tipler stock dropped $5 monday, rosary $3 Tuesday, and rose $7 Wednesday. what was the net change in price of the stock​

Answer:

C

Step-by-step explanation:

Both models represent half of the gymnasium, its just that one is vertical and one is horizontal. Both are basically correct. C is the right answer since it says both models are correct. Each class also does occupy 1/12 of the gymnasium since they get 1/6 of 1/2 of the gymnasium. Of means multiply so 1/6 * 1/2 = 1/12.

Answer:

Drinking coffee and drinking water are independent events because

P(A|B)=P(A)and P(B|A)=P(B)

Step-by-step explanation:

Drinking coffee and water are independent events. People can choose to have both, none or any one. It is on their own will. Those who drink coffee can also drink water. The total of people who drink coffee may include those who drink water also.

Problem 5

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Explanation:

We have these four identities

Notice how computing i^4 leads us back to 1. So i^4 = i^0. The pattern repeats every 4 terms. So we divide the exponent by 4 and look at the remainder. We ignore the quotient entirely. We can see that 28/4 = 7 remainder 0. Meaning that i^28 = i^0 = 1.

We can think of it like this if you wanted

i^28 = (i^4)^7 = 1^7 = 1

Then the sqrt(-36) becomes 6i

So overall, we end up with the final answer of 6i

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Problem 6

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Explanation:

We'll use the ideas mentioned in problem 5

46/4 = 11 remainder 2

i^46 = i^2 = -1

sqrt(-9) = 3i

The two outside negative signs cancel out, but there's still a negative from -1 we found earlier. So we end up with -3i

In other words, here is one way you could write out the steps

[tex]-i^{46}*-\sqrt{-9}\\\\-i^{2}*-3i\\\\i^{2}*3i\\\\-1*3i\\\\-3i\\\\[/tex]

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Problem 7

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Work Shown:

i^10 = i^2 because 10/4 = 2 remainder 2

i^19 = i^3 because 19/4 = 4 remainder 3

i^7 = i^3 because 7/4 = 1 remainder 3

Again, all we care about are the remainders.

[tex]i^{10}+i^{19} - i^{7}\\\\i^{2}+i^{3} - i^{3}\\\\i^{2}\\\\-1[/tex]

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Problem 8

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Work Shown:

i^22*i^6 = i^(22+6) = i^28

Earlier in problem 5, we found that i^28 = i^0 = 1

So,

[tex]i^1 - \left(i^{22}*i^{6}\right)\\\\i^1 - i^{28}\\\\i^1 - i^{0}\\\\i - 1\\\\-1+i[/tex]

Answer:

45 = 3z

Step-by-step explanation:

On the left we have 45

On the right we have 3 z's

45 = 3z

Answer:

45 = 3 z

Step-by-step explanation:

LHS = RHS.

45 = 3 z

Answer:

15x+30y-220

Step-by-step explanation:

Answer:

2nd one

Step-by-step explanation:

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

Answer:

A

Step-by-step explanation:

Answer:

its b i took the test

Step-by-step explanation:

Answer:

The Subtotal cost of all the cakes before tax and delivery

Step-by-step explanation:

(21x+8.25y)

21 is the price of 1 large cake and X is the number of cakes they want to purchase not counting tax and delivery fee.

8.25 is the price of 1 small cake and Y is the number of cakes they want to purchase not counting tax and delivery fee.

Answer:

x²+y²+6x+2y = -8

Step-by-step explanation:

The given equation is:

(x+3)²+(y+1)²=2

We know that, (a+b)² = a²+b²+2ab

Using above property

x²+9+6x+y²+1+2y = 2

x²+y²+6x+2y+10 = 2

x²+y²+6x+2y = -8

Hence, this is the required solution.

Answer:

32 years old.

Step-by-step explanation:

13 times 2 is 26, and 6 added to 26 is 32.

I hope this helps, have a nice day.

Answer:

56 but i could be wrong

Step-by-step explanation:

Answer:

Your answer is correct

Step-by-step explanation:

B. 112 degrees

Answer:

x = 112

Step-by-step explanation:

x and 68 are supplementary angles so they add to 180

x+68 = 180

x = 180 -68

x = 112

Answer:

a) In the interval of [1980,1983].

b) In the interval of [1991, 1996].

Step-by-step explanation:

Fuel efficiency:

The fuel efficiency, for the cars, in x years after 1980, is given by:

[tex]E(x) = 0.36x + 15.9[/tex]

15.9 is the fuel efficiency in 1980.

a. In what years was the average fuel efficiency for cars less than 17 mpg (in interval form)?

From 1980 to:

[tex]E(x) < 17[/tex]

[tex]0.36x + 15.9 < 17[/tex]

[tex]0.36x < 1.1[/tex]

[tex]x < \frac{1.1}{0.36}[/tex]

[tex]x < 3.06[/tex]

3.06 = 1980 + 3 = 1983. So

In the interval of [1980,1983].

b. In what years was the average fuel efficiency for cars more than 20 mpg (in interval form)?

From x until 1996.

[tex]E(x) > 20[/tex]

[tex]0.36x + 15.9 > 20[/tex]

[tex]0.36x > 4.1[/tex]

[tex]x > \frac{4.1}{0.36}[/tex]

[tex]x > 11.38[/tex]

11.38 = 1980 + 11 = 1991. So

In the interval of [1991, 1996].

Answer:

y=6

the first equation:

3(1)+y=9

3+y=9

y=6

the second equation:

y= -4(1)+10

y= -4+10

y=6

I hope this helped! :)

Answer:

21:50

Step-by-step explanation:

We need to find the ratio of 420 m to 1 km.

We know that,

1 km = 1000 m

So,

The ratio becomes,

[tex]\dfrac{420\ m}{1\ km}=\dfrac{420\ m}{1000\ m}\\\\=\dfrac{42\ m}{100\ m}\\\\=\dfrac{21}{50}[/tex]

So, the required ratio is 21:50.

x - 9 ≤ 2(9 - x)

x - 9 ≤ 18 - 2x

3x - 9 ≤ 18

3x ≤ 27

x ≤ 9

(just handle it like an equation)

Answer:

a) Median Height = 66 inches

b) Range of Heights = 18 inches

Step-by-step explanation:

a) The median in a box-and-whisker plot is the second quartile, located between the first and third quartiles indicated by the dashed line. Therefore, the median height is 66 inches.

b) The range in a box-and-whisker plot uses the same process of finding the range of a set of data. You find the difference between the maximum and the minimum values of the data. Therefore, the range of heights is 77 - 59 = 18 inches.

Answer:

3, 9, 15, 21

Step-by-step explanation:

3x1=3 v

3x2=6

3x3=9 v

3x4=12

3x5=15 v

3x6=18

3x7=21 v

Skip one each time, 3, 9, 15, 21

Answer:

Solution given;

diameter[d]=12

we

have

circumference of circle=πd=12π

12 is a required answer.

_________

#LetsStudy

Answer:

x = 10

Step-by-step explanation:

In an equilateral triangle, the altitude, or height is also the median and angle bisector. So, we can say a side of the equilateral triangle is 2 x 5 or 10. Every side of an equilateral triangle is congruent, so x is 10.

Answer:

sí, (yo) quiero un chocolate

Answer:

The approximate proportion of 1-mile long roadways with potholes numbering between 20 and 70 is 0.9735.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 50, standard deviation = 10.

Between 20 and 70.

The normal distribution is symmetric, which means that 50% of the measures are below the mean and 50% are above.

20

20 = 50 - 3*10

So 20 is 3 standard deviations below the mean. Of the 50% of the measures below the mean, 99.7% are within 3 standard deviations of the mean, that is, above 20.

70

70 = 50 + 2*10

So 70 is 2 standard deviations above the mean. Of the 50% of the measures above the mean, 95% are within 2 standard deviations of the mean, that is, below 70.

Percentage:

0.997*50% + 0.95*50% = 97.35%

As a proportion, 97.35%/100 = 0.9735.

The approximate proportion of 1-mile long roadways with potholes numbering between 20 and 70 is 0.9735.

Answer:

First one

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

answers are 3 and 62

Step-by-step explanation:

the answers were give above. If further instruction needed lmk :)

Answer:

22g+1

Step-by-step explanation:

collect like terms

22g+1

Answer:22g+1

Step-by-step explanation:

Awnser:

9,12,18

Step-by-step explanation:

you have to add the smallest numbers together and it has to be greater that the greatest number.

9+12= 21

21>18

Answer:

-10

Step-by-step explanation:

The negative integers greater than -5 are: -4, -3, -2, and -1. So,

(-4)+(-3)+(-2)+(-1) = -10

Answer:

54cm and 36cm

Step-by-step explanation:

triangle a : triangle b

50cm² : 16cm²

25 : 8

thus,

area of triangle a :

2cm×25cm

=50cm²

area of triangle b :

2cm×16cm

=32cm²

then,

perimeter of triangle a:

2cm+2cm+25cm+25cm

=54cm

perimeter of triangle b:

2cm+2cm+16cm+16cm

=36cm