Therefore, the new current on the wire is 3.64 A.
On a sunny day, a rooftop solar panel delivers 60 W of power to the house at an emf of 17 V. How much current flows through the panel
Answer:
3.53 amps
Explanation:
Given data
Power= 60W
Voltage= 17V
The expression relating current, power, and voltage is
P= IV
substitute
60= I*17
I= 60/17
I= 3.53 amps
Hence the current that flows is 3.53 amps
which form of energy is an example of kinetic energy
Answer:
1. realizing of arrow
2. kicking of ball
3. punching the punching bag
The average marathon runner can complete the 42.2-km distance of the marathon in 3 h and 30 min. If the runner's mass is 85 kg, what is the runner's average kinetic energy during the run
Answer:
the runner's average kinetic energy during the run is 476.96 J.
Explanation:
Given;
mass of the runner, m = 85 kg
distance covered by the runner, d = 42.2 km = 42,200 m
time to complete the race, t = 3 hours 30 mins = (3 x 3600s) + (30 x 60s)
= 12,600 s
The speed of the runner, v = d/t
v = 42,200 / 12,600
v = 3.35 m/s
The runner's average kinetic energy during the run is calculated as;
K.E = ¹/₂mv²
K.E = ¹/₂ × 85 × (3.35)²
K.E = 476.96 J
Therefore, the runner's average kinetic energy during the run is 476.96 J.
3. Batteries create electricity and generators create electricity. *
True
False
Two coils have the same number of circular turns and carry the same current. Each rotates in a magnetic field acting perpendicularly to its axis of rotation. Coil 1 has a radius of 4.5 cm and rotates in a 0.21-T field. Coil 2 rotates in a 0.39-T field. Each coil experiences the same maximum torque. What is the radius (in cm) of coil 2
Answer:
Explanation:
Torque acting on a coil in a magnetic field = MBsinθ where M is magnetic moment , B is magnetic field and θ is inclination of the normal to coil with direction of field.
For maximum torque sinθ = 1
Maximum torque = MB
M = NIA where N is no of turns , I is current and A is area of the coil
Maximum torque = NIAB
As maximum torque is same
N₁I₁A₁B₁ = N₂I₂A₂B₂
N₁ = N₂ , I₁ = I₂
A₁B₁ = A₂B₂
π R₁² B₁ = π R₂² B₂
4.5² x .21 = R₂² x .39
R₂² = 10.9
R₂ = 3.3 cm .
The skater lowers her arms as shown in the adjacent
figure decreasing her radius to 0.15 m. Find her new speed.
Answer:
is there more?
Explanation:
can you please tell me what this is
Answer:
200000 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) of roller coaster = 1000 Kg
Velocity (v) of roller coaster = 20 m/s
Kinetic energy (KE) =?
Kinetic energy is simply defined as the energy possess by an object in motion. Mathematically, it can be expressed as:
KE = ½mv²
Where
KE => is the kinetic energy.
m =>is the mass of the object
V => it the velocity of the object.
With the above formula, we can obtain the kinetic energy of the roller coaster as follow:
Mass (m) of roller coaster = 1000 Kg
Velocity (v) of roller coaster = 20 m/s
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 1000 × 20²
KE = 500 × 400
KE = 200000 J
Therefore, the kinetic energy of the roller coaster is 200000 J.