Answer:
0.553 J/g°C
Explanation:
From the question given above, the following data were obtained:
Heat (Q) required = 99.7 J
Mass (M) = 34.7 g
Temperature change (ΔT) = 5.20 °C
Specific heat capacity (C) =?
Thus, we can obtain the specific heat capacity of titanium as follow:
Q = MCΔT
99.7 = 34.7 × C × 5.20
99.7 = 180.44 × C
Divide both side by 180.44
C = 99.7 / 180.44
C = 0.553 J/g°C
Therefore, the specific heat capacity of titanium is 0.553 J/g°C.
Change the following word equation into a formula equation AND balance it. Iron(III) carbonate --> Iron(III) oxide + Carbon dioxide
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