True / False. Selective distribution tends to work best for medium- and higher-priced products or stores that consumers don't expect to find on every street corner.

Therefore, The evaluated expression in terms of the variable t is 151 - 50e^(5t).

To evaluate the expression 151" + 75x' 125x with x = e^(5t) and provide an explanation in 100 words, ending with the main answer in 2 lines.
Expression: 151 + 75x - 125x
Given: x = e^(5t)
Step 1: Substitute x with e^(5t)
Expression: 151 + 75(e^(5t)) - 125(e^(5t))
Step 2: Combine like terms (75e^(5t) and -125e^(5t))
Expression: 151 - 50e^(5t)

Therefore, The evaluated expression in terms of the variable t is 151 - 50e^(5t).

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There are 8 major routes from the center of Happy Town to the center of Peaceful Town that go through the center of Miserable Town, we need to use the concept of permutations and combinations.

There are 5 major routes from Happy Town to Miserable Town, and 3 major routes from Miserable Town to Peaceful Town. Therefore, there are a total of 5 x 3 = 15 possible routes from Happy Town to Peaceful Town via Miserable Town. However, not all of these routes are unique. Some of them may overlap or follow the same path. To eliminate these duplicates, we need to consider the routes that start from Happy Town, pass through Miserable Town, and end at Peaceful Town as a group. Since there are 5 routes from Happy Town to Miserable Town, we can choose any one of them as the starting point. Similarly, since there are 3 routes from Miserable Town to Peaceful Town, we can choose any one of them as the ending point. Therefore, there are 5 x 3 = 15 possible combinations of starting and ending points. However, we have counted each route twice, once for each direction. So, we need to divide the total number of combinations by 2 to get the final answer. Therefore, the number of major routes from the center of Happy Town to the center of Peaceful Town that go through the center of Miserable Town is 15 / 2 = 7.5. However, since we cannot have half a route, we round up to the nearest whole number.

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(a) (A, B) = 0, (b) ||A|| = √2, (c) ||B|| = √2, (d) d(A, B) = -1. These values are calculated using the given inner product formula and the matrices A and B.

Let's calculate the required values step by step

To find (A, B), we need to substitute the elements of matrices A and B into the given inner product formula:

(A, B) = 2(a₁₁)(b₁₁) + (a₁₂)(b₁₂) + (a₂₁)(b₂₁) + 2(a₂₂)(b₂₂)

Substituting the values from matrices A and B:

(A, B) = 2(1)(0) + (0)(1) + (0)(1) + 2(1)(0)

= 0 + 0 + 0 + 0

= 0

Therefore, (A, B) = 0.

To find ||A|| (norm of A), we need to calculate the square root of the sum of squares of the elements of A:

||A|| = √((a₁₁)² + (a₁₂)² + (a₂₁)² + (a₂₂)²)

Substituting the values from matrix A:

||A|| = √((1)² + (0)² + (0)² + (1)²)

= √(1 + 0 + 0 + 1)

= √2

Therefore, ||A|| = √2.

To find ||B|| (norm of B), we can follow the same steps as in part (b):

||B|| = √((b₁₁)² + (b₁₂)² + (b₂₁)² + (b₂₂)²)

Substituting the values from matrix B:

||B|| = √((0)² + (1)² + (1)² + (0)²)

= √(0 + 1 + 1 + 0)

= √2

Therefore, ||B|| = √2.

To find d(A, B), we need to calculate the determinant of the product of matrices A and B:

d(A, B) = |AB|

Multiplying matrices A and B:

AB = [10 + 01 11 + 00;

00 + 11 01 + 10]

= [tex]\left[\begin{array}{cc}0&1&\\1&0\\\end{array}\right][/tex]

Taking the determinant of AB:

|AB| = (0)(0) - (1)(1)

= -1

Therefore, d(A, B) = -1.

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--The given question is incomplete, the complete question is given below " Use the inner product (A,B) = 2a₁₁b₁₁ + a₁₂b₁₂ + a₂₁b₂₁ + 2a₂₂b₂₂ to find (a) (A, B), (b) ll A ll, (c) ll B ll, and (d) d (A, B) for matrices in M₂,₂

A = [1 0; 0 1]

B = [0 1; 1 0]

Thank you, Please show work"--

Answer:

8x minus 2x is equal to 6x.

The critical value t* = 1.708 indicates that we need to go 1.708 standard errors away from the sample mean in both directions to capture 90% of the area under the t-distribution curve. The critical value t* = 2.678 indicates that we need to go 2.678 standard errors away from the sample mean in both directions to capture 99% of the area under the t-distribution curve.

To find the critical value t* for a given confidence interval and degrees of freedom (df), we need to consult a t-table or use a statistical software.

a) For a 90% confidence interval based on df = 25, we look up the t-value for 0.05 (or 1 - 0.9/2) and df = 25 in a t-table or use a calculator. The result is approximately t* = 1.708.

A 90% confidence interval means we want to be 90% confident that the true population parameter falls within the interval. The critical value t* represents the number of standard errors away from the sample mean that we need to go to construct the interval.

With df = 25, we have a smaller sample size and less precision, so we need a higher t-value to achieve the same level of confidence compared to larger samples.

b) For a 99% confidence interval based on df = 52, we look up the t-value for 0.005 (or 1 - 0.99/2) and df = 52 in a t-table or use a calculator. The result is approximately t* = 2.678.

A 99% confidence interval means we want to be 99% confident that the true population parameter falls within the interval. With df = 52, we have a larger sample size and more precision, so we can use a lower t-value to achieve the same level of confidence compared to smaller samples.

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Answer:

8√3

Step-by-step explanation:

method 1

180°-(30°+90°)= 60°

8=sin 30° × chord

sin 30°=1/2

chord=16

x^2 + 8^2 = 16^2

x=√256 - 64

x= √192 = 8√3

method 2:

use arcsin & arccos

method 3:

...

Answer:

-------------------------------

Substitute the coordinates of each point and solve the formed system:

So the value of coefficients is a = 2, b = 3.

integral diverges for the value of c = 6.

The value of the constant c for which the given integral converges is c=6.

When c=6, the integral can be evaluated as follows:

[integral symbol from 0 to infinity] 7x(x^2-1-7c)/(6x+1) dx

= [integral symbol from 0 to infinity] 7x(x^2-43)/(6x+1) dx

To evaluate this integral, we can use long division to divide 7x(x^2-43) by 6x+1. The result is:

7x(x^2-43) ÷ (6x+1) = (7/6)x^2 - (301/36)x + (43/6) - (10/36)/(6x+1)

Therefore,

[integral symbol from 0 to infinity] 7x(x^2-43)/(6x+1) dx

= [integral symbol from 0 to infinity] (7/6)x^2 - (301/36)x + (43/6) - (10/36)/(6x+1) dx

= [(7/6)x^3 - (301/72)x^2 + (43/6)x - (10/36)ln|6x+1|] evaluated from 0 to infinity

= infinity - 0

Thus, the integral diverges.

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Function p is a Exponential   function .The maximum possible area of the bell pepper patch is 18 square feet when the length of the tomato patch is 12 feet.

When the length of the tomato patch is 8 feet, the area of the bell pepper patch cannot be determined without more information about the function p.

The maximum possible area of the bell pepper patch is 18 square feet when the length of the tomato patch is 12 feet. This implies that the function p has a maximum value of 18 at x = 12.

Therefore, the answer is:

Function p cannot be classified without more information.

When the length of the tomato patch is 8 feet, the area of the bell pepper patch cannot be determined without more information about the function p.

The maximum possible area of the bell pepper patch is 18 square feet when the length of the tomato patch is 12 feet.

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The simplification of [tex]{(-3*1/2)}^2 / (-1/4)[/tex] gives us -9.

An expression means any statement having minimum of two numbers or variables and an operator connecting them.

First, we will simplify the expression inside the parentheses:

>>> (-3·1/2) = -3/2.

So we have (-3/2)^2 / (-1/4).

When we square (-3/2), this gives us 9/4.

We will now rewrite the expression as:

(9/4) / (-1/4).

To divide fractions, we will flip second fraction and then multiply, so we have:

(9/4) * (-4/1).

= 9 / 4 * -4 / 1

= 9 / -1

= -9.

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Given that,

Resistivity- Resistivity is a measure of the electrical resistance of a material per unit length and per unit cross-sectional area.

The resistance of a wire is given by

 R=ρL/A

In this case [tex]A=\pi r^2 =\pi (0.50*10^(-3) ) ^2\\=7.85*10^-7\\[/tex]

[tex]\frac{(50*10^-3m)(7.85*1^-7m)}{2m} \\=2.0*10^-8[/tex]

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The equation of the tangent plane to the surface g(x, y) = arctan y/x at the point (8, 0, 0) is z = -8x/65.

To find the equation of the tangent plane to the surface g(x, y) = arctan y/x at the point (8, 0, 0), we first need to find the partial derivatives of g with respect to x and y. Using the quotient rule and the chain rule, we get:

g_x = -y/(x^2+y^2)

g_y = 1/x*(1/(1+(y/x)^2))

Then, we evaluate these partial derivatives at the point (8, 0):

g_x(8, 0) = 0

g_y(8, 0) = 1/8

So the normal vector to the tangent plane is (0, 1/8, -1), and the equation of the tangent plane is of the form ax + by + cz = d. Plugging in the coordinates of the point (8, 0, 0), we get:

a*8 + b*0 + c*0 = d

Simplifying, we get a = d/8. To find the values of b and c, we use the fact that the normal vector is perpendicular to the tangent plane:

0a + 1/8b + (-1)c = 0

Solving for b and c, we get b = -8/65 and c = -1. Therefore, the equation of the tangent plane to the surface g(x, y) = arctan y/x at the point (8, 0, 0) is z = -8x/65.

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Given that tan(x) = −5/12 and x is in quadrant IV, we can use trigonometric identities to find the exact values of the expressions without solving for x.

We can begin by drawing a reference triangle in the fourth quadrant, with the opposite side equal to -5 and the adjacent side equal to 12. Using the Pythagorean theorem, we can find the length of the hypotenuse to be 13. Therefore, sin(x) = -5/13 and cos(x) = 12/13.

From these values, we can find the other trigonometric functions as follows:

csc(x) = 1/sin(x) = -13/5

sec(x) = 1/cos(x) = 13/12

cot(x) = 1/tan(x) = -12/5

So, the exact values of the expressions are sin(x) = -5/13, cos(x) = 12/13, csc(x) = -13/5, sec(x) = 13/12, and cot(x) = -12/5.

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The subsets d and e (Satisfying p(5) = 0 and those of the form p(x) = x^3 + c, respectively) are subspaces of P^4.

To determine which of the given subsets of P^4 (the vector space of polynomials of degree at most 4) are subspaces, we need to check if they satisfy the three properties of a subspace: closure under addition, closure under scalar multiplication, and containing the zero vector.

a. S is the subset consisting of those polynomials satisfying p(5) > 0:

This subset is not a subspace because it does not satisfy closure under scalar multiplication. If we multiply a polynomial in S by a negative scalar, the resulting polynomial will not satisfy p(5) > 0.

b. S is the subset consisting of those polynomials of degree three:

This subset is not a subspace because it does not contain the zero vector, which is the polynomial of degree zero.

c. S is the subset consisting of those polynomials of the form p(x) = ax^3 + bx:

This subset is not a subspace because it does not satisfy closure under addition. If we take two polynomials of this form and add them, the resulting polynomial will have an x^2 term, which is not in the given form.

d. S is the subset consisting of those polynomials satisfying p(5) = 0:

This subset is a subspace. It contains the zero vector, as the zero polynomial satisfies p(5) = 0. It also satisfies closure under addition and scalar multiplication, as the sum or scalar multiple of polynomials that satisfy p(5) = 0 will still satisfy p(5) = 0.

e. S is the subset consisting of those polynomials of the form p(x) = x^3 + c:

This subset is a subspace. It contains the zero vector (when c = 0), and it satisfies closure under addition and scalar multiplication. Adding or multiplying polynomials of this form will still result in a polynomial of the same form.

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The limit of (7x - ln(x)) as x approaches infinity is infinity.

To see why, note that the natural logarithm function ln(x) grows very slowly compared to any polynomial function of x. Specifically, ln(x) grows much more slowly than 7x as x becomes large. Therefore, as x approaches infinity, the 7x term in the expression 7x - ln(x) dominates, and the overall value of the expression approaches infinity. Alternatively, we could apply L'Hopital's rule to the expression by taking the derivative of the numerator and denominator with respect to x. The derivative of 7x is 7, and the derivative of ln(x) is 1/x. Therefore, the limit of the expression is equivalent to the limit of (7 - 1/x) as x approaches infinity. As x approaches infinity, 1/x approaches zero, so the limit of (7 - 1/x) is 7. However, this method requires more work than simply recognizing that the 7x term dominates as x approaches infinity.

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It is less likely that the sample used for the survey is representative of the population as a whole.

The sample for the survey conducted by the town council is not likely to be representative of the entire population for a few reasons.

Firstly the sample is limited to families with children who attend local schools.

This means that families who do not have children or have children who do not attend local schools are not included in the sample.

This could potentially skew the results as the opinions of these groups are not taken into account.

The sample is limited to families who choose to respond to the survey.

This means that families do not respond for whatever reason are not included in the sample.

This could lead to a biased sample as the opinions of those who choose to respond may differ from those who do not.

Thirdly the sample may not be large enough to accurately represent the entire population.

If the sample size is too small it may not provide a representative sample of the population could lead to inaccurate results.

The sample of families with children who attend local schools may provide some useful information it is not likely to be representative of the entire population.

It is important to take into account the limitations of the sample and the potential biases that may be present when interpreting the results.

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The region that lies inside both of the cardioids r = 2 - 2cos(θ) is the entire polar coordinate plane.

To find the region that lies inside both of the cardioids r = 2 - 2cos(θ), we need to determine the common area where both cardioids overlap.

The equation r = 2 - 2cos(θ) represents a cardioid with a radius of 2 and a dent inward due to the negative cosine term. Since we have two identical equations, both cardioids will have the same shape.

To find the region where both cardioids overlap, we need to determine the range of θ values where the cardioids intersect. Let's set the two equations equal to each other:

2 - 2cos(θ) = 2 - 2cos(θ)

By simplifying and rearranging the equation, we get:

cos(θ) = cos(θ)

This equation is true for all values of θ. Therefore, the two cardioids intersect for all values of θ, which means that the region that lies inside both cardioids is the entire polar coordinate plane.

In summary, the region that lies inside both of the cardioids r = 2 - 2cos(θ) is the entire polar coordinate plane.

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False. The statement is not necessarily true.

If 2 is an eigenvalue of a matrix A, it means that there exists a non-zero vector v such that Av = 2v.

To determine if A - 21 is invertible, we need to check if the eigenvalues of A - 21 are all non-zero.

Subtracting a constant from the matrix does not change its eigenvalues. Therefore, if 2 is an eigenvalue of A, then 2 - 21 = -19 is also an eigenvalue of A - 21.

Since -19 is a non-zero eigenvalue, it means that A - 21 is not invertible.

So, the correct statement would be: If 2 is an eigenvalue of A, then A - 21 is not invertible.

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Answer:

S = 9

Step-by-step explanation:

V = h * a * b (a - one of the base's side, b - another side of the base)

S = a * b

27 = 3 * S

S = 27 / 3

S = 9

To prove the given properties of Jacobi symbols, we first use the definition of the Jacobi symbol to rewrite it in terms of Legendre symbols. Then, we use the properties of Legendre symbols to show that (a) if a is congruent to b modulo n, then (na) = (nb) and (b) if a and b are integers, then (na)(nb) = (nab).

If a ≡ b (mod n), then a = b + kn for some integer k.

Using the definition of the Jacobi symbol, we have:

(na) = (3a)(5a)(7a)...

(nb) = (3b)(5b)(7b)...

Let p be an odd prime dividing n. We can write n = p^r * m, where r is a positive integer and m is not divisible by p.

Using the properties of congruence, we have:

3a ≡ 3b (mod [tex]p^r[/tex])

5a ≡ 5b (mod [tex]p^r[/tex])

7a ≡ 7b (mod [tex]p^r[/tex])

...

Since a ≡ b (mod n), we can also say that a ≡ b (mod [tex]p^r[/tex]). Therefore, for each prime factor p, the corresponding terms in the Jacobi symbols (3a/[tex]p^r[/tex]), (5a/[tex]p^r[/tex]), (7a/[tex]p^r[/tex]),... and (3b/[tex]p^r[/tex]), (5b/[tex]p^r[/tex]), (7b/[tex]p^r[/tex]),... are equal.

For each prime factor p, we have

(3a/[tex]p^r[/tex]) = (3b/[tex]p^r[/tex])

(5a/[tex]p^r[/tex]) = (5b/[tex]p^r[/tex])

(7a/[tex]p^r[/tex]) = (7b/[tex]p^r[/tex])

...

Since this holds for all odd prime factors p, we can conclude that (na) = (nb).

Using the multiplicativity property of the Jacobi symbol, we have:

(na)(nb) = (3a)(5a)(7a)...(3b)(5b)(7b)...

Using the same logic as in part (a), we can see that each term in the product on the left side is equal to the corresponding term in the product on the right side for each prime factor p. Therefore, we can write

(na)(nb) = (3ab)(5ab)(7ab)...

Using the definition of the Jacobi symbol, we can simplify this to:

(na)(nb) = (nab)

Thus, we have shown that (na)(nb) = (nab).

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The given series is a p-series of the form [infinity] n^-p, where p is a positive real number. For a p-series to converge, the value of p must be greater than 1.

In the given series, we have ln(n) which is always positive for n > 1. Therefore, we can write the series as [infinity] n^p / (ln(n))^p. To make this series converge, we need to ensure that p > 1.

Now, we can apply the p-test to determine the values of p for which the given series is convergent. The p-test states that if the series is of the form [infinity] n^-p and p > 1, then the series converges. Using this test, we can conclude that the series [infinity] 8 n(ln(n)) p n = 2 converges

if p > 1.

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The area of the pond is 240.41 square yards

From the question, we have the following parameters that can be used in our computation:

Radius, r = 8 3/4

The area of the pond is calculated as

Area = π * r * r

Substitute the known values in the above equation, so, we have the following representation

Area = 3.14 * 8 3/4 * 8 3/4

Evaluate

Area = 240.41

Hence, the area of the pond is 240.41 square yards

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The value of segment r is determined by applying Pythagoras theorem as 8.

The value of segment r is calculated by applying Pythagoras theorem as follows;

From the given diagram, we can set the following equation as follows;

OB² = AB²  +  OA²

The given parameters include;

OB = 2 + r

OA = r

AB = 6

Substitute these values into the equation and solve for r as follows;

(2 + r )² = 6²  +  r²

Simplify as follows;

4 + 4r + r² = 36 + r²

4r = 36 - 4

4r = 32

r = 32/4

r = 8

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The equation of the line tangent to the curve y + ex = 2exy at the point (0, 1) is y = x - 1. (Option C)

To find the equation of the tangent line, we need to first take the derivative of the given curve with respect to x using the product rule. Differentiating both sides with respect to x, we get:

y' + ex = 2ey + 2exy'

Solving for y', we get:

y' = (2ey - ex) / (1 - 2ex)

To find the slope of the tangent line at the point (0,1), we substitute x = 0 and y = 1 into the derivative we found:

y' = (2e - e0) / (1 - 2e0) = 2e / (1 - 2) = -2e

So, the slope of the tangent line at the point (0,1) is -2e. Now we can use the point-slope form of the equation of a line to find the equation of the tangent line:

y - 1 = -2e(x - 0)

Simplifying, we get:

y = -2ex + 1

Rearranging, we get:

y = x - 1

Therefore, the equation of the line tangent to the curve y + ex = 2exy at the point (0, 1) is y = x - 1.

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The time taken before drawdown in the well reaches 2m is 0.077836 min.

The diameter of the well is = 0.4 meter,

Now, we convert the unit of transmissivity (T) from m²/day to m²/sec,

So, Transmissivity (T) is = 108 × m²/day × day/60 min × 1/60sec,

= 1.25 × 10⁻³ m²/sec.

Next, we convert the unit of discharge from liter/second to m³/sec,

1 liter/sec = 0.001 m³/sec,

So, Discharge rate is = 5.6 × 0.001 = 0.0056 m³/sec.

The time "t" required for the drawdown in the well can be calculated by the formula :

S = Q/(4πT) × ln((2.2459 × T × t)/r²S,

where S = Storativity, r = radius, T = Transmissivity ,

Substituting the values,

We get,

2×10⁻⁵ = 0.0056/(4 × π × 1.25 × 10⁻³) × ln((2.2459 × 1.25 × 10⁻³ × t)/(0.2)²2×10⁻⁵,

(2×10⁻⁵×4 × π × 1.25 × 10⁻³)/0.0056 = ln((2.2459 × 1.25 × 10⁻³ × t)/(0.2)²2×10⁻⁵,

5.6 = ln(3509.21875 × t),

[tex]e^{5.6}[/tex] = 3509.21875t

So, t = 273.144/3509.21875;

t = 0.077836 min,

Therefore, it will take 0.077836 min before drawdown in well reaches 2m.

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The given question is incomplete, the complete question is

A 0.4-m diameter well is pumped continuously at a rate of 5.61 liters/second from an aquifer of transmissivity 108 m²/day and storativity 2×10⁻⁵ . How long will it take before the drawdown in the well reaches 2m ?

The volume of the larger pyramid is 64 times the volume of the smaller pyramid.

To find the volume of the larger pyramid, we need to understand the relationship between the volumes of similar solids.

When two solids are similar, their volumes are related by the cube of the scale factor.

In this case, the larger pyramid is a scaled version of the smaller pyramid with a scale factor of 4.

Since the scale factor is 4, the larger pyramid will have linear dimensions that are 4 times greater than the corresponding dimensions of the smaller pyramid.

Let's assume the volume of the smaller pyramid is V.

Since the scale factor is 4, the volume of the larger pyramid will be [tex](4^3)[/tex]times the volume of the smaller pyramid.

The volume of the larger pyramid is given by:

Volume of larger pyramid [tex]= (4^3) \times V = 64V.[/tex]

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The angle between the normals to the cylinder and sphere at their common point can be found using the dot product of the two normal vectors.

First, we need to find the normal vectors at the given point. The gradient of x^2 + y^2 - a^2 gives the normal vector to the cylinder, which is <2x, 2y, 0>. Evaluating at (a/2, a/√3, 0), we get the normal vector <a/√3, a/√3, 0>. The gradient of (x-a)^2 + y^2 + z^2 - a^2 gives the normal vector to the sphere, which is <2(x-a), 2y, 2z>. Evaluating at (a/2, a/√3, 0), we get the normal vector <0, 2a/√3, 0>.  Taking the dot product of the two normal vectors, we get 0, which implies that the two vectors are orthogonal. Therefore, the angle between them is 90 degrees.

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We can use the eigenvectors and eigenvalues information to find the matrix A that corresponds to them.

Let's denote the matrix as A = [a_ij], where i and j are the row and column indices of the matrix, respectively.

We know that v1 is an eigenvector of A corresponding to the eigenvalue λ1, which means that Av1 = λ1v1. Substituting the values of v1 and λ1, we get:

A[-5; -3] = -5[-5; -3]

Expanding the matrix-vector multiplication, we get two equations:

-5a_11 - 3a_21 = 25 (1)
-5a_12 - 3a_22 = 15 (2)

Similarly, v2 is an eigenvector of A corresponding to the eigenvalue λ2, which means that Av2 = λ2v2. Substituting the values of v2 and λ2, we get:

A[-3; 5] = 6[-3; 5]

Expanding the matrix-vector multiplication, we get two equations:

-3a_11 + 5a_21 = -18 (3)
-3a_12 + 5a_22 = 30 (4)

We now have four equations with four unknowns (a_11, a_12, a_21, a_22). We can solve these equations using any method of our choice, such as substitution or elimination. Solving the equations, we get:

a_11 = 3, a_12 = -5, a_21 = -9, a_22 = 7

Therefore, the matrix A is:

A = [ 3 -5 ]
[-9 7 ]

We can verify that this matrix satisfies the eigenvector equations:

Av1 = [-5; -3] = -5v1
Av2 = [-3; 5] = 6v2

Hence, v1 and v2 are indeed eigenvectors of A corresponding to the eigenvalues λ1=-5 and λ2=6, respectively, and A is the corresponding

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