If a truck if it is accelerating at a rate of 5m/s2 and hits a parked car with a force of 16,000 newtons what is its mass?
Answer:
3200kg
Explanation:
F=ma
16000=5m
m=3200kg
Hope this helps!
The mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.
What is mass?A tangible body's mass is the amount of matter it possesses. It's also a metric of inertia or the resistance to velocity when a net force is exerted.
It is given that:
If a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons
As we know,
Newton's second law:
F = ma
Here F is the force acting on an object.
m is the mass of the object
a is the acceleration of the object.
a = 5 m/s²
F = 16,000 N
m = 3200kg
16000 = 5m
3200 kg
Thus, the mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.
Learn more about the mass here:
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Does the speed of the object affect friction?
So which one would increase friction, going slowly, or going fast.
If possible an explanation? Thanks a bunch. :D
Answer:
it would
Explanation:
this is because as something rubs against a surface fast, friction heats it up, like when you rub a surface fast and it gets warm on the palm of your hand, that is friction. hope it helped :)
Amina has a mass of 48.4kg, what is her weight.please show calculation
G=m×g
since g=10N,
G=48.4×10
G=484
I hope it's true .d
good luck
A mover uses a ramp to load a crate of nails onto a truck. The crate, which must be lifted 1.5 m from the street to the bed of the truck, is pushed along the length of the ramp. If the ramp is 4.5 m long and friction between the ramp and crate can be ignored, what is the mechanical advantage of the ramp?
Answer:
3Explanation:
Using the efficiency formula. Efficiency = MA/VR * 100%
MA = Mechanical Advantage
VR = velocity ratio = [tex]\frac{distance\ moved\ by\ effort}{distance\ moved\ by\ load}[/tex]
Distance moved by effort = 4.5m
distance moved by load = 1.5m
VR = 4.5/1.5 =3
Assuming efficiency is 100% (since friction can be ignored)
100% = MA/3 * 100%
1 = MA/3
MA = 3*1
MA = 3
Mechanical Advantage of the ramp is 3
A high surface tension results from _____.
Answer:
Capillary Action.
Explanation:
Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, or even in opposition to, external forces like gravity.
AS WE CLIMB UP, THE PRESSURE INSIDE OUR BODY WILL BE.................. *
1 )low
2)high
3)very high
4)same
ASAP! HELP!
A 66.4 kg person sits on the right end of a seesaw, 2.35m from the fulcrum. On the other end, how far from the fulcrum should a 84.2kg person sit to balance the seesaw?
1: 1.92 m
2: 1.85m
3: 2.08m
4: 1.61 m
Answer:
2. 1.85
Explanation:
the equations weight * distance / other persons weight = distance from fulcrum. so 66.4*2.35/84.2=1.8532 round down to 1.85