Two plates are 2cm apart, a potential difference of 10 V is applied
between them, find the electric field between the plates.

Answers

Answer 1

Answer:

The electric field betwee the plates is 500 V/m

Explanation:

Voltage

The electrical potential difference V between the two plates is expressed as

V=Ed

Where:

E = Electric field strength

d = Distance between the plates

It's expressed in Joules/coulomb, Volts/m or equivalent units.

The plates are separated d=2 cm and a potential difference V=10 V is applied. The electric field strength between the plates can be calculated by solving the formula for E:

[tex]\displaystyle E=\frac{V}{d}[/tex]

Converting cm to m: d=2 / 100 = 0.02 m

[tex]\displaystyle E=\frac{10\ V}{0.02\ m}[/tex]

Dividing:

E = 500 V/m

The electric field betwee the plates is 500 V/m


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Answers

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Answer:

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Explanation:

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i hope this helps