Two clowns at a circus are performing an act in which one clown jumps down
on a seesaw and launches the other clown, who is standing on the opposite
end, as shown in the image below. Without losses due to friction or air
resistance, this process will go on forever in periodic motion. If the clown cn
the left has a mass of 75 kg and a starting height of 7 m, what is the
maximum height that the clown on the right can reach if she has a mass of
50 kg?
7m

Answers

Answer 1

Explanation:

mgh clown 1   =  75 kg * 9.81 m/s^2 * 7 m = 5150.25 J

   = mgh of clown 2

         5150.25 = 50 kg * 9.81 * h

                h = 10.5 m for clown 2


Related Questions

an astronaut of mass m is launched from the surface of the moon in a space craft having an initial vertical acceleration of 5g, where g is the acceleration of free fall in moon. the vertical reaction of the space craft on the astronaut is

Answers

The vertical reaction force R can be calculated as R = -8.1*m N, where the negative sign indicates that it acts in the opposite direction to the initial acceleration (which is upward in this case).

A reaction force is a force that is equal in magnitude but opposite in direction to an action force. It arises from Newton's third law of motion, which states that every action has an equal and opposite reaction. Whenever an object exerts a force on another object, the second object exerts a reaction force on the first object in the opposite direction.

The vertical reaction of the spacecraft on the astronaut is equal in magnitude but opposite in direction to the force that the astronaut exerts on the spacecraft, according to Newton's third law of motion.

The initial vertical acceleration of the spacecraft is 5g, so the force that the spacecraft exerts on the astronaut is F = ma = m(5g), where m is the mass of the astronaut.

Using the acceleration due to gravity on the moon, g = 1.62 m/s^2, we can calculate the force as:

F = m*(5g) = m*(51.62) = 8.1m N

Therefore, the vertical reaction of the spacecraft on the astronaut is equal in magnitude but opposite in direction, so it is:

R = -8.1*m N

Note that the negative sign indicates that the reaction force is in the opposite direction to the initial acceleration, which is upward in this case.

Hence, R = -8.1*m N is the reaction force.

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What is true about the requirements of your academic career plan

Answers

Academic career planning mainly needs, coordination of your educational requirements with your job ambitions.

ACP, or academic career planning, is a student-driven, adult-supported process whereby students develop their own distinct, knowledge-based visions for success after high school through self-exploration and career-reflection as well as the acquisition of career management and planning skills.

It requires the understanding of your abilities, values, and interests relate to potential occupations or jobs matching your abilities, matching your financial needs and career ambitions, etc.

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If the battery is 4.0V the voltmeter reading across R is 2.0V and the resistance per unit length of wire AX is 2 ohms per metre calculate the current in the circuit when AP is 40.0cm(neglect the internal resistance of the battery)

Answers

The current in the circuit is 2.5 A.

Voltage across the wire AX, V = 4 - 2 = 2V

Resistance per unit length of wire AX, R/l = 2 Ω/m

Length of the wire, l = 0.4 m

Resistance of the wire,

R = R/l x R

R = 2 x 0.4 = 0.8 Ω

According to Ohm's law, the current in the wire AX,

I = V/R

I = 2/0.8

I = 2.5 A

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• find the position at = 2.0s of mortocylist heading east through a small city accelerated After he passed The Signpost maketing the city limit his constant acceleraccetereted acceleration at time t=0 was 4- 0m/s² he was 5.0m east of the signpost moving east at Velocity of 15 m/s-​

Answers

At t = 2.0 s, the rider is 43.0 m east of the marker.

How to calculate position?

To solve this problem, use the kinematic equation:

x = x₀ + v₀×t + (1/2)at²

where x = final position,

x₀ = initial position, v₀ = initial velocity,

a = acceleration, and t is the time.

Given that the motorcyclist has a constant acceleration of 4.0 m/s², and initially 5.0 m east of signpost moving east at a velocity of 15 m/s, initial position and velocity:

x₀ = 5.0 m

v₀ = 15 m/s

Now, find the position at t = 2.0 s:

t = 2.0 s

a = 4.0 m/s²

x = x₀ + v₀t + (1/2)at²

x = 5.0 m + 15 m/s(2.0 s) + (1/2)4.0 m/s²(2.0 s)²

x = 5.0 m + 30 m + 8.0 m

x = 43.0 m

Therefore, the position of the motorcyclist at t = 2.0 s is 43.0 m east of the signpost.

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13. A solid has a mass of 200 g in air and when partly immersed in a certain liquid it has a mass of 160 g. Given that the relative density of the liquid is 0.80, calculate the volume of the solid immersed in the liquid.​

Answers

The volume of the solid immersed in the liquid is  5 x 10⁻⁵ m³.

What is the volume of the solid?

The volume of the solid is calculated as follows;

V = (Ws - Wa) / (ρg)

where;

Ws is the weight of the solid in airWa is the weight of the solid in liquidρ is the density of the solidg is gravity

Ws = 0.2 kg x 9.8 m/s²

Ws = 1.96 N

Wa = 0.16 kg x 9.8 m/s²

Wa = 1.568 N

ρ = 0.8 x 1000 g/km³ = 800 kg/m³

The volume is calculated as;

V = (1.96 - 1.568 )/(800 x 9.8)

V = 5 x 10⁻⁵ m³

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The car of mass mc rolls from rest with negligible friction down the curved ramp and around the circular loop. The initial height of the center of mass of the car is at height H. Assume the center of mass of the car is at a height equal to the diameter d of the loop when the car is at the top of the loop.
(a) In terms of the given quantities and any fundamental constants, derive an equation for the speed vtop at the top of the loop. (Neglect the rotational kinetic energy of the wheels).

(b) The car is upside down at the top of the loop. Derive an equation for the minimum speed vmin necessary to make the loop.

Answers

The speed at the top of the loop is √gR.

Let the starting point be A, the lower point of loop be B and the top of loop be C.

So, at A the car is having only potential energy.

PE = mgh

At B, the kinetic energy,

KE = 1/2 mv²

a) At point C,

mv²/R = mg

The velocity at the top point, v(C)

v(top) = √gR

b) According to Conservation of energy, at B and C,

1/2 mv(B)² = 1/2 mv(C)² + mg(2R)

v(B)² = gR + 4gR

Therefore, v(B) = √5gR

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Why is DNA a useful evolutionary clock?

Answers

Because analyzing DNA from present-day and ancient genomes provides a complementary approach for dating evolutionary events. Because certain genetic changes occur at a steady rate per generation, they provide an estimate of the time elapsed.

If you apply a greater force the spring constant will be

Answers

If you apply a greater force the spring constant will remain the same, since it is a constant.

What is Hooke's law?

This law states that the force applied to an elastic material is directly proportional to the extension of the material.

That is as the force applied to an elastic material increases the extension of the elastic material increases provided the elastic limit of the material is not exceeded.

Mathematically, this law can be written as;

F = kx

where;

F is the applied forcek is the spring constx is the extension of the material

So when the force applied is increased, the extension of the material increases as well.

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Help! Offering Brainliest & Points!
Match Letter's with image.

Answers

The correct match is A - trough, B - amplitude, C - crest, and D - wavelength.

A - A trough is the lowest point on a wave, where the displacement of the medium or the amplitude of the wave is at its minimum.

B - Amplitude refers to the maximum displacement or distance moved by a point on a vibrating body or wave, from its equilibrium position.

C - A crest is the highest point on a wave, where the displacement of the medium or the amplitude of the wave is at its maximum.

D - Wavelength is the distance between two corresponding points on a wave, such as the distance between two consecutive crests or troughs. It is often measured in meters or other units of length.

Hence, A - trough, B - amplitude, C - crest, and D - wavelength.

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A guitar string has a length of 65 cm (0.65 m). The frequency of C₂ is 65.4 Hz. The linear
mass density of the Az string is 0.0085 kg/m.
a) What is the frequency of Az? Use the tempered scale.
b) What is a wave speed of the second harmonic wave on the Az string!
c) What is the tension in this string?

Answers

The frequency of Az string is 0.818Hz.

Complete calculations of the string variables

Recall the formula:

f = (1/L) * sqrt(T/μ)

where

L = the length of the string,

T = the tension in the string,

μ = the linear mass density of the string,

f = the frequency.

Given

L = 0.65m, μ = 0.0085kg/m, and we want to find the frequency f.

To find the tension T, we can use the frequency of C₂, which is given as 65.4 Hz. The frequency of C₂ is related to the frequency of Az by the formula:

f(Az) = f(C₂) * 2^(n/12)

where n is the number of semitones between C₂ and Az. We can count the number of semitones using a piano keyboard or a frequency chart.

Az is two octaves lower than C₂, so n = -24.

Substituting the values, we get:

f(Az) = 65.4 Hz * 2^(-24/12) = 0.818 Hz

b) The wave speed of the second harmonic wave on the string can be found using the formula:

v = fλ

where

f = the frequency of the wave

λ = the wavelength

For the second harmonic wave, the wavelength is twice the length of the string, i.e:

λ = 2L = 1.3 m.

Substituting the values, we get:

v = (2f) * L = 2 * 0.818 Hz * 0.65 m ≈ 1.063 m/s

c) The tension in the string is given by the formula:

T = μ * f^2 * L^2

Substituting the values, we get:

T = 0.0085 kg/m * (0.818 Hz)^2 * (0.65 m)^2 ≈ 0.034 N

Therefore, the tension in the string is approximately 0.034 N.

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50 POINTS ANSWER CORRECTLY 4. Identify what elements are made in a Super Red Giant as it starts to die?

Answers

The super red giant star is the aging star and it is a dying star in the final stage of stellar evolution. From the burst of the super red giant star, magnesium is formed from the core of the red giant star.

The super red giant star has a larger mass and produces greater gravitational pressure. The giant red star is in the final stage of dying and the core of the red star has heavier elements like nitrogen, carbon, etc.

In the core of stars, nuclear fusion takes place. Nuclear fusion is the process of two lighter nuclei fusing or joining together to form a heavier nucleus.

The hydrogen fuses to form helium and helium fuses together to form carbon atoms. Carbon atoms fuse together to form oxygen atoms and it forms heavier elements like magnesium and iron.

Hence, from the burst of a super red giant star, heavier elements like magnesium, iron, carbon, and helium ions are formed.

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Can you find out the answers of 20,21,22,23?

Answers

Sentences 20, 21, 22, and 23 can be completed as follows:

20. B. Ultraviolet is used to observe star birth and far away galaxies.

21.  D. Radio waves is used to observe the depths of the Milky Way galaxy.

22. C. Gamma rays are used to observe supernova explosions and radioactive decay.

23. C. Wernher von Braun developed the V-2 rocket.

What are rays?

Rays are beams of light and radiation that can be harmful when used wrongly or advantageous for scientific purposes.

As scientists study extraterrestrial bodies, they often have to use rays for their findings. Gamma rays are known for their use in observing supernova explosions. Also, Wernher Braun is attributed to the development of the V-2 rocket.

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A box rests on a horizontal, frictionless surface. Ali pushes on the box with a force of 18 N to the right and Amina pushes on the box with a force of 12 N to the left. The box moves 4.0 m to the right.

a. Find the work done by Ali,
b. Find the work done by Amina,
c. the net force

Answers

The work done by Ali is 0 N

The work done by Amina is 72 N

The net force is 6 N

What is the work done by Ali and Amina?

The work done by a body is defined as the product of the force applied and the distance through which the force is applied.

Mathematically;

Work done = force * distance

The work done by Ali and Amina respectively is calculated using the formula above:

The work done by Ali = 12 * 0

The work done by Ali = 0 N

The work done by Amina = 18 * 4

The work done by Amina = 72 N

Net force = 18 - 12

Net force = 6 N

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A pendulum of mass 12 kg is released from rest at some height, as shown by
point A in the image below. At the bottom of its arc at point B, it is traveling at
a speed of 19 m/s. What is the approximate amount of energy that has been
lost due to friction and air resistance? (Recall that: g = 9.8 m/s²)

20 m

A35
B186
C78
D112

Answers

The energy lost to friction and air resistance is 186 J.

option B.

What is the energy lost to friction and air resistance?

The energy lost to friction and air resistance is calculated from the change in the mechanical energy of the pendulum.

The initial potential energy of the pendulum at the initial position is calculated as;

PEi = mghi

where;

m is the massg is gravityh is the initial height

P.Ei = 12 kg x 9.8 m/s² x 20 m

P.Ei = 2,352 J

The final kinetic energy of the pendulum is calculated as follows;

K.Ef = 0.5 x 12 kg x (19 m/s)²

K.Ef = 2,166 J

ΔE = 2,166 J - 2,352 J

ΔE = -186 J

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In which stage is the individual aware of the problem and beginning to think
about changing but has made no commitment to change, as they still believe
that the positive aspects outweigh the negative aspects?
OA. Maintenance
OB. Precontemplation
OC. Action
OD. Contemplation

Answers

Answer:

B. Pre-contemplation

Explanation:

Hope this helps :)

A student is investigating what happens when a neutral metal sphere sitting on an insulated stand is touched by negatively charged rod. the set up for the students investigation as shown in the diagram. what will happen to the excess electrons when the negatively charged rod touches the medal sphere 

Answers

The sphere will become negatively charged.

What happens?

When a neutral metal sphere comes into touch with a negatively charged rod, some of the excess electrons from the rod move to the sphere, making it negatively charged.

The extra electrons that are delivered to the sphere will disperse uniformly across its surface, rejecting one another and maintaining the surface by means of electrostatic forces.

Until the negative charge is discharged or somehow neutralized, the sphere will remain negatively charged.

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Find the equivalent resistance between points A and B
shown in Figure 31.

Answers

The equivalent resistance between points A and B is 0.837Ω.

Resistors in series are connected end-to-end so that the current flows through them in sequence. The equivalent resistance of resistors in series is the sum of their individual resistances.

The formula for equivalent resistance of resistors in series: R_eq = R_1 + R_2 + ... + R_n

Resistors in parallel are connected across each other so that the voltage is the same across each resistor. The equivalent resistance of resistors in parallel is the reciprocal of the sum of the reciprocals of their individual resistances.

The formula for equivalent resistance of resistors in parallel: 1/R_eq = 1/R_1 + 1/R_2 + ... + 1/R_n

Here in the Fig.

we can simplify the second set of resistors in parallel (4.8 Ω, 3.3 Ω, and 8.1 Ω) using the same formula:

1/Req1 = 1/4.8 + 1/3.3 + 1/8.1

Req1=1.575Ω

This Req1 connected series with 6.3Ω, then Req of this two resistance given by:

Req2= 1.575Ω+ 6.3Ω

Req2=7.875Ω

Once again this req2 makes the parallel with the other two resistance i. e 1.5Ω and 2.5Ω

Their equivalent resistance  is given by,

1/Req3=1/1.5 + 1/2.5 + 1/7.875

Req3=0.837Ω

Hence, The equivalent resistance between points A and B is 0.837Ω

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21.
is a process that returns to its beginning and repeats itself in the same sequence.
a. Cycle
b. Heat
c. Amplitude

Answers

Answer:

The Correct answer is A

cycle

Answer:

A. Cycle A cycle is a series of events or processes that is repeated again and again, always in the same order.

Explanation:

Two moles of helium gas initially at 170 K
and 0.23 atm are compressed isothermally to
1.78 atm.

1): Find the final volume of the gas. Assume
that helium behaves as an ideal gas. The
universal gas constant is 8.31451 J/K · mol.
Answer in units of m3

2): Find the work done by the gas.
Answer in units of kJ.

3): Find the thermal energy transferred.
Answer in units of kJ.

Answers

The gas's final volume is 0.129 m³ times its beginning volume.

The work done by the gas is -2.6226 kJ, indicating that work is being done on the gas.

The transmitted thermal energy is also -2.6226 kJ.

How to calculate volume, work done and thermal energy?

Using the ideal gas law to solve for the final volume of the gas:

PV = nRT

where P = pressure, V = volume, n = number of moles, R = gas constant, and T = temperature.

Since the process is isothermal, the temperature remains constant at 170 K, therefore:

P₁V₁ = P₂V₂

where P₁ and V₁ = initial pressure and volume, and P₂ and V₂ = final pressure and volume.

Substituting the given values:

(0.23 atm)(V₁) = (1.78 atm)(V₂)

Solving for V₂:

V₂ = (0.23/1.78)V₁ = 0.129 V₁

So the final volume of the gas is 0.129 times the initial volume.

To find the work done by the gas, use the formula:

W = -∫PdV

where the integral is taken from the initial volume V₁ to the final volume V₂. Since the process is isothermal:

W = -nRT ln(V₂/V₁)

Substituting the given values:

W = -(2 mol)(8.31451 J/K·mol)(170 K) ln(0.129) = -2622.6 J = -2.6226 kJ

So the work done by the gas is -2.6226 kJ, which means work is done on the gas.

The thermal energy transferred during the process is equal to the work done by the gas, since the process is isothermal and there is no change in internal energy. Therefore, the thermal energy transferred is also -2.6226 kJ.

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An object that is 0.5 m above the ground has the same
amount of potential energy as a spring that is stretched
0.5 m. Each distance is then doubled.
How will the potential energies of the object and the
spring compare after the distances are doubled?
O The gravitational potential energy of the object will be
two times greater than the elastic potential energy of
the spring.
O The elastic potential energy of the spring will be four
times greater than the gravitational potential energy of
the object.
O The elastic potential energy of the spring will be two
times greater than the gravitational potential energy of
the object.
O The potential energies will remain equal to one
another.

Answers

The gravitational potential energy of the object will be two times greater than the elastic potential energy of the spring after the distances are doubled. The correct option is A.

The gravitational potential energy of an object is given by the formula:

PE = mgh

Where m is the mass of the object, g is the acceleration due to gravity and h is the height of the object above the reference point.

In this case, the height of the object is doubled, so the potential energy will also be doubled. Therefore, when the distance is doubled, the gravitational potential energy of the object will be two times greater than before.

The elastic potential energy of a spring is given by the formula:

PE = 1/2 kx^2

Where k is the spring constant and x is the displacement of the spring from its equilibrium position.

In this case, the displacement of the spring is doubled, so the potential energy will be four times greater than before. Therefore, option B is not correct.

Option C is also not correct because the potential energy of the spring will be four times greater than the gravitational potential energy of the object.

Option D is not correct because the potential energies of the object and the spring are not equal to one another when the distances are doubled.

Therefore, The correct answer is option A.

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Answer correctly ill give brainliest!! Describe how carbon was formed and eventually end up in your body. Your description needs to explain how a star was once born and eventually produced the carbon. Then you are to explain how that carbon end up in our planet and eventually ended up in your body. You need to be very specific and clear in your explanation. You will need more than one sentence to answer this question. Bonus if you incorporate the carbon cycle in your answer

Answers

Answer: Carbon is the chemical backbone of life on Earth. Carbon compounds regulate the Earth’s temperature, make up the food that sustains us, and provide energy that fuels our global economy.

A diagram of the carbon cycle with arrows showing the movement of carbon through a landscape with plants and animals, mountains and a volcano, a river leading to the ocean, and an industrial area. Carbon moves in and out of our atmosphere, ocean, waterways, and soil through burning fossil fuels, precipitation, fires, vegetation, volcanoes, and organic processes.

The carbon cycle. (Image credit: NOAA)

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Most of Earth’s carbon is stored in rocks and sediments. The rest is located in the ocean, atmosphere, and in living organisms. These are the reservoirs through which carbon cycles.

This graph shows the monthly mean carbon dioxide measured at Mauna Loa Observatory, Hawaii, the longest record of direct measurements of CO2 in the atmosphere.

Climate change: Atmospheric carbon dioxide

Carbon dioxide concentrations are rising mostly because of the fossil fuels that people are burning for energy.

Carbon storage and exchange

Carbon moves from one storage reservoir to another through a variety of mechanisms. For example, in the food chain, plants move carbon from the atmosphere into the biosphere through photosynthesis. They use energy from the sun to chemically combine carbon dioxide with hydrogen and oxygen from water to create sugar molecules. Animals that eat plants digest the sugar molecules to get energy for their bodies. Respiration, excretion, and decomposition release the carbon back into the atmosphere or soil, continuing the cycle.

The ocean plays a critical role in carbon storage, as it holds about 50 times more carbon than the atmosphere. Two-way carbon exchange can occur quickly between the ocean’s surface waters and the atmosphere, but carbon may be stored for centuries at the deepest ocean depths.

Rocks like limestone and fossil fuels like coal and oil are storage reservoirs that contain carbon from plants and animals that lived millions of years ago. When these organisms died, slow geologic processes trapped their carbon and transformed it into these natural resources. Processes such as erosion release this carbon back into the atmosphere very slowly, while volcanic activity can release it very quickly. Burning fossil fuels in cars or power plants is another way this carbon can be released into the atmospheric reservoir quickly.

A research vessel ploughs through the waves, braving the strong westerly winds of the Roaring Forties in the Southern Ocean, in order to measure levels of dissolved carbon dioxide in the surface of the ocean.

Southern Ocean confirmed as strong carbon dioxide sink

New research utilizes airborne measurements of carbon dioxide to estimate ocean uptake.

Changes to the carbon cycle

Human activities have a tremendous impact on the carbon cycle. Burning fossil fuels, changing land use, and using limestone to make concrete all transfer significant quantities of carbon into the atmosphere. As a result, the amount of carbon dioxide in the atmosphere is rapidly rising; it is already greater than at any time in the last 3.6 million years. The ocean absorbs much of the carbon dioxide that is released from burning fossil fuels. This extra carbon dioxide is lowering the ocean’s pH, through a process called ocean acidification. Ocean acidification interferes with the ability of marine organisms (including corals, Dungeness crabs, and snails) to build their shells and skeletons.

An aerial view of Century City section of Los Angeles, California.

Atmospheric carbon dioxide rebounds as global pollution rates approach pre-Covid levels

Global carbon emissions are projected to bounce back to after an unprecedented drop caused by the response to the coronavirus pandemic, according to an annual report by the Global Carbon Project.

EDUCATION CONNECTION

Take a bite of dinner, breathe in air, or a drive in a car — you are part of the carbon cycle. The resources in this collection provide real world examples of the changes occurring in the cycle. There is much to learn about this essential topic, and some of the resources highlight exciting career opportunities in this field of study.

Explanation: learn from a middle schooler like me smart

Carbon was formed in stars through nuclear fusion and scattered into space when the star died. Carbon was incorporated into organic molecules through photosynthesis and eventually became part of animals' bodies. The carbon cycle involves the uptake of carbon dioxide by plants, transfer to animals, and release back into the atmosphere through respiration and decomposition, and human activities have disrupted this cycle.

Carbon was formed in the universe through nuclear fusion reactions that took place in the cores of stars. These reactions fused lighter elements into heavier ones, including carbon. When the star eventually died in a supernova explosion, the carbon and other elements were scattered into space.

The carbon, along with other elements, eventually formed clouds of gas and dust that coalesced to form new stars and planets. On our planet, carbon was incorporated into organic molecules through photosynthesis by plants and other photosynthetic organisms. These organic molecules were then consumed by animals, which allowed the carbon to become part of their bodies.

The carbon cycle is the process by which carbon moves through the Earth's atmosphere, oceans, and biosphere. This cycle involves the uptake of carbon dioxide by plants through photosynthesis, the transfer of carbon from plants to animals through the food chain, and the release of carbon back into the atmosphere through respiration and decomposition. Human activities, such as the burning of fossil fuels, have disrupted this cycle, leading to increased levels of carbon dioxide in the atmosphere and contributing to climate change.

Therefore, Nuclear fusion in stars produces carbon, which is then released into space when the star dies. By photosynthesis, carbon was added to organic molecules, eventually becoming a component of animal bodies. Human activities have interrupted the carbon cycle, which involves the intake of carbon dioxide by plants, its transport to animals, and its release back into the atmosphere through respiration and decomposition.

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In a 'keep-fit' exercise, a student of mass 45 kg steps 40 times on and off a box of height 0.50 m. How much work does the student do to raise her body each time she steps on the box

Answers

Answer:Calculate the work done using:

work done (in joules) = force (in newtons) x distance moved (in metres)

To practice calculations involving force, distance and work done.

Explanation: I hope this helps srry if I'm wrong

A gasoline engine has a power output of 210 kW (about 282 hp ). Its thermal efficiency is 28.5%.
a) How much heat must be supplied to the engine per second? Express your answer in joules.
b) How much heat is discarded by the engine per second? Express your answer in joules.

Answers

The heat supplied the engine per second is 736 kJ and the heat discarded by the engine per second is 526 kJ.

A gasoline engine has a power output of 210kW and the effciency of engine is 28.5%. The Work done of the engine in time 1s is,

Work done = power × time

                   = 210 × 1

                  = 210 kJ

The work done of the engine is,W = 210 kW.

The efficiency of the engine,η = Work / (Qh)

Qh is the heat suppllied to the engine, η is the efficiency and is equal to 28.5 %

Qh = 210kW / (0.285)

    = 736.8 kW

The heat discarded by the engine,

(Qc) = Qh - W'

       =  736.8 - 210

       =526.8 kW

The heat discarded by the engine, (Qc) = 526.8 kW

The heat supplied to the engine, (Qh) = 736.8 kW.

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What is true about the requirements of your academic career plan

Answers

A true statement on the requirements of an academic career plan is that it can help you withstand challenges better as you know the direction you are trying to get to.

What is an academic career plan ?

A student's personalized guide composed of their academic and professional objectives is known as an academic career plan. Such a plan illuminates the steps and resources they require to fulfill these aspirations.

It encompasses pinpointing said student's areas of expertise as well as areas in need of growth, discerning potential vocation paths, and determining which abilities, know-how, and experience they must accumulate. To efficiently reach their aims, they may utilize short and long-term goals, methodologies for accomplishing them, and frequent revisions to monitor progress.

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Physic question help

Answers

The good conductors of heat and electricity are Penny, and An aluminum soda can.

option A and B.

What are good conductors of electricity?

Good conductors of electricity are those materials that allow easy passage of electric current through them.

All metals are good conductors of electricity, and some of their examples include;

Aluminum

Copper

Silver

Zinc, etc

Poor conductors on the other hand do not allow easy passage of electric current through them.

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A physical science test book has a mass of 2.2 kg what is the weight on the earth 4 box method

Answers

The weight of the box is determined as 21.56 N.

What is the weight of the box?

The weight of the box is calculated by applying Newton's second law of motion as shown below;

F = mg

where;

m is the mass of the boxg is acceleration due to gravity

The weight of the box is calculated as follows;

W = 2.2 kg x 9.8 m/s²

W = 21.56 N

Thus, the weight of the box is determined by multiplying the mass and acceleration due to gravity.

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Two people hold a rope at either end. One person moves his end of the rope at a frequency of 4.0 Hz and a wavelength of 0.8 m. At what speed does the wave travel through the rope ?

Answers

Answer :

Speed = 3.2 m/s

Explanation :

According to the question, It's given that Two people hold a rope at either end. One person moves his end of the rope at a frequency of 4.0 Hz and a wavelength of 0.8 m.

Frequency (f) = 4.0 HzWavelength [tex] (\lambda)[/tex] = 0.8 m

We know the relationship between frequency and Wavelength. It states that wave speed is equal to the product of frequency and Wavelength .

v = f [tex] \lambda[/tex]

where,

f is frequency i.e 4.0 Hz , [tex] (\lambda)[/tex] is Wavelength i.e 0.8 m

Substituting the values,

[tex]: \implies[/tex]v = 4.0 × 0.8

[tex]: \implies[/tex] v = 3.2 m/s

Therefore, At the speed of 3.2 m/s the wave travel through the rope.

A certain rigid aluminum container contains a liquid at a gauge pressure of P0 = 2.02 × 105 Pa at sea level where the atmospheric pressure is Pa = 1.01 × 105 Pa. The volume of the container is V0 = 2.45 × 10-4 m3. The maximum difference between the pressure inside and outside that this particular container can withstand before bursting or imploding is ΔPmax = 2.35 × 105 Pa.

For this problem, assume that the density of air maintains a constant value of ρa = 1.20 kg / m3 and that the density of seawater maintains a constant value of ρs = 1025 kg / m3.


A) The container is taken from sea level, where the pressure of air is Pa = 1.01 × 105 Pa, to a higher altitude. What is the maximum height h in meters above the ground that the container can be lifted before bursting? Neglect the changes in temperature and acceleration due to gravity with altitude.

B)What is the maximum depth dmax in meters below the surface of the ocean that the container can be taken before imploding?

Answers

The maximum height the container can be lifted before bursting is  970 meters above sea level, and the maximum depth the container can be taken before imploding is 35 meters below the surface of the ocean.

Gauge pressure is the pressure measured relative to the atmospheric pressure at a particular location. It does not take into account the atmospheric pressure and only represents the pressure above or below the atmospheric pressure.

A) To find the maximum height h in meters above the ground that the container can be lifted before bursting, we need to find the new gauge pressure at this higher altitude. We can use the relationship between pressure and altitude:

P = P0 + ρgh

where P is the gauge pressure at the new altitude, ρ is the density of air, g is the acceleration due to gravity (assumed constant), and h is the height above sea level. Solving for h, we get:

h = (P - P0) / (ρg)

We know that the maximum pressure difference the container can withstand is ΔPmax = 2.35 × 105 Pa, so the new gauge pressure at the higher altitude can be found by adding this to the sea level pressure:

P = Pa + ΔPmax = 1.01 × 105 Pa + 2.35 × 105 Pa = 3.36 × 105 Pa

Substituting this into the equation above, along with the given values for ρ and g, we get:

h = (3.36 × 105 Pa - 2.02 × 105 Pa) / (1.20 kg/m3 × 9.81 m/s2) ≈ 970 meters

So, the maximum height the container can be lifted before bursting is approximately 970 meters above sea level.

B) To find the maximum depth dmax in meters below the surface of the ocean that the container can be taken before imploding, we need to find the new gauge pressure at this depth. We can use a similar equation to the one used above, but with the density of seawater instead of the density of air:

P = P0 + ρsgd

where g is the acceleration due to gravity (assumed constant), d is the depth below the surface of the ocean, and ρs is the density of seawater. Solving for d, we get:

d = (P - P0) / (ρsg)

We know that the maximum pressure difference the container can withstand is ΔPmax = 2.35 × 105 Pa, so the new gauge pressure at the maximum depth can be found by subtracting this from the sea level pressure:

P = P0 - ΔPmax = 2.02 × 105 Pa - 2.35 × 105 Pa = -0.33 × 105 Pa

(Note that this gives a negative value for pressure, which means the container will implode rather than burst.)

Substituting this into the equation above, along with the given values for ρs and g, we get:

d = (-0.33 × 105 Pa - 1.01 × 105 Pa) / (1025 kg/m3 × 9.81 m/s2) ≈ -35 meters

So, the maximum depth the container can be taken before imploding is approximately 35 meters below the surface of the ocean.

Therefore, The container can be lifted to a maximum height of 970 meters above sea level without bursting, and it can be submerged to a maximum depth of 35 meters without imploding.

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OA. Elements in the same row of the periodic table have the same
number of electrons.
B. The periodic table is organized by atomic number.
OC. There are two different ways to number the groups of the perio
table.
OD. Each box on the table represents one element.
SUBMIT

Answers

The statement that is true about the periodic table is The periodic table is organized by atomic number. Option B

What is true about the periodic table?

The periodic table is arranged by atomic number, which denotes the number of protons in an atom's nucleus.

Elements are organized in ascending atomic number sequence from left to right and top to bottom.

Given that the elements in the same column (group) often have comparable qualities due to the same amount of valence electrons, this organization allows the elements to be categorized based on their chemical properties.

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12. The distance an object has traveled when starting at an initial velocity is given by the equation:
d = vit +at². In the equation, vi represents the initial velocity, t represents the time traveled, and
a represents the acceleration. Solve the equation for a.

Answers

The equation for acceleration is:

a = (d - vi*t) / t²

The distance an object  traveled when starting at an initial velocity isd = vit +at². represents the initial velocity

The distance an object has traveled when starting at an initial velocity is given by the equation:

d = vit + at²

To solve for acceleration, we need to isolate the term with "a" on one side of the equation. Let's begin by subtracting the first term on the right-hand side of the equation from both sides:

d - vit = at²

Next, we can divide both sides by t² to isolate "a":

a = (d - vit) / t²

Therefore, the equation for acceleration is:

a = (d - vi*t) / t²

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