when two heavy hydrogens combine to for helium , it results in the formation of energy, and a neutron, along with the helium atom
Answer:
When two nuclei form one atom, fusion reactions occur. Two hydrogen atoms combine to produce helium with the sun's reaction. It looks very simplified as follows: H+ H + D + D + H + D. This is referred to as a mass deficit and that mass differential becomes energy.
Explanation:
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At room temperature a mystery substance is observed to take the shape of its container and can expand or be compressed to change its volume this mystery substance is most likely a:
A) liquid
B) solid
C) crystal
D) gas
Answer:
Gas
Explanation:
This is because a gas is the only substance in the given options which can be expanded or compressed as its particles are far away from each other. They can also take the shapes of the containers they are put in.
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Complete the following reaction.
14N+ on →?C+1H
18C
14
1 C
18C
Answer: The complete reaction is as follows.
[tex]^{14}_{7}N + ^{1}_{0}n \rightarrow ^{14}_{6}C + ^{1}_{1}H[/tex]
Explanation:
When nucleus of two or more atoms are bombarded together then it leads to the formation of new particles with new identity. This type of reaction are called nuclear reaction.
For example, [tex]^{14}_{7}N + ^{1}_{0}n \rightarrow ?C + ^{1}_{1}H[/tex]
Here, nitrogen atom when bombarded with a neutron then it is forming hydrogen and a carbon atom.
As total atomic mass on reactant side is (14 + 1) = 15
So, the atomic mass of carbon formed on product side is (15 - 1) = 14.
The number of protons holded by this carbon atom is (7 - 1) = 6.
Therefore, we can conclude that the complete reaction is as follows.
[tex]^{14}_{7}N + ^{1}_{0}n \rightarrow ^{14}_{6}C + ^{1}_{1}H[/tex]
Solution X is saturated at 40 g per 100 g of water. If 45 g of X is
dissolved in 150 g of water, will the solution be saturated,
unsaturated, or supersaturated?
Answer:
unsaturated
Explanation:
What is the wavelength of a photon with a frequency of 6.56 x 10^14 Hz?
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Answer:457
Explanation:
Which property typically indicates strong intermolecular forces are present in a liquid? A) low heat of vaporization B) low critical temperature C) low vapor pressure D) low boiling point E) low melting point
Answer:
C) low vapor pressure
Explanation:
Vapor pressure refers to the pressure created by the vapor produced at a given temperature in a closed container. The pressure created as a result of the production of vapor above the liquid in a closed container. Vapor pressure works as the result of the force of the intermolecular force. When a liquid does evaporates easily it exemplifies that it has low vapor pressure. When the liquid evaporates easily and quickly, it exemplifies that it has high vapor pressure.
Statement that express the property of intermolecular forces that is been exhibited by liquid is C: low vapor pressure.
Intermolecular forces can be regarded as forces that is found between molecules. One of the property of this intermolecular forces can be seen in liquid which low vapour pressure.Vapour pressure is used in knowing the liquid to change into the gaseous state, it is at that point that liquid will reach i.e equilibrium pressure when in closed container.
Therefore, option C is correct.
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A student combines a solution of NaCl(aq) with a solution of AgNO3(aq), and a precipitate forms. Assume that 50.0mL of 1.0MNaCl(aq) and 50.0mL of 1.0MAgNO3(aq) were combined. According to the balanced equation, if 50.0mL of 2.0MNaCl(aq) and 50.0mL of 1.0MAgNO3(aq) were combined, the amount of precipitate formed would:_________
Answer:
Based on the given information, the balanced equation is:
NaCl + AgNO3 = AgCl + NaNO3
Now the moles present in 50 ml of 1M NaCl is,
= 50 * 1/1000 mole = 0.05 mole
And the moles present in 50 ml of 1 M AgNO3 is,
= 50*1/1000 mole = 0.05 mole
Therefore, 0.05 mole of NaCl combines with 0.05 mole of AgNO3 to precipitate 0.05 mole of AgCl.
Now in the second case, to balance the chemical equation, 50 ml of 2 M NaCl combines with 50 ml of 1 M AgNO3. So, the moles present in 50 ml of 2 M NaCl will be,
= 50*2/1000 mole = 0.1 mole
However, the amount of AgNO3 in the second case is not changing, therefore, the amount of AgCl precipitated will be,
= 0.1 - 0.05 = 0.05 mole
Therefore, the amount of precipitate would not change as there is no change in the amount of AgNO3.
The amount of precipitate (NaCl) formed would be 0.05 mole
From the question,
We are to determine the amount of precipitate formed.
First, we will write the balanced chemical equation for the reaction
The balanced chemical equation for the reaction is
NaCl(aq) + AgNO₃(aq) → AgCl(s) + NaNO₃(aq)
This means
1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl and 1 mole of NaNO₃
The precipitate formed is AgCl
Now, we will determine the number of moles of each reactant present
For NaClVolume = 50.0 mL = 0.05 L
Concentration = 2.0 M
Using the formula
Number of moles = Concentration × Volume
∴ Number of moles of NaCl present = 2.0 × 0.05
Number of moles of NaCl present = 0.10 mole
For AgNO₃Volume = 50.0 mL = 0.05 L
Concentration = 1.0 M
∴ Number of moles of AgNO₃present = 1.0 × 0.05
Number of moles of AgNO₃ present = 0.05 mole
Since
1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl
Then,
0.05 mole of NaCl will react with 0.05 mole of AgNO₃ to produce 0.05 mole of AgCl
∴ The number of moles of NaCl formed is 0.05 mole
Hence, the amount of precipitate (NaCl) formed would be 0.05 mole
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Two ways that salinity can increase
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which of the following is always altered when a substance undergoes a chemical change?
A) mass of the substance
B) arrangement of the atoms composing the substance
C) color of the substance
D) state of matter of the substance
team rashta or navier ???
Answer:
navier
JAJDKEKWNEHSJJXIDJ (i need to do that so i can post the answer haha)
Answer: TEAM NAVIER FOR LIFEEEE
IF U SUPPORT TRASHTA, I HAVE NO WORDS TO DESCIRBE YOU
Is anyone good at chemistry if so Can someone help me please NO LINKS
Answer:
6.25 g
Explanation:
From the question given above, the following data were obtained:
Half-life (t½) = 68.8 years
Time (t) = 344 years
Original amount (N₀) = 200 g
Amount remaining (N) =?
Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:
Half-life (t½) = 68.8 years
Time (t) = 344 years
Number of half-lives (n) =
n = t / t½
n = 344 / 68.8
n = 5
Thus, 5 half-lives has elapsed.
Finally, we shall determine the amount of the Uranium-232 that remains. This can be obtained as follow:
Original amount (N₀) = 200 g
Number of half-lives (n) = 5
Amount remaining (N) =?
N = 1/2ⁿ × N₀
N = 1/2⁵ × 200
N = 1/32 × 200
N = 200 / 32
N = 6.25 g
Thus, the amount of Uranium-232 that remains is 6.25 g
1. A pure substance contains ONLY one kind of
Answer:
Elements
Explanation:
What is the mass of 3.32 mols of N2
please help:))))
Answer:
92.96 g
Explanation:
In order to calculate the mass of any number of moles of a given substance, we need to know the substance's molar mass:
Molar mass of N₂ = (Molar Mass of N)*2We can look for the molar mass of N in any periodic table.
Molar mass of N₂ = 28 g/molNow we proceed to calculate the mass of 3.32 moles of N₂:
3.32 mol * 28 g/mol = 92.96 gDeduce the differences that exist in the reaction represented by the diagrams. anyone??
Answer:
The one on the left has more products than reactants and is endothermic
The one on the right has more reactants than products and is exothermic
Explanation:
Endothermic: Energy is absorbed
Exothermic: Energy is released
if a soda can is opened and left on a scale fot 24 hours how might the final mass change?
Answer: If a soda can is opened and left on a scale for 24 hours then the final mass change will decrease.
Explanation:
A soda can is like any other carbonated beverage that contains carbon dioxide dissolved under pressure. So, when a soda can is opened then there will occur a release in pressure due to which excess of carbon dioxide gas moves out of the solution in the form of bubbles.
When soda can is remained open for 24 hours then additional carbon dioxide moves slowly into the air. As a result, there will occur a decrease in final mass change.
Thus, we can conclude that if a soda can is opened and left on a scale for 24 hours then the final mass change will decrease.
Please help ASAP look at the picture please
Answer:
A? its a tie between a and c but a makes the most sense and has the least amount of exceptions. Also that person who keeps sending those bit/ly links, are they legit or are they fake websites i shouldn't use?
Boiling water at sea level is hotter than boiling water in the
mountains.
Identify find a functional groups as indicated
How many molecules are in 5.40 mol of CO2?
Draw the organic product(s) of the following reactions, and include carbon dioxide if it is produced.
KMno4/H3O+
CH3CH2--C---C--H----------->
Answer:
Please find the attached file for the complete solution:
Explanation:
example of cyclization
Answer:
yes
Explanation:
yes
Which group on the periodic table is a noble gas most likely to bond with?
Answer:
The noble gases are the chemical elements in group 18 of the periodic table. They are the most stable due to having the maximum number of valence electrons their outer shell can hold. Therefore, they rarely react with other elements since they are already stable.Explanation:
Formic acid, HCOOH, is a major component in ant bites. Calculate the mass, in grams of 3.14 x 1023
molecules of formic acid.
Answer:
23.97 grams.
Explanation:
First we convert 3.14 x 10²³ molecules into moles, using Avogadro's number:
3.14x10²³ molecules ÷ 6.023x10²³ molecules/mol = 0.521 molesThen we convert 0.521 moles of HCOOH into grams, using the molar mass of formic acid:
0.521 mol * 46 g/mol = 23.97 gThe answer is 23.97 grams.
12. What did Darwin's ideas come to be known as? What is evolution?
If the temperature of 15 grams of water changes from 21C to 24C, how many joules of heat were involved? Show work
Answer:
189 Joules
Explanation:
Applying,
Q = cm(t₂-t₁)............. equation 1
Where Q = Heat, c = specific heat capacity of water, m = mass of water, t₁ = Initial Temperature, t₂ = Final temperature.
From the question,
Given: m = 15 grams = 0.015 kg, t₁ = 21 °C, t₂ = 24 °C
Constant: c = 4200J/kg.°C
Substitute these values into equation 1
Q = 0.015×4200×(24-21)
Q = 0.015×4200×3
Q = 189 Joules
What does electrical energy transform into when used by objects in a home?(2 points)
Batteries and solar panels
Liquid water and water vapor
Other forms of energy
Small particles of light
Answer:
Other forms of energy
Explanation:
none of the other answers could be correct.
Answer:
none of the other answers could be correct.
Explanation:
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Instructions
Balance each equation.Be sure to show off your lists! Remember you cannot add or place off coefficients in the middle of a chemical formula.
Example
2Na + MgF2 —-> 2NaF + 2Mg
Na= 2. Na=2
Mg= 1. Mg=1
F= 2. F=2
3. Cl₂ + 2KI --> 2KCl + I₂
Cl = 2 Cl = 2
K = 2 K = 2
I = 2 I = 2
4. 2NaCl --> 2Na + Cl₂
Na = 2 Na = 2
Cl = 2 Cl = 2
5. 4Na + O₂ --> 2Na₂O
Na = 4 Na = 4
O = 2 O = 2
6. 2Na + 2HCl --> H₂ + 2NaCl
Na = 2 Na = 2
H = 2 H = 2
Cl = 2 Cl = 2
7. 2K + Cl₂ --> 2KCl
K = 2 K = 2
Cl = 2 Cl = 2
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Answer:
90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you
Density measurements can be used to analyze mixtures. For example, the density of solid sand (without air spaces) is about 2.84 g/mL. The density of gold is 19.3 g/mL. If a 1.00 kg sample of sand containing some gold has a density of 3.10 g/mL (without air spaces), what is the percentage of gold in the sample
Answer:
Following are the responses to the given question:
Explanation:
Let S = solid sandy mass inside the blend
Let G = gold mass in such a blend
We search that percent G by mass
Mixture density = total blend mass / total blend volume = 3.10 g/mL
Mixture sum [tex]= S + G = 1 \ kg = 1000\ g[/tex]
Complete mixing volume = sand volume + gold volume volume
Complete mixing volume [tex]= (\frac{sand\ mass}{sand \ density}) + (\frac{gold\ mass}{gold \ density})[/tex]
Total mixture volume:
[tex]= (\frac{S}{2.84}) + (\frac{G}{19.3})\\\\ = \frac{(19.3 S + 2.84 G)}{54.812\ mL}[/tex]
[tex]\text{Mixture Density} = \frac{\text{mass mixture}}{\text{mixture volume}}[/tex]
[tex]= 3.10 \frac{g}{mL} \\\\ \to 3.10 = \frac{1000 \ g}{ \frac{(19.3 S + 2.84 G)}{ 54.812}}\\\\\to 19.3 S + 2.84 G = 17681[/tex]
When
[tex]S + G = 1000 \ g[/tex]
Solving equation:
[tex]\to 19.3 S + 2.84 G = 17 681\\\\\therefore \ S + G = 1000 \ g\\\\\to 19.3 S + 2.84 G = 17 681\\\\\to -2.84S -2.84 G = -2840\\\\----------------\\\\\to 16.46S = 14 841\\\\\to S = 901.7 g \ SanD[/tex]
When
[tex]\to S+ G = 1000\\\\\to G = 1000 - 901.7\ g\\\to G = 98.3 g \ GOLD[/tex]
Explain why the CO2 from your breath had the effect on the pH of water that it did. Explain any anomalies in your experiment.
Explanation:
As atmospheric CO2 levels increase due to anthropogenic causes, dissolved CO2 also increases, which in turn decreases the pH of water. When water becomes saturated with CO2, it not only reduces the ocean's pH, but depletes the calcium carbonate sources as well ³⁵
Calculate the temperature needed to increase 268mL of nitrogen gas at
25°C to 824mL.*
Answer:
643 °C
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 268 mL
Initial temperature (T₁) = 25 °C
Final volume (V₂) = 824 mL
Final temperature (T₂) =?
Next, we shall convert 25 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 25 °C
T(K) = 25 + 273
T(K) = 298 K
Next, we shall determine the final temperature. This can be obtained as follow:
Initial volume (V₁) = 268 mL
Initial temperature (T₁) = 298 K
Final volume (V₂) = 824 mL
Final temperature (T₂) =?
V₁/T₁ = V₂/T₂
268 / 298 = 824 / T₂
Cross multiply
268 × T₂ = 298 × 824
268 × T₂ = 245552
Divide both side by 268
T₂ = 245552 / 268
T₂ ≈ 916 K
Finally, we shall convert 916 K to celsius temperature. This can be obtained:
T(°C) = T(K) – 273
T(K) = 916 K
T(°C) = 916 – 273
T(°C) = 643 °C
Therefore, the final temperature is 643 °C