Turner took a total of 8 quizzes over the course of 4 weeks. How many weeks of school will Turner have to attend this quarter before he will have taken a total of 16 quizzes? Assume the relationship is directly proportional. plz just put the answer

Answer:

7x+Y=-2

Step-by-step explanation:

(y-y1)=m(x-x1)

(Y+4)=-7(x-2)

Y+4=-7x+2

Y+7x=2-4

7x+Y=-2

Not sure what you mean but will be explaining about y = 0 and x =0 anyway.

So for x = 0, that means the value of x is 0.

y = -2(0)+8

y=0+8

y=8

So when x = 0, the value of y is 8 (y = 8) or we can write (0,8)

For y = 0, that means the value of y is 0.

0=-2x+8

-8=-2x

-2x=-8

x=4

So when y = 0, x = 4. We can write as (4,0)

Answer:

This would be 55 degrees because the sum of angles A, B and C = 180 degrees

Answer:

4

Step-by-step explanation:

because 2+2+2+2=8 pretty self explanatory

Answer:

13

Step-by-step explanation:

Answer:

30 and 8

Step-by-step explanation:

30 - 8 = 22

Answer:

He kept 7/12 of the box.

Step-by-step explanation:

We add and convert both 1/6 and 1/4 because we cant add fractions with unlike denominators.

1/6 = 2/12  | 1/4 = 3/12

then add.

2/12 + 3/12 = 5/12.

we subtract this from a whole, which is 12/12.

12/12 - 5/12 = 7/12

he keeps 7/12 of the box

hope this helped!

Answer:

(x − π)⁷ / 5040

(x − 1)³ / 16

Step-by-step explanation:

Taylor series expansion of a function is:

f(x) = ∑ₙ₌₀°° f⁽ⁿ⁾(x₀) / n! (x − x₀)ⁿ

where f⁽ⁿ⁾(x₀) is the nth derivative evaluated at x₀.

For the first problem, f(x) = sin x and x₀ = π.  We want the seventh degree term, so n = 7.

The seventh degree term is therefore: f⁽⁷⁾(π) / 7! (x − π)⁷

Find the seventh derivative of sin x:

f(x) = sin x

f⁽¹⁾(x) = cos x

f⁽²⁾(x) = -sin x

f⁽³⁾(x) = -cos x

f⁽⁴⁾(x) = sin x

f⁽⁵⁾(x) = cos x

f⁽⁶⁾(x) = -sin x

f⁽⁷⁾(x) = -cos x

Evaluated at π, f⁽⁷⁾(x) = 1.  So the seventh degree term is (x − π)⁷ / 5040.

For the second problem, f(x) = √x and x₀ = 1.  We want the third degree term,  so n = 3.

The third degree term is therefore: f⁽³⁾(1) / 3! (x − 1)³

Find the third derivative of √x:

f(x) = √x

f⁽¹⁾(x) = ½ x^-½

f⁽²⁾(x) = -¼ x^-³/₂

f⁽³⁾(x) = ⅜ x^-⁵/₂

Evaluated at 1, f⁽³⁾(x) = ⅜.  So the third degree term is (x − 1)³ / 16.

Answer:

Thus, the greatest number of rides I can go on is 15 rides

Step-by-step explanation:

I have $35.50 to spend for admission plus rides in the amusement park.

Admission costs $13. That leaves me with

$35.50 - $13 = $22.50

to spend on rides.

Considering each ride costs $1.50, we can find the maximum number of rides by dividing the remaining money by the cost per ride as follows:

$22.50 / $1.50 = 15

Thus, the greatest number of rides I can go on is 15 rides

Answer:

(6,-4)

Step-by-step explanation:

I have tried replacing each option with x, y in the equation.

Let's replace (6, -4) with x and y

3x+2y=10

3(6)+2(-4)=10

3(6)= 18 2(-4)= -8

18+(-8)=10

in other words:

18-8=10

The statement is true, so the correct answer is:

(6, -4)

Answer:

hmm, imma have to do the problem

Step-by-step explanation:

Answer: 325

Explanation:

Let the number of adult tickets be x

( since there are an unknown amount of tickets for adults, we already know how many student tickets there are)

Let the number of student tickets be x+60

710=x+x+60

710=2x+60

 -60        -60

650=2x

650/2

= 325

Adult tickets=325

Student tickets=385

Answer:  D

Step-by-step explanation:

If you put -5 and +5 on a number line and count their distance from zero they are both the same distance.

Answer:y = -0.6x + 5

Step-by-step explanation:

Answer:

yessir the one on top is right btw

Step-by-step explanation:

hope this helped