Two friends, Barbara and Neil, are out rollerblading. With respect to the ground, Barbara is skating due south at a speed of 4.6 m/s. Neil is in front of her. With respect to the ground, Neil is skating due west at a speed of 4.4 m/s. Find Neil's velocity (a) magnitude and (b) direction relative to due west, as seen by Barbara.

Option B

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Answer:

C. The potential energy of the particles increases as the intermolecular forces are overcome

Explanation:

Answer:

[tex]m=90.1kg[/tex]

Explanation:

From the question we are told that

Force F=39400

Initial speed [tex]V_1=35m/s[/tex]

Distance[tex]d=1.4m[/tex]

Generally the equation for acceleration is mathematically given by

[tex]a=\frac{V^2-U^2}{2d}[/tex]

[tex]a=\frac{0^2-35^2}{21.4}[/tex]

[tex]a=\frac{0^2-35^2}{21.4}[/tex]

[tex]a=-437.5m/sec^2[/tex]

Generally the equation for mass is mathematically given by

[tex]F=ma\\m=F/a[/tex]

[tex]m=\frac{-39400}{-437.5}[/tex]

[tex]m=90.1kg[/tex]

Answer:

1. This is a speed graph.

2. The slope represents how much the item/ thing is moving at how much distance it moved and the minutes it takes it too move how much distance, but the slope is representing the decrease and increase of it.

3. Increasing, kind of rapidly going up since the slope is rising not falling.

Answer:

ΔQ = 4896 KJ

Heat Flux = 57407.55 W/m²

Cost = $ 0.176

Explanation:

The amount of heat dissipated in two hours can be given as:

[tex]Heat\ Dissipation = \Delta Q = Pt\eta[/tex]

where,

P = Power of Iron = 800 W

t = time taken = 2 hrs

η = Conversion efficiency = 85% = 0.85

[tex]\Delta Q = (800\ W)(7200\ s)(0.85)\\\\[/tex]

ΔQ = 4896 KJ

Now, for heat flux:

[tex]Heat\ Flux = \frac{P}{Surface\ Area}\\\\Heat\ Flux = \frac{800\ W}{0.15\ ft^{2}}\frac{1\ ft^{2}}{0.092903\ m^{2}}[/tex]

Heat Flux = 57407.55 W/m²

Now, for total heat energy in KWhr in two hours:

[tex]Heat\ Energy = (Power)(Time)\\\\Heat\ Energy = (0.8\ KW)(2\ hr)\\\\Heat\ Energy = 1.6\ KWh[/tex]

Now, for the cost:

[tex]Cost = (Heat\ Energy)(Unit\ Cost)\\Cost = (1.6\ KWh)(\$ 0.11\ /KWh)[/tex]

Cost = $ 0.176

Answer:

266 m

Explanation:

Explanation:

K.E =1/2 mv^2

=1/2(156789)(45.6)^2

=78,394.5 × 2,079.36

=163,010,387.52 kg m/s

This should be your answer.

Option 3) a Soccer Ball

will travel the farthest distance.

Answer:

a bowling ball

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Answer:

In summation, acceleration can be defined as the rate of change of velocity with respect to time and the formula expressing the average velocity of an object can be written as: a =Δ v/ Δt The other 4 equations: d = vit+ (1/2) at2

Explanation:

Answer:

The point is neither maximum constructive interference nor perfect destructive interference, the interference is something in between.

Explanation:

Given data in the question;

first we find the wavelength of the sound λ

Then we find the path-length difference to the point from the two speakers, and divide it by the wavelength.

wavelength λ  = velocity / frequency = 340 m/s / 1700 Hz = 0.2 m

L1 = 4 m

L2 = √(4² +2² ) m

delta L = L2 - L1 = √(4² +2² ) m - 4 m = 0.472 m

x = deltaL / λ

If the result is nearly an integer, the waves reinforce at the point.

If it is nearly an integer + 0.5, the waves interfere destructively at the point.

If it is neither, the point is "something in between".

so we solve for  x

x = 0.472 m / 0.2m

x = 2.36

since its not an integer, it is not point maximum constructive interference

delta L = ( 2x + 1 ).λ/2

x = ((2deltaL/λ) - 1)/2

x = (((2×0.472)/0.2) - 1)/2

x = 3.72 / 2

x = 1.86

Here also, it is not an integer, so it is not a point perfect destructive interference.

Therefore, The point is neither maximum constructive interference nor perfect destructive interference, the interference is something in between.

Answer:

interna

Explanation:

please mark as brainllest

Answer:

60V

Explanation: . V = IR = 1

30*2=60

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Answer:

We can easily find out the beginning point of the line by using dot representation. When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system. The vector is a straight line that has a certain end which is fixed to its body.

Position vectors are used to determine the starting position of a line with reference to the origin or starting point of  the coordinate system

Position vectors start at the origin and terminate at any arbitrary point.

In terms of position of a line, position vectors depict the exact position of a line from the starting point of the coordinate system.

In terms of direction of the line, the direction of the position vector points from the starting point of  the coordinate system towards the given point.

Thus, we can conclude that position vectors are used to determine the starting position of a line with reference to the origin or starting point of  the coordinate system.

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Answer:

I think the answer is c electrical, and light , sound hewt

Answer:

22.5 hp

Explanation:

The power delivered to an object is given by :

[tex]P=F\times v[/tex]

Where

F is force and v is velocity of the car.

For the same force, power is directly proportional to the velocity.

So,

[tex]\dfrac{P_1}{P_2}=\dfrac{v_1}{v_2}\\\\P_2=\dfrac{P_1v_2}{v_1}\\\\P_2=\dfrac{15\times 30}{20}\\\\P_2=22.5\ hp[/tex]

So, the new power is 22.5 hp.

This question is incomplete, the complete question is;

A positive charge of magnitude Q1 = 6.5 nC is located at the origin.

A negative charge Q2 = -3.5 nC is located on the positive x-axis at x = 16.5 cm from the origin. The point P is located y = 10.5 cm above charge Q2.

Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.

Answer:

the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C    

Explanation:

Given the data in the question;

Q1 = 6.5 nC, Q2 = -3.5 nC

from the image below, to get our angle ∅

tan∅ = opp/adj

tan∅ = 10.5 / 16.5

tan∅ = 0.636363

∅ = tan⁻¹( 0.636363 )

∅ = 32.47°

also, r1 = √( 16.5² + 10.5²)

r1 = √( 272.25 + 110.25 )

r1 = √382.5

r1 = 19.55 cm = 0.1955 m

Now, the x-component of the electric field at point P due to charge Q1 will be;

Ex = E2cos32.47°

= (kQ1/r1²)cos32.47°

we know that;  k is Coulomb's law constant ( 9 × 10⁹ N.m²/ C²

Q1 = 6.5 nC = 6.5 × 10⁻⁹ C

so we substitute

= ((9 × 10⁹ × 6.5 × 10⁻⁹) / (0.1955)²) cos32.47°

= (58.5 / 0.03822025) × 0.843672

= 1291.33 N/C

Therefore, the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C

Answer:

Another term used to describe a wave is frequency. Since waves are moving, we define frequency as the number of waves that pass a given point in a specified unit of time. The unit commonly used is Hertz which is the number of wave cycles pass a point in one second. So one cycle per second equals one Hertz

Answer:

Explanation:

Force between charge is given by the following expression

F = k Q₁ Q₂ / R² , k = 9 x 10⁹ , Q₁ and Q₂ are charges , R is distance between charges .

Putting the given values ,

.85  = 9 x 10⁹ x 7.1 x 10⁻⁶ x Q₂ / 5.4²

Q₂ = .85 x  5.4² / (9 x 10⁹ x 7.1 x 10⁻⁶ )

= .38788  x 10⁻³ C .

= 387.88 x 10⁻⁶ C .

Answer:

F = 36 N

Explanation:

Given that,

Charge, q₁ = +8 μC

Charge, q₂ = -5 μC

The distance between the charges, r = 10 cm = 0.1 m

We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\F=36\ N[/tex]

So, the magnitude of the electrostatic force is 36 N.

Answer:

Δλ = 3*10⁻³ m.

Explanation:

       [tex]v = \lambda* f (1)[/tex]

       where v is the speed, λ is the wavelength and f is the frequency.

       [tex]\lambda = \frac{v}{f} (2)[/tex]

        [tex]\lambda_{1} =\frac{v}{f_{1}} = \frac{343m/s}{440(1/s)} = 0.779 m (3)[/tex]

        [tex]\lambda_{2} =\frac{v}{f_{2}} = \frac{343m/s}{442(1/s)} = 0.776 m (4)[/tex]

       [tex]\Delta \lambda = \lambda_{1} - \lambda_{2} = 0.779 m - 0.776m = 3e-3 m (5)[/tex]

       ⇒ Δλ = 3*10⁻³ m.

20 push ups

hope thats correct^^

Answer:

Workdone = 0.67 Joules

Explanation:

Given the following data;

Workdone = 6J

Extension = 43 - 28 = 15cm to meters = 15/100 = 0.15m

The workdone to stretch a string is given by the formula;

Workdone = ½ke²

Where;

k is the constant of elasticity.

e is the extension of the string.

We would solve for string constant, k;

6 = ½*k*0.15²

6 = ½*k*0.0225

Cross-multiplying, we have;

12 = 0.0225k

k = 12/0.0225

k = 533.33N/m

a. To find the workdone when e = 33, 38.

Extension = 38 - 33 = 5 to meters = 5/100 = 0.05m

Workdone = ½*533.33*0.05²

Workdone = 266.67 * 0.0025

Workdone = 0.67 Joules

Therefore, the amount of work (in J) needed to stretch the spring from 33 cm to 38 cm is 0.67.

Answer:

B. 2.5

not 2.5m because IMA is unitless.

The identical mechanical advantage of the inclined plane is 2.5.

The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane. The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.

Given parameters:

Length of the inclined plane; d = 5 m.

Height of the inclined plane; h = 2 m.

So, identical mechanical advantage (IMA) of the inclined plane is = Length of the inclined plane ÷ Height of the inclined plane

= 5 m/2 m

= 2.5.

Hence, the  identical mechanical advantage (IMA) of an inclined plane that is 5m long and 2m high is 2.5.

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Answer:

I think it's A, I'm not sure though

Answer:

Explanation:

We shall express each displacement vectorially , i for each unit displacement towards east , j for northward displacement and k for vertical displacement .

14 m due west = - 14 i

22.0 m upward in the elevator = 22 k

12 m north = 12 j

6.00 m east = 6 i

Total displacement = - 14 i + 22 k + 12 j + 6 i

D = - 8 i + 12 j + 22 k

magnitude = √ ( 8² + 12² + 22² )

= √ ( 64 + 144 + 484 )

= √ 692

= 26.3 m

Net displacement from starting point = 26.3 m .

Answer:

Explanation:

From the given information.

The charge density of the cylinder can be computed as:

[tex]\rho = \dfrac{Q_t}{V_t}[/tex]

where:

[tex]Q_t[/tex] = total charge on cylinder

[tex]\rho[/tex] = density of the cylinder

[tex]V_t =[/tex] net volume on cylinder

Considering the charge enclosed by the Gaussian surface; we have:

Q = ρV

Now, determining the volume of the cylinder at a distance r from the axis of the cylinder as follows:

[tex]\int Edsn = \dfrac{q}{\varepsilon_o}[/tex]

Here;

[tex]\hat E \ \ and \ \ \hat n[/tex] are in the same direction;

If we replace [tex]\int Edsn[/tex] with [tex]E ( 2 \pi rl)[/tex] and q with [tex]\rho \pi r^2 l[/tex]; Then:

[tex]E ( 2 \pi rl ) = \dfrac{\rho \pi r^2 l}{\varepsilon _o}[/tex]

By rearrangement;

[tex]E = \dfrac{\rho \pi r^2 l}{ ( 2 \pi rl ) \varepsilon _o}[/tex]

[tex]\mathbf{E = \dfrac{\rho r}{ 2 \varepsilon _o}}[/tex]

(b)

Using the same formula:

[tex]\int Edsn = \dfrac{q}{\varepsilon_o}[/tex]

where;

[tex]\hat E \ \ and \ \ \hat n[/tex] are in the same direction;

If we replace [tex]\int Edsn[/tex] with [tex]E ( 2 \pi rl)[/tex] and [tex]Q_t[/tex] with q;

Then:

[tex]E ( 2 \pi rl ) = \dfrac{Q_t}{\varepsilon _o}[/tex]

[tex]E = \dfrac{Q_t}{( 2 \pi R l ) \varepsilon _o}[/tex]

Replacing [tex]\lambda[/tex] for [tex]\dfrac{Q_t}{l}[/tex].

From above [tex]\lambda[/tex] = the charge per unit length

∴

[tex]\mathbf{E = \dfrac{\lambda}{ 2 \pi R \varepsilon _o}}[/tex]

Answer:

0.011 N-m

Explanation:

Given that

The mass of a solid cylinder, m = 30 kg

The radius of the cylinder, r = 0.18 m

The acceleration of the cylinder, [tex]\alpha =0.023\ rad/s^2[/tex]

It rotates about an axis through its center. We need to find the torque acting on the cylinder. The formula for the torque is given by :

[tex]\tau=I\alpha[/tex]

Where

I is the moment of inertia of the cylinder,

For cylinder,

[tex]I=\dfrac{mr^2}{2}[/tex]

So,

[tex]\tau=\dfrac{mr^2\alpha }{2}\\\\\tau=\dfrac{30\times (0.18)^2\times 0.023 }{2}\\\\\tau=0.011\ N-m[/tex]

So, the required torque on the cylinder is 0.011 N-m.

Answer:

Coulomb's law of Electrostatic Force states that a charged particle attracts or repels other charged particles with a force which is directly proportional to the product of their charges and inversely proportional to the square of the distance between their centers.

Explanation:

Answer:

1➡️ this is the method of decomposition

2➡️ H2 and O2

3➡️ b

sorry if I am wrong

Answer:

smallest area of the heel is 0.000168  m^2

Explanation:

Recall that pressure is defined as: Force / area. Therefore to reach a pressure of 3,500,000 Pa using a force: m * g = 60 kg * 9,8 m/s^2 = 588 N, one needs:

Area = 588 / 3500000 m^2 = 0.000168  m^2