Triangle H J K is cut by line segment A B. Line segment A B goes from side H J to side H K. The length of H A is 5. 25 inches, the length of H B is 3 inches, and the length of B K is 5 inches. What is the length of Line segment A J if Line segment A B is parallel to lines segment J K? 8 in. 8. 75 in. 10. 25 in. 14 in.

Answers

Answer 1

The segments on triangle HJK are illustrations of equivalent ratios

The length of line AJ is 8.75 inches

The given parameters are:

[tex]H A = 5.25[/tex]

[tex]HB = 3[/tex]

[tex]BK = 5[/tex]

Because lines AB and JK are parallel lines, then we have the following equivalent ratios

[tex]HA:HB = AJ:BK[/tex]

Substitute values for length HA, HB and BK.

[tex]5.25:3 = AJ:5[/tex]

Express both ratios as fractions

[tex]\frac{5.25}{3} = \frac{AJ}5[/tex]

Multiply both sides by 5

[tex]\frac{5.25}{3} \times 5= AJ[/tex]

[tex]8.75= AJ[/tex]

Rewrite as:

[tex]AJ = 8.75[/tex]

Hence, the length of line AJ is 8.75 inches

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Triangle H J K Is Cut By Line Segment A B. Line Segment A B Goes From Side H J To Side H K. The Length

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[tex]BrainiacUser1357[/tex]

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Step-by-step explanation:

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Answers

h(x) = g(f(x))

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Answer:

h(x) = sqrt{12x^3 + 32x^2}

The composite function as shown is [tex]g(f(x)) =\sqrt{12x^3+32x^2}[/tex]

Composite functions

Given the following fnctions

[tex]f(x) = 3x^3 + 8x^2\\g(x) = \sqrt{4x}[/tex]

The composite function g(f(x)) is expressed as:

[tex]g(f(x)) =g(3x^3 + 8x^2)\\g(f(x) )=\sqrt{4(3x^3 + 8x^2)} \\g(f(x)) =\sqrt{12x^3+32x^2}[/tex]

Hence the composite function as shown is [tex]g(f(x)) =\sqrt{12x^3+32x^2}[/tex]

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

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Answer:

Step-by-step explanation:

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The five-number summary of the data set given is:

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Answer:

SSS, SAS, ASA, AAS, HL

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Step-by-step explanation:

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Yes. If a+7 is even, then a is odd

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