Answer:
15
Step-by-step explanation:
one side is equal to 5. So 5 ×3
find the initial value seventeen years from now, Ms. speedis car, which is depreciating at 20% per year, will be worth $500
Answer:
Around 22200 dollars
Step-by-step explanation:
Firstly, it was depreciating 20% per year for 17 years. So, if we were to go back in time, it would be appreciating by 25%. Therefore, after doing the plugging in, it is 500 * 1.25^17. The initial value is around 22200. It is around 22204, to be exact.
-25 = 1/2 (10x - 2) + 3x what is x?
Answer:
x=[tex]-\frac{1+2i\sqrt{31} }{5}[/tex]
Step-by-step explanation:
Answer:
-3
Step-by-step explanation:
−25= [tex]\frac{1}{2}[/tex] (10x−2)+3x
−25=([tex]\frac{1}{2}[/tex])(10x)+( [tex]\frac{1}{2}[/tex] )(−2)+3x(Distribute)
−25=5x+−1+3x
−25=(5x+3x)+(−1)(Combine Like Terms)
−25=8x+−1
−25=8x−1
Step 2: Flip the equation.
8x−1=−25
Step 3: Add 1 to both sides.
8x−1+1=−25+1
8x=−24
Step 4: Divide both sides by 8.
8x ÷ 8 = −24 ÷ 8
4(5x – 9) = -2(x + 7) solve and justify each step
Step-by-step explanation:
4(5x-9)=-2(x+7)
4*5x-4*9=-2*x-2*7
20x-36=-2x-14
20x+2x=-14+36
22x=22
x=22/22
x=1
Whats a prime number can you guys give me some examples pls
2 3 5 7 11 13 17 19 23
29 31 37 41 43 47 53 59 61 67
71 73 79 83 89 97 101 103 107 109
113 127 131 137 139 149 151 157 163 167
173 179 181 191 193 197 199 211 223 227
229 233 239 241 251 257 263 269 271 277
281 283 293 307 311 313 317 331 337 347
349 353 359 367 373 379 383 389 397 401
409 419 421 431 433 439 443 449 457 461
463 467 479 487 491 499 503 509 521 523
541 547 557 563 569 571 577 587 593 599
601 607 613 617 619 631 641 643 647 653
659 661 673 677 683 691 701 709 719 727
733 739 743 751 757 761 769 773 787 797
809 811 821 823 827 829 839 853 857 859
863 877 881 883 887 907 911 919 929 937
941 947 953 967 971 977 983 991 997 Thats all the prime numbers between 1 and 1000 Prime numbers can only be multiplied by its self ad one
What is 180(n-2)=s when solving for N
Answer:
n = s/180 +2
Step-by-step explanation:
180(n-2)=s
Distribute
180n - 360 =s
Add 360 to each side
180n -360+360 = s+360
180n = s+360
Divide each side by 180
180n/180 = s/180 + 360/180
n = s/180 +2
2 x 10-6
times what number is equal to 6 x 10-4
Answer:
times -6
Explanation... 2 x 10-6 x -6=56
6 x 10-4=56
Hope this helps
Could someone help me out, I’m not sure how to do these :,)
Answer:
1.) Reflection over y=1
2.) Translation rule: (x-5, y-3)
3.) Reflection over the y axis
4.)Translation rule: (x-4, y+1)
Step-by-step explanation:
NEED HELP WORTH 100 POINTS SHOW YOUR WORK PLEASE
Answer:
Q1:
[tex]-5\sqrt{27c^2}[/tex]
[tex]-5\sqrt{27}\sqrt{c^2}[/tex]
[tex]-5\times\sqrt{9} \sqrt{3} \sqrt{c^2}[/tex]
[tex]-5\times3\sqrt{3}\sqrt{c^2}[/tex]
[tex]-5\times3\sqrt{3}c[/tex]
[tex]-15\sqrt{3}c[/tex]
Q2:
[tex]5\sqrt{72}-3\sqrt{32}[/tex]
[tex]5\sqrt{36} \sqrt{2} -3\sqrt{16} \sqrt{2}[/tex]
[tex]5\times6\sqrt{2}-3\times4\sqrt{2}[/tex]
[tex]30\sqrt{2}-12\sqrt{2}[/tex]
[tex]18\sqrt{2}[/tex]
Q3:
[tex]\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}[/tex]
[tex]\sqrt{36} \sqrt{3} \sqrt{yz} +3\sqrt{49} \sqrt{2} \sqrt{yz} +2\sqrt{25} \sqrt{3} \sqrt{yz}[/tex]
[tex]6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}[/tex]
[tex]16\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}[/tex]
Q4:
[tex]\sqrt{15n^2}\sqrt{10n^3}[/tex]
[tex]\sqrt{15}n\sqrt{10n^3}[/tex]
[tex]\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}[/tex]
[tex]\sqrt{15}\sqrt{10}n^2\sqrt{n}[/tex]
[tex]\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}[/tex]
[tex]5\sqrt{3}\sqrt{2}n^2\sqrt{n}[/tex]
[tex]5\sqrt{6}n^2\sqrt{n}[/tex]
Q5:
[tex]\frac{\sqrt{3x^2y^3}}{4\sqrt{5xy^3}}[/tex]
[tex]\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}[/tex]
Cancel off [tex]\sqrt{x}[/tex]:
[tex]\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}[/tex]
Cancel off [tex]y:[/tex]
[tex]\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}[/tex]
Cancel off [tex]\sqrt{y} :[/tex]
[tex]\frac{\sqrt{3}\sqrt{x}}{4\sqrt{5}}[/tex]
Multiply [tex]\sqrt{5}[/tex] on the numerator and denominator:
[tex]\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}[/tex]
[tex]\frac{\sqrt{15}\sqrt{x}}{20}[/tex]
sorry i pushed add answer
Solve for
16 – 2t = t +9
Liliana buys some softballs at $3 each and gloves at $20 each for her PE
class. She buys twice as many balls as gloves. She spends $138 in total,
which includes $8 tax: Which equation would you use to find the number of
gloves she buys?
Let x represent the number of gloves she buys.
A. 2 + 2x + 8 = 138
B. 20 (2x) + 3 (x) + 8 = 138
C. 20 (2) + 3 (2x) + 8 = 138
D. 20 (x) + 3(2x) = 138
Answer:
d. 20(x)+3(2x)=138
ap3x
The number of gloves she buys is B. 20 (2x) + 3 (x) + 8 = 138, where x = 3.
What are linear equation?A linear equation only has one or two variables. No variables in a linear equation is raised to power greater than 1 or used as denominator of a fraction.
Now it is given that,
Cost of each softball , $3.
Cost of each gloves, $20 .
Total money spend , $138 .
Tax , $8 .
She buys twice as many softballs as gloves.
To Find the number of gloves she buys .
Let , x represent the number of gloves she buys.
So , number of softballs she buys is 2x .
20 (2x) + 3 (x) + 8 = 138
or, 40x + 3x + 8 = 138
or, 43x + 8 = 138
Subtract 8 both the side we get,
43x = 130
or, x = 3.02
0r, x = 3
Hence,the number of gloves she buys is B. 20 (2x) + 3 (x) + 8 = 138, where x = 3
More about linear equation :
https://brainly.com/question/24267899
#SPJ2
The coordinates of point T are (0,4). The midpoint of ST is (1,-5). Find the coordinates of point S.
The other endpoint is
(Type an ordered pair.)
4x+2y=8 what is the y intercept
Find the measure of angle C of △ABC, if m∠A = α, m∠B = 2α its not 10-3a(will mark brainliest!)
Answer:
[tex]C = 180 - 3a[/tex]
Step-by-step explanation:
Given
[tex]A = a[/tex]
[tex]B = 2a[/tex]
Required
[tex]Find\ C[/tex]
Since, ABC is a triangle, we have:
[tex]A + B + C = 180[/tex]
Substitute values for A and C
[tex]a + 2a + C = 180[/tex]
[tex]3a + C = 180[/tex]
Subtract 3a from both sides
[tex]C = 180 - 3a[/tex]
Answer:
180°-3α
Step-by-step explanation:
If you forgot to put the degree sign on 180, that's why you got it wrong!
(-2)(7)(-75)(3)(-2)=?
Answer:
-6300
Step-by-step explanation:
I just plugged it into my calculator, Google's works just fine :)
Muna is making a scale drawing of a gecko. The gecko is 1··2inch wide and 5 inches long. A. She decides to make her drawing of the gecko 1 inch wide. How long will the drawing be? Show your work.
Answer:
[tex]L = 0.83\ in[/tex]
Step-by-step explanation:
Given
Width = 1.2 in when Length = 1 in
Required
Determine the length when width = 1 in
First, we need to determine the ratio:
[tex]Ratio = \frac{Width}{Length}[/tex]
[tex]Ratio = \frac{1.2}{1}[/tex]
[tex]Ratio = 1.2[/tex] --- (1)
Let the required Length be represented with L
So:
[tex]Ratio = \frac{Width}{Length}[/tex]
[tex]Ratio = \frac{1}{L}[/tex] --- (2)
Equate (1) and (2)
[tex]\frac{1}{L} = 1.2[/tex]
Multiply through by L
[tex]L * \frac{1}{L} = 1.2 * L[/tex]
[tex]1 = 1.2 * L[/tex]
Divide through by 1.2
[tex]L = \frac{1}{1.2}[/tex]
[tex]L = 0.83\ in[/tex] (Approximated)
I need help on number 2 , 3 and 4
please don’t skip over me!
show all work
Answer:
a,c,d
Step-by-step explanation:
[tex]a. \\4i^9+4i^7\\=4i(i^2)^4+4i(i^2)^3\\=4i(-1)^4+4i(-1)^3\\=4i-4i\\=0\\b.\\2i^{18}-3i^{11}\\=2(i^2)^9-3i(i^2)^5\\=2(-1)^9-3i(-1)^5\\=-2+3i\\c.\\7i^{36}-11i^{11}-11i^9\\=7(i^2)^{18}-11i(i^2)^5-11i(i^2)^4\\=7(-1)^{18}-11i(-1)^5-11i(-1)^4\\=7+11i-11i\\=7\\d.\\8i^{22}-1\\=8(i^2)^{11}-1\\=8(-1)^{11}-1\\=-8-1\\=-9[/tex]
e.
[tex]2i^{27}+4\\=2i(i^2)^{13}+4\\=2i(-1)^{13}+4\\=-2i+4[/tex]
What is the value of x?
-7.5 (x-3)=3.75
Answer:
x= 2.5
Step-by-step explanation:
-7.5 (x-3) = 3.75
(divide both sides of the equation by -7.5)
x-3 = -0.5
(move the constant to the righthand side and change the sign)
x = -0.5+3
(calculate the sum)
x = 2.5
math 1 work it out please w-2+2w=6 + 5w
Answer:
w = -4
Step-by-step explanation:
w - 2 + 2w = 6 + 5w
Add 2 to both sides.
w + 2w = 8 + 5w
Subtract w from each side.
2w = 8 + 4w
Subtract 4w from each side.
-2w = 8
Divide.
w = -4
Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tacoma's population be in 2010?
Points A, B, and C are collinear. Point B is the midpoint of AC. AB=12x-398. BC=22.
Solve for x. *
Answer:
x = 35Step-by-step explanation:
Collinear points A, B, and C and point B being midpoint of AC means:
AB = BC
12x - 398 = 22
+ 398 + 398
12x = 420
÷12 ÷12
x = 35
please help me on this
Answer:
12x+10
Step-by-step explanation:
Add up the lengths of all sides to find the perimeter
P = x + 2( x+5) + 6(x-1) + 3(x+2)
Distribute
= x + 2x+10 +6x-6 + 3x+6
Combine like terms
=x+ 2x+ 6x+3x + 10 -6+6
= 12x+10
Need help ASAP. Thanks!
Answer: 114
Step-by-step explanation:
To find the perimeter, you will find the distance around the shape by adding the numbers.
The is one missing side and to find that side you will subtract 10 from 38.
38 - 10 = 28
Now add the them.
28 + 5 + 10 + 26 + 10 + 35 = 114
Evaluate 12 - 6+ (14 – 8)^2=
. (1 point)
Answer:
the answer is 42
Step-by-step explanation:
12-6+(14-8)^2
12-6(6)^2
12-6+36
=42
Find the area.
A. 1818 sq cm
B. 1406 sq cm
C. 1246 sq cm
D. 141 sq cm
E. 146 sq cm
Answer:
C
Step-by-step explanation:
39*34= 1326 (the area of the full square
8*10=80 (the area of the small square that is cut off)
1326-80= 1246
Answer:
C = 1246 sq. cm.
Step-by-step explanation:
finding the area is simply splitting the area into two (see image)
A1 = 26 x 39 = 1014
A2 = 8 x 29 = 232
total area = 232 + 1014
total area = 1246 sq. cm.
therefore, the answer is C = 1246 sq. cm.
10 - 3x < 16
Can y’all help me pls
Answer:
x>-2
Step-by-step explanation:
first you subtract 10 from both sides to find x
10-3x-10<16-10
-3x<6
now here you divide both sides by -3
-3x/-3<6/-3
BUT since you are dividing by a negative number the sign will have to flip
so the answer will be
x>-2
10. APPLICATION Inspector 47 at the Zap battery plant
keeps a record of which AA batteries she finds defective.
Although the battery numbers at right do not make an
exact sequence, she thinks they are close to an arithmetic
sequence
a. Write a recursive formula for an arithmetic sequence
that estimates which batteries are defective. Explain
your reasoning
b. Predict the numbers of the next five defective batteries.
c. How many batteries in 100,000 will be defective?
Defective
Batteries
255, 500, 773
998, 1227, 1510,
1721, 2010
A clementine weighs about 80 g What is the approximate weight of 48 clementines?
Answer:
3840g
Step-by-step explanation:
... ..... ......
Frank needs to fill juice cups for his sis there r 35 cups amd it holds 12 fluid ounces. The juice came in a 1 gallon bottle how many 1 gallon bottles of juice will he need to purchase?
Answer:
4 gallons
Step-by-step explanation:
He needs 105 over 3 to fill all the cups. 1 gallon would be 10 and 2 third cups or 32 over 3. 2 gallons would be 21 and 1 third cups or 64 over 3. 3 gallons would be 32 or 96 over 3. 4 gallons would be 42 and 2 third cups or 128 over 3. So 4 gallons would fill up all 35 of his sisters 12 ounces cups. That would leave 7 and 2 third cups that hold the same amount. His sister gets all 35 of her 12 ounces each cups filled and he gets 7 and 2 thirds of new and unused 12 ounces cups. Basically out of the 4 gallons there would be 512 ounces and his sister with all 35 cups that hold 12 ounces each she would get 420 ounces. Which would leave him with 92 ounces of juice for himself. Hope this understandable and helpful.
Please help me to prove this!!!
Answer: see proof below
Step-by-step explanation:
Given: A + B + C = π → A + B = π - C
→ A + C = π - B
Use the Cofunction Identities: sin (π - A) = sin A
sin (A - π/2) = cos A
cos (π/2 - A) = - sin A
Use the Power Reducing Identity: sin ² A - sin² B = sin (A + B) · sin (A - B)
Use the Sum to Product Identity:
sin A - sin B = 2 [cos (A + B)/2] · [sin (A - B)/2]
Proof LHS → RHS:
LHS: sin² A - sin² B - sin² C
= (sin² A - sin² B) - sin² C
Power Reducing: sin (A + B) · sin (A - B) - sin² C
Given: sin (π - C) · sin (A - B) - sin² C
Cofunction: sin C · sin (A - B) - sin² C
Factor: sin C [sin (A - B) - sin C]
[tex]\text{Sum to Product:}\qquad \sin C\bigg[2\cos \bigg(\dfrac{(A-B)+C}{2}\bigg)\cdot \sin \bigg(\dfrac{(A-B)-C}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad \qquad =2\sin C\bigg[\cos \bigg(\dfrac{(A+C)-B}{2}\bigg)\cdot \sin \bigg(\dfrac{A-(B+C)}{2}\bigg)\bigg][/tex]
[tex]\text{Given:}\qquad \qquad 2\sin C\bigg[\cos \bigg(\dfrac{(\pi - B)-B}{2}\bigg)\cdot \sin \bigg(\dfrac{A-(\pi - A)}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =2\sin C\bigg[\cos \bigg(\dfrac{\pi -2B}{2}\bigg)\cdot \sin \bigg(\dfrac{2A-\pi}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =2\sin C\bigg[\cos \bigg(\dfrac{\pi}{2} -B}\bigg)\cdot \sin \bigg(A-\dfrac{\pi}{2}\bigg)\bigg][/tex]
Cofunction: 2 sin C (-sin B) · (cos A)
= -2 sin C · sin B · cos A
= -2 cos A · sin B · sin C
LHS = RHS: -2 cos A · sin B · sin C = -2 cos A · sin B · sin C [tex]\checkmark[/tex]