P(x)/D(x) =

To find the quotient of P(x) and D(x) using long division, we have to divide

[tex]10x^3 + x^2 - 21x + 9 by 5x - 7.[/tex]

Long division is a method of dividing polynomials and it's used to find the** quotient** and the remainder when dividing one** polynomial** by another.

The** **dividend is written in decreasing order of powers of the** variable**.

Divide [tex]10x^3 by 5x to get 2x^2[/tex],

then write this above the line.

Multiply [tex]2x^2 by 5x - 7[/tex] to get[tex]10x^3 - 14x^2[/tex].

Write this below the first polynomial.

Subtract [tex]10x^3 - 10x^3[/tex] to get 0 and

[tex]-21x - (-14x^2)[/tex] to get [tex]-21x + 14x^2[/tex].

Bring down the next term which is 9.

Multiply[tex]2x^2 by 5x[/tex] to get[tex]10x^2[/tex]

write this above the line.

Multiply [tex]2x^2[/tex] by -7 to get -14x, then write this below the second **polynomial**.

Add -21x and 14x^2 to get [tex]14x^2 - 21x[/tex].

Subtract -14x and -14x to get 0, then bring down the next term which is 9.

Divide [tex]14x^2[/tex]by 5x to get 2x, then write this above the line.

**Multiply** 2x by [tex]5x - 7[/tex] to get [tex]10x - 14[/tex].

Write this below the third polynomial. Subtract 9 and -14 to get 23. Since 23 is a **constant**,

[tex]P(x) =[/tex][tex]10x^3 + x^2 - 21x + 9D(x) = 5x - 7[/tex]and

[tex]P(x)/D(x) = Q(x) + R(x)/D(x)= 2x^2 + 2x - 3 + 23/(5x - 7).[/tex]

To know more about ** polynomial **visit:-

https://brainly.com/question/11536910

#SPJ11

6. What principal invested at 13% compounded continuously for 6 years will yield $9000? Round the answer to two decimal places.

The principal invested at 13% **compounded **continuously for 6 years that will yield $9000 is approximately $4,645.85.

To calculate the **principal**, we can use the continuous compounding formula:

A = P * [tex]e^{(rt)[/tex]

Where:

A = Final amount ($9000)

P = Principal

e = Euler's number (approximately 2.71828)

r = Interest rate (13% or 0.13)

t = **Time **in years (6)

Substituting the given values into the formula, we have:

9000 = P * [tex]e^{(0.13 * 6)[/tex]

To solve for P, we can isolate it by dividing both sides of the equation by [tex]e^{(0.13 * 6)[/tex]:

P = 9000 / [tex]e^{(0.13 * 6)[/tex]

Using a calculator, we find that [tex]e^{(0.13 * 6)[/tex] = [tex]2.71828^{(0.78)[/tex] = 2.17448.

Therefore, the principal **invested **at 13% compounded continuously for 6 years that will yield $9000 is approximately $4,645.85.

Learn more about **Compounding**

brainly.com/question/19458442

#SPJ11

(a) Solve the quadratic inequality.

(b) Graph the solution on the number line.

(c) Write the solution of as an inequality or as an interval.

a. A solution to the **quadratic inequality **x² - 25 > -2x - 10 is x < -5 or x > 3.

b. The solution is shown on the **number line** attached below.

c. The solution as an interval is (-∞, -5) ∪ (3, ∞).

What is a quadratic equation?In Mathematics and Geometry, the standard form of a **quadratic equation** is represented by the following equation;

ax² + bx + c = 0

Part a.

Next, we would determine the **solution** for the given **quadratic inequality **as follows;

x² - 25 > -2x - 10

By rearranging and collecting like-terms, we have the following:

x² + 2x + 10 - 25 > 0

x² + 2x - 15 > 0

x² + 5x - 3x - 15 > 0

x(x + 5) -3(x + 5) > 0

(x + 5)(x - 3) > 0

x + 5 > 0

x < -5

x - 3 > 0

x > 3.

Therefore, the **solution** for the given **quadratic inequality **is x < -5 or x > 3.

Part b.

In this exercise, we would use an online graphing calculator to plot the given** solution** x < -5 or x > 3 as shown on the **number line** attached below.

Part c.

The **solution** for the given **quadratic inequality** x² - 25 > -2x - 10 as an interval should be written as follows;

(-∞, -5) ∪ (3, ∞).

As an **inequality**, the **solution** for the given **quadratic inequality** x² - 25 > -2x - 10 should be written as follows;

-5 > x > 3

Read more on **inequality** here: https://brainly.com/question/30665021

#SPJ1

The hypotheses for this problem are: H0: μ = 47 H1: μ > 47 a) Find the test statistic. Round answer to 4 decimal places. Answer: b) Find the p-value. Round answer to 4 decimal places. Answer: c) What is the correct decision? Accept H0 Do not reject H1 Reject H1 Reject H0 Do not reject H0 d) What is the correct summary? There is not enough evidence to support the claim that the mean workweek for employees at start-up companies work more than 47 hours. There is enough evidence to support the claim that the mean workweek for employees at start-up companies work more than 47 hours.

The test statistic and p-value cannot be determined without the sample data. Thus, we cannot provide a specific answer for parts (a) and (b). Without the test statistic and p-value, we cannot make a correct decision regarding accepting or rejecting the null **hypothesis **(H0) or the alternative hypothesis (H1).

Consequently The specific values for the test statistic, p-value, and decision would depend on the **analysis **of the sample data using the appropriate statistical test, such as a t-test or z-test.

a) The test statistic for this problem would depend on the sample data and the type of test being **conducted**. Without the sample data, it is not possible to determine the exact test statistic required to make a decision.

b) Similarly, the p-value would depend on the sample **data **and the type of test being conducted. Without the sample data, it is not possible to calculate the p-value.

c) Without the test statistic and the p-value, it is not possible to make a correct decision regarding accepting or rejecting the null hypothesis (H0) or the **alternative **hypothesis (H1).

d) Based on the **information **provided, we cannot determine the correct summary as it relies on the test statistic, p-value, and decision made based on the data.

Learn more about **hypothesis : brainly.com/question/31319397**

#SPJ11

1. Given an equation of the second degree 3x² + 12xy + 8y² - 30x - 52y + 23 = 0 a. Use translation and rotation to transform the equations in the simplest standard form b. Draw the equation curve c. Determine the focal point of the equation

We have been given an **equation **of the second degree:[tex]3x² + 12xy + 8y² - 30x - 52y + 23 = 0[/tex]

We have to transform the equations in the simplest standard form, draw the equation curve and determine the focal point of the equation. We draw the equation curve from the simplest standard form of the equation as:

Step-by-step answer:

Given an equation of the second **degree **[tex]3x² + 12xy + 8y² - 30x - 52y + 23 = 0.[/tex]

a) Transform the equations in the simplest standard form.[tex]3x² + 12xy + 8y² - 30x - 52y + 23[/tex]

[tex]03x² - 30x + 8y² + 12xy - 52y + 23 = 0[/tex]

(Rearranging the terms)

[tex]3(x² - 10x) + 8(y² - 6.5y)[/tex]

= -23 + 0 + 0 - 0 + 0 + 0

Complete the square to get the standard form.

[tex]3[x² - 10x + 25] + 8[y² - 6.5y + 42.25][/tex]

[tex]= -23 + 3(25) + 8(42.25)3[(x - 5)²/25] + 8[(y - 6.5)²/42.25][/tex]

= 21.0625

Simplifying further,[tex]3(x - 5)²/25 + 8(y - 6.5)²/42.25 = 1[/tex]

b) Draw the equation curve by plotting the **points **on the graph obtained after finding the equation in standard form. The graph will be an ellipse as both x² and y² have the same signs. Let's plot the points.The major axis of the ellipse is 2*sqrt(42.25) = 13. This can be found by 2*sqrt(b²) where b² is the bigger denominator. Here, b² = 42.25

Therefore, the endpoints of the major axis can be found by adding and subtracting 13/2 from 6.5.The minor axis of the ellipse is 2*sqrt(25) = 10. This can be found by 2*sqrt(a²) where a² is the smaller denominator. Here, a² = 25Therefore, the endpoints of the **minor **axis can be found by adding and subtracting 10/2 from 5.The focal point of the equation can be found using the following formula. The focal points lie on the major axis of the ellipse with the center as the midpoint of the major axis.

[tex]a² = b² - c²c²[/tex]

[tex]= b² - a²c²[/tex]

[tex]= 42.25 - 25c[/tex]

= sqrt(17.25)

The distance between the center and the focal point is c. Therefore, the two focal points can be found by adding and subtracting c from the center.(5, 6.5 - c) and (5, 6.5 + c) When c = sqrt(17.25), the **focal **points are approximately (5, 1.832) and (5, 11.168).Thus, the major and minor axes and the focal points have been found.

To know more about **equation **visit :

https://brainly.com/question/10724260

#SPJ11

Consider a two dimensional orthogonal rotation matrix λ Show that λ^-1= λ^1

We have shown that the inverse of the two-dimensional orthogonal **rotation matrix** is equal to its transpose.

In mathematics, an **orthogonal **rotation matrix is a real matrix that preserves the length of each vector and the angle between any two vectors, including those that are not orthogonal.

In this case, we are to prove that the inverse of the orthogonal rotation matrix is equal to its** transpose.**

The two-dimensional orthogonal rotation matrix λ is given by

λ = [cos(θ) -sin(θ);

sin(θ) cos(θ)]

where θ is the angle of rotation.

Let's find the inverse of λ:

λ⁻¹ = [cos(θ) sin(θ);-

sin(θ) cos(θ)]/det(λ)

where det(λ) is the **determinant** of λ, which is

cos²(θ) + sin²(θ) = 1

Therefore,

λ⁻¹ = [cos(θ) sin(θ);-

sin(θ) cos(θ)]

Multiplying both sides by λ, we get

λ⁻¹λ = [cos(θ) sin(θ);-sin(θ) cos(θ)][cos(θ) -sin(θ);

sin(θ) cos(θ)]

λ⁻¹λ = [cos²(θ) + sin²(θ) cos(θ)sin(θ) - cos(θ)sin(θ);

sin(θ)cos(θ) - cos(θ)sin(θ) cos²(θ) + sin²(θ)]

λ⁻¹λ = [1 0;0 1]

This implies thatλ⁻¹ = λ¹And this completes the proof.

Know more about the **transpose.**

**https://brainly.com/question/31047083**

#SPJ11

Consider the following quadratic function. f(x)=3x²-12x+8. (a) Write the equation in the form f(x) = a (x-h)²+k. Then give the vertex of its graph. Writing in the form specified: f(x) = ___

The required **equation** in the **specified form** is f(x) = 3(x - 2)² - 4.

Given that the quadratic function is f(x) = 3x²-12x+8

(a)

Writing the equation in the form f(x) = a(x-h)²+k

Let's first complete the square of the given **quadratic equation**

f(x) = 3x²-12x+8,

f(x) = 3(x² - 4x) + 8

Here, a = 3

f(x) = 3(x² - 4x + 4 - 4) + 8

= 3(x - 2)² - 4

Therefore, the equation in the form f(x) = a(x - h)² + k is given by:

f(x) = 3(x - 2)² - 4

The **vertex **of the **graph** will be at (h, k) => (2, -4)

Therefore, the required equation in the specified form is f(x) = 3(x - 2)² - 4.

To know more about **quadratic equation, **visit:

**https://brainly.com/question/29269455**

#SPJ11

What symbol completes the inequality 6x-3y___ -12

>

<

≥

≤

A **symbol** that completes the inequality 6x - 3y ___ -12 is: C. ≥.

In Mathematics and Geometry, an **inequality** simply refers to a mathematical relation that is typically used for comparing two (2) or more numerical data and variables in an algebraic equation based on any of the **inequality symbols**;

Next, we would evaluate the **inequality **by using specific ordered pairs (x, y) as follows;

(0, 0)

6(0) - 3(0) ? -12

0 ≥ -12

(1, 2)

6(1) - 3(2) ? -12

0 ≥ -12

(-1, 2)

6(-1) - 3(2) ? -12

-12 ≥ -12

Read more on **inequality **here: brainly.com/question/27976143

#SPJ1

(3 pts) Evaluate the integral. Identify any equations arising from technique(s) used. Show work. ∫1-0 y/eˆ³y dy

To evaluate the **integral **∫(1 to 0) y/e^(3y) dy, we can use **integration **by substitution.

Let u = 3y. Then, du = 3dy.

When y = 1, u = 3(1) = 3.

When y = 0, u = 3(0) = 0.

The limits of **integration **can be expressed in terms of u as well.

Now, let's rewrite the integral in terms of u:

∫(1 to 0) y/e^(3y) dy = ∫(3 to 0) (1/3)e^(-u) du.

Next, we can simplify the integral:

∫(3 to 0) (1/3)e^(-u) du = (1/3) ∫(3 to 0) e^(-u) du.

Using the fundamental theorem of **calculus**, we can integrate e^(-u):

(1/3) ∫(3 to 0) e^(-u) du = (1/3) [-e^(-u)] from 3 to 0.

Now, let's substitute the limits of integration:

(1/3) [-e^(-0) - (-e^(-3))].

Simplifying further:

(1/3) [-1 + e^(-3)].

Therefore, the value of the integral ∫(1 to 0) y/e^(3y) dy is (1/3)[-1 + e^(-3)].

To evaluate the integral ∫(1 to 0) y/e^(3y) dy, we can use integration by substitution.

Let u = 3y. Then, du = 3dy.

When y = 1, u = 3(1) = 3.

When y = 0, u = 3(0) = 0.

The limits of integration can be expressed in terms of u as well.

Now, let's rewrite the integral in terms of u:

∫(1 to 0) y/e^(3y) dy = ∫(3 to 0) (1/3)e^(-u) du.

Next, we can simplify the integral:

∫(3 to 0) (1/3)e^(-u) du = (1/3) ∫(3 to 0) e^(-u) du.

Using the fundamental theorem of calculus, we can integrate e^(-u):

(1/3) ∫(3 to 0) e^(-u) du = (1/3) [-e^(-u)] from 3 to 0.

Now, let's substitute the limits of integration:

(1/3) [-e^(-0) - (-e^(-3))].

Simplifying further:

(1/3) [-1 + e^(-3)].

Therefore, the value of the integral ∫(1 to 0) y/e^(3y) dy is (1/3)[-1 + e^(-3)].

To learn more about **calculus : **brainly.com/question/22810844

#SPJ11

the height of a rocket is modeled by the equation h=-(t-8)^2+65 here h is height in meters and t is the time in seconds. what is the max height, what height is it launched from, how long is the rocket above 40m

The **rocket** is above** 40 meters **for 13 - 3 = 10 seconds.

**Launch height**: The rocket is launched at t=0. So, if we substitute t=0 into the equation, we can find the initial height:

h = - (0 - 8)^2 + 65 = -64 + 65 = 1 meter.

Time above 40 meters: To find the** time interval **when the rocket is above 40 meters, we set h = 40 and solve for t:

40 = - (t - 8)^2 + 65

Simplify to: (t - 8)^2 = 65 - 40 = 25

Take the square root: t - 8 = ±5

Solve for t: t = 8 ± 5

So, the rocket is above 40 meters between t = 8 - 5 = 3 seconds and t = 8 + 5 = 13 seconds.

So, the rocket is above 40 meters for 13 - 3 = 10 seconds.

Read more on **height of a rocket **herehttps://brainly.com/question/29574092

#SPJ1

Test whether there is a significant departure from chance preferences for five colas Coke Diet Coke, Pepsi, Diet Peps, or RC Colal for 250 subjects who taste allo them and state which one they like the best One Way Independent Groups ANOVA One Way Repeated Measures ANOVA Two Way Independent Groups ANOVA Two Way Repeated Measures ANOVA Two Way Mixed ANOVA Independent groups t-test Matched groups t-test Mann-Whitney U-Test Wilcoxon Signed Ranks Test

We would use a one-way independent groups ANOVA to test for a significant departure from chance preferences for the five colas. This is because we are testing for differences between groups (the **five colas**), and we are assuming that there is no relationship between the groups.

The one-way repeated measures ANOVA would not be appropriate because we are not testing the same group of subjects at multiple time points. The two-way **ANOVA tests **would not be appropriate because we only have one independent variable (the five colas). The independent groups t-test and the matched groups t-test would not be appropriate because we are testing for differences between more than two groups.

The Mann-Whitney U-Test and the **Wilcoxon **Signed Ranks Test could be used if the data does not meet the assumptions of a parametric test. However, if the data is normally distributed and there are no **outliers**, the one-way independent groups ANOVA is the best choice.

Therefore, in this scenario, the one-way independent groups ANOVA is the best choice to test for a significant departure from chance preferences for the five colas.

To know more about **ANOVA tests **visit -

brainly.com/question/30890178

#SPJ11

From experience, the expected grade in the final Probability exam is 60 points.

1. Using Markov's inequality, what can you say about the probability that a student's grade is greater than 75?

2. IF it is known that σ = 10 using Chebyshev's inequality approximates the probability that the note is between 70 and 80 ?

Using Markov's **inequality**, we can say that the probability that a student's grade is greater than 75 is at most 60/75 or 0.8. This means that at least 80% of the students should score above 60 points. Markov's inequality gives an upper bound on the probability of a random variable taking a large value. It can be used for any non-negative random variable.

Here, the grade of a student is a non-negative random **variable** that takes values between 0 and 100.2. Chebyshev's inequality states that for any random variable, the probability that the value of the random variable deviates from the mean by more than k standard deviations is at most 1/k^2. Using this, we can say that the probability that the note is between 70 and 80 is at least 1 - 1/2^2 or 0.75. We can see that this is a weaker bound than the one obtained using the normal distribution, which would have given a probability of 0.9545.

To know more about **inequality **visit :-

https://brainly.com/question/20383699

#SPJ11

After Doreen puts $80,000 in the Bank and makes no other deposits

or withdrawals, if the bank promises 5.4% interest, how much is in

the account (to the nearest cent) after 24 years?

The answer based on the **compound interest** is the **amount **in the account after 24 years, to the nearest cent is $251,449.95.

The formula for compound interest is [tex]A = P(1 + \frac{r}{n} )^{nt}[/tex],

where: A = the final amount, P = the principal, r = the annual interest rate (as a decimal),n = the number of times the interest is compounded per year, t = the number of years.

For the given problem, the **principal **(P) is $80,000, the annual interest rate (r) is 5.4% or 0.054 in decimal form, the number of times the **interest **is compounded per year (n) is 1 (annually), and the number of years (t) is 24.

**Substituting **these values into the formula,

A = 80000[tex](1 + 0.054/1)^{(1*24)}[/tex] = 80,000(1.054)²⁴ = $251,449.95 (rounded to the nearest cent).

Therefore, the amount in the account after 24 years, to the nearest cent is $251,449.95.

To know more about** Compound interest **visit:

**https://brainly.com/question/29639856**

#SPJ11

10. What is the solution of the initial value problem x' = [1 −5] -3 x, x(0) = ? H cost 2 sin t (a) e-t sin t -t (b) cost + 4 sin t sin t (c) cost + 2 sint sin t cost + 2 sint (d) sin t cost + 4 sin t (e) sin t e -2t e e-2t

The **solution **of the given initial value problem is e-2t[cos t + 2 sin t].

Given that the initial value problem isx' = [1 -5] -3 xand x(0) = ?We know that if A is a matrix and X is the solution of x' = Ax, thenX = eAtX(0)

Where eAt is the **matrix **exponential given bye

Summary: The initial value problem is x' = [1 -5] -3 x, x(0) = ?. The matrix can be written as [1 -5] = PDP-1, where P is the matrix of eigenvectors and D is the matrix of eigenvalues. Then, eAt = PeDtP-1= 1 / 3 [2 1; -1 1][e-2t 0; 0 e-2t][1 1; 1 -2]. Finally, the solution of the initial value problem is e-2t[cos t + 2 sin

Learn more about **matrix **click here:

https://brainly.com/question/2456804

#SPJ11

"calculus practice problems

Find the area under the graph of f over the interval [3,9]. {2x+7, for x≤7 f(x) = {56 - 5/2 x, for x>7 The area is ..... (Type an integer or a simplified fraction.)"

The area under the **graph **of f over the **interval **[3,9] is 149

To find the **area **under the graph of the **function **f over the interval [3,9], we need to split the interval into two parts: [3,7] and (7,9]. In the first part, the function is given by f(x) = 2x + 7, and in the second part, it is given by f(x) = 56 - (5/2)x.

First, let's calculate the area under the graph of f(x) = 2x + 7 over the interval [3,7]. We can find the **definite integral **of 2x + 7 with respect to x:

∫[3 to 7] (2x + 7) dx = [x^2 + 7x] evaluated from 3 to 7.

Substituting the upper and lower limits into the integral, we get:

[(7^2 + 7(7)) - (3^2 + 7(3))] = (49 + 49) - (9 + 21) = 98 - 30 = 68.

Next, let's calculate the area under the graph of f(x) = 56 - (5/2)x over the interval (7,9]. We can find the definite integral of 56 - (5/2)x with respect to x:

∫[7 to 9] (56 - (5/2)x) dx = [56x - (5/4)x^2] **evaluated **from 7 to 9.

**Substituting **the upper and lower limits into the integral, we get:

[(56(9) - (5/4)(9^2)) - (56(7) - (5/4)(7^2))] = (504 - 202.5) - (392 - 171.5) = 301.5 - 220.5 = 81.

Finally, to find the total area under the graph of f over the interval [3,9], we **sum **up the areas from both parts:

Total area = Area from [3 to 7] + Area from (7 to 9] = 68 + 81 = 149.

Therefore, the area under the graph of f over the interval [3,9] is 149.

To learn more about **definite integral** click here: brainly.com/question/29685762

#SPJ11

differential equations

show complete and full work with

nice hand writing

Find a particular solution to the differential equation using the method of Undetermined Coefficients x"(t) - 16x (1) +64X(t)=te R. A solution is xp (0) =

The** particular solution** is given by

[tex]xp(t) = (t/64)e^(Rt) + (1/256)te^(Rt)[/tex] when xp(0) = 0

Given differential equation:

[tex]xp(t) = (t/64)e^(Rt) + (1/256)te^(Rt)[/tex]

We need to find the particular solution using the method of **Undetermined Coefficients.**

The Method of Undetermined Coefficients, also known as the method of trial and error, is a technique used to guess a particular solution to a non-homogeneous linear second-order differential equation. The method involves making an informed guess about the form of the particular solution and then using the derivatives of that guess to determine the coefficients.

To solve the above **differential equation, **we assume the particular solution in the form of polynomial equation of first order:

x(t) = At + B

Substituting this particular solution in the differential equation:

[tex]x''(t) - 16x'(t) + 64x(t) = te^(Rt)[/tex]

Differentiating the assumed particular solution: x'(t) = A and x''(t) = 0

Substituting these values in the differential equation:

[tex]0 - 16(A) + 64(At + B) = te^(Rt)[/tex]

On comparing **coefficients **of t on both sides, we get the value of A.

[tex]64A = te^(Rt)A = (t/64)e^(Rt)[/tex]

On comparing constant terms on both sides, we get the value of B.

-16A + 64B = 0

B = (1/4)

[tex]A = (1/256)te^(Rt)[/tex]

Thus the particular solution of the given differential equation is:

xp(t) = At + B

[tex]xp(t) = (t/64)e^(Rt) + (1/256)te^(Rt)[/tex]

Now, xp(0) = B

= (1/256)*0

= 0

Know more about the ** particular solution**

**https://brainly.com/question/31479320**

#SPJ11

1 - 4 17 -7 If A=[ - ] and AB =[-¹7 -23] 4 3 3 25 b₁ determine the first and second columns of B. Let b₁ be column 1 of B and b₂ be column 2 of B.

Given that, A = [ 1 - 4 ; 17 - 7] and AB = [-¹7 -23 ; 4 3 ; 3 25]B = [ b₁ b₂ ], the first and second **columns** of B are [ - 1 1 ] and [ - 6 2 ] respectively.

Calculate the** inverse** of the **matrix** A to find B. Multiply A inverse with AB to get B. Calculation of the inverse of A

We will find the inverse of A using the following formula; A inverse = 1 / determinant of A × adjoint of A

To calculate the determinant of A, we will use the following formula; | A | = ( a₁₁ × a₂₂ ) - ( a₁₂ × a₂₁ )| A | = ( 1 × - 7 ) - ( - 4 × 17 )| A | = - 7 + 68| A | = 61

Now, we will find the adjoint of A; Adjoint of A = [ (cofactor of a₁₁) (cofactor of a₁₂) ; (cofactor of a₂₁) (cofactor of a₂₂) ]Cofactor of a₁₁ = -7Cofactor of a₁₂ = 4Cofactor of a₂₁ = -17Cofactor of a₂₂ = 1

Therefore, Adjoint of A = [ - 7 4 ; - 17 1]Now, we will find the inverse of A using the above formula; A inverse = 1 / **determinant** of A × adjoint of A= 1 / 61 [ - 7 4 ; - 17 1]= [ - 7 / 61 4 / 61 ; - 17 / 61 1 / 61 ]

Calculation of B To calculate B, we will multiply A inverse with AB.B = A inverse × AB⇒ [ b₁ b₂ ] = [ - 7 / 61 4 / 61 ; - 17 / 61 1 / 61 ] × [ - ¹7 -23 ; 4 3 ; 3 25]⇒ [ b₁ b₂ ] = [ - 1 - 6 ; 1 2 ]

Therefore, the first and second columns of B are [ - 1 1 ] and [ - 6 2 ] respectively.

More on **columns**: https://brainly.com/question/31053916

#SPJ11

In a beauty contest the scores awarded by eight judges weew

5.9 6.7 6.8 6.5 6.7 8.2 6.1 6.3

Using the eight scores determine

The mean ii. The median iii the mode

iv.. the variance of the scores

v. The standard deviation

The results are:

i. **Mean** = 6.775

ii. Median = 6.6

iii. Mode = No mode

iv. Variance ≈ 0.44936875

v. Standard Deviation ≈ 0.6697

To analyze the given scores** **awarded by the eight** judges**, let's calculate the requested measures:

Scores: 5.9, 6.7, 6.8, 6.5, 6.7, 8.2, 6.1, 6.3

i. Mean: The mean is the average of the **scores**. To calculate it, we sum all the scores and divide by the number of scores:

Mean = (5.9 + 6.7 + 6.8 + 6.5 + 6.7 + 8.2 + 6.1 + 6.3) / 8 = 54.2 / 8 = 6.775

ii. **Median**: The median is the middle value when the scores are arranged in ascending order. First, let's sort the scores:

Sorted scores: 5.9, 6.1, 6.3, 6.5, 6.7, 6.7, 6.8, 8.2

Since we have an even number of scores, the median is the average of the two middle values: (6.5 + 6.7) / 2 = 6.6

iii. Mode: The mode is the score(s) that appears most frequently. In this case, there is no score that appears more than once, so there is no mode.

iv. Variance: The variance measures the spread or dispersion of the scores. To calculate it, we need to find the squared difference between each score and the mean, sum them up, and divide by the number of scores minus one:

Variance = [(5.9 - 6.775)^2 + (6.1 - 6.775)^2 + (6.3 - 6.775)^2 + (6.5 - 6.775)^2 + (6.7 - 6.775)^2 + (6.7 - 6.775)^2 + (6.8 - 6.775)^2 + (8.2 - 6.775)^2] / (8 - 1)

= [0.592225 + 0.552025 + 0.471225 + 0.454225 + 0.000225 + 0.000225 + 0.005625 + 2.070025] / 7

= 3.145575 / 7

= 0.44936875

v. Standard Deviation: The standard deviation is the square root of the variance. Taking the square root of the variance calculated above, we get:

Standard Deviation = √0.44936875 ≈ 0.6697

Learn more about the** mean, mode, and median** on:

brainly.com/question/14532771

#SPJ11

MUX implements which of the following logic? a) NAND-XOR. b) XOR-NOT. c) OR-AND. d) AND-OR.

The MUX (multiplexer) logic implements option (d) AND-OR. A multiplexer is a combinational **logic circuit **that selects one of several input signals and forwards it to a single output based on a select signal.

The **outputs** of the AND gates are then fed into an OR gate, which produces the final output. This configuration allows the MUX to select and pass through a specific input signal based on the select signal, performing the AND-OR logic operation. A **multiplexer **has two sets of inputs: the data inputs and the select inputs. The data inputs represent the different signals that can be selected, while the select inputs determine which signal is chosen.

AND-OR MUX, each data input is connected to an AND gate, along with the select inputs. The outputs of the AND gates are then connected to an OR gate, which produces the final output. The select inputs control which AND gate is enabled, allowing the corresponding data input to propagate through the** circuit **and contribute to the final output. This implementation enables the MUX to perform the AND-OR logic function.

Learn more about **logic circuit **click here:

brainly.com/question/31827945

**#SPJ11**

Which of the following functions has the longest period? O f(x) = 2 sin(0.5x) - 11 = Of(x) = 8 cos(2x) - 4 = O f(x)= 7 cos(x) + 13 O f(x) = 6 sin(3x) + 20 (1 point) The productivity of a person at work on a scale of 0 to 10) is modelled by a cosine function: 5 cos + 5, where tis in hours. If the person starts work at t= 0, 2t being 8:00 a.m., at what times is the worker the least productive? IT 10 a.m., 12 noon, and 2 p.m. 10 a.m. and 2 p.m. 11 a.m. and 3 p.m. 12 noon

Hence, the worker is **least productive** at 10 a.m. and 2 p.m.

We have four functions as given below:O f(x) = 2 sin(0.5x) - 11 = Of(x) = 8 cos(2x) - 4 = O f(x)= 7 cos(x) + 13 O f(x) = 6 sin(3x) + 20

To determine which of the above **functions **has the longest period, we will use the formula to calculate the period of a function:

Period (T) = 2π / b1) O f(x) = 2 sin(0.5x) - 11

In this function, b = 0.5

Period (T) = 2π / b = 2π / 0.5 = 4π2) O f(x) = 8 cos(2x) - 4

In this function, b = 2

Period (T) = 2π / b

= 2π / 2

= π3) O f(x)

= 7 cos(x) + 13

In this function, b = 1

Period (T) = 2π / b

= 2π / 1

= 2π4) O f(x)

= 6 sin(3x) + 20

In this function, b = 3

Period (T) = 2π / b

= 2π / 3

The function with the longest period is O f(x) = 2 sin(0.5x) - 11.

The productivity of a person at work on a scale of 0 to 10 is modeled by a cosine function: 5 cos + 5, where t is in hours. If the person starts work at t = 0, 2t being 8:00 a.m.

The cosine function for this **productivity **is given by:

P (t) = 5 cos(πt) + 5At t = 0, the worker starts his job, and 2t is 8:00 a.m.

T = 2π / b

= 2π / π

= 2

We can see that the worker is unproductive every 2 hours. We can determine the hours that he/she is least productive by adding 2 to the **starting **time (0) and multiplying the result by the period

(2).We get 0 + 2(2)

= 4 and 4 + 2(2)

= 8.

To know more about **scale **visit:

https://brainly.com/question/28465126

#SPJ11

Use the sample data and confidence level oven A research institute pollasked respondents if they folt vulnerable to identity theft in the poll, n=1019 and x 600 who said "yos. Use a 95% confidence level. a) Find the best point estimate of the population proportion p

The point estimate of the **population **proportion is: p = 600 / 1019 ≈ 0.588

The best point estimate of the population **proportion**, denoted as p, can be calculated by dividing the number of respondents who answered "yes" (x) by the total number of respondents (n):

p = x / n

In this case, the number of respondents who said "yes" is 600, and the total number of respondents is 1019.

Therefore, the point **estimate **of the population proportion is: p = 600 / 1019 ≈ 0.588

Learn more about **estimate **at https://brainly.com/question/107747

#SPJ4

Find all possible Jordan forms for a matrix whose characteristic polynomial is (x + 2)²(x - 5)³.

The **characteristic polynomial** of the matrix is given as (x + 2)²(x - 5)³. To find all possible Jordan forms, we need to determine the possible sizes of Jordan blocks corresponding to each eigenvalue.

The given characteristic polynomial, (x + 2)²(x - 5)³, indicates that the matrix has two distinct **eigenvalues**: -2 and 5. For each eigenvalue, we determine the possible sizes of Jordan blocks.

1. Eigenvalue -2:

Since the multiplicity of -2 is 2, the possible sizes of Jordan blocks for this eigenvalue are 2x2 and 1x1.

2. Eigenvalue 5:

Since the multiplicity of 5 is 3, the possible sizes of Jordan blocks for this eigenvalue are 3x3, 2x2, and 1x1.

Combining the possible sizes of **Jordan blocks** for each eigenvalue, we can construct all possible Jordan forms. Here are the potential Jordan forms based on the eigenvalues and their multiplicities:

1. (2x2) block for -2, (3x3) block for 5

2. (2x2) block for -2, (2x2) block for 5, (1x1) block for 5

3. (1x1) block for -2, (3x3) block for 5

4. (1x1) block for -2, (2x2) block for 5, (1x1) block for 5

5. (1x1) block for -2, (2x2) block for 5, (2x2) block for 5

These are all the possible **Jordan forms** for a matrix whose characteristic polynomial is (x + 2)²(x - 5)³. Each Jordan form corresponds to a different arrangement of Jordan blocks, which determines the **matrix's structure** and behavior.

To learn more about **eigenvalues **click here: brainly.com/question/13144436

#SPJ11

Find the tangent plane to the equation z = 4x³ + 3xy³ − 2 at the point ( – 2, 1,40) z =

The **tangent plane** to the equation z = 4x³ + 3xy³ − 2 at the point (-2, 1, 40) can be found by calculating the** partial derivatives** and evaluating them at the given point.

To find the tangent plane, we need to calculate the partial derivatives of the given **equation** with respect to x and y. Taking the partial derivative of z with respect to x, we get dz/dx = 12x² + 3y³. Similarly, taking the partial derivative of z with respect to y, we get dz/dy = 9xy².

Next, we evaluate these partial derivatives at the point (-2, 1, 40). **Plugging** in these **values** into the derivatives, we have dz/dx = 12(-2)² + 3(1)³ = 48 + 3 = 51 and dz/dy = 9(-2)(1)² = -18.

Now, using the equation of a plane, which is given by z - z₀ = (dz/dx)(x - x₀) + (dz/dy)(y - y₀), where (x₀, y₀, z₀) is the given point, we substitute the values: 40 - 40 = 51(x - (-2)) - 18(y - 1).

Simplifying the equation, we have 0 = 51x + 18y - 51(2) + 18. Further **simplification** gives us the equation of the tangent plane as 51x + 18y - 123 = 0. This is the equation of the tangent plane to the given equation at the point (-2, 1, 40).

Learn more about **tangent plane** here:

https://brainly.com/question/31433124

#SPJ11

Find the remainder when 170^1801 is divided by 19.

a. 13

b. None of the mentioned.

c. 18

d. 15

e. 17

Option B. None of the **mentione**d is the **remainder** when 170^1801 is divided by 19.

According to **Euler's Theorem**, 170¹⁸ = 1 (mod 19).

Next, note that 1801 = 100*18 + 1. Therefore, we can write:

170¹⁸⁰¹ = (170¹⁸)¹⁰⁰ * 170

= 1¹⁰⁰ * 170

= 170 (mod 19).

Therefore, the** remainder **when170¹⁸⁰¹ is divided by 19 is the same as the remainder when 170 is divided by 19.

170 mod 19 = 2 (since 19*9=171, which is just over 170).

So, the remainder when 170¹⁸⁰¹ is **divided** by 19 is 2, which is not among the provided options.

Hence, the correct answer is:

b. None of the mentioned.

Read more on **division** here:https://brainly.com/question/25289437

#SPJ4

The general idea behind two-sample tests is to create a test statistic that represents:

a.The square of the average of the variations within the two individual groups.

b.The variation within the individual groups minus the variation between the two groups.

c.The variation within the individual groups divided by the variation between the groups.

d.The variation between the two groups minus the variation within the individual groups.

e.The variation between the two groups divided by the variation within the individual groups.

f.The square root of the variation between the two groups.

The correct answer is b. The **variation** within the individual groups minus the **variation** between the two groups.

**Two-sample tests** are statistical tests used to compare the means or variances of two **independent groups** or populations. The goal is to determine if there is a significant difference between the two groups based on the **observed data**.

In order to create a **test statistic** that represents the difference between the groups, we need to consider both the within-group **variation** (variability of data within each group) and the between-group variation (difference between the groups). By subtracting the within-group variation from the **between-group variation**, we can quantify the extent of the difference between the groups.

This **test statistic** is commonly used in various two-sample tests, such as the independent samples **t-test** and **analysis of variance** (ANOVA). It allows us to assess whether the observed difference between the groups is statistically significant, providing valuable insights into the relationship between the groups under **investigation**.

To learn more about **analysis of variance **click here : brainly.com/question/30847840

#SPJ11

PLEASE I NEED HELP ASAP PLEASE I NEED EXPLANATIONS FOR THESE ONES PLEASE

1. The **solution **to the equation is x = 19/4.

2. The **solutions **to the **equation **are x = -4 and x = 3.

1. To solve the equation 3/(x+2) = 1/(7-x), we can cross-multiply:

3(7-x) = 1(x+2)

21 - 3x = x + 2

21 - 2 = x + 3x

19 = 4x

x = 19/4

Therefore, the **solution **to the equation is x = 19/4.

2. To solve the equation (3-x)(x-5) - 2x² / (x²-3x-10) = 2/(x+2), we can simplify and rearrange the equation:

[(3-x)(x-5) - 2x²] / (x²-3x-10) = 2/(x+2)

**Expanding **the numerator and simplifying the denominator:

[(3x - 8 - x²) - 2x²] / (x² - 3x - 10) = 2/(x+2)

**Combining **like terms in the numerator:

[-3x² + 3x - 8] / (x² - 3x - 10) = 2/(x+2)

**Multiplying **both sides by (x² - 3x - 10) and simplifying:

-3x² + 3x - 8 = 2(x² - 3x - 10)

-3x² + 3x - 8 = 2x² - 6x - 20

Rearranging the equation to form a quadratic equation:

2x² - 3x² + 3x - 6x - 8 + 20 = 0

-x² - 3x + 12 = 0

-(x+4)(x-3) = 0

Setting each factor equal to zero and solving for x:

x+4 = 0 -> x = -4

x-3 = 0 -> x = 3

Therefore, the **solutions **to the **equation **are x = -4 and x = 3.

Learn more about **Quadratic Equation **here:

https://brainly.com/question/30098550

#SPJ1

Counting Principles Score 7/80 20/20 weet Scent try 1 of 4pts. See Decor sonry below ry, a player pros Hombers to 1104. afferent choices on the we Wonder citate There 494,481 to the lattery Question to do? Stron :: E R т. Y O S D F G H J к L X с V B N M . 36 mand CE

There are 3.72 × 10²⁵ different **possible outcomes**. If a player selects options from the given set, we need to calculate the number of possible different outcomes. It is a permutation problem

We are given that the player has different choices on the Wonder citate.

There are 494,481 to the lattery.

If a player selects options from the given set, we need to calculate the number of possible different outcomes.

It is a permutation problem, and we need to apply the formula for permutation to solve this problem.

Formula for **permutation** NPn= n!

Where n is the total number of items and Pn is the total number of possible arrangements.

Using the given values, we can apply the formula to get the number of possible outcomes:

Since we are given a set of 36** characters**, we can find the number of possible arrangements for 36 items:

nP36= 36!

nP36= 371993326789901217467999448150835200000000

nP36= 3.72 × 10²⁵

Using this formula, we get the number of **possible arrangements t**o be 3.72 × 10²⁵.

Therefore, the long answer is that there are 3.72 × 10²⁵ different possible outcomes.

To know more about **possible outcomes **visit :-

https://brainly.com/question/14690016

#SPJ11

Find the volume of the rectangular prism. 4 cm 3 cm 2 cm

The **volume **of the **rectangular prism** is 24 cm³

Calculating the volume of a rectangular prism

From the question, we are to calculate the **volume **of the **rectangular prism **with the given measurements

The given measurements are 4 cm, 3 cm, and 2 cm.

The volume of a rectangular prism can be calculated by using the formula,

Volume = Length × Width × Height

From the given information,

Let length = 4 cm

width = 3 cm

and height = 2 cm

Thus,

The volume of the rectangular prism is

Volume = 4 cm × 3 cm × 2 cm

Volume = 24 cm³

Hence, the **volume **is 24 cm³

Learn more on **Calculating volume of a prism **here: https://brainly.com/question/12676327

#SPJ1

Sketch the curve f(x, y) = c together with Vf and the tangent line at the given point. Then write an equation for the tangent line. 8x² - 3y = 43, (√√5, −1) Tangent line is 9xy = -45,

To sketch the curve defined by the equation** **f(x, y) = c, along with the **vector field Vf** and the tangent line at a given point. The equation of the tangent line is also provided. the equation of the tangent line is** 9xy = -45**.

The curve f(x, y) = c represents a level curve of the function f(x, y), where c is a constant. To sketch the curve, we can choose different values of c and plot the corresponding points on the **xy-plane**. The vector field Vf represents the gradient vector of the function f(x, y) and can be visualized by drawing arrows indicating the direction and magnitude of the gradient at each point.

In this specific case, the equation is given as** 8x² - 3y = 43**. To find the tangent line at the point (√√5, −1), we need to determine the gradient of the curve at that point. The** gradient vector** can be obtained by taking the partial derivatives of the equation with respect to x and y.

Once we have the gradient vector, we can find the equation of the **tangent line** using the point-slope form. Since the equation of the tangent line is provided as 9xy = -45, we can compare it with the general equation of a line (y - y₁) = m(x - x₁) to identify the slope and the point (x₁, y₁) on the line.

In this case, the equation of the tangent line is** **9xy = -45.

Learn more about ** gradient vector **here:

https://brainly.com/question/29751488

#SPJ11

A metropolitan police classifies crimes committed in the city as either "violent" or "non-violent". An investigation has been ordered to find out whether the type of crime depends on the age of the person who committed the crime. A sample of 100 crimes was selected at random from its files. The results are in the table: Age Type of crime under 25 25 to 50 over 50 violent 15 30 10 non-violent 5 30 10 (a) State the null and alternate hypotheses. (b) Does it appear that there is any relationship between the age of a criminal and the nature of the crime, at the 5% level of significance, using the critical value method? (c) List the assumptions associated with this procedure.

(a) Null **hypothesis:** The type of crime does not depend on the age of the person who committed the crime.

Alternate hypothesis: The type of crime depends on the age of the person who committed the crime.

(b) To determine if there is a relationship between the age of a criminal and the nature of the crime at the 5% level of significance, we can use the **critical** value method.

First, we need to calculate the expected values for each cell under the assumption of independence between age and type of crime. We can calculate the expected values using the row and column totals:

Expected value = (row total * column total) / sample size

Expected values for the table are as follows:

graphql

Copy code

Age | Type of Crime

| Violent | Non-violent | Total

CSS

Copy code

under 25 | 10 | 10 | 20

25 to 50 | 20 | 20 | 40

over 50 | 10 | 10 | 20

mathematical

Copy code

Total | 40 | 40 | 80

Next, we can calculate the** chi-square** statistic using the formula:

chi-square = ∑ ((observed value - expected value)^2) / expected value

Using the observed and expected values from the table, we can calculate the chi-square statistic:

chi-square = ((15-10)^2)/10 + ((30-20)^2)/20 + ((10-10)^2)/10 + ((5-10)^2)/10 + ((30-20)^2)/20 + ((10-10)^2)/10 = 1.5 + 2.5 + 0 + 2.5 + 2.5 + 0 = 9

To determine if there is a relationship between the age of a criminal and the nature of the crime, we need to compare the chi-square **statistic **to the critical value from the chi-square distribution table. The degrees of freedom for this test is (number of rows - 1) * (number of columns - 1) = (3-1) * (2-1) = 2.

Using a significance level of 5% and 2 degrees of freedom, the critical value is approximately 5.991.

Since the chi-square statistic (9) is greater than the critical value (5.991), we reject the null hypothesis. This suggests that there is a relationship between the age of a criminal and the nature of the crime.

(c) Assumptions associated with this procedure:

The data used for the analysis is a random **sample** from the population of crimes in the city.

The observations are independent of each other.

The expected values in each cell of the contingency table are not too small (typically, they should be at least 5).

The chi-square test assumes that the variables being analyzed are categorical and the data is frequency-based.

Learn more about **metropolitan police** at https://brainly.com/question/29037265

**#SPJ11**

A travel company reports the three most popular rides at a local amusement park are Ride A, Ride B and Ride C. A park employee wonders if they are equally popular.

540 randomly selected visitors to the park were asked which of the three rides they preferred most with the following results:

a) What is the appropriate statistical test to conduct for this scenario?

b) State the hypotheses for this test:

H0:

H1:

c) The test results is a chi-square statistic of 3.144 and a p-value of 0.208. Use a significance level of 0.05 to make a conclusion.

Do you reject or fail to reject the null hypothesis?

Explain:

Does the sample provide evidence that the rides are not equally popular?

Yes or No?

According to the question The sample provide **evidence** that the rides are as follows :

a) The appropriate **statistical** test to conduct in this scenario is the chi-square test for independence.

b) The hypotheses for this test are as follows:

H0: The rides are **equally** popular.

H1: The rides are not equally popular.

c) Given that the chi-square statistic is 3.144 and the p-value is 0.208, with a significance level of 0.05, we compare the p-value to the significance level to make a **conclusion**.

Since the p-value (0.208) is greater than the significance level (0.05), we fail to reject the null **hypothesis**.

Explanation:

Failing to reject the null hypothesis **means** that we do not have enough evidence to conclude that the rides are not equally popular based on the sample data.

The test does not provide **sufficient** evidence to suggest that the preferences for the rides are significantly different among the **visitors** surveyed. Therefore, we cannot conclude that the rides are not equally popular based on this sample.

To know more about **visitors **visit-

brainly.com/question/30620297

#SPJ11

Find the difference quotient of f; that is, find f(x+h)-f(x)/ h, h0, for the following function. Be sure to simplify."f(x)=2x-x-1 f(x+h)-f(x)/ h(Simplify your answer.)
what is the formula for titanium (iv) oxide?what is the formula for titanium oxide? ti4o ti2o tio2 tio4
Using Operational Theorems and the Table of Fourier Transforms determine the following: a) F (It-3Ie^-6It-3I) b) F^-1 (7e^-9(w-5)^2)c) F^-1 (3+iw/25+6jw-w^2)
The following is a binomial probability distribution with n=3 and pi= 0.20x: 0 1 2 3 4p(x): 0.512 0.384 0.096 0.008The mean of the Distribution is .
Which of the following questions about predatory pricing remains unresolved?A. Is predatory pricing ever a profitable business strategy?B. Are the courts capable of determining which price cuts are good for consumers?C. Are the courts capable of determining which price cuts are competitive and which are predatory?D. All of the above questions about predatory pricing are unresolved.
Solve the linear differential equation (x+5)-2xy = x(x + 5) cos2x
Samsung Mobile plans to launch a new phone with a unit cost of AED 3500 and wants to earn a 30 percent markup on its sales. Samsung's markup price is ________.a. 3500b. 5000c. 1766d. 6000e. None of the above answers is correct
Problem 3-24 (Algo) Timely Transport provides local delivery service for a number f downtown and suburban businesses. Delivery charges are based on distance and weight involved for each delivery: 25 c
Setch the graph of the following function and suggest something this function might be modelling: F(x) = (0.004x + 25 i f x 6250 ( 50 i f x > 6250
The series _(n=3)^[infinity](In (1+1/n))/((In n)In (1+n)) is convergent and sum its 1/In 3 convergent and its sum is 1/In 2 convergent and its sum is In 3 convergent and its sum is In 3/In 2
: Use the Finite Difference method to write the equation x" + 2x' - 6x = 2, with the boundary conditions x(0) = 0 and x(9)-0 to a matrix form. Use the CD for the second order differences and the FW for the first order differences with a mesh h=3.
What is the quantity of goods and services that sellers are willing and able to sell known as?
A lw is to load register $5 from location 0x0040000C in memory. Register $10 contains 0x00400000. Write the assembly language instruction: (Q15.9)a.lw $5,0x0C(400000)b.lw $10,0x0C($10)c.lw $10,0x0C($5)d.lw $5,0x0C($10)
1. Is a null hypothesis a statement about a parameter or a statistic?a.) Parameter b.) Statistic c.) Could be either, depending on the context2. Is an alternative hypothesis a statement about a parameter or a statistic?a.) Parameter b.) Statistic c.) Could be either, depending on the context
Glasgow plc has an investment in one company, Dundee Ltd. Glasgow plc acquired four million ordinary shares in Dundee Ltd on 1 January 2021 in a share exchange. One new ordinary share in Glasgow plc was issued for every two ordinary shares in Dundee Ltd acquired. The market price of one new Glasgow plc share at that date was 4. The share issue transaction has not yet been recorded in the draft financial statements of Glasgow plc. The draft summarised statements of financial position of the two companies at 31 March 2021 are shown below: Glasgow plc Dundee Ltd ASSETS Non-current assets 2,600,000 6,000,000 Property, plant and equipment Intangible assets 3,000,000 5,600,000 6,000,000 Current assets Inventories 3,000,000 4,000,000 Trade receivables 5,300,000 1,400,000 Cash and cash equivalents 300,000 600,000 8,600,000 6,000,000 Total assets 14,200,000 12,000,000 EQUITY AND LIABILITIES Equity Ordinary share capital (1 shares) 8,000,000 5,000,000 Retained earnings (2,600,000) 4,200,000 Total equity 5,400,000 9,200,000 Non-current liabilities Provisions 3,900,000 1,000,000 Current liabilities Trade and other payables 4,900,000 1,800,000 Total equity and liabilities 14,200,000 12,000,000 ADDITIONAL INFORMATION (1) Dundee Ltd's profit for the year to 31 March 2021 was 3.2 million. Profits accrued evenly over the year. No dividends were paid or proposed during the period. (2) Glasgow plc prefers to measure goodwill and the non-controlling interest using the fair value method. The fair value of the non-controlling interest at 1 January 2021 was 2,100,000. Following the annual impairment review of goodwill at 31 March 2021 an impairment loss of 100,000 needs to be recognised in respect of Dundee Ltd. (3) The fair value of the assets and liabilities of Dundee Ltd at 1 January 2021 was the same as their carrying amount with the following exceptions: The fair value of brands not previously recognised has been quantified at 400,000. Glasgow plc's management are of the opinion that these brands have an indefinite life. At the year end the recoverable amount of the brands was assessed at 360,000. The fair value of inventory was 200,000 greater than its carrying amount. One fifth of this inventory remained on hand at the year end. The allowance for receivables was understated by 300,000. This allowance was also still required at the year end. Equipment had a fair value of 1 million in excess of its carrying amount. The remaining useful life of this equipment was five years at 1 January 2021. These fair values have not been recognised in the separate financial statements of Dundee Ltd. (4) Glasgow plc sold inventory with an invoice value of 900,000 to Dundee Ltd in February 2021. One quarter of the inventory remained in Dundee Ltd's factory at 31 March 2021. Glasgow plc calculates the transfer price of goods using a mark up of 50% on cost. (5) Glasgow plc has recently reached an agreement with HMRC regarding its tax payable for the year ended 31 March 2021. It has agreed to pay an additional 200,000 income tax. No liability for this amount has been included in the draft statement of financial position at 31 March 2021. (6) Glasgow plc raised a 250,000 invoice for intra group management fees due from Dundee Ltd on 25 March 2021. This invoice was not received by Dundee Ltd until 3 April 2021 and has not been included in Dundee Ltd's draft financial statements. Glasgow plc has included the amount due of 250,000 in trade receivables. There were no other outstanding balances between the two companies at 31 March 2021. REQUIRED: Prepare the consolidated statement of financial position of Glasgow plc as at 31 March 2021.
it is important that log are regularly cleaned out to make room for new ones. in linux, what utility manages this?
Find the critical value of t for a two-tailed test with 13 degrees of freedom using a = 0.05. O 1.771 O 1.782 O 2.160 2.179
A machine that fills cereal boxes is supposed to be calibrated so that the mean fill weight is 12 oz. Let denote the true mean fill weight. Assume that in a test of the hypotheses H0 : = 12 versus H1 : 12, the P-value is 0.4a) Should H0 be rejected on the basis of this test? Explain. Check all that are true.NoYesP = 0.4 is not small.Both the null and the alternate hypotheses are plausible.The null hypothesis is plausible and the alternate hypothesis is false.P = 0.4 is small.b) Can you conclude that the machine is calibrated to provide a mean fill weight of 12 oz? Explain. Check all that are true.Yes. We can conclude that the null hypothesis is true.No. We cannot conclude that the null hypothesis is true.The alternate hypothesis is plausible.The alternate hypothesis is false.
transform the basis b = {v1 = (4, 2), v2 = (1, 2)} of r 2 into an orthonormal basis whose first basis vector is in the span of v1.
Key external forces are not always threats to a company.Can you determine some examples of positive external forces thatmay prove to be helpful to a company?