Answer:
Total momentum, p = 55 kg-m/s
It is given that,
Mass of player 1, m₁ = 85 kg
Mass of player 2, m₂ = 105 kg
Speed of player 1, v₁ = -8 m/s (west)
Speed of player 2, v₂ = 7 m/s (east)
Momentum is equal to the product of mass and velocity. For this system, momentum is given by :
p=m_1v_1+m_2v_2p=m
1
v
1
+m
2
v
2
p=85\ kg\times (-8\ m/s)+105\ kg\times 7\ m/sp=85 kg×(−8 m/s)+105 kg×7 m/s
p = 55 kg-m/s
The total momentum of the system made up of the two players is 55 kg-m/s.
Answer:
p = 55 kg * m/s east
Explanation:
The answer above explains it neatly, but leaves the direction out of the answer. The player heading east has more momentum, so the net momentum of the system is east.
If the velocity of an object changed from 30 m/s to 60 m/s over a period of 10 seconds what would the average acceleration be ?
Alex wants to learn how to surf, but he is not a strong swimmer. He knows he needs to increase his ability to paddle out in order to catch the best waves. Which piece of advice would you give to help him get started on reaching his goal? He should swim at least three times a week at the community pool to build stamina. He should tread water every day to get more comfortable in the water. He should purchase the best surfboard he can afford because it will help him paddle faster. He should watch your friend who is a competitive surfer practice to learn her technique.
Answer:
He should swim at least three times a week at the community pool to build stamina.
Explanation:
A 50 kg circus worker stands on a merry go round platform. If the worker's acceleration is 2.5 m/s2, what is her centripetal force?
F = ma
= 50kg × 2.5 m/s²
= 125 N
Answer : 125N
Explanation :
F = Force (N)
m = mass (kg)
a = acceleration (m/s²)
You are standing on a moving bus, facing forward, and you suddenly fall forward. You can imply form this that the bus’s
the diagram shows the apparent motion of the sun across the sky?
Answer:
The earth rotates west to east
Explanation:
Considering that the sun doesn't really move and the earth is rotating around the sun, and it is moving from east to west with us (the earth) facing it in which means the earth rotates around the sun west to east!
If you run North for 5 meters and then East for 15 meters and then
South for 2 meters all in 22 seconds. What was your speed?
0 points
Answer:
1m/s
Explanation:
D = 22m
T = 22s
S = 22÷22
= 1 m/s
A train travels with a speed of 115km/hr. How much time does it take to cover a distance of 470km.
It would take approximately 4 hours for the train to cover a distance of 470km.
4 hours 5 minutes 13.04 seconds
Calculate the kinetic energy of a 50 kg cart moving at a speed of 18.6 m/s.
Answer:
8649 J
Explanation:
KE = 1/2mv^2
1/2(50)(18.6)^2
1/2(50)(345.96) = 8649 J
An object is falling from a height of d and reaches a final velocity of vf. Calculate velocity when the object has fallen a distance d/2.
Answer:
The final velocity, [tex]v_{f}[/tex], is gd.
Explanation:
The condition here is a free falling object. Thus from the third equation of motion under free fall, we have;
[tex]v_{f}[/tex] = [tex]v_{i}[/tex] + 2gs
where [tex]v_{f}[/tex] is the final velocity of the object, [tex]v_{i}[/tex] is the initial velocity of the object, g is the gravitational force and s is the height.
Since the object falls from a height of d, then [tex]v_{i}[/tex] = 0 m/s, and s = d.
So that;
[tex]v_{f}[/tex] = 0 + 2gd
= 2gd
[tex]v_{f}[/tex] = 2gd
When the distance is [tex]\frac{d}{2}[/tex], [tex]v_{i}[/tex] = 0 m/s.
Then;
[tex]v_{f}[/tex] = 2g[tex]\frac{d}{2}[/tex]
[tex]v_{f}[/tex] = g x d
When the object falls through the height [tex]\frac{d}{2}[/tex], then the final velocity is gd.
WILL MARK BRAINLY!! QUICK HELP PLEASE!
A 40.0 kg rocket produces a
764 N upwards force ("thrust").
What is the net force acting on
the rocket?
Answer:
372Explanation:(40.0)×(9.8)=392
764N-392=372
A merry go round exerts a force of 1000 N on a rider on the
outer ring of animals when it takes 15 seconds to make a
complete revolution. If the person weighs 750 N, the radius
of the circle he is making is m. Round your answer to
the nearest tenth.
Answer:
The radius of the circle made by the person on the merry go round is 74.55 meters
Explanation:
The given parameters are;
The force the merry go round exerts on the rider = 1000 N
The time it takes the merry go round to make one complete revolution = 15 seconds
The weight of the person = 750 N
The radius of the circle made by the person on the merry go round = r
We have;
[tex]F_c = \dfrac{m \cdot v^2}{r} = m \cdot \omega ^2 \cdot r[/tex]
Where;
m = The mass of the person
v = The velocity of the person
[tex]F_c[/tex] = The centrifugal force acting on the person = 1,000 N
r = The radius of the circle made by the person on the merry go round
ω = Angular velocity = 2·π/15 rad/s
We have;
The mass of the person = The weight/(The acceleration due to gravity, g)
∴ The mass of the person = 750/9.81 ≈ 76.45 kg
By substituting the calculated and known values into the equation for the centripetal force, we have;
[tex]F_c[/tex] = m × ω² × r
1000 = 76.45 × (2·π/15)² × r
r = 1000/(76.45 × (2·π/15)²) = 74.55 m
The radius of the circle made by the person on the merry go round = r = 74.55 m.
An object at rest has no net force acting on it.
True or False
Answer:
True
Explanation:
The object is at rest, which means it's not moving, so there is no net force on it, according to Newton's First Law.
how many teeth shows signs of decay?
Answer:
what do you mean
Explanation:
Yuna is writing an opinion piece about her Schools lunch menu which text structure would best Express her ideas check all that apply
Answer:
Cause and effect, problem and solution, order of importance, comparison and contrast.
Explanation:
a small balloon containing baking soda has a mass of 4 grams. A student adds 10 ml. of vinegar
to a 100 gram glass bottle. The student stretches the opening of the balloon over the mouth of
the bottle, mixing the baking soda and vinegar inside the bottle. Once the balloon is inflated, the
student finds the mass of the balloon, bottle, and their contents to be 116 grams. What was the
mass of the vinegar originally in the bottle
F.10g G.12g J.16g
Answer:
10 grams
Explanation:
I took a test with this question earlier.
A sound wave passes from air into water and then into steel. With each change in medium, the velocity of this wave will a(increase,then decrease b(decrease c(increase d( decrease,then increase ?
Answer:
a
Explanation:
because it can increase anything
A 1500 kg car has an applied forward force of 5000 N and experiences an air resistance of 1250 N. What is the car's acceleration?
Answer:
[tex]2.33\ m/s^2[/tex]
Explanation:
Net Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
Fn = m.a
Where a is the acceleration of the object. The net force is the sum of the individual vector forces applied to the object.
The m=1500 Kg car has two horizontal forces applied: the forward force of 5000 N that causes the movement and the air resistance force of 1250 N that opposes motion.
The net force is Fn = 5000 N - 1500 N = 3500 N
To find the acceleration, we solve the equation for a:
[tex]\displaystyle a=\frac{Fn}{m}[/tex]
[tex]\displaystyle a=\frac{3500}{1500}[/tex]
[tex]\boxed{a = 2.33\ m/s^2}[/tex]
The car's acceleration is [tex]a = 2.33\ m/s^2[/tex]
26. For this table of data, which column is the independent variable?
radius of circle (m) area of circle (m2)
3.4
36.317
4.5
63.617
4.6
66.476
6.2
120.763
7.6
181.458
7.7
186.265
8.6
232.352
9.7
295.592
area of circle
o
radius of circle
O
None of these is correct.
Answer:
radius of a circle is measured by an instrument, so it is the independent variable
Explanation:
The independent variable corresponds to the magnitude controlled by the experimenter and in general can be measured by an instrument.
The dependent variable is the variable used to perform the calculations, obtained from a mathematical transformation of the independent variable.
The radius of a circle is measured by an instrument, so it is the independent variable and the area is calculated by
A = π r²
Therefore the area corresponds to the dependent variable
Which of the following is NOT one of the essential components of an exercise program?
Answer:
i dont know dude but ask someone who is in your grade lol
Explanation:
will you help me please
Answer: True
Explanation: It's true because the definition of a Command economy states that it's an economy in which production, investment, prices, and incomes are determined CENTERALLY by a GOVERNMENT.Do you think the inner planets should be explored or should the money be spent on other things? Justify your opinion.
Answer:
yes i think that inner planets should be explored because if we ever find new life or are able to live there then i think its worth takeing a risk.
Explanation:
If you have 100 kg of each of these substances, which would require the most energy to increase its temperature by 25 Kelvin?
A. Iron
B. Carbon
C. Rubber
D. Air
Answer:
iron
Explanation:
Physical values in the real world have two components: magnitude and
Answer:
Dimension.
Explanation:
Shows a car travelling around a bend in the road. The car is travelling at a constant speed. There is a resultant force acting on the car. This resultant force is called the centripetal force. (i) In which direction, A, B, C or D, does the centripetal force act on the car? Tick ( ) one box. A B C D (1) (ii) State the name of the force that provides the centripetal force.
Answer:
This question is incomplete
Explanation:
This question is incomplete but the missing figure is in the attachment below.
When an object is travelling around a circular path, there is a force that tends to draw that object towards the center of the circular path and keep the object moving in the curved path, that force is called the centripetal force. From this description, it can be deduced that the direction of the centripetal force that acts on the car (in the attachment below) is D.
The name of the force that provides this centripetal force is frictional force. This is the force that prevents the car from slipping off the road; keeping it moving in the curved path.
the fall of a body on the earth's surface cannot be a complete free fall why ?
Explanation:
because the boy has larger surface area due to which he offers the larger air resistance which decreases the acceleration so, he will fall towards the earth's surface approximately with constant velocity.
A 4812 kg boulder sits on top of a 203 m cliff. What is its PE?
Answer:
9572992.8 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
From the question we have
PE = 4812 × 9.8 × 203
We have the final answer as
9572992.8 JHope this helps you
help plz The sum of all chemical reactions that take place within an organism is known as ______________. *
Answer:
Metabolism
Explanation:
metabolism is the sum of all chemical reactions that take place within an organism
Answer:
Metabolism
Explanation:
Using Velocity vs Time Graphs to Find Acceleration
A graph titled velocity versus time has horizontal axis time (seconds) and vertical axis velocity (meters per second). A line has 4 straight segments. Line segment A runs from 0 seconds 0 meters per second to 1 seconds 15 meters per second. Then segment B runs to 2 seconds 20 meters per second. Then segment C runs to 4 seconds 20 meters per second. Then segment D runs to 5 seconds 0 meters per second.
The acceleration of segment D is m/s2.
Rank segments A, B, and C from least acceleration to greatest acceleration.
Least:
Greatest:
The acceleration at segment D is -20m/s²
The rank of the acceleration from the least to the greatest is -20m/s² < 0m/s² < 5m/s² < 10m/s² (D<C<B<A)
Acceleration is the change in velocity with respect to time.
a = v-u/t
Acceleration at segment A:
Aa = 15-0/1-0
Aa = 15m/s²
Acceleration at segment B:
Ab = 20-15/2-1
Ab = 5m/s²
Acceleration at segment C:
Aa = 0-0/4-2
Aa = 0m/s²
Acceleration at segment D:
Ac = 0-20/5-4
Ac = -20m/s²
Hence the acceleration at segment D is -20m/s²
The rank of the acceleration from the least to the greatest is -20m/s² < 0m/s² < 5m/s² < 10m/s² (D<C<B<A)
Learn more here: https://brainly.com/question/18398656
Describe the last three years of your life. Include positive and negative experiences.
For a middle school girl
Answer:
my middle school life was horrible and still is sadly ); could you please do my recent brainless <333
Explanation:
My middle school life was eh.i allways got assumed that i was a elementry kid when i was and 6 and 7 grade.until 8th when i hit my grow spurt.my voice end up getting really deep in 8th grade too.tho in 8th i got sent to a certain type of scholl for kids who did bad because of some dum teacher who lied that i hit her when i actually just went to her desk to get my phone sence she saw it in my pocket and took it away.i got sent there for 3 months and was worst thing ever.the treated us like prisoners in that school and made us tacky uniforms that i refused to where.i believe it was a school for 7th-12th.after my expierence at that school my expierence in 8th grade was almost done.i end up being popular at school for being that kid who hit the teacher.ofc that was like 2 years ago im 10th now.i dont really remember my 6th and 7th grade year.only thing i rember is i was a trouble maker and still am a trouble maker.
hope that helped you:)
please make my answer brainiest as im trying get 4 brainiest answers
- During a certain period, the angular position of a rotating object is given by: = − + , where is in radian and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the rotating object at = Sec.
The question is not complete. The complete question is :
During a certain period of time, the angular position of a rotating object is given by [tex]$\theta =2t^2 +10t+5$[/tex], where θ is in radians and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0.00 seconds, (b) at t = 3.00 seconds.
Solution :
Given :
Displacement or angular position of the object, [tex]$\theta =2t^2 +10t+5$[/tex]
∴ Angular speed is [tex]$\omega = \frac{d \theta}{dt}$[/tex]
ω = 10 + 4t
And angular acceleration is [tex]$\alpha = \frac{d \omega}{dt}$[/tex]
α = 4
a). At time, t = 0.00 seconds :
Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]
[tex]$\theta =2(0)^2 +10(0)+5$[/tex]
= 5 rad
Angular speed is ω = 10 + 4t
ω = 10 + 4(0)
= 10 rad/s
Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]
b). At time, t = 3.00 seconds :
Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]
[tex]$\theta =2(3)^2 +10(3)+5$[/tex]
= 53 rad
Angular speed is ω = 10 + 4t
ω = 10 + 4(3)
= 22 rad/s
Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]