Answer:
Acid, Horizontally, Drain off the acid by opening the stopcock
Explanation:
A buret is a calibrated glass appratus used to measure and deliver accurate volume of liquid, usually acids, in acid-base titrations.
Before usually the buret to carry out your titration reaction, it is advised to condition or prepare your buret for use.
To condition the buret, add a small volume of the acid to the buret and rotate the barrel horizontally to ensure that the liquid ( acid) makes contact with the inner surface of the barrel o the buret.
This procedure is done to wash off any previous acid or liquid that the buret had been used for in previous titrations.
Complete this action by opening the stopcock of the buret to drain off the acid and discarding each volume in a designated waste container.
Note that acids could be corrosive and dangerous to the skin and so should be handled with great care
How many grams of CO are produced when 41.0 g of C reacts?
Answer:
95.7 g CO to the nearest tenth.
Explanation:
2C + O2 ---> 2CO
Using relative atomic masses:
24 g C produces 2*12 + 2*16 g CO.
So 41 g produces ( (2*12 + 2*16) * 41 ) / 24
= 95.7 g CO,
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calculate the volume (in milliliters) of the 1.436 M stock NaOH solution needed to prepare 250.0 mL of 0.1342 M dilute NaOH solution.
Answer:
23.36mL of the stock solution are required.
Explanation:
A dilution consist in the addition of solvent to decreases the concentration of a stock solution (The solution more concentrated).
As you want to prepare 250.0mL = 0.2500L of a 0.1342M NaOH, moles of NaOH you require to make this concentration in this volume are:
0.2500L × (0.1342mol / L) = 0.03355 moles of NaOH you require in the diluted solution.
These moles comes from the 1.436M stock solution. The volume of the stock solution you need to add is:
0.03355moles NaOH × (1L / 1.436mol) = 0.02336L of the 1.436M solution =
23.36mL of the stock solution are required.Al(NO3)3+H2SO4=HNO3+Al2(SO4)3
Hey there!:
2 Al(NO)₃+ 3 H₂SO₄ → 1 Al₂O₁₂S₃+ 6 HNO₃
Reagents : Al(NO₃)₃ and H₂SO₄
Products : Al₂O₁₂S₃ and HNO₃
Coefficients : 2 , 3 , 1 and 6
Hope this helps!
solution solution solution
Answer:
Oxygen present in food items makes then rancid due to the presence of oils and fats. If the food is flushed with nitrogen, it prevents it from being oxidised (the nitrogen acts as an antioxidant).
Hope it helps ! :)
Each energy sub level contains __________ number of electrons. For example, sub level D can hold up to _______ electrons. A. the same, 10 B. the same, 14 C. a different, 6 D. a different, 10
Answer:
the same and 14
Explanation:
ed tell chem
Answer: the same 10
Explanation:
Carbon dioxide gas reacts with liquid water to produce aqueous carbonic acid.” Which chemical equation correctly translates this description? CO2 (s) + H2O (g) → H2CO3 (s) CO2 (l) + H2O (l) → H2CO3 (l) CO2 (g) + H2O (g) → H2CO3 (aq) CO2 (g) + H2O (l) → H2CO3 (aq)
Answer: CO2(g)+H2O(I) > H2CO3(Aq)
Explanation:
Got it right?
(4Ga + 3S2 → 2Ga2S3)
1. How many moles of Sulfur are needed to react with 12.5 moles of Gallium
Answer:
9.375
Explanation:
According to the chemical equation, for every 4 moles of gallium, 3 moles of sodium are needed to react. Set up a ratio using this relationship to solve.
4/3 = 12.5/x
4x = 37.5
x = 9.375
You need 9.375 moles of sulfur.
A 2.0 g sample of hydrocarbon was burned in the calorimeter. The temperature rose from 29°c to 32°c and heat and combustion is 11. Kj/g. Thr heat capacity of the calorimeter is
Answer:
THE HEAT CAPACITY OF THE CALORIMETER IS 3666.67 J/C
Explanation:
Mass = 2 g
Temperature difference = 32 C - 29 C = 3 C
Heat of combustion = 11 kJ/g
Heat capacity of the calorimeter = unknown
It is important to note that the heat of combustion of the reaction is the heat absorbed by the calorimeter in raising the mixture by 3 C
So therefore,
Heat = heat capacity * temperature difference
Heat capacity = Heat / temperature difference
Heat capacoty = 11 000 J / 3 C
Heat capacity = 3666.67 J/ C
Why does a new period start on the periodic table, instead of the row continuing? A. A new period starts when a new energy shell starts. B. A new period starts when a new neutron cycle starts. C. None of these D. It is based on how many protons it has.
Answer:
B
Explanation:
All the elements in a period have valence electrons in the same shell. The number of valence electrons increases from left to right in the period. When the shell is full, a new row is started and the process repeats.
A new period starts when a new neutron cycle starts. Hence, option B is correct.
What is the period in the periodic table?A period in the periodic table is a row of chemical elements. All elements in a row have the same number of electron shells.
All the elements in a period have valence electrons in the same shell.
The number of valence electrons increases from left to right in the period.
When the shell is full, a new row is started and the process repeats.
Hence, option B is correct.
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For a given sample of C3H8(g), the enthalpy change during the reaction is -784kJ. How many grams of CO2 are produced? Group of answer choices g
Answer:
[tex]m_{CO_2}=46.6gCO_2[/tex]
Explanation:
Hello,
In this case, considering the combustion of propane:
[tex]C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)\ \ \ \Delta _CH=-2220.0 kJ/mol[/tex]
We can compute the burnt moles of propane as shown below:
[tex]n=\frac{-784kJ}{-2220.0 kJ/mol} =0.353molC_3H_8[/tex]
Then, by noticing propane and carbon dioxide are in a 1:3 molar ratio, we can compute the grams carbon dioxide by using the shown below stoichiometric procedure:
[tex]m_{CO_2}=0.353molC_3H_8*\frac{3molCO_2}{1molC_3H_8} *\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=46.6gCO_2[/tex]
Best regards.
What is the mass of 7.68 x 1024 molecules of phosphorus trichloride?
Answer:
THE MASS OF 7.68 *10^24 MOLECULES OF PHOSPHORUS TRICHLORIDE IS 1746.25 g.
Explanation:
Molar mass of PCl3 = ( 31 + 35.5 *3) = 137.5 g/mol
At 7.68 * 10^24 molecules, how many number of mole is present?
6.03 * 10^23 molecules = 1 mole
7.68*10^24 molecules = x mole
x mole = 7.68 *10^24 molecules/ 6.03 *10^23
x mole = 1.27 *10 moles
x mole = 12.7 moles
Using mole = mass / molar mass
mass = mole * molar mass
mass = 12.7 moles * 137.5 g/mol
mass = 1746.25 g
Hence, the mass of 7.68 *10^24 molecules is 1746.25 g
If the NaOH is added to 35.0 mL of 0.167 M Cu(NO3)2 and the precipitate isolated by filtration, what is the theoretical yield of the reaction?
Answer:
The correct answer is - 0.570 grams
Explanation:
The balanced chemical reaction is given by
Cu(NO3)2(aq) + 2NaOH(aq) --------> Cu(OH)2(s) + 2NaNO3(aq)
1.0 mole 2.0 mole 1.0 mole 2.0 mole
number of mol of Cu(OH)2,
n = Molarity * Volume
= [tex]35.0*0.167 = 5.845[/tex] millimoles
As clear in the equation, 1 mole of Cu(NO3)2 gives 1 mole of Cu(OH)2 , So, 5.845 millimoles of Cu(NO3)2 will produce 5.845 millimoles of Cu(OH)2
Mass of Cu(OH)2 = number of mol * molar mass
= [tex]97.5*5.845*10^-3[/tex]
= 0.570 grams
Thus, the correct answer is - 0.570 grams
Which aqueous solution will have the highest boiling point temperature? A. 0.100 molal NiBr2(aq) B. 0.250 molal CH3OH(aq) C. 0.100 molal MgSO4(aq) D. 0.150 molal Na2SO4(aq) E. 0.150 molal NH4NO3(aq)
Answer: 0.150 m [tex]Na_2SO_4(aq)[/tex] will have highest boiling point.
Explanation:
Formula used for Elevation in boiling point :
[tex]\Delta T_b=i\times k_b\times m[/tex]
where
[tex]\Delta T_b=T_b-T^o_b[/tex]= elevation in boiling point
[tex[k_b[/tex] = boiling point constant
m = molality
i = Van't Hoff factor
A) 0.100 m [tex]NiBr_2[/tex]
i = 3 as [tex]NiBr_2\rightarrrow Ni^{2+}+2Br^-[/tex]
concentration will be [tex]3\times 0.100=0.300[/tex]
B) 0.250 m [tex]CH_3OH[/tex]
i = 1 as [tex]CH_3OH[/tex] is a non electrolyte
concentration will be [tex]1\times 0.250=0.250[/tex]
C) 0.100 molal [tex]MgSO_4(aq)[/tex]
i = 2 as [tex]MgSO_4\rightarrrow Mg^{2+}+SO_4^{2-}[/tex]
concentration will be [tex]2\times 0.100=0.200[/tex]
D. 0.150 molal [tex]Na_2SO_4(aq)[/tex]
i = 3 as [tex]Na_2SO_4\rightarrrow 2Na^{+}+SO_4^{2-}[/tex]
concentration will be [tex]3\times 0.150=0.450[/tex]
E. 0.150 molal [tex]NH_4NO_3(aq)[/tex]
i = 2 as [tex]NH_4NO_3\rightarrrow NH_4^{+}+NO_3^{-}[/tex]
concentration will be [tex]2\times 0.150=0.300[/tex]
The solution having the highest concentration of ions will have the highest boiling point and thus 0.150 m [tex]Na_2SO_4(aq)[/tex] will have highest boiling point.
The aqueous solution that would have the highest temperature at boiling point would be:
D). 0.150 molal Na2SO4(aq)
What is a boiling point?The boiling point is described as the temperature at which the solution starts boiling or the vapor pressure becomes equivalent to the provided external/outer pressure.
To determine the elevation in boiling point, we will use:
Δ[tex]T_{b}[/tex] [tex]= i[/tex] × [tex]k_{b}[/tex] × [tex]m[/tex]
with
[tex]T_{b}[/tex] [tex]= T_{b} - T^{0}_{b}[/tex]
[tex]k_b[/tex] [tex]=[/tex] constant of boiling point
Using this formula,
0.150 molal Na2SO4(aq)
Given,
[tex]i = 3[/tex]
[tex]Na2So4[/tex] will have
[tex]2Na^{+}[/tex] [tex]+[/tex] [tex]SO^{2-}_{4}[/tex]
So,
Concentration [tex]= 3[/tex] × [tex]0.15[/tex][tex]0[/tex]
[tex]= 0.45[/tex][tex]0[/tex]
∵ 0.150 molal [tex]Na2SO4[/tex]Na2SO4(aq) has the maximum concentration.
Thus, option D is the correct answer.
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can somebody please help me asap !!!
Answer:
Option A. 1191.49 K
Explanation:
Data obtained from the question include:
The equation for the reaction is given below:
4HCl + O2 —> 2Cl2 + 2H2O
Enthalpy (H) = +280 KJ/mol = +280000 J/mol
Entropy (S) = +235 J/Kmol
Temperature (T) =..?
The temperature at which the reaction will be feasible can be obtained as follow:
Change in entropy (ΔS) = change in enthalphy (ΔH)/T
(ΔS) = (ΔH)/T
235 = 280000/T
Cross multiply
235 x T = 280000
Divide both side by 235
T = 280000/235
T = 1191.49 K
Therefore, the temperature at which the reaction will be feasible is 1191.49 K
Average Molarity for HCl is .391
Average Molarity for NaOH is .0962
Volume for HCl is:
Trial 1 Your Answer: 14mL
Trial 2 Your Answer: 14mL
Trial 3 Your Answer: 14mL
Volume for NaOH is:
Trial 1: 34.26mL
Trial 2: 33.48mL
Trial 3: 33.84mL
Entry # mass tablet(g) mass antacid(g) Vol HCl(mL) Vol NaOH(mL)
#1: 1.515 0.9010 14.00 34.26
#2: 1.452 0.8370 14.00 33.48
#3: 1.443 0.8280 14.00 33.84
I need help finding the mmoles HCl/mg please.
Answer:
#1: 0.00144 mmolHCl/mg Sample
#2: 0.00155 mmolHCl/mg Sample
#3: 0.00153 mmolHCl/mg Sample
Explanation:
A antiacid (weak base) will react with the HCl thus:
Antiacid + HCl → Water + Salt.
In the titration of antiacid, the strong acid (HCl) is added in excess, and you're titrating with NaOH moles of HCl that doesn't react.
Moles that react are the difference between mmoles of HCl - mmoles NaOH added (mmoles are Molarity×mL added). Thus:
Trial 1: 0.391M×14.00mL - 0.0962M×34.26mL = 2.178 mmoles HCl
Trial 2: 0.391M×14.00mL - 0.0962M×33.48mL = 2.253 mmoles HCl
Trial 3: 0.391M×14.00mL - 0.0962M×33.84mL = 2.219 mmoles HCl
The mass of tablet in mg in the 3 experiments is 1515mg, 1452mg and 1443mg.
Thus, mmoles HCl /mg OF SAMPLE for each trial is:
#1: 2.178mmol / 1515mg
#2: 2.253mmol / 1452mg
#3: 2.219mmol / 1443mg
#1: 0.00144 mmolHCl/mg Sample#2: 0.00155 mmolHCl/mg Sample#3: 0.00153 mmolHCl/mg SampleA mixture of krypton and nitrogen gases, at a total pressure of 711 mm Hg, contains 11.7 grams of krypton and 4.10 grams of nitrogen. What is the partial pressure of each gas in the mixture
Answer:
A. Partial pressure of krypton, Kr is 346.97 mmHg
B. Partial pressure of nitrogen, N2 is 364.03 mmHg.
Explanation:
Step 1:
Data obtained from the question. This include the following:
Total pressure (Pt) = 711 mmHg
Mass of Kr = 11.7 g
Mass of N2 = 4.10 g
Partial pressure of Kr =..?
Partial pressure of N2 =...?
Step 2:
Determination of the number of mole of krypton, Kr and nitrogen, N2. This is illustrated below:
Molar mass of Kr = 84g/mol
Mass of Kr = 11.7g
Mole of Kr =?
Mole = mass /Molar mass
Mole of Kr = 11.7/84 = 0.139 mole
Molar mass of N2 = 2x14 = 28g/mol
Mass of N2 = 4.10g
Mole of N2 =?
Mole = mass /Molar mass
Mole of N2 = 4.1/28 = 0.146 mole
Step 3:
Determination of the mole fraction for each gas. This is illustrated below:
Mole of Kr = 0.139 mole
Mole of N2 = 0.146 mole
Total mole = 0.139 + 0.146 = 0.285 mole
Mole fraction of Kr = mol of Kr/total mol
Mole fraction of Kr = 0.139/0.285
Mole fraction of Kr = 0.488
Mole fraction of N2 = mol of N2/total mol
Mole fraction of N2 = 0.146/0.285
Mole fraction of N2 = 0.512
A. Determination of the partial pressure of krypton, Kr.
This is illustrated below:
Total pressure (Pt) = 711 mmHg
Mole fraction of Kr = 0.488
Partial pressure of Kr =..?
Partial pressure = mole fraction x total pressure
Partial pressure of Kr = 0.488 x 711
Partial pressure of Kr = 346.97 mmHg
B. Determination of the partial pressure of nitrogen, N2
This is illustrated below:
Total pressure (Pt) = 711 mmHg
Mole fraction of N2 = 0.512
Partial pressure of N2 =?
Partial pressure = mole fraction x total pressure
Partial pressure of N2 = 0.512 x 711
Partial pressure of N2 = 364.03 mmHg
4. What is the molar concentration and grams/Liter of a NaOH solution if 86 ml are titrated to an
endpoint by 375 ml of a solution of HCl that is .0175 M?
g/L: ________
Molarity: ____
Answer:
0.76 M
30 g/L
Explanation:
Step 1: Given data
Molarity of the acid (Ma): 0.175 MVolume of the acid (Va): 375 mLMolarity of the base (Mb): ?Volume of the base (Vb): 86 mLStep 2: Calculate the molarity of the base
We will use the following expression.
[tex]Ma \times Va = Mb \times Vb\\Mb = \frac{Ma \times Va}{Vb} = \frac{0.175M \times 375mL}{86mL} = 0.76 M[/tex]
Step 3: Calculate the concentration of the base in g/L
The molar mass of NaOH is 40.00 g/mol.
[tex]\frac{0.76mol}{L} \times \frac{40.00g}{mol} = 30 g/L[/tex]
Calculate the amount of heat required to convert 10.0 grams of ice at –20.°C to steam at 120.°C. (Sp. heat of H2O(s) = 2.09 J/g•°C, Sp. heat of H2O(l) = 4.18 J/g•°C, Sp. heat of H2O(gas) = 2.03 J/g•°C; heat of fusion of H2O(solid) = 333 J/g, heat of vaporization of H2O(liquid) = 2260 J/g).
Answer:
THE AMOUNT OF HEAT REQUIRED TO CONVERT ICE FROM -20 C TO STEAM AT 120 C IS 30 946 J OR 30.946 KJ OF HEAT.
Explanation:
Mass = 10 g
To convert 10 g of ice at -20°C to steam at 120°C, the heat involved is:
1. Heat involved in converting the ice from -20 °c to ice at 0 °C:
Heat = mass * specific heat of water solid * change in temperature
heat = 10g * 2.09 J/g°C * ( 0- (-20))
Heat = 10 * 2.09 * 20
heat = 418 J
2. Heat required to convert the ice from 0°C to water at 0°C:
Heat = mass * specific heat of fusion of water solid
Heat = 10 * 333
Heat = 3330 J
3. Heat required to convert water at 0 C to water at 100 C:
Heat = mass * specific heat of water * change in teperature
Heat = 10 * 4.18 * (100 -0)
Heat = 4180 J
4. Heat required to convert water at 100 C to steam at 100 C:
Heat = mass * specific heat of vaporization
Heat = 10 * 2260
Heat = 22600 J
5. Heat required to convert steam from 100 C to steam at 120 C:
Heat = mass * specific heat of water * change in temperature
Heat = 10 * 2.09 * (120 -100)
Heat = 10 * 2.09 * 20
Heat = 418 J
T
he heat required to convert 10 g of ice at -20 C to steam at 120 C is therefore the total of the individual heat of reactions
Total amount of heat = ( 418 J + 3330 J + 4180 J + 22600 J + 418 J)
Total heat = 30946 J
Determine the [OH⁻] concentration in a 0.344 M Ca(OH)₂ solution.
Answer:
[tex]0.688M[/tex]
Explanation:
Hello,
In this case, it is widely acknowledged that strong bases usually correspond to those formed with metals in groups IA and IIA which have relatively high activity and reactivity, therefore, when they are dissolved in water the following dissociation reaction occurs (for calcium hydroxide):
[tex]Ca(OH)_2\rightarrow Ca^{2+}+2OH^-[/tex]
In such a way, for the same volume, we can compute the concentration of hydroxyl ions by simple stoichiometry (1:2 molar ratio):
[tex]0.344\frac{molCa(OH)_2}{L}*\frac{2molOH^-}{1molCa(OH)_2} \\\\0.688\frac{mol OH^-}{L}[/tex]
Or simply:
[tex]0.688M[/tex]
Regards.
For the reaction 2 A - Products, the concentration of A is monitored over time. A graph of [A] versus time was found to be linear, with a negative slope. Select the true statement regarding this reaction.
A) The reaction is first order with respect to A.
B) The reaction is second order with respect to A.
C) The rate constant has a negative value.
D) In 2 The reaction has a half-life equal to k.
E) None of these statements is true.
Answer:
none of these statements is true
according to the question E) None of these statements is true.
What is a concentration in chemistry?The concentration of a chemical substance expresses the amount of a substance present in a mixture. There are many different ways to express concentration. Chemists use the term solute to describe the substance of interest and the term solvent to describe the material in which the solute is dissolved
What is concentration in chemistry units?
Quantitative units of concentration include molarity, molality, mass percentage, parts per thousand, parts per million, and parts per billion.
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A 32.3-gram sample of gas is found to have a volume of 1.9 liters at 301 K and 1.21 atm. What is the molar mass of this gas? Show all of the work used to solve this problem.
Answer:
351.1g/mol
Explanation:
you can find the answer using The ideal gas equation
n= PV/RT
n=(1.21*1.9/0.082*301)mol
n=0.092 mol
molar mass=Mass/mole
m=32.3g/0.092mol
m=351.1g/mol
The substance used by homeowners and municipal workers to melt ice on sidewalks and roadways is usually calcium chloride rather than sodium chloride. Discuss two possible rea-sons for this preference.
Answer:
1. It dissolves much more ice faster than sodium chloride
2. Calcium chloride is more effective in melting ice at lower temperatures.
Explanation:
Salts are used to melt ice on roadways and sidewalks because they help to lower the freezing point of water.
Sodium chloride and calcium chloride are both salts used for this purpose but calcium chloride is usually preferred for the following two reasons:
1. It dissolves much more ice faster than sodium chloride: Calcium chloride dissolves much more ice faster than sodium chloride because when it dissociates, it produces three ions instead of the two produced when sodium chloride. Therefore, the heat of hydration of its ions is greater than that of sodium chloride.
2. Calcium chloride is more effective in melting ice at lower temperatures. It lowers the freezing point of water more than sodium chloride. Calcium chloride is able to lower the freezing point of water to about -52°C while sodium chloride only lowers it to about -6°C.
If the reaction consumes methane gas ( CH4 ) at a rate of 2.08 M/s, what is the rate of formation of H2 ? the balanced equation is CH4 + N2Cl4 = CCl4 + N2 + 2 H2
Answer:
4.16M/s
Explanation:
Based on the reaction:
CH₄ + N₂Cl₄ ⇄ CCl₄ + N₂ + 2H₂
1 mole of methane, CH₄, produce 2 moles of H₂.
That means whereas 1 mole of methane is consumed, 2 moles of H₂ are formed
Having this in mind, if you are consuming methane at a rate of 2.08M/s, the rate of formation of hydrogen must be twice this rate, because there are produced twice moles of H₂.
Thus, rate of formation of H₂ is:
2.08M/s ₓ 2 =
4.16M/s
The rate of formation of H2 is 4.16M/s
The calculation is as follows:Based on the reaction:
CH₄ + N₂Cl₄ ⇄ CCl₄ + N₂ + 2H₂
here
1 mole of methane, CH₄, produce 2 moles of H₂.
In the case when you are consuming methane at a rate of 2.08M/s, the rate of formation of hydrogen must be twice this rate, because there are produced twice moles of H₂.
Thus, rate of formation of H₂ is:
2.08M/s ( 2) = 4.16M/s
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Using GRIGNARDS REAGENT convert methane to ethanol
Answer:
J
Explanation:
Which of the following is an alkali metal?
A. Lithium (LI)
B. Boron (B)
c. Calcium (Ca)
D. Krypton (Kr)
Answer:
lithium is akali metal
Answer:
lithium is an alkali metal as it lies in group 1st in modern perodic table.
4. What are the potential sources of error that might cause disagreement between the activity series' prediction of reactions and your observations of reactions
Answer:
1. Not to have enough salt water on the foil
2.not cleaning the foil well to remove interfering materials
By what mechanism does cyclohexanol react when treated in sulfuric acid and what compound results?A) E 1; methoxycyclohexane B) E2: methoxycyclohexane C) SN 1; methoxycycloheXafle D) E2; cyclohexene E) E 1: cyclohexene
Answer:
E 1: cyclohexene
Explanation:
This reaction is an example of the dehydration of cyclic alcohols. The reaction proceeds in the following steps;
1) The first step of the process is the protonation of the cyclohexanol by the acid. This now yields H2O^+ attached to the cyclohexane ring.
2) the water molecule, which a good leaving group now leaves yielding a carbocation. This now leaves a cyclohexane carbocation which is highly reactive.
3) A water molecule now abstracts a proton from the carbon adjacent to the carbocation leading to the formation of cyclohexene and the regeneration of the acid catalyst. This is an E1 mechanism because it proceeds via a carbocation intermediate and not a concerted transition state, hence the answer.
According to valence bond theory, which orbitals overlap in the formation of the bond in HCl?
a) 1s on H and 3p on Cl
b) 1s on H and 4s on Cl
c) 1s on H and 2p on Cl
d) 2s on H and 3p on Cl
e) 2s on H and 2p on Cl
New technologies have allowed buildings to become taller and heavier than
ever before. This is an example of:
A. green design.
B. the engineering process.
C. the evolution of building techniques.
D. material failure.
Answer:
C. the evolution of building techniques
Hope this helps.
Which products are formed when aluminum is added to a silver chlorine solution?
Answer:
Alcl3 and Cl2
Explanation:
the product above will be formed
Answer:
silver (Ag) and aluminum chloride (AlCl₃)
Explanation:
The reaction between aluminum and silver chloride is a single replacement reaction. A single replacement reaction is when one element switches places with another.
Al + 3AgCl ➔︎ 3Ag + AlCl₃
In the reaction, the cations (positively charged ions) switch places. Aluminum (Al) switches places with Silver (Ag). So, the products of the reaction are silver and aluminum chloride.
Hope this helps.