To determine the muzzle velocity of a bullet fired from a rifle, you shoot the 2.47-g bullet into a 2.43-kg wooden block. The block is suspended by wires from the ceiling and is initially at rest. After the bullet is embedded in the block, the block swings up to a maximum height of 0.295 cm above its initial position. What is the velocity of the bullet on leaving the gun's barrel

Answer:

Where are fuel cells used?

Fuel cells are used for primary and backup power for commercial, industrial and residential buildings and in remote or inaccessible areas. They are also used to power fuel cell vehicles, including forklifts, automobiles, buses, boats, motorcycles and submarines

Explanation:

Answer:

what the heck is sakurfa

Explanation:

Answer:

Earth has a much greater mass than objects on its surface

Answer:

hello your question has a some missing information below is the missing information

An electron is one of the most fundamental particles in nature. It is everywhere, in all the matter we can see, and it is with electrons that light interacts when it is emitted, absorbed, or scattered in everyday matter. The electron has a more massive cousin called a muon, also with a charge of -1 e, but with a mass of 1.88x10-28 kg. The electron's mass is 9.11x10-31 kg. You can see why a muon is called a "heavy" electron. A muon is also unstable, and left alone at rest in a lab it will turn into an electron, kinetic energy, and two neutrinos with a lifetime of 2.20x10-6 s.

answer :

energy and velocity of Electron : 8*10^-13 J , < 3*10^8 m/s

energy and velocity of Muon :  8*10^-13 J,  9.22 * 10^7 m/s

Explanation:

Determine the energies and velocities of the electrons and Muons when they pass through the hole

i) energy of electron = q1 * V -- ( 1 )

V ( voltage ) = 5 * 10^6 V

q1 ( charge on electron ) = 1.6 * 10^-19 C

back to equation 1 ; energy of electron = ( 1.6 * 10^-19 ) * 5 * 10^6

= 8*10^-13 J

ii) velocity of electron = 1/2 * Me *( Ve)^2

1/2 * Me *( Ve)^2 = 8*10^-13

∴Ve = [tex]\sqrt{(8*10^{-13} )/(9.11*10^{-31} )}[/tex]   <   3*10^8 m/s

iii) energy of muon

= Eu = q*v = 8*10^-13 J

iv ) velocity of Muon = [tex]\sqrt{(8*10^{-13} )/(1.88*10^{-28} )}[/tex]  = 9.22 * 10^7 m/s

Answer:

right

Explanation:

Answer:

uv radiation cause cancer

uv radiation effect our eyes

Answer:

you can get

1:skin cancer

2:eye damage

3:skin damage

4:immune system suppression

choose which two u want

hope this helped

:)

Explanation:

Answer: hetero i think i dont know

Explanation:

Answer:

When two substances that cannot dissolve each other are mixed, a mixture is formed.

i hope this helps a little bit.

Answer:

Wind blows__wind energy ____causing the turbine to turn, rotating shaft works pump__mechanical___energy.

Motion of water moving up from well___kinetic energy___energy.

Water in tank which is positioned 5 feet above the ground level______potential energy

Explanation:

Wind has in it wind energy which is then used to rotate the turbine shaft which is a form of mechanical work and hence possess mechanical energy

Moving water posses kinetic energy and when this water is kept at some height it possess potential energy

Answer:

so you have a question

Explanation:

either way, have a nice day

This question is not complete, the complete question is;

A centroid is an object's geometric center. For an object of uniform composition, its centroid is also its center of mass. Often the centroid of a complex composite body is found by, first, cutting the body into regular shaped segments, and then by calculating the weighted average of the segments' centroids.

An object is made from a uniform piece of sheet metal. The object has dimensions of α = 1.50 ft, where α is the diameter the semi-circle, b= 3.51 ft, and c = 2.20 ft. A hole with diameter d = 0.500 ft is centered at ( 1.21, 0.750 ).

Find x", y", the coordinates of the body's centroid.

Answer:

x" = 1.4857 ft

y" = 0.668 ft

Explanation:

Given the data in the question and as illustrated in the second image below;

from the image;

BC² = DC² - BD²

BC² = 2.2² - 1.5² = 4.84 - 2.25 = 2.59

BC = √2.59 = 1.61 ft

AB = 3.51 ft - 0.75 ft - 1.61 ft = 1.15 ft

so;

A₁ = [tex]\frac{1}{2}[/tex] × 1.51 ft × 1.61 ft  = 1.2075 ft²

x₁ = 0.75 + 1.15 + [tex]\frac{1}{3}[/tex](1.61 ft) = 2.44 ft

y₁ = [tex]\frac{1}{3}[/tex](1.5 ft) = 0.5 ft

A₂ = 1.15 ft × 1.5 ft = 1.725 ft²

x₂ = 0.75 ft + ( 1.15/2 )ft = 1.325 ft

y₂ = ( 1.5/2 ) ft = 0.75 ft

A₃ = [tex]\frac{\pi }{2}[/tex](0.75 ft)² = 0.88 ft²

x₃ = 0.75 - ([tex]\frac{4 }{3\pi }[/tex](0.75 ft)) = 0.43 ft

y₃ = 0.75 ft

diameter d = 0.5 ft and centered at ( 1.21, 0.750 )

A₄ = [tex]\frac{\pi }{4}[/tex]( d )² =  

x₄ = 1.21 ft

y₄ = 0.75 ft

Thus;

x" = [tex]\frac{A_1 x_1 + A_2 x_2 + A_3 x_3 - A_4x_4 }{A_1+A_2+A_3-A_4}[/tex]

so we substitute

x" = [tex]\frac{(1.2075X2.44) + (1.725 X 1.325) + (0.88X0.43) - (0.196 X 1.21 )}{ ( 1.2075 + 1.725 + 0.88 - 0.196 )}[/tex]

x" = [tex]\frac{ (2.9463 + 2.285625 + 0.3784 - 0.23716)}{ 3.6165 }[/tex]

x" = 5.373165 / 3.6165

x" = 1.4857 ft

y" = [tex]\frac{A_1 y_1 + A_2 y_2 + A_3 y_3 - A_4y_4 }{A_1+A_2+A_3-A_4}[/tex]

so we substitute

y" = [tex]\frac{(1.2075X0.5) + (1.725 X 0.75) + (0.88X0.75) - (0.196 X 0.75 )}{ ( 1.2075 + 1.725 + 0.88 - 0.196 )}[/tex]

y" = [tex]\frac{ (0.60375 + 1.29375 + 0.66 - 0.14112)}{ 3.6165 }[/tex]

y" = 2.41638 / 3.6165

y" = 0.668 ft

Therefore,

x" = 1.4857 ft

y" = 0.668 ft

Answer:

Distance is 300 and displacement is 100

Explanation:

Distance= 100+100+100=300

Displacement=100

plz mark me as brainliest.

Answer:

B)60km[W]

Explanation:

The boat travels 20km/h. So every hour the boat goes 20 miles. So if one hour equals 20km. Then 3 hours will be 3*20km which equals 60km. The boat is also going west. So you should consider putting that in your answer as well. So the answer would be B)60km[W].

Hope that helps!

Answer:

love is a feeling that you get for people that you care about.

Explanation:

Answer:

Love is a feeling of affection for someone, when you adore somebody.

I wish true love and soul mates were real ( •_•)

Answer:

B. They are smaller and made of rocky material

Explanation:

i think it's right??

Explanation:

According to the law of conservation of energy, energy can neither be created nor destroyed but can be changed from one form to another.

for example : electrical energy can be converted or changed into light energy, sound energy, heat energy etc. this proofs that the law can be trusted because, it has just been proven by the example above that it can be changed and into many forms

Answer:

7374.4

Explanation:

I took the test

(filler so I can post)

Answer:

Attached below is the required diagram related to the question

answer :

q'3 = WбT^4

engineer's proposal has merit

Explanation:

Let : A'3 represent the deep space

      A'1 represent the surface area , F13 and  F23  represent the view factors

      T1 , T2, T3 ; represent temperatures

      q'3 represent net rate of heat radiation

 Derive the expression for the rate per unit length at which radiation is transferred from the surfaces to deep space

derived expression ; q'3 = WбT^4

attached below is a detailed solution

Given that The emission is proportional to the area of the opening and the surfaces ( 1 and 2 ) have the same temperature hence this problem can be treated as a two surface enclosure. hence the engineer's proposal have merit .

attached below is a prove ( b )

ALL of the quantities are unknown, because you haven't bothered to tell us anything that's known.

Answer:

a)   p = 1.381 10⁻²⁹ kg m / s, b)  λ = 4.80 10⁻⁵ m,

c)  λ/a₀ = 9.6 10⁴ = 10⁵,   λ/aₙ = 4.80 10⁹

Explanation:

a) as the neutral goes at speeds much lower than the speed of light we can use the classical relationships, as the neutral all the thermal energy is the energy of the neutron

           E = p c

           K T = pc

           p = k T / c

           p = [tex]\frac{ 1.381 \ 10^{-23} \ 300}{3 \ 10^8}[/tex]

           p = 1.381 10⁻²⁹ kg m / s

b) the expression for the de Broglie wavelength

          p = h / λ

          λ = h / p

          λ =[tex]\frac{ 6.63 \ 10^{-34} }{1.381 \ 10^{-29}}[/tex]

          λ = 4.80 10⁻⁵ m

c) let's compare this size with the size of atoms a₀ = 0.5 10⁻⁹ m

         λ/a₀ = [tex]\frac{ 4.80 \ 10^{-5} }{0.5 \ 10^{-9}}[/tex]

         λ/a₀ = 9.6 10⁴ = 10⁵

c) let's compare with the atomic nucleus size aₙ = 10⁻¹⁴ m

          λ/aₙ = [tex]\frac{4.80 \ 10^{-5} }{10^{-14} }[/tex]

          λ/aₙ = 4.80 10⁹

Answer:

  v = 5.88 10⁷ m / s

Explanation:

For this exercise we use the relation

          E = m c²

also indicate that all energy is converted into kinetic energy

          E = K = ½ (M-2m) v²

where m is the mass of antimatter and M is the mass of the ship's mass. Factor two is due to the fact that equal amounts of matter and antimatter must be combined

we substitute  

         m c² = ½ (M-2m) v²

        v² = [tex]2 \frac{m}{M+2m} \ c^2[/tex]

let's calculate

        v = [tex]\sqrt{2 \ \frac{4 \ 10^4 }{2 \ 10^6 + 2 \ 4 \ 10^4} \ (3 \ 10^8)^2}[/tex]

         v = [tex]\sqrt{ 34.615 \ 10^{14}}[/tex]

        v = 5.88 10⁷ m / s

Answer:

390 light-years

Explanation:

50 x 7.8 =390

Answer:

Applications of zeroth law of thermodynamics:

1. When we get very hot food, we wait to make it normal. In this case, hot food exchanges heat with surrounding and brings equilibrium.

2. We keep things in the fridge and those things come equilibrium with fridge temperature.

3. Temperature measurement with a thermometer or another device.

4. In the HVAC system, sensors or thermostats are used to indicate temperature. It always comes in a thermal equilibrium with room temperature.

5. If you and the swimming pool you’re in are at the same temperature, no heat is flowing from you to it or from it to you (although the possibility is there). You’re in thermal equilibrium.

Answer:

mass, weight, strength of gravity increases, weight decreases

Explanation:

got it on edge

Answer:

An object’s

✔ mass

will remain constant throughout the universe, but its

✔ weight

can change from planet to planet.

If you increase the mass of a planet, what happens to its gravity?

✔ strength of gravity increases

If the gravity on a planet decreases, what happens to the weight of an object on that planet?

✔ weight decreases

Explanation:

right on edge 22

Answer:

Collision theory is used to predict the rates of chemical reactions, particularly for gases. It is based on the assumption that for a reaction to occur for the reacting species (atoms or molecules) must come together or collide with one another. Not all collisions, however, bring about chemical change.

If two molecules collide with sufficient activation energy, there is no guarantee that the collision will be successful. In fact, the collision theory says that not every collision is successful, even if molecules are moving with enough energy. The reason for this is because molecules also need to collide with the right orientation so that the proper atoms line up with one another, and bonds can break and re-form necessarily.

Answer:

the lowest possible frequency of the emitted tone is 404.79 Hz

Explanation:

   Given the data in the question;

S₁ ←  5.50 m → L

↑

2.20 m

↓

S₂

We know that, the condition for destructive interference is;

Δr = ( 2m + [tex]\frac{1}{2}[/tex] ) × λ

where m = 0, 1, 2, 3 .......

Path difference between the two sound waves from the two speakers is;

Δr = √( 5.50² + 2.20² ) - 5.50

Δr = 5.92368 - 5.50

Δr = 0.42368 m

v = f × λ

f = ( 2m + [tex]\frac{1}{2}[/tex])v / Δr

m = 0, 1, 2, 3, ....

Now, for the lowest possible frequency, let m be 0

so

f = ( 0 + [tex]\frac{1}{2}[/tex])v / Δr

f = [tex]\frac{1}{2}[/tex](v) / Δr

we know that speed of sound in air v = 343 m/s

so we substitute

f = [tex]\frac{1}{2}[/tex](343) / 0.42368

f = 171.5 / 0.42368

f = 404.79 Hz

Therefore, the lowest possible frequency of the emitted tone is 404.79 Hz

Answer:

a. The system will rotate in the clockwise direction with a constant angular speed.

Explanation:

As all the clay is identical sphere and there will be hence same mass 'm' for all three clay spheres. Now their identical speed 'v' and collision time [tex]$'t_0'$[/tex] are also same. So all the spheres will exert same force F on the rod.

[tex]$f=\frac{mv}{t_0}$[/tex]

Force exerted by the clay Z on rod is passing through pivot, so no torque will be produced.

Now clay X will collide at near distance from pivot than that of clay Y.

So clay Y will produce more torque than clay X. So clay Y will give more clockwise torque. So rod will rotate clockwise.

Now in any impact because net force and net torque are zero (because in impact torque and force occurs in equal and opposite pairs). So net angular momentum will be conserved and hence angular speed will be constant.

Therefore it is clear that option (a) is correct.