Two masses sit at the top of two frictionless inclined planes that have different angles,__deleted9917f34947e1359b5705bbac0d9227f8ec5df862078213a2db19c72f00189109deleted__ 0N86-C1-52-40-A837-22820 50% Part (a) What can be said about the speeds of the two masses at the bottom of their respective paths

Answer:

v = [tex]\sqrt{2gh}[/tex]

the speed in the two planes will be the same since it does not depend on the angle of the same

Explanation:

In this exercise we are told that the two inclined planes have no friction force, so we can apply the conservation of energy for each one, we will assume that the initial height in the two planes is the same

starting point. Highest part of each plane

         Em₀ = U = m g h

final point. Lowest part of each plane

        [tex]Em_{f}[/tex] = K = ½ m v²

as there is no friction, the mechanical energy is preserved

          Em₀ = Em_{f}

          mg h = ½ m v²

          v = [tex]\sqrt{2gh}[/tex]

As we can see, the speed in the two planes will be the same since it does not depend on the angle of the same

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