Mathematics High School

Two parallel lines are cut by a transversal as shown below.
Suppose m<8=109. Find m<2 and m<3.

Two Parallel Lines Are Cut By A Transversal As Shown Below.Suppose M&lt;8=109. Find M&lt;2 And M&lt;3.

Answers

Answer 1

Answer:

measure 2 has to be 109 due to the alternate interior angles theorem. Measure 3 has to be 71 due to the supplementary angles theorem.

Answer 2

Angles 8 and 2 are alternate interior angles so they will be the same therefore,m∠2 and m∠3 will be 109° and 71° respectively.

What is an angle?

An angle is a geometry in plane geometry that is created by 2 rays or lines that have an identical terminus.

The identical endpoint of the two rays—is known as the vertex.

Given two parallel lines a transversal.

Angles 8 and 2 are alternate interior angles.

m∠8 = m∠2

m∠2 = 108°

Now,m∠2 and m∠3 are supplementary angles.

Therefore,m∠3 = 180° - 108° = 71°

Hence "Angles 8 and 2 are alternate interior angles so they will be the same therefore,m∠2 and m∠3 will be 109° and 71° respectively".

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Answers

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b

Step-by-step explanation:

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Answers

Answer:

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usbqjqnamallqnbajabqjqnqkqlqlqllqqlqoqoqnajajhchhsgavbsujwhwjwjqqbq.

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What is the measure of angle x? Explain how you know.

Answers

Answer: x = 30' , y = 45'

hope this helps

Step-by-step explanation:

U is 90' it's a right triangle

well simple VRT you already know 2 angles which is 60' and 90'

R = 60'

V = 90'

T = x

you know that a triangle = 180'

so you do

180 - 60 - 90 = x

30 = x

if you want to do y

then you already know that U is 90' on both sides.

since you also know S,

S = 45'

U = 90'

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Answer:

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1) 20%
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The side length of the base of a square pyramid is 30 centimeters. The height of the pyramid is 45 centimeters.
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Answers

Answer:

volume = 13500 [tex]cm^{3}[/tex]

Step-by-step explanation:

For a given pyramid, its volume can be determined by:

volume of pyramid = [tex]\frac{lwh}{3}[/tex]

Where: l is the base length, w is the base width and h id the height of the pyramid.

For the given question, l 30 cm, w = 30 cm and h = 45 cm.

So that,

volume = [tex]\frac{30*30*45}{3}[/tex]

            = [tex]\frac{40500}{3}[/tex]

            = 13500

volume = 13500 [tex]cm^{3}[/tex]

The volume of the pyramid is 13500 [tex]cm^{3}[/tex].

The volume of the square-based pyramid is [tex]13500cm^3[/tex]

The volume of a pyramid is given by

[tex]V=\dfrac{Ah}{3}[/tex]

where

[tex]A=\text{area of the square base}\\h=\text{perpendicular height}[/tex]

The area of the square base, [tex]A[/tex], is calculated as follows

[tex]A=side^2\\=(30cm)^2\\=900cm^2[/tex]

substitute the value of [tex]A[/tex], and [tex]h[/tex] ([tex]45cm[/tex]) into the volume formula to calculate the pyramid's volume

[tex]V=\dfrac{Ah}{3}\\\\=\dfrac{900\times 45}{3}\\\\=13500cm^3[/tex]

Therefore, the volume of the pyramid is [tex]13500cm^3[/tex]

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We always combine the like terms in an expression when we simplify.

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