Two lamps rated 60W; 240V and 100W, 240Vrespectively are connected in series to a 240V power source. Calculate;
a) The resistance of each lamp.
b) The effective resistance of the circuit.
c) The current passing the lamps. pls answer correctly ​

Answers

Answer 1

Answer:

See the answers below.

Explanation:

The total power of the circuit is equal to the sum of the powers of each lamp.

[tex]P=60+100\\P=160 [W][/tex]

Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

[tex]P=V*I[/tex]

where:

P = power [W]

V = voltage [V]

I = current [amp]

[tex]I = P/V\\I=160/240\\I=0.67 [amp][/tex]

So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

a)

[tex]V=I*R[/tex]

where:

V = voltage [V]

I = current [amp]

R = resistance [ohms]

Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

[tex]P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R[/tex]

[tex]60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm][/tex]

b)

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

[tex]R = 133.66 + 225\\R = 358.67 [ohms][/tex]


Related Questions

A(n) ____________ stretch is one done where antagonist muscles are used to stretch the muscles. But the _____________ stretch is one that is done that the muscle needs help from something or someone to stretch the muscle.

Answers

Answer: Dynamic - Static Flexibility

Explanation:

help please asap due 20 minutes please help me ​

Answers

did you turn it in yet?

In a place covered by shadow of cloud sun cannot be seen . Explain with reasons .

Answers

Answer:

Because even though our eyes have a huge dynamic range (ability to pick out details in sharply lit and lesser lit areas simultaneously) than any camera, there's a limit.

When there's strong sunlight, your pupils contract and let less light in, which makes the shadows look darker.

When it's cloudy, your pupils widen and let more light in, which makes the shadows look less dark.

Do some experiments with a camera and you'll soon get the hang of it.

NOTE: Also test HDR (high dynamic range) photography, where the camera takes three or more pictures in quick succession, with different exposure settings, and combines them to get the most detail of both bright and dark areas. The result is more or less what we percieve.

How much would a pair of 0.5 kg shoes weigh on Earth? (Include units in
your answer) *

Answers

Answer:

1.1 lbs

Explanation:

To convert kg to lbs you multiply kilograms by 2.2. So 0.5kg × 2.2 equals to 1.1 lbs

The diagram shows a model of an atom. Who first proposed this model?
A. Bohr
B. Thomson
C. Rutherford
ОО
D. Dalton

Answers

A.Bohr

His model postulated the existence of energy levels or shells of electrons. Electrons could only be found in these specific energy levels; in other words, their energy was quantised, and couldn’t take just any value. Electrons could move between these energy levels but had to do so by either absorbing or emitting energy.

A. Bohr!

This answer is correct because I read the information.

what are the effects of moon rotation and revolution​

Answers

Answer:

The effects of the Moon's rotation includes;

1) The Moon rotation and revolution gives the appearance of a perfectly still Moon to observers of the Moon from the Earth

2) The Moon has two sides, the near side that continuously faces the Earth and the "back" or far side, which is also known as the dark side of the Moon

The effect of the Moon's revolution

1) The tides in the ocean and water bodies, due to the gravitational forces from the Moon

2) The changes in the observed shape of the Moon due to the amount of Sunlight that is able to be reflected from the Moon as a result of the relative position of the Moon, the Earth and the Sun, at a given point in time

3) Lunar and Solar eclipse, when the Earth and the Moon blocks the light coming from the Sun respectively, due to their combined revolution

Explanation:

The duration of the Moon's orbit round the Earth = 27.322 days

The time it takes the Moon to rotate round its axis = 27 days

The Moon is the closest cosmic body to the Earth.

a squirrel runs at a speed of 9.9 m/s with 25 J of kinetic energy

What is the squirrels mass

Answers

Answer:

yeet yeet yeet yeet

Explanation:

Kinetic energy (K.E):-

So, the Mass of the Squirrel is 0.51 Kg (or) 510 grams.

A squirrel runs at a speed of 9.9 m/s with 25 J of kinetic energy.

What is the squirrel’s mass?

Answer: 0.51 kg

an object has an mass of 15 kg and is falling at a rate of 2.0 m/s what is the momentum?

Answers

Answer:

30 kg.m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 15 × 2

We have the final answer as

30 kg.m/s

Hope this helps you

A golf ball is sitting on a tee. The ball is struck with a golf club and flies
through the air. How does the force on the club compare with the force on the
ball when momentum is transferred between the club and ball?

Answers

Answer:

c i kn now it is

Explanation:

show your work. john uses a 25N force to push a boulder off a cliff that is 312m tall. What is the work done on the boulder?​

Answers

Answer:7800

work=force x distance

Force in Newtons

Distance in Meters

Work in Joules

The circumference of the Earth is
approximately 40,075 kilometers.
How many significant figures are
there in the numerical value?

Answers

Answer:

5 sig figures

Explanation:

A hose on the ground projects a water current upwards at an angle 40 to the horizontal at velocity 20 m/s find height at which water hits a wall at 8 m away from the hose (consider that acceleration due to gravity =9.8 m/s2)

Answers

Answer:

The water hits the wall at a height of 5.38 m

Explanation:

Projectile Motion

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

The object describes a parabolic path given by the equation:

[tex]{\displaystyle y=\tan(\theta )\cdot x-{\frac {g}{2v_{0}^{2}\cos ^{2}\theta }}\cdot x^{2}}[/tex]

Where:

y   = vertical displacement

x   = horizontal displacement

θ   = Elevation angle

vo = Initial speed

The hose projects a water current upwards at an angle of θ=40° at a speed vo=20 m/s.

The height at which the water hits a wall located at x=8 m from the hose is:

[tex]{\displaystyle y=\tan40^\circ\cdot 8-{\frac {9.8}{2*20^{2}\cos ^{2}40^\circ }}\cdot 8^{2}}[/tex]

Calculating:

y = 5.38 m

The water hits the wall at a height of 5.38 m

A 250-kg moose stands in the middle of the railroad tracks in Sweden, frozen by the lights of an oncoming 10,000kg train traveling at 20m/s. Even though the engineer attempted in vain to slow the train down in time to avoid hitting the moose, the moose rides down the remaining track sitting on the train’s cowcatcher. What is the final velocity of the train and moose after the collision?
(Momentum & Impulse)

Answers

Answer:

The final velocity of the train and the moose after collision is approximately 19.51 m/s

Explanation:

The given mass of the moose, m₁ = 250 kg

The velocity of the moose, v₁ = 0

The mass of the oncoming train, m₂ = 10,000 kg

The velocity of the train, v₂ = 20 m/s

The velocity of the moose and the train after collision = v₃

By the principle of conservation of linear momentum, the total initial momentum before the collision = The total final momentum after collision

m₁·v₁ + m₂·v₂ = (m₁ + m₂)·v₃

Therefore, by substitution, we have;

250×0 + 10,000× 20 = (10,000 + 250) × v₃

200,000 = 10,250 × v₃

v₃ = 200,000/10,250 ≈ 19.51 m/s

The final velocity of the train and the moose after collision = v₃ ≈ 19.51 m/s

13. Austin rode his bike 10 m/s for two minutes. How far did he travel? A. 200 meters B. 1200 meters C. 1000 meters D. 20 meters​

Answers

Answer:

B. 1200

Explanation:

60 sec in one min in 2 min there will be 120 sec. 10x120=1200

Es muy común que cuando se viaja hacia un río o lago se juegue "ranita", el cual consiste en lanzar una piedra horizontalmente hacia adelante para que cuando ésta toque la superficie del agua haga varios "saltos" sobre el agua. Durante un juego de estos, un desocupado nota que una de las piedras que arroja se demora 0,4 s en tocar la superficie del agua y la toca a 2,5 m de la orilla del lago, desde donde fue lanzada. Encuentre: a) La altura de la que fue lanzada la piedra. b) La velocidad con la que fue lanzada.

Answers

Answer:

a) La piedra es lanzada desde una altura de 0,785 metros.

b) La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.

Explanation:

a) Dado que la piedra es lanzada horizontalmente, tenemos que la piedra experimenta un movimiento horizontal a velocidad constante y uno vertical uniformemente acelerado debido a la gravedad. La altura de la que fue lanzada la piedra se puede determinar mediante la siguiente ecuación cinemática:

[tex]y = y_{o}+v_{o,y}\cdot t +\frac{1}{2}\cdot g\cdot t^{2}[/tex] (1)

Donde:

[tex]y[/tex] - Altura final, medida en metros.

[tex]y_{o}[/tex] - Altura inicial, medida en metros.

[tex]v_{o,y}[/tex] - Componente vertical de la velocidad inicial, medida en metros por segundo.

[tex]t[/tex] - Tiempo, medido en segundos.

[tex]g[/tex] - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que [tex]y = 0\,m[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex], [tex]t = 0,4\,s[/tex] y [tex]g = -9,807\,\frac{m}{s^{2}}[/tex], entonces la altura inicial de la piedra es:

[tex]y_{o} = y-v_{o,y}\cdot t -\frac{1}{2}\cdot g\cdot t^{2}[/tex]

[tex]y_{o} = 0\,m-\left(0\,\frac{m}{s} \right)\cdot (0,4\,s)-\frac{1}{2}\cdot \left(-9,807\,\frac{m}{s^{2}} \right) \cdot (0,4\,s)^{2}[/tex]

[tex]y_{o} = 0,785\,m[/tex]

La piedra es lanzada desde una altura de 0,785 metros.

b) Ahora, obtenemos el componente horizontal de la velocidad inicial a partir de la siguiente ecuación cinemática:

[tex]v_{o,x} = \frac{x-x_{o}}{t}[/tex] (2)

Donde:

[tex]x_{o}[/tex], [tex]x[/tex] - Posiciones horizontales iniciales y finales, medidas en metros.

[tex]t[/tex] - Tiempo, medido en segundos.

Si tenemos que [tex]x_{o} = 0\,m[/tex], [tex]x = 2,5\,m[/tex] y [tex]t = 0,4\,s[/tex], entonces el componente horizontal de la velocidad inicial es:

[tex]v_{o,x} = \frac{2,5\,m-0\,m}{0,4\,s}[/tex]

[tex]v_{o,x} = 6,25\,\frac{m}{s}[/tex]

La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.

A friend is coming to Tim’s house to study after school. What directions would Tim give for reaching his house from the entrance of the school?
(I WILL GIVE BRAINLIEST)

Answers

Answer:

go up the street as you exit the house and make a right and keep going up for 3 blocks and you should see the school

The magnitude of vector vector A is 84.9 m and it points in the +y axis direction. The magnitude of vector vector B is 195.0 m and it points at an angle of 41.0° counterclockwise from +x axis. The magnitude of vector vector C is 126.2 m and it points in the +x axis direction.

Answers

Solution:

The magnitude of A vector is 84.9 m in the positive y-axis direction.

So the X component of A =0

     the Y component of A = 84.9 m

Now the magnitude of B vector is 195 m and it makes an angle of 41° in the direction from the positive x-axis direction.

So  the X component of B = B cos 41°

                                           = 195 x cos 41°

                                           = 195 x 0.75   = 146.25 m

   the Y component of B = B sin 41°

                                           = 195 x sin 41°

                                           = 195 x 0.65   = 126.75 m

Now it is given that vector C has a magnitude of 126.2 m and it makes a direction towards the positive x-axis.

So the X component of C =126.2 m

     the Y component of C = 0

Comparing all these, we get

1. B vector has the largest X component

2. B vector has the largest Y component

Jerry is pushing a 50-kg box across a moth floor with an acceleration of 0.6 m/s2. What force is he applying to the box? *

83.3 N
0.012 N
0
30 N

Answers

Answer:

30 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 50 × 0.6

We have the final answer as

30 N

Hope this helps you

NEED AWNSER NOW! WILL MARK BRAINLY! Which term is defined as the ratio of the speed of light in a vacuum to the speed of light in the material it is passing through?

index of reflection

index of refraction

angle of reflection

angle of incidence

Answers

Answer:

Index of refraction.

Answer:

index of refraction

Explanation:

I just took the k12 quiz.

Give one example where friction is useful. Can someone feed me with correct answer pls c:

Answers

Answer:

Friction is what holds your shoe to the ground. The friction present on the ice is very little, this is the reason why it is hard to walk on the slippery surface of the ice.

Explanation:

Keeping traction on a race track

Describe what happens to the moving boat when the oars are out of the water and the forward thrust is zero

Answers

Answer:

The boat won't be able to move if the oars were out and there was no thruster. If there was a flow of the water then yes there would be a moving boat.

When two ocean plates come together, one ocean plate __________________
under the other, causing a chain of ________________ __________________
to form.

Answers

Answer:

A subduction zone is also generated when two oceanic plates collide — the older plate is forced under the younger one — and it leads to the formation of chains of volcanic islands known as island arcs.

Explanation:

A wagon having a mass of 42 kg is accelerated across a level road at 1.50 m/s2. What net force acts on the wagon horizontally?​

Answers

Answer:

The net force acting on the wagon is 63 N

Explanation:

Net Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass (m) is:

F = m.a

Where (a) is the acceleration of the object.

The wagon has a mass of m=42 Kg is accelerated at [tex]a=1.5\ m/s^2[/tex]. The net force is:

F = 42*1.5

F = 63 N

The net force acting on the wagon is 63 N

draw position time graph when speed is increasing​

Answers

Explanation:

We need to draw position-time graph when the speed is increasing.

The slope of position-time graph gives the speed of an object.

Position means distance covered.

When the speed of an object is increasing with time. It means it is moving with increasing speed.

The attached figure shows the position -time graph when speed is increasing​.

A force of 30 N stretches a very light ideal spring 0.73 m from equilibrium. What is the force constant (spring constant) of the spring

Answers

The forces constant (spring constant) of the spring will be 41.09 N/m.

What is spring force?

The force required to extend or compress a spring by some distance scales linearly concerning that distance is known as the spring force. Its formula is;

F = kx

The given data in the problem is;

F is the spring force = 30 N

K is the spring constant= ?

x is the displacement of spring = 0.73 m

The spring constant is;

K =F/x

K=30/0.73

K=41.09 N/m

Hence the force constant (spring constant) of the spring will be 41.09 N/m.

To learn more about the spring force refer to the link;

https://brainly.com/question/4291098

#SPJ1

Can u anser 5,6 on the picture

Answers

Answer: Number 6 is Periods

Explanation:

Which electron dot diagram shows the bonding between 2 chlorine atoms?2 dots then C l with 2 dots above and 1 dot below then 2 dots then 2 dots then C l with 2 dots above and 1 dot below then 2 dots.2 dots then C l with 2 dots above and 2 dots below then 2 dots then C l with 2 dots above and 2 dot below then 2 dots.2 dots then C l with 2 dots above and 2 dots below then 1 dot then C l with 2 dots above and 2 dots below then 2 dots.2 dots then C l with 2 dots above and 1 dot below then 3 dots then 3 dots then C l with 2 dots above and 1 dot below then 2 dots.

Answers

Answer:

It is B

Explanation:

Answer: 2nd answer

Explanation: took exam

A man speeding at 40m/s decides to outrun the cops and starts to
accelerate at a rate of 2.5m/s2 for 12 seconds. What is the criminal's new
speed?

Answers

Answer:

70 m/s.

Explanation:

Given that,

Initial speed, u = 40 m/s

Acceleration = 2.5 m/s²

Time, t = 12 s

We need to find criminal's new  speed. Let it is v. Using equation of motion to find it as follows :

v = u +at

Substitute all the values

v = 40 + 2.5(12)

v = 70 m/s

So, the new speed is 70 m/s.

A 0.15 kg ball is moving with a velocity of
35 m/s. Find the momentum of the ball.

Answers

Answer:

5.25 kg.m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 0.15 × 35

We have the final answer as

5.25 kg.m/s

Hope this helps you

(Blank) is caused by plate motion.


It’s please help.

Answers

Answer:

heat

Explanation:

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