This shouldn’t be too hard so help if you can please!

Answer:

If it's in decimal form, it can be 30+0.15=30.15

Step-by-step explanation:

Answer:

17>16

Step-by-step explanation:

Answer:

17 is greater than or (>) than any number lower than 17 :)

Step-by-step explanation:

For example, 17>16.. 17> 15, or 17> 14...ect.

Hope this helps! :)

Have a nice day <3

Answer:

c

Step-by-step explanation:

Answer:

56

Step-by-step explanation:

7x8=56

Step-by-step explanation:

7(8)

= 56

use tye substitution property

Answer:

$512.90 should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with mean $480 and standard deviation $20.

This means that [tex]\mu = 480, \sigma = 20[/tex]

How much should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05?

This is the 100 - 5 = 95th percentile, which is X when Z has a pvalue of 0.95, so X when Z = 1.645.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.645 = \frac{X - 480}{20}[/tex]

[tex]X - 480 = 1.645*20[/tex]

[tex]X = 512.9[/tex]

$512.90 should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05

The answer is B

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

area of the figure=(1/2×22/7×12²)+(12×4)+(8×3)

=226.28+48+24

=298.28

Answer:

D. g(x) = 2-x^2

Step-by-step explanation:

g(x) seems to be a vertical translation of f(x).

f(x) = 5-x^2

g(x) = 5-x^2-3 (subtract 3 as a translation down 3 units)

g(x) = 2-x^2

Answer:

5

Step-by-step explanation:

8x + 12 = 52

move constant to right

8x=52-12

subtract numbers

8x=40

divide both sides

x=5

Answer:

A

Step-by-step explanation:

Answer:

116

Step-by-step explanation:

All angles will add up to 360°

So just do 360 -55 -79 -110 = 116

Answer:

The answer is 116 because the sum of angles in a quadrilateral is 360 degrees.

Answer:

4(7+y) and 4·7+4·y

Step-by-step explanation:

4(7+y)= 28+4y

4·7+4·y= 28+4y

Answer:

1.478

Step-by-step explanation:

the answer is seven twelfth

Answer:

$5760

Step-by-step explanation:

12000 × 8 × .06 = 5760

Answer:

467.58

Step-by-step explanation:

Grows 0.4% --> r = .004

Grows every 10 years: exponent of t/10

where t is in years

Write a function:

f(t) = 450(1+0.004)^t/10

96 years means no time conversion is needed due to years being the only unit in the problem

T = 96

f(96) = 450(1+0.004)^96/10

= 467.580247756

≈467.58

youre welcome y'all

Answer:

D .

Sorry if i'm wrong.

[tex]x(2 {x}^{2} + 4x - 1 )\\ = 2 {x}^{3} + 4 {x}^{2} - x[/tex]

Answer:

Is the question really expanded notation

Answer:

divide the diameter by 2

Answer:

I think the answer would be B

Step-by-step explanation:

Because we multiply, distribute and combine like terms

9514 1404 393

Answer:

  8

Step-by-step explanation:

If the bags can either be given or not, each bag can assume one of two states. In order for there to be 200 possible combinations of items in one of two states, there must be at least log2(200) = 7.64 items. The minimum number of bags is x = 8.

_____

The contents of the 8 bags will be Rs. 1, 2, 4, 8, 16, 32, 64, 73.

The discriminant of function [tex]f(x,y)=x^3 + y^4 - 6x-2y^2+3[/tex] is 72xy³ – 24x and points (√2,0), (-√2, 1) and (-√2, -1) are saddle point, and points (√2, 1) and (√2, -1) are local minima.

A function is an expression in terms of one or more variable.

If f(x, y)  is a two-dimensional function that has a local extremum at a point ([tex]x_o, y_o[/tex])  and has continuous partial derivatives at this point, then [tex]f_x (x_o, y_o)=0[/tex] and [tex]f_y (x_o, y_o)=0[/tex]. The second partial derivatives test classifies the point as a local maximum or local minimum.

Then

1. If D > 0 and [tex]f_{xx}(x_o, y_o) > 0[/tex] , the point is a local minimum.

2. If D > 0 and [tex]f_x_x (x_o, y_o) < 0[/tex], the point is a local maximum.

3. If D < 0, the point is a saddle point.

4. If D = 0, higher order tests must be used.

Given that

[tex]f(x,y)=x^3 + y^4 - 6x-2y^2+3[/tex]

[tex]f_x = 3x^2-6[/tex]

[tex]f_x = 0[/tex] implies that [tex]x = \pm\sqrt2[/tex]

[tex]f_y= 4y^3-4y[/tex]

[tex]f_y= 0[/tex]  implies that y = 0; y = [tex]\pm[/tex]1.

Thus, the critical points are (√2,0), (√2,1), (√2, -1);(-√2,0), (-√2,1); (√2, -1).

[tex]f_{xx} = 6x[/tex]; [tex]f_y_y = 12y^3 - 4[/tex], [tex]f_{xy}= 0[/tex]

D(x, y) = [tex]f_{xx}f_{yy} - f_{xy}^2[/tex]

          = 6x × (12y³ – 4)

D(√2, 0) = -24√2 < 0  implies (√2,0)  is a saddle point.

D(√2, 1) = 48√2 > 0 ; [tex]f_{xx}(2, 1) = 6\sqrt2 > 0[/tex] implies (√2, 1)  is local minimum.

D(√2, -1) = 48√2 > 0; [tex]f_{xx}(2, -1) = 6\sqrt2 > 0[/tex]  implies (√2, -1)  is local minimum.

D(-√2, 0) = 24√2 > 0; [tex]f_{xx}(-2,0) = -6\sqrt2 < 0[/tex]  implies (-√2, 0)  is local maximum.

D(-√2, 1) = -48√2 < 0  implies (-√2, 1)  is a saddle point.

D(-√2, -1) = -48√2 < 0  implies (-√2, -1)  is a saddle point.

Thus, (√2,0), (-√2, 1) and (-√2, -1) are saddle point, and (√2, 1) and (√2, -1) are local minima.

Learn more about functions here:

https://brainly.com/question/31062578

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Step-by-step explanation: This equation is prime.